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  • php slideshow sample

    - by serhio
    I try to do a simple image slideshow in php (just cycle images, no links, no other effects). after some googling I found the following in net: <HTML> <HEAD> <TITLE>Php Slideshow</TITLE> <script language="javascript"> var speed = 4000; // time picture is displayed var delay = 3; // time it takes to blend to the next picture x = new Array; var y = 0; <?php $tel=0; $tst='.jpg'; $p= "./images"; $d = dir($p); $first = NULL; while (false !== ($entry = $d->read())) { if (stristr ($entry, $tst)) { $entry = $d->path."/".$entry; print ("x[$tel]='$entry';\n"); if ($first == NULL) { $first = $entry; } $tel++; } } $d->close(); ?> function show() { document.all.pic.filters.blendTrans.Apply(); document.all.pic.src = x[y++]; document.all.pic.filters.blendTrans.Play(delay); if (y > x.length - 1) y = 0; } function timeF() { setTimeout(show, speed); } </script> </HEAD> <BODY > <!-- add html code here --> <?php print ("<IMG src='$first' id='pic' onload='timeF()' style='filter:blendTrans()' >"); ?> <!-- add html code here --> </BODY> </HTML> but it displays only the first image from the cycle. Do I something wrong? the resulting HTML page is: <HTML> <HEAD> <TITLE>Php Slideshow</TITLE> <script language="javascript"> var speed = 4000; // time picture is displayed var delay = 3; // time it takes to blend to the next picture x = new Array; var y = 0; x[0]='./images/under_construction.jpg'; x[1]='./images/BuildingBanner.jpg'; x[2]='./images/littleLift.jpg'; x[3]='./images/msfp_smbus1_01.jpg'; x[4]='./images/escalator.jpg'; function show() { document.all.pic.filters.blendTrans.Apply(); document.all.pic.src = x[y++]; document.all.pic.filters.blendTrans.Play(delay); if (y > x.length - 1) y = 0; } function timeF() { setTimeout(show, speed); } </script> </HEAD> <BODY > <!-- add html code here --> <IMG src='./images/under_construction.jpg' id='pic' onload='timeF()' style='filter:blendTrans()' ><!-- add html code here --> </BODY> </HTML>

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  • Is this PHP/MySQL login script secure?

    - by NightMICU
    Greetings, A site I designed was compromised today, working on damage control at the moment. Two user accounts, including the primary administrator, were accessed without authorization. Please take a look at the log-in script that was in use, any insight on security holes would be appreciated. I am not sure if this was an SQL injection or possibly breach on a computer that had been used to access this area in the past. Thanks <?php //Start session session_start(); //Include DB config require_once('config.php'); //Error message array $errmsg_arr = array(); $errflag = false; //Connect to mysql server $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD); if(!$link) { die('Failed to connect to server: ' . mysql_error()); } //Select database $db = mysql_select_db(DB_DATABASE); if(!$db) { die("Unable to select database"); } //Function to sanitize values received from the form. Prevents SQL injection function clean($str) { $str = @trim($str); if(get_magic_quotes_gpc()) { $str = stripslashes($str); } return mysql_real_escape_string($str); } //Sanitize the POST values $login = clean($_POST['login']); $password = clean($_POST['password']); //Input Validations if($login == '') { $errmsg_arr[] = 'Login ID missing'; $errflag = true; } if($password == '') { $errmsg_arr[] = 'Password missing'; $errflag = true; } //If there are input validations, redirect back to the login form if($errflag) { $_SESSION['ERRMSG_ARR'] = $errmsg_arr; session_write_close(); header("location: http://tapp-essexvfd.org/admin/index.php"); exit(); } //Create query $qry="SELECT * FROM user_control WHERE username='$login' AND password='".md5($_POST['password'])."'"; $result=mysql_query($qry); //Check whether the query was successful or not if($result) { if(mysql_num_rows($result) == 1) { //Login Successful session_regenerate_id(); //Collect details about user and assign session details $member = mysql_fetch_assoc($result); $_SESSION['SESS_MEMBER_ID'] = $member['user_id']; $_SESSION['SESS_USERNAME'] = $member['username']; $_SESSION['SESS_FIRST_NAME'] = $member['name_f']; $_SESSION['SESS_LAST_NAME'] = $member['name_l']; $_SESSION['SESS_STATUS'] = $member['status']; $_SESSION['SESS_LEVEL'] = $member['level']; //Get Last Login $_SESSION['SESS_LAST_LOGIN'] = $member['lastLogin']; //Set Last Login info $qry = "UPDATE user_control SET lastLogin = DATE_ADD(NOW(), INTERVAL 1 HOUR) WHERE user_id = $member[user_id]"; $login = mysql_query($qry) or die(mysql_error()); session_write_close(); if ($member['level'] != "3" || $member['status'] == "Suspended") { header("location: http://members.tapp-essexvfd.org"); //CHANGE!!! } else { header("location: http://tapp-essexvfd.org/admin/admin_main.php"); } exit(); }else { //Login failed header("location: http://tapp-essexvfd.org/admin/index.php"); exit(); } }else { die("Query failed"); } ?>

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  • Separation of presentation and business logic in PHP

    - by Markus Ossi
    I am programming my first real PHP website and am wondering how to make my code more readable to myself. The reference book I am using is PHP and MySQL Web Development 4th ed. The aforementioned book gives three approaches to separating logic and content: include files function or class API template system I haven't chosen any of these yet, as wrapping my brains around these concepts is taking some time. However, my code has become some hybrid of the first two as I am just copy-pasting away here and modifying as I go. On presentation side, all of my pages have these common elements: header, top navigation, sidebar navigation, content, right sidebar and footer. The function-based examples in the book suggest that I could have these display functions that handle all the presentation example. So, my page code will be like this: display_header(); display_navigation(); display_content(); display_footer(); However, I don't like this because the examples in the book have these print statements with HTML and PHP mixed up like this: echo "<tr bgcolor=\"".$color."\"><td><a href=\"".$url."\">" ... I would rather like to have HTML with some PHP in the middle, not the other way round. I am thinking of making my pages so that at the beginning of my page, I will fetch all the data from database and put it in arrays. I will also get the data for variables. If there are any errors in any of these processes, I will put them into error strings. Then, at the HTML code, I will loop through these arrays using foreach and display the content. In some cases, there will be some variables that will be shown. If there is an error variable that is set, I will display that at the proper position. (As a side note: The thing I do not understand is that in most example code, if some database query or whatnot gives an error, there is always: else echo 'Error'; This baffles me, because when the example code gives an error, it is sometimes echoed out even before the HTML has started...) For people who have used ASP.NET, I have gotten somewhat used to the code-behind files and lblError and I am trying to do something similar here. The thing I haven't figured out is how could I do this "do logic first, then presentation" thing so that I would not have to replicate for example the navigation logic and navigation presentation in all of the pages. Should I do some include files or could I use functions here but a little bit differently? Are there any good articles where these "styles" of separating presentation and logic are explained a little bit more thoroughly. The book I have only has one paragraph about this stuff. What I am thinking is that I am talking about some concepts or ways of doing PHP programming here, but I just don't know the terms for them yet. I know this isn't a straight forward question, I just need some help in organizing my thoughts.

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  • Converting PHP pagination to jQuery?

    - by ClarkSKent
    Hey, I have been trying to get this pagination class that I am using to be more ajaxy - meaning when I click on the page number like page [2] the data loads, but I want to load in the data without going to a different page (HTTP request in the background, with no page reloads). Being new to both php and jquery, I am a little unsure on how to achieve this result, especially while using a php class. This is what the main page looks like by the way: <?php $categoryId=$_GET['category']; echo $categoryId; ?> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.1/jquery.min.js"></script> <script type="text/javascript" src="jquery_page.js"></script> <?php //Include the PS_Pagination class include('ps_pagination.php'); //Connect to mysql db $conn = mysql_connect('localhost', 'root', 'root'); mysql_select_db('ajax_demo',$conn); $sql = "select * from explore where category='$categoryId'"; //Create a PS_Pagination object $pager = new PS_Pagination($conn, $sql, 3, 11, 'param1=value1&param2=value2'); //The paginate() function returns a mysql //result set for the current page $rs = $pager->paginate(); //Loop through the result set echo "<table width='800px'>"; while($row = mysql_fetch_assoc($rs)) { echo "<tr>"; echo"<td>"; echo $row['id']; echo"</td>"; echo"<td>"; echo $row['site_description']; echo"</td>"; echo"<td>"; echo $row['site_price']; echo"</td>"; echo "</tr>"; } echo "</table>"; echo "<ul id='pagination'>"; echo "<li>"; //Display the navigation echo $pager->renderFullNav(); echo "</li>"; echo "</ul>"; ?> <div id="loading" ></div> <div id="content" ></div> Would I need to do something with this part of the class?, as seen above: $pager = new PS_Pagination($conn, $sql, 3, 11, 'param1=value1&param2=value2'); Or this?: echo $pager->renderFullNav(); I don't no much about jquery,but i guess I would start it like: $("#pagination li").click(function() { Then load something maybe... I don't no. Any help on this would be great. Thanks.

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  • PHP & MySQL pagination display problem.

    - by TaG
    I asked a similar question like this yesterday but after waiting for ever I figured out part of the problem but now I'm stuck again I'm trying to display ... when the search results are to long because my pagination links will keep on displaying and will not stop until every link is displayed on the page. For example I'm trying to achieve the following in the example below. Can some one help me fix my code so I can update my site. Thanks This is what I want to be able to do. First Previous 1 2 ... 5 6 7 8 9 10 11 12 13 ... 199 200 Next Last Here is my pagination code that displays the links. $display = 20; if (isset($_GET['p']) && is_numeric($_GET['p'])) { $pages = $_GET['p']; } else { $q = "SELECT COUNT(id) FROM comments WHERE user_id=3"; $r = mysqli_query ($mysqli, $q) or trigger_error("Query: $q\n<br />MySQL Error: " . mysqli_error($mysqli)); $row = mysqli_fetch_array ($r, MYSQLI_NUM); $records = $row[0]; if ($records > $display) { $pages = ceil ($records/$display); } else { $pages = 1; } } if (isset($_GET['s']) && is_numeric($_GET['s'])) { $start = $_GET['s']; } else { $start = 0; } //content goes here if ($pages > 1) { echo '<br /><p>'; $current_page = ($start/$display) + 1; if ($current_page != 1) { echo '<a href="index.php">First</a>'; } if ($current_page != 1) { echo '<a href="index.php?s=' . ($start - $display) . '&p=' . $pages . '">Previous</a> '; } for ($i = 1; $i <= $pages; $i++) { if ($i != $current_page) { echo '<a href="index.php?s=' . (($display * ($i - 1))) . '&p=' . $pages . '">' . $i . '</a> '; } else { echo '<span>' . $i . '</span> '; } } if ($current_page != $pages) { echo '<a href="index.php?s=' . ($start + $display) . '&p=' . $pages . '">Next</a>'; } if ($current_page != $pages) { echo '<a href="index.php?s=' . ($pages - 1) . '&p=' . $pages . '">Last</a>'; } echo '</p>'; }

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  • Best way to program a call to php

    - by hairdresser-101
    I've recently posted here http://stackoverflow.com/questions/2627645/accessing-session-when-using-file-get-contents-in-php about a problem I was having and the general consensus is that I'm not doing it right... while I generally think "as long as it works..." I thought I'd get some feedback on how I could do it better... I was to send the exact same email in the exact same format from multiple different areas. When a job is entered (automatically as a part of the POST) Manually when reviewing jobs to re-assign to another installer The original script is a php page which is called using AJAX to send the work order request - this worked by simply calling a standard php page, returning the success or error message and then displaying within the calling page. Now I have tried to use the same page within the automated job entry so it accepts the job via a form, logs it and mails it. My problem is (as you can see from the original post) the function file_get_contents() is not good for this cause in the automated script... My problem is that from an AJAX call I need to do things like include the database connection initialiser, start the session and do whatever else needs to be done in a standalone page... Some or all of these are not required if it is an include so it makes the file only good for one purpose... How do I make the file good for both purposes? I guess I'm looking for recommendations for the best file layout and structure to cater for both scenarios... The current file looks like: <?php session_start(); $order_id = $_GET['order_id']; include('include/database.php'); function getLineItems($order_id) { $query = mysql_query("SELECT ...lineItems..."); //Print rows with data while($row = mysql_fetch_object($query)) { $lineItems .= '...Build Line Item String...'; } return $lineItems; } function send_email($order_id) { //Get data for current job to display $query = mysql_query("SELECT ...Job Details..."); $row = mysql_fetch_object($query); $subject = 'Work Order Request'; $email_message = '...Build Email... ...Include Job Details... '.getLineItems($order_id).' ...Finish Email...'; $headers = '...Create Email Headers...'; if (mail($row->primary_email, $subject, $email_message, $headers)) { $query = mysql_query("...log successful send..."); if (mysql_error()!="") { $message .= '...display mysqlerror()..'; } $message .= '...create success message...'; } else { $query = mysql_query("...log failed send..."); if (mysql_error()!="") { $message .= '...display mysqlerror()..'; } $message .= '...create failed message...'; } return $message; } // END send_email() function //Check supplier info $query = mysql_query("...get suppliers info attached to order_id..."); if (mysql_num_rows($query) > 0) { while($row = mysql_fetch_object($query)) { if ($row->primary_email=="") { $message .= '...no email message...'; } else if ($row->notification_email=="") { $message .= '...no notifications message...'; } else { $message .= send_email($order_id); } } } else { $message .= '...no supplier matched message...'; } print $message; ?>

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  • Why am I getting a 403 error on a POST to a PHP script?

    - by John Gallagher
    Background I want to allow my users to submit a crash report which will get emailed to me. I'm using UKCrashReporter with the bundled PHP script I've modified. This code does a POST to a specified URL along with the crash report. I'm on a shared server running Linux. My main domain is synapticmishap.co.uk. The Problem When I send the crash report off, on the Cocoa side, it reports as having sent it successfully, but I don't receive an email. The code has been used in lots of other well established Cocoa projects and it was working for me a few months ago. That leads me to conclude that the problems are related to my web server setup, something I know almost nothing about. When I look at my log files, I see entries like this: IP Redacted - - [10/Jun/2010:09:47:53 +0100] "POST /synapticmishap/crashreportform.php HTTP/1.1" 403 74 "-" "UKCrashReporter" What I've tried I've tried accessing the page at http://synapticmishap.co.uk/synapticmishap/crashreportform.php via a browser. It loads fine. I've made sure the permissions on this php script are set so anyone can execute it. I've tried removing the deny entries from the section of .htaccess at various levels starting with root. I've downloaded the URLParams plugin for Firefox which allows you to simulate POSTs. I put in the URL above and tried a post with "crashlog" as the parameter and "test" as the value. This generated a 200 log entry in my log file - it seemed to work, although no mail message was sent. Code I've got the following at http://synapticmishap.co.uk/synapticmishap/crashreportform.php. I've simplified it to just the bare bones in an effort to get it working. <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd"> <html> <head> <title>Crash Report</title> </head> <body> <p>This page contains super special magic which submits a crash report item to me.</p> <p>Nothing to see here - move along.</p> <?php mail( "[email protected]", "Crash Report", "\r\n\r\nThis is a test."); ?> </body> </html> This is my top level .htaccess file: RewriteEngine on # -FrontPage- IndexIgnore .htaccess */.??* *~ *# */HEADER* */README* */_vti* <Limit GET POST> order deny,allow deny from all allow from all </Limit> <Limit PUT DELETE> order deny,allow deny from all </Limit> Options All -Indexes RewriteCond %{HTTP_HOST} ^synapticmishap.co.uk$ [OR] RewriteCond %{HTTP_HOST} ^www.synapticmishap.co.uk$ RewriteCond %{HTTP_HOST} ^lapsusapp.co.uk$ [OR] RewriteCond %{HTTP_HOST} ^www.lapsusapp.co.uk$ RewriteRule ^/?$ "http\:\/\/synapticmishap\.co\.uk\/synapticmishap\/lapsuspromo\/" [R=301,L] RewriteCond %{HTTP_HOST} ^jgtutoring.co.uk$ [OR] RewriteCond %{HTTP_HOST} ^www.jgtutoring.co.uk$ RewriteRule ^/?$ "http\:\/\/synapticmishap\.co\.uk\/tutoring" [R=301,L] RewriteCond %{HTTP_HOST} ^synapticmishap.co.uk$ [OR] RewriteCond %{HTTP_HOST} ^www.synapticmishap.co.uk$ RewriteRule ^/?$ "http\:\/\/synapticmishap\.co\.uk\/synapticmishap" [R=301,L] RewriteCond %{HTTP_HOST} ^jgediting.co.uk$ [OR] RewriteCond %{HTTP_HOST} ^www.jgediting.co.uk$ RewriteRule ^/?$ "http\:\/\/synapticmishap\.co\.uk\/editing" [R=301,L] RewriteCond %{HTTP_REFERER} !^$ RewriteCond %{HTTP_REFERER} !^http://synapticmishap.co.uk/.*$ [NC] RewriteCond %{HTTP_REFERER} !^http://synapticmishap.co.uk$ [NC] RewriteCond %{HTTP_REFERER} !^http://www.synapticmishap.co.uk/.*$ [NC] RewriteCond %{HTTP_REFERER} !^http://www.synapticmishap.co.uk$ [NC] RewriteCond %{HTTP_REFERER} !^http://synapticmishap.co.uk/synapticmishap/crashreportform.php/.*$ [NC] RewriteCond %{HTTP_REFERER} !^http://synapticmishap.co.uk/synapticmishap/crashreportform.php$ [NC] RewriteRule .*\.(jpg|jpeg|gif|png|bmp)$ - [F,NC] Help! I'm at the end of my tether with this and I'm in a very unfamiliar space with all this web stuff. I'd be most appreciative of any thoughts people had on why this isn't working. Thanks.

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  • How do I run Firefox OS as a standalone application?

    - by JamesTheAwesomeDude
    I got the add-on for the Firefox OS simulator, and it works great! It even keeps functioning after Firefox is closed, so I can save processing power for other things. I'd like to run it as a standalone application, so that I don't even have to open Firefox in the first place. I've gone to the System Monitor, and it says that the process (I guessed which by CPU usage and filename) was started via /home/james/.mozilla/firefox-trunk/vkuuxfit.default/extensions/[email protected]/resources/r2d2b2g/data/linux64/b2g/plugin-container 3386 true tab, so I tried running that in the Terminal (after I'd closed the simulator, of course,) but it gives this: james@james-OptiPlex-GX620:~/.mozilla/firefox-trunk/vkuuxfit.default/extensions/[email protected]/resources/r2d2b2g/data/linux64/b2g$ ./plugin-container 3386 true tab ./plugin-container: error while loading shared libraries: libxpcom.so: cannot open shared object file: No such file or directory james@james-OptiPlex-GX620:~/.mozilla/firefox-trunk/vkuuxfit.default/extensions/[email protected]/resources/r2d2b2g/data/linux64/b2g$ What should I do? Is what I'm attempting even possible? (It should be, since the simulator kept running even after Firefox itself was closed...) NOTE: I've tried chmod u+sx plugin-container, but that didn't help.

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  • library put in /usr/local/lib is not loaded

    - by IARI
    Let me state in advance: One might think this question would is for server fault, but I think is is Ubuntu (config) specific. In short: I have put libwkhtmltox.so in /usr/local/lib as stated in installation instructions linked below, but it appears the library is not loaded. I am trying to install php-wkhtmltox, a php extension for wkhtmltox on my local desktop (Ubuntu 12.04). I have extracted the source and changed to the corresponding directory. After running phpize, ./configure fails at checking for libwkhtmltox support... yes, shared not found configure: error: Please install libwkhtmltox I suspect the reason the library is not loaded is that the path is not checked!? how do I proceed? Here are instructions I followed: http://davidbomba.com/index.php/2011/08/04/php-wkhtmltox/ http://roundhere.net/journal/install-wkhtmltopdf-php-bindings/

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  • Version Changes: How considerable are the compatibility issues in project?

    - by Aditya P
    For example if we consider ActionScript2.0(based on Objects but programming does not implement much OOP ) vs 3.0(highly OOP) its like a whole new scripting language in the sense of approach, programming style,features you get the idea. In PHP we can see current versions going from 3-5. brief version changes Question :Developers who work on PHP is it easy to migrate from version to version? Question :Are there any extensive compatibility issues, forward or backward? Question :Does your project stick to a particular version till the end ? Question :Does the programming style ,approach change from version to version? Question :If you had to get started on PHP to contribute to a project built earlier versions, would learning the latest version be counterproductive towards this aim? Some related topics i had come across on SE How should I be keeping track of php script version/changes? What is happening to PHP 6? It would be Really helpful in understanding if you could answer this topic directly to the questions put forth.

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  • How does PHP5 fare with earlier versions of the language

    - by Pankaj Upadhyay
    I would like to learn PHP for web development but have been drawn back because of comments like the following*: PHP is good but generates spaghetti code PHP is nice but Python is marriage material PHP lacks stuff that you get in other languages like C# or Java But for PHP5 I have seen some promising comments. So, my question is: How does PHP5 fare with earlier versions of the language and is it good enough now to learn for web development. * Comments are just for reference not to incite a flame war. No comparison of PHP with other languages is asked for here. Please comment just on PHP5 and how it compares with earlier versions.

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  • How to optimise the url for search engines?

    - by phpheini
    I have a php template which has one index.php and all the different pages (content1.html, content2.html etc) are shown on the index.phppage. So for example I can open www.example.com/index.php?content1 and it will show the content1.html. Now what I would like is this: Often you see websites where the url is like: www.example.com/this-is-the-content I know how to do this with an exclamation mark like www.example.com/?content1 <-- here you just dont write the index.php. But how can I do an url name, which is completely different from the filename? For example www.example.com/this-is-some-page would show me the content of index.php?content1

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  • Inspect the referrer in PHP

    - by Ngu Soon Hui
    Is it possible to check who is entering your website in PHP. I have a web application ( written in PHP) that should only allow users entering from some particular websites. Is it possible to get the referral websites by examining the _Request object? If yes, how?

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  • how to enable sqlite3 for php?

    - by terrani
    Hi, I am trying to install sqlite3 for php in ubuntu. I install apt-get php5-sqlite3 and edited php.ini to include sqlite3 extension. When I run phpinfo(); I get SQLITE3 SQLite3 support enabled sqlite3 library version 3.4.2 as shown above, sqlite3 is enabled. However, I get "Class SQLite3 not found" when I use new SQLite3("database");

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  • Simple POST random number issue in PHP

    - by MrEnder
    Ok I am trying to make something to ask you random multiplication questions. Now it asks the questions fine. Generates the random questions fine. But when it reloads the page the random numbers are different... how can I fix this? <?php $rndnum1 = rand(1, 12); $rndnum2 = rand(1, 12); echo "<h3>". $rndnum1 . " x "; echo $rndnum2 . "</h3>"; if($_SERVER["REQUEST_METHOD"] == "GET") { $answer=0; } else if($_SERVER["REQUEST_METHOD"] == "POST") { $answer=trim($_POST["answerInput"]); $check=$rndnum1*$rndnum2; if($answer==$check) { echo "Correct!"; } else { echo "Wrong!"; } } ?> <form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post" > <table> <tr> <td> First Name:&nbsp; </td> <td> <input type="text" name="answerInput" value="<?php echo $answer; ?>" size="20"/> </td> <td> <?php echo $answerError; ?> </td> </tr> <tr> <td class="signupTd" colspan="2"> <input type="submit" name="submit" value="Submit"/> </td> </tr> </table> </form>

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  • Generating a salt in PHP

    - by qster
    What's the best way to generate a cryptographically secure 32 bytes salt in PHP, without depending on libraries seldom included in typical PHP installations? After some googling I discovered that mt_rand is not considered secure enough, but I haven't found a suggestion for a replacement. One article suggested reading from /dev/random but not only this won't work on windows; it is also very slow. I want a reasonable balance between security and speed (ie, it shouldn't take 20 seconds to generate 512 bytes, like /dev/random usually does)

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  • php form-input validation

    - by fusion
    i have a html page in which i enter data which then submits and inserts in a database on a php page. how would i validate in php that the data received is not a duplicate of the data in the database? any help appreciated.

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  • Salesforce/PHP - Bulk Outbound message (SOAP), Time out issue

    - by Phill Pafford
    Salesforce can send up to 100 requests inside 1 SOAP message. While sending this type of Bulk Ooutbound message request my PHP script finishes executing but SF fails to accept the ACK used to clear the message queue on the Salesforce side of things. Looking at the Outbound message log (monitoring) I see all the messages in a pending state with the Delivery Failure Reason "java.net.SocketTimeoutException: Read timed out". If my script has finished execution, why do I get this error? I have tried these methods to increase the execution time on my server as I have no access on the Salesforce side: set_time_limit(0); // in the script max_execution_time = 360 ; Maximum execution time of each script, in seconds max_input_time = 360 ; Maximum amount of time each script may spend parsing request data memory_limit = 32M ; Maximum amount of memory a script may consume I used the high settings just for testing. Any thoughts as to why this is failing the ACK delivery back to Salesforce? Here is some of the code: This is how I accept and send the ACK file for the imcoming SOAP request $data = 'php://input'; $content = file_get_contents($data); if($content) { respond('true'); } else { respond('false'); } The respond function function respond($tf) { $ACK = <<<ACK <?xml version = "1.0" encoding = "utf-8"?> <soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> <soapenv:Body> <notifications xmlns="http://soap.sforce.com/2005/09/outbound"> <Ack>$tf</Ack> </notifications> </soapenv:Body> </soapenv:Envelope> ACK; print trim($ACK); } These are in a generic script that I include into the script that uses the data for a specific workflow. I can process about 25 requests (That are in 1 SOAP response) but once I go over that I get the timeout error in the Salesforce queue. for 50 requests is usually takes my PHP script 86.77 seconds. Could it be Apache? PHP? I have also tested just accepting the 100 request SOAP response and just accepting and sending the ACK the queue clears out, so I know it's on my side of things. I show no errors in the apache log, the script runs fine. Thanks for any insight into this, --Phill

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  • What is wrong with my PHP/MySQL code?

    - by James
    I am building a navigation menu which lists all my categories and subcategories. The problem is it returns only one of these and not all. I have the categories echoed inside the while loop so I'm not sure why it's only showing one result and not all: <?php $query = mysql_query("SELECT * FROM categories_parent"); while ($row = mysql_fetch_assoc($query)) { $id = $row['id']; $name = $row['name']; $slug = $row['slug']; $childStatus = $row['child_status']; // if has child categories if ($childStatus == "1") { echo "<li class='dir'><a href='category.php?slug=$slug'>$name</a>"; echo "<ul id='dropdown'>"; $query = mysql_query("SELECT * FROM categories_child WHERE parent=$id"); while ($row = mysql_fetch_assoc($query)) { $id = $row['id']; $name = $row['name']; $slug = $row['slug']; echo "<li><a href='category.php?slug=$slug'>$name</a></li>"; } echo "</ul>"; echo "</li>"; } // if singular parent else { echo "<li><a href='category.php?slug=$slug'>$name</a></li>"; } } ?> My database tables: -- -- Table structure for table `categories_child` -- CREATE TABLE IF NOT EXISTS `categories_child` ( `id` int(11) NOT NULL AUTO_INCREMENT, `name` varchar(1000) NOT NULL, `slug` varchar(1000) NOT NULL, `parent` int(11) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=139 ; -- -- Dumping data for table `categories_child` -- INSERT INTO `categories_child` (`id`, `name`, `slug`, `parent`) VALUES (138, 'Britney Spears', 'category/celiberties/britney-spears/', 137), (136, 'Tigers', 'category/animals/tigers/', 136), (137, 'Horses', 'category/animals/horses/', 136), (135, 'Lions', 'category/animals/lions/', 136); -- -- Table structure for table `categories_parent` -- CREATE TABLE IF NOT EXISTS `categories_parent` ( `id` int(11) NOT NULL AUTO_INCREMENT, `name` varchar(1000) NOT NULL, `slug` varchar(1000) NOT NULL, `child_status` int(1) NOT NULL DEFAULT '0', PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=139 ; -- -- Dumping data for table `categories_parent` -- INSERT INTO `categories_parent` (`id`, `name`, `slug`, `child_status`) VALUES (137, 'Celiberties', 'category/celiberties/', 1), (138, 'TV Shows', 'category/tv-shows/', 0), (136, 'Animals', 'category/animals/', 1);

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  • Upload an image using class.upload.php via AJAX, display image in form using jQuery

    - by Benjamin
    I am using class.upload.php to handle an image upload from a form that submits employee details to a MySQL database. class.upload.php does EXACTLY what I want it to do, resize the image and rename it - what I am now trying to accomplish is to upload via Ajax after the user selects the file and then display it in the form while they continue entering details. How would this best be accomplished with jQuery?

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  • file doesn't open using PHP fopen

    - by jesop
    i have tried this: <?php $fileip = fopen("test.txt","r"); ?> this should have opened the file in read only mood but it doesn't the test.txt file is in same folder as that of index.php (main project folder) the file doesn't open and when i put echo like : echo $fileip; it returned Resource id #3

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  • PHP GD Reflection with original picture on top

    - by Steve Thomas
    Hi, I have stumbled upon a nice PHP library that uses GD to generate a reflection of a picture. I tried to modify the way so it also display the original image above its reflection to not have to align them in HTML. The script can be found there : http://reflection.corephp.co.uk/v3.php Any idea if this can be done easily ? With my tests, the alpha gradient effect wasnt applied at all. Thank you in advance.

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