Search Results

Search found 50475 results on 2019 pages for 'rpc over http'.

Page 132/2019 | < Previous Page | 128 129 130 131 132 133 134 135 136 137 138 139  | Next Page >

  • HTTP download not working on Rails 3

    - by Test Test
    I have this in my Rails controller: def download_clip send_file "public/output.mp4", :type=>"video/mp4", :filename => "output.mp4", :disposition => 'attachment' end and in my HTML code I have this: <a href="download_clip/"></a> Now could somebody tell me why Firefox's download window will NOT pou up, but chrome downloads the file fine? Instead firefox opens a new window and starts playing the file. I WANT THE DOWNLOAD BOX to POPUP. I have spend too much time on it

    Read the article

  • Lubuntu 13.04, kernel still 3.8.0-32-generic

    - by Blue Ice
    My question is very similar to Ubuntu 13.10, kernel still 3.8.0-31-generic. Recently was updating to Saucy and the ethernet cable got unplugged. So I decided to run Software Update again, to reinstall files. It returned that "everything is up to date". But according to these command-line searches, that is incorrect. How can I install Saucy now safely from the command line? sudo apt-get install lubuntu-desktop Reading package lists... Done Building dependency tree Reading state information... Done lubuntu-desktop is already the newest version. The following package was automatically installed and is no longer required: linux-image-extra-3.8.0-19-generic Use 'apt-get autoremove' to remove it. 0 upgraded, 0 newly installed, 0 to remove and 0 not upgraded. sudo apt-get dist-upgrade Reading package lists... Done Building dependency tree Reading state information... Done Calculating upgrade... Done 0 upgraded, 0 newly installed, 0 to remove and 0 not upgraded. sudo apt-get update Get:1 http://extras.ubuntu.com raring Release.gpg [72 B] Hit http://extras.ubuntu.com raring Release Get:2 http://az-1.hpcloud.mirror.websitedevops.com raring Release.gpg Hit http://extras.ubuntu.com raring/main Sources Hit http://extras.ubuntu.com raring/main i386 Packages Get:3 http://az-1.hpcloud.mirror.websitedevops.com raring-updates Release.gpg Get:4 http://az-1.hpcloud.mirror.websitedevops.com raring-backports Release.gpg Get:5 http://az-1.hpcloud.mirror.websitedevops.com raring-security Release.gpg Get:6 http://az-1.hpcloud.mirror.websitedevops.com raring Release Ign http://extras.ubuntu.com raring/main Translation-en_US Ign http://extras.ubuntu.com raring/main Translation-en Hit http://ppa.launchpad.net raring Release.gpg Ign http://az-1.hpcloud.mirror.websitedevops.com raring Release E: GPG error: http://az-1.hpcloud.mirror.websitedevops.com raring Release: The following signatures were invalid: NODATA 1 NODATA 2 lsb_release -rd Description: Ubuntu 13.04 Release: 13.04 uname -r 3.8.0-32-generic

    Read the article

  • Help with chat server

    - by mithun1538
    I am designing a chat server in java. The communication is Http based and not socket based. In the client side I have an applet. In the server side I have a servlet. Applet: I create a new thread to listen for incoming messages(GET method). The main thread is used to send messages(POST messages). The partial code is : public void start() { System.out.println("Creating new thread"); Thread thread = new Thread(this); thread.start(); } private String getNewMessage() { System.out.println("Inside getNewMessage"); String msg = null; try { while(msg == null) { System.out.println("Trying to listen to servlet"); URL servlet = new URL(getCodeBase(), "NewServlet?mode=msg"); URLConnection con = servlet.openConnection(); con.setUseCaches(false); DataInputStream din = new DataInputStream(new BufferedInputStream(con.getInputStream())); msg = din.readUTF(); System.out.println("message read :" + msg); } } catch (Exception e) { e.printStackTrace(); } return msg + "\n"; } public void run() { System.out.println("Inside new thread"); while(true) { System.out.println("inside first while"); String newMsg = getNewMessage(); chatOutput.append(newMsg); System.out.println("Appended!!"); } } private void jButton1ActionPerformed(java.awt.event.ActionEvent evt) { String message = chatInput.getText(); chatInput.setText(""); chatOutput.append(message + "\n"); try { System.out.println("Trying to send msg :" + message); URL url = new URL(getCodeBase(), "NewServlet"); URLConnection servletConnection = url.openConnection(); servletConnection.setDoInput(true); servletConnection.setDoOutput(true); servletConnection.setUseCaches(false); servletConnection.setRequestProperty("Content-Type", "application/octet-stream"); ObjectOutputStream out = new ObjectOutputStream(servletConnection.getOutputStream()); out.writeObject(message); out.flush(); out.close(); System.out.println("Message sent!"); } catch (Exception e) { e.printStackTrace(); } } This next code is from the servlet side. it uses the Observable interface to identify and send messages to clients. public class NewServlet extends HttpServlet { // getNextMessage() returns the next new message. // It blocks until there is one. public String getNextMessage() { // Create a message sink to wait for a new message from the // message source. System.out.println("inside getNextMessage"); return new MessageSink().getNextMessage(source);} @Override protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { System.out.println("Inside Doget"); response.setContentType("text/plain"); PrintWriter out = response.getWriter(); out.println(getNextMessage()); } // broadcastMessage() informs all currently listening clients that there // is a new message. Causes all calls to getNextMessage() to unblock. public void broadcastMessage(String message) { // Send the message to all the HTTP-connected clients by giving the // message to the message source source.sendMessage(message); } @Override protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { System.out.println("Inside DoPost"); try { ObjectInputStream din= new ObjectInputStream(request.getInputStream()); String message = (String)din.readObject(); System.out.println("received msg"); if (message != null) broadcastMessage(message); System.out.println("Called broadcast"); // Set the status code to indicate there will be no response response.setStatus(response.SC_NO_CONTENT); } catch (Exception e) { e.printStackTrace(); } } /** * Returns a short description of the servlet. * @return a String containing servlet description */ @Override public String getServletInfo() { return "Short description"; } MessageSource source = new MessageSource();} class MessageSource extends Observable { public void sendMessage(String message) { System.out.println("inside sendMsg"); setChanged(); notifyObservers(message); } } class MessageSink implements Observer { String message = null; // set by update() and read by getNextMessage() // Called by the message source when it gets a new message synchronized public void update(Observable o, Object arg) { // Get the new message message = (String)arg; // Wake up our waiting thread notify(); } // Gets the next message sent out from the message source synchronized public String getNextMessage(MessageSource source) { // Tell source we want to be told about new messages source.addObserver(this); System.out.println("AddedObserver"); // Wait until our update() method receives a message while (message == null) { try { wait(); } catch (Exception ignored) { } } // Tell source to stop telling us about new messages source.deleteObserver(this); // Now return the message we received // But first set the message instance variable to null // so update() and getNextMessage() can be called again. String messageCopy = message; message = null; System.out.println("Returning msg"); return messageCopy; } } As you can see I have included System.out.println("Some message"); in some places. this was just for debugging purposes. In java console, i get the following output: Creating new thread Inside new thread. inside first while. Inside getNewMessage. Trying to listen to servlet. In the servlet side, i get the following output in the tomcat logs: Inside Doget. inside getNextMessage. AddedObserver. After i type a message in the applet, and send it, I get the foll output in java console: Trying to send msg :you deR?? Message sent! But in servlet side, I dont get anything in the logs. I used the O'Reily Java Servlet Programming as reference(The observer interface comes from there). But I am not getting any chat communication between two clients. As can be understood from the logs, the POST method is not called. Any reason for this?

    Read the article

  • org.apache.commons.httpclient.HttpClient stuck on request

    - by Roman
    Hi All I have that code : while(!lastPage && currentPage < maxPageSize){ StringBuilder request = new StringBuilder("http://catalog.bizrate.com/services/catalog/v1/us/" + " some more ..."); currentPage++; HttpClient client = new HttpClient(new MultiThreadedHttpConnectionManager()); client.getHttpConnectionManager().getParams().setConnectionTimeout(15000); GetMethod get = new GetMethod(request.toString()); HostConfiguration configuration = new HostConfiguration(); int iGetResultCode = client.executeMethod(configuration, get); if (iGetResultCode != HttpStatus.SC_OK) { System.err.println("Method failed: " + get.getStatusLine()); return; } XMLStreamReader reader = XMLInputFactory.newInstance().createXMLStreamReader(get.getResponseBodyAsStream()); while (reader.hasNext()) { int type = reader.next(); // some more xml parsing ... } reader.close(); get.releaseConnection(); } Somehow the code gets suck from time to time on line : executing request. I cant find the configuration for a request time out (not the connection timeout) , can someone help me maybe , or is there something that I am doing basely wrong ? The client I am using.

    Read the article

  • Why would Basic Auth not work with my WCF client to Java SOAP Web Service?

    - by orj
    I have a Java based web service that requires basic authentication to communicate with it. If I type the WSDL url into my browser I'm prompted for Basic Auth. Which I can get by entering the correct credentials. However using my WCF client doesn't work. I construct my WCF client like this: var binding = new BasicHttpBinding { MaxReceivedMessageSize = 2048 * 10240, Security = { Mode = BasicHttpSecurityMode.TransportCredentialOnly, Transport = { ClientCredentialType = HttpClientCredentialType.Basic, Realm = "MYREALM", ProxyCredentialType = HttpProxyCredentialType.None }, Message = { ClientCredentialType = BasicHttpMessageCredentialType.UserName, AlgorithmSuite = SecurityAlgorithmSuite.Default } } }; var client = new WebServiceClient(binding, endpoint); client.ClientCredentials.UserName.UserName = username; client.ClientCredentials.UserName.Password = password; client.DoWebServiceMethod(); I get the following exception. System.Net.WebException: The remote server returned an error: (401) Unauthorized. at System.Net.HttpWebRequest.GetResponse() at System.ServiceModel.Channels.HttpChannelFactory.HttpRequestChannel.HttpChannelRequest.WaitForReply(TimeSpan timeout) System.ServiceModel.Security.MessageSecurityException: The HTTP request is unauthorized with client authentication scheme 'Basic'. The authentication header received from the server was 'Basic realm="MYREALM"'. From what I can tell I'm doing things right. Where am I going wrong?

    Read the article

  • Android HttpPost: how to get the result

    - by Sumit M Asok
    I have been trying long to send an HttpPost request and retrieve response but even though I was able to make a connection I don't yet get how to get the string message which is returned by the request-response HttpClient httpclient = new DefaultHttpClient(); HttpPost httppost = new HttpPost("http://www.myurl.com/app/page.php"); // Add your data List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(5); nameValuePairs.add(new BasicNameValuePair("type", "20")); nameValuePairs.add(new BasicNameValuePair("mob", "919895865899")); nameValuePairs.add(new BasicNameValuePair("pack", "0")); nameValuePairs.add(new BasicNameValuePair("exchk", "1")); try { httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs)); Log.d("myapp", "works till here. 2"); try { HttpResponse response = httpclient.execute(httppost); Log.d("myapp", "response " + response.getEntity()); } catch (ClientProtocolException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } } catch (UnsupportedEncodingException e) { e.printStackTrace(); } I'm sorry, I sound very naive because I'm new to java. Please help me.

    Read the article

  • Retrieve Flash file post in ASP.NET

    - by Quandary
    Question: In ASP.NET, I retrieve a JPEG-file as Flash post data like this Sub ProcessRequest(ByVal context As HttpContext) Implements IHttpHandler.ProcessRequest context.Response.ContentType = "text/plain" ' Retrieve a bytearray from the post buffer Dim myBuffer As Byte() = context.Request.BinaryRead(Convert.ToInt32(context.Request.InputStream.Length)) System.IO.File.WriteAllBytes("c:\temp\test.jpg", myBuffer) End Sub In Flash, I send it to an asp.net handler like this var jpgSource:BitmapData = cPrint.TakeSnapshot(MovieClip(cGlobals.ccPlanZoomView)); var bmpThisBitmap:Bitmap = new Bitmap(jpgSource); var nQuality:Number = 100; var jpgEncoder:JPGEncoder = new JPGEncoder(nQuality); var jpgStream:ByteArray = jpgEncoder.encode(jpgSource); var header:URLRequestHeader = new URLRequestHeader ("Content-type", "application/octet-stream"); // Make sure to use the correct path to jpg_encoder_download.php var strFileName:String="test.jpg"; var jpgURLRequest:URLRequest = new URLRequest("http://localhost/raumplaner_new/raumplaner_new/cgi-bin/SavePDF.ashx"); //var scriptVars:URLVariables = new URLVariables(); //scriptVars.fn = strFileName; //var myarr:Array= new Array(); //myarr.push(jpgStream); //scriptVars.Files = myarr; jpgURLRequest.requestHeaders.push(header); jpgURLRequest.method = URLRequestMethod.POST; //jpgURLRequest.data = scriptVars; jpgURLRequest.data = jpgStream; var loader:URLLoader = new URLLoader(); loader.dataFormat = URLLoaderDataFormat.BINARY; loader.load(jpgURLRequest); It works but I want to send a few additional variables along, via scriptVars (commented out here). How do I retrieve the JPEG file in that case ? Because if I use parameters, there is no more BinaryRead... Aspecially, how would I read an array of jpeg files (several files) ?

    Read the article

  • How To Disable Curl Debug Output in PHP

    - by streetparade
    I wrote a PHP CUrl Class, if i execute Methods which should return the Content, it returns at first the Headers and after that the Content. So i cant parse any XML Data. I need to Disable This Sample Output. HTTP/1.1 200 OK Date: Thu, 01 Apr 2010 20:11:58 GMT Server: Apache/2.2.9 (Debian) PHP/5.2.6-1+lenny4 with Suhosin-Patch mod_ssl/2.2.9 OpenSSL/0.9.8g X-Powered-By: PHP/5.2.6-1+lenny4 Set-Cookie: PHPSESSID=44beccf62f87546140d4a0bd24bd28b0; path=/ Expires: Thu, 19 Nov 1981 08:52:00 GMT Cache-Control: no-store, no-cache, must-revalidate, post-check=0, pre-check=0 Pragma: no-cache Transfer-Encoding: chunked Content-Type: application/xml Here is The Curl Class <?php class Test_Curl { protected $curl; protected $headers; protected $useragent; protected $url; protected $testkey; public function __construct() { } public function setUseraget($useragent) { $this->useragent = $useragent; return $this; } public function setApiKey($key) { $this->billomatApiKey = $key; } private function curlExecGeneral() { $result = curl_exec($this->curl); curl_close($this->curl); return $result; } private function curlInitGeneral($request) { $this->curl = curl_init($request); curl_setopt($this->curl, CURLOPT_HEADER, true); curl_setopt($this->curl, CURLOPT_HTTPHEADER, array("X-testkey: ".$this->testkey, "Content-Type: application/xml")); curl_setopt($this->curl, CURLOPT_RETURNTRANSFER, true); } public function get($request) { $this->curlInitGeneral($request); curl_setopt ($this->curl, CURLOPT_HTTPGET, true); return $this->curlExecGeneral(); } public function post($request, $xml) { $this->curlInitGeneral($request); curl_setopt ($this->curl, CURLOPT_POST, true); //set the Requestmethod to POST curl_setopt ($this->curl, CURLOPT_POSTFIELDS, $xml); //add the xml data to the Request return $this->curlExecGeneral(); } } ?>

    Read the article

  • What is wrong with my Basic Authentication in my Browser?

    - by Pure.Krome
    Hi folks, i'm trying to goto the following url :- http://user1:pass1@localhost:1234/api/users?format=xml nothing to complex. Notice how i've got the username/password in the url? this, i believe, is for basic authentication. When I do that, the Request Headers are MISSING the 'Authorize' header. Er... that's not right :( I have anonymous authentication only setup on the site. I don't want to have anon off and basic turned on .. because not all of the site requires basic.. only a few action methods. So .. why is this not working? Is this something to do with the fact my code is not sending a 401 challenge or some crap? For What It's Worth, my site is ASP.NET MVC1 running on IIS7 (and the same thing happens when i run it on cassini). Update: If this is an illegal way of calling a resource using basic auth (ala security flaw) .. then is this possible to do, for an ASP.NET MVC website .. per action method (and not the entire site, per say)?

    Read the article

  • silverlight 3: long running wcf call triggers 401.1 (access denied)

    - by sympatric greg
    I have a wcf service consumed by a silverlight 3 control. The Silverlight client uses a basicHttpBindinging that is constructed at runtime from the control's initialization parameters like this: public static T GetServiceClient<T>(string serviceURL) { BasicHttpBinding binding = new BasicHttpBinding(Application.Current.Host.Source.Scheme.Equals("https", StringComparison.InvariantCultureIgnoreCase) ? BasicHttpSecurityMode.Transport : BasicHttpSecurityMode.None); binding.MaxReceivedMessageSize = int.MaxValue; binding.MaxBufferSize = int.MaxValue; binding.Security.Mode = BasicHttpSecurityMode.TransportCredentialOnly; return (T)Activator.CreateInstance(typeof(T), new object[] { binding, new EndpointAddress(serviceURL)}); } The Service implements windows security. Calls were returning as expected until the result set increased to several thousand rows at which time HTTP 401.1 errors were received. The Service's HttpBinding defines closeTime, openTimeout, receiveTimeout and sendTimeOut of 10 minutes. If I limit the size of the resultset the call suceeds. Additional Observations from Fiddler: When Method2 is modified to return a smaller resultset (and avoid the problem), control initialization consists of 4 calls: Service1/Method1 -- result:401 Service1/Method1 -- result:401 (this time header includes element "Authorization: Negotiate TlRMTV..." Service1/Method1 -- result:200 Service1/Method2 -- result:200 (1.25 seconds) When Method2 is configured to return the larger resultset we get: Service1/Method1 -- result:401 Service1/Method1 -- result:401 (this time header includes element "Authorization: Negotiate TlRMTV..." Service1/Method1 -- result:200 Service1/Method2 -- result:401.1 (7.5 seconds) Service1/Method2 -- result:401.1 (15ms) Service1/Method2 -- result:401.1 (7.5 seconds)

    Read the article

  • Android: Unable to make httprequest behind firewall

    - by Yang
    The standard getUrlContent works welll when there is no firewall. But I got exceptions when I try to do it behind a firewall. I've tried to set "http proxy server" in AVD manager, but it didn't work. Any idea how to correctly set it up? protected static synchronized String getUrlContent(String url) throws ApiException { if(url.equals("try")){ return "thanks"; } if (sUserAgent == null) { throw new ApiException("User-Agent string must be prepared"); } // Create client and set our specific user-agent string HttpClient client = new DefaultHttpClient(); HttpGet request = new HttpGet(url); request.setHeader("User-Agent", sUserAgent); try { HttpResponse response = client.execute(request); // Check if server response is valid StatusLine status = response.getStatusLine(); if (status.getStatusCode() != HTTP_STATUS_OK) { throw new ApiException("Invalid response from server: " + status.toString()); } // Pull content stream from response HttpEntity entity = response.getEntity(); InputStream inputStream = entity.getContent(); ByteArrayOutputStream content = new ByteArrayOutputStream(); // Read response into a buffered stream int readBytes = 0; while ((readBytes = inputStream.read(sBuffer)) != -1) { content.write(sBuffer, 0, readBytes); } // Return result from buffered stream return new String(content.toByteArray()); } catch (IOException e) { throw new ApiException("Problem communicating with API", e); } }

    Read the article

  • How do I force or add the content length for ajax type POST requests in Firefox?

    - by Jayson
    I'm trying to POST a http request using ajax, but getting a response from the apache server using modsec_audit that: "POST request must have a Content-Length header." I do not want to disable this in modsec_audit. This occurs only in firefox, and not IE. Further, I switched to using a POST rather than a GET to keep IE from caching my results. This is a simplified version of the code I'm using for the request, I'm not using any javascript framework. function getMyStuff(){ var SearchString = ''; /* build search string */ ... /* now do request */ var xhr = createXMLHttpRequest(); var RequestString = 'someserverscript.cfm' + SearchString; xhr.open("POST", RequestString, true); xhr.onreadystatechange = function(){ processResponse(xhr); } xhr.send(null); } function processResponse(xhr){ var serverResponse = xhr.responseText; var container = document.getElementById('myResultsContainer'); if (xhr.readyState == 4){ container.innerHTML = serverResponse; } } function createXMLHttpRequest(){ try { return new ActiveXObject("Msxml2.XMLHTTP"); } catch (e) {} try { return new ActiveXObject("Microsoft.XMLHTTP"); } catch (e) {} try { return new XMLHttpRequest(); } catch(e) {} return null; } How do I force or add the content length for ajax type POST requests in Firefox?

    Read the article

  • Problem when getting pageContent of an unavailable URL in Java

    - by tiendv
    I have a code for get pagecontent from a URL: import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.net.URL; import java.net.URLConnection; public class GetPageFromURLAction extends Thread { public String stringPageContent; public String targerURL; public String getPageContent(String targetURL) throws IOException { String returnString=""; URL urlString = new URL(targetURL); URLConnection openConnection = urlString.openConnection(); String temp; BufferedReader in = new BufferedReader( newInputStreamReader(openConnection.getInputStream())); while ((temp = in.readLine()) != null) { returnString += temp + "\n"; } in.close(); // String nohtml = sb.toString().replaceAll("\\<.*?>",""); return returnString; } public String getStringPageContent() { return stringPageContent; } public void setStringPageContent(String stringPageContent) { this.stringPageContent = stringPageContent; } public String getTargerURL() { return targerURL; } public void setTargerURL(String targerURL) { this.targerURL = targerURL; } @Override public void run() { try { this.stringPageContent=this.getPageContent(targerURL); } catch (IOException e) { e.printStackTrace(); } } } Sometimes I receive an HTTP error of 405 or 403 and result string is null. I have tried checking permission to connect to the URL with: URLConnection openConnection = urlString.openConnection(); openConnection.getPermission() but it usualy returns null. Does mean that i don't have permission to access the link? I have tried stripping off the query portion of the URL with: String nohtml = sb.toString().replaceAll("\\<.*?>",""); where sb is a Stringbulder, but it doesn't seem to strip off the whole query substring. In an unrelated question, I'd like to use threads here because I must retrieve many URLs; how can I create a multi-thread client to improve the speed?

    Read the article

  • how to save sitecore webpage in html file on local disk or server

    - by Sam
    WebRequest mywebReq ; WebResponse mywebResp ; StreamReader sr ; string strHTML ; StreamWriter sw; mywebReq = WebRequest.Create("http://domain/sitecore/content/test/page10.aspx"); mywebResp = mywebReq.GetResponse(); sr = new StreamReader(mywebResp.GetResponseStream()); strHTML = sr.ReadToEnd(); sw = File.CreateText(Server.MapPath("hello.html")); sw.WriteLine(strHTML); sw.Close(); Hi , I want to save sitecore .aspx page into html file on local disk , but i am getting exception. But if i use any other webpage example(google.com) it works fine. The exception : System.Net.WebException was caught HResult=-2146233079 Message=The remote server returned an error: (404) Not Found. Source=System StackTrace: at System.Net.WebClient.DownloadFile(Uri address, String fileName) at System.Net.WebClient.DownloadFile(String address, String fileName) at BlueDiamond.addmodule.btnSubmit(Object sender, EventArgs e) in c:\inetpub\wwwroot\STGLocal\Website\addmodule.aspx.cs:line 97 InnerException: Any help. Thanks in advance

    Read the article

  • Twitter api - no more than 150 requests per hour....

    - by RenegadeAndy
    Hi. I am writing a twitter app using jtwitter - and its running inside a server inside my work. Anyway - whenever i run it from work it returns the error below and I am only making a couple requests per hour: HTTP/1.1 400 Bad Request {"request":"/1/statuses/user_timeline.json?count=6&id=cicsdemo&","error":"Rate limit exceeded. Clients may not make more than 150 requests per hour."} ] 2010-06-03 18:44:49 zero.timer.TimerTask::run Thread-3 SEVERE [ CWPZA3100E: Exception during processing for timer task, "twitterTimer". Exception: java.lang.ClassCastException: winterwell.jtwitter.Twitter$Status incompatible with java.lang.String ] I run the same code from home - its fine. So obviously at some point twitter thinks our work is all coming from one direct IP - which is why its hitting a limit which it shouldnt. Do I have any choice or workaround - can i make the limit be counted from my direct machine IP - or to my account instead of IP? Can i use a proxy? Has any body else had this problem and solved it?! Before anyone asks the APP must live inside my work - it cannot run anywhere else! Cheers, Andy

    Read the article

  • log in using fitnesse

    - by user1513027
    This is a basic HTTP encoding and formatting question. I need to log in from a RESTFixture to a PHP web service. I need to pass in the account, username, and password, as POST variables just as a login page does. Wireshark shows that my login page formats it as accountNumber=accounttest&username=usertest&password=passtest When I do that in the test, I get a POST array of $_POST: Array ( [accountNumber] => accounttest [amp;username] => usertest [amp;password] => passtest ) That would work but the "amp;" obviously makes it so that PHP doesn't find the username. Content type is the same for both live and the test. [CONTENT_TYPE] = application/x-www-form-urlencoded Here are a few other formats I've tried with results. In all three cases, it fails to parse so all fields end up in one array entry. input: accountNumber=accounttest%amp;username=usertest%amp;password=passtest Result: $_POST: Array ( [accountNumber] = accounttest%amp;username=usertest%amp;password=passtest ) input: accountNumber=accounttest;username=usertest;password=passtest Result: $_POST: Array ( [accountNumber] => accounttest;username=usertest;password=passtest ) input: accountNumber=accounttest%26username=usertest%26password=passtest Result: $_POST: Array ( [accountNumber] = accounttest&username=usertest&password=passtest ) So the last one correctly converts the %26 to &, but doesn't break the items apart into array elements.

    Read the article

  • Analyzing Web Application Speed

    - by Amy
    I'm a bit confused because the logical/programmer brain in me says that if all things are constant, the speed of a function must be constant. I am working on a PHP web application with jqGrid as a front end for showing the data. I am testing on my personal computer, so network traffic does not apply. I make an HTTP request to a PHP function, it returns the data, and then jqGrid renders it. What has me befuddled is that sometimes, Firebug reports that this is taking 300-600 milliseconds sometimes, and sometimes, it's taking 3.68 seconds. I can run the request over and over again, with very radically different response times. The query is the same. The number of users on the system is the same. No network latency. Same code. I'm not running other applications on the computer while testing. I could understand query caching improving performance on subsequent requests, but the speed is just fluctuating wildly with no rhyme or reason. So, my question is, what else can cause such variability in the response time? How can I determine what's doing it? More importantly, is there any way to get things more consistent?

    Read the article

  • GZipStream in an WebHttpResponse producing no data

    - by Pierre 303
    I want to compress my HTTP Responses for client that supports it. Here is the code used to send a standard response: IHttpClientContext context = (IHttpClientContext)sender; IHttpRequest request = e.Request; string responseBody = "This is some random text"; IHttpResponse response = request.CreateResponse(context); using (StreamWriter writer = new StreamWriter(response.Body)) { writer.WriteLine(responseBody); writer.Flush(); response.Send(); } The code above works fine. Now I added gzip support below. When I test it with a browser that supports gzip or a custom method, it returns an empty string. I'm sure I'm missing something simple, but I just can't find it... IHttpClientContext context = (IHttpClientContext)sender; IHttpRequest request = e.Request; string acceptEncoding = request.Headers["Accept-Encoding"]; string responseBody = "This is some random text"; IHttpResponse response = request.CreateResponse(context); if (acceptEncoding != null && acceptEncoding.Contains("gzip")) { byte[] bytes = ASCIIEncoding.ASCII.GetBytes(responseBody); response.AddHeader("Content-Encoding", "gzip"); using (GZipStream writer = new GZipStream(response.Body, CompressionMode.Compress)) { writer.Write(bytes, 0, bytes.Length); writer.Flush(); response.Send(); } } else { using (StreamWriter writer = new StreamWriter(response.Body)) { writer.WriteLine(responseBody); writer.Flush(); response.Send(); } }

    Read the article

  • Receive JSON payload with ZEND framework and / or PHP

    - by kent3800
    I'm receiving a JSON payload from a webservice at my site's internal webpage at /asset/setjob. The following is the JSON payload being posted to /asset/setjob: [{"job": {"source_filename": "beer-drinking-pig.mpg", "current_step": "waiting_for_file", "encoding_profile_id": "nil", "resolution": "nil", "status_url": "http://example.com/api/v1/jobs/1.json", "id": 1, "bitrate": "nil", "current_status": "waiting for file", "current_progress": "nil", "remote_id": "my-own-remote-id"}}] This payload posts one time to this page. The page is not meant for viewing but parsing the JSON object for the id and current_status so that I can insert it into a database. I'm using Zend framework. HOW DO I receive this payload in Zend? Do I $_GET['json']? $_POST['job']? None of these seem to work. I essentially need to assign this payload to a php variable so that I can then manipulate it. I've tried: $jsonStrGet = var_dump($_GET); $jsonStrPost = var_dump($_POST); And I've tried: $response = $this-getResponse(); $body = $response-getBody(); Blockquote Any help would be much appreciated! Thanks.

    Read the article

  • Apache ReWriteEngine throwing 500 Internal Server Error for too many internal redirects... why?!?!?!

    - by Stephen G
    I'm trying to implement a new ReWrite rule on my local dev machine. I have 13 rules set up already, and all work fine (even as of this writing). However, for some reason the newest one is throwing me 500 Internal Server Errors. The ReWrite rule is: RewriteRule stuff/public_html/vault/mystuff/view/(.*) /stuff/public_html/vault/mystuff/view/index.php?stuff=$1 RewriteRule stuff/public_html/vault/mystuff/view/(.*)/ /stuff/public_html/vault/mystuff/view/index.php?stuff=$1 Checked my apache logs and got this: [Thu Jan 13 22:07:43 2011] [error] [client ::1] mod_rewrite: maximum number of internal redirects reached. Assuming configuration error. Use 'RewriteOptions MaxRedirects' to increase the limit if neccessary., referer: http://localhost:8888/stuff/public_html/vault/mystuff/all/index.php?curr=7 On the script I am trying to redirect to view/index.php?stuff=$1, there is nothing that even remotely resembles a redirect of any kind. I do have a very, very basic session verifier being called at the top of the landing script, which is as follows: //Start session session_start(); //Check whether the session variable SESS_MEMBER_ID is present or not if(!isset($_SESSION['SESS_MEMBER_ID']) || (trim($_SESSION['SESS_MEMBER_ID']) == '')) { header("location: ".$root_http.""); exit(); } However, when I access the page directly, it acts as it should, and there is no redirect. All of my other ReWrite rules and their corresponding landing pages are set up the exact same way. This is blowing my mind. Any help, PLEASE!?

    Read the article

  • Redirecting to frontpage after 404 error in PHP

    - by Saif Bechan
    I have a php web page that now uses custom error pages when a page is not found. The custom error pages are included in PHP. So when somebody types in an URL that does not exists I just include an error page, and the error page starts with: <?php header("HTTP/1.1 404 Not> Found"); ?> This also tells crawlers that the page does not exist. Now I have set up a new system. When a user types a wrong url, the user is sent back to the frontpage and a message is displayed on the frontpage. I redirect to the frontpage like this: header('Location:' . __TINY_URL . '/'); Now the problem is PHP just sends back a 200 code, page found. How can I mix these two to create a 404 code on the frontpage. And is this overall a nice way of presenting and error page.

    Read the article

  • Displaying NON-ASCII Characters using HttpClient

    - by Abdullah Gheith
    So, i am using this code to get the whole HTML of a website. But i dont seem to get non-ascii characters with me. all i get is diamonds with question mark. characters like this: å, appears like this: ? I doubt its because of the charset, what could it then be? Log.e("HTML", "henter htmlen.."); String url = "http://beep.tv2.dk"; HttpClient client = new DefaultHttpClient(); client.getParams().setParameter(CoreProtocolPNames.PROTOCOL_VERSION, HttpVersion.HTTP_1_1); client.getParams().setParameter(CoreProtocolPNames.HTTP_ELEMENT_CHARSET, "UTF-8"); HttpGet request = new HttpGet(url); HttpResponse response = client.execute(request); Header h = HeaderValueFormatter response.addHeader(header) String html = ""; InputStream in = response.getEntity().getContent(); BufferedReader reader = new BufferedReader(new InputStreamReader(in)); StringBuilder str = new StringBuilder(); String line = null; while((line = reader.readLine()) != null) { str.append(line); } in.close(); //b = false; html = str.toString();

    Read the article

  • Python 3.3 Webserver restarting problems

    - by IPDGino
    I have made a simple webserver in python, and had some problems with it before as described here: Python (3.3) Webserver script with an interesting error In that question, the answer was to use a While True: loop so that any crashes or errors would be resolved instantly, because it would just start itself again. I've used this for a while, and still want to make the server restart itself every few minutes, but on Linux for some reason it won't work for me. On windows the code below works fine, but on linux it keeps saying Handler class up here ... ... class Server: def __init__(self): self.server_class = HTTPServer self.server_adress = ('MY IP GOES HERE, or localhost', 8080) global httpd httpd = self.server_class(self.server_adress, Handler) self.main() def main(self): if count > 1: global SERVER_UP_SINCE HOUR_CHECK = int(((count - 1) * RESTART_INTERVAL) / 60) SERVER_UPTIME = str(HOUR_CHECK) + " MINUTES" if HOUR_CHECK > 60: minutes = int(HOUR_CHECK % 60) hours = int(HOUR_CHECK // 60) SERVER_UPTIME = ("%s HOURS, %s MINUTES" % (str(hours), str(minutes))) SERVING_ON_ADDR = self.server_adress SERVER_UP_SINCE = str(SERVER_UP_SINCE) SERVER_RESTART_NUMBER = count - 1 print(""" SERVER INFO ------------------------------------- SERVER_UPTIME: %s SERVER_UP_SINCE: %s TOTAL_FILES_SERVED: %d SERVING_ON_ADDR: %s SERVER_RESTART_NUMBER: %s \n\nSERVER HAS RESTARTED """ % (SERVER_UPTIME, SERVER_UP_SINCE, TOTAL_FILES, SERVING_ON_ADDR, SERVER_RESTART_NUMBER)) else: print("SERVER_BOOT=1\nSERVER_ONLINE=TRUE\nRESTART_LOOP=TRUE\nSERVING_ON_ADDR:%s" % str(self.server_adress)) while True: try: httpd.serve_forever() except KeyboardInterrupt: print("Shutting down...") break httpd.shutdown() httpd.socket.close() raise(SystemExit) return def server_restart(): """If you want the restart timer to be longer, replace the number after the RESTART_INTERVAL variable""" global RESTART_INTERVAL RESTART_INTERVAL = 10 threading.Timer(RESTART_INTERVAL, server_restart).start() global count count = count + 1 instance = Server() if __name__ == "__main__": global SERVER_UP_SINCE SERVER_UP_SINCE = strftime("%d-%m-%Y %H:%M:%S", gmtime()) server_restart() Basically, I make a thread to restart it every 10 seconds (For testing purposes) and start the server. After ten seconds it will say File "/home/username/Desktop/Webserver/server.py", line 199, in __init__ httpd = self.server_class(self.server_adress, Handler) File "/usr/lib/python3.3/socketserver.py", line 430, in __init__ self.server_bind() File "/usr/lib/python3.3/http/server.py", line 135, in server_bind socketserver.TCPServer.server_bind(self) File "/usr/lib/python3.3/socketserver.py", line 441, in server_bind self.socket.bind(self.server_address) OSError: [Errno 98] Address already in use As you can see in the except KeyboardInterruption line, I tried everything to make the server stop, and the program stop, but it will NOT stop. But the thing I really want to know is how to make this server able to restart, without giving some wonky errors.

    Read the article

  • Problem uploading app to google app engine

    - by Oberon
    I'm having problems uploading an app to the google-app-engine from my work place. I believe the problem is related to proxy, because I do not see the same problem when following the same procedure from home. (I do not specify HTTP_PROXY from home). These are the commands I run: HTTP_PROXY=http://proxy.<thehostname>.com:8080 HTTP_PROXY=https://proxy.<thehostname>.com:8080 appcfg.py --insecure update myappfolder When running the commands I get prompted for email and password, as expected, but after that it immediately exits with this errormessage: Error 302: --- begin server output --- <HTML> <HEAD> <TITLE>Moved Temporarily</TITLE> </HEAD> <BODY BGCOLOR="#FFFFFF" TEXT="#000000"> <H1>Moved Temporarily</H1> The document has moved <A HREF="https://www.google.com/accounts/ClientLogin">here</A>. </BODY> </HTML> --- end server output --- Note: I added the --insecure option because else it gave a warning of missing ssl module. Any idea how to solve or workaround this problem?

    Read the article

  • Java - How to find the redirected url of a url?

    - by Yatendra Goel
    I am accessing web pages through java as follows: URLConnection con = url.openConnection(); But in some cases, a url redirects to another url. So I want to know the url to which the previous url redirected. Below are the header fields that I got as a response: null-->[HTTP/1.1 200 OK] Cache-control-->[public,max-age=3600] last-modified-->[Sat, 17 Apr 2010 13:45:35 GMT] Transfer-Encoding-->[chunked] Date-->[Sat, 17 Apr 2010 13:45:35 GMT] Vary-->[Accept-Encoding] Expires-->[Sat, 17 Apr 2010 14:45:35 GMT] Set-Cookie-->[cl_def_hp=copenhagen; domain=.craigslist.org; path=/; expires=Sun, 17 Apr 2011 13:45:35 GMT, cl_def_lang=en; domain=.craigslist.org; path=/; expires=Sun, 17 Apr 2011 13:45:35 GMT] Connection-->[close] Content-Type-->[text/html; charset=iso-8859-1;] Server-->[Apache] So at present, I am constructing the redirected url from the value of the Set-Cookie header field. In the above case, the redirected url is copenhagen.craigslist.org Is there any standard way through which I can determine which url the particular url is going to redirect. I know that when a url redirects to other url, the server sends an intermediate response containing a header field that tells the url which it is going to redirect but I am not receiving that intermediate response through the url.openConnection(); method.

    Read the article

< Previous Page | 128 129 130 131 132 133 134 135 136 137 138 139  | Next Page >