Search Results

Search found 13135 results on 526 pages for 'actor model'.

Page 128/526 | < Previous Page | 124 125 126 127 128 129 130 131 132 133 134 135  | Next Page >

  • ASP.NET MVC - creating and handling with URLs with Greater Than and Less Than characters

    - by pcampbell
    Consider a link to a page for a user's profile. A page is creating that URL like this: //Model.Name has value "<bad guy>" Html.ActionLink("foo, "ViewUser", new { id=5, title=Url.Encode(Model.Name) }) The actual outcome was http://mysite/Users/5/%253cbad%2guy%253e When navigating to that URL, the server generates a HTTP Error 400 - Bad Request. Question: Given that the Model.Name may contain Unicode characters, or characters otherwise illegal in URLs, what's the best way to strip out illegal characters, or otherwise encode them? The problem surfaces when testing out 'interesting' user inputs with < and >, but anything could come from the user, and therefore be put in a URL by way of Model.Name.

    Read the article

  • Limit foreign key choices in select in an inline form in admin

    - by mightyhal
    Edited :-) Hopefully a bit clearer now. The logic is of the model is: A Building has many Rooms A Room may be inside another Room (a closet, for instance--ForeignKey on 'self') A Room can only in inside of another Room in the same building (this is the tricky part) Here's the code I have: #spaces/models.py from django.db import models class Building(models.Model): name=models.CharField(max_length=32) def __unicode__(self): return self.name class Room(models.Model): number=models.CharField(max_length=8) building=models.ForeignKey(Building) inside_room=models.ForeignKey('self',blank=True,null=True) def __unicode__(self): return self.number and: #spaces/admin.py from ex.spaces.models import Building, Room from django.contrib import admin class RoomAdmin(admin.ModelAdmin): pass class RoomInline(admin.TabularInline): model = Room extra = 2 class BuildingAdmin(admin.ModelAdmin): inlines=[RoomInline] admin.site.register(Building, BuildingAdmin) admin.site.register(Room) The inline will display only rooms in the current building (which is what I want). The problem, though, is that for the inside_room drop down, it displays all of the rooms in the Rooms table (including those in other buildings). In the inline of rooms, I need to limit the inside_room choices to only rooms which are in the current building being displayed by the main form. I can't figure out a way to do it with either a limit_choices_to in the model, nor can I figure out how exactly to override the admin's inline formset properly (I feel like I should be somehow create a custom inline form, pass the building_id of the main form to the custom inline, then limit the queryset for the field's choices based on that--but I just can't wrap my head around how to do it). Maybe this is too complex for the admin site, but it seems like something that would be generally useful... Thanks again for your help!

    Read the article

  • Generic relations missing with grappelli

    - by diegueus9
    I'm using the last svn revision of grappelli and rev 11840 of django (before multidatabases and stuff), and i'm trying to use generic relations in the admin, but doesn't work, The model: class AutorProyectoLey(DatedModel): tipo_autor = models.ForeignKey(ContentType) autor_id = models.PositiveIntegerField() content_object = generic.GenericForeignKey('tipo_autor', 'autor_id') proyecto_ley = models.ForeignKey(ProyectoLey) The admin: class AutorInline(GenericInlineModelAdmin): model = AutorProyectoLey allow_add = True ct_field = 'tipo_autor' ct_fk_field = 'autor_id' classes = ('collapse-open',) And i put this model of var inlines in another adminmodel, but the html render is : <!-- Inlines --> <!-- Submit-Row -->

    Read the article

  • Why isn't django-nose running the doctests in my models?

    - by Conley Owens
    I'm trying to use doctests with django-nose. All my doctests are running, except not any doctests within a model (unless it is abstract). class TestModel1(models.Model): """ >>> print 'pass' pass """ pass class TestModel2(models.Model): """ >>> print 'pass' pass """ class Meta: abstract = True pass The first doctest does not run and the second does. Why is this?

    Read the article

  • How to display total record count against models in django admin

    - by Rog
    Is there a neat way to make the record/object count for a model appear on the main model list in the admin module? I have found techniques for showing counts of related objects within sets in the list_display page (and I can see the total in the pagination section at the bottom of the same), but haven't come across a neat way to show the record count at the model list level.

    Read the article

  • ASP.Net MVC 3 Full Name In DropDownList

    - by tgriffiths
    I am getting a bit confused with this and need a little help please. I am developing a ASP.Net MVC 3 Web application using Entity Framework 4.1. I have a DropDownList on one of my Razor Views, and I wish to display a list of Full Names, for example Tom Jones Michael Jackson James Brown In my Controller I retrieve a List of User Objects, then select the FirstName and LastName of each User, and pass the data to a SelectList. List<User> Requesters = _userService.GetAllUsersByTypeIDOrgID(46, user.organisationID.Value).ToList(); var RequesterNames = from r in Requesters let person = new { UserID = r.userID, FullName = new { r.firstName, r.lastName } } orderby person.FullName ascending select person; viewModel.RequestersList = new SelectList(RequesterNames, "UserID", "FullName"); return View(viewModel); In my Razor View I have the following @Html.DropDownListFor(model => model.requesterID, Model.RequestersList, "Select", new { @class = "inpt_a"}) @Html.ValidationMessageFor(model => model.requesterID) However, when I run the code I get the following error At least one object must implement IComparable. I feel as if I am going about this the wrong way, so could someone please help with this? Thanks.

    Read the article

  • c#: IsNullableType helper class ?

    - by mark smith
    Hi there, Can anyone help? I have some code that is shared between 2 projects. The code points to a model which basically is a collection of properties that comes from a db. Problem being is that some properties use nullable types in 1 model and the other it doesn't Really the dbs should use the same but they don't .. so for example there is a property called IsAvailble which uses "bool" in one model and the other it uses bool? (nullable type) so in my code i do the following objContract.IsAvailble.Value ? "Yes" : "No" //notice the property .VALUE as its a bool? (nullable type) but this line will fail on model that uses a standard "bool" (not nullable) as there is no property .VALUE on types that are NOT nullable Is there some kind of helper class that i check if the property is a nullable type and i can return .Value .. otherwise i just return the property. Anybody have a solution for this?

    Read the article

  • How to import a resource when using Castle Windsor

    - by Gilbert
    Hi, When using spring.net, i can use <springDestinations> <objects xmlns="http://www.springframework.net"> <import resource="file://~/Config/blablabla.xml"/> </objects> </springDestinations> Using Castle Windsor, i have the following components <components> <component id="Retriever" service="Model.Services.Remote.IRetriever, Model" type="Model.Services.Remote.Retriever, Model"> <parameters> <resourceUrl>http://localhost:8888/Service.svc/</resourceUrl> </parameters> </component> </components> I'd like to to hold my components in a separate xml file for production, development etc etc. Can this be done with Castle Windsor? Thanks :-)

    Read the article

  • Access and modify attributes/objects which are not part of the form backing bean

    - by spa
    I use Spring MVC (via Spring Roo) to build a small web application for administering persons. In the page for creating a person the bean Person is used as form backing object (key "person" in the model map). <form:form action="${form_url}" method="POST" modelAttribute="person"> I would like to add some attributes to the model map which can be altered by the user in the creation form. Basically, I try to add a Boolean, so that I can control which page is displayed next after the user presses the submit button. I try to modify the Boolean (key "myBoolean" in the model map) using a simple checkbox: <form:checkbox id="_myboolean_id" path="myBoolean"/> However, as I am new to Spring MVC I have some difficulties here. The Boolean object is not an attribute of the form backing object. So if I try to access it the following exception is thrown (of course): Invalid property 'myBoolean' of bean class [de.cm.model.Person]: Bean property 'myBoolean' is not readable or has an invalid getter method: Does the return type of the getter match the parameter type of the setter? Is there are way to access a value of the model map directly? The only solution I can imagine right now is a kind of wrapper object around the class Person and my additional attributes which is used as a new form backing object. However, this is more work for a IMHO simple task. Do you have a better solution?

    Read the article

  • django: Display image in admin interface

    - by Oleg Tarasenko
    Hi, I've defined a model which contains a link an image. Is there a way to display the image in the model items list. (e.g. if I defined an article this way: class Article(models.Model): url = models.CharField(max_length = 200, unique = True, help_text="/lessons/") title = models.CharField(max_length = 500) img = models.CharField(max_length = 100) # Contains path to image def __unicode__(self): return u"%s" %title ) Is there a way to display image together with title?

    Read the article

  • Html.BeginForm() not rendering properly

    - by Taskos George
    While searching in stackoverflow the other questions didn't exactly helped in my situation. How it would be possible to debug such an error like the one that the Html.BeginForm does not properly rendered to the page. I use this code @model ExtremeProduction.Models.SelectUserGroupsViewModel @{ ViewBag.Title = "User Groups"; } <h2>Groups for user @Html.DisplayFor(model => model.UserName)</h2> <hr /> @using (Html.BeginForm("UserGroups", "Account", FormMethod.Post, new { encType = "multipart/form-data", id = "userGroupsForm" })) { @Html.AntiForgeryToken() <div class="form-horizontal"> @Html.ValidationSummary(true) <div class="form-group"> <div class="col-md-10"> @Html.HiddenFor(model => model.UserName) </div> </div> <h4>Select Group Assignments</h4> <br /> <hr /> <table> <tr> <th> Select </th> <th> Group </th> </tr> @Html.EditorFor(model => model.Groups) </table> <br /> <hr /> <div class="form-group"> <div class="col-md-offset-2 col-md-10"> <input type="submit" value="Save" class="btn btn-default" /> </div> </div> </div> } <div> @Html.ActionLink("Back to List", "Index") </div> EDIT: Added the Model // Wrapper for SelectGroupEditorViewModel to select user group membership: public class SelectUserGroupsViewModel { public string UserName { get; set; } public string FirstName { get; set; } public string LastName { get; set; } public List<SelectGroupEditorViewModel> Groups { get; set; } public SelectUserGroupsViewModel() { this.Groups = new List<SelectGroupEditorViewModel>(); } public SelectUserGroupsViewModel(ApplicationUser user) : this() { this.UserName = user.UserName; this.FirstName = user.FirstName; this.LastName = user.LastName; var Db = new ApplicationDbContext(); // Add all available groups to the public list: var allGroups = Db.Groups; foreach (var role in allGroups) { // An EditorViewModel will be used by Editor Template: var rvm = new SelectGroupEditorViewModel(role); this.Groups.Add(rvm); } // Set the Selected property to true where user is already a member: foreach (var group in user.Groups) { var checkUserRole = this.Groups.Find(r => r.GroupName == group.Group.Name); checkUserRole.Selected = true; } } } // Used to display a single role group with a checkbox, within a list structure: public class SelectGroupEditorViewModel { public SelectGroupEditorViewModel() { } public SelectGroupEditorViewModel(Group group) { this.GroupName = group.Name; this.GroupId = group.Id; } public bool Selected { get; set; } [Required] public int GroupId { get; set; } public string GroupName { get; set; } } public class Group { public Group() { } public Group(string name) : this() { Roles = new List<ApplicationRoleGroup>(); Name = name; } [Key] [Required] public virtual int Id { get; set; } public virtual string Name { get; set; } public virtual ICollection<ApplicationRoleGroup> Roles { get; set; } } ** EDIT ** And I get this form http://i834.photobucket.com/albums/zz268/gtas/formmine_zpsf6470e02.png I should receive a form like the one that I copied the code like this http://i834.photobucket.com/albums/zz268/gtas/formcopied_zpsdb2f129e.png Any ideas where or how to look the source of evil that makes my life hard for some time now?

    Read the article

  • Render label for a field inside ASP.NET MVC 2 editor templates

    - by artvolk
    I'm starting to use DataAnnotations in ASP.NET MVC and strongly typed template helpers. Now I have this in my views (Snippet is my custom type, Created is DateTime): <tr> <td><%= Html.LabelFor(f => Model.Snippet.Created) %>:</td> <td><%= Html.EditorFor(f => Model.Snippet.Created)%></td> </tr> The editor template for DateTime is like this: <%@ Control Language="C#" Inherits="System.Web.Mvc.ViewUserControl<System.DateTime>" %> <%=Html.TextBox("", Model.ToString("g"))%> But now I want to put inside editor template the whole <tr>, so I'd like to have just this in my view: <%= Html.EditorFor(f => Model.Snippet.Created)%> And something like this in editor template, but I don't know how to render for for label attribute, it should be Snippet_Created for my example, the same as id\name for textbox, so pseudo code: <%@ Control Language="C#" Inherits="System.Web.Mvc.ViewUserControl<System.DateTime>" %> <tr> <td><label for="<What to place here???>"><%=ViewData.ModelMetadata.DisplayName %></label></td> <td><%=Html.TextBox("", Model.ToString("g"))%></td> </tr> The Html.TextBox() have the first parameter empty and id\name for textbox is generated corectly. Thanks in advance!

    Read the article

  • Override ModelState.IsValid Property

    - by griegs
    How can I override the IsValid property? I have a model that's validating as false. I have a custom ValidationAttribute on the model and I'd like to set the IsValid flag for the whole model under certain circumstances. Is this possible?

    Read the article

  • WPF/SL EventAggregator implementation with durable subscribers behavior?

    - by sha1dy
    Hi. Currently I'm building an application using latest Prism for Silverlight 4. I've a module and in that module I've two views with view models. Also I've a module view with two regions for each view. In module initialization I'm registering my views and view models in Unity container and also register views with corresponding regions. The problem is that views should display something similar to table-detail information - first view shows available entities ans the second view shows detail of selected entity. I need a way how to pass them initial selected entity. Newly created first view doesn't have any selected entity and newly created second view doesn't show any details. Currently I'm doing that this way: In module I create two view models and register them as instances in Unity container and then I register views as types for corresponding regions. Each view subscribes to EntitySelectedEvent from EventAggregator. Module initializer publish this event after initialization and this way two views are selecting the same entity. I know this looks ugly - I tried publishing this event from one of view models but the problems is that EventAggregator in Prism doesn't support durable subscribers - this means that if the second view model didn't subscribe to event before the first view model fired it, it won't receive and event. I know this is a normal behavior of EventAggregator, but I'm looking for a solution when view models can fire events without depending on initialization order of them - that is the first model can fire event before the second model was created and the second model will receive this 'queued' event after subscribing to it. Are there any other messaging implementations for WPF/SL which do support such behavior or using a mediator (in my example it's a module itself) isn't such a bad idea after all? One big problem with mediator is that models must be created right away in initialize and they can't be registered as types in container because this leads again to missing subscribers.

    Read the article

  • Need code for make barcode data separate into two textfield

    - by klox
    hello...i have a problem with my project..i want to use barcode scanner for input data to textfield (i'm using jquery). this barcode scanner read serial number and model name of each product..but after scan, serial number and model name appear in one textfield. how to make them appear separately into different text field..first textfield for serial number and second textfield for model name... is there some code to make it??use ajax,javascript or something else??

    Read the article

  • Collection View Item binding issue

    - by Harry
    I have two entities in a Data Model, ENTITY_A, and ENTITY_B, that are related (ENTITY_A with a one-to-many relationship to ENTITY_B named DetailItems). I have set up a NSCollectionView with its appropriate bindings to ENTITY_A, and have placed on a Collection View Item a label. If I bind the label to [Collection View Item] and with a Model Key Path of [representedObject.FIELD_NAME], it works great. If I bind it to a Model Key Path [representedObject.DetailItems.@count], again it works great. If I bind it to a Model Key Path [[email protected]_NAME], I get the following error on the console: addObserver:forKeyPath:options:context:] is not supported. Key path: @sum.FIELD_NAME. Can anyone please help? Thank you, Harry

    Read the article

  • Error while deploying a web application in OSGI container using pax web

    - by RaulDM
    Hello I am trying to deploy a web application in a Felix container. I have all the required configuration done with my web app like the setting up of the manifest headers: Webapp-Context: Bundle-ClassPath: Bundle-Activator: Import-Package: Bundle-SymbolicName: etc The Pax bundles that I have dropped in the same container are: pax-web-service-0.6.0.jar pax-web-jsp-0.7.1.jar pax-web-extender-war-0.7.1.jar pax-logging-service-1.5.0.jar pax-logging-api-1.5.0.jar Though it had been written in the pax web site that pax-web-service is included in pax-war-extender, it seems without pax-web-service bundle, all other bundles become handicapped. I had removed the other pax bundles like pax-web-extender-whiteboard-0.7.1.jar pax-web-jetty-0.7.1.jar, as I have not seen any usefulness of those. The pax-web-jetty-0.7.1.jar even does not get start up. it has dependencies which it could not be able to resolve from any one of the bundle provided by PAX. My browser is displaying: HTTP ERROR 403 Problem accessing /adminmodule/. Reason: FORBIDDEN Powered by Jetty:// while the Console log says: [5884890@qtp-16567002-0 - /adminmodule/] DEBUG org.mortbay.jetty - REQUEST /adminmodule/ on org.mortbay.jetty.HttpConnection@1e94001 [5884890@qtp-16567002-0 - /adminmodule/] DEBUG org.ops4j.pax.web.service.internal.model.ServerModel - Matching [/adminmodule/]... [5884890@qtp-16567002-0 - /adminmodule/] DEBUG org.ops4j.pax.web.service.internal.model.ServerModel - Path [/adminmodule/] matched to {pattern=/adminmodule/.*,model=ResourceModel{id=org.ops4j.pax.web.service.internal.model.ResourceModel-2,name=,urlPatterns=[/],alias=/,servlet=ResourceServlet{context=/adminmodule,alias=/,name=},initParams={},context=ContextModel{id=org.ops4j.pax.web.service.internal.model.ContextModel-1,name=adminmodule,httpContext=org.ops4j.pax.web.extender.war.internal.WebAppWebContainerContext@11710be,contextParams={webapp.context=adminmodule}}}} [5884890@qtp-16567002-0 - /adminmodule/] DEBUG org.ops4j.pax.web.service.internal.HttpServiceContext - Handling request for [/adminmodule/] using http context [org.ops4j.pax.web.extender.war.internal.WebAppWebContainerContext@11710be] [5884890@qtp-16567002-0 - /adminmodule/] DEBUG org.mortbay.jetty - sessionManager=org.mortbay.jetty.servlet.HashSessionManager@19c6163 [5884890@qtp-16567002-0 - /adminmodule/] DEBUG org.mortbay.jetty - session=null [5884890@qtp-16567002-0 - /adminmodule/] DEBUG org.mortbay.jetty - servlet= [5884890@qtp-16567002-0 - /adminmodule/] DEBUG org.mortbay.jetty - chain=org.ops4j.pax.web.service.internal.model.FilterModel-3- [5884890@qtp-16567002-0 - /adminmodule/] DEBUG org.mortbay.jetty - servlet holder= [5884890@qtp-16567002-0 - /adminmodule/] DEBUG org.mortbay.jetty - call filter org.ops4j.pax.web.service.internal.model.FilterModel-3 [5884890@qtp-16567002-0 - /adminmodule/] DEBUG org.ops4j.pax.web.service.internal.WelcomeFilesFilter - Apply welcome files filter... [5884890@qtp-16567002-0 - /adminmodule/] DEBUG org.ops4j.pax.web.service.internal.WelcomeFilesFilter - Servlet path: / [5884890@qtp-16567002-0 - /adminmodule/] DEBUG org.ops4j.pax.web.service.internal.WelcomeFilesFilter - Path info: null [5884890@qtp-16567002-0 - /adminmodule/] INFO org.ops4j.pax.web.service.internal.HttpServiceContext - getting resource: [/adminmodule.jsp] [5884890@qtp-16567002-0 - /adminmodule/] DEBUG org.ops4j.pax.web.extender.war.internal.WebAppWebContainerContext - Searching bundle [com.cisco.zaloni.gwt.admin [1]] for resource [/adminmodule.jsp], normalized to [adminmodule.jsp] [5884890@qtp-16567002-0 - /adminmodule/] DEBUG org.ops4j.pax.web.extender.war.internal.WebAppWebContainerContext - Resource not found [5884890@qtp-16567002-0 - /adminmodule/] INFO org.ops4j.pax.web.service.internal.HttpServiceContext - found resource: null [5884890@qtp-16567002-0 - /adminmodule/] DEBUG org.mortbay.jetty - call servlet [5884890@qtp-16567002-0 - /adminmodule/] DEBUG org.ops4j.pax.web.extender.war.internal.WebAppWebContainerContext - Searching bundle [com.cisco.zaloni.gwt.admin [1]] for resource [/], normalized to [/] [5884890@qtp-16567002-0 - /adminmodule/] DEBUG org.ops4j.pax.web.extender.war.internal.WebAppWebContainerContext - Resource found as url [bundle://1.0:1/] [5884890@qtp-16567002-0 - /adminmodule/] DEBUG org.mortbay.jetty - RESPONSE /adminmodule/ 403 It is really frustrating. please help. as I am new to OSGI. Raul

    Read the article

  • MVC: models interacts with the view?

    - by fayer
    i know that everything is going through the controller. but i often read articles that says something like this: user interacts with the view controller asks the model to change its state model notifies the view when its sate has changed i dont get the 3rd one. why saying that the model notifies the view, when it actually is notifying the controller and the controller is notifying the view?

    Read the article

  • A Django form for entering a 0 to n email addresses

    - by Erik
    I have a Django application with some fairly common models in it: UserProfile and Organization. A UserProfile or an Organization can both have 0 to n emails, so I have an Email model that has a GenericForeignKey. UserProfile and Organization Models both have a GenericRelation called emails that points back to the Email model (summary code provided below). The question: what is the best way to provide an Organization form that allows a user to enter organization details including 0 to n email addresses? My Organization create view is a Django class-based view. I'm leading towards creating a dynamic form and an enabling it with Javascript to allow the user to add as many email addresses as necessary. I will render the form with django-crispy-forms. I've thought about doing this with a formset embedded within the form, but this seems like overkill for email addresses. Embedding a formset in a form delivered by a class-based view is cumbersome too. Note that the same issue occurs with the Organization fields phone_numbers and locations. emails.py: from django.db import models from parent_mixins import Parent_Mixin class Email(Parent_Mixin,models.Model): email_type = models.CharField(blank=True,max_length=100,null=True,default=None,verbose_name='Email Type') email = models.EmailField() class Meta: app_label = 'core' organizations.py: from emails import Email from locations import Location from phone_numbers import Phone_Number from django.contrib.contenttypes import generic from django.db import models class Organization(models.Model): active = models.BooleanField() duns_number = models.CharField(blank=True,default=None,null=True,max_length=9) # need to validate this emails = generic.GenericRelation(Email,content_type_field='parent_type',object_id_field='parent_id') legal_name = models.CharField(blank=True,default=None,null=True,max_length=200) locations = generic.GenericRelation(Location,content_type_field='parent_type',object_id_field='parent_id') name = models.CharField(blank=True,default=None,null=True,max_length=200) organization_group = models.CharField(blank=True,default=None,null=True,max_length=200) organization_type = models.CharField(blank=True,default=None,null=True,max_length=200) phone_numbers = generic.GenericRelation(Phone_Number,content_type_field='parent_type',object_id_field='parent_id') taxpayer_id_number = models.CharField(blank=True,default=None,null=True,max_length=9) # need to validate this class Meta: app_label = 'core' parent_mixins.py from django.contrib.contenttypes.models import ContentType from django.contrib.contenttypes import generic from django.db import models class Parent_Mixin(models.Model): parent_type = models.ForeignKey(ContentType,blank=True,null=True) parent_id = models.PositiveIntegerField(blank=True,null=True) parent = generic.GenericForeignKey('parent_type', 'parent_id') class Meta: abstract = True app_label = 'core'

    Read the article

  • Non Working Relationship

    - by Dominik K.
    Hello everyone, I got a problem with cake's model architecture. I got a Users-Model and a Metas-Model. Here are the model codes: Users: <?php class User extends AppModel { var $name = 'User'; var $validate = array( 'username' => array('notempty'), 'email' => array('email'), 'password' => array('notempty') ); var $displayField = 'username'; var $hasMany = array( 'Meta' => array( 'className' => 'Meta', 'foreignKey' => 'user_id' ) ); } ?> and the Metas Model: <?php class Meta extends AppModel { var $name = 'Meta'; //The Associations below have been created with all possible keys, those that are not needed can be removed var $belongsTo = array( 'User' => array( 'className' => 'User', 'foreignKey' => 'user_id', 'required' => true ) ); } ?> So now the question is why do I not get the Meta data into the User array? Should I get it in the Auth object? Or where can I work with the meta data? hope you can help me! Have a nice Day! Dom

    Read the article

  • Django, ModelForms, User and UserProfile - not hashing password

    - by IvanBernat
    I'm trying to setup a User - UserProfile relationship, display the form and save the data. When submitted, the data is saved, except the password field doesn't get hashed. Additionally, how can I remove the help_text from the username and password (inherited from the User model)? Full code is below, excuse me if it's too long. Models.py USER_IS_CHOICES = ( ('u', 'Choice A'), ('p', 'Choice B'), ('n', 'Ninja'), ) class UserProfile(models.Model): user = models.ForeignKey(User, unique=True) user_is = models.CharField(max_length=1, choices=USER_IS_CHOICES) Forms.py class UserForm(forms.ModelForm): class Meta: model = User fields = ["first_name", "last_name", "username", "email", "password"] def clean_username(self): username = self.cleaned_data['username'] if not re.search(r'^\w+$', username): raise forms.ValidationError('Username can contain only alphanumeric characters') try: User.objects.get(username=username) except ObjectDoesNotExist: return username raise forms.ValidationError('Username is already taken') class UserProfileForm(forms.ModelForm): class Meta: model = UserProfile fields = ['user_is'] Views.py if request.method == 'POST': uform = UserForm(request.POST) pform = UserProfileForm(request.POST) if uform.is_valid() and pform.is_valid(): user = uform.save() profile = pform.save(commit = False) profile.user = user profile.save() return HttpResponseRedirect('/') else: uform = UserForm() pform = UserProfileForm() variables = RequestContext(request, { 'uform':uform, 'pform':pform }) return render_to_response('registration/register.html', variables)

    Read the article

  • How to use SQLAlchemy to dump an SQL file from query expressions to bulk-insert into a DBMS?

    - by Mahmoud Abdelkader
    Please bear with me as I explain the problem, how I tried to solve it, and my question on how to improve it is at the end. I have a 100,000 line csv file from an offline batch job and I needed to insert it into the database as its proper models. Ordinarily, if this is a fairly straight-forward load, this can be trivially loaded by just munging the CSV file to fit a schema, but I had to do some external processing that requires querying and it's just much more convenient to use SQLAlchemy to generate the data I want. The data I want here is 3 models that represent 3 pre-exiting tables in the database and each subsequent model depends on the previous model. For example: Model C --> Foreign Key --> Model B --> Foreign Key --> Model A So, the models must be inserted in the order A, B, and C. I came up with a producer/consumer approach: - instantiate a multiprocessing.Process which contains a threadpool of 50 persister threads that have a threadlocal connection to a database - read a line from the file using the csv DictReader - enqueue the dictionary to the process, where each thread creates the appropriate models by querying the right values and each thread persists the models in the appropriate order This was faster than a non-threaded read/persist but it is way slower than bulk-loading a file into the database. The job finished persisting after about 45 minutes. For fun, I decided to write it in SQL statements, it took 5 minutes. Writing the SQL statements took me a couple of hours, though. So my question is, could I have used a faster method to insert rows using SQLAlchemy? As I understand it, SQLAlchemy is not designed for bulk insert operations, so this is less than ideal. This follows to my question, is there a way to generate the SQL statements using SQLAlchemy, throw them in a file, and then just use a bulk-load into the database? I know about str(model_object) but it does not show the interpolated values. I would appreciate any guidance for how to do this faster. Thanks!

    Read the article

  • [Python]Xml add a node from another xml document

    - by michele
    Hi, I have two xml file: 1)model.xml 2)projectionParametersTemplate.xml I want to extract from 1) Algorithm Node with his child and put it in 2) I have wrote this code but it doesn't function. from xml.dom.minidom import Document from xml.dom import minidom xmlmodel=minidom.parse("/home/michele/Scrivania/d/model.xml") xmltemplate=minidom.parse("/home/michele/Scrivania/d/projectionParametersTemplate.xml") for Node in xmlmodel.getElementsByTagName("Algorithm"): print "\nNode: "+str(Node) for Node2 in xmltemplate.getElementsByTagName("ProjectionParameters"): print "\nNode2: "+str(Node2) Node2.appendChild(Node) This is model.xml link text This is projectionParametersTemplate.xml link text Thanks a lot.

    Read the article

  • Have problems designing input and output for a calculator app

    - by zoul
    Hello! I am writing a button calculator. I have the code split into model, view and a controller. The model knows nothing about formatting, it is only concerned with numbers. All formatting is done in the view. The model gets its input as keypresses, each keypress is a part of an enum: typedef enum { kButtonUnknown = 0, kButtonMemoryClear = 100, kButtonMemoryPlus = 112, kButtonMemoryMinus = 109, kButtonMemoryRecall = 114, kButtonClear = 99, … }; When the user presses a button (say 1), the model receives a button code (kButtonNum1), adds the corresponding number to a string input buffer ("1") and updates the numeric output value (1.0). The controller then passes the numeric output value to the view that formats it (1). This is all plain, simple and clean, but does not really work. The problem is that when user enters a part of a number (say 0.00, going to enter 0.001), the input does not survive the way through model to view and the display says 0 instead of 0.00. I know why this happens ("0.00"::string parses to 0::double and that gets formatted as 0). What I don’t know is how to design the calculator so that the code stays clean and simple and the numbers will show up on screen exactly as the user types them. I’ve already come with some kind of solution, but that’s essentially a hack and breaks the beautiful and simple flow from the calculator model to the display. Ideas? Current solution keeps track of the calculator state. If the calculator is building a number, I take the calculator input buffer (a string) and directly set the display contents (also a string). Otherwise I take the proper path, ie. take the numeric calculator output, pass it to the view as a double and the view uses its internal formatter to create a string for the display. Example input: input | display | mode ------+---------+------------ 0 | 0 | from string 0. | 0. | from string 0.0 | 0.0 | from string 0.0+ | 0 | from number This is ugly. (1) The calculator has to expose its input buffer and state. (2) The view has to expose its display and allow setting its contents directly using a string. (3) I have to duplicate some of the formatting code to format the string I got from the calculator input buffer. If user enters 12345.000, I have to display 12,345.000 and therefore I’ve got to have a commification code for strings. Yuck.

    Read the article

< Previous Page | 124 125 126 127 128 129 130 131 132 133 134 135  | Next Page >