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  • Please help on multiple match replacement

    - by duenguyen
    I have a perl code: my $s = "The+quick+brown+fox+jumps+over+the+lazy+dog+that+is+my+dog"; what I want is to replace every + with space and dog with cat i have this regular expression $s =~ s/+(.*)dog/ ${1}cat/g; But it only match first occurrence of + and last dog. Please help

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  • How Do I grep For non-ASCII Characters in UNIX

    - by Peter Conrey
    I have several very large XML files and I'm trying to find the lines that contain non-ASCII characters. I've tried the following: grep -e "[\x{00FF}-\x{FFFF}]" file.xml But this returns every line in the file, regardless of whether the line contains a character in the range specified. Do I have the syntax wrong or am I doing something else wrong? I've also tried: egrep "[\x{00FF}-\x{FFFF}]" file.xml (with both single and double quotes surrounding the pattern).

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  • preg_match_all problems

    - by NeoNmaN
    i use preg_match_all and need to grab all a href="" tags in my code, but i not relly understand how to its work. i have this reg. exp. ( /(<([\w]+)[^])(.?)(<\/\2)/ ) its take all html codes, i need only all a href tags. i hobe i can get help :)

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  • Regular Expression Pattern for C# with matches

    - by Sumit Gupta
    I am working on project where I need to find Frequency from a given text. I wrote a Regular expression that try to detect frequency, however I am stuck with how C# handle it and how exactly I use it in my software My regular experssion is (\d*)(([,\.]?\s*((k|m)?hz)*)|(\s*((k|m)?hz)*))$ And I am trying to find value from 23,2 Hz 24,4Hz 25,0 Hzsadf 26 Hz 27Khz 28hzzhzhzhdhdwe 29 30.4Hz 31.8 Hz 4343.34.234 Khz 65SD Further Explanation: System needs to work for US and Belgium Culture hence, 23.2 (US) = 23,2 (Be) I try to find a Digit, followed by either khz,mhz,hz or space or , or . If it is , or . then it should have another Digit followed by khz, mhz, hz Any help is appericated.

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  • Simple regular expression for decimal numbers?

    - by finch
    I know this may be the simplest question ever asked on Stack Overflow, but what is the regular expression for a decimal with a precision of 2? Valid examples: 123.12 2 56754 92929292929292.12 0.21 3.1 Invalid examples: 12.1232 2.23332 e666.76 Sorry for the lame question, but for the life of me I haven't been able to find anyone that can help! The decimal place may be option, and that integers may also be included.

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  • How to replace plain URLs with links?

    - by Sergio del Amo
    I am using the function below to match URLs inside a given text and replace them for HTML links. The regular expression is working great, but currently I am only replacing the first match. How I can replace all the URL? I guess I should be using the exec command, but I did not really figure how to do it. function replaceURLWithHTMLLinks(text) { var exp = /(\b(https?|ftp|file):\/\/[-A-Z0-9+&@#\/%?=~_|!:,.;]*[-A-Z0-9+&@#\/%=~_|])/i; return text.replace(exp,"<a href='$1'>$1</a>"); }

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  • Perl Regular expression remove double tabs, line breaks, white spaces

    - by Scoox
    Hi guys, I want to write a perl script that removes double tabs, line breaks and white spaces. What I have so far is: $txt=~s/\r//gs; $txt=~s/ +/ /gs; $txt=~s/\t+/\t/gs; $txt=~s/[\t\n]*\n/\n/gs; $txt=~s/\n+/\n/gs; But, 1. It's not beautiful. Should be possible to do that with far less regexps. 2. It just doesn't work and I really do not know why. It leaves some double tabs, white spaces and empty lines (i.e. lines with only a tab or whitespace) I could solve it with a while, but that is very slow and ugly. Any suggestions?

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  • jquery textarea custom tags replacement

    - by Tim
    Hi all, I'm basically trying to create my own tags - and replace them with the right HTML tags. So {B} {/B} would turn into <b> </b> I have only got so far with this, here: http://www.nacremedia.com/text2.htm Use the [B] button to bold stuff the current selection... it creates two bold tags and one closing for some reason. I'm so close! But I just need a bit of direction to get the final bugs out - can anyone please help?? Also, if there is a better way of doing this altogether then I am more than welcome to new ideas.

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  • Using `rack-rewrite` to Remove the Month and Date from a Permlink

    - by Bryan Veloso
    I've started the process of moving my blog to Octopress, but unfortunately, a limitation of Jekyll doesn't allow me to use abbreviated month names for my permalinks. Therefore I'm looking to just get rid of the month and day bits altogether. I'ved read in this article that you can use rack-rewrite to take care of the redirection, since I am using Heroku to host this. So how would I turn: This: example.com/journal/2012/jan/03/post-of-the-day/ Into this: example.com/journal/2012/post-of-the-day/ Extra points: If I had another rule that redirected /blog/ to /journal/, would that rule still adhere to the above one as well? So from: This: example.com/blog/2012/jan/03/post-of-the-day/ To this: example.com/journal/2012/jan/03/post-of-the-day/ And finally to: example.com/journal/2012/post-of-the-day/ Thanks for the assistance in advance. :)

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  • Regular Expression Sanitize (PHP)

    - by atif089
    Hello, I would like to sanitize a string in to a URL so this is what I basically need. Everything must be removed except alphanumeric characters and spaces and dashed. Spaces should be converter into dashes. Eg. This, is the URL! must return this-is-the-url Thanks

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  • multiline sed using backreferences...

    - by pagid
    Hi, I'm converting patch scripts using a commandline script - within these scripts there's the combination two lines like: --- /dev/null +++ filename.txt which needs to be converted to: --- filename.txt +++ filename.txt Initially I tried: less file.diff | sed -e "s/---\/dev\null\n+++ \(.*\)/--- \1\n+++ \1/" But I had to find out that multiline-handling is much more complex in sed :( Any help is appreciated...

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  • How do I strip multiple (optional) parts of a SQL string using .NET Regular Expressions?

    - by Luc
    I've been working on this for a few hours now and can't find any help on it. Basically, I'm trying to strip a SQL string into various parts (fields, from, where, having, groupBy, orderBy). I refuse to believe that I'm the first person to ever try to do this, so I'd like to ask for some advise from the StackOverflow community. :) To understand what I need, assume the following SQL string: select * from table1 inner join table2 on table1.id = table2.id where field1 = 'sam' having table1.field3 > 0 group by table1.field4 order by table1.field5 I created a regular expression to group the parts accordingly: select\s+(?<fields>.+)\s+from\s+(?<from>.+)\s+where\s+(?<where>.+)\s+having\s+(?<having>.+)\s+group\sby\s+(?<groupby>.+)\s+order\sby\s+(?<orderby>.+) This gives me the following results: fields => * from => table1 inner join table2 on table1.id = table2.id where => field1 = 'sam' having => table1.field3 > 0 groupby => table1.field4 orderby => table1.field5 The problem that I'm faced with is that if any part of the SQL string is missing after the 'from' clause, the regular expression doesn't match. To fix that, I've tried putting each optional part in it's own (...)? group but that doesn't work. It simply put all the optional parts (where, having, groupBy, and orderBy) into the 'from' group. Any ideas?

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  • Regexs in Ruby getting filename

    - by user1290757
    i am extracting file names of html files using line: filename = File.basename(input_filename, ".*") which currently prints full file name excluding .html extension All files are stored in the form of http^x.x.edu^1^2 all file names begin with http^ and contain edu^ what i want is to extract 2 (which changes) but it is always the second element after .edu I have attempted destructive gsub! but i m weak with regular expressions.

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  • Regular expressions in a Python find-and-replace script?

    - by Haidon
    I'm new to Python scripting, so please forgive me in advance if the answer to this question seems inherently obvious. I'm trying to put together a large-scale find-and-replace script using Python. I'm using code similar to the following: findreplace = [ ('term1', 'term2'), ] inF = open(infile,'rb') s=unicode(inF.read(),charenc) inF.close() for couple in findreplace: outtext=s.replace(couple[0],couple[1]) s=outtext outF = open(outFile,'wb') outF.write(outtext.encode('utf-8')) outF.close() How would I go about having the script do a find and replace for regular expressions? Specifically, I want it to find some information (metadata) specified at the top of a text file. Eg: Title: This is the title Author: This is the author Date: This is the date and convert it into LaTeX format. Eg: \title{This is the title} \author{This is the author} \date{This is the date} Maybe I'm tackling this the wrong way. If there's a better way than regular expressions please let me know! Thanks!

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  • glibc regexp performance

    - by Jack
    Anyone has experience measuring glibc regexp functions? Are there any generic tests I need to run to make such a measurements (in addition to testing the exact patterns I intend to search)? Thanks.

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  • PHP: Regular Expression to get a URL from a string

    - by Matthew Iselin
    I'm working on some PHP code which takes input from various sources and needs to find the URLs and save them somewhere. The kind of input that needs to be handled is as follows: http://www.youtube.com/watch?v=IY2j_GPIqRA Try google: http://google.com! (note exclamation mark is not part of the URL) Is http://somesite.com/ down for anyone else? Output: http://www.youtube.com/watch?v=IY2j_GPIqRA http://google.com http://somesite.com/ I've already borrowed one regular expression from the internet which works, but unfortunately wipes the query string out - not good! Any help putting together a regular expression, or perhaps another solution to this problem, would be appreciated.

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  • Convert a complicated string into an array in php

    - by Patrick Beardmore
    I have a php variable that comes from a form that needs tidying up. I hope you can help. The variable contains a list of items (possibly two or three word items with a space in between words). I want to convert it to a comma separated list with no superfluous white space. I want the divisions to fall only at commas, semi-colons or new-lines. Blank cannot be an item. Here's a comprehensive example (with a deliberately messy input): Variable In: "dog, cat ,car,tea pot,, ,,, ;;(++NEW LINE++)fly, cake" Variable Out "dog,cat,car,tea pot,fly,cake" Can anyone help?

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  • Perl Strip Comments with Regex Unique Request

    - by YoDar
    Hello, I'm running a code that read files, do some parsing but need to ignore all comments. There are good explanations how to conduct it. like this link $/ = undef; $_ = <>; s#/\*[^*]*\*+([^/*][^*]*\*+)*/|("(\\.|[^"\\])*"|'(\\.|[^'\\])*'|.[^/"'\\]*)#defined $2 ? $2 : ""#gse; print; My first problem is that after run this line $/ = undef; my code doesn't work properly. Actually, I don't know what it does. But if I could turn it back after ignoring all comments it will be helpful. In general, What is the useful way to ignore all comments without changing the rest of the code ? Thanks, YoDar

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