Search Results

Search found 19716 results on 789 pages for 'zend form'.

Page 133/789 | < Previous Page | 129 130 131 132 133 134 135 136 137 138 139 140  | Next Page >

  • properly setting email subject line delivered from email form

    - by DC1
    I have a email form for my website but here is the issue: when i receive an email, the subject line in my inbox shows whatever the user inputted as subject in the form. id like to override that so that whenever an email comes in. the subject in the email header is always "an inquiry from your website". In the message body, sure i don't mind their specific subject they entered but when I receive an email, id like consistency in my inbox. this is the current code: <?php session_start(); if(isset($_POST['Submit'])) { if( $_SESSION['chapcha_code'] == $_POST['chapcha_code'] && !empty($_SESSION['chapcha_code'] ) ) { $youremail = 'xxxxxxxxx'; $fromsubject = 'An inquiry from your website'; $title = $_POST['title']; $fname = $_POST['fname']; $lname = $_POST['lname']; $mail = $_POST['mail']; $address = $_POST['address']; $city = $_POST['city']; $zip = $_POST['zip']; $country = $_POST['country']; $phone = $_POST['phone']; $subject = $_POST['subject']; $message = $_POST['message']; $headers = "From: $nome <$mail>\r\n"; $to = $youremail; $mailsubject = 'Message received from'.$fromsubject.' Contact Page'; $body = $fromsubject.' The person that contacted you is '.$fname.' '.$lname.' Address: '.$address.' '.$city.', '.$zip.', '.$country.' Phone Number: '.$phone.' E-mail: '.$mail.' Subject: '.$subject.' Message: '.$message.' |---------END MESSAGE----------|'; echo "Thank you for inquiring. We will contact you shortly.<br/>You may return to our <a href='/index.html'>Home Page</a>"; mail($to, $subject, $body, $headers); unset($_SESSION['chapcha_code']); } else { echo 'Sorry, you have provided an invalid security code'; } } else { echo "You must write a message. </br> Please visit our <a href='/contact.html'>Contact Page</a> and try again."; } ?>

    Read the article

  • I have a php form dropdown menu that needs to send information

    - by shinjuo
    I have a dropdown menu that is filled by a mysql database. I need to select one and have it send the information for use on the next page after clicking submit. It does populate the drop down menu like it is supposed to it just does not seem to catch the data on the next page. Here is what I have: removeMain.php <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title></title> </head> <form action="remove.php" method="post"> <?php $link = mysql_connect('********', '********', '*********'); if (!$link){ die('Could not connect: ' . mysql_error()); } mysql_select_db("********", $link); $res = mysql_query("SELECT * FROM cardLists order by cardID") or die(mysql_error()); echo "<select name = CardID>"; while($row=mysql_fetch_assoc($res)) { echo "<option value=$row[ID]>$row[cardID]</a></option>"; } echo "</select>"; ?> Amount to Remove: <input type="text" name="Remove" /> <input type="submit" /> </form> <body> </body> </html> remove.php <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title></title> </head> <body> <?php $link = mysql_connect('*********', '*********', '*********'); if (!$link){ die('Could not connect: ' . mysql_error()); } mysql_select_db("***********y", $link); $query = sprintf("UPDATE cardLists SET AmountLeft = AmountLeft - %s WHERE cardID = '%s'", mysql_real_escape_string($_POST["Remove"]), mysql_real_escape_string($_POST["CardID"])); mysql_query($query); mysql_close($link); ?> <br /> <a href="removeMain.php"> <input type="submit" name="return" id="return" value="Update More" /></a> <a href="index.php"> <input type="submit" name="main" id="main" value="Return To Main" /></a> </body> </html>

    Read the article

  • JSP/Servlet CRUD form with special input field based on join table relationship

    - by user1701467
    There's database with a bunch of tables that are joined with join tables. E.g. Members and Division are joined with MembersDivisions table. JSP/Servlet login functionality has been developed, but now the CRUD functionality needs to be implemented and I was unable to find any tutorials about it, especially involving the join table(when creating new division you can add members to it, or add more to the existing one). Maybe someone could, theoretically, explain how to do the Division part of the CRUD web form?

    Read the article

  • php post form to another php

    - by proyb2
    I want to post a search value from index.php to search.php, index.php <form action="search.php?val=" method="post"> and search.php <?php echo $_GET['val']?> or <?php echo $_POST['val']?> I would like to retain 'val' value in the URL, but search.php could not capture the value of 'val' which appear to be "val=".

    Read the article

  • Jquery Modal Dialog disables form elements

    - by Mr W
    Hi, When I set my jQuery dialog to model=true, it disables my form elements inside the dialog and I cannot use them, only the buttons. I have seen examples where the contents of the dialog is declared in the dialog initiation script and then injected. but that is just to bulky for me, I want to be able to create my markup inside the DIV which I turn into a dialog. Anyone got a solution for me?

    Read the article

  • new form in portlet

    - by srinath
    Hi, How to redirect to new different form page in Grails portlets . When click on "New User" it should show new.gsp (here). but this is not happening and always redirects to view.gsp . I'm using like this in view.gsp : a href="${portletResponse.createActionURL()}" name="new_user" id="new_user"New User please suggest me .

    Read the article

  • Winforms: calling entry form function from a different class

    - by samy
    I'm kinda new to programming and got a question on what is a good practice. I created a class that represents a ball and it has a function Jump() that use 2 timers and get the ball up and down. I know that in Winforms you got to call Invalidate() every time you want to repaint the screen, or part of it. I didn't find a good way to do that, so I reference the form in my class, and called Invalidate() inside my ball class every time I need to repaint to ball movement. (this works but I got a feeling that this is not a good practice) Here is the class I created: public class Ball { public Form1 parent;//----> here is the reference to the form public Rectangle ball; Size size; public Point p; Timer timerBallGoUp = new Timer(); Timer timerBallGDown = new Timer(); public int ballY; public Ball(Size _size, Point _p) { size = _size; p = _p; ball = new Rectangle(p, size); } public void Jump() { ballY = p.Y; timerBallGDown.Elapsed += ballGoDown; timerBallGDown.Interval = 50; timerBallGoUp.Elapsed += ballGoUp; timerBallGoUp.Interval = 50; timerBallGoUp.Start(); } private void ballGoUp(object obj,ElapsedEventArgs e) { p.Y++; ball.Location = new Point(ball.Location.X, p.Y); if (p.Y >= ballY + 50) { timerBallGoUp.Stop(); timerBallGDown.Start(); } parent.Invalidate(); // here i call parent.Invalidate() 1 } private void ballGoDown(object obj, ElapsedEventArgs e) { p.Y--; ball.Location = new Point(ball.Location.X, p.Y); if (p.Y <= ballY) { timerBallGDown.Stop(); timerBallGoUp.Start(); } parent.Invalidate(); // here i call parent.Invalidate() 2 } } I'm wondring if there is a better way to do that? (sorry for my english)

    Read the article

  • To HTMLENCODE or not to HTMLENCODE user input on web form (asp.net vb)

    - by Phil
    I have many params making up an insert form for example: x.Parameters.AddWithValue("@city", City.Text) I had a failed xss attack on the site this morning, so I am trying to beef up security measures anyway.... Should I be adding my input params like this? x.Parameters.AddWithValue("@city", HttpUtility.HtmlEncode(City.Text)) Is there anything else I should consider to avoid attacks? Thanks

    Read the article

  • Complex form widgets in Django

    - by Shekhar
    I am looking for good helper libraries to generate a rather complex form in Django. Dynamic field dependencies: Say if option a is selected certain fields are shown/hidden and subset of these are mandatory depending on option selection. Add more: On clicking "Add more" button that clones some widget. This is something which ToscaWidgets is capable of handle. http://toscawidgets.org/documentation/tw.dynforms/tutorial.html#growing Currently I am managing this with some jquery code however not completely satisfied. TIA

    Read the article

  • android form Fields grouping?

    - by UMMA
    dear friends, i want to know that is there any way to create groups in a form? i am not talking about heading but groups we make with borders around set of specified field sets.(field sets are for example TextView,EditText and button). for example. Vital information: ----- Other information ----- any help would be appriciated.

    Read the article

  • Visual ++ print from main with inheritance on visual form in listbox

    - by captencrunch
    I´ve made a "main" class lets call it A(Veichle), and i have two classes that inherits from A Lets call them B(Car) and C(MC). i also have a handler lets call it "D" that binds A,B and C. Then i have the Form1 class lets call that E(Visual) I want to print out the private members from A on the visual form "E" in a Listbox If i try ex) this-listbox1-items-add(X.veichles[i]-getBrand()); it complains that veichles is a private member in D. How can i get around that?

    Read the article

  • Strict doctype - form and input element

    - by David
    Does anyone know the reasoning behind the strict doctype not allowing input elements to be direct descendents of a form element. I find it annoying that i have to wrap a submit button which is a block level element inside another block level element say a fieldset or a div. However, I cannot find an answer anywhere as to why this actually is.

    Read the article

  • Form resubmission issue-Django html

    - by Hulk
    There is a form ,which is submitted and then the page is redirected to another page.But if the user hits the refresh button again on the new page .the following message is displayed To display this page, Firefox must send information that will repeat any action (such as a search or order confirmation) that was performed earlier. And on press "OK" A duplicate entry is created how do i prevent this or how do i handle this I am using a django,application Thanks..

    Read the article

  • form a number using consecutive numbers

    - by Mahesh
    Hi, I was puzzled with one of the question in Microsoft interview which is as given below: A function should accept a range( 3 - 21 ) and it should print all the consecutive numbers combination's to form each number as given below: 3=1+2 5=2+3 6=1+2+3 7=3+4 9=4+5 10=1+2+3+4 11=5+6 13=6+7 15=1+2+3+4+5 17=7+8 19=8+9 21=10+11 21=1+2+3+4+5+6 could you please help me in forming this sequence in C#? Thanks, Mahesh

    Read the article

< Previous Page | 129 130 131 132 133 134 135 136 137 138 139 140  | Next Page >