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  • linebreak in url with Bibtex and hyperref package

    - by Tim
    Why is this item not shown properly in my bibliography? @misc{ann, abstract = {ANN is an implbmentation of nearest neighbor search.}, author = {David M. Mount and Sunil Arya}, howpublished = {\url{http://www.cs.umd.edu/~mount/ANN/}}, keywords = {knn}, posted-at = {2010-04-08 00:05:04}, priority = {2}, title = {ANN.}, url = "http://www.cs.umd.edu/~mount/ANN/", year = {2008} } @misc{Nilsson96introductionto, author = {Nilsson, Nils J.}, citeulike-article-id = {6995464}, howpublished = {\url{http://robotics.stanford.edu/people/nilsson/mlbook.html}}, keywords = {*file-import-10-04-11}, posted-at = {2010-04-11 06:52:28}, priority = {2}, title = {Introduction to Machine Learning: An Early Draft of a Proposed Textbook.}, year = {1996} } EDIT: I am using \usepackage{hyperref}, not \usepackage{url}. I don't know what changes I just made made the first item appear properly now @misc{ann, abstract = {ANN is an implbmentation of nearest neighbor search.}, author = {David M. Mount and Sunil Arya}, howpublished = {\url{http://www.cs.umd.edu/~mount/ANN/}}, keywords = {ann}, posted-at = {2010-04-08 00:05:04}, priority = {2}, title = {The \textsc{A}pproximate \textsc{N}earest \textsc{N}eighbor \textsc{S}earching \textsc{L}ibrary.}, url = "http://www.cs.umd.edu/~mount/ANN/", year = {2008} } EDIT: Since I am using hyperref package, it produces error when using url package together with it. So the two cannot work together? I would like to use hyper links inside pdf file, so I would like to use hyperref package instead of url package. I googled a bit, and try \usepackage[hyperindex,breaklinks]{hyperref}, but there is still no line break just as before. How can I do it? Is there conflict in the packages that I am now using?: \usepackage{amsmath} \usepackage{amsfonts} \usepackage[dvips]{graphicx} \usepackage{wrapfig} \graphicspath{{./figs/}} \DeclareGraphicsExtensions{.eps} \usepackage{fixltx2e} \usepackage{array} \usepackage{times} \usepackage{fancyhdr} \usepackage{multirow} \usepackage{algorithmic} \usepackage{algorithm} \usepackage{slashbox} \usepackage{multirow} \usepackage{rotating} \usepackage{longtable} \usepackage[hyperindex,breaklinks]{hyperref} \usepackage{forloop} \usepackage{lscape} \usepackage{supertabular} \usepackage{amssymb} \usepackage{amsthm}

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  • XML Attributes or Element Nodes?

    - by Camsoft
    Example XML using element nodes: <?xml version="1.0" encoding="utf-8"?> <users> <user> <name>David Smith</name> <phone>0441 234443</phone> <email>[email protected]</email> <addresses> <address> <street>1 Some Street</street> <town>Toy Town</town> <country>UK</country> </address> <address> <street>5 New Street</street> <town>Lego City</town> <country>US</country> </address> </addresses> </user> </users> Example XML using attributes: <?xml version="1.0" encoding="utf-8"?> <users> <user name="David Smith" phone="0441 234443" email="[email protected]"> <addresses> <address street="1 Some Street" town="Toy Town" country="UK" /> <address street="5 New Street" town="Lego City" country="US" /> </addresses> </user> </users> I'm needing to build an XML file based on data from a relation database and can't work out whether I should use attributes or elements. What is best practice when building XML files?

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  • passing value of index number to different php file.

    - by tooepic
    hi, i am a php beginner and have a question for you please. i have a text file with list of first and last names like this: john,smith sam,lewis david,davidson mike,anderson in my sort.php file, it sorts that name list by first name in ascending order with index number, which will display like this: 1. david,davidson 2. john,smith 3. mike,anderson 4. sam,lewis also, in that sort.php file, there's a form for input type=text where you can type index number and a button to delete that index number entered in that text field: <form action="deletename.php" method="post"> <table> <tr valign="top"> <td>Delete: <input type="text" size="2" name="indexnumber" /> </td> <td> <div align="left"> <input type="submit" name="delete" value="Delete" /> </div> </td> </tr> </table> </form> now the question...is there anything i can do in that form to send the value of that index number i entered in the text field? in other word...if i enter 3, what can i do to that form to send the value "mike,anderson" to deletename.php? thanks in advance.

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  • awk + sorting file according to values in the file and write two diffrent files

    - by yael
    hi I have in file file_test values of right eye and left eye How to separate the file_test to file1 and file2 by awk in order to write the equal values on file1 and different values on file2 as the following example down THX file_test: NAME: jim LAST NAME: bakker right eye: |5|< left eye VALUE: |5|< NAME: Jorg LAST NAME: mitchel right eye: |3|< left eye VALUE: |5|< NAME: jimmy LAST NAME: kartter right eye: |6|< left eye VALUE: |5|< NAME: david LAST NAME: kann right eye: |9|< left eye VALUE: |9|< file1: NAME: jim LAST NAME: bakker right eye: |5|< left eye VALUE: |5|< NAME: david LAST NAME: kann right eye: |9|< left eye VALUE: |9|< file2: NAME: Jorg LAST NAME: mitchel right eye: |3|< left eye VALUE: |5|< NAME: jimmy LAST NAME: kartter right eye: |6|< left eye VALUE: |5|<

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  • scheme struct question

    - by qzar
    ;; definition of the structure "book" ;; author: string - the author of the book ;; title: string - the title of the book ;; genre: symbol - the genre (define-struct book (author title genre)) (define lotr1 (make-book "John R. R. Tolkien" "The Fellowship of the Ring" 'Fantasy)) (define glory (make-book "David Brin" "Glory Season" 'ScienceFiction)) (define firstFamily (make-book "David Baldacci" "First Family" 'Thriller)) (define some-books (list lotr1 glory firstFamily)) ;; count-books-for-genre: symbol (list of books) -> number ;; the procedure takes a symbol and a list of books and produces the number ;; of books from the given symbol and genre ;; example: (count-books-for-genre 'Fantasy some-books) should produce 1 (define (count-books-for-genre genre lob) (if (empty? lob) 0 (if (symbol=? (book-genre (first lob)) genre) (+ 1 (count-books-for-genre (rest lob) genre)) (count-books-for-genre (rest lob) genre) ) ) ) (count-books-for-genre 'Fantasy some-books) It produce following exception first: expected argument of type non-empty list; given 'Fantasy, I don't understand whats the problem. Can somebody give me some explanation ? Thank you very much !

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  • Python DictReader - Skipping rows with missing columns?

    - by victorhooi
    heya, I have a Excel .CSV file I'm attempting to read in with DictReader. All seems to be well, except it seems to omit rows, specifically those with missing columns. Our input looks like: mail,givenName,sn,lorem,ipsum,dolor,telephoneNumber [email protected],ian,bay,3424,8403,2535,+65(2)34523534545 [email protected],mike,gibson,3424,8403,2535,+65(2)34523534545 [email protected],ross,martin,,,,+65(2)34523534545 david[email protected],david,connor,,,,+65(2)34523534545 [email protected],chris,call,3424,8403,2535,+65(2)34523534545 So some of the rows have missing lorem/ipsum/dolor columns, and it's just a string of commas for those. We're reading it in with: def read_gd_dump(input_file="blah 20100423.csv"): gd_extract = csv.DictReader(open('blah 20100423.csv'), restval='missing', dialect='excel') return dict([(row['something'], row) for row in gd_extract]) And I checked that "something" (the key for our dict) isn't one of the missing columns, I had originally suspected it might be that. It's one of the columns after that. However, DictReader seems to completely skip over the rows. I tried setting restval to something, didn't seem to make any difference. I can't seem to find anything in Python's CSV docs (http://docs.python.org/library/csv.html) that would explain this behaviour, but I may have misread something. Any ideas? Thanks, Victor

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  • LINQ XML query at c# wp7

    - by Karloss
    I am working at Windows Phone 7 C#, Xaml, XML and LINQ programming. I need to organize search by part of the name at following XML: <Row> <Myday>23</Myday> <Mymonth>12</Mymonth> <Mynames>Alex, Joanna, Jim</Mynames> </Row> <Row> <Myday>24</Myday> <Mymonth>12</Mymonth> <Mynames>John, David</Mynames> </Row> I have following query: var myData = from query in loadedData.Descendants("Row") where query.Element("Mynames").Value.Contains("Jo") select new Kalendars { Myday = (int)query.Element("Myday"), Mymonth = (int)query.Element("Mymonth"), Mynames = (string)query.Element("Mynames") }; listBoxSearch.ItemsSource = myData; Query problem is, that it will return full part of the names like "Alex, Joanna, Jim" and "John, David". How can i get only Joanna and John? Second question is how it is possible to do that user enters ...Value.Contains("jo") and query still returns Joanna and John? Possible solution (needs some corrections) public string Search_names { get { return search_names; } set { string line = this.Mynames; string[] names = line.Split(new[] { ", " }, StringSplitOptions.None); var jos = from name in names where name.Contains("is") select name; // ["Joanna"] // HOW TO BIND search_names? } }

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  • How do I render *parts* of a svg file?

    - by Fake Code Monkey Rashid
    Hello good people! :) I want to render parts of a svg file by name but for the life of me I cannot figure out how to do so (using python + gtk). Here's the svg file in question: http://david.bellot.free.fr/svg-cards/files/SVG-cards-2.0.1.tar.gz On his site, David, says: You can draw a card either by rendering the file onto a pixmap and clipping each card manually or by using the card's name through a DOM interface. All cards are embedded into a SVG group. I don't know what he means by a DOM interface. I have done some searching and the best result I found that seems to fit what I want to do is: QSvgRenderer *renderer = new QSvgRenderer(QLatin1String("SvgCardDeck.svg")); QGraphicsSvgItem *black = new QGraphicsSvgItem(); QGraphicsSvgItem *red = new QGraphicsSvgItem(); black->setSharedRenderer(renderer); black->setElementId(QLatin1String("black_joker")); red->setSharedRenderer(renderer); red->setElementId(QLatin1String("red_joker")); Notice however that it is for Qt and is not even written in python. This is what I have so far: #!/usr/bin/env python from __future__ import absolute_import import cairo import gtk import rsvg from xml import xpath from xml.dom import minidom window = gtk.Window() window.set_title("Foo") window.set_size_request(256, 256) window.set_property("resizable", False) window.set_position(gtk.WIN_POS_CENTER) window.connect("destroy", gtk.main_quit) window.show() document = minidom.parse("cards.svg") element = xpath.Evaluate("//*[@id='1_club']", document)[0] xml = element.toxml() svg = rsvg.Handle() svg.write(xml) pixbuf = svg.get_pixbuf() image = gtk.Image() image.set_from_pixbuf(pixbuf) image.show() window.add(image) gtk.main() It doesn't work, of course. What am I missing?

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  • Inject App Settings using Windsor

    - by Damian Powell
    How can I inject the value of an appSettings entry (from app.config or web.config) into a service using the Windsor container? If I wanted to inject the value of a Windsor property into a service, I would do something like this: <properties> <importantIntegerProperty>666</importantIntegerProperty> </properties> <component id="myComponent" service="MyApp.IService, MyApp" type="MyApp.Service, MyApp" > <parameters> <importantInteger>#{importantIntegerProperty}</importantInteger> </parameters> </component> However, what I'd really like to do is take the value represented by #{importantIntegerProperty} from an app settings variable which might be defined like this: <appSettings> <add key="importantInteger" value="666"/> </appSettings> EDIT: To clarify; I realise that this is not natively possible with Windsor and the David Hayden article that sliderhouserules refers to is actually about his own (David Hayden's) IoC container, not Windsor. I'm surely not the first person to have this problem so what I'd like to know is how have other people solved this issue?

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  • Strange LINQ to SQL Behavior

    - by mcass20
    What is wrong with the last query? Is it a bug or am I missing something? This query returns 2 records (correct): query = query.Where(Log => SqlMethods.Like(Log.FormattedMessage, "%<key>Name</key><value>David</value>%")); This query returns 2 records (correct): query = query.Where(Log => SqlMethods.Like(Log.FormattedMessage, "%<key>Name</key><value>%David%</value>%")); This query returns 0 records (correct): query = query.Where(Log => SqlMethods.Like(Log.FormattedMessage, "%<key>Name</key><value>av</value>%")); This query returns 2 records (correct): query = query.Where(Log => SqlMethods.Like(Log.FormattedMessage, "%<key>Name</key><value>%av%</value>%")); This query returns 0 records (correct): query = query.Where(Log => SqlMethods.Like(Log.FormattedMessage, "%<key>Name</key><value>v</value>%")); This query returns 15 records (incorrect, should return 2): query = query.Where(Log => SqlMethods.Like(Log.FormattedMessage, "%<key>Name</key><value>%v%</value>%"));

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  • Silverlight Tree View with Multiple Levels

    - by psheriff
    There are many examples of the Silverlight Tree View that you will find on the web, however, most of them only show you how to go to two levels. What if you have more than two levels? This is where understanding exactly how the Hierarchical Data Templates works is vital. In this blog post, I am going to break down how these templates work so you can really understand what is going on underneath the hood. To start, let’s look at the typical two-level Silverlight Tree View that has been hard coded with the values shown below: <sdk:TreeView>  <sdk:TreeViewItem Header="Managers">    <TextBlock Text="Michael" />    <TextBlock Text="Paul" />  </sdk:TreeViewItem>  <sdk:TreeViewItem Header="Supervisors">    <TextBlock Text="John" />    <TextBlock Text="Tim" />    <TextBlock Text="David" />  </sdk:TreeViewItem></sdk:TreeView> Figure 1 shows you how this tree view looks when you run the Silverlight application. Figure 1: A hard-coded, two level Tree View. Next, let’s create three classes to mimic the hard-coded Tree View shown above. First, you need an Employee class and an EmployeeType class. The Employee class simply has one property called Name. The constructor is created to accept a “name” argument that you can use to set the Name property when you create an Employee object. public class Employee{  public Employee(string name)  {    Name = name;  }   public string Name { get; set; }} Finally you create an EmployeeType class. This class has one property called EmpType and contains a generic List<> collection of Employee objects. The property that holds the collection is called Employees. public class EmployeeType{  public EmployeeType(string empType)  {    EmpType = empType;    Employees = new List<Employee>();  }   public string EmpType { get; set; }  public List<Employee> Employees { get; set; }} Finally we have a collection class called EmployeeTypes created using the generic List<> class. It is in the constructor for this class where you will build the collection of EmployeeTypes and fill it with Employee objects: public class EmployeeTypes : List<EmployeeType>{  public EmployeeTypes()  {    EmployeeType type;            type = new EmployeeType("Manager");    type.Employees.Add(new Employee("Michael"));    type.Employees.Add(new Employee("Paul"));    this.Add(type);     type = new EmployeeType("Project Managers");    type.Employees.Add(new Employee("Tim"));    type.Employees.Add(new Employee("John"));    type.Employees.Add(new Employee("David"));    this.Add(type);  }} You now have a data hierarchy in memory (Figure 2) which is what the Tree View control expects to receive as its data source. Figure 2: A hierachial data structure of Employee Types containing a collection of Employee objects. To connect up this hierarchy of data to your Tree View you create an instance of the EmployeeTypes class in XAML as shown in line 13 of Figure 3. The key assigned to this object is “empTypes”. This key is used as the source of data to the entire Tree View by setting the ItemsSource property as shown in Figure 3, Callout #1. Figure 3: You need to start from the bottom up when laying out your templates for a Tree View. The ItemsSource property of the Tree View control is used as the data source in the Hierarchical Data Template with the key of employeeTypeTemplate. In this case there is only one Hierarchical Data Template, so any data you wish to display within that template comes from the collection of Employee Types. The TextBlock control in line 20 uses the EmpType property of the EmployeeType class. You specify the name of the Hierarchical Data Template to use in the ItemTemplate property of the Tree View (Callout #2). For the second (and last) level of the Tree View control you use a normal <DataTemplate> with the name of employeeTemplate (line 14). The Hierarchical Data Template in lines 17-21 sets its ItemTemplate property to the key name of employeeTemplate (Line 19 connects to Line 14). The source of the data for the <DataTemplate> needs to be a property of the EmployeeTypes collection used in the Hierarchical Data Template. In this case that is the Employees property. In the Employees property there is a “Name” property of the Employee class that is used to display the employee name in the second level of the Tree View (Line 15). What is important here is that your lowest level in your Tree View is expressed in a <DataTemplate> and should be listed first in your Resources section. The next level up in your Tree View should be a <HierarchicalDataTemplate> which has its ItemTemplate property set to the key name of the <DataTemplate> and the ItemsSource property set to the data you wish to display in the <DataTemplate>. The Tree View control should have its ItemsSource property set to the data you wish to display in the <HierarchicalDataTemplate> and its ItemTemplate property set to the key name of the <HierarchicalDataTemplate> object. It is in this way that you get the Tree View to display all levels of your hierarchical data structure. Three Levels in a Tree View Now let’s expand upon this concept and use three levels in our Tree View (Figure 4). This Tree View shows that you now have EmployeeTypes at the top of the tree, followed by a small set of employees that themselves manage employees. This means that the EmployeeType class has a collection of Employee objects. Each Employee class has a collection of Employee objects as well. Figure 4: When using 3 levels in your TreeView you will have 2 Hierarchical Data Templates and 1 Data Template. The EmployeeType class has not changed at all from our previous example. However, the Employee class now has one additional property as shown below: public class Employee{  public Employee(string name)  {    Name = name;    ManagedEmployees = new List<Employee>();  }   public string Name { get; set; }  public List<Employee> ManagedEmployees { get; set; }} The next thing that changes in our code is the EmployeeTypes class. The constructor now needs additional code to create a list of managed employees. Below is the new code. public class EmployeeTypes : List<EmployeeType>{  public EmployeeTypes()  {    EmployeeType type;    Employee emp;    Employee managed;     type = new EmployeeType("Manager");    emp = new Employee("Michael");    managed = new Employee("John");    emp.ManagedEmployees.Add(managed);    managed = new Employee("Tim");    emp.ManagedEmployees.Add(managed);    type.Employees.Add(emp);     emp = new Employee("Paul");    managed = new Employee("Michael");    emp.ManagedEmployees.Add(managed);    managed = new Employee("Sara");    emp.ManagedEmployees.Add(managed);    type.Employees.Add(emp);    this.Add(type);     type = new EmployeeType("Project Managers");    type.Employees.Add(new Employee("Tim"));    type.Employees.Add(new Employee("John"));    type.Employees.Add(new Employee("David"));    this.Add(type);  }} Now that you have all of the data built in your classes, you are now ready to hook up this three-level structure to your Tree View. Figure 5 shows the complete XAML needed to hook up your three-level Tree View. You can see in the XAML that there are now two Hierarchical Data Templates and one Data Template. Again you list the Data Template first since that is the lowest level in your Tree View. The next Hierarchical Data Template listed is the next level up from the lowest level, and finally you have a Hierarchical Data Template for the first level in your tree. You need to work your way from the bottom up when creating your Tree View hierarchy. XAML is processed from the top down, so if you attempt to reference a XAML key name that is below where you are referencing it from, you will get a runtime error. Figure 5: For three levels in a Tree View you will need two Hierarchical Data Templates and one Data Template. Each Hierarchical Data Template uses the previous template as its ItemTemplate. The ItemsSource of each Hierarchical Data Template is used to feed the data to the previous template. This is probably the most confusing part about working with the Tree View control. You are expecting the content of the current Hierarchical Data Template to use the properties set in the ItemsSource property of that template. But you need to look to the template lower down in the XAML to see the source of the data as shown in Figure 6. Figure 6: The properties you use within the Content of a template come from the ItemsSource of the next template in the resources section. Summary Understanding how to put together your hierarchy in a Tree View is simple once you understand that you need to work from the bottom up. Start with the bottom node in your Tree View and determine what that will look like and where the data will come from. You then build the next Hierarchical Data Template to feed the data to the previous template you created. You keep doing this for each level in your Tree View until you get to the last level. The data for that last Hierarchical Data Template comes from the ItemsSource in the Tree View itself. NOTE: You can download the sample code for this article by visiting my website at http://www.pdsa.com/downloads. Select “Tips & Tricks”, then select “Silverlight TreeView with Multiple Levels” from the drop down list.

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  • Create MAPI profile for exchange 2007 without Outlook

    - by despart
    Hi, I have a windows server 2003 where I have to create a MAPI profile to read incoming emails of exchange 2007, using a custom utility. I googled a lot and seems that there was a way to do it with newprof.exe utility but it is no longer available. I don't have an outlook license so I need a free way to create MAPI profiles in this server. Thanks. David.

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  • What is the Dell E772c CRT Screen kWh consumption

    - by r0ca
    I have a Dell CRT Screen and the only info I have is this: AC input voltage / frequency / current : 90 to 264 VAC / 50 or 60 Hz + 3 Hz / 1.5 A max. (RMS) at 120 VAC and 0.8 A max.(RMS) at 220 VAC How can I calcultate the energy consumption in Watt for an hour or better, a day. Regards, David.

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  • How to change time (Advanced Eastern Time) on Slackware 8.1

    - by r0ca
    Hi all, I have a linux (Slackware) machine and the time/date is like, June 23rd 2003, 10:00am (It's 11 here) and I am not able to set the time to have it correct. I change the timezome to Montreal but the time is still wrong. Is there a way to force it to sync with my domain controler or even another online NTP server? Thanks, David.

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  • Create MAPI profile for exchange 2007 without MAPI client

    - by despart
    Hi, I have a windows server 2003 where I have to create a MAPI profile to read incoming emails of exchange 2007, using a custom utility. I googled a lot and seems that there was a way to do it with newprof.exe utility but it is no longer available. I don't have an outlook license so I need a free way to create MAPI profiles in this server. Thanks. David.

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  • Apache stopped serving all sites

    - by user36158
    Hi Everyone Hope you can help me, up until last night all sites on my server were displaying fine but now whenever you visit any of them you get the default - "Welcome to Your New Home in Cyberspace!" page - all the domains are setup right, have been working and were working until last night and i haven't edited any of the apache files so i really can't see why they have broken, i am using Debian and all the sites have been activated Really hope someone can help me David

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  • Opendns like 404 page [migrated]

    - by Dmbekker
    People who use OpenDNS and go to a non-existing domain are getting a nice fancy search page telling them that the domain doesn't exists instead of the browser error page. here in my home network we have a win 2008-r2 server with the dns role enabled. Is there any way to make my own fancy looking error page to show up at all computers when they enter a domain not found by the local dns server and the Forwarders / root hints servers? -- David,

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  • VM guest cloning.

    - by davidyuz
    I am able to make a copy of my existing VM guest folder and another folder on my datasource (trying to clone this vm to a new vm). However, I can't seem to add a way to add it to the inventory so that I could start it up. Any suggestion on this matter? I'm using ESX4 Thanks David.

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  • need help with jquery selectors

    - by photographer
    I've got code like that: <ul class="gallery_demo_unstyled"> <li class="active"><img src='001.jpg' /></li> <li><img src='002.jpg' /></li> <li><img src='003.jpg' /></li> <li><img src='004.jpg' /></li> <li><img src='005.jpg' /></li> <li><img src='006.jpg' /></li> </ul> <div class="Paginator"> <a href="../2/" class="Prev">&lt;&lt;</a> <a href="../1/">1</a> <a href="../2/">2</a> <span class="this-page">3</span> <a href="../4/">4</a> <a href="../5/">5</a> <a href="../4/" class="Next">&gt;&gt;</a> </div> <div class="Albums"><div class="AlbumsMenu"> <p><b>ALBUMS</b></p> <p><a href="../../blackandwhite/1/" >blackandwhite</a></p> <p><a href="../../color/1/" class='this-page'>>>color</a></p> <p><a href="../../film/1/" >film</a></p> <p><a href="../../digital/1/" >digital</a></p> <p><a href="../../portraits/1/" >portraits</a></p> </div></div> ...and some JavaScript/jQuery allowing to cycle through the images (the very top li elements) going back to the first image after the last one: $$.nextSelector = function(selector) { return $(selector).is(':last-child') ? $(selector).siblings(':first-child') : $(selector).next(); }; Current page is always 'this-page' class (span or p in my case, but I could change that if necessary). The question: what should I change in my code to make it go after the last image to the next page instead of cycling through the page over and over again, and after the last page to the next album? And to the first image on the first page of the first album after the last-last-last (or just stop there — don't really care)?

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  • phpmailer with hotmail?

    - by nikola
    I'm trying to send emails from my server by a PHP script. I used to send it by a native php function mail and everything worked OK. Here's the code I used: $to = $sMail;<br> $subject = $sSubject;<br> $message = $sMessage; $headers = 'From: [email protected]' . "\r\n";<br> $headers .= 'Reply-To: [email protected]' . "\r\n";<br> $headers .= 'MIME-Version: 1.0' . "\r\n";<br> $headers .= 'Content-type: text/html; charset=UTF-8' . "\r\n";<br> $bRes = mail($to, $subject, $message, $headers); I then switched to PHPMailer, and wasn't able to send mail to Hotmail accounts (all the other still worked). Hotmail server reports the error: "550 SC-001 Mail rejected by Windows Live Hotmail for policy reasons." This is the code I used for PHPMailer: $mail = new PHPMailer();<br> $mail->IsHTML(true);<br> $mail->CharSet = 'UTF-8';<br> $mail->From = '[email protected]';<br> $mail->FromName = 'domain.com';<br> $mail->Subject = $sSubject;;<br> $mail->Body = $sMessage;<br> $mail->AltBody = strip_tags($sMessage;);<br> $mail->AddAddress($sMail);<br> $mail->Send();<br> $mail->ClearAddresses();<br> $mail->ClearAttachments(); As the sending works with the native function, I'm sure my server is able to send mails to hotmail. There must be a property to set when using PHPMailer, but I can't seem to find the right one. Anyone knows something abouth this? Thank you very much!

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  • Filter chain halted as [:login_required] rendered_or_redirected

    - by Magicked
    Hopefully I can explain this well enough, but please let me know if more information is needed! I'm building a form where a user can create an "incident". This incident has the following relationships: belongs_to: customer (customer has_many incidents) belongs_to: user (user has_many incidents) has_one: incident_status (incident_status belongs to incident) The form allows the user to assign the incident to a user (select form) and then select an incident status. The incident is nested in customer. However, I'm getting the following in the server logs: Processing IncidentsController#create (for 127.0.0.1 at 2010-04-26 10:41:33) [POST] Parameters: {"commit"=>"Create", "action"=>"create", "authenticity_token"=>"YhW++vd/dnLoNV/DSl1DULcaWq/RwP7jvLOVx9jQblA=", "customer_id"=>"4", "controller"=>"incidents", "incident"=>{"title"=>"Some Bad Incident", "incident_status_id"=>"1", "user_id"=>"2", "other_name"=>"SS01-042310-001"}} User Load (0.3ms) SELECT * FROM "users" WHERE ("users"."id" = 2) LIMIT 1 Redirected to http://localhost:3000/session/new Filter chain halted as [:login_required] rendered_or_redirected. Completed in 55ms (DB: 0) | 302 Found [http://localhost/customers/4/incidents] It looks to me like it's trying to gather information about the user, even though it already has the id (which is all it needs to create the incident), and the user may not have permission to do a select statement like that? I'm rather confused. Here is the relevant (I think) information in the Incident controller. before_filter :login_required, :get_customer def new @incident = @customer.incidents.build @users = @customer.users @statuses = IncidentStatus.find(:all) respond_to do |format| format.html # new.html.erb format.xml { render :xml => @incident } end end def create @incident = @customer.incidents.build(params[:incident]) respond_to do |format| if @incident.save flash[:notice] = 'Incident was successfully created.' format.html { redirect_to(@incident) } format.xml { render :xml => @incident, :status => :created, :location => @incident } else format.html { render :action => "new" } format.xml { render :xml => @incident.errors, :status => :unprocessable_entity } end end end Just as an FYI, I am using the restful_authentication plugin. So in summary, when I submit the incident creation form, it does not save the incident because it halts. I'm still very new to rails, so my skill at diagnosing problems like this is still very bad. I'm going in circles. :) Thanks in advance for any help. Please let me know if more information is needed and I'll edit it in!

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  • Error trying to run rails server

    - by David87
    I am trying to get a basic Rails application to run on my Mac OS X 10.6.5. I created a new app called demo (rails new demo), then went into the demo directory and tried to start the app with rails server. Here is the error message I received: "/Users/dpetrovi/.gem/ruby/1.8/gems/sqlite3-ruby-1.3.2/lib/sqlite3/sqlite3_native.bundle: [BUG] Segmentation fault ruby 1.8.7 (2010-12-23 patchlevel 330) [i686-darwin10] Abort trap" I checked bundle install in the demo folder: "Using rake (0.8.7) Using abstract (1.0.0) Using activesupport (3.0.3) Using builder (2.1.2) Using i18n (0.5.0) Using activemodel (3.0.3) Using erubis (2.6.6) Using rack (1.2.1) Using rack-mount (0.6.13) Using rack-test (0.5.6) Using tzinfo (0.3.23) Using actionpack (3.0.3) Using mime-types (1.16) Using polyglot (0.3.1) Using treetop (1.4.9) Using mail (2.2.13) Using actionmailer (3.0.3) Using arel (2.0.6) Using activerecord (3.0.3) Using activeresource (3.0.3) Using bundler (1.0.7) Using thor (0.14.6) Using railties (3.0.3) Using rails (3.0.3) Using sqlite3-ruby (1.3.2) Your bundle is complete! Use bundle show [gemname] to see where a bundled gem is installed." Ruby, RubyGems, and sqlite3 were installed using MacPorts. Then I used gem to try to install the sqlite3-ruby interface. (sudo gem install sqlite3-ruby). Here is where I first noticed something could be off: "Successfully installed sqlite3-ruby-1.3.2 1 gem installed Installing ri documentation for sqlite3-ruby-1.3.2... No definition for libversion Enclosing class/module 'mSqlite3' for class Statement not known Installing RDoc documentation for sqlite3-ruby-1.3.2... No definition for libversion Enclosing class/module 'mSqlite3' for class Statement not known " I had rails running well on my system a few months ago, so I figured maybe I had some duplicates and it was trying to use the wrong one. I ran: "for cmd in ruby irb gem rake; do which $cmd; done" and got: "/opt/local/bin/ruby /opt/local/bin/irb /opt/local/bin/gem /opt/local/bin/rake" Checking where sqlite3 also gets me: "/opt/local/bin/sqlite3" so they all seem to be in the right place. Obviously /opt/local/bin is in my system path. If I check gems server, it shows that I have installed sqlite3-ruby 1.3.2 gem. Not sure what the problem could be? I am using ruby 1.8.7 (2010-12-23 patchlevel 330) [i686-darwin10]. Macports claims this is the latest (although ive seen 1.9.1) One more thing-- in irb, I tried to check which version of sqlite3 my sqlite3-ruby is bound to, but I can only get this far: ":irb(main):001:0 require 'rubygems' = true irb(main):002:0 require 'sqlite3' /Users/dpetrovi/.gem/ruby/1.8/gems/sqlite3-ruby-1.3.2/lib/sqlite3/sqlite3_native.bundle: [BUG] Segmentation fault ruby 1.8.7 (2010-12-23 patchlevel 330) [i686-darwin10] Abort trap" Any suggestions? Im hoping I overlooked something obvious. Thanks

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  • flickr.photos.search strange behavior with nested xml response

    - by JohnIdol
    I am querying flickr with the following request: view-source:http://www.flickr.com/services/rest/?method=flickr.photos.search&api_key=MY_KEY&text=cork&per_page=12&&format=rest if I put the above url in the browser I get the following as I would expect: <rsp stat="ok"> <photos page="1" pages="22661" perpage="12" total="271924"> <photo id="4587565363" owner="46277999@N05" secret="717118838d" server="4029" farm="5" title="06052010(001)" ispublic="1" isfriend="0" isfamily="0" /> <photo id="4587466773" owner="25901874@N06" secret="32c5a1a57f" server="4002" farm="5" title="black wine cork 2 BW" ispublic="1" isfriend="0" isfamily="0" /> <photo id="4588084730" owner="25901874@N06" secret="b27eef5635" server="4032" farm="5" title="black wine cork 2" ispublic="1" isfriend="0" isfamily="0" /> <photo id="4587457789" owner="43115275@N00" secret="ae0daa0ab6" server="4034" farm="5" title="Matthew" ispublic="1" isfriend="0" isfamily="0" /> <photo id="4587443837" owner="49967920@N07" secret="2b4c1a58de" server="4066" farm="5" title="Two car garage" ispublic="1" isfriend="0" isfamily="0" /> <photo id="4588050906" owner="45827769@N06" secret="72de138f7e" server="4067" farm="5" title="Dabie Mountains, Central China" ispublic="1" isfriend="0" isfamily="0" /> <photo id="4587979300" owner="36531359@N00" secret="e5f8b30734" server="3299" farm="4" title="stroll" ispublic="1" isfriend="0" isfamily="0" /> <photo id="4587304769" owner="7904649@N02" secret="995062f550" server="4034" farm="5" title="IMG_4325" ispublic="1" isfriend="0" isfamily="0" /> <photo id="4587306827" owner="7904649@N02" secret="b92d7ff916" server="4050" farm="5" title="IMG_4329" ispublic="1" isfriend="0" isfamily="0" /> <photo id="4587311657" owner="7904649@N02" secret="bb1b34ccf8" server="4053" farm="5" title="IMG_4336" ispublic="1" isfriend="0" isfamily="0" /> <photo id="4587933110" owner="7904649@N02" secret="f733b1d482" server="3300" farm="4" title="IMG_4334" ispublic="1" isfriend="0" isfamily="0" /> <photo id="4587930650" owner="7904649@N02" secret="9bc202b3ed" server="4018" farm="5" title="IMG_4331" ispublic="1" isfriend="0" isfamily="0" /> </photos> </rsp> Now I've got something very simple PHP to query the exact same url, called from javascript through AJAX - it all works as I can see putting a breakpoint in my javascript function that handles the response: function HandleResponse(response) { document.getElementById('ResponseDiv').innerHTML = response; } Looking at response value in the snippet above I see what I expect (xml formed as above) - then the strangest thing happens: when I inspect the DOM instead of having photo elements all as children of photos they're all nested within each other. What amI missing - How is this possible in light of the fact that the response string is definitely formed as I would expect it to be?

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  • Flex: convert VideoPlayer.currentTime to string "00:00:00:000"

    - by numediaweb
    Hi there! what about this one: I want to format the currentTime displayed by a videoPlayer component inside flex, something like : 8230.999 to something like 01:59:59:999 which is "hours:minutes:seconds:milliseconds" I trie different sets of codes but they can't get it to work because currentTime is nor a correct miliseconds time as it adds a floating 3 digit point to seconds; so instead of : 2000ms it outputs 2.000 something people like me just can't understand! thanx for any help :) ### UPDATE I still have problem with milliseconds. here's the current MXML: <?xml version="1.0" encoding="utf-8"?> <s:Application xmlns:fx="http://ns.adobe.com/mxml/2009" xmlns:s="library://ns.adobe.com/flex/spark" xmlns:mx="library://ns.adobe.com/flex/mx" minWidth="955" minHeight="600"> <fx:Script> <![CDATA[ protected function convert_clickHandler(event:MouseEvent):void { var val:Number = new Number(inPut.text); //inPut.text = 1000.001 //val = val * 1000; outPut.text = timeFormat(val); } public static function timeFormat(value:Number):String { var milliseconds:Number = value % 1000; var seconds:Number = Math.floor((value/1000) % 60); var minutes:Number = Math.floor((value/60000) % 60); var hours:Number = Math.floor((value/3600000) % 24); var s_miliseconds:String = (milliseconds<10 ? "00" : (milliseconds<100 ? "0" : ""))+ String(milliseconds); var s_seconds:String = seconds < 10 ? "0" + String(seconds) : String(seconds); var s_minutes:String = minutes < 10 ? "0" + String(minutes) : String(minutes); var s_hours:String = hours < 10 ? "0" + String(hours) : String(hours); return s_hours + ":" + s_minutes + ":" + s_seconds + '.'+s_miliseconds; // returns 00:00:01.000.0009999999999763531 should return 00:00:01.001 // I still have problem with milliseconds } ]]> </fx:Script> <fx:Declarations> <!-- Place non-visual elements (e.g., services, value objects) here --> </fx:Declarations> <s:TextInput x="240" y="72" id="inPut" text="1000.001"/> <s:TextInput x="240" y="140" id="outPut"/> <s:Button x="274" y="107" label="convert" id="convert" click="convert_clickHandler(event)"/> </s:Application>

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