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• WPF StaticResource bound to subproperty

  - by mizipzor

  I have a class thats created as a resource: <Window.Resources> <Model:MyModel x:Key="model" /> </Window.Resources> The MyModel class has a cli property named Foo. I want the selected value in a combobox to be bound to this property. I thought I could do this but Im getting errors: <ComboBox SelectedItem="{Binding Source={StaticResource model.Foo}}" /> Heres the error: Cannot find resource named '{model.Foo}'. Where did I go wrong? What extra parameters do I need to specify to properly bind to a subproperty?

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• Accessing inter-schema tables and relations in hibernate

  - by nitesh

  There is a typical situation being faced where different tables are scattered through different schemas in Oracle database and they are related to each other (encompassing all different types of relations). How can they be represented in Hibernate using annotations as when a sessionfactory handle is created for one schema, tables in that schema can't access other related tables (foreign key relation to tables in other schema)? For a query like following, exception is thrown - "from table1 as model where model.table2Name.table2column = "+foo Exception comes as - org.hibernate.QueryException: could not resolve property: table2column of: com.test.table1 [from com.test.table1 as model where model.table2Name.table2column = 1] Here table1 and table2 are present in different schemas.

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• Rails ActiveRecord - How to set association save order

  - by Altonymous

  I have a weird relationship that needs to be maintained for legacy processes. I'm trying to figure out how to create the relationship given the new model association. New Relationship Setup Machine has_many MachineReadings has_many Disks has_many DiskReadings Old Relationship Setup Machine has_many MachineReadings has_many DiskReadings has_many Disks The problem is data will come in on the Machine model as nested attributes using the new relationship setup. I need to update the machine_reading_id in the DiskReading model so the old association can continue to be used. I tried doing this via an after_save hook that would traverse back up to the machine and then down to the readings to get the machine_reading.id so I could populate the DiskReading model. However, the associations aren't being saved in the order I would expect. They are saving the Disks & DiskReadings before saving the MachineReadings. So when I go after the machine_reading.id it hasn't been written and thus I am unable to get access to it. For example: #machine_disk_reading.rb after_save :build_old_relationship def build_old_relationship self.machine_reading_id = self.disk.machine.readings.find_by_date_time(self.date_time).id end

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• Teacher confused about MVC?

  - by Gideon

  I have an assignment to create a game in java using MVC as a pattern. The thing is that stuff I read about MVC aren't really what the teacher is telling me. What I read is that the Model are the information objects, they are manipulated by the controllers. So in a game the controller mutates the placement of the objects and check if there is any collision etc. What my teacher told me is that I should put everything that is universal to the platform in the models and the controllers should only tell the model which input is given. That means the game loop will be in a model class, but also collision checks etc. So what I get from his story is that the View is the screen, the Controller is the unput handeler, and the Model is the rest. Can someone point me in the right direction?

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• How can I keep the the logic to translate a ViewModel's values to a Where clause to apply to a linq query out of My Controller?

  - by Mr. Manager

  This same problem keeps cropping up. I have a viewModel that doesn't have any persistent backing. It is just a ViewModel to generate a search input form. I want to build a large where clause from the values the user entered. If the Action Accepts as a parameter SearchViewModel How do I do this without passing my viewModel to my service layer? Service shouldn't know about ViewModels right? Oh and if I serialize it, then it would be a big string and the key/values would be strongly typed. SearchViewModel this is just a snippet. [Display(Name="Address")] public string AddressKeywords { get; set; } /// <summary> /// Gets or sets the census. /// </summary> public string Census { get; set; } /// <summary> /// Gets or sets the lot block sub. /// </summary> public string LotBlockSub { get; set; } /// <summary> /// Gets or sets the owner keywords. /// </summary> [Display(Name="Owner")] public string OwnerKeywords { get; set; } In my controller action I was thinking of something like this. but I would think all this logic doesn't belong in my Controller. ActionResult GetSearchResults(SearchViewModel model){ var query = service.GetAllParcels(); if(model.Census != null){ query = query.Where(x=>x.Census == model.Census); } if (model.OwnerKeywords != null){ query = query.Where(x=>x.Owners == model.OwnerKeywords); } return View(query.ToList()); }

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• How to pass javascript variable to asp code with ASP.NET MVC

  - by Bolu

  for(var i=0; i<<%=Model.Mydatalist.Count%>;i++) { //then I need to pass i to Mydatalist like Model.Mydatalist[i] } //var myJSdata="<%Model.Mydatalist["&i&"]%>"; is not working.. as system see i (i's value) as a string, and will throw exception: cannot convert string to int.

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• How to create the automatic mass form submitter (javascript-ajax script) to be used on the 3rd part

  - by Daniel

  I need a script that can handle the following tasks. Take user data from my database and fill in and submit / post data to forms located on third part websites.: So I want to know if is it hard to create or do somebody knows if does exists some script for mass form submissions in PHP -Javascript-Ajax ? I run Dancers & Hostess & Model jobs website, I would like to find some script which allows the girls automaticly submit to hundreds websites forms (other 3rd part model agencies) with their similar model application form info on my website previously specified, 1).Firstly the girls will fill out my agency portfolio very detailed form , like this i will get all the model personal info from them , 2) Secondly i would like to allow for example models to submit to 100 and more other model agencies forms (I will find those websites before, and I will get their field names = values and thanks to some script would like to connect them with every girl data already created in my website to submit . I would like to implement it to my wordpress website where the girls has their portfolios instead of my pages . I would like to offer this service especially to models , it should work like some directory submitters , The script knows names - values and fill it out itself, but I want it online - browser side, where the girls should only fill out captcha if there is and click the button "submit".After succesful submit it should offer other form to submit. I would be very happy if you know the answer or if you can redirect me to some article

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• Django admin - remove field if editing an object

  - by John McCollum

  I have a model which is accessible through the Django admin area, something like the following: # model class Foo(models.Model): field_a = models.CharField(max_length=100) field_b = models.CharField(max_length=100) # admin.py class FooAdmin(admin.ModelAdmin): pass Let's say that I want to show field_a and field_b if the user is adding an object, but only field_a if the user is editing an object. Is there a simple way to do this, perhaps using the fields attribute? If if comes to it, I could hack a JavaScript solution, but it doesn't feel right to do that at all!

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• MVC3 html.TextBox

  - by BigTommy79

  I have login view that takes a LoginPageViewModel: public class LoginPageViewModel : PageViewModel { public string ReturnUrl { get; set; } public bool PreviousLoginFailed { get; set; } public LoginFormViewModel EditForm { get; set; } } which is rendered in the view. When a user tries to log in I only want to post the LoginFormViewModel (Model.EditForm) to the controller: public ActionResult Login(LoginFormViewModel loginDetails) { //do stuff } Using Html.TextBox I can specify the name of the form field manually 'loginDetails.UserName' and post back to the controller and everything works. @model Web.Controllers.User.ViewModels.LoginPageViewModel @using (Html.BeginForm()){ @Html.Hidden("loginDetails.ReturnUrl", Model.ReturnUrl) @Html.LabelFor(x => x.EditForm.UserName, "User Name:") @Html.TextBox("loginDetails.UserName", Model.EditForm.UserName) @Html.ValidationMessageFor(x => x.EditForm.UserName) ..... But what I want to do is to use the staticaly typed helper, something like: @Html.TextBoxFor(x => x.EditForm.UserName) But I'm unable to get this to work. Are you only able to post back the same model when useing the strongly typed helpers? Is there something I'm missing on this? Intellisense doesn't seem to give any clues such as a form field string.

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• Does Spring MVC form submit data bind children objects automagically?

  - by predhme

  I have a data model that is something like this: public class Report { // report owner private User user; ... typical getter setter ... } public class User { ... omitted for clarity } What happens is when a report is created, the current user is set to the report user object. When the report is edited, the spring controller handling the POST request is receiving a report where the user object is null. Here is what my controller looks like: @Controller @RequestMapping("/report") public class ReportController { @RequestMapping(value = "/edit/{id}", method = RequestMethod.GET) public String editReport(@PathVariable Long id, Model model) { Report r = backend.getReport(id); // fully loads object model.addAttribute("report", report); return "report/edit"; } @RequestMapping(value = "/edit/{id}", method = RequestMethod.POST) public String process(@ModelAttribute("report") Report r) { backend.save(r); return "redirect:/report/show" + r.getId(); } } I ran things throw the debugger and it looks like in the editReport method the model object is storing the fully loaded report object (I can see the user inside the report). On the form jsp I can do the following: ${report.user.username} and the correct result is rendered. However, when I look at the debugger in the process method, the passed in Report r has a null user. I don't need to do any special data binding to ensure that information is retained do I?

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• Subprocess with variables & Command from different class

  - by Pastelinux

  source: http://pastebin.com/utL7Ebeq My thinking is that if i run from controller class "main" it will allow me to take the "data" from Class "model", def "filename". It doesn't seem to work. As you can see below what i mean class Controller: def __init__(self): self.model = Model() self.view = View() def main(self): data = self.model.filename() self.view.tcpdump(data) class View: def tcpdump(self, command): subprocess.call(command.split(), shell=False) When i run my code i get this error: subprocess.call(command.split(), shell=False) AttributeError: 'NoneType' object has no attribute 'split' My guess means that its not picking up command (look at source for reference) or that its not getting command with variables. But i know the error when variables are not being picked up so i don't think it is that. My question is, from what i have thus far, how do i from "class view" grab "command" for my subprocesses to run. Thanks~ John Riselvato

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• rendering html to png (server-side)

  - by jonny

  Hi! I have a workflow model. Internet Explorer doesn't support some features required for model editing functionality (and regular user doesn't need it). I want a read-only preview of my model. Is it possible to server-side render my html to image?

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• MVC Validator.TryValidateObject does not validate custom atrribute, validateAllProperties = true

  - by nealsu

  When calling Validator.TryValidateObject with validateAllProperties = true my custom validation attribute does not get triggered. The ValidationResult does not contain an entry for my erroneous property value. Below is the model, attribute and code used to test this. //Model public class Model { [AmountGreaterThanZero] public int? Amount { get; set; } } //Attribute public sealed class AmountGreaterThanZero: ValidationAttribute { private const string errorMessage = "Amount should be greater than zero."; public AmountGreaterThanZero() : base(errorMessage) { } public override string FormatErrorMessage(string name) { return errorMessage; } protected override ValidationResult IsValid(object value, ValidationContext validationContext) { if (value != null) { if ((int)value <= 0) { var message = FormatErrorMessage(validationContext.DisplayName); return new ValidationResult(message); } } return null; } } //Validation Code var container = new Container(); container.ModelList = new List<Model>() { new Model() { Amount = -5 } }; var validationContext = new ValidationContext(container, null, null); var validationResults = new List<ValidationResult>(); var modelIsValid = Validator.TryValidateObject(container, validationContext, validationResults, true); Note: That the validation works fine and ValidationResult returns with correct error message if I use the TryValidateProperty method.

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• ASP.NET MVC Generic Partial

  - by gnome

  Is is possible to have a partial view inherit more than one model? I have three models (Contacts, Clients, Vendors) that all have address information (Address). In the interest of being DRY I pulled the address info into it's own model, Addresses. I created a partial create / update view of addresses and what to render this in other other three model's create / update views.

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• Access: Expression too complex to be evaluated

  - by user2502964

  I'm trying to sort out values from a database by the weekending date. The script I'm using functions on 6 of my 7 databases (they are all constructed identically). The 7th database doesn't function. I get the expression too complex error. any help figuring out why?? Here is my code: SELECT UPC_Test.Type, UPC_Test.[Model No], UPC_Test.[Model Desc], UPC_Test.[Serial No], Format(DateValue([UPC_Test].[Test Date]+7-Weekday([UPC_Test].[Test Date],0)),"m/d/yyyy") AS [Test Date], UPC_Test.Parameter, UPC_Test.[Failure Symptom], UPC_Test.[Repair Action], UPC_Test.[Factory Select], UPC_Test.[Test Station] FROM UPC_Test GROUP BY UPC_Test.Type, UPC_Test.[Model No], UPC_Test.[Model Desc], UPC_Test.[Serial No], Format(DateValue([UPC_Test].[Test Date]+7-Weekday([UPC_Test].[Test Date],0)),"m/d/yyyy"), UPC_Test.Parameter, UPC_Test.[Failure Symptom], UPC_Test.[Repair Action], UPC_Test.[Factory Select], UPC_Test.[Test Station] HAVING (((UPC_Test.Type)="Production") AND ((Format(DateValue([UPC_Test].[Test Date]+7-Weekday([UPC_Test].[Test Date],0)),"m/d/yyyy"))=[Enter]) AND ((UPC_Test.[Failure Symptom])<>"") AND ((UPC_Test.[Repair Action])<>"") AND ((UPC_Test.[Test Station])="UPC RF Test")) ORDER BY Format(DateValue([UPC_Test].[Test Date]+7-Weekday([UPC_Test].[Test Date],0)),"m/d/yyyy");

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• ManyToManyField error when having recursive structure. How to solve it?

  - by luc

  Hello, I have the following table in the model with a recursive structure (a page can have children pages) class DynamicPage(models.Model): name = models.CharField("Titre",max_length=200) parent = models.ForeignKey('self',null=True,blank=True) I want to create another table with manytomany relation with this one: class UserMessage(models.Model): name = models.CharField("Nom", max_length=100) page = models.ManyToManyField(DynamicPage) The generated SQL creates the following constraint: ALTER TABLE `website_dynamicpage` ADD CONSTRAINT `parent_id_refs_id_29c58e1b` FOREIGN KEY (`parent_id`) REFERENCES `website_dynamicpage` (`id`); I would like to have the ManyToMany with the page itself (the id) and not with the parent field. How to modify the model to make the constraint using the id and not the parent? Thanks in advance

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• Where do I put constants file for Codeigniter (PHP)?

  - by wag2639

  I have a list of constants (I'm using them as an enum), some are define statements, and some are just global variables. Where am I suppose to put them in the MVC framework so I can use them for both my model and my controller that needs to reference it? I'd rather not stick it into config/constants.php since they shouldn't be called except for by this model and the controllers that use it. Edit 1: Clarification To be more specific, I have my message_model model and it has a bunch of constants that I need that are stored in message_model_constants.php. Where should I put message_model_constants.php and is there a way to have it automatically included by the controller that loads message_model when message_model is not (and I don't want it to be) auto-loaded. Edit 2: I really don't want to have the constants auto-loaded except for when I use the model

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• Entity framework: Need a easy going, clean database migration solution.

  - by user469652

  I'm using entity framework model first development, and I need to do database migration often, The EF database generation power pack doesn't help a lot, because that data migration never worked here. The database migration here I mean, change the model, and then I can update the existing database from the model, but creating a new one. Is there any free of charge tool here invented here yet? Or would this going to be a new feature of next EF release? PS: I love django's ORM.

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• What is the meaning of @ModelAttribute annotation at method argument level?

  - by beemaster

  Spring 3 reference teaches us: When you place it on a method parameter, @ModelAttribute maps a model attribute to the specific, annotated method parameter I don't understand this magic spell, because i sure that model object's alias (key value if using ModelMap as return type) passed to the View after executing of the request handler method. Therefore when request handler method executes the model object's name can't be mapped to the method parameter. To solve this contradiction i went to stackoverflow and found this detailed example. The author of example said: // The "personAttribute" model has been passed to the controller from the JSP It seems, he is charmed by Spring reference... To dispel the charms i deployed his sample app in my environment and cruelly cut @ModelAttribute annotation from method MainController.saveEdit. As result the application works without any changes! So i conclude: the @ModelAttribute annotation is not needed to pass web form's field values to the argument's fields. Then i stuck to the question: what is the mean of @ModelAttribute annotation? If the only mean is to set alias for model object in View, then why this way better than explicitly adding of object to ModelMap?

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• Spring MVC - Set an actionURL parameter with Javascript

  - by jeffl8n

  Is it possible to dynamically set a Spring MVC portlet:actionURL portlet:param using javascript? I have tried with the following code, but the id value always comes across as null to the controller. I have verified that setting the portlet:param manually passes the value correctly: <portlet:param name="id" value="2" /> I have also verified the value in the javascript is being set correctly and is not null. (Note: I've changed the variable names, etc. from the original code to simplify it and obfuscate it since it is my employer's code.) JSP: <portlet:actionURL var="modifyURL"> <portlet:param name="do" value="modify" /> <portlet:param name="id" value="${model.id}" /> </portlet:actionURL> ... <form:form action="${modifyURL}" id="modifyForm" modelAttribute="model"> <form:hidden path="id" id="id" /> </form:form> Javascript called when the update URL is clicked: function update() { document.forms[0]["id"].value = selectedId; document.forms[0].submit(); } Controller: @RequestMapping(params = {"do=modify"}) public void modify(@ModelAttribute("model") Model model, @RequestParam(value = "id", required=true) Long id, ActionRequest request, ActionResponse response, SessionStatus sessionStatus, ModelMap modelMap) { ....

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• how to copy from one column to another but with different format

  - by Bob

  I hv a table like this:- Item Model Remarks ----------------------------------------- A 10022009 B 10032006 C 05081997 I need to copy the info from "Model" to "Remarks" with the following format:- Item Model Remarks ----------------------------------------- A 10022009 20090210 B 10032006 20060310 C 05081997 19970805 Thanks

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• Django call function when an object gets added

  - by dotty

  Hay, i have a simple model class Manufacturer(models.Model): name = models.CharField() car_count = models.IntegerField() class Car(models.Model): maker = ForeignKey(Manufacturer) I want to update the car_count field when a car is added to a manufacturer, I'm aware i could just count the Manufacturer.car_set() to get the value, but i want the value to be stored within that car_count field. How would i do this? EDIT Would something like this work? def save(self): if self.id: car_count = self.car_set.count() self.save()

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• Question about architecting asp.net mvc application ?

  - by Misnomer

  I have read little bit about architecture and also patterns in order to follow the best practices. So this is the architecture we have and I wanted to know what you think of it and any proposed changes or improvements to it - Presentation Layer - Contains all the views,controllers and any helper classes that the view requires also it containes the reference to Model Layer and Business Layer. Business Project - Contains all the business logic and validation and security helper classes that are being used by it. It contains a reference to DataAccess Layer and Model Layer. Data Access Layer - Contains the actual queries being made on the entity classes(CRUD) operations on the entity classes. It contains reference to Model Layer. Model Layer - Contains the entity framework model,DTOs,Enums.Does not really have a reference to any of the above layers. What are your thoughts on the above architecture ? The problem is that I am getting confused by reading about like say the repository pattern, domain driven design and other design patterns. The architecture we have although not that strict still is relatively alright I think and does not really muddle things but I maybe wrong. I would appreciate any help or suggestions here. Thanks !

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• Should I create a new extension for an xml file?

  - by macleojw

  I'm working with a data model stored in XML files. I want to create some metadata for the model and store it alongside, but would like to be able to distinguish between the two. The data model is imported into some software from time to time and we don't want it to try to import the meta data files. To get round this, I've been thinking of creating a new extension for the metadata xml files (say .mdml). Is this good practice?

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• How to make paging start from 1 instead of 0 in ASP.NET MVC

  - by ssx

  I used the paging example of the Nerddinner tutorial. But I also wanted to add page Numbers, somehting like that: <<< 1 2 3 4 5 6 The code below works if i start my paging from 0, but not from 1. How can I fix this ? Here is my code: PaginatedList.cs public class PaginatedList<T> : List<T> { public int PageIndex { get; private set; } public int PageSize { get; private set; } public int TotalCount { get; private set; } public int TotalPages { get; private set; } public PaginatedList(IQueryable<T> source, int pageIndex, int pageSize) { PageIndex = pageIndex; PageSize = pageSize; TotalCount = source.Count(); TotalPages = (int) Math.Ceiling(TotalCount / (double)PageSize); this.AddRange(source.Skip(PageIndex * PageSize).Take(PageSize)); } public bool HasPreviousPage { get { return (PageIndex > 0); } } public bool HasNextPage { get { return (PageIndex+1 < TotalPages); } } } UserController.cs public ActionResult List(int? page) { const int pageSize = 20; IUserRepository userRepository = new UserRepository(); IQueryable<User> listUsers = userRepository.GetAll(); PaginatedList<User> paginatedUsers = new PaginatedList<User>(listUsers, page ?? 0, pageSize); return View(paginatedUsers); } List.cshtml @if (Model.HasPreviousPage) { @Html.RouteLink(" Previous ", "PaginatedUsers", new { page = (Model.PageIndex - 1) }) } @for (int i = 1; i <= Model.TotalPages; i++) { @Html.RouteLink(@i.ToString(), "PaginatedUsers", new { page = (@i ) }) } @if (Model.HasNextPage) { @Html.RouteLink(" Next ", "PaginatedUsers", new { page = (Model.PageIndex + 1) }) }

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