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  • DNS Zone file and virtual host question

    - by Jake
    Hi all, I'm trying to set up a virtual host for redmine.SITENAME.com. I've edited the httpd.conf file and now I'm trying to edit my DNS settings. However, I'm not sure exactly what to do. Here's an snippet of what's already in the named.conf file (the file was made by someone else who is unreachable): zone "SITENAME.com" { type master; file "SITENAME.com"; allow-transfer { ip.address.here.00; common-allow-transfer; }; }; I figure if I want to get redmine.SITENAME.com working, I need to copy that entry and just replace SITENAME.com with redmine.SITENAME.com but will that work? I was under the impression I needed a .db file but I don't see any reference to one in the current named.conf file. Any advice would be great and if you need more info to answer the question, don't hesitate to ask.

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  • Identify "Composite Document File"

    - by Steven
    In a folder containing several PowerPoint Presentations and Spreadsheets, I discovered the following file: Name: ppt115.tmp Size: 160 MB Meta: No EXIF or other metadata Type: (as identified by the cygwin / linux program 'file') Composite Document File V2 Document, No summary info Notes: The filename does not correspond to other files in the directory. Neither MS Power Point nor Excel can open the file. MS Word will only attempt to recover text. Please help me identify this file. Is it just a temporary file that I can safely remove?

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  • Default permission for newly-created files/folders using ACLs not respected by commands like "unzip"

    - by Ngoc Pham
    I am having trouble with setting up a system for multiple users accessing the same set of files. I've read tuts and docs around and played with ACLs but haven't succeeded yet. MY SCENARIO: Have multiple users, for example, user1 and user2, which is belong to a group called sharedusers. They must have all WRITE permission to a same set of files and directories, say underlying in /userdata/sharing/. I have the folder's group set to sharedusers and SGID to have all newly created files/dirs inside set to same group. ubuntu@home:/userdata$ ll drwxr-sr-x 2 ubuntu sharedusers 4096 Nov 24 03:51 sharing/ I set ACLs for this directory so I can have permission of sub dirs/files inheritted from its parents. ubuntu@home:/userdata$ setfacl -m group:sharedusers:rwx sharing/ ubuntu@home:/userdata$ setfacl -d -m group:sharedusers:rwx sharing/ Here's what I've got: ubuntu@home:/userdata$ getfacl sharing/ # file: sharing/ # owner: ubuntu # group: sharedusers # flags: -s- user::rwx group::r-x group:sharedusers:rwx mask::rwx other::r-x default:user::rwx default:group::r-x default:group:sharedusers:rwx default:mask::rwx default:other::r-x Seems okay as when I create new folder with new files inside and the permission is correct. ubuntu@home:/userdata/sharing$ mkdir a && cd a ubuntu@home:/userdata/sharing/a$ touch a_test ubuntu@home:/userdata/sharing/a$ getfacl a_test # file: a_test # owner: ubuntu # group: sharedusers user::rw- group::r-x #effective:r-- group:sharedusers:rwx #effective:rw- mask::rw- other::r-- As you can see, the sharedusers group has effective permission rw-. HOWEVER, if I have a zip file, and use unzip -q command to unzip the file inside the folder sharing, the extracted folders don't have group write permisison. Therefore, the users from group sharedusers cannot modify files under those extracted folders. ubuntu@home:/userdata/sharing$ unzip -q Joomla_3.0.2-Stable-Full_Package.zip ubuntu@home:/userdata/sharing$ ll drwxrwsr-x+ 2 ubuntu sharedusers 4096 Nov 24 04:00 a/ drwxr-xr-x+ 10 ubuntu sharedusers 4096 Nov 7 01:52 administrator/ drwxr-xr-x+ 13 ubuntu sharedusers 4096 Nov 7 01:52 components/ You an spot the difference in permissions between folder a (created before) and folder administrator extracted by unzip. And the ACLs of a files inside administrator: ubuntu@home:/userdata/sharing$ getfacl administrator/index.php # file: administrator/index.php # owner: ubuntu # group: ubuntu user::rw- group::r-x #effective:r-- group:sharedusers:rwx #effective:r-- mask::r-- other::r-- It also has ubuntu group, not sharedusers group as expected. Could someone please explain the problem and give me advice? Thank you in advance!

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  • How to troubleshoot if a zip file is valid or if it is big file size to be unzipped ?

    - by mireille raad
    Hello , I am trying to unzip a file with the size of 2GB I am getting the following error : unzip CLTE_C_08.zip Archive: CLTE_C_08.zip End-of-central-directory signature not found. Either this file is not a zipfile, or it constitutes one disk of a multi-part archive. In the latter case the central directory and zipfile comment will be found on the last disk(s) of this archive. unzip: cannot find zipfile directory in one of CLTE_C_08.zip or CLTE_C_08.zip.zip, and cannot find CLTE_C_08.zip.ZIP, period. After some googling, some people say that this error is because the file is too big, others say because file is corrupt, others say that it could be a not unix archive. So my question , how to find out if file is valid archive file on my Centos and what is the command/trick to uncompress big files ( if any ) Thanks in advance :)

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  • Problem opening password encrypted .docx file on Word 2003

    - by molecule
    Hi all, I am having a problem opening a .docx file on my Word 2003. I have installed the Compatibility pack for 2007 but when i try to open this particular file, I receive the error "Word experienced an error trying to open the file. Try these suggestions. 1. Check the file permissions for the document, 2. Make sure there is sufficient free memory and disk space, 3. Open the file with the Text Recovery converter. I do not think it is any of the errors as I am able to open it on a different PC with Word 2003 as well. I also do not have any issues opening any non-password encrypted .docx files. Has anyone experienced the same issue? Most posts on the internet relate to "open and repair" but as mentioned, I am able to open this file on another PC without any problems. Any advice is greatly appreciated. Thanks, George

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  • How to troubleshoot if a zip file is valid or if it is big file size to be unzipped ?

    - by mireille raad
    Hello , I am trying to unzip a file with the size of 2GB I am getting the following error : unzip CLTE_C_08.zip Archive: CLTE_C_08.zip End-of-central-directory signature not found. Either this file is not a zipfile, or it constitutes one disk of a multi-part archive. In the latter case the central directory and zipfile comment will be found on the last disk(s) of this archive. unzip: cannot find zipfile directory in one of CLTE_C_08.zip or CLTE_C_08.zip.zip, and cannot find CLTE_C_08.zip.ZIP, period. After some googling, some people say that this error is because the file is too big, others say because file is corrupt, others say that it could be a not unix archive. So my question , how to find out if file is valid archive file on my Centos and what is the command/trick to uncompress big files ( if any ) Thanks in advance :)

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  • Lotus 8.5 Question Attaching file in mail

    - by Boxdog
    A user has lost the ability to attach files in mail. Drag and still drop works, but not toolbar Attach or Actions / Attach file. I have replaced Design template for mail . Backup and reinstalled Lotus. Using only the users notes.ini user.id & names.nsf. but still the function still does not work. Is there a registry key that may control this function or can it be a corrupt *.ini or *.id file?

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  • Require file for mount and also update the file after mount?

    - by Andy Shinn
    I am trying to make sure a directory exists for a mount and then also update the permissions of that directory after the mount happens. I am receiving the following error: err: Failed to apply catalog: Cannot alias File[pre_eos_mount] to ["/var/tmp/eos"] at /etc/puppet/modules/mymodule/manifests/eos.pp:29; resource ["File", "/var/tmp/eos"] already declared at /etc/puppet/modules/mymodule/manifests/eos.pp:47 I would like to do something like this: file { $eos_mount : ensure = 'directory', mode = '1777', owner = 'root', group = 'root', } mount { $eos_mount : ensure = 'mounted', device = $lv_device, fstype = $fstype, options = 'defaults,noatime,nodiratime', require = File[$eos_mount], notify = File['post_eos'], } file { 'post_eos' : path = $eos_mount, ensure = 'directory', mode = '1777', owner = 'root', group = 'root', } What is a way to ensure permissions of a folder after it has been mounted?

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  • Loading velocity template inside a jar file

    - by Rafael
    I have a project where I want to load a velocity template to complete it with parameters. The whole application is packaged as a jar file. What I initially thought of doing was this: VelocityEngine ve = new VelocityEngine(); URL url = this.getClass().getResource("/templates/"); File file = new File(url.getFile()); ve = new VelocityEngine(); ve.setProperty(RuntimeConstants.RESOURCE_LOADER, "file"); ve.setProperty(RuntimeConstants.FILE_RESOURCE_LOADER_PATH, file.getAbsolutePath()); ve.setProperty(RuntimeConstants.FILE_RESOURCE_LOADER_CACHE, "true"); ve.init(); VelocityContext context = new VelocityContext(); if (properties != null) { stringfyNulls(properties); for (Map.Entry<String, Object> property : properties.entrySet()) { context.put(property.getKey(), property.getValue()); } } final String templatePath = templateName + ".vm"; Template template = ve.getTemplate(templatePath, "UTF-8"); String outFileName = File.createTempFile("p2d_report", ".html").getAbsolutePath(); BufferedWriter writer = new BufferedWriter(new FileWriter(new File(outFileName))); template.merge(context, writer); writer.flush(); writer.close(); And this works fine when I run it in eclipse. However, once I package the program and try to run it using the command line I get an error because the file could not be found. I imagine the problem is in this line: ve.setProperty(RuntimeConstants.FILE_RESOURCE_LOADER_PATH, file.getAbsolutePath()); Because in a jar the absolute file does not exist, since it's inside a zip, but I couldn't yet find a better way to do it. Anyone has any ideas?

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  • Why does first call to java.io.File.createTempFile(String,String,File) take 5 seconds on Citrix?

    - by Ben Roling
    While debugging slow startup of an Eclipse RCP app on a Citrix server, I came to find out that java.io.createTempFile(String,String,File) is taking 5 seconds. It does this only on the first execution and only for certain user accounts. Specifically, I am noticing it Citrix anonymous user accounts. I have not tried many other types of accounts, but this behavior is not exhibited with an administrator account. Also, it does not matter if the user has access to write to the given directory or not. If the user does not have access, the call will take 5 seconds to fail. If they do have access, the call with take 5 seconds to succeed. This is on a Windows 2003 Server. I've tried Sun's 1.6.0_16 and 1.6.0_19 JREs and see the same behavior. I googled a bit expecting this to be some sort of known issue, but didn't find anything. It seems like someone else would have had to have run into this before. The Eclipse Platform uses File.createTempFile() to test various directories to see if they are writeable during initialization and this issue adds 5 seconds to the startup time of our application. I imagine somebody has run into this before and might have some insight. Here is sample code I executed to see that it is indeed this call that is consuming the time. I also tried it with a second call to createTempFile and notice that subsequent calls return nearly instantaneously. public static void main(final String[] args) throws IOException { final File directory = new File(args[0]); final long startTime = System.currentTimeMillis(); File file = null; try { file = File.createTempFile("prefix", "suffix", directory); System.out.println(file.getAbsolutePath()); } finally { System.out.println(System.currentTimeMillis() - startTime); if (file != null) { file.delete(); } } } Sample output of this program is the following: C:\java.exe -jar filetest.jar C:/Temp C:\Temp\prefix8098550723198856667suffix 5093

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  • Rails upload file to ftp server

    - by Bob
    I'm on Rails 2.3.5 and Ruby 1.8.6 and trying to figure out how to let a user upload a file to a FTP server on a different machine than my Rails app. Also my Rails app will be hosted on Heroku which doesn't facilitate the writing of files to the local filesystem. index.html.erb <% form_tag '/ftp/upload', :method => :post, :multipart => true do %> <label for="file">File to Upload</label> <%= file_field_tag "file" %> <%= submit_tag 'Upload' %> <% end %> ftp_controller.rb require 'net/ftp' class FtpController < ApplicationController def upload file = params[:file] ftp = Net::FTP.new('remote-ftp-server') ftp.login(user = "***", passwd = "***") ftp.puttextfile(file.read, File.basename(file.original_filename)) ftp.quit() end def index end end Currently I'm just trying to get the Rails app to work on my Windows laptop. With the above code, I'm getting this error Errno::ENOENT in FtpController#upload No such file or directory -.... followed by a dump of the file contents Anyone knows what's going on?

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  • AIR File.resolvePath won't work anymore

    - by Palleas
    Hi all, I'm having a very strange issue, it looks like my application can't create file anymore. It works w/ directories, but the so-many-times-used resolvePath() methods doesn't. Here is what I do : var databaseFileContent : File = new File(File.desktopDirectory.nativePath + "/testing"); databaseFileContent.createDirectory(); databaseFileContent.resolvePath("test"); (Here I'm trying on desktop but that's the same w/ applicationStorageDirectory) When I execute this, it works only for the "testing" folder which is actually created, but my file isn't. I tried to create another application, doing this : trace(File.desktopDirectory.resolvePath("maiswtf.db").exists); trace(File.applicationStorageDirectory.resolvePath("wtf.db").exists); Both are displaying "false". Am I missing something here? I have another application with this code : var databaseFileContent : File = File.applicationStorageDirectory.resolvePath(File.separator + "sitra.db"); When I run this one, it works perfectly! My file is created at /sitra.db! Any hints? I thinks I'm going mad :/ Thanks!

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  • PHP 5.3.8 startup warning

    - by David
    How do I solve my PHP startup warning: PHP Warning: PHP Startup: Unable to load dynamic library '/usr/lib/php/extensions /no-debug-non-zts-20090626/imap.so' - /usr/lib/php/extensions/no-debug-non-zts-20090626 /imap.so: cannot open shared object file: No such file or directory in Unknown on line 0 PHP Warning: PHP Startup: Unable to load dynamic library '/usr/lib/php/extensions /no-debug-non-zts-20090626/mcrypt.so' - /usr/lib/php/extensions/no-debug-non-zts- 20090626/mcrypt.so: cannot open shared object file: No such file or directory in Unknown on line 0 PHP Warning: PHP Startup: Unable to load dynamic library '/usr/lib/php/extensions /no-debug-non-zts-20090626/memcache.so' - /usr/lib/php/extensions/no-debug-non-zts- 20090626/memcache.so: cannot open shared object file: No such file or directory in Unknown on line 0 PHP Warning: PHP Startup: Unable to load dynamic library '/usr/lib/php/extensions /no-debug-non-zts-20090626/mysql.so' - /usr/lib/php/extensions/no-debug-non-zts- 20090626/mysql.so: cannot open shared object file: No such file or directory in Unknown on line 0 PHP Warning: PHP Startup: Unable to load dynamic library '/usr/lib /php/extensions/no-debug-non-zts-20090626/mysqli.so' - /usr/lib/php/extensions /no-debug-non-zts-20090626/mysqli.so: cannot open shared object file: No such file or directory in Unknown on line 0 PHP Warning: PHP Startup: Unable to load dynamic library '/usr/lib/php/extensions /no-debug-non-zts-20090626/pdo.so' - /usr/lib/php/extensions/no-debug-non-zts-20090626 /pdo.so: cannot open shared object file: No such file or directory in Unknown on line 0 PHP Warning: PHP Startup: Unable to load dynamic library '/usr/lib/php/extensions /no-debug-non-zts-20090626/pdo_mysql.so' - /usr/lib/php/extensions/no-debug-non-zts- 20090626/pdo_mysql.so: cannot open shared object file: No such file or directory in Unknown on line 0 PHP Warning: PHP Startup: Unable to load dynamic library '/usr/lib/php/extensions /no-debug-non-zts-20090626/suhosin.so' - /usr/lib/php/extensions/no-debug-non-zts- 20090626/suhosin.so: cannot open shared object file: No such file or directory in Unknown on line 0 I've many configuration files in my config folder, I don't know where they come from: PHP Deprecated: Comments starting with '#' are deprecated in /etc/php5/conf.d/gd.ini on line 1 in Unknown on line 0 PHP Deprecated: Comments starting with '#' are deprecated in /etc/php5/conf.d/gd.ini on line 2 in Unknown on line 0 PHP Deprecated: Comments starting with '#' are deprecated in /etc/php5/conf.d/imap.ini on line 1 in Unknown on line 0 PHP Deprecated: Comments starting with '#' are deprecated in /etc/php5/conf.d/mcrypt.ini on line 1 in Unknown on line 0 PHP Deprecated: Comments starting with '#' are deprecated in /etc/php5/conf.d /memcache.ini on line 1 in Unknown on line 0 PHP Deprecated: Comments starting with '#' are deprecated in /etc/php5/conf.d /mysql.ini on line 1 in Unknown on line 0 PHP Deprecated: Comments starting with '#' are deprecated in /etc/php5/conf.d /mysqli.ini on line 1 in Unknown on line 0 PHP Deprecated: Comments starting with '#' are deprecated in /etc/php5/conf.d/pdo.ini on line 1 in Unknown on line 0 PHP Deprecated: Comments starting with '#' are deprecated in /etc/php5/conf.d /pdo_mysql.ini on line 1 in Unknown on line 0 PHP Deprecated: Comments starting with '#' are deprecated in /etc/php5/conf.d/xcache.ini on line 1 in Unknown on line 0 PHP Deprecated: Comments starting with '#' are deprecated in /etc/php5/conf.d/xcache.ini on line 9 in Unknown on line 0 Because of the warning I think I don't need them?

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  • Difference between putting variables in header vs putting variables in source

    - by Mohit Deshpande
    Say I declare a header file with a variable: int count; Then in the source file, I want to use count. Do I have to declare it as: extern int count Or can I just use it in my source file? All assuming that I have #include "someheader.h". Or should I just declare it in the source file? What is the difference between putting count in the header file vs the source file? Or does it not matter?

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  • Need help manipulating WAV (RIFF) Files at a byte level

    - by Eric
    I'm writing an an application in C# that will record audio files (*.wav) and automatically tag and name them. Wave files are RIFF files (like AVI) which can contain meta data chunks in addition to the waveform data chunks. So now I'm trying to figure out how to read and write the RIFF meta data to and from recorded wave files. I'm using NAudio for recording the files, and asked on their forums as well on SO for way to read and write RIFF tags. While I received a number of good answers, none of the solutions allowed for reading and writing RIFF chunks as easily as I would like. But more importantly I have very little experience dealing with files at a byte level, and think this could be a good opportunity to learn. So now I want to try writing my own class(es) that can read in a RIFF file and allow meta data to be read, and written from the file. I've used streams in C#, but always with the entire stream at once. So now I'm little lost that I have to consider a file byte by byte. Specifically how would I go about removing or inserting bytes to and from the middle of a file? I've tried reading a file through a FileStream into a byte array (byte[]) as shown in the code below. System.IO.FileStream waveFileStream = System.IO.File.OpenRead(@"C:\sound.wav"); byte[] waveBytes = new byte[waveFileStream.Length]; waveFileStream.Read(waveBytes, 0, waveBytes.Length); And I could see through the Visual Studio debugger that the first four byte are the RIFF header of the file. But arrays are a pain to deal with when performing actions that change their size like inserting or removing values. So I was thinking I could then to the byte[] into a List like this. List<byte> list = waveBytes.ToList<byte>(); Which would make any manipulation of the file byte by byte a whole lot easier, but I'm worried I might be missing something like a class in the System.IO name-space that would make all this even easier. Am I on the right track, or is there a better way to do this? I should also mention that I'm not hugely concerned with performance, and would prefer not to deal with pointers or unsafe code blocks like this guy. If it helps at all here is a good article on the RIFF/WAV file format.

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  • .NET C# Filestream writing to file and reading the bfile

    - by pythonrg7
    I have a web service that checks a dictionary to see if a file exists and then if it does exist it reads the file, otherwise it saves to the file. This is from a web app. I wonder what is the best way to do this because I occasionally get a FileNotFoundException exception if the same file is accessed at the same time. Here's the relevant parts of the code: String signature; signature = "FILE," + value1 + "," + value2 + "," + value3 + "," + value4; // this is going to be the filename string result; MultipleRecordset mrSummary = new MultipleRecordset(); // MultipleRecordset is an object that retrieves data from a sql server database if (mrSummary.existsFile(signature)) { result = mrSummary.retrieveFile(signature); } else { result = mrSummary.getMultipleRecordsets(System.Configuration.ConfigurationManager.ConnectionStrings["MyConnectionString"].ConnectionString.ToString(), value1, value2, value3, value4); mrSummary.saveFile(signature, result); } Here's the code to see if the file already exists: private static Dictionary dict = new Dictionary(); public bool existsFile(string signature) { if (dict.ContainsKey(signature)) { return true; } else { return false; } } Here's what I use to retrieve if it already exists: try { byte[] buffer; FileStream fileStream = new FileStream(@System.Configuration.ConfigurationManager.AppSettings["CACHEPATH"] + filename, FileMode.Open, FileAccess.Read, FileShare.Read); try { int length = 0x8000; // get file length buffer = new byte[length]; // create buffer int count; // actual number of bytes read JSONstring = ""; while ((count = fileStream.Read(buffer, 0, length)) > 0) { JSONstring += System.Text.ASCIIEncoding.ASCII.GetString(buffer, 0, count); } } finally { fileStream.Close(); } } catch (Exception e) { JSONstring = "{\"error\":\"" + e.ToString() + "\"}"; } If the file doesn't previously exist it saves the JSON to the file: try { if (dict.ContainsKey(filename) == false) { dict.Add(filename, true); } else { this.retrieveFile(filename, ipaddress); } } catch { } try { TextWriter tw = new StreamWriter(@System.Configuration.ConfigurationManager.AppSettings["CACHEPATH"] + filename); tw.WriteLine(JSONstring); tw.Close(); } catch { } Here are the details to the exception I sometimes get from running the above code: System.IO.FileNotFoundException: Could not find file 'E:\inetpub\wwwroot\cache\FILE,36,36.25,14.5,14.75'. File name: 'E:\inetpub\wwwroot\cache\FILE,36,36.25,14.5,14.75' at System.IO.__Error.WinIOError(Int32 errorCode, String maybeFullPath) at System.IO.FileStream.Init(String path, FileMode mode, FileAccess access, Int32 rights, Boolean useRights, FileShare share, Int32 bufferSize, FileOptions options, SECURITY_ATTRIBUTES secAttrs, String msgPath, Boolean bFromProxy) at System.IO.FileStream..ctor(String path, FileMode mode, FileAccess access, FileShare share) at com.myname.business.MultipleRecordset.retrieveFile(String filename, String ipaddress)

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  • synchronized block in JSP tag class

    - by Sudhakar
    Hi, I am trying to find answer for the following ,for the past couple of days ,but couldnt find comprehensive answer Problem Statement I have a custom JSP tag class which handles a web form submission ,captures data and write it to same file in the filesystem. As all web applications,this can be triggeredsimultaneosly ,and i fear that multiple threads would be in action handling each of the submission (we all know thats how Servlet works.) CODE synchronized (this){ final String reportFileName = "testReport.csv"; File reportDir = new File( rootCsDirectory, "reports" ); if(!reportDir.isDirectory())reportDir.mkdir(); File reportFile = new File (reportDir, reportFileName); logReport(reportFile,reportContent.toString()); } ISSUE: - A File object can be opened by one thread for writing and at same time another thread might try to access and fail and throw an exception So i thought of synchronizing (on the object ) should solve the issue , but read some where that jsp engine would have pool of jsp tag objects, so i am afraid that synchronized (this) wont work and it should be changed to synchronized (this.getClass())

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  • Error processing Spree sample images - file not recognized by identify command in paperclip geometry.rb:29

    - by purpletonic
    I'm getting an error when I run the Spree sample data. It occurs when Spree tries to load in the product data, specifically the product images. Here's the error I'm getting: * Execute db:load_file loading ruby <GEM DIR>/sample/lib/tasks/../../db/sample/spree/products.rb -- Processing image: ror_tote.jpeg rake aborted! /var/folders/91/63kgbtds2czgp0skw3f8190r0000gn/T/ror_tote.jpeg20121007-21549-2rktq1 is not recognized by the 'identify' command. <GEM DIR>/paperclip-2.7.1/lib/paperclip/geometry.rb:31:in `from_file' <GEM DIR>/spree/core/app/models/spree/image.rb:35:in `find_dimensions' I've made sure ImageMagick is installed correctly, as previously I was having problems with it. Here's the output I'm getting when running the identify command directly. $ identify Version: ImageMagick 6.7.7-6 2012-10-06 Q16 http://www.imagemagick.org Copyright: Copyright (C) 1999-2012 ImageMagick Studio LLC Features: OpenCL ... other usage info omitted ... I also used pry with the pry-debugger and put a breakpoint in geometry.rb inside of Paperclip. Here's what that section of geometry.rb looks like: # Uses ImageMagick to determing the dimensions of a file, passed in as either a # File or path. # NOTE: (race cond) Do not reassign the 'file' variable inside this method as it is likely to be # a Tempfile object, which would be eligible for file deletion when no longer referenced. def self.from_file file file_path = file.respond_to?(:path) ? file.path : file raise(Errors::NotIdentifiedByImageMagickError.new("Cannot find the geometry of a file with a blank name")) if file_path.blank? geometry = begin silence_stream(STDERR) do binding.pry Paperclip.run("identify", "-format %wx%h :file", :file => "#{file_path}[0]") end rescue Cocaine::ExitStatusError "" rescue Cocaine::CommandNotFoundError => e raise Errors::CommandNotFoundError.new("Could not run the `identify` command. Please install ImageMagick.") end parse(geometry) || raise(Errors::NotIdentifiedByImageMagickError.new("#{file_path} is not recognized by the 'identify' command.")) end At the point of my binding.pry statement, the file_path variable is set to the following: file_path => "/var/folders/91/63kgbtds2czgp0skw3f8190r0000gn/T/ror_tote.jpeg20121007-22732-1ctl1g1" I've also double checked that this exists, by opening my finder in this directory, and opened it with preview app; and also that the program can run identify by running %x{identify} in pry, and I receive the same version Version: ImageMagick 6.7.7-6 2012-10-06 Q16 as before. Removing the additional digits (is this a timestamp?) after the file extension and running the Paperclip.run command manually in Pry gives me a different error: Cocaine::ExitStatusError: Command 'identify -format %wx%h :file' returned 1. Expected 0 I've also tried manually updating the Paperclip gem in Spree to 3.0.2 and still get the same error. So, I'm not really sure what else to try. Is there still something incorrect with my ImageMagick setup?

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  • would like to create a .php file that reads an .xml file and delivers xml output from the .xml file

    - by Andy
    I know it sounds weird but I need it for a workaround. So some link in an ActionScript links for a .php file. As I am unable to edit this link in the AS I need some workaround. I have the xml and the .php file needs to output that exact xml code. How can this be done. Ultimately I would like to create a .php script that outputs xml. Where can I find instructions on how to do this? thanks!

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  • Declare variable as exern if initialized in header?

    - by Mohit Deshpande
    Say I declare a header file with a variable: int count; Then in the source file, I want to use count. Do I have to declare it as: extern int count Or can I just use it in my source file? All assuming that I have #include "someheader.h". Or should I just declare it in the source file? What is the difference between putting count in the header file vs the source file? Or does it not matter?

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  • Is there a function that can read a php function post-parsing?

    - by Rob
    I've got a php file echoing hashes from a MySQL database. This is necessary for a remote program I'm using, but at the same time I need my other php script opening and checking it for specified strings POST parsing. If it checks for the string pre-parsing, it'll just get the MySQL query rather than the strings to look for. I'm not sure if any functions do this. Does fopen() read the file prior to parsing? or file_get_contents()? If so, is there a function that'll read the file after the php and mysql code runs? The file with the hashes query and echo is in the same directory as the php file reading it, if that makes a difference. Perhaps fopen reads it post-parse, and I've done something wrong, but at first I was storing the hashes directly in the file, and it was working fine. After I changed it to echo the contents of the MySQL table, it bugged out.

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  • Why Doesn't This Java Code Skip Lines with #?

    - by Nathan
    I'm trying to allow an external .txt file that is read by a Java script be able to have some comments in the beginning of the file so others can easily edit it and add more to it. But if the file contains # (the sign designated for a line that is a comment) it just returns the error that there is a "Format Error in file" (the IOException - so it is getting past that first "IF"...) Can someone help? Here's the portion of the code that deals with commenting lines out of the .txt file being called earlier in the script: while ((line = br.readLine()) != null) { line = line.trim(); if (line.length() < 1 || line.charAt(0) == '#') { // ignore comments continue; } final String[] parts = line.split("="); if (parts.length != 2) { throw new IOException("Format error in file " + JLanguageTool.getDataBroker().getFromRulesDirAsUrl(getFileName()) + ", line: " + line); }

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  • Downloading large file with php

    - by Alessandro
    Hi, I have to write a php script to download potentially large files. The file I'm reporting here works fine most of the times. However, if the client's connection is slow the request ends (with status code 200) in the middle of the downloading, but not always at the very same point, and not at the very same time. I tried to overwrite some php.ini variables (see the first statements) but the problem remains. I don't know if it's relevant but my hosting server is SiteGround, and for simple static file requests, the download works fine also with slow connections. I've found Forced downloading large file with php but I didn't understand mario's answer. I'm new to web programming. So here's my code. <?php ini_set('memory_limit','16M'); ini_set('post_max_size', '30M'); set_time_limit(0); include ('../private/database_connection.php'); $downloadFolder = '../download/'; $fileName = $_POST['file']; $filePath = $downloadFolder . $fileName; if($fileName == NULL) { exit; } ob_start(); session_start(); if(!isset($_SESSION['Username'])) { // or redirect to login (remembering this download request) $_SESSION['previousPage'] = 'download.php?file=' . $fileName; header("Location: login.php"); exit; } if (file_exists($filePath)) { header('Content-Description: File Transfer'); header('Content-Type: application/octet-stream'); //header('Content-Disposition: attachment; filename='.$fileName); header("Content-Disposition: attachment; filename=\"$fileName\""); header('Content-Transfer-Encoding: binary'); header('Expires: 0'); header('Cache-Control: must-revalidate, post-check=0, pre-check=0'); //header('Pragma: public'); header('Content-Length: ' . filesize($filePath)); ob_clean(); flush(); // download // 1 // readfile($filePath); // 2 $file = @fopen($filePath,"rb"); if ($file) { while(!feof($file)) { print(fread($file, 1024*8)); flush(); if (connection_status()!=0) { @fclose($file); die(); } } @fclose($file); } exit; } else { header('HTTP/1.1 404 File not found'); exit; } ?>

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  • OSError: [Error 1] Operation not permitted

    - by user1357576
    I am trying to run a python script which uses a binary file (xFiles.bin.addr_patched) created by a postlinker. However, I am getting this error. File "abc.py", line 74, in ParseCmd shutil.copy(gOptions.inputX, gWorkingXFile) File "/usr/lib/python2.6/shutil.py", line 89, in copy copymode(src, dst) File "/usr/lib/python2.6/shutil.py", line 66, in copymode os.chmod(dst, mode) OSError: [Errno 1] Operation not permitted: 'myPath/xFiles.bin.addr_patched' When I checked the permissions of this xFiles.bin, by ls-l, it shows that -rwxrwxrwx 1 nobody nogroup I presume the error is because this file was created by some other application, the python script I am running does not have access to it. Since I am beginner wrt ubuntu, I don't really know how to fix it. Any suggestions on how to fix this? SOLVED: As one of the answers Suggested : chown username:groupname file name fixes this issue

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