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  • Construction Paper, Legos, and Architectural Modeling

    I can remember as a kid playing with construction paper and Legos to explore my imagination. Through my exploration I was able to build airplanes, footballs, guns, and more, out of paper. Additionally I could create entire cities, robots, or anything else I could image out of Legos.  These toys, I now realize were in fact tools that gave me an opportunity to explore my ideas in the physical world through the use of modeling.  My imagination was allowed to run wild as I, unknowingly at the time, made design decisions that directly affected the models I was building from the raw materials.  To prove my point further, I can remember building a paper airplane that seemed to go nowhere when I tried to throw it. So I decided to attach a paper clip to the plane before I decided to throw it the next time to test my concept that by adding more weight to the plane that it would fly better and for longer distances. The paper airplane allowed me to model my design decision through the use of creating an artifact in that I created a paper airplane that was carrying extra weight through the incorporation of the paper clip in to the design. Also, I remember using Legos to build all sorts of creations, and these creations became artifacts of my imagination. As I further and further defined my Lego creations through the process of playing I was able to create elaborate artifacts of my imagination. These artifacts represented design decision I had made in the evolution of my creation through my child like design process. In some form or fashion the artifacts I created as a kid are very similar to the artifacts that I create when I model a software architectural concept or a software design in that the process of making decisions is directly translated in to a tangible model in the form of an architectural model. Architectural models have been defined as artifacts that depict design decisions of a system’s architecture.  The act of creating architectural models is the act of architectural modeling. Furthermore, architectural modeling is the process of creating a physical model based architectural concepts and documenting these design decisions. In the process of creating models, the standard notation used is Architectural modeling notation. This notation is the primary method of capturing the essence of design decisions regarding architecture.  Modeling notations can vary based on the need and intent of a project; typically they range from natural language to a diagram based notation. Currently, Unified Markup Language (UML) is the industry standard in terms of architectural modeling notation  because allows for architectures to be defined through a series of boxes, lines, arrows and other basic symbols that encapsulate design designs in to virtual components, connectors, configurations and interfaces.  Furthermore UML allows for additional break down of models through the use of natural language as to explain each section of the model in plain English. One of the major factors in architectural modeling is to define what is to be modeled. As a basic rule of thumb, I tend to model architecture based on the complexity of systems or sub sub-systems of architecture. Another key factor is the level of detail that is actually needed for a model. For example if I am modeling a system for a CEO to view then the low level details will be omitted. In comparison, if I was modeling a system for another engineer to actually implement I would include as much detailed information as I could to help the engineer implement my design.

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  • Core Data migration problem: "Persistent store migration failed, missing source managed object model

    - by John Gallagher
    The Background A Cocoa Non Document Core Data project with two Managed Object Models. Model 1 stays the same. Model 2 has changed, so I want to migrate the store. I've created a new version by Design Data Model Add Model Version in Xcode. The difference between versions is a single relationship that's been changed from to a one to many. I've made my changes to the model, then saved. I've made a new Mapping Model that has the old model as a source and new model as a destination. I've ensured all Mapping Models and Data Models and are being compiled and all are copied to the Resource folder of my app bundle. I've switched on migrations by passing in a dictionary with the NSMigratePersistentStoresAutomaticallyOption key as [NSNumber numberWithBool:YES] when adding the Persistent Store. Rather than merging all models in the bundle, I've specified the two models I want to use (model 1 and the new version of model 2) and merged them using modelByMergingModels: The Problem No matter what I do to migrate, I get the error message: "Persistent store migration failed, missing source managed object model." What I've Tried I clean after every single build. I've tried various combinations of having only the model I'm migrating to in Resources, being compiled, or both. Since the error message implies it can't find the source model for my migration, I've tried having every version of the model in both the Resources folder and being compiled. I've made sure I'm not making a really basic error by switching back to the original version of my data model. The app runs fine. I've deleted the Mapping Model and the new version of the model, cleaned, then recreated both. I've tried making a different change in the new model - deleting an entity instead. I'm at my wits end. I can't help but think I've made a huge mistake somewhere that I'm not seeing. Any ideas?

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  • django crispy-forms inline forms

    - by abolotnov
    I'm trying to adopt crispy-forms and bootstrap and use as much of their functionality as possible instead of inventing something over and over again. Is there a way to have inline forms functionality with crispy-forms/bootstrap like django-admin forms have? Here is an example: class NewProjectForm(forms.Form): name = forms.CharField(required=True, label=_(u'???????? ???????'), widget=forms.TextInput(attrs={'class':'input-block-level'})) group = forms.ModelChoiceField(required=False, queryset=Group.objects.all(), label=_(u'?????? ????????'), widget=forms.Select(attrs={'class':'input-block-level'})) description = forms.CharField(required=False, label=_(u'???????? ???????'), widget=forms.Textarea(attrs={'class':'input-block-level'})) class Meta: model = Project fields = ('name','description','group') def __init__(self, *args, **kwargs): self.helper = FormHelper() self.helper.form_class = 'horizontal-form' self.helper.form_action = 'submit_new_project' self.helper.layout = Layout( Field('name', css_class='input-block-level'), Field('group', css_class='input-block-level'), Field('description',css_class='input-block-level'), ) self.helper.add_input(Submit('submit',_(u'??????? ??????'))) self.helper.add_input(Submit('cancel',_(u'? ?????????'))) super(NewProjectForm, self).__init__(*args, **kwargs) it will display a decent form: How do I go about adding a form that basically represents this model: class Link(models.Model): name = models.CharField(max_length=255, blank=False, null=False, verbose_name=_(u'????????')) url = models.URLField(blank=False, null=False, verbose_name=_(u'??????')) project = models.ForeignKey('Project') So there will be a project and name/url links and way to add many, like same thing is done in django-admin where you are able to add extra 'rows' with data related to your main model. On the sreenshot below you are able to fill out data for 'Question' object and below that you are able to add data for QuestionOption objects -you are able to click the '+' icon to add as many QuestionOptions as you want. I'm not looking for a way to get the forms auto-generated from models (that's nice but not the most important) - is there a way to construct a form that will let you add 'rows' of data like django-admin does?

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  • joomla: editing the mvc package for joomla component development

    - by PROFESSOR
    hi! i m new to joomla component development i hv just downloaded bunch of files from some jooomla mvc generater website.which llok like smthng like this hello.xml - frontend/index.html - frontend/hello.php - frontend/controller.php - frontend/models/index.html - frontend/models/hello.php - frontend/views/index.html - frontend/views/hello/index.html - frontend/views/hello/view.html.php - frontend/views/hello/metadata.xml - frontend/views/hello/tmpl/index.html - frontend/views/hello/tmpl/default.php - frontend/views/hello/tmpl/default.xml - frontend/assets/index.html - frontend/assets/images/index.html - backend/index.html - backend/admin.hello.php - backend/controller.php - backend/CHANGELOG.php - backend/views/index.html - backend/views/hello/index.html - backend/views/hello/view.html.php - backend/views/hello/tmpl/index.html - backend/views/hello/tmpl/default.php - backend/models/index.html - backend/models/hello.php - backend/assets/index.html - backend/assets/images/index.html - languages-front/en-GB/en-GB.com_hello.ini - languages-admin/en-GB/en-GB.com_hello.ini MVC Generator version 1.0.5 but dont know how to edit and where to edit those files pls help i m trying to make my only php based application to a joomla component

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  • How to add limit option in Magento API call.

    - by ritesh
    I am creating web service for my store. I am using magento API to collect product list from store. But it display all the 500 records. And i want it 25 records per page. What to add in API call? Or What filter will be apply for this? //create soap object $proxy = new SoapClient('http://localhsot/magento/api/soap/?wsdl'); // create authorized session id using api user name and api key // $sessionId = $proxy->login('apiUser', 'apiKey'); $sessionId = $proxy->login('test_admin', '12345678'); $filters = array( ); // Get list of product $productlist = $proxy->call($sessionId, 'product.list', array($filters)); print_r($productlist );

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  • django error ,about django-sphinx

    - by zjm1126
    from django.db import models from djangosphinx.models import SphinxSearch class MyModel(models.Model): search = SphinxSearch() # optional: defaults to db_table # If your index name does not match MyModel._meta.db_table # Note: You can only generate automatic configurations from the ./manage.py script # if your index name matches. search = SphinxSearch('index_name') # Or maybe we want to be more.. specific searchdelta = SphinxSearch( index='index_name delta_name', weights={ 'name': 100, 'description': 10, 'tags': 80, }, mode='SPH_MATCH_ALL', rankmode='SPH_RANK_NONE', ) queryset = MyModel.search.query('query') results1 = queryset.order_by('@weight', '@id', 'my_attribute') results2 = queryset.filter(my_attribute=5) results3 = queryset.filter(my_other_attribute=[5, 3,4]) results4 = queryset.exclude(my_attribute=5)[0:10] results5 = queryset.count() # as of 2.0 you can now access an attribute to get the weight and similar arguments for result in results1: print result, result._sphinx # you can also access a similar set of meta data on the queryset itself (once it's been sliced or executed in any way) print results1._sphinx and Traceback (most recent call last): File "D:\zjm_code\sphinx_test\models.py", line 1, in <module> from django.db import models File "D:\Python25\Lib\site-packages\django\db\__init__.py", line 10, in <module> if not settings.DATABASE_ENGINE: File "D:\Python25\Lib\site-packages\django\utils\functional.py", line 269, in __getattr__ self._setup() File "D:\Python25\Lib\site-packages\django\conf\__init__.py", line 38, in _setup raise ImportError("Settings cannot be imported, because environment variable %s is undefined." % ENVIRONMENT_VARIABLE) ImportError: Settings cannot be imported, because environment variable DJANGO_SETTINGS_MODULE is undefined.

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  • django+uploadify - don't working

    - by Erico
    Hi, I'm trying to use an example posted on the "github" the link is http://github.com/tstone/django-uploadify. And I'm having trouble getting work. can you help me? I followed step by step, but does not work. Accessing the "URL" / upload / the only thing is that returns "True" part of settings.py import os PROJECT_ROOT_PATH = os.path.dirname(os.path.abspath(file)) MEDIA_ROOT = os.path.join(PROJECT_ROOT_PATH, 'media') TEMPLATE_DIRS = ( os.path.join(PROJECT_ROOT_PATH, 'templates')) urls.py from django.conf.urls.defaults import * from django.conf import settings from teste.uploadify.views import * from django.contrib import admin admin.autodiscover() urlpatterns = patterns('', (r'^admin/', include(admin.site.urls)), url(r'upload/$', upload, name='uploadify_upload'), ) views.py from django.http import HttpResponse import django.dispatch upload_received = django.dispatch.Signal(providing_args=['data']) def upload(request, *args, **kwargs): if request.method == 'POST': if request.FILES: upload_received.send(sender='uploadify', data=request.FILES['Filedata']) return HttpResponse('True') models.py from django.db import models def upload_received_handler(sender, data, **kwargs): if file: new_media = Media.objects.create( file = data, new_upload = True, ) new_media.save() upload_received.connect(upload_received_handler, dispatch_uid='uploadify.media.upload_received') class Media(models.Model): file = models.FileField(upload_to='images/upload/', null=True, blank=True) new_upload = models.BooleanField() uploadify_tags.py from django import template from teste import settings register = template.Library() @register.inclusion_tag('uploadify/multi_file_upload.html', takes_context=True) def multi_file_upload(context, upload_complete_url): """ * filesUploaded - The total number of files uploaded * errors - The total number of errors while uploading * allBytesLoaded - The total number of bytes uploaded * speed - The average speed of all uploaded files """ return { 'upload_complete_url' : upload_complete_url, 'uploadify_path' : settings.UPLOADIFY_PATH, # checar essa linha 'upload_path' : settings.UPLOADIFY_UPLOAD_PATH, } template - uploadify/multi_file_upload.html {% load uploadify_tags }{ multi_file_upload '/media/images/upload/' %} <script type="text/javascript" src="{{ MEDIA_URL }}js/swfobject.js"></script> <script type="text/javascript" src="{{ MEDIA_URL }}js/jquery.uploadify.js"></script> <div id="uploadify" class="multi-file-upload"><input id="fileInput" name="fileInput" type="file" /></div> <script type="text/javascript">// <![CDATA[ $(document).ready(function() { $('#fileInput').uploadify({ 'uploader' : '/media/swf/uploadify.swf', 'script' : '{% url uploadify_upload %}', 'cancelImg' : '/media/images/uploadify-remove.png/', 'auto' : true, 'folder' : '/media/images/upload/', 'multi' : true, 'onAllComplete' : allComplete }); }); function allComplete(event, data) { $('#uploadify').load('{{ upload_complete_url }}', { 'filesUploaded' : data.filesUploaded, 'errorCount' : data.errors, 'allBytesLoaded' : data.allBytesLoaded, 'speed' : data.speed }); // raise custom event $('#uploadify') .trigger('allUploadsComplete', data); } // ]]</script>

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  • Django and ImageField Question

    - by Hellnar
    Hello I have a such model: Foo (models.Model): slug = models.SlugField(unique=True) image = models.ImageField(upload_to='uploads/') I want to do two things with this: First of all, I want my image to be forced to resize to a specific width and height after the upload. I have tried this reading the documentation but seems to getting error: image = models.ImageField(upload_to='uploads/', height_field=258, width_field=425) Secondly, when adding an item via admin panel, I want my image's file name to be renamed as same as slug, if any issue arises (like if such named image already exists, add "_" to the end as it used to do. IE: My slug is i-love-you-guys , uploaded image such have i-love-you-guys.png at the end.

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  • how to use SQL wildcard % with Queryset extra>select?

    - by tylias
    I'm trying to add weights to search terms I'm using to filter a queryset. Using the '%' wildcard is causing me some problems. I'm using the extra() modifier to add a weight parameter to the queryset, which I will be using to inform a sort ordering. (See http://docs.djangoproject.com/en/1.1/ref/models/querysets/#extra-select-none-where-none-params-none-tables-none-order-by-none-select-params-none ) Here's the gist of the code: def viewname(request) ... exact_matchstrings="" exact_matchstrings.append("(accountprofile.first_name LIKE '" + term + "')") exact_matchstrings.append("(accountprofile.first_name LIKE '" + term + '\%' + "')") extraquerystring = " + ".join(exact_matchstrings) return_queryset = return_queryset.extra( select = { 'match_weight': extraquerystring }, ) The effect I'm going for is that if the search term matches exactly, the weight associated with the record is 2, but if the term merely starts with the search term and isn't an exact match, the weight is 1. (for example, if 'term' = 'Jon', an entry with first_name='Jon' gets a weight of 2 but an entry with an entry with first_name = 'Jonathan' gets a weight of 1.) I can test the statement in SQL and it seems to work well enough. If I make this SQL query from the mysql shell, no problem: select (first_name like "Carl") + (first_name like "Car%") from accountprofile; But trying to run it via the extra() modifier in my view code and evaluating the resulting queryset gives me the following error: Traceback (most recent call last): File "<console>", line 1, in <module> File "/usr/local/lib/python2.6/dist-packages/django/db/models/query.py", line 68, in __repr__ data = list(self[:REPR_OUTPUT_SIZE + 1]) File "/usr/local/lib/python2.6/dist-packages/django/db/models/query.py", line 83, in __len__ self._result_cache.extend(list(self._iter)) File "/usr/local/lib/python2.6/dist-packages/django/db/models/query.py", line 238, in iterator for row in self.query.results_iter(): File "/usr/local/lib/python2.6/dist-packages/django/db/models/sql/query.py", line 287, in results_iter for rows in self.execute_sql(MULTI): File "/usr/local/lib/python2.6/dist-packages/django/db/models/sql/query.py", line 2369, in execute_sql cursor.execute(sql, params) File "/usr/local/lib/python2.6/dist-packages/django/db/backends/util.py", line 22, in execute sql = self.db.ops.last_executed_query(self.cursor, sql, params) File "/usr/local/lib/python2.6/dist-packages/django/db/backends/__init__.py", line 217, in last_executed_query return smart_unicode(sql) % u_params ValueError: unsupported format character ''' (0x27) at index 309 I've tried it escaping and not escaping % wildcard but that doesn't solve the problem. Doesn't seem to affect it at all, really. Any ideas?

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  • spring 3 AOP anotated advises

    - by Art79
    Trying to figure out how to Proxy my beans with AOP advices in annotated way. I have a simple class @Service public class RestSampleDao { @MonitorTimer public Collection<User> getUsers(){ .... return users; } } i have created custom annotation for monitoring execution time @Target({ ElementType.METHOD, ElementType.TYPE }) @Retention(RetentionPolicy.RUNTIME) public @interface MonitorTimer { } and advise to do some fake monitoring public class MonitorTimerAdvice implements MethodInterceptor { public Object invoke(MethodInvocation invocation) throws Throwable{ try { long start = System.currentTimeMillis(); Object retVal = invocation.proceed(); long end = System.currentTimeMillis(); long differenceMs = end - start; System.out.println("\ncall took " + differenceMs + " ms "); return retVal; } catch(Throwable t){ System.out.println("\nerror occured"); throw t; } } } now i can use it if i manually proxy the instance of dao like this AnnotationMatchingPointcut pc = new AnnotationMatchingPointcut(null, MonitorTimer.class); Advisor advisor = new DefaultPointcutAdvisor(pc, new MonitorTimerAdvice()); ProxyFactory pf = new ProxyFactory(); pf.setTarget( sampleDao ); pf.addAdvisor(advisor); RestSampleDao proxy = (RestSampleDao) pf.getProxy(); mv.addObject( proxy.getUsers() ); but how do i set it up in Spring so that my custom annotated methods would get proxied by this interceptor automatically? i would like to inject proxied samepleDao instead of real one. Can that be done without xml configurations? i think should be possible to just annotate methods i want to intercept and spring DI would proxy what is necessary. or do i have to use aspectj for that? would prefere simplest solution :- ) thanks a lot for help!

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  • Castle Windsor upgrade causes TypeLoadException for generic types

    - by Neil Barnwell
    I have the following mapping in my Castle Windsor xml file which has worked okay (unchanged) for some time: <component id="defaultBasicRepository" service="MyApp.Models.Repositories.IBasicRepository`1, MyApp.Models" type="MyApp.Models.Repositories.Linq.BasicRepository`1, MyApp.Models" lifestyle="perWebRequest"/> I got this from the Windsor documentation at http://www.castleproject.org/container/documentation/v1rc3/usersguide/genericssupport.html. Since I upgraded Windsor, I now get the following exception at runtime: Description: An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code. Exception Details: System.TypeLoadException: GenericArguments[0], 'T', on 'MyApp.Models.Repositories.Linq.BasicRepository`1[TEntity]' violates the constraint of type parameter 'TEntity'. Source Error: Line 44: public static void ConfigureIoC() Line 45: { Line 46: var windsor = new WindsorContainer("Windsor.xml"); Line 47: Line 48: ServiceLocator.SetLocatorProvider(() = new WindsorServiceLocator(windsor)); I'm using ASP.NET MVC 1.0, Visual Studio 2008 and Castle Windsor as downloaded from http://sourceforge.net/projects/castleproject/files/InversionOfControl/2.1/Castle-Windsor-2.1.1.zip/download Can anyone shed any light on this? I'm sure the upgrade of Castle Windsor is what caused it - it's been working well for ages.

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  • Django query if field value is one of multiple choices

    - by Nathan
    Say I want to model a system where a piece of data can have multiple tags (e.g. a question on a StackOverflow is the data, it's set of tags are the tags). I can model this in Django with the following: class Tag(models.Model): name = models.CharField(10) class Data(models.Model): tags = models.ManyToManyField(Tag) Given a set of strings, what's the best way to go about finding all Data objects that have one of these strings as the name of a tag in their tag list. I've come up with the following, but can't help thinking there is a more "Djangonic" way. Any ideas? tags = [ "foo", "bar", "baz" ] q_objects = Q( tags__name = tags[0] ) for t in tags[1:]: q_objects = q_objects | Q( tags__name = t ) data = Data.objects.filter( q_objects ).distinct()

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  • Why is the unit test useful when the view is not unit testable in MVVM?

    - by BigTiger
    Why is the unit test useful when the view is not unit testable in MVVM? In MVVM, we have the models, view-models, and views. The claimed advantage is that MVVM can make the models and view=models unit testable. But all the three parties belong to the same application. If the views are not unit testable, why test the other two? Will unit testing the other two and leave one not tested improve the quality? Removing all the code-behind from the views sounds weird to me. How about the code-behind only handles the pure UI operations?

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  • WCF - Passing CurrentPrincipal in the Header

    - by David Ward
    I have a WCF service that needs to know the Principal of the calling user. In the constructor of the service I have: Principal = OperationContext.Current.IncomingMessageHeaders.GetHeader<MyPrincipal>("myPrincipal", "ns"); and in the calling code I have something like: using (var factory = new ChannelFactory<IMyService>(localBinding, endpoint)) { var proxy = factory.CreateChannel(); using (var scope = new OperationContextScope((IContextChannel)proxy)) { var customHeader = MessageHeader.CreateHeader("myPrincipal", "ns", Thread.CurrentPrincipal); OperationContext.Current.OutgoingMessageHeaders.Add(customHeader); newList = proxy.CreateList(); } } This all works fine. My question is, how can I avoid having to wrap all proxy method calls in the using (var scope...{ [create header and add to OperationContext]? Could I create a custom ChannelFactory that will handle adding the myPrincipal header to the operation context? Something like that would save a whole load of copy/paste which I'd rather not do but I'm not sure how to achieve it:) Thanks

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  • Django + FastCGI - randomly raising OperationalError

    - by ibz
    I'm running a Django application. Had it under Apache + mod_python before, and it was all OK. Switched to Lighttpd + FastCGI. Now I randomly get the following exception (neither the place nor the time where it appears seem to be predictable). Since it's random, and it appears only after switching to FastCGI, I assume it has something to do with some settings. Found a few results when googleing, but they seem to be related to setting maxrequests=1. However, I use the default, which is 0. Any ideas where to look for? PS. I'm using PostgreSQL. Might be related to that as well, since the exception appears when making a database query. Thanks. File "/usr/lib/python2.6/site-packages/django/core/handlers/base.py", line 86, in get_response response = callback(request, *callback_args, **callback_kwargs) File "/usr/lib/python2.6/site-packages/django/contrib/admin/sites.py", line 140, in root if not self.has_permission(request): File "/usr/lib/python2.6/site-packages/django/contrib/admin/sites.py", line 99, in has_permission return request.user.is_authenticated() and request.user.is_staff File "/usr/lib/python2.6/site-packages/django/contrib/auth/middleware.py", line 5, in __get__ request._cached_user = get_user(request) File "/usr/lib/python2.6/site-packages/django/contrib/auth/__init__.py", line 83, in get_user user_id = request.session[SESSION_KEY] File "/usr/lib/python2.6/site-packages/django/contrib/sessions/backends/base.py", line 46, in __getitem__ return self._session[key] File "/usr/lib/python2.6/site-packages/django/contrib/sessions/backends/base.py", line 172, in _get_session self._session_cache = self.load() File "/usr/lib/python2.6/site-packages/django/contrib/sessions/backends/db.py", line 16, in load expire_date__gt=datetime.datetime.now() File "/usr/lib/python2.6/site-packages/django/db/models/manager.py", line 93, in get return self.get_query_set().get(*args, **kwargs) File "/usr/lib/python2.6/site-packages/django/db/models/query.py", line 304, in get num = len(clone) File "/usr/lib/python2.6/site-packages/django/db/models/query.py", line 160, in __len__ self._result_cache = list(self.iterator()) File "/usr/lib/python2.6/site-packages/django/db/models/query.py", line 275, in iterator for row in self.query.results_iter(): File "/usr/lib/python2.6/site-packages/django/db/models/sql/query.py", line 206, in results_iter for rows in self.execute_sql(MULTI): File "/usr/lib/python2.6/site-packages/django/db/models/sql/query.py", line 1734, in execute_sql cursor.execute(sql, params) OperationalError: server closed the connection unexpectedly This probably means the server terminated abnormally before or while processing the request.

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  • In Django, can you add a method to querysets?

    - by Paul D. Waite
    In Django, if I have a model class, e.g. from django.db import models class Transaction(models.Model): ... then if I want to add methods to the model, to store reasonably complex filters, I can add a custom model manager, e.g. class TransactionManager(models.Manager): def reasonable_complex_filter(self): return self.get_query_set().filter(...) class Transaction(models.Model): objects = TransactionManager() And then I can do: >>> Transaction.objects.reasonably_complex_filter() Is there any way I can add a custom method that can be chained to the end of a query set from the model? I.e. add the custom method in such a way that I can do this: >>> Transaction.objects.filter(...).reasonably_complex_filter()

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  • Django queries: Count number of objects with FK to model instance

    - by Chris Lawlor
    This should be easy but for some reason I'm having trouble finding it. I have the following: App(models.Model): ... Release(models.Model): date = models.DateTimeField() App = models.ForeignKey(App) ... How can I query for all App objects that have at least one Release? I started typing: App.objects.all().annotate(release_count=Count('??????')).filter(release_count__gt=0) Which won't work because Count doesn't span relationships, at least as far as I can tell. BONUS: Ultimately, I'd also like to be able to sort Apps by latest release date. I'm thinking of caching the latest release date in the app to make this a little easier (and cheaper), and updating it in the Release model's save method, unless of course there is a better way. Edit: I'm using Django 1.1 - not averse to migrating to dev in anticipation of 1.2 if there is a compelling reason though.

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  • Generic relations missing with grappelli

    - by diegueus9
    I'm using the last svn revision of grappelli and rev 11840 of django (before multidatabases and stuff), and i'm trying to use generic relations in the admin, but doesn't work, The model: class AutorProyectoLey(DatedModel): tipo_autor = models.ForeignKey(ContentType) autor_id = models.PositiveIntegerField() content_object = generic.GenericForeignKey('tipo_autor', 'autor_id') proyecto_ley = models.ForeignKey(ProyectoLey) The admin: class AutorInline(GenericInlineModelAdmin): model = AutorProyectoLey allow_add = True ct_field = 'tipo_autor' ct_fk_field = 'autor_id' classes = ('collapse-open',) And i put this model of var inlines in another adminmodel, but the html render is : <!-- Inlines --> <!-- Submit-Row -->

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  • Rails fields_for :child_index option explanation

    - by Timothy
    I have been trying to create a complex form with many nested models, and make it dynamic. Now I found that making a nested model isn't difficult with accepts_nested_attributes_for, but making it nested and dynamic was seemingly impossible if there were multiple nested models. I came across http://github.com/ryanb/complex-form-examples/blob/master/app/helpers/application_helper.rb which does it very elegantly. Could anyone shed some light on lines 13 and 16? 13 form_builder.object.class.reflect_on_association(method).klass.new and 16 form_builder.fields_for(method, options[:object], :child_index => "new_#{method}") do |f| From intuition, line 13 instantiates a new object, but why must it do so many method calls? I couldn't find any documentation for the :child_index option on line 16. When the form is created, a very large number is used as an index for new models, whereas existing models are indexed by their id. How does this work?

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  • Django IN query as a string result - invalid literal for int() with base 10

    - by bmelton
    Trying to query a 'Favorites' model to get a list of items a user has favorited, and then querying against a different model to get the objects back from that query to present to the template, but I'm getting an error: "invalid literal for int() with base 10" Looking over all of the other instances of that error, I couldn't find any in which the asker actually wanted to work with a comma separated list of integers, so I'm kind of at a loss. Model class Favorite(models.Model): # key should be the model name, id is the model.id, and user is the User object. key = models.CharField(max_length=255, unique=True) val = models.IntegerField(default=0) user = models.ForeignKey(User) class Admin: list_display = ('key', 'id', 'user') View def index(request): favorites = Favorite.objects.filter(key='blog', user=request.user.pk) values = "" for favorite in favorites: values += "%s," % favorite.val #values = "[%s]" % values blogs = Blog.objects.filter(pk__in=values) return render_to_response('favorite/index.html', { "favorites" : favorites, "blogs" : blogs, "values" : values, }, context_instance=RequestContext(request) ) enter code here

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  • Django debug error

    - by Hulk
    I have the following in my model: class info(models.Model): add = models.CharField(max_length=255) name = models.CharField(max_length=255) An in the views when i say info_l = info.objects.filter(id=1) logging.debug(info_l.name) i get an error saying name doesnt exist at debug statement. 'QuerySet' object has no attribute 'name' 1.How can this be resolved. 2.Also how to query for only one field instead of selecting all like select name from info.

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  • Django, ModelForms, User and UserProfile - not hashing password

    - by IvanBernat
    I'm trying to setup a User - UserProfile relationship, display the form and save the data. When submitted, the data is saved, except the password field doesn't get hashed. Additionally, how can I remove the help_text from the username and password (inherited from the User model)? Full code is below, excuse me if it's too long. Models.py USER_IS_CHOICES = ( ('u', 'Choice A'), ('p', 'Choice B'), ('n', 'Ninja'), ) class UserProfile(models.Model): user = models.ForeignKey(User, unique=True) user_is = models.CharField(max_length=1, choices=USER_IS_CHOICES) Forms.py class UserForm(forms.ModelForm): class Meta: model = User fields = ["first_name", "last_name", "username", "email", "password"] def clean_username(self): username = self.cleaned_data['username'] if not re.search(r'^\w+$', username): raise forms.ValidationError('Username can contain only alphanumeric characters') try: User.objects.get(username=username) except ObjectDoesNotExist: return username raise forms.ValidationError('Username is already taken') class UserProfileForm(forms.ModelForm): class Meta: model = UserProfile fields = ['user_is'] Views.py if request.method == 'POST': uform = UserForm(request.POST) pform = UserProfileForm(request.POST) if uform.is_valid() and pform.is_valid(): user = uform.save() profile = pform.save(commit = False) profile.user = user profile.save() return HttpResponseRedirect('/') else: uform = UserForm() pform = UserProfileForm() variables = RequestContext(request, { 'uform':uform, 'pform':pform }) return render_to_response('registration/register.html', variables)

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  • How to use SQLAlchemy to dump an SQL file from query expressions to bulk-insert into a DBMS?

    - by Mahmoud Abdelkader
    Please bear with me as I explain the problem, how I tried to solve it, and my question on how to improve it is at the end. I have a 100,000 line csv file from an offline batch job and I needed to insert it into the database as its proper models. Ordinarily, if this is a fairly straight-forward load, this can be trivially loaded by just munging the CSV file to fit a schema, but I had to do some external processing that requires querying and it's just much more convenient to use SQLAlchemy to generate the data I want. The data I want here is 3 models that represent 3 pre-exiting tables in the database and each subsequent model depends on the previous model. For example: Model C --> Foreign Key --> Model B --> Foreign Key --> Model A So, the models must be inserted in the order A, B, and C. I came up with a producer/consumer approach: - instantiate a multiprocessing.Process which contains a threadpool of 50 persister threads that have a threadlocal connection to a database - read a line from the file using the csv DictReader - enqueue the dictionary to the process, where each thread creates the appropriate models by querying the right values and each thread persists the models in the appropriate order This was faster than a non-threaded read/persist but it is way slower than bulk-loading a file into the database. The job finished persisting after about 45 minutes. For fun, I decided to write it in SQL statements, it took 5 minutes. Writing the SQL statements took me a couple of hours, though. So my question is, could I have used a faster method to insert rows using SQLAlchemy? As I understand it, SQLAlchemy is not designed for bulk insert operations, so this is less than ideal. This follows to my question, is there a way to generate the SQL statements using SQLAlchemy, throw them in a file, and then just use a bulk-load into the database? I know about str(model_object) but it does not show the interpolated values. I would appreciate any guidance for how to do this faster. Thanks!

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  • Why isn't this MVC Html Helper extension method working?

    - by Blankman
    My base controller looks like: public abstract MyBaseMasterController<TMasterViewModel> : Controller { } public MyMasterController: MyBaseMasterController<SomeThingModel> { } Extension method: public static string DoSomething(this HtmlHelper htmlHelper) { StringBuilder sb = new StringBuilder(); sb.Append("var cnwglobals = {"); var controller = htmlHelper.ViewContext.Controller as MyMasterController; if (controller == null) { } return sb.ToString(); } In my view I do: <% Html.Dosomething(); %> I get an error: CS1061: 'System.Web.Mvc.HtmlHelper<Blah.Models.ViewModelForMasterWrapper<Blah.Models.MasterViewModel>>' does not contain a definition for 'DoSomething' and no extension method 'DoSomething' accepting a first argument of type 'System.Web.Mvc.HtmlHelper<Blah.Models.ViewModelForMasterWrapper<Blah.Models.MasterViewModel>>' could be found (are you missing a using directive or an assembly reference?)

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  • asp.net not deserializing soap response

    - by Tanya
    Hi all, I have been given a wsdl and have used wsdl.exe to create my proxy classes. I am able to call the function to initiate the request with some valid parameters and this returns my response object which is always EMPTY. When i inspect the soap message response using fiddler the soap does have valid data that should be deserialzed to the proxy classes. Can i manually intercept the derserializing call of the proxy classes generated by wsdl and check that .net is correctly derializing the soap response? Thank you

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