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  • [ScriptMethod(ResponseFormat = ResponseFormat.Json)]

    - by gnomixa
    In ASP.net web service if the above isn't specified , what is the response format by default? Also, if my web service below: [WebMethod()] public List<Sample> GenerateSamples(string[][] data) { ResultsFactory f = new ResultsFactory(data); List<Sample> samples = f.GenerateSamples(); return samples; } returns the list of objects, If I change the response format to JSON, I have to change the return type to string, then how do I access objects in my javascript? Currently I call this web service in my JS such as: $.ajax({ type: "POST", url: "http://localhost/TemplateWebService/Service.asmx/GenerateSamples", data: jsonText, contentType: "application/json; charset=utf-8", dataType: "json", success: function(response) { var samples = (typeof response.d) == 'string' ? eval('(' + response.d + ')') : response.d; if (samples.length > 0) { doSomethingHere(samples); } else { alert("No samples have been generated"); } }, error: function(xhr, status, error) { var msg = JSON.parse(xhr.responseText); alert(msg.Message); } }); What i noticed though, even though everything works perfectly fine, the eval statement never gets executed, which means that the web service always returns a string! So my question is, is [ScriptMethod(ResponseFormat = ResponseFormat.Json)] necessary on the web service definition side? The way things are now, I can use samples array and access each object and its properties as I normally would in any OOP code, which is very convenient, and everything works no problem, but I just wanted to make sure that I am not missing anything in my set up. I took the basics of combining Jquery's ajax with asp.net from Encosia side, and the response type wasn't mentioned there - I read it on another site and am I not sure how vital it is.

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  • SOAP-ERROR: Encoding: object hasn’t ‘website_ids’ property

    - by Shane van Wyk
    i am struggling to get the products listed/called from magneto via SOAP. I am using the following statement please help, tell me what i am doing wrong. I am sending down the username and apikey vi the “LogInSession.Session()” method, it just keeps the connection info. string sessionId = LogInSession.Session(); MagentoSOAPv2.MagentoService ms = new MagentoSOAPv2.MagentoService(); var productList = ms.catalogProductList(sessionId, new MagentoSOAPv2.filters(), storeView: "1"); foreach (var pi in productList) { Response.Write("category_ids" + pi.category_ids + "<br/>"); Response.Write("name" + pi.name + "<br/>"); Response.Write("product_id" + pi.product_id + "<br/>"); Response.Write("set" + pi.set + "<br/>"); Response.Write("sku" + pi.sku + "<br/>"); Response.Write("type" + pi.type + "<br/>"); Response.Write("website_ids" + pi.website_ids + "<br/>"); }

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  • Problem calling Request using RequestBuilder

    - by Tushar Ahirrao
    Hi My Code is String url = "http: gd.geobytes.com/gd?after=-1&variables=GeobytesCountry,GeobytesCity"; RequestBuilder builder = new RequestBuilder(RequestBuilder.GET, URL .encode(url)); try { Request request = builder.sendRequest(null, new RequestCallback() { public void onError(Request request, Throwable exception) { Couldn't connect to server (could be timeout, SOP violation, etc.) } public void onResponseReceived(Request request, Response response) { System.out.println(response.getText() + "Response"); if (200 == response.getStatusCode()) { Window.alert(response.getText()); } else { Window.alert(response.getText()); } } }); } catch (RequestException e) { e.printStackTrace(); } i receive following error com.google.gwt.http.client.RequestPermissionException: The URL http://gd.geobytes.com/gd?after=-1&variables=GeobytesCountry,GeobytesCity is invalid or violates the same-origin security restriction at com.google.gwt.http.client.RequestBuilder.doSend(RequestBuilder.java:378) at com.google.gwt.http.client.RequestBuilder.sendRequest(RequestBuilder.java:254) at com.ip.client.IpAddressTest.onModuleLoad(IpAddressTest.java:46) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25) at java.lang.reflect.Method.invoke(Method.java:597) at com.google.gwt.dev.shell.ModuleSpace.onLoad(ModuleSpace.java:369) at com.google.gwt.dev.shell.OophmSessionHandler.loadModule(OophmSessionHandler.java:185) at com.google.gwt.dev.shell.BrowserChannelServer.processConnection(BrowserChannelServer.java:380) at com.google.gwt.dev.shell.BrowserChannelServer.run(BrowserChannelServer.java:222) at java.lang.Thread.run(Thread.java:619) Caused by: com.google.gwt.http.client.RequestException: (NS_ERROR_DOM_BAD_URI): Access to restricted URI denied

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  • File Uploading In Google Application Engine Using Django

    - by Ayush
    I am using gae with django. I have an project named MusicSite with following url mapping- urls.py from django.conf.urls.defaults import * from MusicSite.views import MainHandler from MusicSite.views import UploadHandler from MusicSite.views import ServeHandler urlpatterns = patterns('',(r'^start/', MainHandler), (r'^upload/', UploadHandler), (r'^/serve/([^/]+)?', ServeHandler), ) There is an application MusicSite inside MusicFun with the following codes- views.py import os import urllib from google.appengine.ext import blobstore from google.appengine.ext import webapp from google.appengine.ext.webapp import blobstore_handlers from google.appengine.ext.webapp import template from google.appengine.ext.webapp.util import run_wsgi_app def MainHandler(request): response=HttpResponse() upload_url = blobstore.create_upload_url('http://localhost: 8000/upload/') response.write('') response.write('' % upload_url) response.write("""Upload File: """) return HttpResponse(response) def UploadHandler(request): upload_files=request.FILES['file'] blob_info = upload_files[0] response.redirect('http://localhost:8000/serve/%s' % blob_info.key()) class ServeHandler(blobstore_handlers.BlobstoreDownloadHandler): def get(self, resource): resource = str(urllib.unquote(resource)) blob_info = blobstore.BlobInfo.get(resource) self.send_blob(blob_info) now whenever a upload a file using /start and click Submit i am taken to a blank page with the following url- localhost:8000/_ah/upload/ahhnb29nbGUtYXBwLWVuZ2luZS1kamFuZ29yGwsSFV9fQmxvYlVwbG9hZFNlc3Npb25fXxgHDA These random alphabets keep varying but the result is same. A blank page after every upload. Somebody please help. The server responses are as below- INFO:root:"GET /start/ HTTP/1.1" 200 - INFO:root:"GET /favicon.ico HTTP/1.1" 404 - INFO:root:Internal redirection to http://localhost:8000/upload/ INFO:root:Upload handler returned 500 ERROR:root:Invalid upload handler response. Only 301, 302 and 303 statuses are permitted and it may not have a content body. INFO:root:"POST /_ah/upload/ ahhnb29nbGUtYXBwLWVuZ2luZS1kamFuZ29yGwsSFV9fQmxvYlVwbG9hZFNlc3Npb25fXxgCDA HTTP/1.1" 500 - INFO:root:"GET /favicon.ico HTTP/1.1" 404 -

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  • ThreadAbortException (WebClient using DownloadFile to grab file from server)

    - by baron
    Hi Everyone, Referencing my Earlier Question, regarding downloading a file from a server and handling exceptions properly. I am positive that I had this solved, then in classic programming fashion, returned days later to frustratingly find it broken :-( Updated code: private static void GoGetIt(HttpContext context) { var directoryInfoOfWhereTheDirectoryFullOfFilesShouldBe = new FileInfo(......); var name = SomeBasicLogicToDecideName(); //if (!directoryInfoOfWhereTheDirectoryFullOfFilesShouldBe.RefreshExists()) //{ // throw new Exception(string.Format("Could not find {0}.", name)); //} var tempDirectory = ""; //Omitted - creates temporary directory try { directoryInfoOfWhereTheDirectoryFullOfFilesShouldBe.CopyAll(tempDirectory); var response = context.Response; response.ContentType = "binary/octet-stream"; response.AddHeader("Content-Disposition", string.Format("attachment;filename={0}.zip", name)); ZipHelper.ZipDirectoryToStream(tempDirectory, response.OutputStream); response.End(); } catch (Exception ex) { Debug.WriteLine(ex.ToString()); context.Response.StatusCode = 404; } finally { tempDirectory.DeleteWithPrejudice(); } } This was working fine, and returning the zip, otherwise if the file didn't exist returning 404. Then on the client side I could handle this: public bool Download() { try { using (var client = new WebClient()) { client.DownloadFile(name, tempFilePath); } } catch (Exception) { fileExists = false; } return fileExists; } But the problem now is two things. 1) I get System.Threading.ThreadAbortException: Thread was being aborted in the server side try-catch block. Usually this was just a file not found exception. I have no idea what or why that new exception is throwing? 2) Now that a different exception is throwing on the server side instead of the file not found, it would seem I can't use this set up for the application, because back on client side, any exception is assumed to be filenotfound. Any help, especially info on why this ThreadAbortException is throwing!?!? greatly appreciated. Cheers

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  • Export the datagrid data to text in asp.net

    - by SRIRAM
    Problem:It will asks there is no assembly reference/namespace for Database Database db = DatabaseFactory.CreateDatabase(); DBCommandWrapper selectCommandWrapper = db.GetStoredProcCommandWrapper("sp_GetLatestArticles"); DataSet ds = db.ExecuteDataSet(selectCommandWrapper); StringBuilder str = new StringBuilder(); for(int i=0;i<=ds.Tables[0].Rows.Count - 1; i++) { for(int j=0;j<=ds.Tables[0].Columns.Count - 1; j++) { str.Append(ds.Tables[0].Rows[i][j].ToString()); } str.Append("<BR>"); } Response.Clear(); Response.AddHeader("content-disposition", "attachment;filename=FileName.txt"); Response.Charset = ""; Response.Cache.SetCacheability(HttpCacheability.NoCache); Response.ContentType = "application/vnd.text"; System.IO.StringWriter stringWrite = new System.IO.StringWriter(); System.Web.UI.HtmlTextWriter htmlWrite = new HtmlTextWriter(stringWrite); Response.Write(str.ToString()); Response.End();

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  • Send HTTP 404 from Application_Error

    - by Dmitriy Nagirnyak
    Hi, First of all, quickly what exactly I want to achieve: translate particular exception into the HTTP 404 so the ASP.NET can handle it further. I am handling exceptions in the ASP.NET (MVC2) this way: protected void Application_Error(object sender, EventArgs e) { var err = Server.GetLastError(); if (err == null) return; err = err.GetBaseException(); var noObject = err as ObjectNotFoundException; if (noObject != null) HandleObjectNotFound(); var handled = noObject != null; if (!handled) Logger.Fatal("Unhandled exception has occured in application.", err); } private void HandleObjectNotFound() { Server.ClearError(); Response.Clear(); // new HttpExcepton(404, "Not Found"); // Throw or not to throw? Response.StatusCode = 404; Response.StatusDescription = "Not Found"; Response.StatusDescription = "Not Found"; Response.Write("The whole HTML body explaining whata 404 is??"); } The problem is that I cannot configure default customErrors to work with it. When it is on then it never redirects to the page specified in customErrors: <error statusCode="404" redirect="404.html"/>. I also tried to raise new HttpExcepton(404, "Not Found") from the handler but then the response code is 200 which I don't understand why. So the questions are: What is the proper way of translating AnException into HTTP 404 response? How does customErrors section work when handling exceptions in Application_Error? Why throwing HttpException(404) renders (blank) page with success (200) status? Thanks, Dmitriy.

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  • Retrieving image from database using Ajax

    - by ama
    I'm trying to read image from database with Ajax, but I could not read the xmlhttp.responseText to the img src. The image is saved as binary data in database and also retrieved as binary data. I'm using Ajax in JSP, because I want to give the user the ability to upload images and I will view the last uploaded image, on mouse over action the Ajax will be activated and get the image back, the problem is in reading the img from the response. This is the Ajax function: function ajaxFunction(path) { if (xmlhttp) { var s = path; xmlhttp.open("GET", s, true); xmlhttp.onreadystatechange = handleServerResponse; xmlhttp.send(null); } } function handleServerResponse() { if (xmlhttp.readyState == 4) { var Image = document.getElementById(Image_Element_Name); document.getElementById(Image_Element_Name).src = "data:" + xmlhttp.responseText; } } I also got exception in the server: 10415315 [TP-Processor1] WARN core.MsgContext - Error sending end packet java.net.SocketException: Broken pipe at java.net.SocketOutputStream.socketWrite0(Native Method) at java.net.SocketOutputStream.socketWrite(SocketOutputStream.java:92) at java.net.SocketOutputStream.write(SocketOutputStream.java:136) at org.apache.jk.common.ChannelSocket.send(ChannelSocket.java:537) at org.apache.jk.common.JkInputStream.endMessage(JkInputStream.java:127) at org.apache.jk.core.MsgContext.action(MsgContext.java:302) at org.apache.coyote.Response.action(Response.java:183) at org.apache.coyote.Response.finish(Response.java:305) at org.apache.catalina.connector.OutputBuffer.close(OutputBuffer.java:281) at org.apache.catalina.connector.Response.finishResponse(Response.java:478) at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:154) at org.apache.jk.server.JkCoyoteHandler.invoke(JkCoyoteHandler.java:200) at org.apache.jk.common.HandlerRequest.invoke(HandlerRequest.java:283) at org.apache.jk.common.ChannelSocket.invoke(ChannelSocket.java:773) at org.apache.jk.common.ChannelSocket.processConnection(ChannelSocket.java:703) at org.apache.jk.common.ChannelSocket$SocketConnection.runIt(ChannelSocket.java:895) at org.apache.tomcat.util.threads.ThreadPool$ControlRunnable.run(ThreadPool.java:685) at java.lang.Thread.run(Thread.java:619) 10415316 [TP-Processor1] WARN common.ChannelSocket - processCallbacks status 2

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  • Translate an exception into 404 from Application_Error

    - by Dmitriy Nagirnyak
    Hi, First of all, quickly what exactly I want to achieve: translate particular exception into the HTTP 404 so the ASP.NET can handle it further. I am handling exceptions in the ASP.NET (MVC2) this way: protected void Application_Error(object sender, EventArgs e) { var err = Server.GetLastError(); if (err == null) return; err = err.GetBaseException(); var noObject = err as ObjectNotFoundException; if (noObject != null) HandleObjectNotFound(); var handled = noObject != null; if (!handled) Logger.Fatal("Unhandled exception has occured in application.", err); } private void HandleObjectNotFound() { Server.ClearError(); Response.Clear(); // new HttpExcepton(404, "Not Found"); // Throw or not to throw? Response.StatusCode = 404; Response.StatusDescription = "Not Found"; Response.StatusDescription = "Not Found"; Response.Write("The whole HTML body explaining whata 404 is??"); } The problem is that I cannot configure default customErrors to work with it. When it is on then it never redirects to the page specified in customErrors: <error statusCode="404" redirect="404.html"/>. I also tried to raise new HttpExcepton(404, "Not Found") from the handler but then the response code is 200 which I don't understand why. So the questions are: What is the proper way of translating AnException into HTTP 404 response? How does customErrors section work when handling exceptions in Application_Error? Why throwing HttpException(404) renders (blank) page with success (200) status? Thanks, Dmitriy.

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  • Validating User Input? C#

    - by Alex
    Hi, in an assignment, I have designed a input validation loop in C#, and I would like it to be able to check for the correct input format. I'm not for sure, but I think my designed loop is not checking the type of input, just what char is entered. I know I could use a try-catch block, but shouldn't you only use exceptions for exceptional situations? This is not an exceptional situation, because I expect that the user would enter an incorrect value. Input validation is not part of my assignment, so the loop is in a homework assignment, but is not part of the homework assignment. Question: Is there a way I could redesign this loop so that it checks for valid input type as well? Code: do { Console.Write("Do you wish to enter another complex number?: (Y or N)"); response = char.Parse(Console.ReadLine()); response = char.ToUpper(response); if (response != 'Y' && response != 'N') Console.WriteLine("You must respond Y or N!"); } while (response != 'Y' && response != 'N'); Thanks!!

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  • DOJO : How do you reinitiate form elements after ajax call ?

    - by Dural
    I'm trying to do a couple of things using Zend Framework & Dojo Toolkit, and any help would be appreciated. Here's the problem: I have a form that is rendered with the Zend Framework form class, which has an ajax radio button selection. Clicking one of these radio buttons will send an ajax request to another controller, which has no layout, just a rendered form. The ajax request will then populate a div with the new form options. Problem is, when I replace the innerHTML of the div with the ajax response, all the form inputs and elements are not inheriting the same Dojo styling and form validation. I was wondering if there is a way to reinitate form elements after an ajax call? I have tried to use the code attached which I found and modified slightly for this example, however it did not work. If I use the line dojo.parser.parse( div ); nothing changes (rg_adress in the example is the ID of a form element that is placed on the DOM). Here is the console.log of rg_address: <input type="text" dojotype="dijit.form.ValidationTextBox" required="1" invalidmessage="The first name of the recipient" value="" name="rg_address" id="rg_address" class="textbox"/> onClick=' dojo.xhrGet( { url: "/transfer/newrecipient/", handleAs: "text", timeout: 10000, // Time in milliseconds // The LOAD function will be called on a successful response. load: function(response, ioArgs) { $("#newRecipient").html(response); $("#newPayMethod").html(""); $("#newPayDetail").html(""); var div = dojo.byId("rg_address"); console.log( div ); dojo.parser.parse( div ); return response; }, // The ERROR function will be called in an error case. error: function(response, ioArgs) { $("#newRecipient").html("Error loading registration form"); $("#newPayMethod").html(""); $("#newPayDetail").html(""); return response; } });' Thanks, Dural

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  • WCF contracts - namespaces and SerializationExceptions

    - by qntmfred
    I am using a third party web service that offers the following calls and responses http://api.athirdparty.com/rest/foo?apikey=1234 <response> <foo>this is a foo</foo> </response> and http://api.athirdparty.com/rest/bar?apikey=1234 <response> <bar>this is a bar</bar> </response> This is the contract and supporting types I wrote [ServiceContract] [XmlSerializerFormat] public interface IFooBarService { [OperationContract] [WebGet( BodyStyle = WebMessageBodyStyle.Bare, ResponseFormat = WebMessageFormat.Xml, UriTemplate = "foo?key={apikey}")] FooResponse GetFoo(string apikey); [OperationContract] [WebGet( BodyStyle = WebMessageBodyStyle.Bare, ResponseFormat = WebMessageFormat.Xml, UriTemplate = "bar?key={apikey}")] BarResponse GetBar(string apikey); } [XmlRoot("response")] public class FooResponse { [XmlElement("foo")] public string Foo { get; set; } } [XmlRoot("response")] public class BarResponse { [XmlElement("bar")] public string Bar { get; set; } } and then my client looks like this static void Main(string[] args) { using (WebChannelFactory<IFooBarService> cf = new WebChannelFactory<IFooBarService>("thirdparty")) { var channel = cf.CreateChannel(); FooResponse result = channel.GetFoo("1234"); } } When I run this I get the following exception Unable to deserialize XML body with root name 'response' and root namespace '' (for operation 'GetFoo' and contract ('IFooBarService', 'http://tempuri.org/')) using XmlSerializer. Ensure that the type corresponding to the XML is added to the known types collection of the service. If I comment out the GetBar operation from IFooBarService, it works fine. I know I'm missing an important concept here - just don't know quite what to look for. What is the proper way to construct my contract types, so that they can be properly deserialized?

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  • Android: Unable to make httprequest behind firewall

    - by Yang
    The standard getUrlContent works welll when there is no firewall. But I got exceptions when I try to do it behind a firewall. I've tried to set "http proxy server" in AVD manager, but it didn't work. Any idea how to correctly set it up? protected static synchronized String getUrlContent(String url) throws ApiException { if(url.equals("try")){ return "thanks"; } if (sUserAgent == null) { throw new ApiException("User-Agent string must be prepared"); } // Create client and set our specific user-agent string HttpClient client = new DefaultHttpClient(); HttpGet request = new HttpGet(url); request.setHeader("User-Agent", sUserAgent); try { HttpResponse response = client.execute(request); // Check if server response is valid StatusLine status = response.getStatusLine(); if (status.getStatusCode() != HTTP_STATUS_OK) { throw new ApiException("Invalid response from server: " + status.toString()); } // Pull content stream from response HttpEntity entity = response.getEntity(); InputStream inputStream = entity.getContent(); ByteArrayOutputStream content = new ByteArrayOutputStream(); // Read response into a buffered stream int readBytes = 0; while ((readBytes = inputStream.read(sBuffer)) != -1) { content.write(sBuffer, 0, readBytes); } // Return result from buffered stream return new String(content.toByteArray()); } catch (IOException e) { throw new ApiException("Problem communicating with API", e); } }

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  • How can I embed images in an ASP.NET Generated Word File

    - by Nikos Steiakakis
    Hi everyone! I have a quite common problem, as I saw in the various user groups but could not find a suitable answer. What I want to do is generate an ASP.NET page in my website which will have the option of being exported into Microsoft Word .doc format. The method I have used is this: Response.Clear(); Response.AddHeader("content-disposition", "attachment;filename=Test.doc"); Response.Charset = ""; Response.Cache.SetCacheability(HttpCacheability.NoCache); Response.ContentType = "application/msword"; StringWriter sw = new StringWriter(); HtmlTextWriter htmlWrite = new HtmlTextWriter(sw); Page.RenderControl(htmlWrite); Response.Write(sw.ToString()); Response.End(); However this eventhough it generates a word doc, the images are note embedded in the document, rather they are placed as links. I have looked for a way to do this, but have not found something that actually worked. I would appreciate any help I can get, since this as "last minute" requirement (talk about typical) Thanks

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  • HttpWebRequest.BeginGetResponse() does not return the second time

    - by evilfred
    Hi, I make one HttpWebRequest and call GetResponse() on it to get a synchronous response. Then after processing that response, I make a new HttpWebRequest and call BeginGetResponse() on it. Since BeginGetResponse() is an asynchronous call I expect it to return right away, but it doesn't! Why not? Here is some stripped down sample code: HttpWebRequest request = RequestFactory.MakeSessionCreationRequest(); try { // Get the response from the server. using (WebResponse response = request.GetResponse()) { using (Stream responseStream = response.GetResponseStream()) { ; // Get the response. } } ; // Process the response. } catch (WebException e) { Logger("Caught WebException when attempting to connect: " + e); return; } // Make the second, asynchronous request. HttpWebRequest msgRequest = RequestFactory.MakeMessageRequest(); IAsyncResult result = msgRequest.BeginGetResponse( new AsyncCallback(HandleResponse), msgRequest); // PROBLEM: This line is never reached!!! Logger("Message send started");

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  • code to ping websites works sometimes ...

    - by trustfundbaby
    I'm testing out a piece of code to ping a bunch of websites I own on a regular basis, to make sure they're up. I'm using rails and so far I have this hideous test action that I'm using to try it out (see below). The problem though, is that sometimes it works, and other times it won't ... sometimes it runs through the code just fine, other times, it seems to completely ignore the begin/rescue block ... a. I need help figuring out what the problem is b. And refactoring this to make it look respectable. Your help is much appreciated. require 'net/http' require 'uri' def ping @sites = NewsSource.all @sites.each do |site| if site.uri and !site.uri.empty? uri = URI.parse(site.uri) response = nil path = uri.path.blank? ? '/' : uri.path path = uri.query.blank? ? path : "#{path}?#{uri.query}" begin Net::HTTP.start(uri.host, uri.port) {|http| http.open_timeout = 30 http.read_timeout = 30 response = http.head(path) } if response.code.eql?('200') or response.code.eql?('301') or response.code.eql?('302') site.up = true else site.up = false end site.up_check_msg = response.message site.up_check_code = response.code rescue Errno::EBADF rescue Timeout::Error site.up = false site.up_check_msg = 'timeout' site.up_check_code = '408' end site.up_check_time = 0.seconds.ago site.save end end end

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  • how to use cookies in HttpsURLConnection in android.

    - by sajjoo
    hello guys, actually i am new in Android and now i have to add the cookies in my project. i am using HttpsUrlConnection. here is how i am making request and getting response from a webserver and now i have to add cookies aswell. URL url = new URL(strUrl); HttpsURLConnection connection = (HttpsURLConnection) url.openConnection(); connection.setRequestMethod("POST"); connection.setRequestProperty("Content-Type", "application/soap+xml; charset=utf-8"); connection.setRequestProperty("Content-Length", ""+ Integer.toString(request.getBytes().length)); connection.setUseCaches (false); connection.setDoInput(true); connection.setDoOutput(true); // send Request... DataOutputStream wr = new DataOutputStream (connection.getOutputStream()); wr.writeBytes (request); wr.flush (); wr.close (); //Get response... DataInputStream is = new DataInputStream(connection.getInputStream()); String line; StringBuffer response = new StringBuffer(); while((line = is.readLine()) != null) { response.append(line); } is.close(); FileLogger.writeFile("Soap.txt", "RESPONSE: " + methodName + "\n" + response); HashMap<String, String> parameters = null; try { parameters = SoapRequest.responseParser(response.toString(), methodName); } catch (ParserConfigurationException e) { // TODO Auto-generated catch block e.printStackTrace(); } catch (SAXException e) { // TODO Auto-generated catch block e.printStackTrace(); } return parameters; any help will be appreciative, thanks

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  • unable to get values from JSON converted from XML

    - by Dkong
    I have passed some JSON to my page via a webservice. I used JSON.NET to convert XML to JSON. The JSON output looks ok to me, but I am unable to access some of the items in the response. I am not sure why it is not working. I am using jQuery to read the response and make the webservice call. Even when I try to read the length of the array it says 'undefined' function GetFeed(){ document.getElementById("marq").innerHTML = ''; $.ajax({ type: "POST", url: "ticker.asmx/GetStockTicker", data: "{}", contentType: "application/json; charset=utf-8", dataType: "json", success: function(response) { var obj = (typeof response.d) == 'string' ? eval('(' + response.d + ')') : response.d; for (var i = 0; i < obj.length; i++) { $('#marq').html(obj[i].person); } } }); } This is a copy and paste of my response as it appeared in firebug: {"d":"{\"?xml\":{\"@version\":\"1.0\",\"@standalone\":\"no\"},\"root\":{\"person\":[{\"@id\":\"1\",\"name\":\"Alan\",\"url\":\"http://www.google.com\"},{\"@id\":\"2\",\"name\":\"Louis\",\"url\":\"http://www.yahoo.com\"}]}}"}

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  • Sample twitter application

    - by Jack
    I have installed WAMP and running PHP scripts on localhost. I have enabled cURL. Here is my code. <?php function updateTwitter($status) { // Twitter login information $username = 'xxxxx'; $password = 'xxxxx'; // The url of the update function $url = 'http://twitter.com/statuses/update.xml'; // Arguments we are posting to Twitter $postargs = 'status='.urlencode($status); // Will store the response we get from Twitter $responseInfo=array(); // Initialize CURL $ch = curl_init($url); // Tell CURL we are doing a POST curl_setopt($ch, CURLOPT_PROXY,"localhost:80"); curl_setopt ($ch, CURLOPT_POST, true); // Give CURL the arguments in the POST curl_setopt ($ch, CURLOPT_POSTFIELDS, $postargs); // Set the username and password in the CURL call curl_setopt($ch, CURLOPT_USERPWD, $username.':'.$password); // Set some cur flags (not too important) curl_setopt($ch, CURLOPT_VERBOSE, 1); curl_setopt($ch, CURLOPT_NOBODY, 0); curl_setopt($ch, CURLOPT_HEADER, 0); curl_setopt($ch, CURLOPT_FOLLOWLOCATION,1); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); // execute the CURL call $response = curl_exec($ch); if($response === false) { echo 'Curl error: ' . curl_error($ch); } else { echo 'Operation completed without any errors<br/>'; } // Get information about the response $responseInfo=curl_getinfo($ch); // Close the CURL connection curl_close($ch); // Make sure we received a response from Twitter if(intval($responseInfo['http_code'])==200){ // Display the response from Twitter echo $response; }else{ // Something went wrong echo "Error: " . $responseInfo['http_code']; } curl_close($ch); } updateTwitter("Just finished a sweet tutorial on http://brandontreb.com"); ?> Here's my output Operation completed without any errors Error: 404 Here's what error 404 means 404 Not Found: The URI requested is invalid or the resource requested, such as a user, does not exists. Please help.

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  • Read quicktime movie from servlet in a webpage?

    - by khue
    Hi, I have a servlet that construct response to a media file request by reading the file from server: File uploadFile = new File("C:\\TEMP\\movie.mov"); FileInputStream in = new FileInputStream(uploadFile); Then write that stream to the response stream. My question is how do I play the media file in the webpage using embed or object tag to read the media stream from the response? Here is my code in the servlet: public void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { request.getParameter("location"); uploadFile(response); } private void uploadFile(HttpServletResponse response) { File transferFile = new File("C:/TEMP/captured.mov"); FileInputStream in = null; try { in = new FileInputStream(transferFile); } catch (FileNotFoundException e) { System.out.println("File not found"); } try { System.out.println("in byes i s" + in.available()); } catch (IOException e) { } DataOutputStream responseStream = null; try { responseStream = new DataOutputStream(response.getOutputStream()); } catch (IOException e) { System.out.println("Io exception"); } try { Util.copyStream(in, responseStream); } catch (CopyStreamException e) { System.out.println("copy Stream exception"); } try { responseStream.flush(); } catch (IOException e) { } try { responseStream.close(); } catch (IOException e) { } } And here is html page as Ryan suggested: <embed SRC="http://localhost:7101/movies/transferservlet" WIDTH=100 HEIGHT=196 AUTOPLAY=true CONTROLLER=true LOOP=false PLUGINSPAGE="http://www.apple.com/quicktime/"> Any ideas?

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  • Export the datagrid data to text in asp.net+c#.net

    - by SRIRAM
    Problem:It will asks there is no assembly reference/namespace for Database Database db = DatabaseFactory.CreateDatabase(); DBCommandWrapper selectCommandWrapper = db.GetStoredProcCommandWrapper("sp_GetLatestArticles"); DataSet ds = db.ExecuteDataSet(selectCommandWrapper); StringBuilder str = new StringBuilder(); for(int i=0;i<=ds.Tables[0].Rows.Count - 1; i++) { for(int j=0;j<=ds.Tables[0].Columns.Count - 1; j++) { str.Append(ds.Tables[0].Rows[i][j].ToString()); } str.Append("<BR>"); } Response.Clear(); Response.AddHeader("content-disposition", "attachment;filename=FileName.txt"); Response.Charset = ""; Response.Cache.SetCacheability(HttpCacheability.NoCache); Response.ContentType = "application/vnd.text"; System.IO.StringWriter stringWrite = new System.IO.StringWriter(); System.Web.UI.HtmlTextWriter htmlWrite = new HtmlTextWriter(stringWrite); Response.Write(str.ToString()); Response.End();

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  • Servlet that starts a thread only once for every visitor

    - by user858749
    Hey I want to implement a Java Servlet that starts a thread only once for every single user. Even on refresh it should not start again. My last approach brought me some trouble so no code^^. Any Suggestions for the layout of the servlet? public class LoaderServlet extends HttpServlet { // The thread to load the needed information private LoaderThread loader; // The last.fm account private String lfmaccount; public LoaderServlet() { super(); lfmaccount = ""; } @Override protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { if (loader != null) { response.setContentType("text/plain"); response.setHeader("Cache-Control", "no-cache"); PrintWriter out = response.getWriter(); out.write(loader.getStatus()); out.flush(); out.close(); } else { loader = new LoaderThread(lfmaccount); loader.start(); request.getRequestDispatcher("WEB-INF/pages/loader.jsp").forward( request, response); } } @Override protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { if (lfmaccount.isEmpty()) { lfmaccount = request.getSession().getAttribute("lfmUser") .toString(); } request.getRequestDispatcher("WEB-INF/pages/loader.jsp").forward( request, response); } } The jsp uses ajax to regularly post to the servlet and get the status. The thread just runs like 3 minutes, crawling some last.fm data.

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  • XML parsing problem

    - by Albinoswordfish
    I'm having this strange XML parsing problem. I have this XML string I'm trying to parse <?xml version="1.0"?> <response status="success"> <lot>32342</lot> </response> I'm using XPath with Java in order to do this. I'm using the Xpath expression "/response/@status" to find the text "success". However whenever I evaluate this expression I get an empty string. However I am able to successfully parse this string using "/response/@type" <?xml version="1.0"?> <response type="success"> <lot>32342</lot> </response> So why would simply changing the name of the attribute change the return string to nothing? is = new InputSource(testWOcreateStrGood); xPathexpressionSuccess = xPath.compile("/response/@status"); responseStr = xPathexpressionSuccess.evaluate(is); reponseStr is the string I posted earlier with the "status" attribute

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  • Android Bluetooth syncing

    - by Darryl
    I am connecting to a bluetooth enabled camera, and I am able to connect using the methods found in the BluetoothChat example. I need to send commands to the camera. The issue is that I also need to get a response BACK from the camera after I send the command in the first place. So basically I need to write a command and receive a response. However, the thing is that the commands sometimes don't generate a response. Even the documentation on the camera says that you "have to send the sync command as many as 25 times on power up before you will get a response." So I cannot just write a command and wait for a response, as the "read" function blocks the thread. If I have the read function in another thread, like the bluetooth chat example, there seems to be sync issues, i.e., if I issue a write command, how can I know that it is reading if that is happening in another thread? I did set a global variable to check for, but this seems "iffy" at best. So basically I need to write to the bluetooth and then attempt to read from it. However, I need to let that read timeout and if I haven't received a response, I need to write again until I get a response (or until it's tried a set number of times). I don't need the read function to be going all the time in the background. Any ideas? Thanks in advance for your time.

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  • Mechanize form submit not going to the correct response page, no errors as to why. Something I'm doing?

    - by Zack Shapiro
    I threw this all in one controller for testing purposes. My code fills out the form correctly for adding a new address to your Amazon account. There are two buttons that submit this form, one takes you to add a new address which is what I don't want, and the other is just a Save & Continue input/image. When I submit the form via that button, as I do below, the form is still on the page, filled out as I have with my code. Inspecting the page titles, they're the same. There are no discernible errors that Mechanize or Amazon spit back. Any ideas? class AmazonCrawler def initialize @agent = Mechanize.new do |agent| agent.user_agent_alias = 'Mac Safari' agent.follow_meta_refresh = true agent.redirect_ok = true end end def login # login_url = "https://www.amazon.com/ap/signin?_encoding=UTF8&openid.assoc_handle=usflex&openid.claimed_id=http%3A%2F%2Fspecs.openid.net%2Fauth%2F2.0%2Fidentifier_select&openid.identity=http%3A%2F%2Fspecs.openid.net%2Fauth%2F2.0%2Fidentifier_select&openid.mode=checkid_setup&openid.ns=http%3A%2F%2Fspecs.openid.net%2Fauth%2F2.0&openid.ns.pape=http%3A%2F%2Fspecs.openid.net%2Fextensions%2Fpape%2F1.0&openid.pape.max_auth_age=0&openid.return_to=https%3A%2F%2Fwww.amazon.com%2Fgp%2Fcss%2Fhomepage.html%3Fie%3DUTF8%26ref_%3Dgno_yam_ya" login_url = "https://www.amazon.com/gp/css/account/address/view.html?ie=UTF8&ref_=ya_add_address&viewID=newAddress" @agent.get(login_url) form = @agent.page.forms.first form.email = "[email protected]" form.radiobuttons.first.value = "0" form.radiobuttons.last.check form.password = "my_password" dashboard = @agent.submit(form) end end class UsersController < ApplicationController def index response = AmazonCrawler.new.login form = response.forms[1] # fill out form form.enterAddressFullName == "Your Name" form.enterAddressAddressLine1 = "123 Main Street" form.enterAddressAddressLine2 = "Apartment 34" form.enterAddressCity = "San Francisco" form.enterAddressStateOrRegion = "CA" form.enterAddressPostalCode = "94101" form.enterAddressPhoneNumber = "415-555-1212" form.AddressType = "RES" new_response = form.submit( form.button_with(value: /Save.*Continue/) ) end end

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