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  • how relate one table to another for future records

    - by Sinan
    I have a games table which holds the data about a game. Then another table which holds the data about news. So far so good. First I thought about creating a junction table for game_news so I could relate news to games. This way works as intended when the game exists. So whenever I insert a news I can relate it to a game using the junction table. However there are cases when there is news about game but the game isn't published and it doesn't exists. So my question would be; is there a way to relate these news to a particular game when the game record is created. What is the best way to do this? Any ideas?

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  • NHibernate mapping one table on two classes with where selection

    - by Rene Schulte
    We would like to map a single table on two classes with NHibernate. The mapping has to be dynamically depending on the value of a column. Here's a simple example to make it a bit clearer: We have a table called Person with the columns id, Name and Sex. The data from this table should be mapped either on the class Male or on the class Female depending on the value of the column Sex. In Pseudocode: create instance of Male with data from table Person where Person.Sex = 'm'; create instance of Female with data from table Person where Person.Sex = 'f'; The benefit is we have strongly typed domain models and can later avoid switch statements. Is this possible with NHibernate or do we have to map the Person table into a flat Person class first? Then afterwards we would have to use a custom factory method that takes a flat Person instance and returns a Female or Male instance. Would be good if NHibernate (or another library) can handle this.

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  • Regex with all optional parts but at least one required

    - by Alan Mendelevich
    I need to write a regex that matches strings like "abc", "ab", "ac", "bc", "a", "b", "c". Order is important and it shouldn't match multiple appearances of the same part. a?b?c? almost does the trick. Except it matches empty strings too. Is there any way to prevent it from matching empty strings or maybe a different way to write a regex for the task.

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  • Django: many-to-one fields and data integrity

    - by John
    Let's say that I have a Person who runs an inventory system. Each Person has some Cars, and each Car has a very large number of Parts (thousands, let's say). A Person, Bob, uses a Django form to create a Car. Now, Bob goes to create some Parts. It is only at the form level that Django knows that the Parts belong to some specific Car, and that the Parts.ForeignKey(Car) field should only have a specific Car as a choice. When creating a Part, you have to mess with the form's constructor or similar in order to limit the choice of Cars to only the cars owned by Bob. It does not seem proper that to enforce this ownership at the form level. It seems that other users' Cars must be inaccessible to anyone but the owner of the Car. What do you all think about this, and is there any way to enforce this?

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  • SELECT a list of elements and 5 tags for each one

    - by Vittorio Vittori
    Hi, I'm trying to query a set of buldings listed on a table, these buildings are linked with tags. I'm able to do it, but my problem is how limit the number of tags to see: table buildings id building_name style 1 Pompidou bla 2 Alcatraz bla 3 etc. etc. table tags // they can be 50 or more per building id tag_name 1 minimal 2 gothic 3 classical 4 modern 5 etc. table buildings_tags id building_id tag_id I though to do something like this to retrieve the list, but this isn't compplete: SELECT DISTINCT(tag), bulding_name FROM buldings INNER JOIN buildings_tags ON buildings.id = buildings_tags.building_id INNER JOIN tags ON tags.id = buildings_tags.tag_id LIMIT 0, 20 // result building tag Pompidou great Pompidou france Pompidou paris Pompidou industrial Pompidou renzo piano <= How to stop at the 5th result? Pompidou hi-tech Pompidou famous place Pompidou wtf etc.. etc... this query loads the buildings, but this query loads all the tags linked for the building, and not only 5 of them?

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  • How can I overlay one image onto another?

    - by Edward Tanguay
    I would like to display an image composed of two images. I want image rectangle.png to show with image sticker.png on top of it with its left-hand corner at pixel 10, 10. Here is as far as I got, but how do I combine the images? Image image = new Image(); image.Source = new BitmapImage(new Uri(@"c:\test\rectangle.png")); image.Stretch = Stretch.None; image.HorizontalAlignment = HorizontalAlignment.Left; Image imageSticker = new Image(); imageSticker.Source = new BitmapImage(new Uri(@"c:\test\sticker.png")); image.OverlayImage(imageSticker, 10, 10); //how to do this? TheContent.Content = image;

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  • Implement master detail in one datagrid in wpf

    - by Archie
    Hello, I have classes as following: public class Property { public string PropertyName { get; set; } public int SumSubPropertValue; private List<SubProperty> propertyList; public void CalculateSumSubPropertValue { // implementation} } public class SubProperty { public string SubPropertyName { get; set; } public int SubPropertyValue { get; set; } } I have grouped the rows in datagrid on PropertyName . When the user clicks on PropertyName expnader the columns should display SubPropertyName and SubPropertyValue. Also SumSubPropertValue should appear in front of PropertyName in the expander header. My Datagrid is bound to a CollectionViewSource as follows: CollectionViewSource view = new CollectionViewSource(); view.Source = infoList; view.GroupDescriptions.Add(new PropertyGroupDescription("PropertyName")); Where infoList is ObservableCollection<Property>. My datagrid colmns look like <my:DataGrid.Columns> <my:DataGridTextColumn Header="SubPropertyName" Binding="{Binding SubPropertName}" Width="*"/> <my:DataGridTextColumn Header="SubPropertyValue" Binding="{Binding SubPropertyValue}" Width="*"/> </my:DataGrid.Columns> Can someone help me with it?

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  • multiple currency formats in one column - Access 2007

    - by glinch
    Hi there, Is it possible to have multiple currency denominations in a field? I have a field that will have a currency value that will be either euro's or sterling dependent on whether or not the applicable record is in the currency zone. Is this possible in Access or will i need to have seperate fields for euro/sterling? Thanks in advance for any help Noel

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  • django powering multiple shops from one code base on a single domain

    - by imanc
    Hey, I am new to django and python and am trying to figure out how to modify an existing app to run multiple shops through a single domain. Django's sites middleware seems inappropriate in this particular case because it manages different domains, not sites run through the same domain, e.g. : domain.com/uk domain.com/us domain.com/es etc. Each site will need translated content - and minor template changes. The solution needs to be flexible enough to allow for easy modification of templates. The forms will also need to vary a bit, e.g minor variances in fields and validation for each country specific shop. I am thinking along the lines of the following as a solution and would love some feedback from experienced django-ers: In short: same codebase, but separate country specific urls files, separate templates and separate database Create a middleware class that does IP localisation, determines the country based on the URL and creates a database connection, e.g. /au/ will point to the au specific database and so on. in root urls.py have routes that point to a separate country specific routing file, e..g (r'^au/',include('urls_au')), (r'^es/',include('urls_es')), use a single template directory but in that directory have a localised directory structure, e.g. /base.html and /uk/base.html and write a custom template loader that looks for local templates first. (or have a separate directory for each shop and set the template directory path in middleware) use the django internationalisation to manage translation strings throughout slight variances in forms and models (e.g. ZA has an ID field, France has 'door code' and 'floor' etc.) I am unsure how to handle these variations but I suspect the tables will contain all fields but allowing nulls and the model will have all fields but allowing nulls. The forms will to be modified slightly for each shop. Anyway, I am keen to get feedback on the best way to go about achieving this multi site solution. It seems like it would work, but feels a bit "hackish" and I wonder if there's a more elegant way of getting this solution to work. Thanks, imanc

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  • Two UIViews in one .xib file?

    - by Tronic
    hi, i made a second uiview in mei .xib file. the first view is landscape and i get it by following code ItemController *newItem; newItem = [[ItemController alloc] init]; newItem.view..... how can i "activate" the second view, so i can use it with newItem.view2... is that possible? the second view is portait mode, so it should be hidden and when turning the ipad the first view should be hidden and the second gets visible. thanks

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  • Copying one form's values to another form using JQuery

    - by rsturim
    I have a "shipping" form that I want to offer users the ability to copy their input values over to their "billing" form by simply checking a checkbox. I've coded up a solution that works -- but, I'm sort of new to jQuery and wanted some criticism on how I went about achieving this. Is this well done -- any refactorings you'd recommend? Any advice would be much appreciated! The Script <script type="text/javascript"> $(function() { $("#copy").click(function() { if($(this).is(":checked")){ var $allShippingInputs = $(":input:not(input[type=submit])", "form#shipping"); $allShippingInputs.each(function() { var billingInput = "#" + this.name.replace("ship", "bill"); $(billingInput).val($(this).val()); }) //console.log("checked"); } else { $(':input','#billing') .not(':button, :submit, :reset, :hidden') .val('') .removeAttr('checked') .removeAttr('selected'); //console.log("not checked") } }); }); </script> The Form <div> <form action="" method="get" name="shipping" id="shipping"> <fieldset> <legend>Shipping</legend> <ul> <li> <label for="ship_first_name">First Name:</label> <input type="text" name="ship_first_name" id="ship_first_name" value="John" size="" /> </li> <li> <label for="ship_last_name">Last Name:</label> <input type="text" name="ship_last_name" id="ship_last_name" value="Smith" size="" /> </li> <li> <label for="ship_state">State:</label> <select name="ship_state" id="ship_state"> <option value="RI">Rhode Island</option> <option value="VT" selected="selected">Vermont</option> <option value="CT">Connecticut</option> </select> </li> <li> <label for="ship_zip_code">Zip Code</label> <input type="text" name="ship_zip_code" id="ship_zip_code" value="05401" size="8" /> </li> <li> <input type="submit" name="" /> </li> </ul> </fieldset> </form> </div> <div> <form action="" method="get" name="billing" id="billing"> <fieldset> <legend>Billing</legend> <ul> <li> <input type="checkbox" name="copy" id="copy" /> <label for="copy">Same of my shipping</label> </li> <li> <label for="bill_first_name">First Name:</label> <input type="text" name="bill_first_name" id="bill_first_name" value="" size="" /> </li> <li> <label for="bill_last_name">Last Name:</label> <input type="text" name="bill_last_name" id="bill_last_name" value="" size="" /> </li> <li> <label for="bill_state">State:</label> <select name="bill_state" id="bill_state"> <option>-- Choose State --</option> <option value="RI">Rhode Island</option> <option value="VT">Vermont</option> <option value="CT">Connecticut</option> </select> </li> <li> <label for="bill_zip_code">Zip Code</label> <input type="text" name="bill_zip_code" id="bill_zip_code" value="" size="8" /> </li> <li> <input type="submit" name="" /> </li> </ul> </fieldset> </form> </div>

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  • MYSQL in PHPMYADMIN - create table relationship from one table

    - by Stanley DecoWood
    I want to create a table relationship with MYSQL PHPMYADMIN. I have this Create table: CREATE TABLE students(code_students int(8)not null AUTO_INCREMENT, name_students varchar(25), age_students int(3), degree_program varchar(25), code_advisor int(8)not null, primary key(code_students, code_advisor) ); and i want to make a create table named advise relationship between code_students, code_advisor.

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  • How can I display an ASP.NET MVC html part from one application in another

    - by Frank Sessions
    We have several asp.net MVC apps in the following setup SecurityApp (root application - handles forms auth for SSO and has a profile edit page) Application1 (virtual directory) Application2 (virtual directory) Application3 (virtual directory) so that domain.com points to SecurityApp and domain.com/Application1 etc point to their associated virtual directories. All of our Single Sign On (SSO) is working properly using forms authentication. Based on the users permissions when logging in a menu that lists their available applications and a logout link will be generated and saved in the cache - this menu displays fine whenever the user is in the SecurityApp (editing their profile) but we cannot figure out how to get the Applications in the virtual directories to display the same application menu. We have tried: 1) Using JSONP to do an request that will return the html for the menu. The ajax call returns the HTML with the html; however, because User.IsAuthenticated is false the menu comes back empty. 2) We created a user control and include it along with the dll's for the SecurityApp project and this works; however, we dont want to have to include all the dlls for the SecurityApp project in every application that we create (along with all the app settings in the web.config) We would like this to be as simple as possible to implement so that anyone creating a new app can add the menu to their application in as few steps as possible... Any ideas? To Clarify - we are using ASP.NET MVC 1.0 since these apps are in production and we do not have the okay to go to ASP.NET MVC 2.0 (unfortunately)

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  • php run function on all images from one dir in recursive mode (noob)

    - by Steve
    hey guyz i have a function $result = create_watermark( 'input_file_name' ,'output_file_name'); i have dir called /images n have 500 images in it and all images are link images_(some_unknown_numbers).png (all png) now i want run them thru function in loop and want out put like /markedimage/images_1.png images_2.png images_3.png i need help how can i run them in loop and how out put name can change want run script on Ubuntu so we can use shell too if any body want check function it is here http://paste2.org/p/789149 plz provide me code because i m newbie thanks in advance

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  • Does any one know of a packet generator?

    - by Benoit
    We have a networked device, and we would like to perform some tests on how it handles malformed packets. Is there a product out there that can generate arbitrary packets and packet sequences? I would like to be able to specify a set of TCP/IP payloads and it would open a connection and send the data. Obviouly, the TCP/IP checksum should be calculated correctly, etc... Kind of like a wireshark in reverse. Note that I am not interested in network loading and blasting millions of packet.

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  • After Adding "readonly" attribute on text box not able to remove it in one event

    - by Sreedhar K
    Steps to repro USE Internet Explorer Check unlimited check box Click on text box (It will remove tick/check from check box) Try to enter text in text box We cannot enter in the text box 4. Click again on the text box. Now we will be able to enter text in the text box We tried by 1. Making attribute readOnly to flase i.e. $('#myinput').attr('readOnly', false); 2. Calling $('#myinput').click(); Below is the HTML code <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>Make input read only</title> <script type="text/javascript" src="http://ajax.microsoft.com/ajax/jquery/jquery-1.4.4.min.js"></script> </head> <body> <input id="myinput" type="text" /> <input id="mycheck" type="checkbox" /> <script type="text/javascript"> /*oncheck box click*/ $('#mycheck').click(function () { if ($(this).attr('checked')) { $('#myinput').attr('readOnly', 'readOnly'); } else { $('#myinput').removeAttr('readOnly'); /* also tried * $('#myinput').attr('readOnly', false); * $('#myinput').attr('readOnly', ''); */ } }); /*on text box click*/ $('#myinput').click(function () { $('#mycheck').removeAttr('checked'); $('#myinput').removeAttr('readOnly'); /* also tried * $('#myinput').attr('readOnly', false); * $('#myinput').attr('readOnly', ''); */ }); </script> </body> </html> Live copy

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  • Replacing characters with specified one

    - by mahesh
    Hello All, I have a string as follows - MFMFMF now i want to change this string to FMFMFM how to do this , help needed pls i had tried select replace(replace('mfmfmf','M','F'),'F','M') this gives me result - MMMMMM which i donot what i want the output to be FMFMFM Need your help D.Mahesh

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  • Multiple projects with multiple (different) build configuration in one solution

    - by KTC
    What is the correct and easy step by step way to have multiple build configurations in the same VS project, where the Solution also contain multiple projects? The projects would have different build configurations. Basically, I'm looking for something like project A with Dll Debug, Dll Release, Static (library) Debug, and Static (library) Release, project B with Debug & Release that build a .exe.

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  • Returning new object, overwrite the existing one in Java

    - by lupin
    Note: This is an assignment. Hi, Ok I have this method that will create a supposedly union of 2 sets. i mport java.io.*; class Set { public int numberOfElements; public String[] setElements; public int maxNumberOfElements; // constructor for our Set class public Set(int numberOfE, int setE, int maxNumberOfE) { this.numberOfElements = numberOfE; this.setElements = new String[setE]; this.maxNumberOfElements = maxNumberOfE; } // Helper method to shorten/remove element of array since we're using basic array instead of ArrayList or HashSet from collection interface :( static String[] removeAt(int k, String[] arr) { final int L = arr.length; String[] ret = new String[L - 1]; System.arraycopy(arr, 0, ret, 0, k); System.arraycopy(arr, k + 1, ret, k, L - k - 1); return ret; } int findElement(String element) { int retval = 0; for ( int i = 0; i < setElements.length; i++) { if ( setElements[i] != null && setElements[i].equals(element) ) { return retval = i; } retval = -1; } return retval; } void add(String newValue) { int elem = findElement(newValue); if( numberOfElements < maxNumberOfElements && elem == -1 ) { setElements[numberOfElements] = newValue; numberOfElements++; } } int getLength() { if ( setElements != null ) { return setElements.length; } else { return 0; } } String[] emptySet() { setElements = new String[0]; return setElements; } Boolean isFull() { Boolean True = new Boolean(true); Boolean False = new Boolean(false); if ( setElements.length == maxNumberOfElements ){ return True; } else { return False; } } Boolean isEmpty() { Boolean True = new Boolean(true); Boolean False = new Boolean(false); if ( setElements.length == 0 ) { return True; } else { return False; } } void remove(String newValue) { for ( int i = 0; i < setElements.length; i++) { if ( setElements[i] != null && setElements[i].equals(newValue) ) { setElements = removeAt(i,setElements); } } } int isAMember(String element) { int retval = -1; for ( int i = 0; i < setElements.length; i++ ) { if (setElements[i] != null && setElements[i].equals(element)) { return retval = i; } } return retval; } void printSet() { for ( int i = 0; i < setElements.length; i++) { if (setElements[i] != null) { System.out.println("Member elements on index: "+ i +" " + setElements[i]); } } } String[] getMember() { String[] tempArray = new String[setElements.length]; for ( int i = 0; i < setElements.length; i++) { if(setElements[i] != null) { tempArray[i] = setElements[i]; } } return tempArray; } Set union(Set x, Set y) { String[] newXtemparray = new String[x.getLength()]; String[] newYtemparray = new String[y.getLength()]; int len = newYtemparray.length + newXtemparray.length; Set temp = new Set(0,len,len); newXtemparray = x.getMember(); newYtemparray = x.getMember(); for(int i = 0; i < newYtemparray.length; i++) { temp.add(newYtemparray[i]); } for(int j = 0; j < newXtemparray.length; j++) { temp.add(newXtemparray[j]); } return temp; } Set difference(Set x, Set y) { String[] newXtemparray = new String[x.getLength()]; String[] newYtemparray = new String[y.getLength()]; int len = newYtemparray.length + newXtemparray.length; Set temp = new Set(0,len,len); newXtemparray = x.getMember(); newYtemparray = x.getMember(); for(int i = 0; i < newXtemparray.length; i++) { temp.add(newYtemparray[i]); } for(int j = 0; j < newYtemparray.length; j++) { int retval = temp.findElement(newYtemparray[j]); if( retval != -1 ) { temp.remove(newYtemparray[j]); } } return temp; } } // This is the SetDemo class that will make use of our Set class class SetDemo { public static void main(String[] args) { //get input from keyboard BufferedReader keyboard; InputStreamReader reader; String temp = ""; reader = new InputStreamReader(System.in); keyboard = new BufferedReader(reader); try { System.out.println("Enter string element to be added" ); temp = keyboard.readLine( ); System.out.println("You entered " + temp ); } catch (IOException IOerr) { System.out.println("There was an error during input"); } /* ************************************************************************** * Test cases for our new created Set class. * ************************************************************************** */ Set setA = new Set(0,10,10); setA.add(temp); setA.add("b"); setA.add("b"); setA.add("hello"); setA.add("world"); setA.add("six"); setA.add("seven"); setA.add("b"); int size = setA.getLength(); System.out.println("Set size is: " + size ); Boolean isempty = setA.isEmpty(); System.out.println("Set is empty? " + isempty ); int ismember = setA.isAMember("sixb"); System.out.println("Element sixb is member of setA? " + ismember ); Boolean output = setA.isFull(); System.out.println("Set is full? " + output ); //setA.printSet(); int index = setA.findElement("world"); System.out.println("Element b located on index: " + index ); setA.remove("b"); //setA.emptySet(); int resize = setA.getLength(); System.out.println("Set size is: " + resize ); //setA.printSet(); Set setB = new Set(0,10,10); setB.add("b"); setB.add("z"); setB.add("x"); setB.add("y"); Set setC = setA.union(setB,setA); System.out.println("Elements of setA"); setA.printSet(); System.out.println("Union of setA and setB"); setC.printSet(); } } The union method works a sense that somehow I can call another method on it but it doesn't do the job, i supposedly would create and union of all elements of setA and setB but it only return element of setB. Sample output follows: java SetDemo Enter string element to be added hello You entered hello Set size is: 10 Set is empty? false Element sixb is member of setA? -1 Set is full? true Element b located on index: 2 Set size is: 9 Elements of setA Member elements on index: 0 hello Member elements on index: 1 world Member elements on index: 2 six Member elements on index: 3 seven Union of setA and setB Member elements on index: 0 b Member elements on index: 1 z Member elements on index: 2 x Member elements on index: 3 y thanks, lupin

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  • Releasing an app - Developed on one account, releasing/approving on another

    - by stumac85
    Hi there, We have developed an application for a company who want to release it under their own account. It has been developed on our account and has had provisioning profiles attached to it from our own account. What is the best way to do this? Do I have to send them the xCode project and talk them through how to attack a provisioning profile to the project? Or can I just get their login details and create a provisioning profile from the Mac in the office and do it for them? Or is there a "transfer to different account" option? Many thanks!

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  • Get multiple records with one query

    - by Lewy
    User table: name lastname Bob Presley Jamie Cox Lucy Bush Find users q = Query.new("Bob Presley, Cox, Lucy") q.find_users => {0=>{:name=>"Bob", :lastname=>"Presley"}, 1=>{:lastname=>"Cox"}, 2=>{:name=>"Lucy"}} Question: I've got hash with few names and lastnames. I need to build Activerecord query to fetch all users from that hash. I can do object = [] hash = q.find_users hash.each do |data| #check if data[:lastname] and data[:name] exist # object << User.where(:name => ..., :lastname => ...) end But I think it is higly inefficient. How should I do this ?

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