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  • autologin component doesn't work on remote server

    - by user606521
    I am using autologin component from http://milesj.me/code/cakephp/auto-login (v 3.5.1). It works on my localhost WAMP server but fails on remote server. I am using this settings in beforeFilter() callback: $this->AutoLogin->settings = array( // Model settings 'model' => 'User', 'username' => 'username', 'password' => 'password', // Controller settings 'plugin' => '', 'controller' => 'users', // Cookie settings 'cookieName' => 'rememberMe', 'expires' => '+1 month', // Process logic 'active' => true, 'redirect' => true, 'requirePrompt' => true ); On remote server it simply doesn't autolog users after the browser was closed. I can't figure out what may cause the problem. -------------------- edit I figured out what is causing the problem but I don't know how to fix this. First of all cookie is set like this: $this->Cookie->write('key',array('username' => 'someusername', 'hash' => 'somehash', ...) ); Then it's readed like this: $cookie = $this->Cookie->read('key'); On my WAMP server $cookie is array('username' => 'someusername', 'hash' => 'somehash', ...) and on remote server returned $cookie is string(159) "{\"username\":\"YWxlay5iYXJzsdsdZXdza2ldssd21haWwuY29t\",\"password\":\"YWxlazc3ODEy\",\"hash\":\"aa15bffff9ca12cdcgfgb351d8bfg2f370bf458\",\"time\":1339923926}" and it should be: array( 'username' => "YWxlay5iYXJzsdsdZXdza2ldssd21haWwuY29t", 'password' => "YWxlazc3ODEy", ...) Why the retuned cookie is string not array?

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  • python global variable not working in apache

    - by Suhail
    I am facing issue with the global variable, when i run in the django development server it works fine, but in apache it doesn't work here is the code below: red= "/foodfolio3/test/" def showAddRecipe(request): #global objc if "userid" in request.session: objc["ErrorMsgURL"]= "" try: urlList= request.POST URL= str(urlList['url']) URL= URL.strip('http://') URL= "http://" + URL recipe= __addRecipeUrl__(URL) if (recipe == 'FailToOpenURL') or (recipe == 'Invalid-website-URL'): #request.session["ErrorMsgURL"]= "Kindly check URL, Please enter a valid URL" objc["ErrorMsgURL"]= "Kindly check URL, Please enter a valid URL" print "here global_context =", objc arurl= HttpResponseRedirect("/foodfolio3/add/import/") arurl['ErrorMsgURL']= objc["ErrorMsgURL"] #return HttpResponseRedirect("/foodfolio3/add/import/") #return render_to_response('addRecipeUrl.html', objc, context_instance = RequestContext(request)) return (arurl) else: objc["recipe"] = recipe return render_to_response('addRecipe.html', objc, context_instance = RequestContext(request)) except: objc["recipe"] = "" return render_to_response('addRecipe.html', objc, context_instance = RequestContext(request)) else: global red red= "/foodfolio3/add/" return HttpResponseRedirect("/foodfolio3/login") def showAddRecipeUrl(request): if "userid" in request.session: return render_to_response('addRecipeUrl.html', objc, context_instance = RequestContext(request)) else: global red red= "/foodfolio3/add/import/" return HttpResponseRedirect("/foodfolio3/login") def showLogin(request): obj = {} obj["error_message"] = "" obj["registered"] = "" if request.method == "POST": if (red == "/foodfolio3/test"): next= '/foodfolio3/recipes' else: next= red try: username = request.POST['username'] password = request.POST['password'] user = authenticate(username=username, password=password) except: user = authenticate(request=request) if user is not None: if user.is_active: login(request, user) request.session["userid"] = user.id # Redirect to a success page. return HttpResponseRedirect(next) this code works fine in django development server, but in apache, the url is getting redirected to '/foodfolio3/recipes'

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  • Apache is looking for htaccess and htpasswd files that aren't there

    - by user1094092
    Having an issue where Apache is requesting authentication, and looking for an .htpasswd file, based on instructions from an .htaccess file that's no longer in DocumentRoot. Background: In my DocumentRoot, I'd previously copied an .htaccess and .htpasswd file from another machine (along with all of the other website files). .htaccess contents: AuthType Basic AuthName "Password is required" AuthUserFile /some/directory/that/was/on/the/other/server/not/this/one/.htpasswd Require valid-user Here's the catch: I moved .htaccess and .htpasswd out of DocumentRoot and even renamed the files. There is no longer an .htaccess file in DocumentRoot at all. But, when I try to access localhost from a browser, I am prompted to enter the login and password. When I enter the login and password (from the old, not-in-DocumentRoot .hpasswd file), I get a 500 Internal Server error and the log shows: [error] [client 127.0.0.1] (2)No such file or directory: Could not open password file: /some/directory/that/was/on/the/other/server/not/this/one/.htpasswd This has been quite a puzzle, because there's no longer a .htaccess or .htpasswd file anywhere in DocumentRoot !! Have tried several apache restarts and also tried using a blank .htaccess file in the DocumentRoot. Even grepped the entire machine for references to AuthType Basic to see if I missed anything. httpd.conf looks normal enough...I can post that if needed, but this question seems long enough as it is :) Thanks for any assistance you can provide

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  • a + sing in email address

    - by d.andreykiv
    Hi. I need to submit an email address with a "+" sign and validate in on server. But server receives email like "[email protected]" as "aaa [email protected]". I send all data as POST request with following code NSURL* url = [NSURL URLWithString:[NSString stringWithFormat:@"%@%@", url, @"/signUp"]]; NSString *post = [NSString stringWithFormat:@"&email=%@&userName=%@&password=%@", user.email, user.userName, user.password]; NSData *postData = [post dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:NO]; NSData* data = [self sendRequest:url postData:postData]; post variable before encoding has value &[email protected]&userName=Asdfasdfadsfadsf&password=sdfasdf after encoding it is same &[email protected]&userName=Asdfasdfadsfadsf&password=sdfasdf Method I use to send request looks like following code: -(id) sendRequest:(NSURL*) url postData:(NSData*)postData { // Create request NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init]; NSString *postLength = [NSString stringWithFormat:@"%d",[postData length]]; [request setURL:url]; [request setHTTPMethod:@"POST"]; [request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Current-Type"]; [request setValue:postLength forHTTPHeaderField:@"Content-Length"]; [request setHTTPBody:postData]; NSURLResponse *urlResponse; NSData *data = [NSURLConnection sendSynchronousRequest:request returningResponse:&urlResponse error:nil]; [request release]; return data; }

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  • PHP Class Question

    - by Jerry
    Hi all I am trying to build a PHP class to check the username and password in MySql. I am getting "mysql_query(): supplied argument is not a valid MySQL-Link resource in D:\2010Portfolio\football\main.php on line 38" database has errors:" message. When I move my userQuery code out of my Class, it works fine. Only if it is inside my Class. I am not sure if the problem is that I don't build the connection to mysql inside my Class or not. Thanks for any helps!! Here is my code <?php $userName=$_POST['userName']; $userPw=$_POST['password']; class checkUsers { public $userName; public $userPw; function checkUsers($userName='', $userPw=''){ $this->userName=$userName; $this->userPw=$userPw; } function check1(){ if (empty($this->userName) || empty($this->userPw)){ $message="<strong>Please Enter Username and Password</strong>"; }else{ //line 38 is next line $userQuery=mysql_query("SELECT userName, userPw FROM user WHERE userName='$this->userName' and userPw='$this->userPw'", $connection); if (!$userQuery){ die("database has errors: ". mysql_error()); } if(mysql_num_rows($userQuery)==0){ $message="Please enter valid username and password"; } }//end empty check return $message; }//end check1 method }//end Class $checkUser=new checkUsers($userName, $userPw); echo $checkUser->check1(); ?> I appreciate any helps!!!!

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  • Using C# to HttpPost data to a web page

    - by druffmuff
    I want to log in into a website using C# code. Here's the html code of the example form: <form action="http://www.site.com/login.php" method="post" name="login" id="login"> <table border="0" cellpadding="2" cellspacing="0"> <tbody> <tr><td><b>User:</b></td><td colspan=\"2\"><b>Password:</b></td></tr> <tr> <td><input class="inputbg" name="user" type="text"></td> <td><input class="inputbg" name="password" type="password"></td> <td><input type="submit" name="user_control" value="Submit" class="buttonbg"></td> </tr> </tbody></table> </form> This is what I have tried so far with unsuccessful results: HttpWebRequest request = (HttpWebRequest)WebRequest.Create("http://www.site.com/login.php"); request.Method = "POST"; using (StreamWriter writer = new StreamWriter(request.GetRequestStream(), Encoding.ASCII)) { writer.Write("user=user&password=pass&user_control=Eingabe"); } HttpWebResponse response = (HttpWebResponse)request.GetResponse(); using (StreamReader reader = new StreamReader(response.GetResponseStream())) { stream = new StreamWriter("login.html"); stream.Write(reader.ReadToEnd()); stream.Close(); } Any Ideas, why this is failing?

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  • PHP -- automatic SQL injection protection?

    - by ashgromnies
    I took over maintenance of a PHP app recently and I'm not super familiar with PHP but some of the things I've been seeing on the site are making me nervous that it could be vulnerable to a SQL injection attack. For example, see how this code for logging into the administrative section works: $password = md5(HASH_SALT . $_POST['loginPass']); $query = "SELECT * FROM `administrators` WHERE `active`='1' AND `email`='{$_POST['loginEmail']}' AND `password`='{$password}'"; $userInfo = db_fetch_array(db_query($query)); if($userInfo['id']) { $_SESSION['adminLoggedIn'] = true; // user is logged in, other junk happens here, not important The creators of the site made a special db_query method and db_fetch_array method, shown here: function db_query($qstring,$print=0) { return @mysql(DB_NAME,$qstring); } function db_fetch_array($qhandle) { return @mysql_fetch_array($qhandle); } Now, this makes me think I should be able to do some sort of SQL injection attack with an email address like: ' OR 'x'='x' LIMIT 1; and some random password. When I use that on the command line, I get an administrative user back, but when I try it in the application, I get an invalid username/password error, like I should. Could there be some sort of global PHP configuration they have enabled to block these attacks? Where would that be configured? Here is the PHP --version information: # php --version PHP 5.2.12 (cli) (built: Feb 28 2010 15:59:21) Copyright (c) 1997-2009 The PHP Group Zend Engine v2.2.0, Copyright (c) 1998-2009 Zend Technologies with the ionCube PHP Loader v3.3.14, Copyright (c) 2002-2010, by ionCube Ltd., and with Zend Optimizer v3.3.9, Copyright (c) 1998-2009, by Zend Technologies

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  • SharePoint webpart with button to auto-login to 3rd party website

    - by JCdowney
    I have been tasked with creating a SharePoint 2007 webpart that logs the user directly into our website (which uses forms authentication). Most likely the username and password will be same in the SharePoint account as in our website. Ideally we would like it to be fully integrated in that the webpart looks up the SP login & password, somehow encodes that using SHA1, MD5 or similar encryption, then passes that along to our login page on the query string. However given we have little experience with SharePoint, and that it's probably impossible to programmatically access the SP username/password from a webpart we realize this isn't very likely to be possible and if so would probably require a lot of development time. Another option would be to load a login form from the website within an iframe in the webpart, which would show the login & password first but store a "remember me" cookie after the first login, and on each subsequent load display just a button that logs them in directly using the cookie. Has anyone done something similar before? I'm in over my head, any guidance would be much appreciated! :)

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  • ASP.NET MVC - ValidationSummary set from a different controller

    - by Rap
    I have a HomeController with an Index action that shows the Index.aspx view. It has a username/password login section. When the user clicks the submit button, it POSTs to a Login action in the AccountController. <% Html.BeginForm("Login", "Account", FormMethod.Post); %> In that action, it tests for Username/Password validity and if invalid, sends the user back to the Login page with a message that the credentials were bad. [HttpPost] public ActionResult Login(LoginViewModel Model, string ReturnUrl) { User user = MembershipService.ValidateUser(Model.UserName, Model.Password); if (user != null) { //Detail removed here FormsService.SignIn(user.ToString(), Model.RememberMe); return Redirect(ReturnUrl); } else { ModelState.AddModelError("", "The user name or password provided is incorrect."); } // If we got this far, something failed, redisplay form return RedirectToAction("Index", "Home"); // <-- Here is the problem. ModelState is lost. } But here's the problem: the ValidationSummary is always blank because we're losing the Model when we RedirectToAction. How do I send the user to the action on a different controller without a Redirect?

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  • Can I get the amount of time for which a key is pressed on a keyboard

    - by Adi
    Dear all, I am working on a project in which I have to develop bio-passwords based on user's keystroke style. Suppose a user types a password for 20 times, his keystrokes are recorded, like holdtime : time for which a particular key is pressed. digraph time : time it takes to press a different key. suppose a user types a password " COMPUTER". I need to know the time for which every key is pressed. something like : holdtime for the above password is C-- 200ms O-- 130ms M-- 150ms P-- 175ms U-- 320ms T-- 230ms E-- 120ms R-- 300ms The rational behind this is , every user will have a different holdtime. Say a old person is typing the password, he will take more time then a student. And it will be unique to a particular person. To do this project, I need to record the time for each key pressed. I would greatly appreciate if anyone can guide me in how to get these times. Editing from here.. Language is not important, but I would prefer it in C. I am more interested in getting the dataset.

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  • Using CookieJar in Python to log in to a website from "Google App Engine". What's wrong here?

    - by brilliant
    Hello everybody, I've been trying to find a python code that would log in to my mail box on yahoo.com from "Google App Engine" . Here (click here to see that page) I was given this code: import urllib, urllib2, cookielib url = "https://login.yahoo.com/config/login?" form_data = {'login' : 'my-login-here', 'passwd' : 'my-password-here'} jar = cookielib.CookieJar() opener = urllib2.build_opener(urllib2.HTTPCookieProcessor(jar)) form_data = urllib.urlencode(form_data) # data returned from this pages contains redirection resp = opener.open(url, form_data) # yahoo redirects to http://my.yahoo.com, so lets go there instead resp = opener.open('http://mail.yahoo.com') print resp.read() The author of this script looked into HTML script of yahoo log-in form and came up with this script. That log-in form contains two fields, one for users' Yahoo! ID and another one is for users' password. Here is how HTML code of that page for both of those fields looks like: User ID field: <input type="text" maxlength="96" class="yreg_ipt" size="17" value="" id="username" name="login"> Password field: <input type="password" maxlength="64" class="yreg_ipt" size="17" value="" id="passwd" name="passwd"> However, when I uploaded this code to Google App Engine I discovered that this log-in form keeps coming back to me, which, I assume, means that logging-in process didn't succeed. Why is it so?

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  • Using CookieJar in Python to log in to a website from "Google App Engine". What's wrong here?

    - by brilliant
    Hello everybody, I've been trying to find a python code that would log in to my mail box on yahoo.com from "Google App Engine" . Here (click here to see that page) I was given this code: import urllib, urllib2, cookielib url = "https://login.yahoo.com/config/login?" form_data = {'login' : 'my-login-here', 'passwd' : 'my-password-here'} jar = cookielib.CookieJar() opener = urllib2.build_opener(urllib2.HTTPCookieProcessor(jar)) form_data = urllib.urlencode(form_data) # data returned from this pages contains redirection resp = opener.open(url, form_data) # yahoo redirects to http://my.yahoo.com, so lets go there instead resp = opener.open('http://mail.yahoo.com') print resp.read() The author of this script looked into HTML script of yahoo log-in form and came up with this script. That log-in form contains two fields, one for users' Yahoo! ID and another one is for users' password. Here is how HTML code of that page for both of those fields looks like: User ID field: <input type="text" maxlength="96" class="yreg_ipt" size="17" value="" id="username" name="login"> Password field: <input type="password" maxlength="64" class="yreg_ipt" size="17" value="" id="passwd" name="passwd"> However, when I uploaded this code to Google App Engine I discovered that this log-in form keeps coming back to me, which, I assume, means that logging-in process didn't succeed. Why is it so?

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  • Android Dev: The constructor Intent(new View.OnClickListener(){}, Class<DrinksTwitter>) is undefined

    - by Malcolm Woods Spark
    package com.android.drinksonme; import android.app.Activity; import android.content.Intent; import android.os.Bundle; import android.view.View; import android.view.View.OnClickListener; import android.widget.Button; import android.widget.EditText; import android.widget.TextView; public class Screen2 extends Activity { // Declare our Views, so we can access them later private EditText etUsername; private EditText etPassword; private Button btnLogin; private Button btnSignUp; private TextView lblResult; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); // Get the EditText and Button References etUsername = (EditText)findViewById(R.id.username); etPassword = (EditText)findViewById(R.id.password); btnLogin = (Button)findViewById(R.id.login_button); btnSignUp = (Button)findViewById(R.id.signup_button); lblResult = (TextView)findViewById(R.id.result); // Set Click Listener btnLogin.setOnClickListener(new OnClickListener() { @Override public void onClick(View v) { // Check Login String username = etUsername.getText().toString(); String password = etPassword.getText().toString(); if(username.equals("test") && password.equals("test")){ final Intent i = new Intent(this, DrinksTwitter.class); //error on this line startActivity(i); // lblResult.setText("Login successful."); } else { lblResult.setText("Invalid username or password."); } } }); final Intent k = new Intent(Screen2.this, SignUp.class); btnSignUp.setOnClickListener(new OnClickListener() { public void onClick(View v) { startActivity(k); } }); } }

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  • Problem in getting response from server in jquery

    - by Alvin
    Hello, I'm using $.ajax(options) method to pass the request to server based on username and password, but whenever I try to print the response by XMLHttpRequest object when response gets successful, I'm getting an empty value. $(document).ready(function(){ $("#form").submit(function(){ $.ajax({url:"Chat.jsp",type:"POST",data:$("#form").serialize(),success:function(request) { alert(request.responseText); //This is displaying nothing },error:function(){document.write("YOU can't");}}); }); }); This is what I'm doing in my servlets code after executing query: try { String user = request.getParameter("j_username"); String password = request.getParameter("j_password"); if(user != null && password != null) { String query = "Select * from users where user_name="+"\'"+user+"\'"+"&& user_pass="+"\""+password+"\""; DBCheck db= new DBCheck(); boolean b = db.doExecuteQuery(con.createStatement(),query); response.setHeader("Cache-Control", "no-cache"); if(b) { response.getWriter().println("Username already exits"); } else { response.getWriter().println("Username doesn't exit"); } } } catch(SQLException ex) { ex.printStackTrace(); } } May I know the problem, and how can I fix it?

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  • Firefox proxy dilemma

    - by Mike L.
    Any idea why when using system proxy settings in firefox, it can not accept a proxy such as: user:[email protected]:port ??? IE will allow and connect to a proxy in this format. Not only does firefox not work, but it does not prompt for the password, nor attempt to make a connection to the proxy. Basically get a "proxy server not found" error. Anybody know a way around this? I am working on a proxy switching program for IE & Firefox, and I would like to use system-wide proxy settings. If I just store the server:port combination, firefox prompts for the password, as well as IE. Then they can be cached and it will not ask again. Maybe my only option is to programmatically cache the user/pass? Anybody know a way to do this? I am pretty sure IE stores them at HTTP basic authentication passwords and I can add them with AddCredential. After saving a password for a proxy in firefox, it shows up in saved passwords in a format like "moz-proxy://server:port" anybody know how to programmatically add a saved password to firefox? Thanks

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  • Sorcery/Capybara: Cannon log in with :js => true

    - by PlankTon
    I've been using capybara for a while, but I'm new to sorcery. I have a very odd problem whereby if I run the specs without Capybara's :js = true functionality I can log in fine, but if I try to specify :js = true on a spec, username/password cannot be found. Here's the authentication macro: module AuthenticationMacros def sign_in user = FactoryGirl.create(:user) user.activate! visit new_sessions_path fill_in 'Email Address', :with => user.email fill_in 'Password', :with => 'foobar' click_button 'Sign In' user end end Which is called in specs like this: feature "project setup" do include AuthenticationMacros background do sign_in end scenario "creating a project" do "my spec here" end The above code works fine. However, IF I change the scenario spec from (in this case) scenario "adding questions to a project" do to scenario "adding questions to a project", :js => true do login fails with an 'incorrect username/password' combination. Literally the only change is that :js = true. I'm using the default capybara javascript driver. (Loads up Firefox) Any ideas what could be going on here? I'm completely stumped. I'm using Capybara 2.0.1, Sorcery 0.7.13. There is no javascript on the sign in page and save_and_open_page before clicking 'sign in' confirms that the correct details are entered into the username/password fields. Any suggestions really appreciated - I'm at a loss.

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  • How can I spec out an authlogic sessions controller using using a stub?

    - by Dave
    I want to test my User Session Controller testing that a user session is first built then saved. My UserSession class looks like this: class UserSession < Authlogic::Session::Base end The create method of my UserSessionsController looks like this: def create @user_session = UserSession.new(params[:user_session]) if @user_session.save flash[:notice] = "Successfully logged in." redirect_back_or_default administer_home_page_url else render :new end end and my controller spec looks like this: describe UserSessionsController do it "should build a new user session" do UserSession.stub!(:new).with(:email, :password) UserSession.should_receive(:new).with(:email => "[email protected]", :password => "foobar") post :create, :user_session => { :email => "[email protected]", :password => "foobar" } end end I stub out the new method but I still get the following error when I run the test: Spec::Mocks::MockExpectationError in 'UserSessionsController should build a new user session' <UserSession (class)> received :new with unexpected arguments expected: ({:password=>"foobar", :email=>"[email protected]"}) got: ({:priority_record=>nil}, nil) It's although the new method is being called on UserSession before my controller code is getting called. Calling activate_authlogic makes no difference.

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  • Make Trac use a Drupal user database for authentication

    - by denisw
    I am trying to set up a Trac instance as a complement to a Drupal site and would like to give users the possibility to use their Drupal account in Trac, too, ideally in a single sign-on fashion (if the user is already logged into Drupal, he is automatically logged into Trac). The question now is how to accomplish this. I have found a plugin named DrupalIntegration which seems to implement that functionality; however, it is poorly documented - in fact, not documented at all. I managed to install it, but don't know how to configure it. Here is what I came up with from looking at the source code and the documentation of the AccountManager plugin (on which DrupalIntegration depends): [components] trac.web.auth.loginmodule = disabled acct_mgr.api = enabled acct_mgr.web_ui.LoginModule = enabled acct_mgr.web_ui.RegistrationModule = disabled TracDrupalIntegration.DrupalIntegration = enabled [account-manager] drupal_database = mysql://<usernam>:<password>@localhost/<db> password_store = DrupalIntegration (<username>, <password> and <db> are naturally substituted with the correct data). While the Trac log says: 2010-12-18 10:54:09,570 Trac[loader] DEBUG: Loading TracDrupalIntegration from /usr/lib/python2.5/site-packages/TracDrupalIntegration-0.1-py2.5.egg this doesn't seem to work: trying to log in with a Drupal username / password results in an "Invalid username or password" error. Has someone used the DrupalIntegration and can point out to me what I did wrong? Or is there any other approach you know (or even have used in the past) to integrate Drupal and Trac that way?

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  • Firefox proxy delima

    - by Mike L.
    Any idea why when using system proxy settings in firefox, it can not accept a proxy such as: user:[email protected]:port ??? IE will allow and connect to a proxy in this format. Not only does firefox not work, but it does not prompt for the password, nor attempt to make a connection to the proxy. Basically get a "proxy server not found" error. Anybody know a way around this? I am working on a proxy switching program for IE & Firefox, and I would like to use system-wide proxy settings. If I just store the server:port combination, firefox prompts for the password, as well as IE. Then they can be cached and it will not ask again. Maybe my only option is to programmatically cache the user/pass? Anybody know a way to do this? I am pretty sure IE stores them at HTTP basic authentication passwords and I can add them with AddCredential. After saving a password for a proxy in firefox, it shows up in saved passwords in a format like "moz-proxy://server:port" anybody know how to programmatically add a saved password to firefox? Thanks

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  • MongoDB C# - Hide property from serializer

    - by ehftwelve
    This is what my user model looks like: namespace Api.Models { public class User { [BsonId(IdGenerator = typeof(StringObjectIdGenerator))] [BsonRequired] public string Id { get; set; } [Required(ErrorMessage = "Username is required.")] [StringLength(20, MinimumLength=3, ErrorMessage="Username must be between 3 and 20 characters.")] [BsonRequired] public string Username { get; set; } [Required(ErrorMessage="Email is required.")] [EmailAddress(ErrorMessage="Valid email required.")] [BsonRequired] public string Email { get; set; } [Required(ErrorMessage = "Password is required.")] [StringLength(50, MinimumLength=8, ErrorMessage="Password must be between 8 and 50 characters.")] [BsonRequired] public string Password { get; set; } [BsonRequired] public string Salt { get; set; } } } I want to write, and require, all of the properties into the MongoDB Database. What I don't want to do, is expose the Password and Salt properties when I send this through the request. Is there any sort of data attribute that I can set that will write it, but not expose it when displayed to any API user?

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  • Remote connection to SQL Server Express fails

    - by worlds-apart89
    I have two computers that share the same Internet IP address. Using one of the computers, I can remotely connect to a SQL Server database on the other. Here is my connection string: SqlConnection connection = new SqlConnection(@"Data Source=192.168.1.101\SQLEXPRESSNI,1433;Network Library=DBMSSOCN;Initial Catalog=FirstDB;Persist Security Info=True;User ID=username;Password=password;"); 192.168.1.101 is the server, SQLEXPRESSNI is the SQL Server instance name, and FirstDB is the name of the database. Now, I have another computer with a different Internet IP address. I want to connect to the server above using the third computer that does not belong to my local area network. I dont have access to that third computer at the moment, so I want to use (if possible) the client computer in LAN again. SqlConnection connection = new SqlConnection(@"Data Source=SharedInternetIP\SQLEXPRESSNI,1433;Network Library=DBMSSOCN;Initial Catalog=FirstDB;Persist Security Info=True;User ID=username;Password=password;"); Does not work Note that I am a beginner, so I am not quite sure what I am doing even though I know what I want to do. By passing the Internet IP to the SqlConnection object rather than the local IP address, how can I successfully connect to the server computer, using the client computer in the same network? Also note that my ultimate goal is to connect to the server with an external client, but I don't have access to that computer right now. I'd appreciate any help.

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  • Java reading xml element without prefix but within the scope of a namespace

    - by wsxedc
    Functionally, the two blocks should be the same <soapenv:Body> <ns1:login xmlns:ns1="urn:soap.sof.com"> <userInfo> <username>superuser</username> <password>qapass</password> </userInfo> </ns1:login> </soapenv:Body> ----------------------- <soapenv:Body> <ns1:login xmlns:ns1="urn:soap.sof.com"> <ns1:userInfo> <ns1:username>superuser</ns1:username> <ns1:password>qapass</ns1:password> </ns1:userInfo> </ns1:login> </soapenv:Body> However, how when I read using AXIS2 and I have tested it with java6 as well, I am having a problem. MessageFactory factory = MessageFactory.newInstance(); SOAPMessage soapMsg = factory.createMessage(new MimeHeaders(), SimpleTest.class.getResourceAsStream("LoginSoap.xml")); SOAPBody body = soapMsg.getSOAPBody(); NodeList nodeList = body.getElementsByTagNameNS("urn:soap.sof.com", "login"); System.out.println("Try to get login element" + nodeList.getLength()); // I can get the login element Node item = nodeList.item(0); NodeList elementsByTagNameNS = ((Element)item).getElementsByTagNameNS("urn:soap.sof.com", "username"); System.out.println("try to get username element " + elementsByTagNameNS.getLength()); So if I replace the 2nd getElementsByTagNameNS with ((Element)item).getElementsByTagName("username");, I am able to get the username element. Doesn't username have ns1 namespace even though it doesn't have the prefix? Am I suppose to keep track of the namespace scope to read an element? Wouldn't it became nasty if my xml elements are many level deep? Is there a workaround where I can read the element in ns1 namespace without knowing whether a prefix is defined?

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  • Alternative for table mark-up in ASP.NET not working properly

    - by yetanothercoder
    Using Visual WebDeveloper 2010 Express and ASP.NET 4.0 Don't know whether its relevant but the whole thing is in a ContentPlaceHolder and inside an UpdatePanel. To avoid using the old table tr td model, I have created a simple form like this <div class="admin-form"> <asp:Label ID="UserNameLabel" runat="server" CssClass="form-label" Text="User Name" /> <asp:TextBox ID="UserNameText" runat="server" Width="200px"/> <br /> <asp:Label ID="PasswordLabel" runat="server" CssClass="form-label" Text="Password" /> <asp:TextBox ID="PasswordText" runat="server" TextMode="Password" Width="200px"/> <br /> <asp:Label ID="ConfirmPasswordLabel" runat="server" CssClass="form-label" Text="Confirm Password" /> <asp:TextBox ID="ConfirmPasswordText" runat="server" TextMode="Password" Width="200px"/> <br /> <asp:Label ID="EmailLabel" runat="server" CssClass="form-label" Text="Email" /> <asp:TextBox ID="EmailText" runat="server" Width="200px"/> <br /> <br /> <br /> <span class="form-label"></span> <asp:Button ID="CreateUserButton" runat="server" CssClass="button blue" Text="Create New User"/> </div> And the CSS .form-label { width: 300px !important; } This renders incorrectly as I would like to have all textboxes vertically lined after taking 300px. What is wrong? P.S: I cannot use HTML Controls like label as I have resx for globalization

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  • Laravel - Mail class Exception

    - by Christian Giupponi
    I need to send email within my app and this is my code: if( $agent->save() ) { //Preparo la mail da inviare con i dati di login $data = [ 'nome' => $input['nome'], 'cognome' => $input['cognome'], 'email' => $input['email'], 'password' => $input['password'] ]; //ATTENZIONE //Questo è da rimuovere in produzione, finge di inviare la mail Mail::pretend(); //Recuero il template e passo alla funzione i dati Mail::send('emails.agents.registration', $data, function($message) use ($data) { $message->to( $data['email'], $data['nome'].' '.$data['cognome'] )->subject('Benvenuto!'); }); return Redirect::action('admin.agents.index')->with('positive_flash_message', 'Agente inserito correttamente.'); } As you can see I have use the Mail::pretend to avoid the email send in development, the problem is that I get this error every time I try to send an email: Undefined property: Illuminate\Mail\Message::$email (View: /var/www/progetti/app/views/emails/agents/registration.blade.php) nd this is my blade view: Email: {{ $message->email }} Password: {{ $message->password }} What's wrong with $message?

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  • shell script stopped working --- need to rewrite?

    - by OopsForgotMyOtherUserName
    The script below worked on my Mac OS X. I'm now using Ubuntu OS, and the script is no longer working. I'm wondering if there's something that I need to change here? I did change the first line from #!/bin/bash to #!/bin/sh, but it's still throwing up an error.... Essentially, I get an error when I try to run it: Syntax error: end of file unexpected (expecting ")") #!/bin/sh REMOTE='ftp.example.com' USER='USERNAME' PASSWORD='PASSWORD' CMDFILE='/jtmp/rc.ftp' FTPLOG='/jtmp/ftplog' PATTERN='SampFile*' date > $FTPLOG rm $CMDFILE 2>/dev/null LISTING=$(ftp -in $REMOTE <<EOF user $USER $PASSWORD cd download ls $PATTERN quit EOF ) echo "open $REMOTE" >> $CMDFILE echo "user $USER $PASSWORD" >> $CMDFILE echo "verbose" >> $CMDFILE echo "bin" >> $CMDFILE echo "cd download" >> $CMDFILE for FILE in $LISTING do echo "get $FILE" >> $CMDFILE done echo "quit" >> $CMDFILE ftp -in < $CMDFILE >> $FTPLOG 2>&1 rm $CMDFILE

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