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  • Threads to make video out of images

    - by masood
    updates: I think/ suspect the imageIO is not thread safe. shared by all threads. the read() call might use resources that are also shared. Thus it will give the performance of a single thread no matter how many threads used. ? if its correct . what is the solution (in practical code) Single request and response model at one time do not utilizes full network/internet bandwidth, thus resulting in low performance. (benchmark is of half speed utilization or even lower) This is to make a video out of an IP cam that gives a new image on each request. http://149.5.43.10:8001/snapshot.jpg It makes a delay of 3 - 8 seconds no matter what I do. Changed thread no. and thread time intervals, debugged the code by System.out.println statements to see if threads work. All seems normal. Any help? Please show some practical code. You may modify mine. This code works (javascript) with much smoother frame rate and max bandwidth usage. but the later code (java) dont. same 3 to 8 seconds gap. <!DOCTYPE html> <html> <head> <script type="text/javascript"> (function(){ var img="/*url*/"; var interval=50; var pointer=0; function showImg(image,idx) { if(idx<=pointer) return; document.body.replaceChild(image,document.getElementsByTagName("img")[0]); pointer=idx; preload(); } function preload() { var cache=null,idx=0;; for(var i=0;i<5;i++) { idx=Date.now()+interval*(i+1); cache=new Image(); cache.onload=(function(ele,idx){return function(){showImg(ele,idx);};})(cache,idx); cache.src=img+"?"+idx; } } window.onload=function(){ document.getElementsByTagName("img")[0].onload=preload; document.getElementsByTagName("img")[0].src="/*initial url*/"; }; })(); </script> </head> <body> <img /> </body> </html> and of java (with problem) : package camba; import java.applet.Applet; import java.awt.Button; import java.awt.Graphics; import java.awt.Image; import java.awt.Label; import java.awt.Panel; import java.awt.TextField; import java.awt.event.ActionEvent; import java.awt.event.ActionListener; import java.net.URL; import java.security.Timestamp; import java.util.Date; import java.util.concurrent.TimeUnit; import java.util.concurrent.atomic.AtomicBoolean; import javax.imageio.ImageIO; public class Camba extends Applet implements ActionListener{ Image img; TextField textField; Label label; Button start,stop; boolean terminate = false; long viewTime; public void init(){ label = new Label("please enter camera URL "); add(label); textField = new TextField(30); add(textField); start = new Button("Start"); add(start); start.addActionListener(this); stop = new Button("Stop"); add(stop); stop.addActionListener(this); } public void actionPerformed(ActionEvent e){ Button source = (Button)e.getSource(); if(source.getLabel() == "Start"){ for (int i = 0; i < 7; i++) { myThread(50*i); } System.out.println("start..."); } if(source.getLabel() == "Stop"){ terminate = true; System.out.println("stop..."); } } public void paint(Graphics g) { update(g); } public void update(Graphics g){ try{ viewTime = System.currentTimeMillis(); g.drawImage(img, 100, 100, this); } catch(Exception e) { e.printStackTrace(); } } public void myThread(final int sleepTime){ new Thread(new Runnable() { public void run() { while(!terminate){ try { TimeUnit.MILLISECONDS.sleep(sleepTime); } catch (InterruptedException ex) { ex.printStackTrace(); } long requestTime= 0; Image tempImage = null; try { URL pic = null; requestTime= System.currentTimeMillis(); pic = new URL(getDocumentBase(), textField.getText()); tempImage = ImageIO.read(pic); } catch(Exception e) { e.printStackTrace(); } if(requestTime >= /*last view time*/viewTime){ img = tempImage; Camba.this.repaint(); } } }}).start(); System.out.println("thread started..."); } }

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  • Python : How to close a UDP socket while is waiting for data in recv ?

    - by alexroat
    Hello, let's consider this code in python: import socket import threading import sys import select class UDPServer: def __init__(self): self.s=None self.t=None def start(self,port=8888): if not self.s: self.s=socket.socket(socket.AF_INET, socket.SOCK_DGRAM) self.s.bind(("",port)) self.t=threading.Thread(target=self.run) self.t.start() def stop(self): if self.s: self.s.close() self.t.join() self.t=None def run(self): while True: try: #receive data data,addr=self.s.recvfrom(1024) self.onPacket(addr,data) except: break self.s=None def onPacket(self,addr,data): print addr,data us=UDPServer() while True: sys.stdout.write("UDP server> ") cmd=sys.stdin.readline() if cmd=="start\n": print "starting server..." us.start(8888) print "done" elif cmd=="stop\n": print "stopping server..." us.stop() print "done" elif cmd=="quit\n": print "Quitting ..." us.stop() break; print "bye bye" It runs an interactive shell with which I can start and stop an UDP server. The server is implemented through a class which launches a thread in which there's a infinite loop of recv/*onPacket* callback inside a try/except block which should detect the error and the exits from the loop. What I expect is that when I type "stop" on the shell the socket is closed and an exception is raised by the recvfrom function because of the invalidation of the file descriptor. Instead, it seems that recvfrom still to block the thread waiting for data even after the close call. Why this strange behavior ? I've always used this patter to implements an UDP server in C++ and JAVA and it always worked. I've tried also with a "select" passing a list with the socket to the xread argument, in order to get an event of file descriptor disruption from select instead that from recvfrom, but select seems to be "insensible" to the close too. I need to have a unique code which maintain the same behavior on Linux and Windows with python 2.5 - 2.6. Thanks.

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  • Tomcat startup logs - SEVERE: Error filterStart how to get a stack trace?

    - by Benju
    When I start Tomcat I get the following error: Jun 10, 2010 5:17:25 PM org.apache.catalina.core.StandardContext start SEVERE: Error filterStart Jun 10, 2010 5:17:25 PM org.apache.catalina.core.StandardContext start SEVERE: Context [/mywebapplication] startup failed due to previous errors It seems odd that the logs for Tomcat would not include a stack trace. Does somebody have a suggestion for how to increase the logging in Tomcat to get stack traces for errors like this?

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  • Problems with variadic function

    - by morpheous
    I have the following function from some legacy code that I am maintaining. long getMaxStart(long start, long count, const myStruct *s1, ...) { long i1, maxstart; myStruct *s2; va_list marker; maxstart = start; /*BUGFIX: 003 */ /*(va_start(marker, count);*/ va_start(marker, s1); for (i1 = 1; i1 <= count; i1++) { s2 = va_arg(marker, myStruct *); /* <- s2 is assigned null here */ maxstart = MAX(maxstart, s2->firstvalid); /* <- SEGV here */ } va_end(marker); return (maxstart); } When the function is called with only one myStruct argument, it causes a SEGV. The code compiled and run without crashing on Windows XP when I compiled it using VS2005. I have now moved the code to Ubuntu Karmic and I am having problems with the stricter compiler on Linux. Is anyone able to spot what is causing the parameter not to be read correctly in the var_arg() statement? I am compiling using gcc version 4.4.1 Edit The statement that causes the SEGV is this one: start = getMaxStart(start, 1, ms1); The variables 'start' and 'ms1' have valid values when the code execution first reaches this line.

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  • Java calendar day_of_week not working

    - by Raptrex
    I have a for loop starting at startTime going up to endTime and I would like it to print out the date if it is either a monday, tuesday, wednesday, thursday, or friday. Currently, it is only printing out the endTime date. The other stuff splits the string, which you can ignore. Since 5/16/2010 is a sunday, it should print out 17,18,19,20,21, 24 and 25. However it only prints 25 import java.util.*; public class test { public static void main(String[] args) { String startTime = "5/16/2010 11:44 AM"; String endTime = "5/25/2010 12:00 PM"; GregorianCalendar startCal = new GregorianCalendar(); startCal.setLenient(true); String[] start = splitString(startTime); //this sets year, month day startCal.set(Integer.parseInt(start[2]),Integer.parseInt(start[0])-1,Integer.parseInt(start[1])); startCal.set(GregorianCalendar.HOUR, Integer.parseInt(start[3])); startCal.set(GregorianCalendar.MINUTE, Integer.parseInt(start[4])); if (start[5].equalsIgnoreCase("AM")) { startCal.set(GregorianCalendar.AM_PM, 0); } else { startCal.set(GregorianCalendar.AM_PM, 1); } GregorianCalendar endCal = new GregorianCalendar(); endCal.setLenient(true); String[] end = splitString(endTime); endCal.set(Integer.parseInt(end[2]),Integer.parseInt(end[0])-1,Integer.parseInt(end[1])); endCal.set(GregorianCalendar.HOUR, Integer.parseInt(end[3])); endCal.set(GregorianCalendar.MINUTE, Integer.parseInt(end[4])); if (end[5].equalsIgnoreCase("AM")) { endCal.set(GregorianCalendar.AM_PM, 0); } else { endCal.set(GregorianCalendar.AM_PM, 1); } for (int i = startCal.get(Calendar.DATE); i < endCal.get(Calendar.DATE); i++) { if (startCal.get(Calendar.DAY_OF_WEEK) == Calendar.MONDAY || startCal.get(Calendar.DAY_OF_WEEK) == Calendar.TUESDAY || startCal.get(Calendar.DAY_OF_WEEK) == Calendar.WEDNESDAY || startCal.get(Calendar.DAY_OF_WEEK) == Calendar.THURSDAY || startCal.get(Calendar.DAY_OF_WEEK) == Calendar.FRIDAY) { startCal.set(Calendar.DATE, i); System.out.println(startCal.get(Calendar.DATE)); } } } private static String[] splitDate(String date) { String[] temp1 = date.split(" "); // split by space String[] temp2 = temp1[0].split("/"); // split by / //5/21/2010 10:00 AM return temp2; // return 5 21 2010 in one array } private static String[] splitTime(String date) { String[] temp1 = date.split(" "); // split by space String[] temp2 = temp1[1].split(":"); // split by : //5/21/2010 10:00 AM String[] temp3 = {temp2[0], temp2[1], temp1[2]}; return temp3; // return 10 00 AM in one array } private static String[] splitString(String date) { String[] temp1 = splitDate(date); String[] temp2 = splitTime(date); String[] temp3 = new String[6]; return dateFill(temp3, temp2[0], temp2[1], temp2[2], temp1[0], temp1[1], temp1[2]); } private static String[] dateFill(String[] date, String hours, String minutes, String ampm, String month, String day, String year) { date[0] = month; date[1] = day; date[2] = year; date[3] = hours; date[4] = minutes; date[5] = ampm; return date; } private String dateString(String[] date) { //return month+" "+day+", "+year+" "+hours+":"+minutes+" "+ampm //5/21/2010 10:00 AM return date[3]+"/"+date[4]+"/ "+date[5]+" "+date[0]+":"+date[1]+" "+date[2]; } }

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  • Dynamically including multiple files within php for image descriptions

    - by Steve Jones
    Working on implementing image descriptions to a php run gallery and can't seem to figure out how to call each text file for each individual image. //total number of images $total = 77; //max number of thumbnails per page $max = 9; //what image do we want to start from? $startcount = $_GET["start"]; //if there is not a defined starting image, we start with the first if(empty($startcount)) { $startcount = 0; } //start off the loop at 1 $loop = 1; //start the loop while($loop <= $max) { //for the picture labels $num = $startcount + $loop; if($num > $total) { $num = $num - 1; break; } // Add class="last" to every third list item if(is_int($num / 3)) { $last = ' class="last"'; } else { $last = ""; } //the code for the image echo ' <li'.$last.'><a href="images/portfolio/pic-'.$num.'.jpg" rel="milkbox[gall1]"><img src="images/portfolio/thumbs/pic-'.$num.'-thumb.jpg" width="256" height="138" alt="Thumbnail of image '.$num.'" /></a><div>'.$num.'</div></li>'; I see that I can call the text files by number using '.$num.' (I have 77 individual text files with a phrase in each) but how do I tell it to call the files?

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  • Getting problem in threading in JAVA

    - by chetans
    In this program i want to stop GenerateImage & MovingImage Thread both... And i want to start those threads from begining. Can u send me the solution? Here is the code........ package Game; import java.applet.Applet; import java.awt.Color; import java.awt.Dimension; import java.awt.Graphics; import java.awt.Image; import java.awt.MediaTracker; import java.awt.event.KeyEvent; import java.awt.event.KeyListener; import java.net.MalformedURLException; import java.net.URL; public class ThreadInApplet extends Applet implements KeyListener { private static final long serialVersionUID = 1L; Image[] asteroidImage; Image spaceshipImage; String levelstr="Easy Level"; int[] XPos,YPos; int number=0,XPosOfSpaceship,YPosOfSpaceship,NoOfObstacles=5,speed=1,level=1,spaceBtnPressdCntr=0; boolean gameStart=false,pauseGame=false,collideUp=false,collideDown=false,collideLeft=false,collideRight=false; private Image offScreenImage; private Dimension offScreenSize; private Graphics offScreenGraphics; Thread GenerateImages,MoveImages; public void init() { try { GenerateImages=new Thread () //thread to create obstacles { synchronized public void run () { for(int g=0;g<NoOfObstacles;g++) { try { sleep(1000); } catch (InterruptedException e) { e.printStackTrace(); } number++; // Temporary counter to count the no of obstacles created } } } ; MoveImages=new Thread () //thread to move obstacles { @SuppressWarnings("deprecation") synchronized public void run () { while(YPos[NoOfObstacles-1]!=600) { pauseGame=false; if(collide()==true) { GenerateImages.suspend(); repaint(); } else GenerateImages.resume(); for(int l=0;l<number;l++) { if(collide()==false) YPos[l]++; else GenerateImages.suspend(); } repaint(); try { sleep(speed); } catch (InterruptedException e) { e.printStackTrace(); } } if(YPos[NoOfObstacles-1]>=600) //level complete state { level++; try { levelUpdation(level); System.out.println("aahe"); } catch (MalformedURLException e) { e.printStackTrace(); } repaint(); } } }; initialPos(); spaceshipImage=getImage(new URL(getCodeBase(),"images/space.png")); for(int i=0;i<NoOfObstacles;i++) { asteroidImage[i]=getImage(new URL(getCodeBase(),"images/asteroid.png")); XPos[i]=(int) (Math.random()*700); YPos[i]=0; } MediaTracker tracker = new MediaTracker (this); for(int i=0;i<NoOfObstacles;i++) { tracker.addImage (asteroidImage[i], 0); } } catch (MalformedURLException e) { e.printStackTrace(); } setBackground(Color.black); addKeyListener(this); } //Sets initial positions of spaceship & obstacle images------------------------------------------------------ public void initialPos() throws MalformedURLException { asteroidImage=new Image[NoOfObstacles]; XPos=new int[NoOfObstacles]; YPos=new int[NoOfObstacles]; XPosOfSpaceship=getWidth()/2-35; YPosOfSpaceship=getHeight()-100; collideUp = false; collideDown=false; collideLeft=false; collideRight=false; } //level finished updations------------------------------------------------------------------------------ @SuppressWarnings("deprecation") public void levelUpdation(int level) throws MalformedURLException { NoOfObstacles=NoOfObstacles+20; speed=speed-3; System.out.println(NoOfObstacles+" "+speed); pauseGame=true; initialPos(); repaint(); } //paint method of graphics to print the messages--------------------------------------------------------- public void paint(Graphics g) { g.setColor(Color.white); if(gameStart==false) { g.drawString("SPACE to start", (getWidth()/2)-15, getHeight()/2); g.drawString(levelstr, (getWidth()/2), getHeight()/2+20); } if(level>1) { if(level==2) levelstr="Medium Level"; else levelstr="High Level"; g.drawString("Level Complete ", (getWidth()/2)-15, getHeight()/2); g.drawString(levelstr, (getWidth()/2), getHeight()/2+20); //g.drawString("SPACE to start", (getWidth()/2)-15, getHeight()/2+40); } for(int n=0;n<number;n++) { if(n>0) g.drawImage(asteroidImage[n],XPos[n],YPos[n],this); } g.drawImage(spaceshipImage,XPosOfSpaceship,YPosOfSpaceship,this); } //update method of graphics to print the messages--------------------------------------------------------- @SuppressWarnings("deprecation") public void update(Graphics g) { Dimension d = size(); if((offScreenImage == null) || (d.width != offScreenSize.width) || (d.height != offScreenSize.height)) { offScreenImage = createImage(d.width, d.height); offScreenSize = d; offScreenGraphics = offScreenImage.getGraphics(); } offScreenGraphics.clearRect(0, 0, d.width, d.height); paint(offScreenGraphics); g.drawImage(offScreenImage, 0, 0, null); } public void keyReleased(KeyEvent arg0){} public void keyTyped(KeyEvent arg0) {} //---------------------Key pressed event to start game & to move the spaceship-------------------------------------- public void keyPressed(KeyEvent e) { if(e.getKeyCode()==32) { spaceBtnPressdCntr++; if(spaceBtnPressdCntr==1) { gameStart=true; GenerateImages.start(); MoveImages.start(); } } if(gameStart==true) { if(e.getKeyCode()==37) { new Thread () { @SuppressWarnings("deprecation") synchronized public void run () { for(int cnt1=1;cnt1<=10;cnt1++) { if(collide()==true && collideLeft == true) { GenerateImages.suspend(); } else { if(XPosOfSpaceship>0) XPosOfSpaceship--; } } repaint(); } }.start(); } if(e.getKeyCode()==38) { new Thread () { @SuppressWarnings("deprecation") synchronized public void run () { for(int cnt1=1;cnt1<=10;cnt1++) { if(collide()==true && collideUp == true) { GenerateImages.suspend(); } else { if(YPosOfSpaceship>10) YPosOfSpaceship--; } } repaint(); } }.start(); } if(e.getKeyCode()==39) { new Thread () { @SuppressWarnings("deprecation") synchronized public void run () { for(int cnt1=1;cnt1<=10;cnt1++) { if(collide()==true && collideRight == true) { GenerateImages.suspend(); } else { if(XPosOfSpaceship<750) XPosOfSpaceship++; } } repaint(); } }.start(); } if(e.getKeyCode()==40) { new Thread () { @SuppressWarnings("deprecation") synchronized public void run () { for(int cnt1=1;cnt1<=10;cnt1++) { if(collide()==true && collideDown == true) { GenerateImages.suspend(); } else { if(YPosOfSpaceship<550) YPosOfSpaceship++; } } repaint(); } }.start(); } } } //------------------------------Collision checking between Spaceship & obstacles------------------------------ public boolean collide() { int x1,y1,x2,y2,x3,y3,x4,y4; //coordinates of obstacles int a1,b1,a2,b2,a3,b3,a4,b4; //coordinates of spaceship a1 =XPosOfSpaceship; b1=YPosOfSpaceship; a2=a1+spaceshipImage.getWidth(this); b2=b1; a3=a1; b3=b1+spaceshipImage.getHeight(this); a4=a2; b4=b3; for(int a=0;a<number;a++) { x1 =XPos[a]; y1=YPos[a]; x2=x1+asteroidImage[a].getWidth(this); y2=y1; x3=x1; y3=y1+asteroidImage[a].getHeight(this); x4=x2; y4=y3; /********checking asteroid touch spaceship from up direction********/ if(y3==b1 && x4>=a1 && x4<=a2) { collideUp = true; collideDown=false; collideLeft=false; collideRight=false; return(true); } if(y3==b1 && x3>=a1 && x3<=a2) { collideUp = true; collideDown=false; collideLeft=false; collideRight=false; return(true); } /********checking asteroid touch spaceship from left direction******/ if(x2==a1 && y4>=b1 && y4<=b3) { collideLeft=true; collideUp = false; collideDown=false; collideRight=false; return(true); } if(x2==a1 && y2>=b1 && y2<=b3) { collideLeft=true; collideUp = false; collideDown=false; collideRight=false; return(true); } /********checking asteroid touch spaceship from right direction*****/ if(x1==a2 && y3>=b2 && y3<=b4) { collideRight=true; collideLeft=false; collideUp = false; collideDown=false; return(true); } if(x1==a2 && y1>=b2 && y1<=b4) { collideRight=true; collideLeft=false; collideUp = false; collideDown=false; return(true); } /********checking asteroid touch spaceship from down direction*****/ if(y1==b3 && x2>=a3 && x2<=a4) { collideDown=true; collideRight=false; collideLeft=false; collideUp = false; return(true); } if(y1==b3 && x1>=a3 && x1<=a4) { collideDown=true; collideRight=false; collideLeft=false; collideUp = false; return(true); } } return(false); } }

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  • questions regarding the use of A* with the 15-square puzzle

    - by Cheeso
    I'm trying to build an A* solver for a 15-square puzzle. The goal is to re-arrange the tiles so that they appear in their natural positions. You can only slide one tile at a time. Each possible state of the puzzle is a node in the search graph. For the h(x) function, I am using an aggregate sum, across all tiles, of the tile's dislocation from the goal state. In the above image, the 5 is at location 0,0, and it belongs at location 1,0, therefore it contributes 1 to the h(x) function. The next tile is the 11, located at 0,1, and belongs at 2,2, therefore it contributes 3 to h(x). And so on. EDIT: I now understand this is what they call "Manhattan distance", or "taxicab distance". I have been using a step count for g(x). In my implementation, for any node in the state graph, g is just +1 from the prior node's g. To find successive nodes, I just examine where I can possibly move the "hole" in the puzzle. There are 3 neighbors for the puzzle state (aka node) that is displayed: the hole can move north, west, or east. My A* search sometimes converges to a solution in 20s, sometimes 180s, and sometimes doesn't converge at all (waited 10 mins or more). I think h is reasonable. I'm wondering if I've modeled g properly. In other words, is it possible that my A* function is reaching a node in the graph via a path that is not the shortest path? Maybe have I not waited long enough? Maybe 10 minutes is not long enough? For a fully random arrangement, (assuming no parity problems), What is the average number of permutations an A* solution will examine? (please show the math) I'm going to look for logic errors in my code, but in the meantime, Any tips? (ps: it's done in Javascript). Also, no, this isn't CompSci homework. It's just a personal exploration thing. I'm just trying to learn Javascript. EDIT: I've found that the run-time is highly depend upon the heuristic. I saw the 10x factor applied to the heuristic from the article someone mentioned, and it made me wonder - why 10x? Why linear? Because this is done in javascript, I could modify the code to dynamically update an html table with the node currently being considered. This allowd me to peek at the algorithm as it was progressing. With a regular taxicab distance heuristic, I watched as it failed to converge. There were 5's and 12's in the top row, and they kept hanging around. I'd see 1,2,3,4 creep into the top row, but then they'd drop out, and other numbers would move up there. What I was hoping to see was 1,2,3,4 sort of creeping up to the top, and then staying there. I thought to myself - this is not the way I solve this personally. Doing this manually, I solve the top row, then the 2ne row, then the 3rd and 4th rows sort of concurrently. So I tweaked the h(x) function to more heavily weight the higher rows and the "lefter" columns. The result was that the A* converged much more quickly. It now runs in 3 minutes instead of "indefinitely". With the "peek" I talked about, I can see the smaller numbers creep up to the higher rows and stay there. Not only does this seem like the right thing, it runs much faster. I'm in the process of trying a bunch of variations. It seems pretty clear that A* runtime is very sensitive to the heuristic. Currently the best heuristic I've found uses the summation of dislocation * ((4-i) + (4-j)) where i and j are the row and column, and dislocation is the taxicab distance. One interesting part of the result I got: with a particular heuristic I find a path very quickly, but it is obviously not the shortest path. I think this is because I am weighting the heuristic. In one case I got a path of 178 steps in 10s. My own manual effort produce a solution in 87 moves. (much more than 10s). More investigation warranted. So the result is I am seeing it converge must faster, and the path is definitely not the shortest. I have to think about this more. Code: var stop = false; function Astar(start, goal, callback) { // start and goal are nodes in the graph, represented by // an array of 16 ints. The goal is: [1,2,3,...14,15,0] // Zero represents the hole. // callback is a method to call when finished. This runs a long time, // therefore we need to use setTimeout() to break it up, to avoid // the browser warning like "Stop running this script?" // g is the actual distance traveled from initial node to current node. // h is the heuristic estimate of distance from current to goal. stop = false; start.g = start.dontgo = 0; // calcHeuristic inserts an .h member into the array calcHeuristicDistance(start); // start the stack with one element var closed = []; // set of nodes already evaluated. var open = [ start ]; // set of nodes to evaluate (start with initial node) var iteration = function() { if (open.length==0) { // no more nodes. Fail. callback(null); return; } var current = open.shift(); // get highest priority node // update the browser with a table representation of the // node being evaluated $("#solution").html(stateToString(current)); // check solution returns true if current == goal if (checkSolution(current,goal)) { // reconstructPath just records the position of the hole // through each node var path= reconstructPath(start,current); callback(path); return; } closed.push(current); // get the set of neighbors. This is 3 or fewer nodes. // (nextStates is optimized to NOT turn directly back on itself) var neighbors = nextStates(current, goal); for (var i=0; i<neighbors.length; i++) { var n = neighbors[i]; // skip this one if we've already visited it if (closed.containsNode(n)) continue; // .g, .h, and .previous get assigned implicitly when // calculating neighbors. n.g is nothing more than // current.g+1 ; // add to the open list if (!open.containsNode(n)) { // slot into the list, in priority order (minimum f first) open.priorityPush(n); n.previous = current; } } if (stop) { callback(null); return; } setTimeout(iteration, 1); }; // kick off the first iteration iteration(); return null; }

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  • C++ Array vs vector

    - by blue_river
    when using C++ vector, time spent is 718 milliseconds, while when I use Array, time is almost 0 milliseconds. Why so much performance difference? int _tmain(int argc, _TCHAR* argv[]) { const int size = 10000; clock_t start, end; start = clock(); vector<int> v(size*size); for(int i = 0; i < size; i++) { for(int j = 0; j < size; j++) { v[i*size+j] = 1; } } end = clock(); cout<< (end - start) <<" milliseconds."<<endl; // 718 milliseconds int f = 0; start = clock(); int arr[size*size]; for(int i = 0; i < size; i++) { for(int j = 0; j < size; j++) { arr[i*size+j] = 1; } } end = clock(); cout<< ( end - start) <<" milliseconds."<<endl; // 0 milliseconds return 0; }

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  • How do you convert date taken from a bash script to milliseconds in java program?

    - by Matt Pascoe
    I am writing a piece of code in java that needs to take a time sent from a bash script and parse the time to milliseconds. When I check the millisecond conversion on the date everything is correct except for the month I have sent which is January instead of March. Here is the variable I create in the bash script, which later in the script I pass to the java program: TIME=`date +%m%d%Y_%H:%M:%S` Here is the java code which parses the time to milliseconds: String dt = "${scriptstart}"; java.text.SimpleDateFormat scriptStart = new java.text.SimpleDateFormat("MMDDyyyy_HH:mm:ss"); long start = scriptStart.parse(dt).getTime(); The goal of this statement is to find the elapsed time between the start of the script and the current system time. To troubleshoot this I printed out the two: System Time = 1269898069496 (converted = Mon Mar 29 2010 16:27:49 GMT-0500 (Central Daylight Time)) Script Start = 03292010_16:27:45 Script Start in Milli = 1264804065000 (Converted = Fri Jan 29 2010 16:27:45 GMT-0600 (Central Standard Time))

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  • Tomcat V6.0 and eclipse issue

    - by Kaddy
    when i start tomcat from eclipse v3.3.1.1 it start but then if i try to access a web application from a browser it does not detect that the server is started...i need to stop the server from eclipse and then restart it by running start.bat and then the web app works fine...can any one tell me why is this happening ..?

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  • Grails-Write Selenium code inside a EasyB scenario.

    - by WaZ
    I am trying to write some selenium inside my scenario's. However, when I try to start Selenium using the following code: before "start selenium", { given "selenium is up and running", { selenium = new DefaultSelenium("localhost", 4444, "*firefox", "http://www.google.com.my/") selenium.start() } I get an error: Error running easyb tests: org.codehaus.groovy.control.MultipleCompilationErrorsException: startup failed, : 7: unable to resolve class DefaultSelenium I am trying to implement something like this http://www.theserverside.com/news/thread.tss?thread_id=55184 Much appreciated.

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  • extJs Json Reader

    - by tinti
    Please help me with this problem. I'm new in extJs and i need a little help. I have this code Ext.onReady(function() { var datesStore = new Ext.data.JsonStore({ start : 'StartTableDate', end : 'FinishTableDate', autoLoad : true, proxy : new Ext.data.HttpProxy({ url : 'dates.json', method:'GET' }), fields : [ // 2 mandatory fields {name:'StartTableDate'}, {name:'FinishTableDate'} ] }); // i want to pass to variable start si end the values from JSON var start = 'StartTableDate'; var end = 'FinishTableDate';

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  • Grouping arrays with consecutive keys

    - by KPL
    Hello people, I've an array like this - Array ( [16] => 424 [17] => 404 [18] => 416 [21] => 404 [22] => 456 [23] => 879 [28] => 456 [29] => 456 [32] => 123 [35] => 465 ) The output of this array would be Array ( [0] => Array ( ['start'] => 16 ['stop'] => 18 ) [1] => Array ( ['start'] => 21 ['stop'] => 23 ) [2] => Array ( ['start'] => 28 ['stop'] => 29 ) [3] => Array ( ['start'] => 32 ['stop'] => 33 ) [4] => Array ( ['start'] => 35 ['stop'] => 36 ) ) I don't really need the values. Just grouping the keys. And if consecutive integer doesn't exist for a particular key(like for [32] and [35]), 'stop' should be the consecutive integer. Thank you all for help.

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  • C++ Vector vs Array (Time)

    - by vsha041
    I have got here two programs with me, both are doing exactly the same task. They are just setting an boolean array / vector to the value true. The program using vector takes 27 seconds to run whereas the program involving array with 5 times greater size takes less than 1 s. I would like to know the exact reason as to why there is such a major difference ? Are vectors really that inefficient ? Program using vectors #include <iostream> #include <vector> #include <ctime> using namespace std; int main(){ const int size = 2000; time_t start, end; time(&start); vector<bool> v(size); for(int i = 0; i < size; i++){ for(int j = 0; j < size; j++){ v[i] = true; } } time(&end); cout<<difftime(end, start)<<" seconds."<<endl; } Runtime - 27 seconds Program using Array #include <iostream> #include <ctime> using namespace std; int main(){ const int size = 10000; // 5 times more size time_t start, end; time(&start); bool v[size]; for(int i = 0; i < size; i++){ for(int j = 0; j < size; j++){ v[i] = true; } } time(&end); cout<<difftime(end, start)<<" seconds."<<endl; } Runtime - < 1 seconds Platform - Visual Studio 2008 OS - Windows Vista 32 bit SP 1 Processor Intel(R) Pentium(R) Dual CPU T2370 @ 1.73GHz Memory (RAM) 1.00 GB Thanks Amare

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  • iPhone UITextView leaves room for 2 lines at the bottom

    - by Ton
    Hi Guys, When i start typing text in a default textView in my viewcontroller, its not going to the bottom of the textfield. It leaves room for 2 more lines of text and then starts scrolling. I want it to start scrolling when i start going beyond the last line. I tried everything, and i dont know what i can do? Anyone any ideas?

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  • How to implement iterator as an attribute of a class in Java

    - by de3
    Hi, let's say I have this simple MyArray class, with two simple methods: add, delete and an iterator. In the main method we can see how it is supposed to be used: public class MyArray { int start; int end; int[] arr; myIterator it; public MyArray(){ this.start=0; this.end=0; this.arr=new int[500]; it=new myIterator(); } public void add(int el){ this.arr[this.end]=el; this.end++; } public void delete(){ this.arr[this.start]=0; this.start++; } public static void main(String[] args){ MyArray m=new MyArray(); m.add(3); m.add(299); m.add(19); m.add(27); while(m.it.hasNext()){ System.out.println(m.it.next()); } } And then MyIterator should be implemented somehow: import java.util.Iterator; public class myIterator implements Iterator{ @Override public boolean hasNext() { // TODO Auto-generated method stub return false; } @Override public Object next() { // TODO Auto-generated method stub return null; } @Override public void remove() { // TODO Auto-generated method stub } } MyIterator should iterate arr from MyArray class, from start to end values; both are also attributes of MyArray. So, as MyIterator should use MyArray attributes, how should MyIterator be implemented? Perhaps I can send the current object in the initialization: it=new myIterator(this); But I guess it's not the best soultion. Or maybe MyArray itself should implement Iterator interface? How is this solved?

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  • Delay in the implementation of text change in Statusbar control

    - by ehsan zeynali
    I have a function a time consuming operation that is done I want to start and end operations appear to be user (By statusbar control) But when performed function, both text executed at the end of function. (user can not sees "Start Operation ...") What solution do you recommend to me? private void btnUpdateDataBase_Click(object sender, RoutedEventArgs e) { TextBlockStatus.Text = "Start Operation ..."; //Time consuming operation TextBlockStatus.Text = "End Operation ..."; }

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  • Splitting a string which contain multiple symbols to get specific values

    - by Eon Rusted du Plessis
    I cannot believe I am having trouble with this following string String filter = "name=Default;pattern=%%;start=Last;end=Now"; This is a short and possibly duplicate question, but how would I split this string to get: string Name = "Default"; string Pattern = "%%" ; string start = "Last" ; string end = "Now" ; Reason why I ask is my deadline is very soon, and this is literally the last thing I must do. I'm Panicking, and I'm stuck on this basic command. I tried: pattern = filter.Split(new string[] { "pattern=", ";" }, StringSplitOptions.RemoveEmptyEntries)[1]; //Gets the pattern startDate = filter.Split(new string[] { "start=", ";" }, StringSplitOptions.RemoveEmptyEntries)[1]; //Gets the start date I happen to get the pattern which I needed, but as soon as I try to split start, I get the value as "Pattern=%%" What can I do? Forgot to mention The list in this string which needs splitting may not be in any particular order . this is a single sample of a string which will be read out of a stringCollection (reading these filters from Properties.Settings.Filters

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  • change php variable on click event

    - by Claudiu
    I want to change php variable ($start and $end called by var b1 and var b2) if the user clicks on button. Now I know that php is server side, but how can I do it? I read something about using $get but I don't know how to implement it: <?php if ( is_user_logged_in() ) { ?> <input type="submit" value="Start Chat" id="start_chat" style="position: absolute; top: 30px; left: 10px;" /> <?php } ?> <script> jQuery('#start_chat').click(function(){ $(this).data('clicked', true); }); var b1 = '<?php echo $start; ?>'; var b2 = '<?php echo $end; ?>'; if(jQuery('#start_chat').data('clicked')) { // change var b1 and b2 } else { // do not change anything } </script> <div id="eu_la"> <?php $start = strtotime('9:30'); $end = strtotime('12:30'); $timenow = date('U'); if((date('w') == 4) && ($timenow >= $start && $timenow <= $end)) { // day 2 = Tuesday include('facut_mine.php'); } else { do_shortcode('[upzslider usingphp=true]'); } ?>

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  • Find all substrings between two strings

    - by Orsol
    I need to get all substrings from string. For ex: StringParser.GetSubstrings("[start]aaaaaa[end] wwwww [start]cccccc[end]", "[start]", "[end]"); that returns 2 string "aaaaaa" and "cccccc" Suppose we have only one level of nesting. Not sure about regexp, but I think it will be userful.

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  • question about prefix and suffix in java

    - by kate
    hi!!I have an issue and i want your help!I have a specific REGEX which i have named it "unique" and i want to store the data that it gives me!! The prefix and the suffix of this regex!!so!!someone has told me to use var prefix and var suffix but i don't know how to do it! for your convinience i give u my xml for this regex <reg name="unique"> <start><![CDATA[ <!-- 72 HOURS FORECASTS --> ]]></start> <end><![CDATA[<!-- 72 HOURS FORECASTS -->]]></end> </reg> the code where i call this regex is int k = 0; for(Xml reg_is:fetchsite.child("site").child("regexps").children("reg")) { if(reg_is.string("name").contains("unique")){ if(reg_is.child("start").content()=="") error += "\tNo prefix reg.exp. given.\n"; else prefix = HtmlMethods.removeBreaks(replaceVariables(reg_is.child("start").content())); if(reg_is.child("end").content()=="") error += "\tNo suffix reg.exp. given.\n"; else suffix = HtmlMethods.removeBreaks(replaceVariables(reg_is.child("end").content())); } else{ poleis[k][0]= HtmlMethods.removeBreaks(reg_is.string("name")); poleis[k][1] = HtmlMethods.removeBreaks(replaceVariables(reg_is.child("start").content())); poleis[k][2] = HtmlMethods.removeBreaks(replaceVariables(reg_is.child("end").content())); k++; }

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