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  • Spring's JdbcDaoSupport (using MySQL Connector/J) fails after executing sql that adds FK

    - by John
    I am using Spring's JdbcDaoSupport class with a DriverManagerDataSource using the MySQL Connector/J 5.0 driver (driverClassName=com.mysql.jdbc.driver). allowMultiQueries is set to true in the url. My application is an in-house tool we recently developed that executes sql scripts in a directory one-by-one (allows us to re-create our schema and reference table data for a given date, etc, but I digress). The sql scripts sometime contain multiple statements (hence allowMultiQueries), so one script can create a table, add indexes for that table, etc. The problem happens when including a statement to add a foreign key constraint in one of these files. If I have a file that looks like... --(column/constraint names are examples) CREATE TABLE myTable ( fk1 BIGINT(19) NOT NULL, fk2 BIGINT(19) NOT NULL, PRIMARY KEY (fk1, fk2) ); ALTER TABLE myTable ADD CONSTRAINT myTable_fk1 FOREIGN KEY (fk1) REFERENCES myOtherTable (id) ; ALTER TABLE myTable ADD CONSTRAINT myTable_fk2 FOREIGN KEY (fk2) REFERENCES myOtherOtherTable (id) ; then JdbcTemplate.execute throws an UncategorizedSqlException with the following error message and stack trace: Exception in thread "main" org.springframework.jdbc.UncategorizedSQLException: StatementCallback; uncategorized SQLException for SQL [ THE SQL YOU SEE ABOVE LISTED HERE ]; SQL state [HY000]; error code [1005]; Can't create table 'myDatabase.myTable' (errno: 150); nested exception is java.sql.SQLException: Can't create table 'myDatabase.myTable' (errno: 150) at org.springframework.jdbc.support.AbstractFallbackSQLExceptionTranslator.translate(AbstractFallbackSQLExceptionTranslator.java:83) at org.springframework.jdbc.support.AbstractFallbackSQLExceptionTranslator.translate(AbstractFallbackSQLExceptionTranslator.java:80) at org.springframework.jdbc.support.AbstractFallbackSQLExceptionTranslator.translate(AbstractFallbackSQLExceptionTranslator.java:80) and the table and foreign keys are not inserted. Also, especially weird: if I take the foreign key statements out of the script I showed above and then place them in their own script that executes after (so I now have 1 script with just the create table statement, and 1 script with the add foreign key statements that executes after that) then what happens is: tool executes create table script, works fine, table is created tool executes add fk script, throws the same exception as seen above (except errno=121 this time), but the FKs actually get added (!!!) In other words, when the create table/FK statements are in the same script then the exception is thrown and nothing is created, but when they are different scripts a nearly identical exception is thrown but both things get created. Any help on this would be greatly appreciated. Please let me know if you'd like me to clarify anything more.

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  • mysql procedure to update numeric reference in previous rows when one is updated

    - by markcial
    There's a table like this one ______________________ | id | title | order | |----------------------| | 1 | test1 | 1 | |-----|--------|-------| | 2 | test2 | 2 | |-----|--------|-------| | 3 | test3 | 3 | |-----|--------|-------| | 4 | test4 | 4 | '----------------------' when i introduce in my mysql shell a single update to a row $sql UPDATE `table` SET order=1 WHERE id=3; And then procedure or method resamples order column in the before update lower values to get its order renewed like this ______________________ | id | title | order | |----------------------| | 1 | test1 | 2 | |-----|--------|-------| | 2 | test2 | 3 | |-----|--------|-------| | 3 | test3 | 1 | |-----|--------|-------| | 4 | test4 | 4 | '----------------------' Any help would be appreciated, thanks!

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  • connecting to phpMyAdmin database with PHP/MySQL

    - by user303955
    I've made a database using phpMyAdmin , now I want to make a register form for my site where peaple can register .I know how to work with input tags in HTML and I know how to insert data into a database but my problem is that I don't know how I can connect to the database that is already made in phpMyAdmin.

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  • (mySQL) Unable to query 2 tables properly for data

    - by Devner
    I have 2 tables. One is 'page_links' and the other is 'rpp'. Table page_links is the superset of table rpp. The following is the schema of my tables: -- Table structure for table `page_links` -- CREATE TABLE IF NOT EXISTS `page_links` ( `page` varchar(255) NOT NULL, `page_link` varchar(100) NOT NULL, `heading_id` tinyint(3) unsigned NOT NULL, PRIMARY KEY (`page`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; -- -- Dumping data for table `page_links` -- INSERT INTO `page_links` (`page`, `page_link`, `heading_id`) VALUES ('a1.php', 'A1', 8), ('b1.php', 'B1', 8), ('c1.php', 'C1', 5), ('d1.php', 'D1', 5), ('e1.php', 'E1', 8), ('f1.php', 'F1', 8), ('g1.php', 'G1', 8), ('h1.php', 'H1', 1), ('i1.php', 'I1', 1), ('j1.php', 'J1', 8), ('k1.php', 'K1', 8), ('l1.php', 'L1', 8), ('m1.php', 'M1', 8), ('n1.php', 'N1', 8), ('o1.php', 'O1', 8), ('p1.php', 'P1', 4), ('q1.php', 'Q1', 5), ('r1.php', 'R1', 4); -- Table structure for table `rpp` -- CREATE TABLE IF NOT EXISTS `rpp` ( `role_id` tinyint(3) unsigned NOT NULL, `page` varchar(255) NOT NULL, `is_allowed` tinyint(1) NOT NULL, PRIMARY KEY (`role_id`,`page`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; -- -- Dumping data for table `rpp` -- INSERT INTO `rpp` (`role_id`, `page`, `is_allowed`) VALUES (3, 'a1.php', 1), (3, 'b1.php', 1), (3, 'c1.php', 1), (3, 'd1.php', 1), (3, 'e1.php', 1), (3, 'f1.php', 1), (3, 'h1.php', 1), (3, 'i1.php', 1), (3, 'l1.php', 1), (3, 'm1.php', 1), (3, 'n1.php', 1), (4, 'a1.php', 1), (4, 'b1.php', 1), (4, 'q1.php', 1), (5, 'r1.php', 1); WHAT I AM TRYING TO DO: I am trying to query both the above tables (in a single query) in such a way that all the pages from page_links are displayed along with the is_allowed value from rpp for a particular role. For example, I want to get the is_allowed value of all the pages from rpp for role_id = 3 and at the same time, list all the available pages from page_links. A clear example of my expected result would be: page is_allowed role_id ---------------------------------------- a1.php 1 3 b1.php 1 3 c1.php 1 3 d1.php 1 3 e1.php 1 3 f1.php 1 3 g1.php NULL NULL h1.php 1 3 i1.php 1 3 j1.php NULL NULL k1.php NULL NULL l1.php 1 3 m1.php 1 3 n1.php 1 3 o1.php NULL NULL p1.php NULL NULL q1.php NULL NULL r1.php NULL NULL One more example of my desired result could be achieved by doing a LEFT JOIN rpp ON page_links.page = rpp.page but we need to omit using role_id = 3 (or any value) to be able to get that. But I do want to specify the role_id as well and get the results. I need the query to be able to get this result. I would appreciate any replies that could help me with this. If you can suggest me any changes as well to the table(s) design to be able to achieve the desired result, that's good as well. Thanks in advance.

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  • Mysql Syntax Error

    - by tarnfeld
    Any idea why this is popping up :( ? You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'CREATE TABLE `clocks` ( `id` int(11) NOT NULL AUTO_INCREMENT, ' at line 6

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  • MySQL More Tables or More Rows

    - by Pez Cuckow
    I am working on a game that I am going to open to the public to have on their game. The game stores lots of information (about 300 rows) per website and spends a lot of time updating values within this MySQL database. Is it better (faster/efficient) to add a new table for every website or to just have 1000's of rows in one table and add a column "website_id" or similar?

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  • MySQL Group By and bracketing according to age.

    - by text
    Is that possible that MySQL can handle grouping of data according to age bracket? In my users table, age value is their actual age. I want to group them according to age bracket. For example: ages below 1 year old as age1, 1-4 yrs as age2, 5-9 yrs. old as age3 and so on.

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  • Memcache vs MySQL in memory

    - by TimK
    I have a database that won't grow much in size. It's current size is about 1 GB. Achieving the fastest performance is desired. Question: When should I use Memcache vs simply using MySQL Innodb ability to store all my content within RAM (innodb_buffer_pool_size)?

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  • MySQL optimised code for 2 tables?

    - by David19801
    Hi, I have 2 tables, Table1: id,int1,int2,int3,int4,int5 Table2: integers (autoincrement),blobdata The query I want to use is given the id I want to get the blobdata from table2 associated with the 5 integers in table1. I've only ever used one table in mysql so have no idea how to do this properly. Is it possible? EDIT: id is username, integers in table2 is just integers. but have not built the tables yet, so can change if need to.

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  • PHPFOG and MySql

    - by jim dif
    I am playing around with PHPFog and as a result I ended up with a MySql database. I am trying to figure out how to connect to it with a success message. PHPFog says use this: mysql_connect( $server = getenv('MYSQL_DB_HOST'), $username = getenv('MYSQL_USERNAME'), $password = getenv('MYSQL_PASSWORD')); mysql_select_db(getenv('MYSQL_DB_NAME')); So I basically plug my variables into the above? Or Do I do something different? Thanks, Jim

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  • Creating tables and inserting data (MySQL Dump) using PHP Doctrine 1.2

    - by Dimitry
    Hello. I got a script that create a new database, now I need to fill that database with tables and values (from a MySQL dump file). I'm using PHP - Doctrine 1.2. Here is how I create the database: $manager = Doctrine_Manager::getInstance(); $newConn = $manager->openConnection($customer->Config->db_connection_string); $newConn->createDatabase(); How I do this? Thanks!

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  • MySQL specifying exact order with WHERE `id` IN (...)

    - by Gray Fox
    Is there an easy way to order MySQL results respectively by WHERE id IN (...) clause? Example: SELECT * FROM articles WHERE articles.id IN (4, 2, 5, 9, 3) to return Article with id = 4 Article with id = 2 Article with id = 5 Article with id = 9 Article with id = 3 and also SELECT * FROM articles WHERE articles.id IN (4, 2, 5, 9, 3) LIMIT 2,2 to return Article with id = 5 Article with id = 9

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  • Connecting to remote mysql database with API

    - by Ajay
    I am designing a desktop application in C#, which needs to be connected to my online mysql database. I tried to give access in control panel a "%" which means from any IP, but it is not working. May be the hosting provider (bigrock) not allowing that. Alternatively, I am trying to write some code in online on PHP which will get the "sql" as parameter and returns the output as JSON format using json_encode. Is there any alternate methods which is better approach.

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  • how to implement single sign on for asp.net,mysql websites

    - by kranthi
    Hi, I am using mysql database for my asp.net website.I need to implement to single sign on for multiple instances of my website.Currently to check if a user has logged in I am using a user control which checks for a "loggedin" cookie with single instance of the website.Now I need to extend the logic to achieve single signon for multiple instances of the same site. Could someone please help. Thanks.

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