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  • what is the best way to analyze user raw query and detect what who want to search

    - by Sadegh
    hi, i am developing a very basic prototype of web search engine and now i want to know what is the best way to analyze user raw query and detect what who want to search. like Google, Bing, Yahoo etc... an example user query is something like this: Google+Maps+"South+Africa"+Brasil+OR+Italy+OR+Spain+-Argentina+Netherland and i want to splite this to a generic list of each term(single) like this: IEnumerable<KeyValuePair<TermType, string>> <TermType.All, "Google"> <TermType.All, "Maps"> <TermType.Exact, "South"> <TermType.Exact, "Africa"> <TermType.Any, "Brazil"> <TermType.Any, "Italy"> <TermType.Any, "Spain"> <TermType.None, "Argentina"> <TermType.None, "Netherland"> i don't want complete code, i want guidance, solution, tips or anything that's help me to write best for anylize user raw query. thanks in advance

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  • Deeply nested subqueries for traversing trees in MySQL

    - by nickf
    I have a table in my database where I store a tree structure using the hybrid Nested Set (MPTT) model (the one which has lft and rght values) and the Adjacency List model (storing parent_id on each node). my_table (id, parent_id, lft, rght, alias) This question doesn't relate to any of the MPTT aspects of the tree but I thought I'd leave it in in case anyone had a good idea about how to leverage that. I want to convert a path of aliases to a specific node. For example: "users.admins.nickf" would find the node with alias "nickf" which is a child of one with alias "admins" which is a child of "users" which is at the root. There is a unique index on (parent_id, alias). I started out by writing the function so it would split the path to its parts, then query the database one by one: SELECT `id` FROM `my_table` WHERE `parent_id` IS NULL AND `alias` = 'users';-- 1 SELECT `id` FROM `my_table` WHERE `parent_id` = 1 AND `alias` = 'admins'; -- 8 SELECT `id` FROM `my_table` WHERE `parent_id` = 8 AND `alias` = 'nickf'; -- 37 But then I realised I could do it with a single query, using a variable amount of nesting: SELECT `id` FROM `my_table` WHERE `parent_id` = ( SELECT `id` FROM `my_table` WHERE `parent_id` = ( SELECT `id` FROM `my_table` WHERE `parent_id` IS NULL AND `alias` = 'users' ) AND `alias` = 'admins' ) AND `alias` = 'nickf'; Since the number of sub-queries is dependent on the number of steps in the path, am I going to run into issues with having too many subqueries? (If there even is such a thing) Are there any better/smarter ways to perform this query?

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  • AJAX help needed

    - by tharindu
    Hi guys.. i have problem in ajax.. im new comer for ajax...:) <script type="text/javascript"> $(document).ready(function() { $("#bcode").focus(); //prevents autocomplete in some browsers $("#bcode").attr('autocomplete', 'off').keyup(function(event) { var name = $("#bcode").val(); $("#status").empty(); if(name.length > 17 ) { selectAll(); $("#status").html('<img align="absmiddle" src="loading.gif" /> Checking availability...').show(); $.ajax({ type: "POST", url: "namecheck.php", data: "bcode="+ name, success: function(msg) { $("#status").html(msg).show(); } }); } else { $("#status").html('').addClass('err').show(); } }); }); //--> </script> i got text box value 'bcode' using '$_POST['bcode']' <input name="bcode" type="text" class="bcode" id="bcode" maxlength="18"; /> also i have menu/list in that form <select name="pallete" class="list_box" id="select"> <option value="P0" selected> </option> <option value="P1">P1</option> <option value="P2">P2</option> <option value="P3">P3</option> <option value="P4">P4</option> <option value="P5">P5</option> </select> How i can access selected item from php file by using '$_POST['pallete']' please help me. Thanks in advance..

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  • Python lists/arrays: disable negative indexing wrap-around

    - by wim
    While I find the negative number wraparound (i.e. A[-2] indexing the second-to-last element) extremely useful in many cases, there are often use cases I come across where it is more of an annoyance than helpful, and I find myself wishing for an alternate syntax to use when I would rather disable that particular behaviour. Here is a canned 2D example below, but I have had the same peeve a few times with other data structures and in other numbers of dimensions. import numpy as np A = np.random.randint(0, 2, (5, 10)) def foo(i, j, r=2): '''sum of neighbours within r steps of A[i,j]''' return A[i-r:i+r+1, j-r:j+r+1].sum() In the slice above I would rather that any negative number to the slice would be treated the same as None is, rather than wrapping to the other end of the array. Because of the wrapping, the otherwise nice implementation above gives incorrect results at boundary conditions and requires some sort of patch like: def ugly_foo(i, j, r=2): def thing(n): return None if n < 0 else n return A[thing(i-r):i+r+1, thing(j-r):j+r+1].sum() I have also tried zero-padding the array or list, but it is still inelegant (requires adjusting the lookup locations indices accordingly) and inefficient (requires copying the array). Am I missing some standard trick or elegant solution for slicing like this? I noticed that python and numpy already handle the case where you specify too large a number nicely - that is, if the index is greater than the shape of the array it behaves the same as if it were None.

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  • Overriding CSS style 'display:none' in javascript

    - by jsarma
    I'm trying to add a checkbox toggle that hides and shows list elements by changing their style display attribute from "none" to "inline", but it's not working. I'm setting the attribute's style to "display:none" in the CSS file. Then I set it to "display:inline" in javascript when someone checks a box. The javascript is successfully changing the element's property to inline, but for some reason the element remains invisible. If I do the opposite, by setting the display to inline in the CSS and overriding it to none in the javascript, it works fine. I don't see why this would work one way but not the other. I'm using chrome. Here is the code. Any feedback is appreciated. CSS file: #tabmenu li[status='disabled'] a, a.active, #disabled { color: #777777; background: #DDDDDD; font: normal 1em Arial; border: 1px solid black; border-radius: inherit; padding: 0px 5px 0px 5px; margin: 0px; text-decoration: none; cursor:hand; display:none; } HTML: <ul id="tabmenu"> <li name='tab' id='tab1' selected='no' status='disabled'></li> </ul> JAVASCRIPT (from command line, or onchange of a checkbox) tab = document.getElementById('tab1'); tab.style.display = 'inline';

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  • Problem with underscore(_) in Collections.binarySearch (Java)

    - by Alex Cheng
    Hi all. Problem: I am using Java Tutorials™ sourcecode for this. This is the source code. I tried this: --following with another section of sorted words-- words.add("count"); words.add("cvs"); words.add("dce"); words.add("depth"); --following with another section of sorted words-- and it works perfectly. However when I use this: --just a section of sorted words-- words.add("count"); words.add("cvs"); words.add("dce_iface"); words.add("dce_opnum"); words.add("dce_stub_data"); words.add("depth"); --following with another section of sorted words-- It does show dce_iface when I type dce, but when I type _ then following with o or s it shows me something else like dce_offset where the offset comes from words.add("fragoffset"); somewhere in the list. What can I do to solve this problem? Thank you in advance.

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  • How to remove duplicate content, which is still indexed, but not linked to anymore?

    - by David
    A bug in the tool, which we use to create search-engine-friendly URLs changed our whole URL-structure overnight, and we only noticed after Google already indexed the page. Now, we have a massive duplicate content issue, causing a harsh drop in rankings. Webmaster Tools shows over 1,000 duplicate title tags, so I don't think, Google understands what is going on. Right URL: abc.com/price/sharp-ah-l13-12000-btu.html Wrong URL: abc.com/item/sharp-l-series-ahl13-12000-btu.html (created by mistake) After that, we ... Changed back all URLs to the "Right URLs" Set up a 301-redirect for all "Wrong URLs" a few days later Now, still a massive amount of pages is in the index twice. As we do not link internally to the "Wrong URLs" anymore, I am not sure, if Google will re-crawl them very soon. What can we do to solve this issue and tell Google, that all the "Wrong URLs" now redirect to the "Right URLs"? Best, David

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  • What's the best way to manage list item sort order with Drag & Drop UI?

    - by Reddy S R
    I have a list of Students that I should display to user on a web page in tabular format. The items are stored in DB along with SortOrder information. On the web page, user can rearrange the list order by dragging and dropping the items to their desired sort order, similar to this post. Below is a screenshot of my test page. In the above example, each row has sort order info attached to it. When I drop John Doe (Student Id 10) above the Student Id 1 row, the list order should now be: 2, 10, 1, 8, 11. What's the optimistic (less resource hungry) way to store and update Sort Order information? My only idea for now is, for every change in the list's sort order, every object's SortOrder value should be updated, which in my opinion is very resource hungry. Just FYI: I might have at most 25 rows in my table.

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  • Is a program linked against an LGPL library in linux still under GPL?

    - by Jonathan Henson
    If I were to write say, an embeded linux video server, how much of the code do I have to offer to someone who requests the source? Do I have to offer the code that directly links against the GPL covered code or do I have to offer all code? For instance, if I use gstreamer, or any other LGPL code, on a linux platform in my program, does all of my code become under GPL simply because somewhere in the chain, the LGPL program had to link agaist GPL code? I guess this is an extension of the question. Can you write a C library that compiles in linux that does not become subject to GPL?

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  • Why do I get this Debug Assertion Failed? Expression: list iterator not dereferenceable [migrated]

    - by Karel
    I'm trying this example in the (translated to dutch) book of Bjarne Stroustrup (C++): #include <vector> #include <list> #include "complex.h" complex ac[200]; std::vector<complex> vc; std::list<complex> l; template<class In, class Out> void Copy(In from, In too_far, Out to) { while(from != too_far) { *to = *from; ++to; ++from; } } void g(std::vector<complex>& vc , std::list<complex>& lc) { Copy(&ac[0], &ac[200], lc.begin()); // generates debug error Copy(lc.begin(), lc.end(), vc.begin()); // also generates debug error } void f() { ac[0] = complex(10,20); g(vc, l); } int main () { f(); } ** Compiling and Linking goes successful (0 errors/warnings)** But at runtime I get this error: Debug Assertion Failed! Program: path to exe file: \program files\ms vs studio 10.0\vc\include\list Line: 207 Expression: list iterator not dereferenceable For information on how your program can cause an assertion failure, see the Visual C++ documentation on asserts. (Press retry to debug the application)

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  • Empty APN list on your Android phone? Restart the phone to fix it

    - by Gopinath
    Today I tried to connect to internet on my Google Galaxy Nexus running on 4.2.2 using Cellular Data connection and it failed. Tried reaching customer care representative to figure out why data connection is not working, but the robots (Interactive Voice Response systems) never allowed me to reach a human. After digging through the settings I found empty list of APN (Access Point Names) is the reason for not able to connect to internet. Not sure what caused APN list to vanish but I tried to create a new one that matches with the settings required for AT & T mobile. To my surprise I found that the newly created APN is also not shown in the APN list. Well there is something wrong with the phone – my APN’s are not shown as well as the newly created one is also not displayed. A simple Google search on this problem shown many forum discussions list and the solution to resolve the issue is to restart the phone. As soon as I restarted my phone the APN list is automatically populated and I’m able to connect to internet on my mobile.

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  • do you still get a bounce in google analytics if all the linked pages/content is loaded dyanmicly?

    - by sam
    Google analytics describes a bounce as a user that visits and leaves before after their first page. But if your site is a one page site, with content loaded dynamicly using javascript you could have a user one your site go through loads of info, text images but would that still count as a bounce ? Or once they click on an a-tag even if it is <a href="#"> can google analytics see that ? (im aware of click tracking in analytics) but i was wandering if google picks up these clicks by default..

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  • Why are some bugs I'm affected by and subscribed to missing in my launchpad bug list?

    - by joschi
    I have a long list of bugs in my launchpad account but some bugs I set to being affected by and being subscribed to are not showing up in that list. Even when I change the options of bugs to show I don't get these bugs.First I thought these were bugs being set to 'wishlist' but some of them are showing up in the list. Does anyone else know that he/she is subscribed to a bug he/she doesn't find in his bug list? And maybe there's also someone who knows how to fix this.

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  • How to determine the end of list has been reached?

    - by Sweta Dwivedi
    I'm trying to animate my object according to a set of recorded values from kinect skeleton stream by saving the (x,y,z) stream from the skeletal data into a list and then set my objects x and y position from the x,y of the list. However, once the list end has been reached it starts to animate again from the start. I don't want that - I just want the model position to keep going in the positive X direction. Is there any way I can check if end of the list has been reached and to just update the model position in x direction? Or is there any other way to continue moving my sprite once the points in the list are over... i dont want it to start animating all the way again.. protected override void Update(GameTime gameTime) { //position += spriteSpeed * (float)gameTime.ElapsedGameTime.TotalSeconds; //// TODO: Add your update logic here using (StreamReader r = new StreamReader(f)) { string line; Viewport view = graphics.GraphicsDevice.Viewport; int maxWidth = view.Width; int maxHeight = view.Height; while((line = r.ReadLine()) != null) { string[] temp = line.Split(','); int x = (int) Math.Floor(((float.Parse(temp[0]) * 0.5f) + 0.5f) * maxWidth); int y = (int) Math.Floor(((float.Parse(temp[1]) * -0.5f) + 0.5f) * maxHeight); motion_2.Add(new Point(x, y)); } } position.X = motion_2[i].X; position.Y = motion_2[i].Y; i++; a_butterfly_up.Update(gameTime); a_butterfly_side.Update(gameTime); G_vidPlayer.Play(mossV); base.Update(gameTime); }

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  • How often do you use data structures (ie Binary Trees, Linked Lists) in your jobs/side projects?

    - by Chris2021
    It seems to me that, for everyday use, more primitive data structures like arrays get the job done just as well as a binary tree would. My question is how common is to use these structures when writing code for projects at work or projects that you pursue in your free time? I understand the better insertion time/deletion time/sorting time for certain structures but would that really matter that much if you were working with a relatively small amount of data?

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  • If I create a link to a folder, how can I get from that linked folder to the "real" folder from within Nautilus?

    - by snowguy
    Say I have a folder several layers down in my documents folder. And I want easy access to it from my desktop. To do that I: Go to the parent folder in Nautilus. Right click on the folder's Icon and choose Make Link Cut / Paste the new "Link to ..." folder onto my desktop. Great. And mostly this works fine for me. But suppose I want to get to that folder's parent. I can of course get there using the original path--what Nautilus calls the "link path" which I can see in the properties of the folder. But that seems harder than it ought to be. How can I click on the folder and go to the link path directly?

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  • How do I remove a malformed line from my sources.list?

    - by eminencejae
    I have unistalled and reinstalled the Ubuntu Software Center as per info I found in a similar thread and I got the same response about line 91 or something like that. I just tried to upload a screen shot but since I'm new it won't allow me to. I also can not figure out how to cut and paste anything so I have to hand type what the error screen says, both when I attempt to open the software center and nothing happens, when I try to enter commands into the terminal to uninstall, reinstall, whatever I get the same following: COULD NOT INTITIALIZE THE PACKAGE INFORMATION An unresolvable problem occured while initializing the package information Please report t:his bug against the 'update-manager' package and include the following error message: 'E: Malformed line 91 in source list/etc/apt/sources.list (dist parse) E: The list of sources could not be read., E: The package list of status file could not be parsed or opened. How do I report bugs? What can be done about this. I have searched and everything everyone says to do leads me back to the same line error message. So, I don't know how to get to line 91 in the source list; to tell you what it says. Sorry, I'm really new to this. That is what I need is to find out how to get there and fix what it says. I would really like to NOT have to re partition my hard drive and start from scratch, so I'm really looking forward to getting this problem solved. I need to be able to install new software.

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  • How to get a list of installed software packages? [closed]

    - by mblaettermann
    Possible Duplicate: How to list all installed packages? I am on a "grown" system. My initial setup was using Ubuntu 9.04. But now with the 12.04 Update I got stuck. My System is freezing or wired errors occour. I want to reinstall my system on a clean partition. How can I get a list of the packages I installed in my system? I want a list with the base packages not all the dependecies, so I can install all packages on my clean install again with the correct (maybe new) dependencies. I other words: I want to retrieve a list of all packages installed with apt-get directly. Not the ones it additionally installs with these packages. Thanks!

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  • Why would you use data structures (ie Binary Trees, Linked Lists) in your jobs/side projects? [closed]

    - by Chris2021
    It seems to me that, for everyday use, more primitive data structures like arrays get the job done just as well as a binary tree would. My question is how common is to use these structures when writing code for projects at work or projects that you pursue in your free time? I understand the better insertion time/deletion time/sorting time for certain structures but would that really matter that much if you were working with a relatively small amount of data?

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  • How can I get a complete list of non-standard repositories in use?

    - by MagicFab
    While doing some support audits I'd like to know what would be the most efficient/compact way to get a list of all extra reporitories being used on a given Ubuntu workstation using command line (not via the GUI tools). So far I am using: diff'ing a standard sources.list file against the workstation's examining files under cat /etc/apt/sources.list.d Any other ideas on how to best go about this ?

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  • Difficult to replicate objects (object Customer) on the list? [migrated]

    - by gandolf
    I wrote a program that does work with files like delete and update, store, and search And all customers But I have a problem with the method is LoadAll Once the data are read from the file and then Deserialize the object becomes But when I want to save the list of objects in the list are repeated. How can I prevent the duplication in this code? var customerStr = File.ReadAllLines (address); The code is written in CustomerDataAccess class DataAccess Layer. Project File The main problem with the method LoadAll Code: public ICollection<Customer> LoadAll() { var alldata = File.ReadAllLines(address); List<Customer> lst = new List<Customer>(); foreach (var s in alldata) { var objCustomer = customerSerializer.Deserialize(s); lst.Add(objCustomer); } return lst; }

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  • Flex list control itemrenderer issue

    - by Jerry
    Hi Guys I am working on a small photo Gallery. I create a xml file and try to link it to my List control with itemrenderer. However, when I tried to save the file, I got access of undefined property data. Here is my code...and thanks a lot! <?xml version="1.0" encoding="utf-8"?> <s:Application xmlns:fx="http://ns.adobe.com/mxml/2009" xmlns:s="library://ns.adobe.com/flex/spark" xmlns:mx="library://ns.adobe.com/flex/mx" minWidth="955" minHeight="600"> <fx:Declarations> <fx:Model id="pictureXML" source="data/pictures.xml"/> <s:ArrayList id="pictureArray" source="{pictureXML.picture}"/> </fx:Declarations> <s:List id="pictureGrid" dataProvider="{pictureArray}" horizontalCenter="0" top="20"> <s:itemRenderer> <fx:Component> <s:HGroup> <mx:Image source="images/big/{data.source}" /> <s:Label text="{data.caption}"/> </s:HGroup> </fx:Component> </s:itemRenderer> </s:List> </s:Application> My xml <?xml version="1.0"?> <album> <picture> <source>city1.jpg </source> <caption>City View 1</caption> </picture> <picture> <source>city2.jpg </source> <caption>City View 2</caption> </picture> <picture> <source>city3.jpg </source> <caption>City View 3</caption> </picture> <picture> <source>city4.jpg </source> <caption>City View 4</caption> </picture> <picture> <source>city5.jpg </source> <caption>City View 5</caption> </picture> <picture> <source>city6.jpg </source> <caption>City View 6</caption> </picture> <picture> <source>city7.jpg </source> <caption>City View 7</caption> </picture> <picture> <source>city8.jpg </source> <caption>City View 8</caption> </picture> <picture> <source>city9.jpg </source> <caption>City View 9</caption> </picture> <picture> <source>city10.jpg </source> <caption>City View 10</caption> </picture> </album> I appreciate any helps!!!

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  • convert the output into an list

    - by prince23
    using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Linq.Expressions; using System.Xml.XPath; using System.Xml.Linq; namespace SampleProgram1 { class Program { static void Main(string[] args) { string xml = @"<people> <person><name>kumar</name><school>fes</school><parent>All</parent></person> <person><name>manju</name><school>fes</school><parent>kumar</parent></person> <person><name>anu</name><school>frank</school><parent>kumar</parent></person> <person><name>anitha</name><school>jss</school><parent>All</parent></person> <person><name>rohit</name><school>frank</school><parent>manju</parent></person> <person><name>anill</name><school>vijaya</school><parent>manju</parent></person> <person><name>vani</name><school>jss</school><parent>kumar</parent></person> <person><name>soumya</name><school>jss</school><parent>kumar</parent></person> <person><name>madhu</name><school>jss</school><parent>rohit</parent></person> <person><name>shiva</name><school>jss</school><parent>rohit</parent></person> <person><name>vanitha</name><school>jss</school><parent>anitha</parent></person> <person><name>anu</name><school>jss</school><parent>anitha</parent></person> </people>"; XDocument document = XDocument.Parse(xml); var people = (from person in document.Descendants("person") select new Person { Name = (string)person.Element("name"), School = (string)person.Element("school"), Parent = (string)person.Element("parent") }).ToList(); var parents = people.Where(p => p.Parent == "All"); Action<Person> findChildren = null; findChildren = person => { List<Person> children = people.Where(p => p.Parent == person.Name).ToList(); person.Children = children; foreach (Person p in children) findChildren(p); }; foreach (Person parent in parents) { findChildren(parent); } Action<Person, int> showChildren = null; showChildren = (person, tabs) => { //Console.WriteLine(new string('\t', tabs) + person.Name); if (person.Children != null) { foreach (Person p in person.Children) showChildren(p, tabs + 1); } }; foreach (Person parent in parents) { showChildren(parent, 0); } // Console.Read(); } } class Person { public string Name { get; set; } public string School { get; set; } public string Parent { get; set; } public List<Person> Children { get; set; } } } this my program where i need to put the output into a list an dthen bind the lsit into gridview can any one help me out in syntax achiveing this one. i am using c# 3.5

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  • CSS: Horizontal, comma-separated list with fixed <li> width

    - by hello
    Hello, I would like to achieve the following structure: [gfhtfg..., kgjrfg..., asd, mrhgf, ] ^-------^ ^-------^ ^-------^ ^-------^ X X X X (X = a fixed length) I've got a <div> with a fixed length, and inside it an horizontal, comma-separated list (ul) of links. The <li> elements should have a fixed width, and so if the links exceed a fixed length an ellipsis will be shown (using the text-overflow property). I know two ways to make a list horizontal. One is using display: inline and the other using the float property. With the first approach, I can't set a fixed width because the CSS specification doesn't allow setting the width of inline elements. The second approach creates a mess :O Setting float on the <a> element, intending to limit the width there, separates it from the commas. There are no browser-compatibility issues, I only have to support WebKit. I included the code I attempted to work with: <!DOCTYPE html> <html lang="en"> <head> <title>a title</title> <style> body { font-family: arial; font-size: 10pt; } div { height: 30px; width: 300px; background: #eee; border: 1px solid #ccc; text-align: center; } ul { margin: 0px; padding: 0px; } ul li:after { content: ","; } ul li:last-child:after { content: ""; } ul li a { text-decoration: none; color: #666; } ul li { margin: 0px; padding: 0px; list-style: none; overflow: hidden; text-overflow: ellipsis; -webkit-text-overflow: ellipsis; /* Inline elements can't have a width (and they shouldn't according to the specification */ display: inline; width: 30px; } </style> </head> <body> <div> <ul> <li><a href="#">a certain link</a></li> <li><a href="#">link</a></li> <li><a href="#">once again</a></li> <li><a href="#">another one</a></li> </ul> </div> </body> </html> Thank you.

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  • Passing a list of files to javac

    - by Robert Menteer
    How can I get the javac task to use an existing fileset? In my build.xml I have created several filesets to be used in multiple places throughout build file. Here is how they have been defined: <fileset dir = "${src}" id = "java.source.all"> <include name = "**/*.java" /> </fileset> <fileset dir = "${src}" id = "java.source.examples"> <include name = "**/Examples/**/*.java" /> </fileset> <fileset dir = "${src}" id = "java.source.tests"> <include name = "**/Tests/*.java" /> </fileset> <fileset dir = "${src}" id = "java.source.project"> <include name = "**/*.java" /> <exclude name = "**/Examples/**/*.java" /> <exclude name = "**/Tests/**/*.java" /> </fileset> I have also used macrodef to compile the java files so the javac task does not need to be repeated multiple times. The macro looks like this: <macrodef name="compile"> <attribute name="sourceref"/> <sequential> <javac srcdir = "${src}" destdir = "${build}" classpathref = "classpath" includeantruntime = "no" debug = "${debug}"> <filelist dir="." files="@{sourceref}" /> <-- email is about this </javac> </sequential> What I'm trying to do is compile only the classes that are needed for specific targets not all the targets in the source tree. And do so without having to specify the files every time. Here are how the targets are defined: <target name = "compile-examples" depends = "init"> <compile sourceref = "${toString:java.source.examples}" /> </target> <target name = "compile-project" depends = "init"> <compile sourceref = "${toString:java.source.project}" /> </target> <target name = "compile-tests" depends = "init"> <compile sourceref = "${toString:java.source.tests}" /> </target> As you can see each target specifies the java files to be compiled as a simi-colon separated list of absolute file names. The only problem with this is that javac does not support filelist. It also does not support fileset, path or pathset. I've tried using but it treats the list as a single file name. Another thing I tried is sending the reference directly (not using toString) and using but include does not have a ref attribute. SO THE QUESTION IS: How do you get the javac task to use a reference to a fileset that was defined in another part of the build file? I'm not interested in solutions that cause me to have multiple javac tasks. Completely re-writting the macro is acceptable. Changes to the targets are also acceptable provided redundant code between targets is kept to a minimum. p.s. Another problem is that fileset wants a comma separated list. I've only done a brief search for a way to convert semi-colons to commas and haven't found a way to do that. p.p.s. Sorry for the yelling but some people are too quick to post responses that don't address the subject.

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