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  • unordered lists as columns

    - by Ben
    I am trying to use unordered lists as columns something setup like the following: <ul> <li>word 1</li> <li>word 1</li> <li>word 1</li> <li>word 1</li> <li>word 1</li> </ul> <ul> <li>word 2</li> <li>word 2</li> <li>word 2</li> <li>word 2</li> <li>word 2</li> </ul> What would I need to do as far as css these to lineup side by side as vertical lists with no bullets. I'm sure I'm missing something simple but I can't seem to figure it out. I specifically need this to work in IE7. Thanks in advance, Ben

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  • Database design grouping contacts by lists and companies

    - by Serge
    Hi, I'm wondering what would be the best way to group contacts by their company. Right now a user can group their contacts by custom created lists but I'd like to be able to group contacts by their company as well as store the contact's position (i.e. Project Manager of XYZ company). Database wise this is what I have for grouping contacts into lists contact [id_contact] [int] PK NOT NULL, [lastName] [varchar] (128) NULL, [firstName] [varchar] (128) NULL, ...... contact_list [id_contact] [int] FK, [id_list] [int] FK, list [id_list] [int] PK [id_user] [int] FK [list_name] [varchar] (128) NOT NULL, [description] [TEXT] NULL Should I implement something similar for grouping contacts by company? If so how would I store the contact's position in that company and how can I prevent data corruption if a user modifies a contact's company name. For instance John Doe changed companies but the other co-workers are still in the old company. I doubt that will happen often (might not even happen at all) but better be safe than sorry. I'm also keeping an audit trail so in a way the contact would still need to be linked to the old company as well as the new one but without confusing what company he's actually working at the moment. I hope that made sense... Has anyone encountered such a problem? UPDATE Would something like this make sense contact_company [id_contact_company] [int] PK [id_contact] [int] FK [id_company] [int] FK [contact_title] [varchar] (128) company [id_company] [int] PK NOT NULL, [company_name] [varchar] (128) NULL, [company_description] [varchar] (300) NULL, [created_date] [datetime] NOT NULL This way a contact can work for more than one company and contacts can be grouped by companies

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  • 2 Mutually exclusive RadioButton "Lists"

    - by user72603
    I think this has to be THE most frustrating thing I've ever done in web forms. Yet one would think it would be the easiest of all things in the world to do. That is this: I need 2 separate lists of radiobuttons on my .aspx page. One set allows a customer to select an option. The other set does also but for a different purpose. But only one set can have a selected radiobutton. Ok I've tried this using 2 asp.net Radiobuttonlists controls on the same page. Got around the nasty bug with GroupName (asp.net assigns the control's uniqueID which prevents the groupname from ever working because now, 2 radiobuttonlists can't have the same groupname for all their radiobuttons because each radiobuttonlist has a different uniqueID thus the bug assigns the unique ID as the name attribute when the buttons are rendered. since the name sets are different, they are not mutually exclusive). Anyway, so I created that custom RadioButtonListcontrol and fixed that groupname problem. But when ended up happening is when I went to put 2 instances of my new custom radiobuttonlist control on my .aspx page, all was swell until I noticed that every time I checked for radiobuttonlist1.SelectedValue or radiobuttonlist2.SelectedValue (did not matter which I was checking) the value always spit back string.empty and i was not able to figure out why (see http://forums.asp.net/t/1401117.aspx). Ok onto the third try tonight and into the break of dawn (no sleep). I tried to instead just scrap trying to use 2 custom radiobuttonlists altogether because of that string.empty issue and try to spit out 2 sets of radiobuttonlists via using 2 asp.net repeaters and a standard input HTML tag inside. Got that working. Ok but the 2 lists still are not mutually exclusive. I can select a value in the first set of radiobuttons from repeater1 and same goes for repeater2. I cannot for the life of me get the "sets" to be mutually exclusive sets of radiobuttons.

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  • Permuting a binary tree without the use of lists

    - by Banang
    I need to find an algorithm for generating every possible permutation of a binary tree, and need to do so without using lists (this is because the tree itself carries semantics and restraints that cannot be translated into lists). I've found an algorithm that works for trees with the height of three or less, but whenever I get to greater hights, I loose one set of possible permutations per height added. Each node carries information about its original state, so that one node can determine if all possible permutations have been tried for that node. Also, the node carries information on weather or not it's been 'swapped', i.e. if it has seen all possible permutations of it's subtree. The tree is left-centered, meaning that the right node should always (except in some cases that I don't need to cover for this algorithm) be a leaf node, while the left node is always either a leaf or a branch. The algorithm I'm using at the moment can be described sort of like this: if the left child node has been swapped swap my right node with the left child nodes right node set the left child node as 'unswapped' if the current node is back to its original state swap my right node with the lowest left nodes' right node swap the lowest left nodes two childnodes set my left node as 'unswapped' set my left chilnode to use this as it's original state set this node as swapped return null return this; else if the left child has not been swapped if the result of trying to permute left child is null return the permutation of this node else return the permutation of the left child node if this node has a left node and a right node that are both leaves swap them set this node to be 'swapped' The desired behaviour of the algoritm would be something like this: branch / | branch 3 / | branch 2 / | 0 1 branch / | branch 3 / | branch 2 / | 1 0 <-- first swap branch / | branch 3 / | branch 1 <-- second swap / | 2 0 branch / | branch 3 / | branch 1 / | 0 2 <-- third swap branch / | branch 3 / | branch 0 <-- fourth swap / | 1 2 and so on... Sorry for the ridiculisly long and waddly explanation, would really, really apreciate any sort of help you guys could offer me. Thanks a bunch!

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  • Comparing lists in Standard ML

    - by user1050640
    I am extremely new to SML and we just got out first programming assignment for class and I need a little insight. The question is: write an ML function, called minus: int list * int list -> int list, that takes two non-decreasing integer lists and produces a non-decreasing integer list obtained by removing the elements from the first input list which are also found in the second input list. For example, minus( [1,1,1,2,2], [1,1,2,3] ) = [1,2] minus( [1,1,2,3],[1,1,1,2,2] ) = [3] Here is my attempt at answering the question. Can anyone tell me what I am doing incorrectly? I don't quite understand parsing lists. fun minus(xs,nil) = [] | minus(nil,ys) = [] | minus(x::xs,y::ys) = if x=y then minus(xs,ys) else x :: minus(x,ys); Here is a fix I just did, I think this is right now? fun minus(L1,nil) = L1 | minus(nil,L2) = [] | minus(L1,L2) = if hd(L1) > hd(L2) then minus(L1,tl(L2)) else if hd(L1) = hd(L2) then minus(tl(L1),tl(L2)) else hd(L1) :: minus(tl(L1), L2);

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  • Combine Lists with Same Heads in a 2D List (OCaml)

    - by Atticus
    Hi guys, I'm working with a list of lists in OCaml, and I'm trying to write a function that combines all of the lists that share the same head. This is what I have so far, and I make use of the List.hd built-in function, but not surprisingly, I'm getting the failure "hd" error: let rec combineSameHead list nlist = match list with | [] -> []@nlist | h::t -> if List.hd h = List.hd (List.hd t) then combineSameHead t nlist@uniq(h@(List.hd t)) else combineSameHead t nlist@h;; So for example, if I have this list: [[Sentence; Quiet]; [Sentence; Grunt]; [Sentence; Shout]] I want to combine it into: [[Sentence; Quiet; Grunt; Shout]] The function uniq I wrote just removes all duplicates within a list. Please let me know how I would go about completing this. Thanks in advance!

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  • Approach For Syncing One SharePoint List With One or More SharePoint Lists

    - by plattnum
    What would be the best approach or strategy for configuring, customizing or developing in SharePoint a solution that allows me to keep one or more SharePoint lists in sync with a SharePoint list I have designated as a master or parent list. I would like to be able to create a master/parent list of some information that can be extended or used by different parts of the organization without them being able to CRUD any items on the actual columns of the master list. (I have seen some commercial web parts that offer column security on SharePoint lists and although that’s one way of potentially meeting my needs I would like to explore other options.) Scenario: I have a list called FOO: FOO Title Description I would like to create a new list BAR based off of FOO (BAR is managed by sub-organization that doesn't have access to FOO List): BAR FOO.Title (Read-Only) FOO.Description (Read-Only) NewColumn1 NewColumn2 Actions: Create- If a new item is entered in FOO I would like the new item added to BAR. Read - N/A Update - If the title or description is changed in FOO I would like it changed in BAR. Delete- No Deletes in the scenario. (Deletes are handled by the business with status column.) Templates with content extraction offer me this but it’s a one time shot at list creation. Just not sure what the best approach or strategy would be for this in MOSS 2007. Thanks!

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  • new to lists on python

    - by user1762229
    This is my current code: while True: try: mylist = [0] * 7 for x in range(7): sales = float(input("Sales for day:")) mylist[x] = sales if sales < 0: print ("Sorry,invalid. Try again.") except: print ("Sorry, invalid. Try again.") else: break print (mylist) best = max(sales) worst = min(sales) print ("Your best day had", best, "in sales.") print ("Your worst day had", worst, "in sales.") When I run it I get this: Sales for day:-5 Sorry,invalid. Try again. Sales for day:-6 Sorry,invalid. Try again. Sales for day:-7 Sorry,invalid. Try again. Sales for day:-8 Sorry,invalid. Try again. Sales for day:-9 Sorry,invalid. Try again. Sales for day:-2 Sorry,invalid. Try again. Sales for day:-5 Sorry,invalid. Try again. [-5.0, -6.0, -7.0, -8.0, -9.0, -2.0, -5.0] Traceback (most recent call last): File "C:/Users/Si Hong/Desktop/HuangSiHong_assign9_part.py", line 45, in <module> best = max(sales) TypeError: 'float' object is not iterable I am not quite sure how to code it so that, the lists do NOT take in negative values, because I only want values 0 or greater. I am not sure how to solve the TypeError issue so that the min and max values will print as in my code My last issue is, if I want to find the average value of the seven inputs that an user puts in, how should I go about this in pulling the values out of the lists Thank you so much

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  • Using FindAll on a List<List<T>> type

    - by Ken Foster
    Assuming public class MyClass { public int ID {get; set; } public string Name {get; set; } } and List<MyClass> classList = //populate with MyClass instances of various IDs I can do List<MyClass> result = classList.FindAll(class => class.ID == 123); and that will give me a list of just classes with ID = 123. Works great, looks elegant. Now, if I had List<List<MyClass>> listOfClassLists = //populate with Lists of MyClass instances How do I get a filtered list where the lists themselves are filtered. I tried List<List<MyClass>> result = listOfClassLists.FindAll (list => list.FindAll(class => class.ID == 123).Count > 0); it looks elegant, but doesn't work. It only includes Lists of classes where at least one class has an ID of 123, but it includes ALL MyClass instances in that list, not just the ones that match. I ended up having to do List<List<MyClass>> result = Results(listOfClassLists, 123); private List<List<MyClass>> Results(List<List<MyClass>> myListOfLists, int id) { List<List<MyClass>> results = new List<List<MyClass>>(); foreach (List<MyClass> myClassList in myListOfLists) { List<MyClass> subList = myClassList.FindAll(myClass => myClass.ID == id); if (subList.Count > 0) results.Add(subList); } return results; } which gets the job done, but isn't that elegant. Just looking for better ways to do a FindAll on a List of Lists. Ken

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  • Look for match in a nested list in Python

    - by elfuego1
    Hello everybody, I have two nested lists of different sizes: A = [[1, 7, 3, 5], [5, 5, 14, 10]] B = [[1, 17, 3, 5], [1487, 34, 14, 74], [1487, 34, 3, 87], [141, 25, 14, 10]] I'd like to gather all nested lists from list B if A[2:4] == B[2:4] and put it into list L: L = [[1, 17, 3, 5], [141, 25, 14, 10]] Additionally if the match occurs then I want to change last element of sublist B into first element of sublist A so the final solution would look like this: L1 = [[1, 17, 3, 1], [141, 25, 14, 5]]

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  • PYTHON: Look for match in a nested list

    - by elfuego1
    Hello everybody, I have two nested lists of different sizes: A = [[1, 7, 3, 5], [5, 5, 14, 10]] B = [[1, 17, 3, 5], [1487, 34, 14, 74], [1487, 34, 3, 87], [141, 25, 14, 10]] I'd like to gather all nested lists from list B if A[2:4] == B[2:4] and put it into list L: L = [[1, 17, 3, 5], [141, 25, 14, 10]] Would you help me with this?

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  • Synaptic returns error

    - by donvoldy666
    I get the following error message when I run synaptic and I can't install any programs SystemError: W:Ignoring file 'getdeb.list.bck' in directory '/etc/apt/sources.list.d/' as it has an invalid filename extension, W:Duplicate sources.list entry 'http://extras.ubuntu.com/ubuntu/ precise/main i386 Packages (/var/lib/apt/lists/extras.ubuntu.com_ubuntu_dists_precise_main_binary-i386_Packages), W:Duplicate sources.list entry 'http://extras.ubuntu.com/ubuntu/ ' precise/main i386 Packages (/var/lib/apt/lists/extras.ubuntu.com_ubuntu_dists_precise_main_binary-i386_Packages), W:Duplicate sources.list entry 'http://extras.ubuntu.com/ubuntu/ precise/main i386 Packages (/var/lib/apt/lists/extras.ubuntu.com_ubuntu_dists_precise_main_binary-i386_Packages), W:Duplicate sources.list entry ' 'http://extras.ubuntu.com/ubuntu'/ precise/main i386 Packages (/var/lib/apt/lists/extras.ubuntu.com_ubuntu_dists_precise_main_binary-i386_Packages), W:Duplicate sources.list entry' 'http://extras.ubuntu.com/ubuntu/ precise/main i386 Packages (/var/lib/apt/lists/extras.ubuntu.com_ubuntu_dists_precise_main_binary-i386_Packages), W:Duplicate sources.list entry 'http://extras.ubuntu.com/ubuntu/ precise/main i386 Packages (/var/lib/apt/lists/extras.ubuntu.com_ubuntu_dists_precise_main_binary-i386_Packages), W:Duplicate sources.list entry 'http://ppa.launchpad.net/ubuntu-mozilla-security/ppa/ubuntu/ precise/main i386 Packages (/var/lib/apt/lists/ppa.launchpad.net_ubuntu-mozilla-security_ppa_ubuntu_dists_precise_main_binary-i386_Packages), E:Encountered a section with no Package: header, E:Problem with MergeList /var/lib/apt/lists/packages.rssowl.org_ubuntu_dists_precise_main_i18n_Translation-en, E:The package lists or status file could not be parsed or opened. I'm new to Linux so please help me out .

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  • MVVM pattern and nested view models - communication and lookup lists

    - by LostInWPF
    I am using Prism for a new application that I am creating. There are several lookup lists that will be used in several places in the application. Therefore it makes sense to define it once and use that everywhere I need that functionality. My current solution is to use typed data templates to render the controls inside a content control. <DataTemplate DataType={x:Type ListOfCountriesViewModel}> <ComboBox ItemsSource={Binding Countries} SelectedItem="{Binding SelectedCountry"/> </DataTemplate> <DataTemplate DataType={x:Type ListOfRegionsViewModel}> <ComboBox ItemsSource={Binding Countries} SelectedItem={Binding SelectedRegion} /> </DataTemplate> public class ParentViewModel { SelectedCountry get; set; SelectedRegion get; set; ListOfCountriesViewModel CountriesVM; ListOfRegionsViewModel RgnsVM; } Then in my window I have 2 content controls and the rest of the controls <ContentControl Content="{Binding CountriesVM}"></ContentControl> <ContentControl Content="{Binding RgnsVM}"></ContentControl> <Rest of controls on view> At the moment I have this working and the SelectedItems for the combo boxes are publising events via EventAggregator from the child view models which are then subscribed to in the parent view model. I am not sure that this is the best way to go as I can imagine I would end up with a lot of events very quickly and it will become unwieldy. Also if I was to use the same view model on another window it will publish the event and this parent viewmodel is subscribed to it which could have unintended consequences. My questions are :- Is this the best way to put lookup lists in a view which can be re-used across screens? How do I make it so that the combobox which is bound to the child viewmodel sets the relevant property on the parent viewmodel without using events / mediator. e.g in this case SelectedCountry for example? Any alternative implementation proposals for what I am trying to do? I have a feeling I am missing something obvious and there is so much info it is hard to know what is right so any help would be most gratefully received.

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  • Linq find differences in two lists

    - by Salo
    I have two list of members like this: Before: Peter, Ken, Julia, Tom After: Peter, Robert, Julia, Tom As you can see, Ken is is out and Robert is in. What I want is to detect the changes. I want a list of what has changed in both lists. How can linq help me?

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  • Sharepoint webpart combobox of lists

    - by ifunky
    Hi, I have a webpart that works off of a list but what I'm trying to do create a dropdown that contains a list of sharepoint lists so that when the user edits the page and selects 'modify shared webpart' they are able to choose a list item and that gets parsed back to the webpart. Any examples or links to examples appreciated! Thanks Dan

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  • jqueryui autocomplete: lists entries with search terms in middle

    - by Akshey
    Hi, I am using jqueryui autocomplete widget for autocompleting a 'country' field but I am facing an issue. Suppose the user enters "in", I want the jqueryui to list countries like 'india', 'indonesia' which start with 'in', but it also lists the countries which have 'in' somewhere in the name (like: argentina). How can I solve this issue? jQuery(".autocomplete").autocomplete({ source: CountrySuggestions, //CountrySuggestions is an array in javascript containing the list of countries minLength: 2 }); Akshey

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  • Exclude one or more elements from being connected (using connectWith) in jQuery's sortable lists

    - by Lev
    I have two lists, one with an ID of "vlist" and one with an ID of "hlist". The "vlist" holds elements which should be visible, while the "hlist" holds items that should remain hidden. The idea here is to allow the administrator of the system to specify which elements/fields should be shown on a sign-up page, and which shouldn't. The two lists are connected using "connectWith", so the administrator can drag items from the visible list to the hidden list (or vice versa). My dilemma is that there are a few fields I want locked into the visible list, but still sortable within that one list. For example, the "username", "email" and "password" fields should be locked within the visible list (as they always need to be used for registration). Is this even possible? Perhaps it is a no-brainer that I simply haven't discovered yet. I've looked around through jQuery's documentation for a while and can't seem to find anything related to this scenario. I have found how you can "cancel" specific elements in the list from being sortable altogether or even disabled from being a dropable target, but this doesn't do it. The user should still have the ability to drag these items within the "visible" list, in case they want to adjust the ordering of the locked fields. I'm also aware that you can contain sortable elements within a specific element or DOM object, but this also can't be used as this only seems to apply to the whole sortable list, and not specific elements of that list. I've even tried to see if something like this would work after I built the sortable listing(s): $('#vlist > #slist-li-username').sortable('option', 'containment', '#vlist'); Obviously, that didn't work either or I wouldn't be posting this. In case it might help, I thought I'd throw in the code I'm using now; here is the jQuery code: $(function() { $('#vlist, #hlist').sortable ({ connectWith: '.signup-set_flist', forcePlaceholderSize: true, receive: function (event, ui) { var itemID = ui.item.attr('id'); var fID = itemID.replace(/slist-li-/g, ''); var hID = 'slist-' + fID; if (ui.sender.attr('id') == 'vlist') { $('#'+hID).val(''); } else { $('#'+hID).val(fID); } } }).disableSelection(); $('#vlist > #slist-li-username').sortable('option', 'containment', '#vlist'); }); And as for the HTML, I'll upload it to here (since StackOverflow seems to break when I paste it in here - even in code mode): http://sikosoft.net/jquery-sort-connect.html Any help would greatly be appreciated! :) Oh, and be gentle as this is my first question here. ;)

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  • scala currying by nested functions or by multiple parameter lists

    - by Morgan Creighton
    In Scala, I can define a function with two parameter lists. def myAdd(x :Int)(y :Int) = x + y This makes it easy to define a partially applied function. val plusFive = myAdd(5) _ But, I can accomplish something similar by defining and returning a nested function. def myOtherAdd(x :Int) = { def f(y :Int) = x + y f _ } Cosmetically, I've moved the underscore, but this still feels like currying. val otherPlusFive = myOtherAdd(5) What criteria should I use to prefer one approach over the other?

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  • Algorithm to retrieve every possible combination of sublists of a two lists

    - by sgmoore
    Suppose I have two lists, how do I iterate through every possible combination of every sublist, such that each item appears once and only once. I guess an example could be if you have employees and jobs and you want split them into teams, where each employee can only be in one team and each job can only be in one team. Eg List<string> employees = new List<string>() { "Adam", "Bob"} ; List<string> jobs = new List<string>() { "1", "2", "3"}; I want Adam : 1 Bob : 2 , 3 Adam : 1 , 2 Bob : 3 Adam : 1 , 3 Bob : 2 Adam : 2 Bob : 1 , 3 Adam : 2 , 3 Bob : 1 Adam : 3 Bob : 1 , 2 Adam, Bob : 1, 2, 3 I tried using the answer to this stackoverflow question to generate a list of every possible combination of employees and every possible combination of jobs and then select one item from each from each list, but that's about as far as I got. I don't know the maximum size of the lists, but it would be certainly be less than 100 and there may be other limiting factors (such as each team can have no more than 5 employees) Update Not sure whether this can be tidied up more and/or simplified, but this is what I have ended up with so far. It uses the Group algorithm supplied by Yorye (see his answer below), but I removed the orderby which I don't need and caused problems if the keys are not comparable. var employees = new List<string>() { "Adam", "Bob" } ; var jobs = new List<string>() { "1", "2", "3" }; int c= 0; foreach (int noOfTeams in Enumerable.Range(1, employees.Count)) { var hs = new HashSet<string>(); foreach( var grouping in Group(Enumerable.Range(1, noOfTeams).ToList(), employees)) { // Generate a unique key for each group to detect duplicates. var key = string.Join(":" , grouping.Select(sub => string.Join(",", sub))); if (!hs.Add(key)) continue; List<List<string>> teams = (from r in grouping select r.ToList()).ToList(); foreach (var group in Group(teams, jobs)) { foreach (var sub in group) { Console.WriteLine(String.Join(", " , sub.Key ) + " : " + string.Join(", ", sub)); } Console.WriteLine(); c++; } } } Console.WriteLine(String.Format("{0:n0} combinations for {1} employees and {2} jobs" , c , employees.Count, jobs.Count)); Since I'm not worried about the order of the results, this seems to give me what I need.

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  • Using PyLab to create a 2D graph from two separate lists

    - by user324333
    Hey Guys, This seems like a basic problem with an easy answer but I simply cannot figure it out no matter how much I try. I am trying to create a line graph based on two lists. For my x-axis, I want my list to be a set of strings. x_axis_list = ["Jan-06","Jul-06","Jan-07","Jul-07","Jan-08"] y_axis_list = [5,7,6,8,9] Any suggestions on how to best graph these items?

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  • Under what circumstances are linked lists useful?

    - by Jerry Coffin
    Most times I see people try to use linked lists, it seems to me like a poor (or very poor) choice. Perhaps it would be useful to explore the circumstances under which a linked list is or is not a good choice of data structure. Ideally, answers would expound on the criteria to use in selecting a data structure, and which data structures are likely to work best under specified circumstances.

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  • Reading lists from a file in Ruby

    - by Gjorgji
    Hi, I have a txt file which contains data in the following format: X1 Y1 X2 Y2 etc.. I want to read the data from this file and create two lists in ruby (X containing X1, X2 and Y containing Y1, Y2). How can I do this in Ruby? Thanks.

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