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  • Get current user from View

    - by gosu kiwi
    So what I want to do is, in my main layout, have a menu for logged in users, and a different for anon users. THe layout will be used on every page, so I'm not sure how to do this, as I've seen, the Auth Component can only be used in the controller, this would be nice if I had to do this in only one view, but for every view, how can I do this? Do I have to do something on AppController? What I want to do is basically // layout <?php if(logged): ?> Welcome <?php echo $user; ?> <?php else: ?> Welcom anon, Log in? <?php endif; ?>

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  • iPhone - At user event create objects in the view

    - by insaneshow
    Hello, I am new to iPhone programming, so I think part of the problem is that I don't know what I really want to google to find my answer. I am looking for a method that allows a user to draw a line on the screen. There is no guarantee that it will be straight, it can be curved or whatever. I was thinking that I could create some small square image, and then as they draw, place them into a NSset. But I am not really sure how to communicate each new object up to the view. Up to this point, I've just been messing around with objects I put on the view and then assign movement to those, this is my first jump into on-the-fly object creation. It might be that I just need to jump into a class/object type or even a tutorial, any guidance would be great. Thanks!

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  • EF4 (CPT5) ForeignKeyAttribute in base class - Assert Failure entityType != null

    - by Anthony Johnston
    Getting an error when trying to set a ForeignKeyAttribute in a base class class User{} abstract class FruitBase{ [ForeignKey("CreateById")] public User CreateBy{ get; set; } public int CreateById{ get; set; } } class Banana{} class DataContext : DbContext{ DbSet<Banana> Bananas{ get; set; } } If I move the FruitBase code into the banana, all is well, but I don't want to, as there will be many many fruit and I want to remain relatively DRY if I can Is this a know issue that will be fixed by March? Does anyone know a work around?

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  • How to release my view from stack ?

    - by aman-gupta
    Hi, In my application I m using following coding convention to open my default screen :-- AppDelegate *ptrDefaultScreen = (AppDelegate *)[[UIApplication sharedApplication]delegate]; [self.navigationController presentModalViewController:ptrDefaultScreen.FrmFlashScreenLink animated:YES]; but when I move to other screen after default screen ,my default screen is still exists even i used [self dismissModelViewController:YES]; to dimiss default screen from view. where I m wrong I want my default screen will be completely removed from view. Is any other way to call default screen before actual application. Please help me out.Thanks in advance

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  • Does Entity Framework saves related classes automatically?

    - by herbatnic
    Let's assume that we have such classes public class A{ string someField { get; set; } public virtual B B {get; set; } } public class B { int someIntField {get; set; } [ForeignKey("Id")] [Required] public virtual A A { get; set; } } In code I create new instances for both of them and making relation like: A a = new A () { someField = "abcd"}; B b = new B () { someIntField = 42 }; A.B = b; B.A = a; Should I using DBContext to save both classes like that: using (var db = new myDbContext()) { myDbContext.As.Add(A); myDbContext.Bs.Add(B); myDBContext.SaveChanges(); } Or saving it like that: using (var db = new myDbContext()) { myDbContext.As.Add(A); myDbContext.SaveChanges(); } is enough to store related objects into database?

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  • How to move to another view without using a button

    - by Will
    My first view displays an image and action indicator while web-servers and database function are run in that background. I want the application to go to my tab view when the functions have been completed. How do I do this? Here is what the views look like. What I have tried: TabBarViewController *tab = [[TabBarViewController alloc]init]; [self presentViewController:tab animated:NO completion:nil]; and [self performSegueWithIdentifier:@"first" sender:self]; Please can you help my to understand how to do this. I have spent many hours googling this problem and couldn't work out how to do it. Thanks EDIT: Added Code

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  • ERROR: there is no parameter $1 when creating view

    - by idlemoments
    When we try to create a view within a funcion we get ERROR: there is no parameter $1. This is the sample code. Begin CREATE VIEW artikelnr AS SELECT datum, 'uitgifte' as "type", CASE WHEN 'test'='test' THEN 0 END as "aantal ontvangen", aantal as "aantal uitgegeven" FROM uitgifteregel JOIN artikel ON artikel.artikelnr = new.artikelnr JOIN uitgifte ON uitgifte.uitgiftenr = uitgifteregel.uitgiftenr UNION SELECT datum, 'ontvangst' as "type", aantal as "aantal ontvangen" , CASE WHEN 'test'='test' THEN 0 END as "aantal uitgegeven" FROM ontvangstregel JOIN artikel ON artikel.artikelnr = new.artikelnr JOIN ontvangst ON ontvangst.ontvangstnr = ontvangstregel.ontvangstnr; Return new; end; When we replace new.artikelnr on line 7 with value 1 it works like it should, but the function needs to work with different artikelnr's. example line 7: JOIN artikel ON artikel.artikelnr = new.artikelnr Please point us in the right direction.

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  • A Map of View instances?

    - by user291701
    Is it possible to keep references to views keyed off of their hashCode? Something like: Map<Integer, View> views; views.put(view1.hashCode(), view1); views.put(view2.hashCode(), view2); views.put(viewN.hashCode(), viewN); I have a few in my view hierarchy and am downloading images for each. I want to be able to iterate over them quickly, or see if I've already previously added one (hence the map).

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  • Asp.net with MVC multiple model in one view (create, update)

    - by Abdalmohaymen
    I have problem in asp.ne Mvc with multiple model in one view on create and update I 'm work on exams system class Questions and class Answers Question is aparent class and Answers is a child class [Bind(exclude("id"))] class Quesions { public string question{get; set;} public Datetime Timepostquestion{get; set;} } [Bind(exclude("id"))] class Answers { public string answer{get; set;} public Datetime Timepostanswer{get; set;} public questionId {get; set;} } in a view I use two classes how to use classes in insert and update what a way which I have to solve my problem

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  • Eclipse does not refresh project files in package explorer view

    - by EugeneP
    Today I see a strange behaviour of Eclipse 3.5.2 for the first time in 3 months. First, when I run a main function, it runs a previously compiled version. Let's say I press Ctrl+F11 in the window with an open java class and existing main function. Usually it rebuilds the class and runs a new version. Today even if there was a compile mistake, it would run fine. So I guess it does not recompile the class. Next, more strangely, if I intentionally make a mistake in the code and Eclipse underlines those lines in red, still the project Explorer does not mark them as containing errors. They remain of grey color if there were not any errors. First I did not know how to solve this problem. I tried to reopen the project, restart Eclipse and finally reboot the OS. After the tenth attempt, after rebooting, Eclipse said that all project's files are "OUT OF SYNC with the file system". When I pressed "Refresh" - F5 on a project's header name in Project Explorer it finally marked all the files with errors as containing errors and running the main function gave the desired result. An hour of my work passed and this happened again , with the other project. All the same. No marking of files as red, running no matter what old version of class with no compile errors. And since Eclipse does not tell that files are out of sync, simply pressing F5 on a project cannot help. What can you suggest?

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  • Android refresh StateListDrawable problem

    - by Max
    Hi all, I have a strange problem with StateListDrawable or maybe (probably) I'm missing something. I created a test application for it and the same problem occurs. So, this is my StateListDrawable resourse in file test_selection.xml <?xml version="1.0" encoding="utf-8"?> <selector xmlns:android="http://schemas.android.com/apk/res/android"> <item android:state_selected="true"> <shape android:shape="rectangle" android:background="#ff0000"> <corners android:radius="10dp" /> <gradient android:startColor="#ff5555" android:endColor="#ff5555" android:angle="0" /> </shape> </item> <item android:state_selected="false"> <shape android:shape="rectangle" android:background="#eeeeee"> <corners android:radius="10dp" /> <gradient android:startColor="#eeeeee" android:endColor="#eeeeee" android:angle="0" /> </shape> </item> </selector> It's a very simple selector that draw a red color for selected state and a white rect for the unselected one. My main.xml template is very simple. I simply use a TextView that uses the selection as background. <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:orientation="vertical" android:layout_width="fill_parent" android:layout_height="fill_parent"> <TextView android:layout_width="fill_parent" android:layout_height="wrap_content" android:text="@string/hello" android:textSize="30dp" android:id="@+id/test_view_example" android:background="@drawable/test_selection"/> <Button android:layout_width="wrap_content" android:layout_height="wrap_content" android:id="@+id/refresh" android:onClick="updateView" android:text="refresh"></Button> </LinearLayout> My Activity code is also very simple. public class TestDrawableStateActivity extends Activity { private final static int[] SELECTED_STATE = { android.R.attr.state_selected }; private final static int[] UNSELECTED_STATE = {}; private TextView textView; /** Called when the activity is first created. */ @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); textView = (TextView) findViewById(R.id.test_view_example); } @Override protected void onResume() { super.onResume(); // Carichiamo la Drawable if(textView.getBackground().setState(SELECTED_STATE)){ textView.invalidate(); } } public void updateView(View view) { if(textView.getBackground().setState(SELECTED_STATE)){ textView.invalidate(); }; } } When Activity starts I try to set the state of my Drawable (the StateListDrawable) with the value SELECTED. It seems all very simple.... but the problem is that the state is not shown. If, later, I click a button and execute the method updateView() the state changes. Where is my problem? Where am I wrong? Thankx a lot Max

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  • MVC3 View For Loop values initialization

    - by Ryan
    So I have a for loop in my View that is supposed to render out the input boxes. Now inside these input boxes I want to put lables that disappear when you click on them. This is all simple. Now it's probably because my brain was wired for php first, and it has been difficult to get it to think in lambdas and object orientation, but I can't figure out how to do this: @{ for (int i = 0; i < 3; i++) { <div class="editor-label grid_2">User</div> Model.Users[i].UserFirstName = "First Name"; Model.Users[i].UserLastName = "Last Name"; Model.Users[i].UserEmailAddress = "Email Address"; <div class="grid_10"> @Html.TextBoxFor(m => Model.Users[i].UserFirstName, new { @class = "user-input" }) @Html.TextBoxFor(m => Model.Users[i].UserLastName, new { @class = "user-input" }) @Html.TextBoxFor(m => Model.Users[i].UserEmailAddress, new { @class = "user-input-long" }) @Html.CheckBoxFor(m => Model.Users[i].IsUserAdmin) <span>&nbsp;admin?</span> </div> <div class="clear"> </div> } } And initialize the values for the users. And you're probably thinking "Of course that won't work. You're going to get a Null Reference Exception", and you would be correct. I might need to initialize them somewhere else and I don't realize it but I'm just not sure. I've tried the [DefaultValue("First Name")] route and that doesn't work. I'm probably thinking about this wrong, but my brain is already shot from trying to figure out how to wire up these events to the controller, so any help would be appreciated!

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  • How to customize android analog clock widget through configuration screen

    - by michJ
    I'm trying to develop my own analog clock widget on the home screen. It's based on the stock ICS analog clock widget, but when added to the homescreen, my widget opens a configuration screen first. On this screen you can choose the color you want the clock to be (through a colorpicker dialog). You also see a preview of the clock in the chosen color on this screen. (See picture). My problem is changing the color of the widget on the home screen to the chosen color (when you hit the apply button). I have three .png files that I use for the dial, hour hand and minute hand. I color them using this code in my widgetconfig class: Drawable dial = getResources().getDrawable(R.drawable.clockbackground); dial.setColorFilter(color, PorterDuff.Mode.MULTIPLY); //hour Drawable hour = getResources().getDrawable(R.drawable.hourhand); hour.setColorFilter(color, PorterDuff.Mode.MULTIPLY); //minute Drawable min = getResources().getDrawable(R.drawable.minutehand); min.setColorFilter(color, PorterDuff.Mode.MULTIPLY); // clock AnalogClock clockpreview = (AnalogClock) findViewById(R.id.ACconfig); clockpreview.setBackgroundDrawable(dial); This works fine because I can find the AnalogClock since it's in the layout xml file of the configuration screen, which I set in the OnCreate() through setContentView(). The problem is that for the clock widget on my screen I have to use RemoteViews. So I tried setting the new background of the clock widget through RemoteViews. But RemoteViews seems too limited to do this. I need something like setTextViewText() but then for the background of my analog clock widget, like for example: RemoteViews views = new RemoteViews(context.getPackageName(), R.layout.clockwidget); views.setAnalogClockBackgroundDrawable(dial); The clock widget background seems sort of unchangeable. How can I recolor my clockwidget on homescreen in widgetconfig class? There must be a way because it seems so easy to do at first... My project consists of the widget config class and clockwidget class, widgetconfig.xml, clockwidget.xml, and widget_info.xml (for appwidgetprovider).

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  • How to retrieve items from a django queryset?

    - by sharataka
    I'm trying to get the video element in a queryset but am having trouble retrieving it. user_channel = Everything.objects.filter(profile = request.user, playlist = 'Channel') print user_channel[0] #returns the first result without error print user_channel[0]['video'] #returns error Models.py: class Everything(models.Model): profile = models.ForeignKey(User) playlist = models.CharField('Playlist', max_length = 2000, null=True, blank=True) platform = models.CharField('Platform', max_length = 2000, null=True, blank=True) video = models.CharField('VideoID', max_length = 2000, null=True, blank=True) video_title = models.CharField('Title of Video', max_length = 2000, null=True, blank=True) def __unicode__(self): return u'%s %s %s %s %s' % (self.profile, self.playlist, self.platform, self.video, self.video_title)

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  • Looking into ASP.Net MVC 4.0 Mobile Development - part 1

    - by nikolaosk
    In this post I will be looking how ASP.Net MVC 4.0 helps us to create web solutions that target mobile devices.We all experience the magic that is the World Wide Web through mobile devices. Millions of people around the world, use tablets and smartphones to view the contents of websites,e-shops and portals.ASP.Net MVC 4.0 includes a new mobile project template and the ability to render a different set of views for different types of devices.There is a new feature that is called browser overriding which allows us to control exactly what a user is going to see from your web application regardless of what type of device he is using.In order to follow along this post you must have Visual Studio 2012 and .Net Framework 4.5 installed in your machine.Download and install VS 2012 using this link.My machine runs on Windows 8 and Visual Studio 2012 works just fine.It will work fine in Windows 7 as well so do not worry if you do not have the latest Microsoft operating system.1) Launch VS 2012 and create a new Web Forms application by going to File - >New Project - > ASP.Net MVC 4 Web Application and then click OKHave a look at the picture below  2) From the available templates select Mobile Application and then click OK.Have a look at the picture below 3) When I run the application I get the mobile view of the page. I would like to show you what a typical ASP.Net MVC 4.0 application looks like. So I will create a new simple ASP.Net MVC 4.0 Web Application. When I run the application I get the normal page view.Have a look at the picture below.On the left is the mobile view and on the right the normal view. As you can see we have more or less the same content in our mobile application (log in,register) compared with the normal ASP.Net MVC 4.0 application but it is optimised for mobile devices. 4) Let me explain how and when the mobile view is selected and finally rendered.There is a feature in MVC 4.0 that is called Display Modes and with this feature the runtime will select a view.If we have 2 views e.g contact.mobile.cshtml and contact.cshtml in our application the Controller at some point will instruct the runtime to select and render a view named contact.The runtime will look at the browser making the request and will determine if it is a mobile browser or a desktop browser. So if there is a request from my IPhone Safari browser for a particular site, if there is a mobile view the MVC 4.0 will select it and render it. If there is not a mobile view, the normal view will be rendered.5) In the  ASP.Net MVC 4.0 (Internet application) I created earlier (not the first project which was a mobile one) I can run it once more and see how it looks on the browser. If I want to view it with a mobile browser I must download one emulator like Opera Mobile.You can download Opera Mobile hereWhen I run the application I get the same view in both the desktop and the mobile browser. That was to be expected. Have a look at the picture below 6) Then I create another version of the _Layout.mobile.cshtml view in the Shared folder.I simply copy and paste the _Layout.cshtml  into the same folder and then rename it to _Layout.mobile.cshtml and then just alter the contents of the _Layout.mobile.cshtml.When I run again the application I get a different view on the desktop browser and a different one on the Opera mobile browser.Have a look at the picture below ?he Controller will instruct the ASP.Net runtime to select and render a view named _Layout.mobile.cshtml when the request will come from a mobile browser.?he runtime knows that a browser is a mobile one through the ASP.Net browser capability provider. Hope it helps!!!

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  • View Generated Source (After AJAX/JavaScript) in C#

    - by Michael La Voie
    Is there a way to view the generated source of a web page (the code after all AJAX calls and JavaScript DOM manipulations have taken place) from a C# application without opening up a browser from the code? Viewing the initial page using a WebRequest or WebClient object works ok, but if the page makes extensive use of JavaScript to alter the DOM on page load, then these don't provide an accurate picture of the page. I have tried using Selenium and Watin UI testing frameworks and they work perfectly, supplying the generated source as it appears after all JavaScript manipulations are completed. Unfortunately, they do this by opening up an actual web browser, which is very slow. I've implemented a selenium server which offloads this work to another machine, but there is still a substantial delay. Is there a .Net library that will load and parse a page (like a browser) and spit out the generated code? Clearly, Google and Yahoo aren't opening up browsers for every page they want to spider (of course they may have more resources than me...). Is there such a library or am I out of luck unless I'm willing to dissect the source code of an open source browser? SOLUTION Well, thank you everyone for you're help. I have a working solution that is about 10X faster then Selenium. Woo! Thanks to this old article from beansoftware I was able to use the System.Windows.Forms.WebBrwoswer control to download the page and parse it, then give em the generated source. Even though the control is in Windows.Forms, you can still run it from Asp.Net (which is what I'm doing), just remember to add System.Window.Forms to your project references. There are two notable things about the code. First, the WebBrowser control is called in a new thread. This is because it must run on a single threaded apartment. Second, the GeneratedSource variable is set in two places. This is not due to an intelligent design decision :) I'm still working on it and will update this answer when I'm done. wb_DocumentCompleted() is called multiple times. First when the initial HTML is downloaded, then again when the first round of JavaScript completes. Unfortunately, the site I'm scraping has 3 different loading stages. 1) Load initial HTML 2) Do first round of JavaScript DOM manipulation 3) pause for half a second then do a second round of JS DOM manipulation. For some reason, the second round isn't cause by the wb_DocumentCompleted() function, but it is always caught when wb.ReadyState == Complete. So why not remove it from wb_DocumentCompleted()? I'm still not sure why it isn't caught there and that's where the beadsoftware article recommended putting it. I'm going to keep looking into it. I just wanted to publish this code so anyone who's interested can use it. Enjoy! using System.Threading; using System.Windows.Forms; public class WebProcessor { private string GeneratedSource{ get; set; } private string URL { get; set; } public string GetGeneratedHTML(string url) { URL = url; Thread t = new Thread(new ThreadStart(WebBrowserThread)); t.SetApartmentState(ApartmentState.STA); t.Start(); t.Join(); return GeneratedSource; } private void WebBrowserThread() { WebBrowser wb = new WebBrowser(); wb.Navigate(URL); wb.DocumentCompleted += new WebBrowserDocumentCompletedEventHandler( wb_DocumentCompleted); while (wb.ReadyState != WebBrowserReadyState.Complete) Application.DoEvents(); //Added this line, because the final HTML takes a while to show up GeneratedSource= wb.Document.Body.InnerHtml; wb.Dispose(); } private void wb_DocumentCompleted(object sender, WebBrowserDocumentCompletedEventArgs e) { WebBrowser wb = (WebBrowser)sender; GeneratedSource= wb.Document.Body.InnerHtml; } }

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  • What causes a WPF ListCollectionView that uses custom sorting to re-sort its items?

    - by Drew Noakes
    Consider this code (type names genericised for the purposes of example): // Bound to ListBox.ItemsSource _items = new ObservableCollection<Item>(); // ...Items are added here ... // Specify custom IComparer for this collection view _itemsView = CollectionViewSource.GetDefaultView(_items) ((ListCollectionView)_itemsView).CustomSort = new ItemComparer(); When I set CustomSort, the collection is sorted as I expect. However I require the data to re-sort itself at runtime in response to the changing of the properties on Item. The Item class derives from INotifyPropertyChanged and I know that the property fires correctly as my data template updates the values on screen, only the sorting logic is not being called. I have also tried raising INotifyPropertyChanged.PropertyChanged passing an empty string, to see if a generic notification would cause the sorting to be initiated. No bananas. EDIT In response to Kent's suggestion I thought I'd point out that sorting the items using this has the same result, namely that the collection sorts once but does not re-sort as the data changes: _itemsView.SortDescriptions.Add( new SortDescription("PropertyName", ListSortDirection.Ascending));

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  • web2py server-side comments

    - by MikeWyatt
    In a web2py view, how do I comment out server-side code? In ASP.NET, I can surround any HTML or code tags with <%-- and --% and that block will not be compiled or sent to the client. Velocity does the same thing with #* and *#. Is there an equivalent in web2py? ASP.NET <div> <p><%=foo.bar%></p> <%-- don't print twice! <p><%=foo.bar%></p> --%> </div> web2py <div> <p><%=foo.bar%></p> ??? don't print twice! <p><%=foo.bar%></p> ??? </div>

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  • Zend Framework: how to remove rendered views in the controller?

    - by takpar
    i want to render one of these sets of views: head body-$id1 foot OR head body-$id2 foot which set exsists. i do it like this: try { $this->render("head"); $this->render("body-$id1"); $this->render("foot"); } catch (Exception $e) { $this->render("head"); $this->render("body-$id2"); $this->render("foot"); } but it causes the head view be rendered twice if body-$id1 does not exists. do you have a better solution? in another saying, may i check the existance of body-$id1 before rendering it?

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  • In MVC framworks (such as Ruby on Rails), does usually Model spell as singular and controller and vi

    - by Jian Lin
    I usually see Ruby on Rails books using script/generate model Story name:string link:string which is a singular Story, while when it is controller script/generate controller Stories index then the Story now is Stories, which is plural. Is this a standard on Ruby on Rails? Is it true in other MVC frameworks too, like CakePHP, Symfony, Django, or TurboGears? I see that in the book Rails Space, the controller is also called User, which is the same as the model name, and it is the only exception I see. Update: also, when scaffold is done on Ruby on Rails, then automatically, the model is singular and the controller and view are both plural.

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  • General approach for posting business logic status messages to UI?

    - by generalt
    Hello all. I have been struggling with this question for awhile now, and I haven't reached a conclusion. I'm not typically a UI programmer, so forgive the noobishness. I'm writing a typical application with a UI layer (WPF) and a business layer. I want to post status messages to the UI from the business layer (perhaps deep within the business layer), but I don't want the business layer to have any knowledge of the UI. Is there a generally accepted pattern for this? I was thinking to have a message queue of some sort to which the business layer posts status messages, and have the view model of the UI subscribe to that queue and intercept messages from the queue and route them to the UI. Is that a good approach? Is there somewhere else I should start? Thank you.

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  • producing a typewriter-like effect

    - by Tony Ennis
    Android newb here. Please use small words :-) I'd like to simulate typewriter output on my Android. The output being displayed is generated by a game and is somewhat freeform. The effect I want to see individual characters appear at a rate of about 6 characters a second. When a 'carriage return' is seen, I'd like to insert a delay then resume typing on the left. What are some suggestions on views? Would the view of choice for this be a TextView? Even that seems like overkill for this read-only coarsely scrolling output. I saw something on this thread about an AsyncTask. That looks useful. Perhaps my game will write to some manner of buffer, and a subclass of AsyncTask will pull characters out every .15 seconds or so, add them to the TextView, then invalidate() the TextView? Sound like a plan?

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  • Rails: textfield list to array of strings

    - by poseid
    I want to take input from a textfield and turn it into an array of strings. After having submitted the "post", I want to display again the textfield, but with the array showed below. I have a view that would look like: <% form_tag "/list2array" do -%> <%= text_area_tag "mylist" %> <div><%= submit_tag 'save' %></div> <% end -%> <% @myArray.each do |item| %> <%= item %> <% end %> And as a start for the controller: class List2ArrayController < ApplicationController def index end def save @myArray = params[:mylist].split("\r\n") end end However, after the post, I only get an empty textfield without values in the array from the previous POST. Do I need to use the model layer for my experiment? How? Or do I need to modify my controller?

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