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• Check for a unique value within a count, but get all results

  - by pedalpete

  I'm trying to create a single query which, similar to stack overflow, will give me the number of votes, but also make sure that the currently viewing user can't upvote again if they've already upvoted. my query currently looks like SELECT cid, text, COUNT(votes.parentid) FROM comments LEFT JOIN votes ON comments.cid=votes.parentid AND votes.type=3 WHERE comments.type=0 AND comments.parentid='$commentParentid' GROUP BY comments.cid But I'm completely stumpted on how to add the check to see if the userid is in the votes table. The other option is to add a seperate query where SELECT COUNT(*) FROM votes WHERE userid='$userid' AND parentid='$commentParentid' AND type=3 I'm just realizing I'm so lost with this that I don't even really know what tags to provide.

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• Help with grasping (INNER?) JOIN

  - by Greenie

  I'm having trouble building a query. I can do what I want in 3 different queries. SELECT id FROM table1 WHERE url LIKE '%/$downloadfile' put that in $url_id SELECT item_id FROM table2 WHERE rel_id = '$url_id'" put that in $item_id SELECT rel_id FROM table2 WHERE rel_id = '$item_id' AND field_id = '42'" put that in $user_id But from reading examples on joins and inner joins I think there's a more elegant way. I cant wrap my brain around writing a better query (but would like to) I can describe how it should go: table1 fields: id, url table2 fields item_id, rel_id, field_id I know the last part of table1.url (LIKE '%/$filename') with that I select table1.id. table1.id is equal to one entry in table2.rel_id. So get that and select the table2.item_id. In table2 there is another entry which has the same table2.item_id and it will have a table2.field_id = '42' And finally the value I need is the table2.rel_id where the table2.field_id was 42. I will fetch that value and put it in $user_id Can this be done with one query using joins/inner joins?

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• Is it valid to have more than one question mark in a URL?

  - by Bungle

  I came across the following URL today: http://www.sfgate.com/cgi-bin/blogs/inmarin/detail??blogid=122&entry_id=64497 Notice the doubled question mark at the beginning of the query string: ??blogid=122&entry_id=64497 My browser didn't seem to have any trouble with it, and running a quick bookmarklet: javascript:alert(document.location.search); just gave me the query string shown above. Is this a valid URL? The reason I'm being so pedantic (assuming that I am) is because I need to parse URLs like this for query parameters, and supporting doubled question marks would require some changes to my code. Obviously if they're in the wild, I'll need to support them; I'm mainly curious if it's my fault for not adhering to URL standards exactly, or if it's in fact a non-standard URL.

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• SQL Server indexed view matching of views with joins not working

  - by usr

  Does anyone have experience of when SQL Servr 2008 R2 is able to automatically match indexed view (also known as materialized views) that contain joins to a query? for example the view select dbo.Orders.Date, dbo.OrderDetails.ProductID from dbo.OrderDetails join dbo.Orders on dbo.OrderDetails.OrderID = dbo.Orders.ID cannot be automatically matched to the same exact query. When I select directly from this view ith (noexpand) I actually get a much faster query plan that does a scan on the clustered index of the indexed view. Can I get SQL Server to do this matching automatically? I have quite a few queries and views... I am on enterprise edition of SQL Server 2008 R2.

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• how to order a group result with Linq?

  - by Aaron

  How can I order the results from "group ... by... into..." statement in linq? For instance: var queryResult = from records in container.tableWhatever where records.Time >= DateTime.Today group records by tableWhatever.tableHeader.UserId into userRecords select new { UserID = userRecords.Key, Records = userRecords }; The query returns records in table "contain.tableWhatever" grouped by "UserId". I want the returned results within each group ordered by time decending. How can I do that? More specific, assume the above query return only one group like the following: {UserID = 1, Records= {name1 5/3/2010_7:10pm; name2 5/3/2010_8:10pm; name3 5/3/2010_9:10pm} } After insert the orderby statement in the above query, the returned results should be like this: {UserID = 1, Records= {name3 5/3/2010_9:10pm; name2 5/3/2010_8:10pm; name1 5/3/2010_7:10pm} } Thanks for help!

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• Intime and OutTime for the Modified date

  - by Jash

  Question is already posted on June 4, but still am not get the Proper answer Again Table Structure: T_Person – Table 1 CARDNO 168 471 488 247 519 518 331 240 518 386 441 331 T_Cardevent – Table 2 CARDEVENTDATE CARDEVENTTIME 20090225 163932 20090225 164630 20090225 165027 20090225 165137 20090225 165147 20090225 165715 20090225 165749 20090303 162059 20090303 162723 20090303 155029 20090303 155707 20090303 162824 Query SELECT CARDNO, CARDEVENTDATE, (1000000 * CAST (CARDEVENTDATE AS BIGINT) + CAST (CARDEVENTTIME AS BIGINT) - 30001) / 1000000 AS CardEvenDateAdjusted, CARDEVENTTIME FROM T_CARDEVENT WHERE (CARDEVENTDATE > 20090601) GROUP BY CARDNO, CARDEVENTDATE, CARDEVENTTIME, (1000000 * CAST(CARDEVENTDATE AS BIGINT) + CAST(CARDEVENTTIME AS BIGINT) - 30001) / 1000000 ORDER BY CARDNO, CARDEVENDATEADJUSTED From this above query date is displaying correctly according to that time 03:00:01 to 03:00:00 How can I get min (time) and Max (time) for the adjusted date? I need the sql query for the above condition. Help me? Urgent Please

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• $where in mongodb web shell not working

  - by Bravo

  i have the below set of test documents which i inserted in to the mongodb and when i use to query the db using the $where get the below exception Error: database error: $where query, but no script engine Any idea why the $where clause not working test data : db.things.save({ "_id" : 1, "domainName" : "test11.com", "hosting" : "hostgator.com" }) db.things.save({ "_id" : 2, "domainName" : "test2.com", "hosting" : "aws.amazon.com"}) db.things.save({ "_id" : 3, "domainName" : "test3.com", "hosting" : "aws.amazon.com" }) db.things.save({ "_id" : 4, "domainName" : "test4.com", "hosting" : "hostgator.com" }) db.things.save({ "_id" : 5, "domainName" : "test5.com", "hosting" : "aws.amazon.com" }) db.things.save({ "_id" : 6, "domainName" : "test6.com", "hosting" : "cloud.google.com" }) db.things.save({ "_id" : 7, "domainName" : "test7.com", "hosting" : "aws.amazon.com" }) db.things.save({ "_id" : 8, "domainName" : "test8.com", "hosting" : "hostgator.com" }) db.things.save({ "_id" : 9, "domainName" : "test9.com", "hosting" : "cloud.google.com" }) db.things.save({ "_id" : 10, "domainName" : "test10.com", "hosting" : "godaddy.com" }) query used : db.things.find( { $where: "this.domainName == 'test11.com'" } );

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• how so select similarities in MySQL?

  - by mysqllearner

  Currently, I am doing a search function. Lets say in my database, I have this data: Keyword1 Keyword2 Keyword3 Keysomething Key and the user entered: "Key" as the keyword to search. This is my current query: Q1: SELECT * FROM data WHERE (data_string LIKE '$key%' OR data_string LIKE '%$key%' OR data_string LIKE '%$key') Basically, I have 2 questions: How do I sort by (order by) similarity. From above example, I should have "Key" as my first result. My current result is: Keyword1, Keyword2, Keyword3, Keysomething and Key My SQL query only search by the "data_string" column, what if I want to seach others column? Do I need to do something like this: Q2: SELECT * FROM data WHERE (data_string LIKE '$key%' OR data_string LIKE '%$key%' OR data_string LIKE '%$key') OR (data_other LIKE '$key%' OR data_other LIKE '%$key%' OR data_other LIKE '%$key') ... Is there any better/faster query than Q2?

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• group by with 3 diffrent

  - by NN

  I have 2 table and I wanna a query with 3 column result in on of them 2 column with view count and title name and in the other 1 column with type_ and i wanna to grouping type_ with max(view count) and show the them title but i didn't have any idea about grouping expression. i think we can solve in by using sub query but i don't know which column use in group by. 2 table join with this expression class pk=resource key i exam this query: SELECT t.title,j.type_ FROM tags asset t,journal article j where type_ in (select type_ from journal article,tags asset where class pk=resource key group by type_) but the answer was wrong

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• How to retrieve Google Appengine Objects by id (Long value) ?

  - by David

  Hi, i have declared an entity the following way: public class MyEntity { @PrimaryKey @Persistent(valueStrategy = IdGeneratorStrategy.IDENTITY) private Long id; @Persistent private String text; //getters and setters } Now I want to retrieve the objects using the id. I tried to manage it from the Google Appengine Data Viewer with "SELECT * FROM MyEntity Where id = 382005" or via a query in a servlet. I get no results returned. But i know for sure that the object with the id exists (i made a jsp which queries all objects in the db and displays them in the db). So what is wrong in my query? Am I querying the wrong field? The Google Appengine Data Viewer names the field "ID/name" and it has the value "id=382005". Do I have to query with this names? I've tried but it didn't work out :(

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• Get result from mysql orderd by IN clause

  - by SchlaWiener

  I have the following query SELECT * FROM invoice WHERE invoice_id IN (13, 15, 9, 27) My result is: invoice_id | invoice_number | ... ------------------------------------ 9 | 201006003 | 13 | 201006020 | 15 | 201006022 | 27 | 201006035 | which is the result set I want except that is ordered by the invoice_id (which is an autoincrement value). Now I want the result in the order I specified in my query (13, 15, ...). Is there a way to achive that? The background is that I have a DataTable bound to a DataGridView. The user can filter and sort the result but if he want's to print the result I don't use the DataTable for printing because it only contains the most important columns and instead I pull the whole records from the database and pass it to my printing control. I also tried to extend the existing DataTable with the missing results but that seems to slower than using the IN (...) query.

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• query regarding fixing the page size

  - by sukhada

  -- <f:subview id="header"> <tiles:insert definition="page.header" flush="false"/> </f:subview> <!-- </h:panelGroup>--> <h:panelGroup id="topMenu" > <tiles:insert definition="page.topMenu" flush="false"/> </h:panelGroup> <h:panelGroup id="pageContext"> <f:subview id="body"> <tiles:insert attribute="body" flush="false"/> </f:subview> </h:panelGroup> <f:facet name="footer"> <f:subview id="footer"> <tiles:insert definition="page.footer" flush="false"/> </f:subview> </f:facet> </h:panelGrid> this is structure or layout of page in tiles but m loading another page the it disturbing the layout the layout so how can i fix the page size?

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• advanced search with mysql

  - by Arsenal

  I'm creating a search function for my website where the user can put in anything he likes in a textfield. It get's matched against anything (name, title, job, car brand, ... you name it) I initially wrote the query with an INNER JOIN on every table that needed to be searched. SELECT column1, column2, ... FROM person INNER JOIN person_car ON ... INNER JOIN car ... This ended up in a query with 6 or 8 INNER JOINs, and a whole lot WHERE ... LIKE '%searchvalue%' Now this query seems to cause a time'out in MySql, and I even got a warning from my hosting provider that the queries just taking up too many resources. Now obviously I'm doing this very wrong, but I was wondering how the correct approach to these kind of search functions is. Thanks!

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• Group by clause return latest row information

  - by I Like PHP

  below is my table structure table_movie_info i_movie_id |movie_actor_id |movie_actress_id |movie_director_id | movie_producer_id 48 | 5 | 9 | 66 | 21 48 | 6 | 15 | 88 | 22 48 | 7 | 12 | 77 | 23 one more table is table_movie movie_id | movie_year | movie_genre_id |movie_rating 1 | 2009 | 6 | 8 2 | 2001 | 5 | 7.5 48 | 2007 | 3 | 6.8 now i need total movie information using both table,i write below query SELECT * FROM table_movie_info LEFT JOIN table_movie ON movie_id = i_movie_id WHERE i_movie_id=48 GROUP BY i_movie_id above query return only one row , but i need such type of information movie_id=48, actors_id list=5,6,7 acttress_id list=9,15,12 etc.. please tell me the optimized query which h return complete information i need. thanks for helping me always.

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• Querying Same Lookup Table With Multiple Columns

  - by dmaruca

  I'm a bit confused on this. I have a data table structured like this: Table: Data DataID Val 1 Value 1 2 Value 2 3 Value 3 4 Value 4 Then I have another table structured like this: Table: Table1 Col1 Col2 1 2 3 4 4 3 2 1 Both columns from Table1 point to the data in the data table. How can I get this data to show in a query? For example, a query to return this: Query: Query1 Column1 Column2 Value 1 Value 2 Value 3 Value 4 Value 4 Value 3 Value 2 Value 1 I'm familiar enough with SQL to do a join with one column, but lost beyond that. Any help is appreciated. Sample sql or a link to something to read. Thanks! PS: This is in sqlite

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• MySQL AND alternative for eatch table in a join

  - by Scott

  I have a simple join in a query however I need to have a condition on both of the tables "confirmed='yes'" but if one of the tables doesn't have any that match the query returns with no rows. Database: .----------parties----------. | id - party_id - confirmed | |---------------------------| | 1 1 yes | | 1 2 no | | 1 3 no | +---------------------------+ .-----------events----------. | id - event_id - confirmed | |---------------------------| | 1 1 no | +---------------------------+ Query: SELECT p.party_id, e.event_id FROM parties p LEFT JOIN events e ON p.id=e.id WHERE p.id = '1' AND p.party_id IN (1,2,3) AND e.event_id IN (1) AND p.confirmed='yes' AND e.confirmed='yes' It returns nothing but I want it to return party_id 1 with a empty event_id. I hope this make sense and I not missing anything, Thanks for your help!

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• MySQL AND alternative for each table in a join

  - by Scott

  I have a simple join in a query however I need to have a condition on both of the tables "confirmed='yes'" but if one of the tables doesn't have any that match the query returns with no rows. Database: .----------parties----------. | id - party_id - confirmed | |---------------------------| | 1 1 yes | | 1 2 no | | 1 3 no | +---------------------------+ .-----------events----------. | id - event_id - confirmed | |---------------------------| | 1 1 no | +---------------------------+ Query: SELECT p.party_id, e.event_id FROM parties p LEFT JOIN events e ON p.id=e.id WHERE p.id = '1' AND p.party_id IN (1,2,3) AND e.event_id IN (1) AND p.confirmed='yes' AND e.confirmed='yes' It returns nothing but I want it to return party_id 1 with a empty event_id. I hope this make sense and I not missing anything, Thanks for your help!

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• Mongo: Finding from multiple queries

  - by waxical

  New to Mongo here. I'm using the PHP lib and trying to work out how I can find in a collection from multiple queries. I could do this by repeating the query with a different query, but I wondered if it can be done in one. I.e. $idsToLookFor = array(2124,4241,5553); $query = $db->thisCollection->find(array('id' => $idsToLookFor)); That's what I'd like to do. However it doesn't work. What I'm trying to do is find a set of results for all the id's at one time. Possible or just do a findOne on each with a foreach/for?

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• xPath insert before and after - With DOM and PHP

  - by Jens Törnell

  I need to add a class to a HTML structure. My class is called "container" and should start right after div/ul/li (the child of ul and its simblings, not grandchilds) and should end right before the closing of the same element. My whole code looks like this: <?php $content = ' <div class="sidebar-1"> <ul> <li> <h4>Title</h4> <ul> <li><a href="http://www.test.com">Test</a></li> <li><a href="http://www.test.com">Test</a></li> </ul> </li> <li> <p>Paragraf</p> </li> <li> <h4>New title</h4> <ul> <li>Some text</li> <li>Some text åäö</li> </ul> </li> </ul> </div> '; $doc = new DOMDocument(); $doc->loadHTML($content); $x = new DOMXPath($doc); $start_text = '<div class="container">'; $end_text = '</div>'; foreach($x->query('//div/ul/li') as $anchor) { $anchor->insertBefore(new DOMText($start_text),$anchor->firstChild); } echo $doc->saveXML($doc->getElementsByTagName('ul')->item(0)); ?> It works as far as i can add the class opening but not the closing element. I also get strange encoding doing this. I want the output to be the same encoding as the input. The result should be <div class="sidebar-1"> <ul> <li> <div class="content"> <h4>Title</h4> <ul> <li><a href="http://www.test.com">Test</a></li> <li><a href="http://www.test.com">Test</a></li> </ul> </div> </li> <li> <div class="content"> <p>Paragraf</p> </div> </li> <li> <div class="content"> <h4>New title</h4> <ul> <li>Some text</li> <li>Some text åäö</li> </ul> </div> </li> </ul> </div>

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• SharePoint 2010 search crawl not working

  - by J. Hammond

  I have the following set up: 1 x Windows server 2008 R2 running SQL 1 x Windows server 2008 R2 running SharePoint 2010. I have an issue with the search service application, the crawl appears to run for a never ending amount of time with 0 successes and 0 failures. Checking the Search Application Topology, I find that "Query Component 0" is "Not Responding". I have tried the following: I have ensured that the index directory has the right permissions applied to it and the search service account is in the right groups to consume those permissions. I have re-created the search service application. I have restarted the search service manually. I have trawled the net as much as possible to find a solution but as of yet have not come across something that has resolved this issue. Any input will be very much appreciated

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• Correlate GROUP BY and LEFT JOIN on multiple criteria to show latest record?

  - by Sunbird

  In a simple stock management database, quantity of new stock is added and shipped until quantity reaches zero. Each stock movement is assigned a reference, only the latest reference is used. In the example provided, the latest references are never shown, the stock ID's 1,4 should have references charlie, foxtrot respectively, but instead show alpha, delta. How can a GROUP BY and LEFT JOIN on multiple criteria be correlated to show the latest record? http://sqlfiddle.com/#!2/6bf37/107 CREATE TABLE stock ( id tinyint PRIMARY KEY, quantity int, parent_id tinyint ); CREATE TABLE stock_reference ( id tinyint PRIMARY KEY, stock_id tinyint, stock_reference_type_id tinyint, reference varchar(50) ); CREATE TABLE stock_reference_type ( id tinyint PRIMARY KEY, name varchar(50) ); INSERT INTO stock VALUES (1, 10, 1), (2, -5, 1), (3, -5, 1), (4, 20, 4), (5, -10, 4), (6, -5, 4); INSERT INTO stock_reference VALUES (1, 1, 1, 'Alpha'), (2, 2, 1, 'Beta'), (3, 3, 1, 'Charlie'), (4, 4, 1, 'Delta'), (5, 5, 1, 'Echo'), (6, 6, 1, 'Foxtrot'); INSERT INTO stock_reference_type VALUES (1, 'Customer Reference'); SELECT stock.id, SUM(stock.quantity) as quantity, customer.reference FROM stock LEFT JOIN stock_reference AS customer ON stock.id = customer.stock_id AND stock_reference_type_id = 1 GROUP BY stock.parent_id

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• make multiple, composite query in oracle

  - by Meloun

  How can i make multiple, composite query in oracle? for example this several queries in one step? 1 CREATE TABLE test (id NUMBER PRIMARY KEY, name VARCHAR2(30)); 2 CREATE SEQUENCE test_sequence START WITH 1 INCREMENT BY 1; 3 CREATE OR REPLACE TRIGGER test_trigger BEFORE INSERT ON test REFERENCING NEW AS NEW FOR EACH ROW BEGIN SELECT test_sequence.nextval INTO :NEW.ID FROM dual; END; 4 INSERT INTO test (name) VALUES ('Jon'); 5 INSERT INTO test (name) VALUES ('Meloun');

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• How to insert sub root node in xml file

  - by pravakar

  Hi guys hope all are doing good. I want to create one sub root node in my xml file like, <CapitalJobsList xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> <JobAds> -- element to create <JobAd> <AdvertiserDetails> <AdvertiserId>718508549</AdvertiserId> <AdvertiserName>ABC</AdvertiserName> </AdvertiserDetails> <ConsultantDetails> <ContactName>Naga Divakar</ContactName> <ContactPhone>6239 7755</ContactPhone> <ContactEmail>[email protected]</ContactEmail> <ContactFax>12345678912</ContactFax> </ConsultantDetails> <JobAdDetails> <DateEntered>2009-10-03T21:09:35.500</DateEntered> <AdvertiserJobRef>83754865</AdvertiserJobRef> <Title>IT Operations Manager</Title> <DescriptionShort>Large scale/exciting projects Mentor and manage o...</DescriptionShort> <Description>Large scale/exciting projects Mentor and manage others Management/technical mix This is a fantastic opportunity to join a high profile client who is active across both the commercial and Government domain. As the IT Operations Manager you will be responsible for leading and mentoring a small team of Infrastructure Engineers to ensure the availability and performance of the IT infrastructure. You w</Description> <SalaryMin>0.00</SalaryMin> <SalaryMax>0.00</SalaryMax> <WorkType xsi:nil="true" /> <Location>) as [JobAd/JobAdDetails/Bullets], isnull(Job</Location> <PostCode>2600</PostCode> <ClosingDate>2009-11-01T00:00:00</ClosingDate> <Keywords xsi:nil="true" /> <ApplyEmail xsi:nil="true" /> <ApplyURL>http://jobview.careerone.com.au/GetJob.aspx?JobID=83754865</ApplyURL> </JobAdDetails> <JobAdOptions> <BlindPost xsi:nil="true" /> <AdFormatType xsi:nil="true" /> <AdTemplateName xsi:nil="true" /> <ShowContactDetails xsi:nil="true" /> <ShowSalary xsi:nil="true" /> <HasVideo xsi:nil="true" /> <ResumeRequired>1</ResumeRequired> <ResidentsOnly>0</ResidentsOnly> </JobAdOptions> <CategoryList> <Category xsi:nil="true" /> </CategoryList> <RegionsList> <Region>ACT</Region> </RegionsList> <LevelsList> <Level xsi:nil="true" /> </LevelsList> </JobAd> <JobAd> <AdvertiserDetails> <AdvertiserId>718508549</AdvertiserId> <AdvertiserName>ABC</AdvertiserName> </AdvertiserDetails> <ConsultantDetails> <ContactName>Naga Divakar</ContactName> <ContactPhone>6239 7755</ContactPhone> <ContactEmail>[email protected]</ContactEmail> <ContactFax>12345678912</ContactFax> </ConsultantDetails> <JobAdDetails> <DateEntered>2009-10-03T21:09:35.530</DateEntered> <AdvertiserJobRef>83731488</AdvertiserJobRef> <Title>SAP Developers Required in Canberra - 12 month contract</Title> <DescriptionShort>My client, a large government department in Canbe...</DescriptionShort> <Description>My client, a large government department in Canberra, seeks two SAP Developers for 12 month ongoing contracts. Two SAP Developers Required Expert level ABAP programming skills Large SAP landscape - SAP R/3, SAP Web, SAP BI, SAP ITS My client, a large government department in Canberra, seeks two SAP Developers for 12 month ongoing contracts. My client is a large government department in Canberra, a</Description> <SalaryMin>0.00</SalaryMin> <SalaryMax>0.00</SalaryMax> <WorkType xsi:nil="true" /> <Location>) as [JobAd/JobAdDetails/Bullets], isnull(Job</Location> <PostCode>2600</PostCode> <ClosingDate>2009-11-01T00:00:00</ClosingDate> <Keywords xsi:nil="true" /> <ApplyEmail xsi:nil="true" /> <ApplyURL>http://jobview.careerone.com.au/GetJob.aspx?JobID=83731488</ApplyURL> </JobAdDetails> <JobAdOptions> <BlindPost xsi:nil="true" /> <AdFormatType xsi:nil="true" /> <AdTemplateName xsi:nil="true" /> <ShowContactDetails xsi:nil="true" /> <ShowSalary xsi:nil="true" /> <HasVideo xsi:nil="true" /> <ResumeRequired>1</ResumeRequired> <ResidentsOnly>0</ResidentsOnly> </JobAdOptions> <CategoryList> <Category xsi:nil="true" /> </CategoryList> <RegionsList> <Region>ACT</Region> </RegionsList> <LevelsList> <Level xsi:nil="true" /> </LevelsList> </JobAd> </JobAds> </CapitalJobsList> I have used the sql query for xml path like: select r.advid as [JobAd/AdvertiserDetails/AdvertiserId], CompanyName as [JobAd/AdvertiserDetails/AdvertiserName], firstname +'' ''+ lastname as [JobAd/ConsultantDetails/ContactName], WorkPhone as [JobAd/ConsultantDetails/ContactPhone], AdvEmail as [JobAd/ConsultantDetails/ContactEmail], FaxNo as [JobAd/ConsultantDetails/ContactFax], Job_CreatedDate as [JobAd/JobAdDetails/DateEntered], Job_Id as [JobAd/JobAdDetails/AdvertiserJobRef], Job_Title as [JobAd/JobAdDetails/Title], substring(Job_Description,0,50)+''...'' as [JobAd/JobAdDetails/DescriptionShort], Job_Description as [JobAd/JobAdDetails/Description], CONVERT(DECIMAL(10,2),MinSalary) as [JobAd/JobAdDetails/SalaryMin], CONVERT(DECIMAL(10,2),MaxSalary) as [JobAd/JobAdDetails/SalaryMax], Job_Type as [JobAd/JobAdDetails/WorkType], isnull(Job_Bullets,'') as [JobAd/JobAdDetails/Bullets], isnull(Job_Location,'') as [JobAd/JobAdDetails/Location], Job_PostCode as [JobAd/JobAdDetails/PostCode], Job_ExpireDate as [JobAd/JobAdDetails/ClosingDate], Job_Keywords as [JobAd/JobAdDetails/Keywords], ApplyEmail as [JobAd/JobAdDetails/ApplyEmail], Job_BrandURL+Job_Id as [JobAd/JobAdDetails/ApplyURL], BlindPost as [JobAd/JobAdOptions/BlindPost], AdFormatType as [JobAd/JobAdOptions/AdFormatType], AdTemplateName as [JobAd/JobAdOptions/AdTemplateName], ShowContactDetails as [JobAd/JobAdOptions/ShowContactDetails], ShowSalary as [JobAd/JobAdOptions/ShowSalary], HasVideo as [JobAd/JobAdOptions/HasVideo], ResumeRequired as [JobAd/JobAdOptions/ResumeRequired], ResidentsOnly as [JobAd/JobAdOptions/ResidentsOnly], Job_Category as [JobAd/CategoryList/Category], Job_Location_State as [JobAd/RegionsList/Region], [Level] as [JobAd/LevelsList/Level] from DR_Adv_Registration r, DR_CareerOne_ACTJobs j where r.Advid = j.Advid and job_location_city like(''%'+''+ @City +''+'%'') and job_location_state in('''+ @State +''') and job_status=1 for xml path(''''), Root(''CapitalJobsList''),ELEMENTS XSINIL So, suggest me how to get the sub root node. Thanks in advance

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• Balanced Search Tree Query, Asymtotic Analysis..

  - by AGeek

  Hi, The situation is as follows:- We have n number and we have print them in sorted order. We have access to balanced dictionary data structure, which supports the operations serach, insert, delete, minimum, maximum each in O(log n) time. We want to retrieve the numbers in sorted order in O(n log n) time using only the insert and in-order traversal. The answer to this is:- Sort() initialize(t) while(not EOF) read(x) insert(x,t); Traverse(t); Now the query is if we read the elements in time "n" and then traverse the elements in "log n"(in-order traversal) time,, then the total time for this algorithm (n+logn)time, according to me.. Please explain the follow up of this algorithm for the time calculation.. How it will sort the list in O(nlogn) time?? Thanks.

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• Attributes passed to .build() dont show up in the query

  - by Sebastian

  Hi there guys! Hope your all enjoying your hollydays. Ive run into a pretty funny problem when trying to insert rows into a really really simple database table. The basic idea is pretty simple. The user selects one/multiple users in a multiselect which are supposed to be added to a group. This piece of code will insert a row into the user_group_relationships table, but the users id always @group = Group.find(params[:group_id]) params[:newMember][:users].each do |uid| # For debugging purposes. puts 'Uid:'+uid @rel = @group.user_group_relationships.build( :user_id => uid.to_i ) @rel.save end The user id always gets inserted as null even though it is clearly there. You can see the uid in this example is 5, so it should work. Uid:5 ... SQL (0.3ms) INSERT INTO "user_group_relationships" ("created_at", "group_id", "updated_at", "user_id") VALUES ('2010-12-27 14:03:24.331303', 2, '2010-12-27 14:03:24.331303', NULL) Any ideas why this fails?

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