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  • Unable to get data from content in jQuery?

    - by Srikanth Chilukuri
    I have 2 HTML files and 2 js files. In App.html I want to include login.html and need to fetch the data from login.html and need to use in in App. App.html <!DOCTYPE html> <html> <head> <meta charset="ISO-8859-1"> <title>Insert title here</title> <script type="text/javascript" src='js/jquery.js'></script> <script type="text/javascript" src="js/app.js"></script> <script type="text/javascript" src="js/login.js"></script> </head> <body> <div id="content"></div> </body> </html> Login.html <!DOCTYPE html> <html> <head> <meta charset="ISO-8859-1"> <title>Insert title here</title> <script type="text/javascript" src='js/jquery.js'></script> </head> <body> <div> <div data-role="fieldcontain"> <label for="userid" id="luserid" ><strong>UserId : </strong></label> <input type="text" name="userid" id="userid" value="" class="logon" placeholder="Username" required/> </div> <div data-role="fieldcontain"> <label for="password" id="lpassword"><strong>Password :</strong></label> <input type="password" name="password" id="password" class="logon" value="" placeholder="Password" required/> </div> <div class="ui-body"> <fieldset class="ui-grid-a"> <div class="ui-block-a"><a data-role="button" id="loginbtn" data-theme="b">Login</a></div> </fieldset> </div> </div> </body> </html> app.js $(document).ready(function(){ $('#content').load('login.html'); }); login.js $(document).ready(function(){ var userid= $("#userid").val(); var upassword= $("#password").val(); alert(userid); alert(upassword); }); Please help me out on this. Note: I do not want to include the login.js in the Login.html.

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  • How can I separate error_messages from two forms on one page?

    - by itkevin
    I have two forms in one view updating the User Profile. One Form is to Update my name etc. and one is to change my password. Profile Form: - form_for @user, :url => account_path do |f| = f.error_messages ...form fields here... Password Form: - form_for @user, :url => account_path do |pf| = pf.error_messages ...password fields here... As you can see they both point to the same update action in the users controller. If I type in a invalid password both error_messages show me the same error message. How can I output separate error messages per form?

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  • select command in mysql doesnot return any row

    - by jeyshree
    i created a database using the command CREATE TABLE login_table2(user_name VARCHAR(32), first_name VARCHAR(32), last_name VARCHAR(32), password VARCHAR(64)); then i inserted a data using command INSERT INTO login_table2(user_name ,first_name , last_name , password ) VALUES('ramya', 'ramya', 'muthu', 'India'); the data got inserted into the table. then i inserted another set of data using command INSERT INTO login_table2(user_name ,first_name , last_name , password ) VALUES('jeyshree', 'jey', 'shree', 'India'); the data got inserted into the table too. then i gave the command SELECT first_name FROM login_table2; the command displayed all the first_ name in the table. however when i gave the command SELECT password FROM login_table2 WHERE user_name = 'ramya'; it does not fetch anything though the entry exist in the table.mention where i am going wrong.awaiting your reply.

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  • SVN Subversion use explicit cached credentials

    - by Nick
    I am trying to run a SVN command in a script, but the script is launched as a system service that has cached svn username/password credentials. I could always just put the username/password arguments in the command: svn info --username bob --password pass but I'd rather not have my username/password just sitting in a text file. I've discovered that my cached credentails (when run svn normally) end up here: C:\Documents and Settings\bob\Application Data\Subversion\auth\svn.simple\6ef188c2163f1ccc860a690b7ad21a15 Is there any way I could copy this cached credential file to where my script exists and just call that file explicitly?

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  • Parse error in PHP login form

    - by user225269
    I'm trying to have a login form in php. But my current code doesnt work. Here is the form: <form name="form1" method="post" action="loginverify.php"> <td><font size="3">Username:</td> <td></td> <td><input type="text" name="uname" value="" maxlength="15"/><br/></td> <td><font size="3">Password:</td> <td></td> <td><input type="text" name="pword" value="" maxlength="15"/><br/></td> <tr> <td>&nbsp;</td> <td>&nbsp;</td> <td><input type="submit" name="Submit" value="Login" /></td> </form> And the verify.php <?php session_start(); ?> <?php $host="localhost"; $username="root"; $password="nitoryolai123$%^"; $db_name="login"; $tbl="users"; $connection=mysql_connect($host, $username, $password) or die("cannot connect"); mysql_select_db($db_name, $connection) or die("cannot select db"); $user=$_POST['uname'] $pass=$_POST['pword'] $sql="SELECT Username, Password from users where Username='$user' and Password='$pass'"; $result=mysql_query[$sql]; $count=mysql_num_rows($result); if($count==1){ $SESSION['Username']=$user; echo"<a href='searchmain.php'> CONTINUE</a>"; } else{ echo"wrong username or password"; echo"<a href='loginform.php'>Back</a>"; } ?> Is there something wrong with my code. I get this parse error at line 15, which is this: $pass=$_POST['pword'] But when I try to remove it.It goes to line 16 or line 17 again. What do I do

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  • Convert SQL Server Varbinary field to MYSQL, keeping data intact

    - by Mike Sheridan
    I was given the daunting task of converting a ASP website to PHP and SQL Server to MySQL, and I ran into an issue that hopefully somebody can help I have a user table which has a password field with datatype Varbinary(128), are using pwdencrypt to encrypt the password. Is there a way to transfer that over to MySQL, and somehow i need to be able to keep the password intact... how can i go about that? any pointers would be greatly appreciated!

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  • Query having 2 Where Clause

    - by Harsha M V
    i am trying to login and want to validate username and password against the records in the database. I am not sure how to pass two Where clause public Boolean login(String username, String password) throws SQLException { Cursor mCursor = db.query(TABLE_USERS, new String[] { ID, KEY_NAME, KEY_USERNAME}, KEY_USERNAME + "=" + "'"+username+"'", KEY_PASSWORD + "=" + "'"+password+"'", null, null, null, null, null); if (mCursor.moveToFirst()) { return true; } return false; } Am getting a Syntax Error.

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  • Programmatically setup a PEAP connection in Windows Mobile

    - by tomlog
    I have been working on this for a few days and this is doing my head in: Our application is built using the .NET Compact Framework 2.0 and running on Windows Mobile 5 & 6 devices. We can set the WLAN connection of the device programmatically using the Wireless Zero Config functions (described here: msdn.microsoft.com/en-us/library/ms894771.aspx), most notably the WZCSetInterface function which we pinvoke from our application. This works fine for WEP and WPA-PSK connections. In a recent effort to add support for WPA2 networks we decided to modify the code. We have successfully added support for WPA2 which uses a certificate for the 802.1x authentication by setting the correct registry settings before calling WZCSetInterface. Now we want to do the same for WPA2 using PEAP (MS-CHAPv2) authentication. When manually creating such a connection in Windows Mobile the user will be prompted to enter the domain/user/password details. In our application we will have those details stored locally and want to do this all programmatically without any user intervention. So I thought going along the same route as the certificate authentication, setting the correct registry entries before calling WZCSetInterface. The registry settings we set are: \HKCU\Comm\EAP\Config\[ssid name] Enable8021x = 1 (DWORD) LastAuthSuccessful = 1 (DWORD) EapTypeId = 25 (DWORD) Identity = "domain\username" (string) Password = binary blob containing the password that is encrypted using the CryptProtectData function (described here: msdn.microsoft.com/en-us/library/ms938309.aspx) But when these settings are set and I call WZCSetInterface with the correct parameters, it still prompts me with the User Logon dialog asking for the domain/username/password. Has anyone got an idea what I need to do to prevent the password dialog from appearing and connect straight away with the settings stored in the registry?

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  • All is working except if($_POST['submit']=='Update')

    - by user1319909
    I have a working registration and login system. I am trying to create a form where a user can add product registration info (via mysql update). I can't seem to get the db to actually update the fields. What am I missing here?!? <?php define('INCLUDE_CHECK',true); require 'connect.php'; require 'functions.php'; // Those two files can be included only if INCLUDE_CHECK is defined session_name('tzLogin'); // Starting the session session_set_cookie_params(2*7*24*60*60); // Making the cookie live for 2 weeks session_start(); if($_SESSION['id'] && !isset($_COOKIE['tzRemember']) && !$_SESSION['rememberMe']) { // If you are logged in, but you don't have the tzRemember cookie (browser restart) // and you have not checked the rememberMe checkbox: $_SESSION = array(); session_destroy(); // Destroy the session } if(isset($_GET['logoff'])) { $_SESSION = array(); session_destroy(); header("Location: index_login3.php"); exit; } if($_POST['submit']=='Login') { // Checking whether the Login form has been submitted $err = array(); // Will hold our errors if(!$_POST['username'] || !$_POST['password']) $err[] = 'All the fields must be filled in!'; if(!count($err)) { $_POST['username'] = mysql_real_escape_string($_POST['username']); $_POST['password'] = mysql_real_escape_string($_POST['password']); $_POST['rememberMe'] = (int)$_POST['rememberMe']; // Escaping all input data $row = mysql_fetch_assoc(mysql_query("SELECT * FROM electrix_users WHERE usr='{$_POST['username']}' AND pass='".md5($_POST['password'])."'")); if($row['usr']) { // If everything is OK login $_SESSION['usr']=$row['usr']; $_SESSION['id'] = $row['id']; $_SESSION['email'] = $row['email']; $_SESSION['first'] = $row['first']; $_SESSION['last'] = $row['last']; $_SESSION['address1'] = $row['address1']; $_SESSION['address2'] = $row['address2']; $_SESSION['city'] = $row['city']; $_SESSION['state'] = $row['state']; $_SESSION['zip'] = $row['zip']; $_SESSION['country'] = $row['country']; $_SESSION['product1'] = $row['product1']; $_SESSION['serial1'] = $row['serial1']; $_SESSION['product2'] = $row['product2']; $_SESSION['serial2'] = $row['serial2']; $_SESSION['product3'] = $row['product3']; $_SESSION['serial3'] = $row['serial3']; $_SESSION['rememberMe'] = $_POST['rememberMe']; // Store some data in the session setcookie('tzRemember',$_POST['rememberMe']); } else $err[]='Wrong username and/or password!'; } if($err) $_SESSION['msg']['login-err'] = implode('<br />',$err); // Save the error messages in the session header("Location: index_login3.php"); exit; } else if($_POST['submit']=='Register') { // If the Register form has been submitted $err = array(); if(strlen($_POST['username'])<4 || strlen($_POST['username'])>32) { $err[]='Your username must be between 3 and 32 characters!'; } if(preg_match('/[^a-z0-9\-\_\.]+/i',$_POST['username'])) { $err[]='Your username contains invalid characters!'; } if(!checkEmail($_POST['email'])) { $err[]='Your email is not valid!'; } if(!count($err)) { // If there are no errors $pass = substr(md5($_SERVER['REMOTE_ADDR'].microtime().rand(1,100000)),0,6); // Generate a random password $_POST['email'] = mysql_real_escape_string($_POST['email']); $_POST['username'] = mysql_real_escape_string($_POST['username']); $_POST['first'] = mysql_real_escape_string($_POST['first']); $_POST['last'] = mysql_real_escape_string($_POST['last']); $_POST['address1'] = mysql_real_escape_string($_POST['address1']); $_POST['address2'] = mysql_real_escape_string($_POST['address2']); $_POST['city'] = mysql_real_escape_string($_POST['city']); $_POST['state'] = mysql_real_escape_string($_POST['state']); $_POST['zip'] = mysql_real_escape_string($_POST['zip']); $_POST['country'] = mysql_real_escape_string($_POST['country']); // Escape the input data mysql_query(" INSERT INTO electrix_users(usr,pass,email,first,last,address1,address2,city,state,zip,country,regIP,dt) VALUES( '".$_POST['username']."', '".md5($pass)."', '".$_POST['email']."', '".$_POST['first']."', '".$_POST['last']."', '".$_POST['address1']."', '".$_POST['address2']."', '".$_POST['city']."', '".$_POST['state']."', '".$_POST['zip']."', '".$_POST['country']."', '".$_SERVER['REMOTE_ADDR']."', NOW() )"); if(mysql_affected_rows($link)==1) { send_mail( '[email protected]', $_POST['email'], 'Your New Electrix User Password', 'Thank you for registering at www.electrixpro.com. Your password is: '.$pass); $_SESSION['msg']['reg-success']='We sent you an email with your new password!'; } else $err[]='This username is already taken!'; } if(count($err)) { $_SESSION['msg']['reg-err'] = implode('<br />',$err); } header("Location: index_login3.php"); exit; } if($_POST['submit']=='Update') { { mysql_query(" UPDATE electrix_users(product1,serial1,product2,serial2,product3,serial3) WHERE usr='{$_POST['username']}' VALUES( '".$_POST['product1']."', '".$_POST['serial1']."', '".$_POST['product2']."', '".$_POST['serial2']."', '".$_POST['product3']."', '".$_POST['serial3']."', )"); if(mysql_affected_rows($link)==1) { $_SESSION['msg']['upd-success']='Thank you for registering your Electrix product'; } else $err[]='So Sad!'; } if(count($err)) { $_SESSION['msg']['upd-err'] = implode('<br />',$err); } header("Location: index_login3.php"); exit; } if($_SESSION['msg']) { // The script below shows the sliding panel on page load $script = ' <script type="text/javascript"> $(function(){ $("div#panel").show(); $("#toggle a").toggle(); }); </script>'; } ?>

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  • (PHP)how to hold javascript alertbox on screen

    - by Piyush
    when user changes password I want to show message "Successfully changed!" and when user clicks on OK button of alert box I call logout.php and force user to login with new password.But the problem is PHP header() is not waiting for alertbox and directly goes to logout.php. my code- if($count==1) { $sqlchange="UPDATE $tbl_name SET password='$newpassword' WHERE userId='$myusername'"; unset($result); $result=mysql_query($sqlchange,$link); if($result>0) { ?> <script type="text/javascript"> alert("Your Password has been changed successfully.Please login again."); </script> <?php header("location:logout.php"); exit; } else {....

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  • Why do i get segfault at the end of the application after everything's beed done properly ?

    - by VaioIsBorn
    #include <string.h> #include <stdlib.h> #include <stdio.h> int main(void) { unsigned char *stole; unsigned char pass[] = "m4ak47"; printf("Vnesi password: \t"); scanf("%s", stole); if(strncmp(stole, pass, sizeof(pass)) != 0) { printf("wrong password!\n"); exit(0); } else printf("Password correct\n"); printf("some stuf here...\n\n"); return 0; } This program is working nice, but with one problem - if the password is correct then it DOES do the printing of 'some stuf here...' but it also shows me segmentation fault error at the end. Why ?

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  • validation message display repeatedly

    - by Raam
    hello, in struts2, i create a simple appln.I use client side validation(using ActionClass-Validation.xml),when i get validation error it displays the message well..but a error repeatedly occur it display the old and new message again and again..how can i solve the issue? user name: xxx password error password error password : Button thankss

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  • Creating a session user login php

    - by user2419393
    I'm stuck on how to create a session for a user who logs in. I got the part of checking to make sure the log in information corresponds with the database information, but is stuck on how to take the email address and store into a session. Here is my php code below. <?php include '../View/header.php'; session_start(); require('../model/database.php'); $email = $_POST['username']; $password = $_POST['password']; $sql = "SELECT emailAddress FROM customers WHERE emailAddress ='$email' AND password = '$password'"; $result = mysql_query($sql, $db); if (!$result) { echo "DB Error, could not query the database\n"; echo 'MySQL Error: ' . mysql_error(); exit; } while ($row = mysql_fetch_assoc($result)) { echo $row['emailAddress']; } mysql_free_result($result); ?>

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  • hibernate annotation bi-directional mapping

    - by smithystar
    I'm building a web application using Spring framework and Hibernate with annotation and get stuck with a simple mapping between two entities. I'm trying to create a many-to-many relationship between User and Course. I followed one of the Hibernate tutorials and my implementation is as follows: User class: @Entity @Table(name="USER") public class User { private Long id; private String email; private String password; private Set<Course> courses = new HashSet<Course>(0); @Id @GeneratedValue @Column(name="USER_ID") public Long getId() { return id; } public void setId(Long id) { this.id = id; } @Column(name="USER_EMAIL") public String getEmail() { return email; } public void setEmail(String email) { this.email = email; } @Column(name="USER_PASSWORD") public String getPassword() { return password; } public void setPassword(String password) { this.password = password; } @ManyToMany(cascade = CascadeType.ALL) @JoinTable(name = "USER_COURSE", joinColumns = { @JoinColumn(name = "USER_ID") }, inverseJoinColumns = { @JoinColumn(name = "COURSE_ID") }) public Set<Course> getCourses() { return courses; } public void setCourses(Set<Course> courses) { this.courses = courses; } } Course class: @Entity @Table(name="COURSE") public class Course { private Long id; private String name; @Id @GeneratedValue @Column(name="COURSE_ID") public Long getId() { return id; } public void setId(Long id) { this.id = id; } @Column(name="NAME") public String getName() { return name; } public void setName(String name) { this.name = name; } } The problem is that this implementation only allows me to go one way user.getCourses() What do I need to change, so I can go in both directions? user.getCourses() course.getUsers() Any help would be appreciated.

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  • ios - how do I concatinate strings to create a url?

    - by GeekedOut
    I am trying to make a url by first collecting the parameters, and then in one statement creating the actual url. Here is what I am trying to do: NSString *urlString = @"http://www.some_login_url.com?email=%@&password=%@"; NSString *email = self.email.text; NSString *password = self.password.text; NSString *url_to_send = [NSString stringWithFormat:@"%@%@", urlString , email , password]; So what I wanted to do was replace the @ symbols with the values in the variables, but instead the second variable just got appended to the end of the string. How would I change the last line so I could put the right parameters in their correct spots? Thanks!!

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  • SFTP in Python? (platform independent)

    - by Mark Wilbur
    I'm working on a simple tool that transfers files to a hard-coded location with the password also hard-coded. I'm a python novice, but thanks to ftplib, it was easy: import ftplib info= ('someuser', 'password') #hard-coded def putfile(file, site, dir, user=(), verbose=True): """ upload a file by ftp to a site/directory login hard-coded, binary transfer """ if verbose: print 'Uploading', file local = open(file, 'rb') remote = ftplib.FTP(site) remote.login(*user) remote.cwd(dir) remote.storbinary('STOR ' + file, local, 1024) remote.quit() local.close() if verbose: print 'Upload done.' if __name__ == '__main__': site = 'somewhere.com' #hard-coded dir = './uploads/' #hard-coded import sys, getpass putfile(sys.argv[1], site, dir, user=info) The problem is that I can't find any library that supports sFTP. What's the normal way to do something like this securely? Edit: Thanks to the answers here, I've gotten it working with Paramiko and this was the syntax. import paramiko host = "THEHOST.com" #hard-coded port = 22 transport = paramiko.Transport((host, port)) password = "THEPASSWORD" #hard-coded username = "THEUSERNAME" #hard-coded transport.connect(username = username, password = password) sftp = paramiko.SFTPClient.from_transport(transport) import sys path = './THETARGETDIRECTORY/' + sys.argv[1] #hard-coded localpath = sys.argv[1] sftp.put(localpath, path) sftp.close() transport.close() print 'Upload done.' Thanks again!

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  • [PersistenceException: org.hibernate.exception.SQLGrammarException: could not execute query]

    - by doniyor
    i need help. i am trying to select from database thru sql statement in play framework, but it gives me error, i cannot figure out where the clue is. here is the code: @Transactional public static Users findByUsernameAndPassword(String username, String password){ String hash = DigestUtils.md5Hex(password); Query q = JPA.em().createNativeQuery("select * from USERS where" + "USERNAME=? and PASSWORD=?").setParameter(1, username).setParameter(2, password); List<Users> users = q.getResultList(); if(users.isEmpty()){ return null; } else{ return users.get(0); here is the eror message: [PersistenceException: org.hibernate.exception.SQLGrammarException: could not execute query] can someone help me please! any help i would appreciate! thanks

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  • write to xml file using objective c

    - by Mith
    Hi, ok, I managed to read from xml file using NSXMLParser but now i don't know how to write to xml file. I have a xml file , say <?xml version="1.0" encoding="UTF-8"?> <root> <user id="abcd" password="pass1"/> <user id="efg" password="pass2"/> </root> Now when a new user enters details, I want to store them in a new tag.. lets say like, the id is "hhhh" and password is"pass3" I want to add a new tag with attributes as such <user id="hhhh" password="pass3"/> to the xml file. How should I do this. Please explain in an elaborate way . I am a newbie here. Any links to tutorials or examples will be much helpful. Thanks

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  • how to listen to Enter button when using JOptionPane.showOptionDialog

    - by MemoryLeak
    I use: char[] password = null; JPasswordField jpf = new JPasswordField(30); java.lang.Object [] messageInput = { prompt, jpf }; java.lang.Object [] options = { jpf , "OK", "Cancel"}; int result = JOptionPane.showOptionDialog(null, messageInput, title, JOptionPane.OK_CANCEL_OPTION, JOptionPane.QUESTION_MESSAGE, null, options, ""); JOptionPane.showMessageDialog(null, result); if (result == 1) { password = jpf.getPassword(); } else if(result == JOptionPane.CANCEL_OPTION) { } return password; to get password, but this can not listen to the Enter button. I know if I set the options parameter to null, can make the dialog listen to "enter" button, but if I do that, the dialog don't focus to the textbox when show up. Can someone help me on this ? Thanks in advance !

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  • How to disconnect an existing ruby sequel connection to a database?

    - by MG
    I mean the one which was previously established as DB = Sequel.sqlite('my_blog.db') or DB = Sequel.connect('postgres://user:password@localhost/my_db') or DB = Sequel.postgres('my_db', :user => 'user', :password => 'password', :host => 'localhost') or etcetera. The Sequel::Database class has no public instance method called "disconnect" or so though it has "connect" one. Maybe somebody already faced that problem. I would appreciate any idea.

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  • Beginner Android Dev question navigating through intents, getting errors not sure how to fix it. I've tried rearranging and everything even tabbing.

    - by user554786
    /*I created this Sign-In page. I start by declaring variables for username/password & buttons. If user enters "test" as username & "test" as password and hits the login button, its supposed to go to the DrinksTwitter.class activity, else throw error message I created. To me the code and login makes perfect sense. I'm not sure why it wont go to the next activity I want it to go to */ package com.android.drinksonme; import android.app.Activity; import android.content.Intent; import android.os.Bundle; import android.view.View; import android.view.View.OnClickListener; import android.widget.Button; import android.widget.EditText; import android.widget.TextView; public class Screen2 extends Activity { // Declare our Views, so we can access them later private EditText etUsername; private EditText etPassword; private Button btnLogin; private Button btnSignUp; private TextView lblResult; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); // Get the EditText and Button References etUsername = (EditText)findViewById(R.id.username); etPassword = (EditText)findViewById(R.id.password); btnLogin = (Button)findViewById(R.id.login_button); btnSignUp = (Button)findViewById(R.id.signup_button); lblResult = (TextView)findViewById(R.id.result); // Check Login String username = etUsername.getText().toString(); String password = etPassword.getText().toString(); if(username.equals("test") && password.equals("test")){ final Intent i = new Intent(Screen2.this, DrinksTwitter.class); btnLogin.setOnClickListener(new OnClickListener() { public void onClick(View v) { startActivity(i); } // lblResult.setText("Login successful."); else { /* ERROR- Syntax error on token "else", { expected */ lblResult.setText("Invalid username or password."); } } }); final Intent k = new Intent(Screen2.this, SignUp.class); btnSignUp.setOnClickListener(new OnClickListener() { public void onClick(View v) { startActivity(k); } }); /* ERROR- Syntax error, insert "}" to complete Statement*/ } }

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  • Java AD Authentication across Trusted Domains

    - by benjiisnotcool
    I am trying to implement Active Directory authentication in Java which will be ran from a Linux machine. Our AD set-up will consist of multiple servers that share trust relationships with one another so for our test environment we have two domain controllers: test1.ad1.foo.com who trusts test2.ad2.bar.com. Using the code below I can successfully authenticate a user from test1 but not on test2: public class ADDetailsProvider implements ResultSetProvider { private String domain; private String user; private String password; public ADDetailsProvider(String user, String password) { //extract domain name if (user.contains("\\")) { this.user = user.substring((user.lastIndexOf("\\") + 1), user.length()); this.domain = user.substring(0, user.lastIndexOf("\\")); } else { this.user = user; this.domain = ""; } this.password = password; } /* Test from the command line */ public static void main (String[] argv) throws SQLException { ResultSetProvider res = processADLogin(argv[0], argv[1]); ResultSet results = null; res.assignRowValues(results, 0); System.out.println(argv[0] + " " + argv[1]); } public boolean assignRowValues(ResultSet results, int currentRow) throws SQLException { // Only want a single row if (currentRow >= 1) return false; try { ADAuthenticator adAuth = new ADAuthenticator(); LdapContext ldapCtx = adAuth.authenticate(this.domain, this.user, this.password); NamingEnumeration userDetails = adAuth.getUserDetails(ldapCtx, this.user); // Fill the result set (throws SQLException). while (userDetails.hasMoreElements()) { Attribute attr = (Attribute)userDetails.next(); results.updateString(attr.getID(), attr.get().toString()); } results.updateInt("authenticated", 1); return true; } catch (FileNotFoundException fnf) { Logger.getAnonymousLogger().log(Level.WARNING, "Caught File Not Found Exception trying to read cris_authentication.properties"); results.updateInt("authenticated", 0); return false; } catch (IOException ioe) { Logger.getAnonymousLogger().log(Level.WARNING, "Caught IO Excpetion processing login"); results.updateInt("authenticated", 0); return false; } catch (AuthenticationException aex) { Logger.getAnonymousLogger().log(Level.WARNING, "Caught Authentication Exception attempting to bind to LDAP for [{0}]", this.user); results.updateInt("authenticated", 0); return true; } catch (NamingException ne) { Logger.getAnonymousLogger().log(Level.WARNING, "Caught Naming Exception performing user search or LDAP bind for [{0}]", this.user); results.updateInt("authenticated", 0); return true; } } public void close() { // nothing needed here } /** * This method is called via a Postgres function binding to access the * functionality provided by this class. */ public static ResultSetProvider processADLogin(String user, String password) { return new ADDetailsProvider(user, password); } } public class ADAuthenticator { public ADAuthenticator() throws FileNotFoundException, IOException { Properties props = new Properties(); InputStream inStream = this.getClass().getClassLoader(). getResourceAsStream("com/bar/foo/ad/authentication.properties"); props.load(inStream); this.domain = props.getProperty("ldap.domain"); inStream.close(); } public LdapContext authenticate(String domain, String user, String pass) throws AuthenticationException, NamingException, IOException { Hashtable env = new Hashtable(); this.domain = domain; env.put(Context.INITIAL_CONTEXT_FACTORY, com.sun.jndi.ldap.LdapCtxFactory); env.put(Context.PROVIDER_URL, "ldap://" + test1.ad1.foo.com + ":" + 3268); env.put(Context.SECURITY_AUTHENTICATION, simple); env.put(Context.REFERRAL, follow); env.put(Context.SECURITY_PRINCIPAL, (domain + "\\" + user)); env.put(Context.SECURITY_CREDENTIALS, pass); // Bind using specified username and password LdapContext ldapCtx = new InitialLdapContext(env, null); return ldapCtx; } public NamingEnumeration getUserDetails(LdapContext ldapCtx, String user) throws NamingException { // List of attributes to return from LDAP query String returnAttributes[] = {"ou", "sAMAccountName", "givenName", "sn", "memberOf"}; //Create the search controls SearchControls searchCtls = new SearchControls(); searchCtls.setReturningAttributes(returnAttributes); //Specify the search scope searchCtls.setSearchScope(SearchControls.SUBTREE_SCOPE); // Specify the user to search against String searchFilter = "(&(objectClass=*)(sAMAccountName=" + user + "))"; //Perform the search NamingEnumeration answer = ldapCtx.search("dc=dev4,dc=dbt,dc=ukhealth,dc=local", searchFilter, searchCtls); // Only care about the first tuple Attributes userAttributes = ((SearchResult)answer.next()).getAttributes(); if (userAttributes.size() <= 0) throw new NamingException(); return (NamingEnumeration) userAttributes.getAll(); } From what I understand of the trust relationship, if trust1 receives a login attempt for a user in trust2, then it should forward the login attempt on to it and it works this out from the user's domain name. Is this correct or am I missing something or is this not possible using the method above? --EDIT-- The stack trace from the LDAP bind is {java.naming.provider.url=ldap://test1.ad1.foo.com:3268, java.naming.factory.initial=com.sun.jndi.ldap.LdapCtxFactory, java.naming.security.authentication=simple, java.naming.referral=follow} 30-Oct-2012 13:16:02 ADDetailsProvider assignRowValues WARNING: Caught Authentication Exception attempting to bind to LDAP for [trusttest] Auth error is [LDAP: error code 49 - 80090308: LdapErr: DSID-0C0903A9, comment: AcceptSecurityContext error, data 52e, v1db0]

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  • Knowing the user name in a Page

    - by ctacke
    Let's assume the following: I have an IIS web site set up IIS is configured to use Digest authentication I'm running an ASP.NET page The page has a code-behing assembly that overrides Page_Load When a user navigates to that page, I get a security prompt for the username and password. If the username and password are invalid (i.e. incorrect password) is there a way for the called page, in Page_Load to know, or does IIS handle this and return the 401 before the ASP.NET engine ever gets around to resolving the actual Page class that will get executed?

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  • How to detect invalid user input in a Batch File?

    - by user2975367
    I want to use a batch file to ask for a password to continue, i have very simple code that works. @echo off :Begin cls echo. echo Enter Password set /p pass= if %pass%==Password goto Start :Start cls echo What would you like me to do? (Date/Chrome/Lock/Shutdown/Close) set /p task= if %task%==Date goto Task=Date if %task%==Chrome goto Task=Chrome if %task%==Lock goto Task=Lock if %task%==Shutdown goto Task=Shutdown if %task%==Close goto Task=Close I need to detect when the user entered an invalid password, i have spent an hour researching but i found nothing. I'm not advanced in any way so try and keep it very simple like the code above. Please help me.

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  • How to use the values from session variables in jsp pages that got saved using @Scope("session") in the mvc controllers

    - by droidsites
    Doing a web site using spring mvc. I added a SignupController to handle all the sign up related requests. Once user signup I am adding that to a session using @Scope("session"). Below is the SignupController code, SignupController.java @Controller @Scope("session") public class SignupController { @Autowired SignupServiceInter signUpService; private static final Logger logger = Logger.getLogger(SignupController.class); private String sessionUser; @RequestMapping("/SignupService") public ModelAndView signUp(@RequestParam("userid") String userId, @RequestParam("password") String password,@RequestParam("mailid") String emailId){ logger.debug(" userId:"+userId+"::Password::"+password+"::"); String signupResult; try { signUpService.registerUser(userId, password,emailId); sessionUser = userId; //adding the sign up user to the session return new ModelAndView("userHomePage","loginResult","Success"); //Navigate to user Home page if everything goes right } catch (UserExistsException e) { signupResult = e.toString(); return new ModelAndView("signUp","loginResult", signupResult); //Navigate to signUp page back if user does not exist } } } I am using "sessionUser" variable to store the signed up User Id. My understanding is that when I use @Scope("session") for the controller all the instance variables will added to HttpSession. So by that understanding I tried to access this "SessionUser" in userHomePage.jsp as, userHomepage.jsp Welcome to <%=session.getAttribute("sessionUser")%> But it throws null. So my question is how to use the values from session variables in jsp pages that got saved using @Scope("session") in the mvc controllers. Note: My work around is that pass that signed User Id to jsp page through ModelAndView, but it seems passing the value like these among the pages takes me back to managing state among pages using QueryStrings days.

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