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  • mysql query: SELECT DISTINCT column1, GROUP BY column2

    - by Adam
    Right now I have the following query: SELECT name, COUNT(name), time, price, ip, SUM(price) FROM tablename WHERE time >= $yesterday AND time <$today GROUP BY name And what I'd like to do is add a DISTINCT by column 'ip', i.e. SELECT DISTINCT ip FROM tablename So my final output would be all the columns, from all the rows that where time is today, grouped by name (with name count for each repeating name) and no duplicate ip addresses. What should my query look like? (or alternatively, how can I add the missing filter to the output with php)? Thanks in advance.

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  • How can I set an account lockout policy for the administrator account on rdp?

    - by reinier
    I'm following this page on security tips for RDP (for my online server): http://www.mobydisk.com/techres/securing_remote_desktop.html Now I don't have a special user account for RDP access. Just the administrator can log on. However, I want to make sure that someone can't brute force the password. I've set the 'account lockout policy' to 3 attempts and a retry after 3 minutes. However, when I connect back with RDP I can still try 5 times before RDP breaks the connection. I can then immediately reconnect and try 5 more times. Any ideas if there is a lockout policy which also holds true fro the admin?

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  • Grouping with operands question

    - by Filip
    I have a table: mysql> desc kursy_bid; +-----------+-------------+------+-----+---------+-------+ | Field | Type | Null | Key | Default | Extra | +-----------+-------------+------+-----+---------+-------+ | datetime | datetime | NO | PRI | NULL | | | currency | varchar(6) | NO | PRI | NULL | | | value | varchar(10) | YES | | NULL | | +-----------+-------------+------+-----+---------+-------+ 3 rows in set (0.01 sec) I would like to select some rows from a table, grouped by some time interval (can be one day) where I will have the first row and the last row of the group, the max(value) and min(value). I tried: select datetime, (select value order by datetime asc limit 1) open, (select value order by datetime desc limit 1) close, max(value), min(value) from kursy_bid_test where datetime > '2009-09-14 00:00:00' and currency = 'eurpln' group by month(datetime), day(datetime), hour(datetime); but the output is: | open | close | datetime | max(value) | min(value) | +--------+--------+---------------------+------------+------------+ | 1.4581 | 1.4581 | 2009-09-14 00:00:05 | 4.1712 | 1.4581 | | 1.4581 | 1.4581 | 2009-09-14 01:00:01 | 1.4581 | 1.4581 | As you see open and close is the same (but they shouldn't be). What should be the query to do what I want?

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  • sql select statement with a group by

    - by user85116
    I have data in 2 tables, and I want to create a report. Table A: tableAID (primary key) name Table B: tableBID (primary key) grade tableAID (foreign key, references Table A) There is much more to both tables, but those are the relevant columns. The query I want to run, conceptually, is this: select TableA.name, avg(TableB.grade) where TableB.tableAID = TableA.tableAID The problem of course is that I'm using an aggregate function (avg), and I can rewrite it like this: select avg(grade), tableAID from TableB group by tableAID but then I only get the ID of TableA, whereas I really need that name column which appears in TableA, not just the ID. Is it possible to write a query to do this in one statement, or would I first need to execute the second query I listed, get the list of id's, then query each record in TableA for the name column... seems to me I'm missing something obvious here, but I'm (quite obviously) not an sql guru...

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  • Top x rows and group by (again)

    - by Tibor Szasz
    Hello, I know it's a frequent question but I just can't figure it out and the examples I found didn't helped. What I learned, the best strategy is to try to find the top and bottom values of the top range and then select the rest, but implementing is a bit tricky. Example table: id | title | group_id | votes I'd like to get the top 3 voted rows from the table, for each group. I'm expecting this result: 91 | hello1 | 1 | 10 28 | hello2 | 1 | 9 73 | hello3 | 1 | 8 84 | hello4 | 2 | 456 58 | hello5 | 2 | 11 56 | hello6 | 2 | 0 17 | hello7 | 3 | 50 78 | hello8 | 3 | 9 99 | hello9 | 3 | 1 I've fond complex queries and examples, but they didn't really helped.

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  • MySQL: filling empty fields with zeroes when using GROUP BY

    - by SaltLake
    I've got MySQL table CREATE TABLE cms_webstat ( ID int NOT NULL auto_increment PRIMARY KEY, TIMESTAMP_X timestamp DEFAULT CURRENT_TIMESTAMP, # ... some other fields ... ) which contains statistics about site visitors. For getting visits per hour I use SELECT hour(TIMESTAMP_X) as HOUR , count(*) AS HOUR_STAT FROM cms_webstat GROUP BY HOUR ORDER BY HOUR DESC which gives me | HOUR | HOUR_STAT | | 24 | 15 | | 23 | 12 | | 22 | 9 | | 20 | 3 | | 18 | 2 | | 15 | 1 | | 12 | 3 | | 9 | 1 | | 3 | 5 | | 2 | 7 | | 1 | 9 | | 0 | 12 | And I'd like to get following: | HOUR | HOUR_STAT | | 24 | 15 | | 23 | 12 | | 22 | 9 | | 21 | 0 | | 20 | 3 | | 19 | 0 | | 18 | 2 | | 17 | 0 | | 16 | 0 | | 15 | 1 | | 14 | 0 | | 13 | 0 | | 12 | 3 | | 11 | 0 | | 10 | 0 | | 9 | 1 | | 8 | 0 | | 7 | 0 | | 6 | 0 | | 5 | 0 | | 4 | 0 | | 3 | 5 | | 2 | 7 | | 1 | 9 | | 0 | 12 | How should I modify the query to get such result? Thanks.

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  • SQL vs MySQL: Rules about aggregate operations and GROUP BY

    - by Phazyck
    In this book I'm currently reading while following a course on databases, the following example of an illegal query using an aggregate operator is given: Find the name and age of the oldest sailor. Consider the following attempt to answer this query: SELECT S.name, S.age FROM Sailors.S The intent is for this query to return not only the maximum age but also the name of the sailors having that age. However, this query is illegal in SQL--if the SELECT clause uses an aggregate operation, then it must use only aggregate operations unless the query contains a GROUP BY clause! Some time later while doing an exercise using MySQL, I faced a similar problem, and made a mistake similar to the one mentioned. However, MySQL didn't complain and just spit out some tables which later turned out not be what I needed. Is the query above really illegal in SQL, but legal in MySQL, and if so, why is that? In what situation would one need to make such a query?

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  • Getting counts of 0 from a query with a double group by

    - by Maltiriel
    I'm trying to write a query that gets the counts for a table (call it item) categorized by two different things, call them type and code. What I'm hoping for as output is the following: Type Code Count 1 A 3 1 B 0 1 C 10 2 A 0 2 B 13 2 C 2 And so forth. Both type and code are found in lookup tables, and each item can have just one type but more than one code, so there's also a pivot (aka junction or join) table for the codes. I have a query that can get this result: Type Code Count 1 A 3 1 C 10 2 B 13 2 C 2 and it looks like (with join conditions omitted): SELECT typelookup.name, codelookup.name, COUNT(item.id) FROM typelookup LEFT OUTER JOIN item JOIN itemcodepivot RIGHT OUTER JOIN codelookup GROUP BY typelookup.name, codelookup.name Is there any way to alter this query to get the results I'm looking for? This is in MySQL, if that matters. I'm not actually sure this is possible all in one query, but if it is I'd really like to know how. Thanks for any ideas.

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  • Working by group by for grouping data into string format

    - by Shantanu Gupta
    I have a table that contains some data given below. It uses a tree like structure i.e. Department SubD1, SubD2 ..... PreSubD1, PreSubD1... PreSubD2, PreSubD2... pk_map_id preferences ImmediateParent Department_Id -------------------- -------------------- -------------------- -------------------- 20 14 5 1 21 15 5 1 22 16 6 1 23 9 4 2 24 4 3 2 25 24 20 2 26 25 20 2 27 23 13 2 I want to group my records on behalf of department then immediate parent then preferences each seperated by ',' i.e. department Immediate Parent preferences 1 5,6 14,15,16 2 4,3,20,13 9,4,24,25,23 and this table also Immediate parent preferences 5 14,15 6 16 4 9 3 4 20 24,25 13 13 In actual scenario all these are my ids which are to be replaced by their string fields. I am using sql server 2k5

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  • how to select and group mysql data based on the follwoing table

    - by user1151680
    how can I achieve the desired result in mysql if my table looks like this. result|year 1 |2011 2 |2011 1 |2011 0 |2011 1 |2012 2 |2012 1 = Won, 2 = lost, 0 = draw Every year can have multiple values like this. Not sure how I can get the desired result like below. year won lost draw totalPlayed 2011 2 1 1 3 2012 1 1 0 2 I have tried the following query but does not get the desired result select year, league_types.league_name, sum(if(result = 1,1,0)) as won, sum(if(result = 0,1,0)) as draw, sum(if(result = 4,1,0)) as noResult, sum(if(result = 2,1,0)) as lost, sum(if(result = 3,1,0)) as tied, sum(if(result > 0 and result < 4,1,0)) as played from match_score_card inner join fixtures on match_score_card.match_id = fixtures.match_id inner join league_types on fixtures.league_id = league_types.league_id where team_id = 1 group by year order by year desc

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  • MySQL query with JOINS and GROUP BY

    - by user1854049
    I'm building a MySQL query but I can't seem to get it right. I have four tables: - customers - orders - sales_rates - purchase_rates There is a 1:n relation 'customernr' between customers and orders. There is a 1:n relation 'ordernr' between orders and sales_rates. There is a 1:n relation 'ordernr' between orders and purchase_rates. What I would like to do is produce an output of all customers with their total purchase and sales amounts. So far I have the following query. SELECT c.customernr, c.customer_name, SUM(sr.sales_price) AS sales_price, SUM(pr.purchase_price) AS purchase_price FROM orders o, customers c, sales_rates sr, purchase_rates pr WHERE o.customernr = c.customernr AND o.ordernr = sr.ordernr AND o.ordernr = pr.ordernr GROUP BY k.bedrijfsnaam The result of the sales_price and purchase_price is far too high. I seem to be getting double counts. What am I doing wrong? Is it possible to perform this in a single query? Thank for your response!

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  • Oracle Group By Issue

    - by m_oLogin
    Hello community, I am strugling with what seems an easy problem to tackle (at least for me in MySQL / SqlServer!) I'll simplify the problem. Let's say I have the following table: Table VOTE ID ID_IDEA DATE_VOTE with ID_IDEA FK(IDEA.ID) 1 3 10/10/10 2 0 09/09/10 3 3 08/08/10 4 3 11/11/10 5 0 06/06/10 6 1 05/05/10 I'm trying to find the latest votes given for each individual idea, meaning I want to return only rows with ID 4, 2 and 6. It seems with Oracle that you can't use GROUP BY without using a function like SUM(), AVG, etc. I'm a bit confused about how it's supposed to work. Please advise, Thanks.

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  • Can I install applications to Remote Desktop Session Hosts via Group Policy?

    - by CC.
    I have a GPO that installs an application using the Software installation policy under Computer Configuration. I assign this GPO to the OU with our desktop/laptop computers, and my clients all install the software fine. I have another separate OU that covers our new Server 2012 RD session hosts. Previously, we've manually installed applications on our one Terminal Server. Now we have one Broker and two Session Hosts. I'd like to take my existing GPO, assign it to the session hosts, and have it install on the next reboot after a gpupdate so I'm sure that each is identically configured. Given this info: Should I be able to install applications via GPO to Session Hosts? Will Group Policy automatically install the applications as if I put the session host into /install mode, or do I need to do that?

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  • Oracle Utilities Application Framework V4.1 Group Fix 4 available

    - by ACShorten
    Oracle Utilities Application Framework V4.1 Group Fix 4 is available from My Oracle Support as Patch 13523301. This Group Fix contains a number of enhancements and keeps fixes up to date to the latest patch level. The enhancements included in this Group Fix include: UI Hints - In previous group fixes of the Oracle Utilities Application Framework the infrastructure to support UI Hints was introduced. This group fix completes the release of this functionality. Prior to this enhancement, products and implementers typically would build at least one UI Map per Business Object to display and/or maintain the object. Whilst, this can be generated using the UI Map maintenance function and stored, this enhancement allows additional tags and elements to be added to the Business Object directly to allow dynamic generation of the UI Map for maintenance and viewing the object. This reduces the need to generate and build a UI Map at all for that object. This will reduce maintenance effort of maintaining the product and implementation by eliminating the need to maintain the HTML for the UI Map. This also allows lower skilled personnel to maintain the system. Help and working examples are available from the View schema attributes and node names option from the Schema Tips dashboard zone. For example: Note: For examples of the hints, refer to an of the following Business Objects F1_OutcomeStyleLookup, F1-TodoSumEmailType, F1-BOStatusReason or F1-BIGeneralMasterConfig. Setting batch log file names -  By default the batch infrastructure supplied with the Oracle Utilities Application Framework sets the name and location of the log files to set values. In Group Fix 4 a set of user exits have been added to allow implementers and partners to set their own filename and location.  Refer to the Release Notes in the download for more details.

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  • Setting up group disk quotas

    - by Ray
    I am hoping to get some advice in setting up disk quotas. So, I know about: Adding usrquota and grpquota on to /etc/fstab for the file systems that need to be managed. Using edquota to assign disk quotas to users. However, I need to do the last step for multiple users and edquota seems to be a bit troublesome. One solution that I have found is that I can do: sudo edquota -u foo -p bar. This will copy the disk quota of bar to user foo. I was wondering if this is the best solution? I tried setting up group disk quotas but they don't seem to be working. Are group quotas meant to help in the assignment of the same quota to multiple users? Or are they suppose to give a total limit to a set of users? For example, if users A, B, C are in group X then assigning a quota of 20 GB gives each user 20 GB or does it give 20 GB to the entire group X to divide up? I'm interested in doing the former, but not the latter. Right now, I've assigned group disk quotas and they aren't working. So, I guess it is due to my misunderstanding of group disk quotas... My problem is I want to easily give the same quota to multiple users; any suggestions on the best way to do this out of what I've tried above or anything else I may not have thought of? Thank you!

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  • Using pkexec policy to run out of /opt/

    - by liberavia
    I still try to make it possible to run my app with root priveleges. Therefore I created two policies to run the application via pkexec (one for /usr/bin and one for /opt/extras... ) and added them to the setup.py: data_files=[('/usr/share/polkit-1/actions', ['data/com.ubuntu.pkexec.armorforge.policy']), ('/usr/share/polkit-1/actions', ['data/com.ubuntu.extras.pkexec.armorforge.policy']), ('/usr/bin/', ['data/armorforge-pkexec'])] ) additionally I added a startscript which uses pkexec for starting the application. It distinguishes between the two places and is used in the Exec-Statement of the desktopfile: #!/bin/sh if [ -f /opt/extras.ubuntu.com/armorforge/bin/armorforge ]; then pkexec "/opt/extras.ubuntu.com/armorforge/bin/armorforge" "$@" else pkexec `which armorforge` "$@" fi If I simply do a quickly package everything will work right. But if I package with extras option: quickly package --extras the Exec-statement will be exchanged. Even if I try to simulate the pkexec call via armorforge-pkexec It will aks for a password and then returns this: andre@andre-desktop:~/Entwicklung/Ubuntu/armorforge$ armorforge-pkexec (armorforge:10108): GLib-GIO-ERROR **: Settings schema 'org.gnome.desktop.interface' is not installed Trace/breakpoint trap (core dumped) So ok, I could not trick the opt-thing. How can I make sure, that my Application will run with root priveleges out of opt. I copied the way of using pkexec from synaptic. My application is for communicating with apparmor which currently has no dbus interface. Else I need to write into /etc/apparmor.d-folder. How should I deal with the opt-build which, as far as I understand, is required to submit my application to the ubuntu software center. Thanks for any hints and/or links :-)

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  • GROUP BY ID range?

    - by d0ugal
    Given a data set like this; +-----+---------------------+--------+ | id | date | result | +-----+---------------------+--------+ | 121 | 2009-07-11 13:23:24 | -1 | | 122 | 2009-07-11 13:23:24 | -1 | | 123 | 2009-07-11 13:23:24 | -1 | | 124 | 2009-07-11 13:23:24 | -1 | | 125 | 2009-07-11 13:23:24 | -1 | | 126 | 2009-07-11 13:23:24 | -1 | | 127 | 2009-07-11 13:23:24 | -1 | | 128 | 2009-07-11 13:23:24 | -1 | | 129 | 2009-07-11 13:23:24 | -1 | | 130 | 2009-07-11 13:23:24 | -1 | | 131 | 2009-07-11 13:23:24 | -1 | | 132 | 2009-07-11 13:23:24 | -1 | | 133 | 2009-07-11 13:23:24 | -1 | | 134 | 2009-07-11 13:23:24 | -1 | | 135 | 2009-07-11 13:23:24 | -1 | | 136 | 2009-07-11 13:23:24 | -1 | | 137 | 2009-07-11 13:23:24 | -1 | | 138 | 2009-07-11 13:23:24 | 1 | | 139 | 2009-07-11 13:23:24 | 0 | | 140 | 2009-07-11 13:23:24 | -1 | +-----+---------------------+--------+ How would I go about grouping the results by day 5 records at a time. The above results is part of the live data, there is over 100,000 results rows in the table and its growing. Basically I want to measure the change over time, so want to take a SUM of the result every X records. In the real data I'll be doing it ever 100 or 1000 but for the data above perhaps every 5. If i could sort it by date I would do something like this; SELECT DATE_FORMAT(date, '%h%i') ym, COUNT(result) 'Total Games', SUM(result) as 'Score' FROM nn_log GROUP BY ym; I can't figure out a way of doing something similar with numbers. The order is sorted by the date but I hope to split the data up every x results. It's safe to assume there are no blank rows. Doing it above with the data you could do multiple selects like; SELECT SUM(result) FROM table LIMIT 0,5; SELECT SUM(result) FROM table LIMIT 5,5; SELECT SUM(result) FROM table LIMIT 10,5; Thats obviously not a very good way to scale up to a bigger problem. I could just write a loop but I'd like to reduce the number of queries.

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  • MySQL Update query with left join and group by

    - by Rob
    I am trying to create an update query and making little progress in getting the right syntax. The following query is working: SELECT t.Index1, t.Index2, COUNT( m.EventType ) FROM Table t LEFT JOIN MEvents m ON (m.Index1 = t.Index1 AND m.Index2 = t.Index2 AND (m.EventType = 'A' OR m.EventType = 'B') ) WHERE (t.SpecialEventCount IS NULL) GROUP BY t.Index1, t.Index2 It creates a list of triplets Index1,Index2,EventCounts. It only does this for case where t.SpecialEventCount is NULL. The update query I am trying to write should set this SpecialEventCount to that count, i.e. COUNT(m.EventType) in the query above. This number could be 0 or any positive number (hence the left join). Index1 and Index2 together are unique in Table t and they are used to identify events in MEvent. How do I have to modify the select query to become an update query? I.e. something like UPDATE Table SET SpecialEventCount=COUNT(m.EventType)..... but I am confused what to put where and have failed with numerous different guesses.

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  • Ext3 fs: Block bitmap for group 1 not in group (block 0). is fs dead?

    - by ip
    My company has a server with one big partition with Mysql database and php files. Now this partition seems to be corrupted, as reported from kernel messages when I tried to mount it manually: [329862.817837] EXT3-fs error (device loop1): ext3_check_descriptors: Block bitmap for group 1 not in group (block 0)! [329862.817846] EXT3-fs: group descriptors corrupted! I've tried to recovery it running tools from a PLD livecd. These are the tools I have tested: - e2retrieve - testdisk - photorec - dd_rescue/dd_rhelp - ddrescue - fsck.ext2 - e2salvage without any success. dumpe2fs 1.41.3 (12-Oct-2008) Filesystem volume name: /dev/sda3 Last mounted on: <not available> Filesystem UUID: dd51610b-6de0-4392-a6f3-67160dbc0343 Filesystem magic number: 0xEF53 Filesystem revision #: 1 (dynamic) Filesystem features: has_journal filetype sparse_super Default mount options: (none) Filesystem state: not clean with errors Errors behavior: Continue Filesystem OS type: Linux Inode count: 9502720 Block count: 18987570 Reserved block count: 949378 Free blocks: 11555345 Free inodes: 11858398 First block: 0 Block size: 4096 Fragment size: 4096 Blocks per group: 32768 Fragments per group: 32768 Inodes per group: 16384 Inode blocks per group: 512 Last mount time: Wed Mar 24 09:31:03 2010 Last write time: Mon Apr 12 11:46:32 2010 Mount count: 10 Maximum mount count: 30 Last checked: Thu Jan 1 01:00:00 1970 Check interval: 0 (<none>) Reserved blocks uid: 0 (user root) Reserved blocks gid: 0 (group root) First inode: 11 Inode size: 128 Journal inode: 8 Journal backup: inode blocks dumpe2fs: A block group is missing an inode table while reading journal inode e2fsck 1.41.3 (12-Oct-2008) fsck.ext3: Group descriptors look bad... trying backup blocks... fsck.ext3: A block group is missing an inode table while checking ext3 journal for /dev/sda3 I tried also backup superblocks, same error result. There's any other tools I have to test before considering these disk definitely unrecoverable? Many thanks, ip

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  • Mapping printers using Group Policy Preferences; works on Windows XP, not on Windows 7 x64

    - by Graeme Donaldson
    I'm trying to use Group Policy Preferences to manage user connections to shared printers. The print server is Windows Server 2003 R2 Std edition. Several printers are installed, and I've added x64 editions of all the drivers to the print server as well. I've created a new GPO containing the printer preference settings. Printer mappings are targeted based on AD security group membership. I log on to a Windows XP PC with the Group Policy CSEs installed and the printer maps perfectly. I log on to a Windows 7 x64 PC and it doesn't map. If I manually connect to the shared printer, I get a prompt which asks me to confirm if I trust the server before installing the driver, and then it works perfectly. I have domain admin rights and my UAC settings have not been changed from the default, i.e. UAC is enabled and the default level is selected. Is the printer mapping failing because it's unable to prompt me to install the driver, or is there something else afoot?

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  • How do you apply proxy settings per computer instead of per user?

    - by Oliver Salzburg
    So far, I've used a user group policy object utilizing Internet Explorer maintenance to set a proxy for the user in IE. We have now deployed the Enterprise Client (EC) starter group policy to our domain and this policy affects this behavior. The EC group policy uses the policy Make proxy settings per-machine (rather than per-user). This policy describes itself as: This policy is intended to ensure that proxy settings apply uniformly to the same computer and do not vary from user to user. Great! This seems to be an improvement over my previous setup. If you enable this policy, users cannot set user-specific proxy settings. They must use the zones created for all users of the computer. What zones and where do I configure the proxy settings for them? I assumed the policy would simply take the user settings and apply them, but that's not what's happening. Now no proxy server is set at all. So my previous settings obviously no longer have any effect. So far, I've only come up with solutions that involved direct manipulation of the Windows registry. Which is fine, I guess, but the way the proxy is configured for users makes it appear as if there could be a higher level approach.

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  • How To - Securing a JAX-WS with OWSM Message Protection Policy in JDeveloper - 11g

    - by Prakash Yamuna
    As promised in this post, here is a How-To that describes how to secure a simple HelloWorld JAX-WS with OWSM message protection policy and test it with SOAP UI. The How-To reuses the picture I posted earlier about the relationship and interplay b/w Keystore, Credential store, jps-config.xml ,etc. One of the other more frequent requests I hear from folks within Oracle and customers is how to test OWSM with SOAP UI. SOAP UI in general works very well as testing tool for web services secure with wss10 policies.

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  • Microsoft Updates Service Pack Support Policy

    Microsoft announced a slight revision on Tuesday to its end-of-support policy for software service packs....Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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  • XenApp 6.5 – How to create and set a Policy using PowerShell

    - by Waclaw Chrabaszcz
    Originally posted on: http://geekswithblogs.net/Wchrabaszcz/archive/2013/06/20/xenapp-6.5--how-to-create-and-set-a-policy.aspxHere is my homework Add-PSSnapin -name Citrix.Common.* -ErrorAction SilentlyContinueNew-Item LocalFarmGpo:\User\MyPolicycd LocalFarmGpo:\User\MyPolicy\Settings\ICA\SecuritySet-ItemProperty .\MinimumEncryptionLevel State EnabledSet-ItemProperty .\MinimumEncryptionLevel Value Bits128cd LocalFarmGpo:\User\MyPolicy\Filters\WorkerGroupNew-Item -Name "All Servers" -Value "All Servers"Set-ItemProperty LocalFarmGpo:\User\MyPolicy -Name Priority -Value 2  So cute …

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