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  • You need to format the disk in drive

    - by Sab
    I was copying some files over to my external hard disk and suddenly a message popped up saying that some file was open and it could not continue.It asks me whether I want to cancel the operation and I said cancel(The other operation was continue.) After that whenever I plug in the usb into the same computer it does not work. It keeps saying that I need to format the disk to continue. Luckily for me it opened on another computer and am backing up all my data. But now I am wondering why exactly this happened. Is it that the hard disk is weak. Also as an addon I currently use http://www.dtidata.com/windowssurfacescanner/ program to check for bad sectors. Is this the recommended way or is there some other better more reliable way to check if my hard disk is failing? Also could the above problem be because the hard disk is failing? If not why does it happen.Even if the hard disk is interrupted in the middle of a read write cycle doesnt there exist error handling code to enable gracefull recovery?

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  • Can't login via ssh after upgrading to Ubuntu 12.10

    - by user42899
    I have an Ubuntu 12.04LTS instance on AWS EC2 and I upgraded it to 12.10 following the instructions at https://help.ubuntu.com/community/QuantalUpgrades. After upgrading I can no longer ssh into my VM. It isn't accepting my ssh key and my password is also rejected. The VM is running, reachable, and SSH is started. The problem seems to be about the authentication part. SSH has been the only way for me to access that VM. What are my options? ubuntu@alice:~$ ssh -v -i .ssh/sos.pem [email protected] OpenSSH_5.9p1 Debian-5ubuntu1, OpenSSL 1.0.1 14 Mar 2012 debug1: Reading configuration data /home/ubuntu/.ssh/config debug1: Reading configuration data /etc/ssh/ssh_config debug1: /etc/ssh/ssh_config line 19: Applying options for * debug1: Connecting to www.hostname.com [37.37.37.37] port 22. debug1: Connection established. debug1: identity file .ssh/sos.pem type -1 debug1: identity file .ssh/sos.pem-cert type -1 debug1: Remote protocol version 2.0, remote software version OpenSSH_5.9p1 Debian-5ubuntu1 debug1: match: OpenSSH_5.9p1 Debian-5ubuntu1 pat OpenSSH* debug1: Enabling compatibility mode for protocol 2.0 debug1: Local version string SSH-2.0-OpenSSH_5.9p1 Debian-5ubuntu1 debug1: SSH2_MSG_KEXINIT sent debug1: SSH2_MSG_KEXINIT received debug1: kex: server->client aes128-ctr hmac-md5 none debug1: kex: client->server aes128-ctr hmac-md5 none debug1: sending SSH2_MSG_KEX_ECDH_INIT debug1: expecting SSH2_MSG_KEX_ECDH_REPLY debug1: Server host key: RSA 33:33:33:33:33:33:33:33:33:33:33:33:33:33 debug1: Host '[www.hostname.com]:22' is known and matches the RSA host key. debug1: Found key in /home/ubuntu/.ssh/known_hosts:12 debug1: ssh_rsa_verify: signature correct debug1: SSH2_MSG_NEWKEYS sent debug1: expecting SSH2_MSG_NEWKEYS debug1: SSH2_MSG_NEWKEYS received debug1: Roaming not allowed by server debug1: SSH2_MSG_SERVICE_REQUEST sent debug1: SSH2_MSG_SERVICE_ACCEPT received debug1: Authentications that can continue: publickey,password debug1: Next authentication method: publickey debug1: Trying private key: .ssh/sos.pem debug1: read PEM private key done: type RSA debug1: Authentications that can continue: publickey,password debug1: Next authentication method: password [email protected]'s password: debug1: Authentications that can continue: publickey,password Permission denied, please try again.

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  • SQL Server Reporting Services - website blank, builder works

    - by Keith
    We have a few reports in SQL Server Reporting Services. For some reason when we run the report from the website, it doesn't return any data. When I run the same report from the Report Builder, it returns data. I looked in the logs and the only errors I could find is: ReportingServicesService!library!8!6/15/2012-08:12:33:: i INFO: Current DB Version Unknown, Instance Version C.0.8.54. ReportingServicesService!library!8!6/15/2012-08:12:33:: e ERROR: Throwing Microsoft.ReportingServices.Diagnostics.Utilities.InvalidReportServerDatabaseException: The version of the report server database is either in a format that is not valid, or it cannot be read. The found version is 'Unknown'. The expected version is 'C.0.8.54'. To continue, update the version of the report server database and verify access rights., ;Info: Microsoft.ReportingServices.Diagnostics.Utilities.InvalidReportServerDatabaseException: The version of the report server database is either in a format that is not valid, or it cannot be read. The found version is 'Unknown'. The expected version is 'C.0.8.54'. To continue, update the version of the report server database and verify access rights. ReportingServicesService!library!8!6/15/2012-08:12:33:: e ERROR: Exception caught while starting service. Error: Microsoft.ReportingServices.Diagnostics.Utilities.InvalidReportServerDatabaseException: The version of the report server database is either in a format that is not valid, or it cannot be read. The found version is 'Unknown'. The expected version is 'C.0.8.54'. To continue, update the version of the report server database and verify access rights. I'm not really sure why it would be a different version. It's all SQL Server 2008 R2 and I haven't made any changes to it since it's been running.

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  • Can I use multiple URLs in the URL field of KeePass?

    - by Sammy
    I am using KeePass version 2.19. What I would like to do is have more than just one URL address associated with a given user name and password. The entry for a given website might look something like this... Title google User Name email Password pass URL https://accounts.google.com/ServiceLogin?hl=en&continue=https://www.google.com/ https://accounts.google.com/ServiceLogin?hl=sv&continue=https://www.google.com/ https://accounts.google.com/ServiceLogin?hl=de&continue=https://www.google.com/ As you can see the ?hl=en changes into ?hl=sv and then to ?hl=de for the three different languages in which I wish to view the Google log-in page. But this of course could be something completely different, like different web services from the same provider like YouTube and Gmail by Google. Very much like SE where you have several websites but only use one user name and password. I imagine something along the lines of having multiple entries for one and the same website, where KeePass would actually prompt you to choose which one you want to use. So you have several user names and passwords that use the same URL. But is it possible to have several URLs using the same user name and password, so that KeePass asks me "to which of the following three URLs do you want to auto-log into with this password"?

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  • Windows 7 & Photoshop CS5.1 - "Fonts missing" issue - I have the font!! (sort of)

    - by Tigue Von Bond
    I've noticed a really aggravating issue with Adobe Photoshop CS5.1 on at least two occasions. I downloaded a layered PSD file to work with, in the release notes it directed me to a download page for all of the font used, which was Futura Medium Condensed. I chcked and did not have any Futura fonts at all. So I downloaded and installed the font from the source provided by the provider of the PSD. I closed and reopened Photoshop and when I open the PSD file I get an error saying: Some text layers contain fonts that are missing. These layers will need to have the missing fonts replaced before they can be used for vector based output. I then go to edit the text layer and receive: The following fonts are missing for text layer "discount" Future CondensedExtraBold Font substitution will occur. Continue? If I click OK, it substitutes Myriad Pro for this layer. Didn't I download the right font? I go into the font dropdown and see I have a font with a slightly different name "Futura-CondensedExtraBold-Th Regular" I have also seen this issue with Helvetica. I have received a PSD file, same "some text layers contain fonts that are missing These..." error dialog when I open up the file - and when I go to edit a layer with text I get: The following fonts are missing for text layer "Home": Helvetica Font substitution will occur. Continue? I click continue - it substitutes Myriad Pro - and check my font list and sure enough I have a bunch of Helvetica fonts, none exactly named "Helvetica" Is this a common issue? Googling it yielded a few people with similar problems (I think all on Macs) but either no concrete help or no response. Is it that the two font names aren't EXACT matches? If that is the case is there any way of setting up Photoshop to more intelligently substitute or even set up some sort of mapping (if "Helvetica" then substitute "Helvetica Lt Std" ? Is there anything else, maybe something that I am not thinking of?

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  • Ubuntu 9.10 RSA authentication: ssh fails, filezilla runs fine

    - by MariusPontmercy
    This is quite a mistery for me. I usually use passwordless RSA authentication to login into my remote *nix servers with ssh and sftp. Never had any problem until now. I cannot connect to an Ubuntu 9.10 machine: user@myclient$ ssh -i .ssh/Ganymede_key [email protected] [...] debug1: Host 'ganymede.server.com' is known and matches the RSA host key. debug1: Found key in /home/user/.ssh/known_hosts:14 debug2: bits set: 494/1024 debug1: ssh_rsa_verify: signature correct debug2: kex_derive_keys debug2: set_newkeys: mode 1 debug1: SSH2_MSG_NEWKEYS sent debug1: expecting SSH2_MSG_NEWKEYS debug2: set_newkeys: mode 0 debug1: SSH2_MSG_NEWKEYS received debug1: SSH2_MSG_SERVICE_REQUEST sent debug2: service_accept: ssh-userauth debug1: SSH2_MSG_SERVICE_ACCEPT received debug2: key: .ssh/Ganymede_key (0xb96a0ef8) debug2: key: .ssh/Ganymede_key ((nil)) debug1: Authentications that can continue: publickey,password,keyboard-interactive debug1: Next authentication method: publickey debug1: Offering public key: .ssh/Ganymede_key debug2: we sent a publickey packet, wait for reply debug1: Authentications that can continue: publickey,password,keyboard-interactive debug1: Trying private key: .ssh/Ganymede_key debug1: read PEM private key done: type RSA debug2: we sent a publickey packet, wait for reply debug1: Authentications that can continue: publickey,password,keyboard-interactive debug2: we did not send a packet, disable method debug1: Next authentication method: keyboard-interactive debug2: userauth_kbdint debug2: we sent a keyboard-interactive packet, wait for reply debug2: input_userauth_info_req debug2: input_userauth_info_req: num_prompts 1 Then it falls back to password authentication. If I disable password authentication on the remote machine my connection attempt just fails with a "Permission denied (publickey)." state. Same thing for sftp from command line. The "funny" thing is that the exact same RSA key works like a charm with a Filezilla sftp session instead: 12:08:00 Trace: Offered public key from "/home/user/.filezilla/keys/Ganymede_key" 12:08:00 Trace: Offer of public key accepted, trying to authenticate using it. 12:08:01 Trace: Access granted 12:08:01 Trace: Opened channel for session 12:08:01 Trace: Started a shell/command 12:08:01 Status: Connected to ganymede.server.com 12:08:02 Trace: CSftpControlSocket::ConnectParseResponse() 12:08:02 Trace: CSftpControlSocket::ResetOperation(0) 12:08:02 Trace: CControlSocket::ResetOperation(0) 12:08:02 Status: Retrieving directory listing... 12:08:02 Trace: CSftpControlSocket::SendNextCommand() 12:08:02 Trace: CSftpControlSocket::ChangeDirSend() 12:08:02 Command: pwd 12:08:02 Response: Current directory is: "/root" 12:08:02 Trace: CSftpControlSocket::ResetOperation(0) 12:08:02 Trace: CControlSocket::ResetOperation(0) 12:08:02 Trace: CSftpControlSocket::ParseSubcommandResult(0) 12:08:02 Trace: CSftpControlSocket::ListSubcommandResult() 12:08:02 Trace: CSftpControlSocket::ResetOperation(0) 12:08:02 Trace: CControlSocket::ResetOperation(0) 12:08:02 Status: Directory listing successful Any thoughts? M

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  • Password-less login into localhost

    - by Brad
    I am trying to setup password-less login into my localhost because it's required for a tutorial. I went through the normal steps of generating an rsa key and appending the public key to authorized_keys but I am still prompted for a password. I've also enabled RSAAuthentication and PubKeyAuthentication in /etc/ssh_config. Following other suggestions I've seen, I tried: chmod go-w ~/ chmod 700 ~/.ssh chmod 600 ~/.ssh/authorized_keys But the problem persists. Here is the output from ssh -v localhost: (tutorial)bnels21-2:tutorial bnels21$ ssh -v localhost OpenSSH_5.9p1, OpenSSL 0.9.8r 8 Feb 2011 debug1: Reading configuration data /etc/ssh_config debug1: /etc/ssh_config line 20: Applying options for * debug1: Connecting to localhost [::1] port 22. debug1: Connection established. debug1: identity file /Users/bnels21/.ssh/id_rsa type 1 debug1: identity file /Users/bnels21/.ssh/id_rsa-cert type -1 debug1: identity file /Users/bnels21/.ssh/id_dsa type -1 debug1: identity file /Users/bnels21/.ssh/id_dsa-cert type -1 debug1: Remote protocol version 2.0, remote software version OpenSSH_5.9 debug1: match: OpenSSH_5.9 pat OpenSSH* debug1: Enabling compatibility mode for protocol 2.0 debug1: Local version string SSH-2.0-OpenSSH_5.9 debug1: SSH2_MSG_KEXINIT sent debug1: SSH2_MSG_KEXINIT received debug1: kex: server->client aes128-ctr hmac-md5 none debug1: kex: client->server aes128-ctr hmac-md5 none debug1: SSH2_MSG_KEX_DH_GEX_REQUEST(1024<1024<8192) sent debug1: expecting SSH2_MSG_KEX_DH_GEX_GROUP debug1: SSH2_MSG_KEX_DH_GEX_INIT sent debug1: expecting SSH2_MSG_KEX_DH_GEX_REPLY debug1: Server host key: RSA 1c:31:0e:56:93:45:dc:f0:77:6c:bd:90:27:3b:c6:43 debug1: Host 'localhost' is known and matches the RSA host key. debug1: Found key in /Users/bnels21/.ssh/known_hosts:11 debug1: ssh_rsa_verify: signature correct debug1: SSH2_MSG_NEWKEYS sent debug1: expecting SSH2_MSG_NEWKEYS debug1: SSH2_MSG_NEWKEYS received debug1: Roaming not allowed by server debug1: SSH2_MSG_SERVICE_REQUEST sent debug1: SSH2_MSG_SERVICE_ACCEPT received debug1: Authentications that can continue: publickey,keyboard-interactive debug1: Next authentication method: publickey debug1: Offering RSA public key: /Users/bnels21/.ssh/id_rsa debug1: Authentications that can continue: publickey,keyboard-interactive debug1: Offering RSA public key: id_rsa3 debug1: Authentications that can continue: publickey,keyboard-interactive debug1: Trying private key: /Users/bnels21/.ssh/id_dsa debug1: Next authentication method: keyboard-interactive Password: Any suggestions? I'm running OSX 10.8.

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  • certificate SSH login does not work on 22 but other port

    - by Hugo
    On my Red Hat server, the sshd will not accept my correct certificate login. However, If i start another sshd on another port, it works! (I assume the second sshd loads the same configruation files.) second sshd started with: sudo /usr/sbin/sshd -p 54321 -d #-d is optional and prints debug output ssh strange-host -p 22 -vvv prints: debug1: Authentications that can continue: publickey,gssapi-keyex,gssapi-with-mic,password debug1: Offering public key: /home/me/.ssh/id_dsa debug3: send_pubkey_test debug2: we sent a publickey packet, wait for reply debug3: Wrote 528 bytes for a total of 2389 debug1: Authentications that can continue: publickey,gssapi-keyex,gssapi-with-mic,password debug2: we did not send a packet, disable method debug3: authmethod_lookup password ssh strange-host -p 54321 -vvv prints: debug1: Authentications that can continue: publickey,gssapi-keyex,gssapi-with-mic,password debug1: Offering public key: /home/me/.ssh/id_dsa debug3: send_pubkey_test debug2: we sent a publickey packet, wait for reply debug3: Wrote 528 bytes for a total of 2389 debug1: Server accepts key: pkalg ssh-dss blen 433 debug2: input_userauth_pk_ok: SHA1 fp 0f:1c:df:27:f7:86:49:a8:47:7e:7f:f3:32:1c:7d:04:a3:73:a5:72 So the question is why the difference? I have thought of no way to get any helpful logging from the "standard" sshd to troubleshoot the problem.

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  • Executing a workflow from another workflow ?

    - by Mina Samy
    Hi all I have a console sequential workflow that at a certain step I use the InvokeWorkflow activity to invoke another workflow and then check a certain value that is set by the second workflow, and continue the execution of the first workflow normally the problem is when InvokeWorkflow activity is executed the program executes the second workflow and exits, the execution is not returned back to the first workflow. is there a way to call the second workflow from the first and wait till it ends and then continue the execution of the first. thanks

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  • NSFetchRequest returns correct number of objects, but each object contains nil attributes

    - by BU
    Hi, I can't figure out why this is happening. I can add to the context. But when I retrieve the objects, it returns the correct number of objects but the attributes of the objects are null. I am adding 3 instances with this code: +(BOOL)addStoreWithID:(NSNumber *)ID Latitude:(NSNumber *)latitude Longitude:(NSNumber *)longitude Name:(NSString *)name { Stores *store = (Stores *)[NSEntityDescription insertNewObjectForEntityForName:@"Stores" inManagedObjectContext:[[SharedResources instance] managedObjectContext]]; store.ID = ID; store.Latitude = latitude; store.Longitude = longitude; store.Name = name; NSError *error; if(![[[SharedResources instance] managedObjectContext] save:&error]) { //Handle the error return NO; } return YES; } I get the result: 2010-03-07 19:19:37.060 GamePouch_iPhone[11337:207] Store name is Starbucks (gdb) continue 2010-03-07 19:19:37.933 GamePouch_iPhone[11337:207] Store name is Dunkin Donuts (gdb) continue 2010-03-07 19:19:38.717 GamePouch_iPhone[11337:207] Store name is Krispy Kreme I have confirmed that this code is visited three times and none of the attributes are nil. Then when I try to retrieve it, I use the following code: +(NSMutableArray *)fetchAllObjects { NSFetchRequest *request; request = [[NSFetchRequest alloc] init]; NSEntityDescription *entity = [NSEntityDescription entityForName:@"Stores" inManagedObjectContext:[[SharedResources instance] managedObjectContext]]; [request setEntity:entity]; NSSortDescriptor *sortDescriptor = [[NSSortDescriptor alloc] initWithKey:@"ID" ascending:YES]; NSArray *sortDescriptors = [[NSArray alloc] initWithObjects:sortDescriptor, nil]; [request setSortDescriptors:sortDescriptors]; NSError *error; NSMutableArray *array = [[[SharedResources instance] managedObjectContext] executeFetchRequest:request error:&error]; [request release]; [sortDescriptor release]; [sortDescriptors release]; for(int i=0;i<3;i++) { Stores *tempStore = (Stores *)[array objectAtIndex:i]; NSLog(@"store name is %@",[tempStore Name]); } return array; } I get the result: 2010-03-07 19:21:00.504 GamePouch_iPhone[11337:207] store name is (null) (gdb) continue 2010-03-07 19:21:01.541 GamePouch_iPhone[11337:207] store name is (null) (gdb) continue 2010-03-07 19:21:02.503 GamePouch_iPhone[11337:207] store name is (null) Thanks a lot for reading. Any help would be much appreciated. Thanks Bakhtiyar uddin

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  • How can I execute a non-blocking System.Beep()?

    - by Siracuse
    In C# I can perform a Console.Beep(). However, if you specify a duration of say 1000, or 1 second, it will not execute the next line of code until that second passes. Is there any way possible to execute Console.Beep() in a non-blocking fashion so it will continue to beep and still continue executing the code below it while beeping?

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  • Why won't this hit test fire a second time? wpf

    - by csciguy
    All, I have a main window that contains two custom objects (AnimatedCharacter). These objects are nothing but images. These images might contain transparent portions. One of these objects slightly overlaps the other object. There is a listener attached to the main window and is as follows. private void Window_MouseLeftButtonUp_1(object sender, MouseButtonEventArgs e) { Point pt = e.GetPosition((UIElement)sender); //store off the mouse pt hitPointMouse = pt; //clear the result list hitResultsSubList.Clear(); EllipseGeometry m_egHitArea = new EllipseGeometry(pt, 1, 1); VisualTreeHelper.HitTest(sender as Visual, HitTestFilterFuncNew, new HitTestResultCallback(HitTestCallback), new GeometryHitTestParameters(m_egHitArea)); //Check all sub items you have now hit if (hitResultsSubList.Count > 0) { CheckSubHitItems(hitResultsSubList); } } The idea is to filter out only a select group of items (called AnimatedCharacters). The hittest and filters are as follows public HitTestResultBehavior HitTestCallback(HitTestResult htrResult) { IntersectionDetail idDetail = ((GeometryHitTestResult)htrResult).IntersectionDetail; switch (idDetail) { case IntersectionDetail.FullyContains: return HitTestResultBehavior.Continue; case IntersectionDetail.Intersects: return HitTestResultBehavior.Continue; case IntersectionDetail.FullyInside: return HitTestResultBehavior.Continue; default: return HitTestResultBehavior.Stop; } } public HitTestFilterBehavior HitTestFilterFuncNew(DependencyObject potentialHitTestTarget) { if (potentialHitTestTarget.GetType() == typeof(AnimatedCharacter)) { hitResultsSubList.Add(potentialHitTestTarget as AnimatedCharacter); } return HitTestFilterBehavior.Continue; } This returns me back a list (called hitResultsSubList) that I attempt to then process further. I want to take everything in the hitResultsSubList and run a hit test on it again. This time, the hit test will be checking alpha levels on the particular animatedCharacter object. private void CheckSubHitItems(List<DependencyObject> hitResultsSub) { for(int i = 0; i<hitResultsSub.Count; i++) { hitResultsList.Clear(); AnimatedCharacter ac = hitResultsSub[i] as AnimatedCharacter; try { //DEBUGGER SKIPS THIS NEXT LINE EVERY SINGLE TIME. VisualTreeHelper.HitTest(ac, null, new HitTestResultCallback(hitCallBack), new PointHitTestParameters(hitPointMouse)); } catch (Exception e) { System.Diagnostics.Debug.WriteLine(e.StackTrace); } if (hitResultsList.Count > 0) { //do something here } } } Here is my problem now. The hit test in the second function (CheckSubHitItems) never gets called. There are definitely items (DependencyObjects of the type AnimatedCharacter) in the hitResultSub, but no matter what, the second hit test will not fire. I can walk the for loop fine, but when that line is hit, I get the following console statement. Step into: Stepping over non-user code 'System.MulticastDelegate.CtorClosed' No exceptions are thrown. Any help is appreciated.

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  • Exit to command line in Python

    - by fuenfundachtzig
    I have a script that I want to exit early under some condition: if not "id" in dir(): print "id not set, cannot continue" # exit here! # otherwise continue with the rest of the script... print "alright..." [ more code ] I run this script using execfile("foo.py") from the Python interactive prompt and I would like the script to exit going back to the command line. How do I do this? If I use sys.exit(), the Python interpreter exits completely.

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  • C - equivalent of .NET Console.ReadLine

    - by John Williams
    I need to accomplish the same behavior as .NET Console.ReadLine function provides. The program execution should continue when the user pushes enter key. The following code is not sufficient, as it requires additional input: printf ("Press Enter to continue"); scanf ("%s",str); Any suggestions?

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  • Stop Search param in directories by grep immediately after param match

    - by yael
    hi friends I use the following command to find under /var some param in my script grep -R "param" /var/* 2/dev/null |grep -wq "param" my problem is that: after grep find the param in file grep continue to search until all searches under /var/* will completed How to perform stop immediately after grep match the param word For example when I run the: grep -R "param" /var/* 2/dev/null |grep -wq "param" grep find the param after one second. But grep continue to sears other same param and its take almost 30 seconds How to stop the grep immediately after param match? THX

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  • Alpha-Beta cutoff

    - by Becky
    I understand the basics of this search, however the beta cut-off part is confusing me, when beta <= value of alphabeta I can either return beta, break, or continue the loop. return beta doesn't seem to work properly at all, it returns the wrong players move for a different state of the board (further into the search tree) break seems to work correctly, it is very fast but it seems a bit TOO fast continue is a lot slower than break but it seems more correct...I'm guessing this is the right way but pseudocode on google all use 'break' but because this is pseudocode I'm not sure what they mean by 'break'

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  • jquery-plugin columnizer: is it really so slow ?

    - by Patrick
    hi, I'm using jquery-plugin columnizer http://www.google.com/search?sourceid=chrome&ie=UTF-8&q=columnizer for this website: http://donatellabernardi.ch/drupal It is sometimes very slow to create the columns (you can try changing the browser window size, or selecting a filter. Sometimes Firefox gives the error message: "Unresponsive Javascript script" and I have to press on continue to continue the navigation. thanks

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  • How to keep a shell open across multiple ajax requests in PHP?

    - by Joost van Doorn
    I need to use a shell across multiple ajax requests. Basically this means that the next request should be able to continue with the same shell where the other process left off. The purpose is to communicate with daemons like FTP to open an FTP connection and log in and in the next request continue with that connection and be able to use it for uploads. But it's not limited to only the FTP daemon (as I know that FTP is supported in PHP).

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  • Python urllib2 multiple try statement on urlopen()

    - by Kura
    So, simply I want to be able to run a for across a list of URLs, if one fails then I want to continue on to try the next. I've tried using the following but sadly it throws and exception if the first URL doesn't work. servers = ('http://www.google.com', 'http://www.stackoverflow.com') for server in servers: try: u = urllib2.urlopen(server) except urllib2.URLError: continue else: break else: raise Any ideas? Thanks in advance.

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  • Is there still a place for XML in the future?

    - by David Neale
    Now that many people seem to be moving towards JSON for web communication I am wondering about why XML should continue to be used. I appreciate that XML has many years on JSON, during which time it has been widely adopted. However, the fact that it is so well-adopted appears to be the one decisive reason why it should continue to be used. Is there a good reason why XML should not gradually be phased out in favour of JSON?

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  • BufferedReader no longer buffering after a while?

    - by BobTurbo
    Sorry I can't post code but I have a bufferedreader with 50000000 bytes set as the buffer size. It works as you would expect for half an hour, the HDD light flashing every two minutes or so, reading in the big chunk of data, and then going quiet again as the CPU processes it. But after about half an hour (this is a very big file), the HDD starts thrashing as if it is reading one byte at a time. It is still in the same loop and I think I checked free ram to rule out swapping (heap size is default). Probably won't get any helpful answers, but worth a try. OK I have changed heap size to 768mb and still nothing. There is plenty of free memory and java.exe is only using about 300mb. Now I have profiled it and heap stays at about 200MB, well below what is available. CPU stays at 50%. Yet the HDD starts thrashing like crazy. I have.. no idea. I am going to rewrite the whole thing in c#, that is my solution. Here is the code (it is just a throw-away script, not pretty): BufferedReader s = null; HashMap<String, Integer> allWords = new HashMap<String, Integer>(); HashSet<String> pageWords = new HashSet<String>(); long[] pageCount = new long[78592]; long pages = 0; Scanner wordFile = new Scanner(new BufferedReader(new FileReader("allWords.txt"))); while (wordFile.hasNext()) { allWords.put(wordFile.next(), Integer.parseInt(wordFile.next())); } s = new BufferedReader(new FileReader("wikipedia/enwiki-latest-pages-articles.xml"), 50000000); StringBuilder words = new StringBuilder(); String nextLine = null; while ((nextLine = s.readLine()) != null) { if (a.matcher(nextLine).matches()) { continue; } else if (b.matcher(nextLine).matches()) { continue; } else if (c.matcher(nextLine).matches()) { continue; } else if (d.matcher(nextLine).matches()) { nextLine = s.readLine(); if (e.matcher(nextLine).matches()) { if (f.matcher(s.readLine()).matches()) { pageWords.addAll(Arrays.asList(words.toString().toLowerCase().split("[^a-zA-Z]"))); words.setLength(0); pages++; for (String word : pageWords) { if (allWords.containsKey(word)) { pageCount[allWords.get(word)]++; } else if (!word.isEmpty() && allWords.containsKey(word.substring(0, word.length() - 1))) { pageCount[allWords.get(word.substring(0, word.length() - 1))]++; } } pageWords.clear(); } } } else if (g.matcher(nextLine).matches()) { continue; } words.append(nextLine); words.append(" "); }

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  • What happens if an exception is thrown during finalize()

    - by Psykocyber
    What would happen if an exception is thrown during the execution of finalize()? Is the stack unwind like normally? Does it continue finalize() and ignore the exception? Does it stop finalize() and continue GC the object? Or something else? I'm not looking for guidelines of using finalize() there are plently of pages explaining that.

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