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  • Group Video Chat On iPad With Fring App

    - by Gopinath
    Apple’s Facetime is the simplest and most easy to use video chat application available for iOS devices and Apple Macs. Facetime lets you have a one-to-one video chat, but what about having a group chat on your iPad with a bunch of friends? Here comes Fring App for iPad that lets you group chat up to 4 members at a time. Unlike Facetime Fring does not impose any restriction on the network connectivity for video chatting. You can initiate a group video chatting on any network (3G, Wi-Fi, 4G, etc.) but Wi-Fi is the most preferred option for smooth video streaming. Also Fring is a cross platform application(runs on iOS, Android & Nokia), so your group video chat session can have a mix of devices – iPads, Android smartphones/tablets and Nokia mobiles. Anyone mobile device with a front facing  cam and Fring app is allowed to join the party. Here is the promotional ad of Fring’s group video chatting application By the way did I say that Fring is a free app? Group video on iPad at no cost!!! Download Fring from Apple’s AppStore This article titled,Group Video Chat On iPad With Fring App, was originally published at Tech Dreams. Grab our rss feed or fan us on Facebook to get updates from us.

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  • How do I use Group Policy on a domain to delete Temporary Internet Files?

    - by Muhammad Ali
    I have a domain controller running on Windows 2008 Server R2 and users login to application servers on which Windows 2003 Server SP2 is installed. I have applied a Group Policy to clean temporary internet files on exit i.e to delete all temporary internet files when users close the browser. But the group policy doesn't seem to work as user profile size keeps on increasing and the major space is occupied by temporary internet files therefore increasing the disk usage. How can i enforce automatic deletion of temporary internet files?

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  • MYSQL - Group by limit

    - by jono2010
    Hello Is there a simple way to LIMIT the GROUP BY results to the top 2. The following query returns all the results. Using 'LIMIT 2' reduces the overall list to the top 2 entries only. select distinct(rating_name), id_markets, sum(rating_good) 'good', sum(rating_neutral)'neutral', sum(rating_bad) 'bad' from ratings where rating_year=year(curdate()) and rating_week= week(curdate(),1) group by rating_name,id_markets order by rating_name, sum(rating_good) desc Results in the following :- poland 78 48 24 12 <- keep poland 1 15 5 0 <- keep poland 23 12 6 3 poland 2 5 0 0 poland 3 0 5 0 poland 4 0 0 5 ireland 1 9 3 0 <- keep ireland 2 3 0 0 <- keep ireland 3 0 3 0 ireland 4 0 0 3 france 12 24 12 6 <- keep france 1 3 1 0 <- keep france 231 1 0 0 france 2 1 0 0 france 4 0 0 1 france 3 0 1 0 Thanks Jon

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  • Reading Active Directory group users in SharePoint

    - by Faiz
    Hi, Say that i have an active directory group called "Group1". I add this Group1 to a SharePoint site ( People and Group New User). All the users that are part of Group1 can now access sharepoint site. Now,for a specific custom webpart, i need to target to only users who belong to Group1. But when a user who belongs to Group1 logs into the sharepoint site, i am not finding a way to determine from within SharePoint context if this user belongs to Group1. Any thoughts? Thanks, Faiz

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  • Two separate fields need to be grouped in one group

    - by Sigita
    I have two fields: Mother's employer and Father's employer, and I need to group on the employer. Could somebody help me combine the two above fields into one group? Both fields are in one table. FOr example a child named John Lewis is a record in a table and he has a father and a mother and Mother's employer is IBM and Father's employer is ISF. And so forth. I need to come up with a list By employer where it would show: Employer: IBM John Lewis Emplyer: ISF John Lewis Employer: .... Thank you, Sigita

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  • Odd GROUP BY output DB2 - Results not as expected

    - by CallCthulhu
    If I run the following query: select load_cyc_num , crnt_dnlq_age_cde , sum(cc_min_pymt_amt) as min_pymt , sum(ec_tot_bal) as budget , case when ec_tot_bal 0 then 'Y' else 'N' end as budget , case when ac_stat_cde in ('A0P','A1P','ARP','A3P') then 'Y' else 'N' end as arngmnt , sum(sn_close_bal) as st_bal from statements where (sn_close_bal 0 or ec_tot_bal 0) and load_cyc_num in (200911) group by load_cyc_num , crnt_dnlq_age_cde , case when ec_tot_bal 0 then 'Y' else 'N' end , case when ac_stat_cde in ('A0P','A1P','ARP','A3P') then 'Y' else 'N' end then I get the correct "BUDGET" grouping, but not the correct "ARRANGEMENT" grouping, only two rows have a "Y". If I change the order of the case statements in the GROUP BY, then I get the correct grouping (full Y-N breakdown for both columns). Am I missing something obvious?

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  • Enterprise level control of ClickOnce product on corporate network with group policy?

    - by MrEdmundo
    Hi there I'm a developer looking at introducing ClickOnce deployment for an internal .NET Winforms application that will be distributed via the corporate network. Currently the product roll out and updates are handled by Group Policy however I would like to control the updates via ClickOnce deployment now. What I would like to know is, how should I initially roll out the package to make sure that all users have got it. Can I use a combination of Group Policy (the roll out) and then rely on the ClickOnce deployment model for any further updates?

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  • Mysql query different group by

    - by solomongaby
    Hello i have a products table that contains normal products and configurable product It has a basic stucture of: id name price configurable ('yes', 'no') id_configuration Normal products have configurable no and 0 as id configuration, and configurable products have it set to yes and have the same id_configuration value. The current query is: SELECT `products`.* FROM `products`, `categories`, `product_categories` WHERE `categories`.`id` = 23 AND `products`.`id` = `product_categories`.`id_product` AND `categories`.`id` = `product_categories`.`id_category` AND `products`.`active` = 'yes' AND ORDER BY `pos_new` ASC, `created` DESC LIMIT 0,20 I was wondering if there is a way to group by id_configuration, but only for the configurable products. The reason is that i want only one of the configuration products to show in search. I was thinking i could do a join, but was wondering if there is a way to do some kind of special group by. For example for configurable yes the field should be id_configuration otherwise it should be the id field Thanks a lot for any sugestions

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  • Ubuntu One Preferences does not show usage, name, e-mail, current plan

    - by Jim
    Ubuntuone is correctly synchronizing selected files between two computers running Ubuntu 10.10. When I open Ubuntuone Preferences, Account tab, on one computer it does not display the usage, name e-mail or current plan. On the other computer all information is shown correctly. On the Devices tab the 2 computers are not shown. They do show correctly on the other computer. Any ideas on how to fix this problem. I have reinstalled Ubuntuone per this link.

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  • SQL: GROUP BY after JOIN without overriding rows?

    - by krismeld
    I have a table of basketball leagues, a table af teams and a table of players like this: LEAGUES ID | NAME | ------------------ 1 | NBA | 2 | ABA | TEAMS: ID | NAME | LEAGUE_ID ------------------------------ 20 | BULLS | 1 21 | KNICKS | 2 PLAYERS: ID | TEAM_ID | FIRST_NAME | LAST_NAME | --------------------------------------------- 1 | 21 | John | Starks | 2 | 21 | Patrick | Ewing | Given a League ID, I would like to retrieve all the players' names and their team ID from all the teams in that league, so I do this: SELECT t.id AS team_id, p.id AS player_id, p.first_name, p.last_name FROM teams AS t JOIN players AS p ON p.team_id = t.id WHERE t.league_id = 1 which returns: [0] => stdClass Object ( [team_id] => 21 [player_id] => 1 [first_name] => John [last_name] => Starks ) [1] => stdClass Object ( [team_id] => 21 [player_id] => 2 [first_name] => Patrick [last_name] => Ewing ) + around 500 more objects... Since I will use this result to populate a dropdown menu for each team containing each team's list of players, I would like to group my result by team ID, so the loop to create these dropdowns will only have to cycle through each team ID instead of all 500+ players each time. But when I use the GROUP BY like this: SELECT t.id AS team_id, p.id AS player_id, p.first_name, p.last_name FROM teams AS t JOIN players AS p ON p.team_id = t.id WHERE t.league_id = 1 GROUP BY t.id it only returns one player from each team like this, overriding all the other players on the same team because of the use of the same column names. [0] => stdClass Object ( [team_id] => 21 [player_id] => 2 [first_name] => Patrick [last_name] => Ewing ) [1] => stdClass Object ( [team_id] => 22 [player_id] => 31 [first_name] => Shawn [last_name] => Kemp ) etc... I would like to return something like this: [0] => stdClass Object ( [team_id] => 2 [player_id1] => 1 [first_name1] => John [last_name1] => Starks [player_id2] => 2 [first_name2] => Patrick [last_name2] => Ewing +10 more players from this team... ) +25 more teams... Is it possible somehow?

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  • SQL GROUP BY with "default values"

    - by Christoph Schiessl
    I'm trying to create SELECT statement with a GROUP BY clause, which should return "default values". Imagine the following simple MySQL table: CREATE TABLE `tracker` ( `id` INTEGER PRIMARY KEY auto_increment, `date` DATETIME NOT NULL, `customer_id` INTEGER NOT NULL ); The table contains only one record: INSERT INTO `tracker` (`date`, `customer_id`) VALUES('2010-05-03', 1); After wards I'm executing the following SQL query: SELECT DATE(`date`), COUNT(customer_id) FROM tracker WHERE DATE(`date`) >= '2010-05-01' AND DATE(`date`) <= '2010-05-05' GROUP BY DATE(`date`) ORDER BY DATE(`date`); And get the expected result set: +----+---------------------+-------------+ | id | date | customer_id | +----+---------------------+-------------+ | 1 | 2010-05-10 00:00:00 | 1 | +----+---------------------+-------------+ However, I would like the result set to look like this: +--------------+--------------------+ | DATE(`date`) | COUNT(customer_id) | +--------------+--------------------+ | 2010-05-01 | 0 | | 2010-05-02 | 0 | | 2010-05-03 | 1 | | 2010-05-04 | 0 | | 2010-05-05 | 0 | +--------------+--------------------+ Is it possible to achieve this behavior?

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  • Ubuntuone Preferences does not show usage, name, e-mail, current plan

    - by Jim
    Ubuntuone is correctly synchronizing selected files between two computers running Ubuntu 10.10. When I open Ubuntuone Preferences, Account tab, on one computer it does not display the usage, name e-mail or current plan. On the other computer all information is shown correctly. On the Devices tab the 2 computers are not shown. They do show correctly on the other computer. Any ideas on how to fix this problem. I have reinstalled Ubuntuone per this link: https://wiki.ubuntu.com/UbuntuOne/FAQ/HowDoICompletelyRemoveAndReinstallUbuntuOne

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  • Determining Cross Domain Active Directory Group Membership

    - by thecaptain0220
    I am currently working on a project where I need to query Active Directory to determine group membership of a user. I initially was locating the user and retrieving the memberOf attribute. The problem with this is that there is a domain and a child domain. The groups are universal groups so they can be used in both domains and they don't show up in the memberOf attribute. Unfortunately there doesn't seem to be much info around for Active Directory access with C++. Is there anyway to determine group membership in this case in C++?

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  • Wallpaper in Windows 7 locked down by domain group policy?

    - by Robert Dailey
    So I am in a situation where my wallpaper is locked to a specific image on my work computer via group policy. I can't change it via the Personalization settings since it is grayed out and says it has been set by the system administrator. Anyone know some local GPO and/or registry hackery I can do to override the domain's policy? I could probably get away with logging in under a local account for this, but I want that to be a last resort. Thanks in advance.

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  • Nhibernate linq group by duplicate fields

    - by jaspion
    Hello, I have a simple query like: from e in endContratoRepository.GetAll() where e.Contrato.idContrato == contrato.idContrato && e.Volume.idVolume == 1 && group e by new { e.dpto.idDepartamento, e.centroCusto.idCentroCusto } into grp select new Entidade { Contagem = grp.Count(), centroCusto = grp.Key.idCentroCusto, dpto = grp.Key.idDepartamento } and the problem: The fields that are in the group by, are duplicated in the generated query. The fields centroCusto and dpto appears twice, so when I try to get the field centroCusto, I get dpto. Anyone know how to solve this? thanks a lot!

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  • MySQL GROUP BY with three tables

    - by Psaniko
    I have the following tables: posts (post_id, content, etc) comments (comment_id, post_id, content, etc) posts_categories (post_category_id, post_id, category_id) and this query: SELECT `p`.*, COUNT(comments.comment_id) AS cmts, posts_categories.*,comments.* FROM `posts` AS `p` LEFT JOIN `posts_categories` ON `p`.post_id = `posts_categories`.post_id LEFT JOIN `comments` ON `p`.post_id = `comments`.post_id GROUP BY `p`.`post_id` There are three comments on post_id=1 and four in total. In posts_categories there are two rows, both assigned to post_id=1. I have four rows in posts. But if I query the statement above I get a result of 6 for COUNT(comments.comment_id) at post_id=1. How is this possible? I guess the mistake is somewhere in the GROUP BY clause but I can't figure out where. Any suggestions?

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  • SELECT * , COUNT( * ) FROM GROUP BY ORDER BY DESC

    - by quanganh_developer
    I have a table like: gold gold_city | gold_type | gold_selltime ------------------------------------- city1 | type 1 | 2012-01-01 city1 | type 1 | 2012-02-02 city1 | type 1 | 2012-03-03 city2 | type 2 | 2012-01-01 city2 | type 2 | 2012-02-02 city2 | type 2 | 2012-03-03 city3 | type 3 | 2012-01-01 city3 | type 3 | 2012-02-02 city3 | type 3 | 2012-03-03 How can I get 1 last result order by gold_selltime desc each group by gold_city and gold_type I used this: SELECT * , COUNT( * ) FROM gold_2012 GROUP BY gold_type , gold_city ORDER BY gold_selltime DESC but it did work. I only have result like: gold_city | gold_type | gold_selltime ------------------------------------- city1 | type 1 | 2012-01-01 city2 | type 2 | 2012-01-01 city3 | type 3 | 2012-01-01 but I need it like: gold_city | gold_type | gold_selltime ------------------------------------- city1 | type 1 | 2012-03-03 city2 | type 2 | 2012-03-03 city3 | type 3 | 2012-03-03

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  • Concatenate and group multiple rows in Oracle

    - by user1693347
    Suppose I have a table like this: NAME GROUP name1 groupA name2 groupB name5 groupC name4 groupA name3 groupC I'd like to have a result like this: GROUP NAMES groupA name1,name4 groupB name2 groupC name3,name5 If there were only one column in the table, I could concatenate the records by doing the following, but with grouping in the context, I really don't have much idea. Any suggestion is welcome, thanks in advance! Concatatenating one column table: SELECT names FROM (SELECT SYS_CONNECT_BY_PATH(names,' ') names, level FROM name_table START WITH names = (SELECT names FROM name_table WHERE rownum = 1) CONNECT BY PRIOR names < names ORDER BY level DESC) WHERE rownum = 1

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  • WatchGuard 'Internal Policy' intermittently blocking outbound web traffic

    - by vfilby
    I have a lot of legitimate outbound traffic intermittently being denied by WatchGuard's "Internal Policy." Today I tried to go to Splunk's homepage and my traffic was denied by my watchguard XTM 22 with Pro upgrade. What is the "Internal Policy" and what can I do to control it? Example of Traffic being blocked Type Date Action Source IP Port Interface Destination IP Port Policy Traffic 2011-09-21T18:24:43 Deny 10.0.0.90 49627 3-Primary LAN 64.127.105.40 80 Firebox Internal Policy http/tcp Top three firewall policies:

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  • how to get more vacation time than "policy" allows

    - by SpashHit
    At my company, the maximum vacation is 3 weeks for everyone but executives. Therefore I cannot even start negotiating for an increase to 4 weeks.. it's a non-starter because it's "against policy"... even though I think my experience and value to the company warrant it, and I've gotten 4 weeks at previous jobs. (I know I could have made a "hard stand" before taking this job, but that's water under the bridge) Any advice? I was kind of thinking of taking the "you want to be competitive" tack to get them to change their policy but I don't know where to find the kind of data I would need to support that.

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  • Grouping by property value and writing group members

    - by Will S
    I need to group the following list by the department value but am having trouble with the LINQ syntax. Here's my list of objects: var people = new List<Person> { new Person { name = "John", department = new List<fields> {new fields { name = "department", value = "IT"}}}, new Person { name = "Sally", department = new List<fields> {new fields { name = "department", value = "IT"}}}, new Person { name = "Bob", department = new List<fields> {new fields { name = "department", value = "Finance"}}}, new Person { name = "Wanda", department = new List<fields> {new fields { name = "department", value = "Finance"}}}, }; I've toyed around with grouping. This is as far as I've got: var query = from p in people from field in p.department where field.name == "department" group p by field.value into departments select new { Department = departments.Key, Name = departments }; So can iterate over the groups, but not sure how to list the Person names - foreach (var department in query) { Console.WriteLine("Department: {0}", department.Department); foreach (var foo in department.Department) { // ?? } } Any ideas on what to do better or how to list the names of the relevant departments?

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  • Mapping printers using Group Policy Preferences; works on Windows XP, not on Windows 7 x64

    - by Graeme Donaldson
    I'm trying to use Group Policy Preferences to manage user connections to shared printers. The print server is Windows Server 2003 R2 Std edition. Several printers are installed, and I've added x64 editions of all the drivers to the print server as well. I've created a new GPO containing the printer preference settings. Printer mappings are targeted based on AD security group membership. I log on to a Windows XP PC with the Group Policy CSEs installed and the printer maps perfectly. I log on to a Windows 7 x64 PC and it doesn't map. If I manually connect to the shared printer, I get a prompt which asks me to confirm if I trust the server before installing the driver, and then it works perfectly. I have domain admin rights and my UAC settings have not been changed from the default, i.e. UAC is enabled and the default level is selected. Is the printer mapping failing because it's unable to prompt me to install the driver, or is there something else afoot?

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