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  • MS Access 2003 - Save button enabling on form open on different tabs

    - by Justin
    I have a tab control on a form, and a couple different tabs have save buttons on them. Once the user saves data (via SQL statements in VBA), I set the .enabled = false so that they cannot use this button again until moving to a brand new record (which is a button click on the overall form). so when my form open i was going to reference a sub that enabled all these save buttons because the open event would mean new record. though i get an error that says it either does not exist, or is closed. any ideas? thanks EDIT: Sub Example() error handling Dim db as dao.database dim rs as dao.recordset dim sql as string SQL = "INSERT INTO tblMain (Name, Address, CITY) VALUES (" if not isnull (me.name) then sql = sql & """" & me.name & """," else sql = sql & " NULL," end if if not insull(me.adress) then sql = sql & " """ & me.address & """," else sql = sql & " NULL," end if if not isnull(me.city) then sql = sql & " """ & me.city & """," else sql = sql & " NULL," end if 'debug.print(sql) set db = currentdb db.execute (sql) MsgBox "Changes were successfully saved" me.MyTabCtl.Pages.Item("SecondPage").setfocus me.cmdSaveInfo.enabled = false and then on then the cmdSave needs to get re enabled on a new record (which by the way, this form is unbound), so it all happens when the form is re-opened. I tried this: Sub Form_Open() me.cmdSaveInfo.enabled = true End Sub and this is where I get the error stated above. So this is also not the tab that has focus when the form opens. Is that why I get this error? I cannot enable or disable a control when the tab is not showing?

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  • Nested asynchronous calls do not seem to execute as expected

    - by Kristof Van Landschoot
    While trying out jQuery, I have a question that is probably a newbie mistake, but I cannot seem to find the solution. This is the code: $.get("index.html", function() { var i = 0; for (; i < 3; i++) { var lDiv = document.createElement('div'); lDiv.id = 'body-' + i; document.getElementById('body').appendChild(lDiv); $.get('index.html', function(data) { lDiv.innerHTML = "<p>Hello World " + i + "</p>"; }); } }); The output seems to be <div id='body-0'></div> <div id='body-1'></div> <div id='body-2'> <p>Hello World 3</p> </div> I expected the lDiv.innerHTML= code to be executed for each i, but apparently it is only executed for the last i? What am I overlooking?

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  • C & MinGW: Hello World gives me the error "programm too big to fit in memory"

    - by user1692088
    I'm new here. Here's my problem: I installed MinGW on my Windows 7 Home Premium 32-bit Netbook with Intel Atom CPU N550, 1.50GHz and 2GB RAM. Now I made a file named hello.h and tried to compile it via CMD with the following command: "gcc c:\workspace\c\helloworld\hello.h -o out.exe" It compiles with no error, but when I try to run out.exe, it gives me following error: "program too big to fit in memory" Things I have checked: I have added "C:\MinGW\bin" to the Windows PATH Variable I have googled for about one hour, but ever since I'm a newbie, I can't really figure out what the problem is. I have compiled the same code on my 64-bit machine, compiles perfectly, but cannot be run due to 64-bit <- 16-bit problematic. I'd really appreciate, if someone could figure out, what the problem is. Btw, here's my hello.h: #include <stdio.h> int main(void){ printf("Hello, World\n"); } ... That's it. Thanks for your replies. Cheers, Boris

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  • iPhone Rendering Question

    - by slythic
    Hi all, I'm new to iPhone/Objective-C development. I "jumped the gun" and started reading and implementing some chapters from O'Reilly's iPhone Development. I was following the ebook's code exactly and my code was generating the following error: CGContextSetFillColorWithColor: invalid context CGContextFillRects: invalid context CGContextSetFillColorWithColor: invalid context CGContextGetShouldSmoothFonts: invalid context However, when I downloaded the sample code for the same chapter the code is different. Book Code: - (void) Render { CGContextRef g = UIGraphicsGetCurrentContext(); //fill background with gray CGContextSetFillColorWithColor(g, [UIColor grayColor].CGColor); CGContextFillRect(g, CGRectMake(0, 0, self.frame.size.width, self.frame.size.height)); //draw text in black. CGContextSetFillColorWithColor(g, [UIColor blackColor].CGColor); [@"O'Reilly Rules!" drawAtPoint:CGPointMake(10.0, 20.0) withFont:[UIFont systemFontOfSize:[UIFont systemFontSize]]]; } Actual Project Code from the website (works): - (void) Render { [self setNeedsDisplay]; //this sets up a deferred call to drawRect. } - (void)drawRect:(CGRect)rect { CGContextRef g = UIGraphicsGetCurrentContext(); //fill background with gray CGContextSetFillColorWithColor(g, [UIColor grayColor].CGColor); CGContextFillRect(g, CGRectMake(0, 0, self.frame.size.width, self.frame.size.height)); //draw text in black. CGContextSetFillColorWithColor(g, [UIColor blackColor].CGColor); [@"O'Reilly Rules!" drawAtPoint:CGPointMake(10.0, 20.0) withFont:[UIFont systemFontOfSize:[UIFont systemFontSize]]]; } What is it about these lines of code that make the app render correctly? - (void) Render { [self setNeedsDisplay]; //this sets up a deferred call to drawRect. } - (void)drawRect:(CGRect)rect { Thanks in advance for helping out a newbie!

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  • Oracle - Getting Select Count(*) from ... as an output parameter in System.Data.OracleClient

    - by cbeuker
    Greetings all, I have a question. I am trying to build a parametrized query to get me the number of rows from a table in Oracle. Rather simple. However I am an Oracle newbie.. I know in SQL Server you can do something like: Select @outputVariable = count(*) from sometable where name = @SomeOtherVariable and then you can set up an Output parameter in the System.Data.SqlClient to get the @outputVariable. Thinking that one should be able to do this in Oracle as well, I have the following query Select count(*) into :theCount from sometable where name = :SomeValue I set up my oracle parameters (using System.Data.OracleClient - yes I know it will be deprecated in .Net 4 - but that's what I am working with for now) as follows IDbCommand command = new OracleCommand(); command.CommandText = "Select count(*) into :theCount from sometable where name = :SomeValue"); command.CommandType = CommandType.Text; OracleParameter parameterTheCount = new OracleParameter(":theCount ", OracleType.Number); parameterTheCount .Direction = ParameterDirection.Output; command.Parameters.Add(parameterTheCount ); OracleParameter parameterSomeValue = new OracleParameter(":SomeValue", OracleType.VarChar, 40); parameterSomeValue .Direction = ParameterDirection.Input; parameterSomeValue .Value = "TheValueToLookFor"; command.Parameters.Add(parameterSomeValue ); command.Connection = myconnectionObject; command.ExecuteNonQuery(); int theCount = (int)parameterTheCount.Value; At which point I was hoping the count would be in the parameter parameterTheCount that I could readily access. I keep getting the error ora-01036 which http://ora-01036.ora-code.com tells me to check my binding in the sql statement. Am I messing something up in the SQL statement? Am I missing something simple elsewhere? I could just use command.ExecuteScaler() as I am only getting one item, and am probably going to end up using that, but at this point, curiosity has got the better of me. What if I had two parameters I wanted back from my query (ie: select max(ColA), min(ColB) into :max, :min.....) Thanks..

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  • JME: How to get the complete screen in WHITE without buttons, etc etc

    - by Sepala
    Please have a look at the following code /* * To change this template, choose Tools | Templates * and open the template in the editor. */ import javax.microedition.midlet.*; import javax.microedition.lcdui.*; /** */ public class Midlet extends MIDlet{ private Form f; private Display d; private Command start,stop; private Thread t; public Midlet() { t = new Thread(new TurnLightOn()); } public void startApp() { f = new Form("Back Light On"); d = Display.getDisplay(this); d.setCurrent(f); start = new Command("Turn On",Command.OK,0); stop = new Command("Turn Off",Command.OK,1); f.addCommand(start); f.setCommandListener(new Action()); } public void pauseApp() { } public void destroyApp(boolean unconditional) { this.notifyDestroyed(); } private class Action implements CommandListener { public void commandAction(Command c, Displayable dis) { f.append("Light is Turnning On"); t.start(); } } private class ActionOff implements CommandListener { public void commandAction(Command c, Displayable dis) { } } private class TurnLightOn implements Runnable { public void run() { f.append("Working"); for(int i=0;i<100;i++) { try { d.flashBacklight(200); d.vibrate(200); Thread.sleep(1000); } catch (InterruptedException ex) { ex.printStackTrace(); } } } } } First, Please note I am a 100% newbie to Java Mobile. In here, I am making the light on and vibrate on when user click the button. However, I really wanted to create a SOS application which turn the whole screen into white, and go to black, like that, in the thread. I guess I didn't achieve that by this app because even the lights are on, the buttons are still there. I tried to turn the "Form" color to "white" but it seems like JME has no "Color" class! Please help!

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  • nanoc installation setup in Linux

    - by Ananth
    I'm a newbie to Ruby. Trying to setup nanoc in my machine. I'm running Ubuntu 14.04. After the nanoc installation, when I type $nanoc --version I get the following errors: /home/ananth/.rvm/gems/ruby-head@global/gems/bundler-1.6.2/lib/bundler/shared_helpers.rb:24:in `default_gemfile': Could not locate Gemfile (Bundler::GemfileNotFound) from /home/ananth/.rvm/gems/ruby-head@global/gems/bundler-1.6.2/lib/bundler.rb:248:in `default_gemfile' from /home/ananth/.rvm/gems/ruby-head@global/gems/bundler-1.6.2/lib/bundler.rb:192:in `root' from /home/ananth/.rvm/gems/ruby-head@global/gems/bundler-1.6.2/lib/bundler.rb:99:in `bundle_path' from /home/ananth/.rvm/gems/ruby-head@global/gems/bundler-1.6.2/lib/bundler.rb:400:in `configure_gem_home_and_path' from /home/ananth/.rvm/gems/ruby-head@global/gems/bundler-1.6.2/lib/bundler.rb:90:in `configure' from /home/ananth/.rvm/gems/ruby-head@global/gems/bundler-1.6.2/lib/bundler.rb:151:in `definition' from /home/ananth/.rvm/gems/ruby-head@global/gems/bundler-1.6.2/lib/bundler.rb:116:in `setup' from /home/ananth/.rvm/gems/ruby-head@global/gems/bundler-1.6.2/lib/bundler.rb:132:in `require' from /home/ananth/.rvm/gems/ruby-head/gems/nanoc-3.7.0/bin/nanoc:7:in `<top (required)>' from /home/ananth/.rvm/gems/ruby-head/bin/nanoc:23:in `load' from /home/ananth/.rvm/gems/ruby-head/bin/nanoc:23:in `<main>' from /home/ananth/.rvm/gems/ruby-head/bin/ruby_executable_hooks:15:in `eval' from /home/ananth/.rvm/gems/ruby-head/bin/ruby_executable_hooks:15:in `<main>' Am I missing something from my rvm? Anything to do with $PATH, .bashrc or .bash_profile? Thanks for the help in advance!

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  • What does the subversion error "Could not read status line" mean?

    - by Jergason
    Exact duplicate: SVN: Could not read status line: connection was closed by server This is not an exact duplicate. The other question was asking about getting the error in a specific situation, and the answer was vauge at best. This is a fairly basic question, but it is driving me nuts. I have set up a brand new repository at beanstalk.com. They give me the url, http://.svn.beanstalkapp.com/blog. They also automatically create the tag, trunk and branches folder in the repository. I have checked out the trunk folder and used svn add to add the new file. I am trying to do my first commit, but I get this error: Commit failed (details follow): CHECKOUT of '/foo/!svn/bln/1': Could not read status line: connection was closed by server. (http://user_name@my_name.svn.beanstalkapp.com) What does this mean, and what causes it? I have googled for a definition of what "Could not read status line" means, but was unable to find anything explaining it. edit: I was getting this error while trying to manipulate my repository from behind a firewall. I still don't know what was causing it, but I don't have this problem at home. Strangeness.

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  • Append to a webpage in javascript

    - by Lily
    What I want to do is that: a webpage with continuously updating content. (In my case is updating every 2s) New content is appended to the old one instead of overwriting the old one. Here is the code I have: var msg_list = new Array( "<message>Hello, Clare</message>", "<message>Hello,Lily</message>", "<message>Hello, Kevin</message>", "<message>Hello, Bill</message>" ); var number = 0; function send_msg() { document.write(number + " " + msg_list[number%4]+'<br/>'); number = number + 1; } var my_interval = setInterval('send_msg()', 2000); However, in both IE and Firefox, only one line is printed out, and the page will not be updated anymore. Interestingly in Chrome, the lines being printed out continuously, which is what I am looking for. I know that document.write() is called when the page is loaded according to this. So it's definitely not the way to update the webpage continuously. What will be the best way to achieve what I want to do? Totally newbie in Javascript. Thank you. Lily

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  • Strange Problem with Webservice and IIS

    - by Rene
    Hello there, I have a Problem which confuses me a little bit, resp. where I don't have any Idea about what it could be. The System I'm using is Windows Vista, IIS 7.0, VS2008, Windows Software Factory, Entity Framework, WCF. The Binding for all Webservices is wshttpbinding. I'm using a Webservice hosted in IIS. This Webservice uses/calls another Webservice (also installed in the IIS). If I use a client calling the first Webservice (which calls the second Webservice) it works fine for about 4-10 Times. And then (it is repeatable to get this Problem, but sometimes it happens after 4, sometimes after 10 Time, but it always will happen), the Service and the IIS gets stuck. Stuck means, that this Webservice isn't callable anymore and generates an timeout after 1 minute. Even increasing Timeout doesn't change anything. If i try to restart the IIS I get an timeout error. So the IIS is also "stuck" (it is not really stuck, but I can't restart it). Only if I kill the w3wp.exe IIS is restartable and the Webservice will work again (until i again call this service several times). The logfiles (i'm no expert in things like logging or where to find/enable such logs, so to say : i'm a newbie) like http-logging, Event Viewer or WCF-Message Logging don't show any hints upon the source of the problem. I don't have this problem when I'm using a Webservice which doesn't call another Service. Calling a Webservice is done by Service Reference (I'm using no Proxy-Classes), but I think this should be no Problem. I have no idea of what is happening, nor how to solve this Problem. Regards Rene

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  • How do I browse a Websphere MQ message without removing it?

    - by jmgant
    I'm writing a .NET Windows Forms application that will post a message to a Websphere MQ queue and then poll a different queue for a response. If a response is returned, the application will partially process the response in real time. But the response needs to stay in the queue so that a daily batch job, which also reads from the response queue, can do the rest of the processing. I've gotten as far as reading the message. What I haven't been able to figure out is how to read it without removing it. Here's what I've got so far. I'm an MQ newbie, so any suggestions will be appreciated. And feel free to respond in C#. Public Function GetMessage(ByVal msgID As String) As MQMessage Dim q = ConnectToResponseQueue() Dim msg As New MQMessage() Dim getOpts As New MQGetMessageOptions() Dim runThru = Now.AddMilliseconds(CInt(ConfigurationManager.AppSettings("responseTimeoutMS"))) System.Threading.Thread.Sleep(1000) 'Wait for one second before checking for the first response' While True Try q.Get(msg, getOpts) Return msg Catch ex As MQException When ex.Reason = MQC.MQRC_NO_MSG_AVAILABLE If Now > runThru Then Throw ex System.Threading.Thread.Sleep(3000) Finally q.Close() End Try End While Return Nothing 'Should never reach here' End Function NOTE: I haven't verified that my code actually removes the message. But that's how I understand MQ to work, and that appears to be what's happening. Please correct me if that's not the default behavior.

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  • how to indicate a change in list elements' order using jquery?

    - by keisimone
    i am using jquery sortable. right now i have a list of items that i can ALREADY use drag and drop. which is cool. i will use a submit button at the bottom of the list to submit the new order. the change in the list is not automatically submitted. All i need is somehow indicate that an element's position has changed. I googled quite a bit. no answer. original list: item1 item2 item3 item4 item5 submitbutton here. changed list: i moved item 2 below item3 for eg. item1 item3 item2 * item4 item5 submitbutton here. how do i use the sortable in jquery for me to display a sign on the item 2? i think should be the change event of sortable but i still do not know how to use it since i am a newbie in jquery. http://docs.jquery.com/UI/Sortable#event-change thank you.

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  • Installation failed for Scala eclipse plugin

    - by Ramesh Vel
    Hi, I am Scala newbie. Just started playing. Today i started to install scala plugin for eclipse (in ubuntu machine), but its failed everytime. Below the error message. An error occurred while collecting items to be installed session context was:(profile=PlatformProfile, phase=org.eclipse.equinox.internal.provisional.p2.engine.phases.Collect, operand=, action=). No repository found containing: osgi.bundle,ch.epfl.lamp.sdt.aspects,2.7.7.final No repository found containing: osgi.bundle,ch.epfl.lamp.sdt.core,2.7.7.final No repository found containing: org.eclipse.update.feature,ch.epfl.lamp.sdt,2.7.7.final No repository found containing: osgi.bundle,org.aspectj.runtime,1.6.4.20090304172355 No repository found containing: osgi.bundle,org.aspectj.weaver,1.6.4.20090304172355 No repository found containing: org.eclipse.update.feature,org.eclipse.contribution.weaving,1.6.4.20090313172428 No repository found containing: osgi.bundle,org.eclipse.contribution.weaving.jdt,1.6.4.20090313172428 No repository found containing: osgi.bundle,org.eclipse.equinox.weaving.aspectj,1.0.0.200902241436 No repository found containing: osgi.bundle,org.eclipse.equinox.weaving.hook,1.0.0.200902121956 No repository found containing: osgi.bundle,scala.library,2.7.7.final No repository found containing: osgi.bundle,scala.tools.nsc,2.7.7.final Can someone clarify me what was the problem. Cheer

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  • Trouble passing JSP values to ActionForm (Struts)

    - by tacotime
    Hi, I am a newbie to Struts and have inherited a problem. I am trying to pass 3 values contained in the same table cell from a JSP to my ActionForm class. The first value (and others in the JSP) work fine, but for some reason the other two do not. I have the appropriate getters and setters, but only the first (newrecnum) shows up, the other two are null. Is there a limitation to only pass the first value? Or is there something else wrong? Here is the JSP code: <td> <html:text size="10" maxlength="10" property="newrecnum"/><br> <html:text size="5" maxlength="5" property="newrectime"/> <html:select property="newreccode" disabled="true"> <html:option value="YES">YES</html:option> <html:option value="NO">NO</html:option></html:select> </td> I can include the ActionForm code as well if needed. Thanks!

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  • Java hangs when trying to close a ProcessBuilder OutputStream

    - by Jeff Bullard
    I have the following Java code to start a ProcessBuilder, open an OutputStream, have the process write a string to an OutputStream, and then close the OutputStream. The whole thing hangs indefinitely when I try to close the OutputStream. This only happens on Windows, never on Mac or Linux. Some of the related questions seem to be close to the same problem I'm having, but I haven't been able to figure out how to apply the answers to my problem, as I am a relative newbie with Java. Here is the code. You can see I have put in a lot of println statements to try to isolate the problem. System.out.println("GenMic trying to get the input file now"); System.out.flush(); OutputStream out = child.getOutputStream(); try { System.out.println("GenMic getting ready to write the input file to out"); System.out.flush(); out.write(intext.getBytes()); System.out.println("GenMic finished writing to out"); System.out.flush(); out.close(); System.out.println("GenMic closed OutputStream"); System.out.flush(); } catch (IOException iox) { System.out.println("GenMic caught IOException 2"); System.out.flush(); String detailedMessage = iox.getMessage(); System.out.println("Exception: " + detailedMessage); System.out.flush(); throw new RuntimeException(iox); } And here is the output when this chunk is executed: GenMic trying to get the input file now GenMic getting ready to write the input file to out GenMic finished writing to out

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  • Re-use of database object in sub-sonic

    - by cantabilesoftware
    Yet another newbie SubSonic/ActiveRecord question. Suppose I want to insert a couple of records, currently I'm doing this: using (var scope = new System.Transactions.TransactionScope()) { // Insert company company c = new company(); c.name = "ACME"; c.Save(); // Insert some options company_option o = new company_option(); o.name = "ColorScheme"; o.value = "Red"; o.company_id = c.company_id; o.Save(); o = new company_option(); o.name = "PreferredMode"; o.value = "Fast"; o.company_id = c.company_id; o.Save(); scope.Complete(); } Stepping through this code however, each of the company/company_option constructors go off and create a new myappDB object which just seems wasteful. Is this the recommended approach or should I be trying to re-use a single DB object - and if so, what's the easiest way to do this?

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  • Grayscale image with colored spotlight in JavaFX

    - by DaUltimateTrooper
    I need a way to have a gray scale image in an ImageView and on mouse moved if the cursor position is in the ImageView bounds to show a colored spotlight on the mouse position. I have created a sample to help you understand what I need. This sample negates the colors of a colored image on the onMouseMoved event. package javafxapplication3; import javafx.scene.effect.BlendMode; import javafx.scene.Group; import javafx.scene.image.Image; import javafx.scene.image.ImageView; import javafx.scene.input.MouseEvent; import javafx.scene.paint.Color; import javafx.scene.paint.RadialGradient; import javafx.scene.paint.Stop; import javafx.scene.Scene; import javafx.scene.shape.Circle; import javafx.stage.Stage; var spotlightX = 0.0; var spotlightY = 0.0; var visible = false; var anImage = Image { url: "{__DIR__}picture1.jpg" } Stage { title: "Spotlighting" scene: Scene { fill: Color.WHITE content: [ Group { blendMode: BlendMode.EXCLUSION content: [ ImageView { image: anImage onMouseMoved: function (me: MouseEvent) { if (me.x > anImage.width - 10 or me.x < 10 or me.y > anImage.height - 10 or me.y < 10) { visible = false; } else { visible = true; } spotlightX = me.x; spotlightY = me.y; } }, Group { id: "spotlight" content: [ Circle { visible: bind visible translateX: bind spotlightX translateY: bind spotlightY radius: 60 fill: RadialGradient { centerX: 0.5 centerY: 0.5 stops: [ Stop { offset: 0.1, color: Color.WHITE }, Stop { offset: 0.5, color: Color.BLACK }, ] } } ] } ] }, ] }, } I am a total newbie what can I say...

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  • Vertical Image Border Changes Alignment when Screen is not maximized

    - by Randy
    I have some pretty straightforward HTML code with a few tables to organize various items of text or images. All works fine except that I need to place a vertical border on both the left and right sides of the screen. I am able to do this with a 2x2 pixel image that I stretch out. When the user has their screen maximized, everything looks great. But when the user hits "Restore Down", then the borders stay in place, but the tables get shoved down so that they start below where the borders end, which is off screen. in other words, the relational alignment between the borders and the tables gets all screwed up. Does anybody know how to make this alignment stay consistent on a restore down? I'm pretty much a newbie with html and asp, so speak slowly. If there is a better method to accomplish this, I'm all ears. Thanks. Here is the relevant section of code: <%@ Master Language="C#" AutoEventWireup="true" CodeFile="MasterPage.master.cs" Inherits="MasterPage" % <form id="form1" runat="server"> <asp:Image ID="LeftBorder" src="../Images/Border_Blue.jpg" runat="server" WIDTH="15" HEIGHT="1000" BORDER="0" alt="Image Missing" align="left"/> <asp:Image ID="RightBorder" src="../Images/Border_Blue.jpg" runat="server" WIDTH="15" HEIGHT="1000" BORDER="0" alt="Image Missing" align="right" /> <table id="BannerTable" style="height: 100px"> <tr> <td width="934px"> <img src="../Images/Header.jpg" alt="Image Missing" id="ImgBanner" align="left"/></td> </tr> </table>

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  • ListBox Items Not Visible after DataBinding

    - by SidC
    Good Evening All, I am writing a page that allows users to search a parts table, select quantities and a listbox is to be populated with gridview values. Here's a snippet of my aspx page: <asp:ListBox runat="server" ID="lbItems" Width="155px"> <asp:ListItem></asp:ListItem> <asp:ListItem></asp:ListItem> <asp:ListItem></asp:ListItem> <asp:ListItem></asp:ListItem> <asp:ListItem></asp:ListItem> </asp:ListBox> Here's the relevant contents of codebehind: Protected Sub Page_Load(ByVal sender As Object, ByVal e As System.EventArgs) Handles Me.Load 'Define DataTable Columns as incoming gridview fields Dim dtSelParts As DataTable = New DataTable Dim dr As DataRow = dtSelParts.NewRow() dtSelParts.Columns.Add("PartNumber") dtSelParts.Columns.Add("NSN") dtSelParts.Columns.Add("PartName") dtSelParts.Columns.Add("Qty") 'Select those gridview rows that have txtQty <> 0 For Each row As GridViewRow In MySearch.Rows Dim textboxText As String = _ CType(row.FindControl("txtQty"), TextBox).Text If textboxText <> "0" Then 'Create the row dr = dtSelParts.NewRow() 'Fill the row with data dr("PartNumber") = MySearch.DataKeys(row.RowIndex)("PartNumber") dr("NSN") = MySearch.DataKeys(row.RowIndex)("NSN") dr("PartName") = MySearch.DataKeys(row.RowIndex)("PartName") 'Add the row to the table dtSelParts.Rows.Add(dr) End If Next 'Need to send items to Listbox control lbItems lbItems.DataSource = New DataView(dtSelParts) lbItems.DataValueField = "PartNumber" lbItems.DataValueField = "NSN" lbItems.DataValueField = "PartName" lbItems.DataBind() End Sub The page runs fine in that my search functiobnality is intact, and I can input quantity values into my gridview's textbox. When I click Add to Quote the Listbox receives focus, but no list items are visible. I've created several list items in the aspx page, however I don't know how to populate the contents of my datatable in the listbox. Can someone help a newbie with this, seemingly, easy issue? Thanks, Sid

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  • Can't Display Bitmap of Higher Resolution than CDC area

    - by T. Jones
    Hi there dear gurus and expert coders. i am not gonna start with im a newbie and don't know much about image programming but unfortunately those are the facts :( I am trying to display an image from a bitmap pointer *ImageData which is of resolution 1392x1032. I am trying to draw that at an area of resolution or size 627x474. However, repeated trying doesnt seem to work. It works when I change the bitmap image I created from *ImageData width and height to resolution or size of around 627x474 I really do not know how to solve this after trying all possible solutions from various forums and google. pDC is a CDC* and memDC is a CDC initialized in an earlier method Anything uninitialized here was initialized in other methods. Here is my code dear humble gurus. Do provide me with guidance Yoda and Obi-Wan provided to Luke Skywalker. void DemoControl::ShowImage( void *ImageData ) { int Width; //Width of Image From Camera int Height; //Height of Image From Camera int m_DisplayWidth = 627 ;//width of rectangle area to display int m_DisplayHeight = 474;//height of rectangle area to display GetImageSize( &Width, &Height ) ; //this will return Width = 1392, Height 1032 CBitmap bitmap; bitmap.CreateBitmap(Width,Height,32,1,ImageData); CBitmap* pOldBitmap = memDC.SelectObject((CBitmap*)&bitmap); pDC->BitBlt(22, 24, 627, 474, &memDC, 0, 0, SRCCOPY); memDC.SelectObject((CBitmap*)pOldBitmap); ReleaseDC(pDC); }

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  • Setting routes in application.ini in Zend Framework

    - by Paul Watson
    I'm a Zend Framework newbie, and I'm trying to work out how to add another route to my application.ini file. I currently have my routes set up as follows: resources.router.routes.artists.route = /artists/:stub resources.router.routes.artists.defaults.controller = artists resources.router.routes.artists.defaults.action = display ...so that /artists/joe-bloggs uses the "display" action of the "artists" controller to dipslay the profile the artist in question - that works fine. What I want to do now is to set up another route so that /artists/joe-bloggs/random-gallery-name goes to the "galleries" action of the "artists" controller. I tried adding an additional block to the application.ini file (beneath the block above) like so: resources.router.routes.artists.route = /artists/:stub/:gallery resources.router.routes.artists.defaults.controller = artists resources.router.routes.artists.defaults.action = galleries ...but when I do that the page at /artists/joe-bloggs no longer works (Zend tries to route it to the "joe-bloggs" controller). How do I set up the routes in application.ini so that I can change the action of the "artists" controller depending on whether "/:gallery" exists? I realise I'm probably making a really stupid mistake, so please point out my stupidity and set me on the right path (no pun intended).

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  • Associate new Authlogic Model to existing Models

    - by BriteLite
    Hello, While playing around with Rails (since I am a newbie) while reading Agile Rails book I came across an issue using the Gem Authlogic that I don't know how to address. I have a simple business Model. The tables store the following information: Name, Address, Latitude, and Longitude. The above approach has been working fine, because using the console I can enter the information and it shows up, where I need it to. My issue now is that I want to add authentication to it. As in assign those records in the table, to individual accounts. Since Authlogic is an authentication gem, can this be done? What I am trying to get to here is that, I enter a few records and leave it at that. Few days later, I want to assign those individual rows in the table to an authlogic model so the person to whom the record should belong can authenticate to it and make changes. Any code samples, blog posts to better help me understand would be great! Thank You.

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  • Issue with 'Hello Android' tutorial

    - by Mike Needham
    I am brand new to Eclipse and Android, but somewhat familiar with Java. That having been said, I tried to follow the 'Hello Android' tutorial from the developer site using the latest Eclipse (Galieo) and the 2.1 Android SDK, I am on a Macintosh running Snow Leopard (OS X 10.6). I have a default virtual device (though my target is actually for phones like my own HTC Incredible which has the snapdragon processor and of course all the latest accoutrement in smart phones. Everything seemed to go okay until I went to RUN>RUN and then selected 'Android Application'. My computer spins it's wheels for a while and then I see two errors. I have pasted the output below: [2010-05-04 01:53:46 - HelloAndroid] ------------------------------ [2010-05-04 01:53:46 - HelloAndroid] Android Launch! [2010-05-04 01:53:46 - HelloAndroid] adb is running normally. [2010-05-04 01:53:46 - HelloAndroid] Performing com.example.helloandroid.HelloAndroid activity launch [2010-05-04 01:53:46 - HelloAndroid] Automatic Target Mode: launching new emulator with compatible AVD 'myAVD' [2010-05-04 01:53:46 - HelloAndroid] Launching a new emulator with Virtual Device 'myAVD' [2010-05-04 01:53:58 - HelloAndroid] New emulator found: emulator-5554 [2010-05-04 01:53:58 - HelloAndroid] Waiting for HOME ('android.process.acore') to be launched... [2010-05-04 01:53:59 - Emulator] 2010-05-04 01:53:59.501 emulator[10398:903] Warning once: This application, or a library it uses, is using NSQuickDrawView, which has been deprecated. Apps should cease use of QuickDraw and move to Quartz. [2010-05-04 01:54:23 - HelloAndroid] emulator-5554 disconnected! Cancelling 'com.example.helloandroid.HelloAndroid activity launch'! I never do see the text in the emulator and the emulator crashes with a message about it quitting unexpectedly. The actual code is line by line from the tutorial and I have never been able to get to the XML part yet. I am not sure what is wrong with my environment setup or if it is just an incompatibility with Snow Leopard? I would REALLY appreciate any help in resolving this as I am very interested in developing on this platform. Thank-you, Mike N Lawrence, Kansas

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  • emacs: Inferior-mode python-shell appears "lagged"

    - by Begbie00
    Hi all - I'm a Python(3.1.2)/emacs(23.2) newbie teaching myself tkinter using the pythonware tutorial found here. Relevant code is pasted below the question. Question: when I click the Hello button (which should call the say_hi function) why does the inferior python shell (i.e. the one I kicked off with C-c C-c) wait to execute the say_hi print function until I either a) click the Quit button or b) close the root widget down? When I try the same in IDLE, each click of the Hello button produces an immediate print in the IDLE python shell, even before I click Quit or close the root widget. Is there some quirk in the way emacs runs the Python shell (vs. IDLE) that causes this "lagged" behavior? I've noticed similar emacs lags vs. IDLE as I've worked through Project Euler problems, but this is the clearest example I've seen yet. FYI: I use python.el and have a relatively clean init.el... (setq python-python-command "d:/bin/python31/python") is the only line in my init.el. Thanks, Mike === Begin Code=== from tkinter import * class App: def __init__(self,master): frame = Frame(master) frame.pack() self.button = Button(frame, text="QUIT", fg="red", command=frame.quit) self.button.pack(side=LEFT) self.hi_there = Button(frame, text="Hello", command=self.say_hi) self.hi_there.pack(side=LEFT) def say_hi(self): print("hi there, everyone!") root = Tk() app = App(root) root.mainloop()

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  • Why does this data YYYY-MM-DD regex fail in Java?

    - by ProfessionalAmateur
    Hello StackOverFlow, My first question and Im excited... I've lurked since go-live and love the site, however I apologize for any newbie errors, formatting, etc... I'm attempting to validate the format of a string field that contains a date in Java. We will receive the date in a string, I will validate its format before parsing it into a real Date object. The format being passed in is in the YYYY-MM-DD format. However I'm stuck on one of my tests, if I pass in "1999-12-33" the test will fail (as it should with a day number 33) with this incomplete pattern: ((19|20)\\d{2})-([1-9]|0[1-9]|1[0-2])-([12][0-9]|3[01]) However as soon as I add the characters in bold below it passes the test (but should not) ((19|20)\\d{2})-([1-9]|0[1-9]|1[0-2])-(0[1-9]|[1-9]|[12][0-9]|3[01]) *additional note, I know I can change the 0[1-9]|[1-9] into 0?[1-9] but I wanted to break everything down to its most simple format to try and find why this isn't working. Here is the scrap test I've put together to run through all the different date scenarios: import java.util.regex.Matcher; import java.util.regex.Pattern; public class scrapTest { public scrapTest() { } public static void main(String[] args) { scrapTest a = new scrapTest(); boolean flag = a.verfiyDateFormat("1999-12-33"); } private boolean verfiyDateFormat(String dateStr){ Pattern datePattern = Pattern.compile("((19|20)\\d{2})-([1-9]|0[1-9]|1[0-2])-(0[1-9]|[1-9]|[12][0-9]|3[01])"); Matcher dateMatcher = datePattern.matcher(dateStr); if(!dateMatcher.find()){ System.out.println("Invalid date format!!! -> " + dateStr); return false; } System.out.println("Valid date format."); return true; } } Ive been programming for ~10 years but extremely new to Java, so please feel free to explain anything as elementary as you see fit.

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