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  • Unpredictable CCK field name in returned View data

    - by AK
    I'm using views_get_view_result to directly access the data in a view. I've stumbled upon this odd behavior where cck fields are prefixed with the first field name as a query optimization. Explained here. What's bizarre though is that fields are named differently depending on whether I retrieve that data as Anonymous or as Admin. I'm pretty sure all my permissions are set up, and the view itself has no restrictions. What is going on here? This is a big problem since I can't know how to retrieve a field. Here's a dump of the two view results. Notice that node_data_field_game_date_field_game_home_score_value != node_data_field_game_official_field_game_home_score_value. // View as Admin stdClass Object ( [nid] => 3191 [node_data_field_game_date_field_game_date_value] => 2010-03-27T00:00:00 [node_type] => game [node_vid] => 5039 [node_data_field_game_date_field_game_official_value] => 0 [node_node_data_field_game_home_team_title] => TeamA [node_node_data_field_game_home_team_nid] => 3396 [node_data_field_game_date_field_game_home_score_value] => 68 [node_node_data_field_game_visitor_team_title] => TeamB [node_node_data_field_game_visitor_team_nid] => 3442 [node_data_field_game_date_field_game_visitor_score_value] => 118 ) // View as Anonymous stdClass Object ( [nid] => 3191 [node_data_field_game_date_field_game_date_value] => 2010-03-27T00:00:00 [node_type] => game [node_vid] => 5039 [node_data_field_game_official_field_game_official_value] => 0 [node_node_data_field_game_home_team_title] => TeamA [node_node_data_field_game_home_team_nid] => 3396 [node_data_field_game_official_field_game_home_score_value] => 68 [node_node_data_field_game_visitor_team_title] => TeamB [node_node_data_field_game_visitor_team_nid] => 3442 [node_data_field_game_official_field_game_visitor_score_value] => 118 )

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  • [N]Hibernate: view-like fetching properties of associated class

    - by chiccodoro
    (Felt quite helpless in formulating an appropriate title...) In my C# app I display a list of "A" objects, along with some properties of their associated "B" objects and properties of B's associated "C" objects: A.Name B.Name B.SomeValue C.Name Foo Bar 123 HelloWorld Bar Hello 432 World ... To clarify: A has an FK to B, B has an FK to C. (Such as, e.g. BankAccount - Person - Company). I have tried two approaches to load these properties from the database (using NHibernate): A fast approach and a clean approach. My eventual question is how to do a fast & clean approach. Fast approach: Define a view in the database which joins A, B, C and provides all these fields. In the A class, define properties "BName", "BSomeValue", "CName" Define a hibernate mapping between A and the View, whereas the needed B and C properties are mapped with update="false" insert="false" and do actually stem from B and C tables, but Hibernate is not aware of that since it uses the view. This way, the listing only loads one object per "A" record, which is quite fast. If the code tries to access the actual associated property, "A.B", I issue another HQL query to get B, set the property and update the faked BName and BSomeValue properties as well. Clean approach: There is no view. Class A is mapped to table A, B to B, C to C. When loading the list of A, I do a double left-join-fetch to get B and C as well: from A a left join fetch a.B left join fetch a.B.C B.Name, B.SomeValue and C.Name are accessed through the eagerly loaded associations. The disadvantage of this approach is that it gets slower and takes more memory, since it needs to created and map 3 objects per "A" record: An A, B, and C object each. Fast and clean approach: I feel somehow uncomfortable using a database view that hides a join and treat that in NHibernate as if it was a table. So I would like to do something like: Have no views in the database. Declare properties "BName", "BSomeValue", "CName" in class "A". Define the mapping for A such that NHibernate fetches A and these properties together using a join SQL query as a database view would do. The mapping should still allow for defining lazy many-to-one associations for getting A.B.C My questions: Is this possible? Is it [un]artful? Is there a better way?

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  • How to retrieve view of MultiIndex DataFrame

    - by Henry S. Harrison
    This question was inspired by this question. I had the same problem, updating a MultiIndex DataFrame by selection. The drop_level=False solution in Pandas 0.13 will allow me to achieve the same result, but I am still wondering why I cannot get a view from the MultiIndex DataFrame. In other words, why does this not work?: >>> sat = d.xs('sat', level='day', copy=False) Traceback (most recent call last): File "<stdin>", line 1, in <module> File "C:\Python27\lib\site-packages\pandas\core\frame.py", line 2248, in xs raise ValueError('Cannot retrieve view (copy=False)') ValueError: Cannot retrieve view (copy=False) Of course it could be only because it is not implemented, but is there a reason? Is it somehow ambiguous or impossible to implement? Returning a view is more intuitive to me than returning a copy then later updating the original. I looked through the source and it seems this situation is checked explicitly to raise an error. Alternatively, is it possible to get the same sort of view from any of the other indexing methods? I've experimented but have not been successful. [edit] Some potential implementations are discussed here. I guess with the last question above I'm wondering what the current best solution is to index into arbitrary multiindex slices and cross-sections.

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  • Using indexes on/through a MySQL view

    - by Peeja
    We've got a MySQL table in which rows are never updated, but instead new rows are added and the old ones marked obsolete. Think Rails' acts_as_paranoid, but for every update. To make working with Rails sane, we've got a view which selects only the rows which are "current". That makes a much better "table" for our ActiveRecord model. The snag: our indexes aren't being used anymore. Queries on the view don't use the underlying tables' indexes. You can't add an index to a view. Without indexes, the app is unbearably slow. The only solution we've come up with is to build a materialized view, but that's a pain in MySQL because they're not natively supported. Is there a better way to do this?

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  • Configuration and Model-View

    - by HH
    I am using the Model-View pattern on a small application I'm writing. Here's the scenario: The model maintains a list of directories from where it can extract the data that it needs. The View has a Configuration or a Setting dialog where the user can modify this list of directories (the dialog has a JList displaying the list in addition to add and remove buttons). I need some advice from the community: The View needs to communicate these changes to the model. I thought first of adding to the model these methods: addDirectory() and removeDirectory(). But I am trying to limit the number of methods (or channels) that the View can use to communicate with and manipulate the model. Is there any good practice for this? Thank you.

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  • In partial view: "The model item passed into the dictionary is of type"

    - by Dave
    I lack understanding of some basic MVC concepts, despite all my searching. I created an MVC project in Visual Studio, which contains the partial view _LogOnPartial.shtml. I just want to access information within the view pertaining to the user, to put in a user dropdown menu. When I try to put this at the top of the partial view cshtml page I get the above error: @model MyProject_MVC.Models.UserRepository When I try this I also get an error: @Html.Partial("_LogOnPartial", MyProject_MVC.Models.UserRepository) 'MyProject_MVC.Models.UserRepository' is a 'type', which is not valid in the given context

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  • CCK NodeReference - Pass current user id as argument to selection view

    - by Chaulky
    Hi all, I'm trying to create a view to limit the options available to a user for a CCK NodeReference field. I want to pass the current user's ID as an argument to the view that selects the options for the CCK NodeReference field. Basically when the user creates a new item, I only want them to be able to reference a node which they created (not someone else's node). I've got a view set up that accepts a user ID as an argument, but how do I pass the current user's ID to the view from the CCK NodeReference field? Thanks in advance!!!

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  • How to determine the current view bounds in split view of Ipad App?

    - by Mahesh
    Hello friends, I have tried following code to determine current view bounds in shouldAutoRotate.. fn UIViewController *temp1 = [appDelegate.splitViewController.viewControllers objectAtIndex:1]; float screenwidth = temp1.view.bounds.size.width; float screenheight = temp1.view.bounds.size.height; bt actually when u rotate from one mode to another, it provides the bound values of old one insted the fresh bound values..? Any one know that how to achieve it?

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  • iPhone crashing when presenting modal view controller

    - by Michael Waterfall
    I'm trying to display a modal view straight after another view has been presented modally (the second is a loading view that appears). - (void)viewDidAppear:(BOOL)animated { [super viewDidAppear:animated]; // Show load LoadViewController *loader = [[LoadViewController alloc] init]; [self presentModalViewController: loader animated:NO]; [loader release]; } But when I do this I get a "Program received signal: "EXC_BAD_ACCESS"." error. The stack trace is: 0 0x30b43234 in -[UIWindowController transitionViewDidComplete:fromView:toView:] 1 0x3095828e in -[UITransitionView notifyDidCompleteTransition:] 2 0x3091af0d in -[UIViewAnimationState sendDelegateAnimationDidStop:finished:] 3 0x3091ad7c in -[UIViewAnimationState animationDidStop:finished:] 4 0x0051e331 in run_animation_callbacks 5 0x0051e109 in CA::timer_callback 6 0x302454a0 in CFRunLoopRunSpecific 7 0x30244628 in CFRunLoopRunInMode 8 0x32044c31 in GSEventRunModal 9 0x32044cf6 in GSEventRun 10 0x309021ee in UIApplicationMain 11 0x00002154 in main at main.m:14 Any ideas? I'm totally stumped! The loading view is empty so there's definitely nothing going on in there that's causing the error. Is it something to do with launching 2 views modally in the same event loop or something? Thanks, Mike Edit: Very strange... I have modified it slightly so that the loading view is shown after a tiny delay, and this works fine! So it appears to be something within the same event loop! - (void)viewDidAppear:(BOOL)animated { [super viewDidAppear:animated]; // Show load [self performSelector:@selector(doit) withObject:nil afterDelay:0.1]; } - (void)doit { [self presentModalViewController:loader animated:YES]; }

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  • modal view not showing inside didfinishpickingimage

    - by sebastien
    Hi, I have a viewcontroller, and I would like to display a modal view controller with : presentModalViewController when a user finished picking an image. The modal view controller is working fine when I call it from a button in my main view. But when I call it from didfinishpickingimage callback nothing happens. Thanks.

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  • explaining $this->load->view()

    - by ajsie
    in a controller you can use this method to load a view. but i want to know behind the scenes here. im new to php and frameworks, but i’ve learned the basics of OOP. when $this-view() is made then the method in the current class or the parent class is used. but what does this mean: $this-load-view(). what is the intermediate load? is it a function or is it a property? where is it located? how could it contain view()? grateful for explanation.

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  • How to make softkeyboard candidate view not block application view?

    - by Cedric
    Hi, I am playing with the Demo SoftKeyboard the comes with the Android SDK. In portrait mode when the candidate view is shown, it doesn't move the app up as the default android keyboard does. Hence it covers part of the application view. What should be changed in order to make the candidate view in the demo softkeyboard behave as the default android keyboard does? I've also looked at the source of the android keyboard from git but found nothing related to this behavior.

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  • Android return to the original position of the view after MotionEvent

    - by Kurty
    My application currently changes to another random int (View) when I let go of it (ACTION_UP) but the view stays in the same spot where I dropped it. I want it to return to the original location (the middle of the screen) when I drop it so I can repeat the process. // OnTouch and MotionEvent OnTouchListener dragt = new OnTouchListener() { public boolean onTouch(View v, MotionEvent me) { FrameLayout.LayoutParams par = (FrameLayout.LayoutParams) v.getLayoutParams(); switch (v.getId()) { case R.id.randomView: } switch(me.getAction()) { case MotionEvent.ACTION_MOVE: par.gravity = 0; par.setMargins((int)me.getRawX() - (v.getWidth())/2, (int)me.getRawY() - (v.getHeight())/2, 0, 0); v.setLayoutParams(par); break; case MotionEvent.ACTION_UP: // tallies score. score++; textScore.setText(String.valueOf(score)); // this generates the new view but the location is still the same color.setImageResource(mImageIds[rgenerator.nextInt(mImageIds.length)]); break; } return true; } };

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  • ListView is Widget(View) or Layout(Viewgroup)?

    - by Manoj Maurya
    Hi All, I need your help to explore few topics in Android. My understanding is Widget is View and Layout is ViewGroups in Android. I described the problems as below- Please go through the below links- developer.android.com/guide/topics/ui/custom-components.html- (add http:// in the beginning) developer.android.com/resources/tutorials/views/index.html - (add http:// in the beginning) In the first link ListView is included as Widget and in the Second link ListView has been shown as Layout. So, is ListView is Widget(View) or Layout(Viewgroup)? Same is the case for Spinner in Andriod developer.android.com/resources/tutorials/views/hello-spinner.html- (add http:// in the beginning) (Link- says Spinner is Widget(View)) developer.android.com/guide/topics/ui/layout-objects.html- (add http:// in the beginning) says Spinner is Layout(ViewGroup) So, Spinner is View or ViewGroup? Please update me with your views?

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  • Xcode: view references for a variable?

    - by David.Chu.ca
    I am new to Xcode. I am not sure if there is a way to view a variable's references just like "Find all references" in Visual Studio by right click on a var? For example, in my .h file, I would like to know or view all the references for property isSet: @interface MyInterface { ... BOOL isSet; // view all references to this var? ... }

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  • Performing multiple fetches in Core Data within the same view

    - by yesimarobot
    I have my CD store setup and everything is working. Once my initial fetch is performed, I need to perform several fetches based on calculations using the data from my first fetch. The examples provided from Apple are great, and helped me get everything going but I'm struggling with executing successive fetches. Any suggestions, or tutorial links are appreciated. Table View loads data from CD store. When a user taps a row it pushes a detail view The detail view loads details from CD. [THE ABOVE STEPS ARE ALL WORKING] I perform several calculations on the data fetched in the detail view. I need to then perform several other fetches based on the results of my calculations.

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  • How can I use different metadata for a Dynamic Data form view and the list view?

    - by ProfK
    We often need a summarised list view with more detailed form view. So far, the only two way I can think of doing this are using a 'custom' list or form view than uses a sumplimentary 'remove' or 'add' list of fields anb generalise this over all entity sets, or create a custom metadata provider that infers somehow which columns to supply. Are there any other ways of distinguishing these two views? PS, I wrote a fun little general details page, that handles insert, edit, and view, all on one page template. Maybe I could somehow use that? It's here.

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  • Render partial view with updated value.

    - by janiya
    I am working on asp.net mvc project using views and partial views. Multiple partial views are being rendered in single view. Now my problem is that when ever i update some values in partial view and render it again through controller it does not show partial view with updated value.... to see updated value i have to refresh the page each time.

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  • Date and time picker in one view...

    - by Rahul Varma
    Hi guys, I wanted to know whether we can implement both date and time picker in one view... In iphone app you can pick both date and time through one view. But in android we have date picker and time picker seperately. So, is there any method by which i can get values of both date and time from one view???

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