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  • Converting DTOs to View Models

    - by illvm
    Does anyone know of a good (read: quick to code) method for converting DTOs to View Models or mapping DTO members to View Model members? Lately I've been finding myself writing many conversion and helper methods but this is a very arduous and tedious task. Moreover, it will often needs to be done twice (DTO - View Model, View Model - DTO). Is there a methodology, technique, or technology which would allow me to do this more quickly and efficiently?

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  • Django: Set foreign key using integer?

    - by User
    Is there a way to set foreign key relationship using the integer id of a model? This would be for optimization purposes. For example, suppose I have an Employee model: class Employee(models.Model): first_name = models.CharField(max_length=100) last_name = models.CharField(max_length=100) type = models.ForeignKey('EmployeeType') and EmployeeType(models.Model): type = models.CharField(max_length=100) I want the flexibility of having unlimited employee types, but in the deployed application there will likely be only a single type so I'm wondering if there is a way to hardcode the id and set the relationship this way. This way I can avoid a db call to get the EmployeeType object first.

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  • Why the HelloWorld of opennlp library works fine on Java but doesn't work with Jruby?

    - by 0x90
    I am getting this error: SyntaxError: hello.rb:13: syntax error, unexpected tIDENTIFIER public HelloWorld( InputStream data ) throws IOException { The HelloWorld.rb is: require "java" import java.io.FileInputStream; import java.io.InputStream; import java.io.IOException; import opennlp.tools.postag.POSModel; import opennlp.tools.postag.POSTaggerME; public class HelloWorld { private POSModel model; public HelloWorld( InputStream data ) throws IOException { setModel( new POSModel( data ) ); } public void run( String sentence ) { POSTaggerME tagger = new POSTaggerME( getModel() ); String[] words = sentence.split( "\\s+" ); String[] tags = tagger.tag( words ); double[] probs = tagger.probs(); for( int i = 0; i < tags.length; i++ ) { System.out.println( words[i] + " => " + tags[i] + " @ " + probs[i] ); } } private void setModel( POSModel model ) { this.model = model; } private POSModel getModel() { return this.model; } public static void main( String args[] ) throws IOException { if( args.length < 2 ) { System.out.println( "HelloWord <file> \"sentence to tag\"" ); return; } InputStream is = new FileInputStream( args[0] ); HelloWorld hw = new HelloWorld( is ); is.close(); hw.run( args[1] ); } } when running ruby HelloWorld.rb "I am trying to make it work" when I run the HelloWorld.java "I am trying to make it work" it works perfectly, of course the .java doesn't contain the require java statement. EDIT: I followed the following steps. The output for jruby -v : jruby 1.6.7.2 (ruby-1.8.7-p357) (2012-05-01 26e08ba) (Java HotSpot(TM) 64-Bit Server VM 1.6.0_35) [darwin-x86_64-java]

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  • When using Dependency Injection with StructureMap how do I chooose among multiple constructors?

    - by Mark Rogers
    I'm trying to get structuremap to build Fluent Nhibernate's SessionSource object for some of my intregration tests. The only problem is that Fluent's concrete implementation of ISessionSource (SessionSource) has 3 constructors: public SessionSource(PersistenceModel model) { Initialize(new Configuration().Configure(), model); } public SessionSource(IDictionary<string, string> properties, PersistenceModel model) { Initialize(new Configuration().AddProperties(properties), model); } public SessionSource(FluentConfiguration config) { configuration = config.Configuration; sessionFactory = config.BuildSessionFactory(); dialect = Dialect.GetDialect(configuration.Properties); } I've tried configuring my ObjectFactory supplying an argument for the first constructor but it seems like it wants to try the second one. How do I configure my ObjectFactory so that I can choose the first constructor or perhaps even another one if I decide to use that?

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  • Simplest way to extend doctrine for MVC Models

    - by RobertPitt
    Im developing my own framework that uses namespaces. Doctrine is already integrated into my auto loading system and im now at the stage where ill be creating the model system for my application Usually i would create a simple model like so: namespace Application\Models; class Users extends \Framework\Models\Database{} which would inherit all the default database model methods, But with Doctrine im still learning how it all works, as its not just a simple DBAL. I need to understand whats the part of doctrine my classes would extend where i can do the following: namespace Application\Models; class Users Extends Doctrine\Something\Table { public $__table_name = "users"; } And thus within the controller i would be able to do the following: public function Display($uid) { $User = $this->Model->Users->findOne(array("id" => (int)$id)); } Anyone help me get my head around this ?

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  • Django form and User data

    - by Dean
    I have a model that looks like this: class Client(models.Model): name = models.CharField(max_length=100, primary_key=True) user = models.ForeignKey(User) class Contract(models.Model): title = models.CharField(max_length=100, primary_key=True) start_date = models.DateField() end_date = models.DateField() description = models.TextField() client = models.ForeignKey(Client) user = models.ForeignKey(User) How can i configure a django form so that only clients associated with that user show in the field in the form? My initial thought was this in my forms.py: client = forms.ModelChoiceField(queryset=Client.objects.filter(user__username = User.username)) But it didn't work. So how else would I go about it?

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  • How can I inherit an ASP.NET MVC controller and change only the view?

    - by AlexWalker
    I have a controller that's inheriting from a base controller, and I'm wondering how I can utilize all of the logic from the base controller, but return a different view than the base controller uses. The base controller populates a model object and passes that model object to its view, but I'm not sure how I can access that model object in the child controller so that I can pass it to the child controller's view.

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  • django access to parent

    - by SledgehammerPL
    model: class Product(models.Model): name = models.CharField(max_length = 128) (...) def __unicode__(self): return self.name class Receipt(models.Model): name = models.CharField(max_length=128) (...) components = models.ManyToManyField(Product, through='ReceiptComponent') def __unicode__(self): return self.name class ReceiptComponent(models.Model): product = models.ForeignKey(Product) receipt = models.ForeignKey(Receipt) quantity = models.FloatField(max_length=9) unit = models.ForeignKey(Unit) def __unicode__(self): return unicode(self.quantity!=0 and self.quantity or '') + ' ' + unicode(self.unit) + ' ' + self.product.genitive And now I'd like to get list of the most often useable products: ReceiptComponent.objects.values('product').annotate(Count('product')).order_by('-product__count' the example result: [{'product': 3, 'product__count': 5}, {'product': 6, 'product__count': 4}, {'product': 5, 'product__count': 3}, {'product': 7, 'product__count': 2}, {'product': 1, 'product__count': 2}, {'product': 11, 'product__count': 1}, {'product': 8, 'product__count': 1}, {'product': 4, 'product__count': 1}, {'product': 9, 'product__count': 1}] It's almost what I need. But I'd prefer having Product object not product value, because I'd like to use this in views.py for generating list.

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  • Custom constructors for models in Google App Engine (python)

    - by Nikhil Chelliah
    I'm getting back to programming for Google App Engine and I've found, in old, unused code, instances in which I wrote constructors for models. It seems like a good idea, but there's no mention of it online and I can't test to see if it works. Here's a contrived example, with no error-checking, etc.: class Dog(db.Model): name = db.StringProperty(required=True) breeds = db.StringListProperty() age = db.IntegerProperty(default=0) def __init__(self, name, breed_list, **kwargs): db.Model.__init__(**kwargs) self.name = name self.breeds = breed_list.split() rufus = Dog('Rufus', 'spaniel terrier labrador') rufus.put() The **kwargs are passed on to the Model constructor in case the model is constructed with a specified parent or key_name, or in case other properties (like age) are specified. This constructor differs from the default in that it requires that a name and breed_list be specified (although it can't ensure that they're strings), and it parses breed_list in a way that the default constructor could not. Is this a legitimate form of instantiation, or should I just use functions or static/class methods? And if it works, why aren't custom constructors used more often?

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  • How to make item view render rich (html) text in PyQt?

    - by Giorgio Gelardi
    I'm trying to translate code from this thread in python: import sys from PyQt4.QtCore import * from PyQt4.QtGui import * __data__ = [ "Lorem ipsum dolor sit amet, consectetur adipisicing elit, sed do eiusmod tempor incididunt ut labore et dolore magna aliqua.", "Ut enim ad minim veniam, quis nostrud exercitation ullamco laboris nisi ut aliquip ex ea commodo consequat.", "Duis aute irure dolor in reprehenderit in voluptate velit esse cillum dolore eu fugiat nulla pariatur.", "Excepteur sint occaecat cupidatat non proident, sunt in culpa qui officia deserunt mollit anim id est laborum." ] def get_html_box(text): return '''<table border="0" width="100%"><tr width="100%" valign="top"> <td width="1%"><img src="softwarecenter.png"/></td> <td><table border="0" width="100%" height="100%"> <tr><td><b><a href="http://www.google.com">titolo</a></b></td></tr> <tr><td>{0}</td></tr><tr><td align="right">88/88/8888, 88:88</td></tr> </table></td></tr></table>'''.format(text) class HTMLDelegate(QStyledItemDelegate): def paint(self, painter, option, index): model = index.model() record = model.listdata[index.row()] doc = QTextDocument(self) doc.setHtml(get_html_box(record)) doc.setTextWidth(option.rect.width()) painter.save() ctx = QAbstractTextDocumentLayout.PaintContext() ctx.clip = QRectF(0, option.rect.top(), option.rect.width(), option.rect.height()) dl = doc.documentLayout() dl.draw(painter, ctx) painter.restore() def sizeHint(self, option, index): model = index.model() record = model.listdata[index.row()] doc = QTextDocument(self) doc.setHtml(get_html_box(record)) doc.setTextWidth(option.rect.width()) return QSize(doc.idealWidth(), doc.size().height()) class MyListModel(QAbstractListModel): def __init__(self, parent=None, *args): super(MyListModel, self).__init__(parent, *args) self.listdata = __data__ def rowCount(self, parent=QModelIndex()): return len(self.listdata) def data(self, index, role=Qt.DisplayRole): return index.isValid() and QVariant(self.listdata[index.row()]) or QVariant() class MyWindow(QWidget): def __init__(self, *args): super(MyWindow, self).__init__(*args) # listview self.lv = QListView() self.lv.setModel(MyListModel(self)) self.lv.setItemDelegate(HTMLDelegate(self)) self.lv.setResizeMode(QListView.Adjust) # layout layout = QVBoxLayout() layout.addWidget(self.lv) self.setLayout(layout) if __name__ == "__main__": app = QApplication(sys.argv) w = MyWindow() w.show() sys.exit(app.exec_()) Element's size and position are not calculated correctly I guess, perhaps because I haven't understand at all the style related parts from original code. Can someone help me?

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  • Using a backwards relation (i.e FOO_set) for ModelChoiceField in Django

    - by Bwmat
    I have a model called Movie, which has a ManyToManyField called director to a model called Person, and I'm trying to create a form with ModelChoiceField like so: class MovieSearchForm(forms.Form): producer = forms.ModelChoiceField(label='Produced by', queryset=movies.models.Person.producer_set, required=False) but this seems to be failing to compile (I'm getting a ViewDoesNotExist exception for the view that uses the form, but it goes away if I just replace the queryset with all the person objects), I'm guessing because '.producer_set' is being evaluated too 'early'. How can I get this work? here are the relevant parts of the movie/person classes: class Person(models.Model): name = models.CharField(max_length=100) class Movie(models.Model): ... producer = models.ForeignKey(Person, related_name="producers") director = models.ForeignKey(Person, related_name="directors") What I'm trying to do is get ever Person who is used in the producer field of some Movie.

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  • How do I use Asp MVC Url Helpers to generate RESTful links?

    - by Josh
    I'm trying to use Html.ActionLink to generate a link with in this form: /Action/Model/Id/Parameter1/Parameter2 I've used: <%= Html.ActionLink("Link Text", "Action", "Model", new { id = var, parament1=var1 }, null) % but it always ends up looking like /Action/Model/Id?parameter1=variable I've seen similar questions on Stackoverflow and elsewhere, but I can't find a solution that works/makes sense. Any help would be appreciated.

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  • Class name to view path

    - by Alexey Poimtsev
    Hi, I have a RoR application and model SomeModel. I have views for this model and I want to know - is there any method to get the view's path? Of course I can use for this model instance m = SomeModel.new v = m.class.class_name.pluralize.downcase It's working, but maybe you know a better way? :)

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  • DJANGO complex modelling

    - by SledgehammerPL
    Hello. I have such model now: receipt contains components. component contain product. The difference between component and product is, that component has quantity and measure unit: eg. component is 100g sugar - sugar is a product. So I need to make lots of components to satisfy different recipes - 100g sugar is not equal 200g sugar I wonder if I can remodel it to kick off components - in pure sql it's rather easy, but I'm trying to USE django - not making workarounds. class Receipt(models.Model): name = models.CharField(max_length=128) (...) components = models.ManyToManyField(Component) class Component(models.Model): quantity = models.FloatField(max_length=9) unit = models.ForeignKey(Unit) product = models.ForeignKey(Product) class Product(models.Model): name = models.CharField(max_length = 128) TIA

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  • How can I order fields in Django ModelForm?

    - by joozek
    I have an 'order' Model: class Order(models.Model): date_time=models.DateTimeField() # other stuff And I'm using Django ModelForm class to render a form, but I want to display date and time widgets separately. I've came up with this: class Form(forms.ModelForm): class Meta: model = Order exclude = ('date_time',) date = forms.DateField() time = forms.TimeField() The problem is that I want to put these fields somewhere between 'other stuff'

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  • MySQL searching using many 'like' operators: is there a better way?

    - by DrAgonmoray
    I have a page that gets all rows from a table in a database, then displays the rows in an HTML table. That works great, but now I want to implement a 'search' feature. There is a searchbox, and search-terms are separated by a space. I am going to make it search three fields for the search terms, 'make' 'model' and 'type.' These three fields are VARCHAR(30). Currently if I wanted to search using 3 terms (say 'cool' 'abc' and '123') my query would look something like this. SELECT * FROM table WHERE make LIKE '%cool%' OR make LIKE '%abc%' OR make LIKE '%123%' OR model LIKE '%cool%' OR model LIKE '%abc%' OR model LIKE '%123%' OR type LIKE '%cool%' OR type LIKE '%abc%' OR type LIKE '%123%' That looks really bad, and it will get even worse if there are more search terms or more fields to search. My question to you: is there a better way to search? If so, what?

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  • Bind Child table data on View field- MVC ASP.Net

    - by Tassadaque
    I have two tables Contact and Addresses. Addresses is the child table of Contact. When i create view for Contact. i also want to get addresses for user as many as user wants. For contact table i bind the textbox and add validation like this <%= Html.TextBoxFor(model => model.ContactName) %> <%= Html.ValidationMessageFor(model => model.ContactName) %> Now my question is that how can i bind address field on create view screen. Regards Tassadaque

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  • c# Lambda Expression built with LinqKit does not compile

    - by Frank Michael Kraft
    This lambda does not compile, but I do not understand why. using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Linq.Expressions; using LinqKit; namespace ConsoleApplication2 { class Program { static void Main(string[] args) { var barModel = new BarModel(); string id = "some"; Console.WriteLine(barModel.subFor(id).ToString()); // output: m => (True AndAlso (m.key == value(ConsoleApplication2.Bar`1+<>c__DisplayClass0[ConsoleApplication2.Model]).id)) Console.ReadKey(); var subworkitems = barModel.list.Where(barModel.subFor(id).Compile()); // Exception {"variable 'm' of type 'ConsoleApplication2.Model' referenced from scope '', but it is not defined"} Console.WriteLine(subworkitems.ToString()); Console.ReadKey(); } } class Bar<TModel> { public Bar(Expression<Func<TModel, string>> foreignKeyExpression) { _foreignKeyExpression = foreignKeyExpression; } private Expression<Func<TModel, string>> _foreignKeyExpression { get; set; } public Expression<Func<TModel, bool>> subFor(string id) { var ex = forTargetId(id); return ex; } public Expression<Func<TModel, bool>> forTargetId(String id) { var fc = _foreignKeyExpression; Expression<Func<TModel, bool>> predicate = m => true; var result = predicate.And(m => fc.Invoke(m) == id).Expand(); return result; } } class Model { public string key; public string value; } class BarModel : Bar<Model> { public List<Model> list; public BarModel() : base(m => m.key) { list = new List<Model>(); } } }

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  • How do I specify (1) an order and (2) a meaninful string representation for users in my Django application?

    - by David Faux
    I have a Django application with users. I have a model called "Course" with a foreign key called "teacher" to the default User model that Django provides: class Course(models.Model): ... teacher = models.ForeignKey(User, related_name='courses_taught') When I create a model form to edit information for individual courses, the possible users for the teacher field appear in this long select menu of user names. These users are ordered by ID, which is of meager use to me. How can I order these users by their last names? change the string representation of the User class to be "Firstname Lastname (username)" instead of "username"?

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  • Saving multiple select form data in db

    - by fl00r
    Hi. I've got form for some model A, which has got few fields: tile description ... colors colors are selected from multiple select and options are ['red', 'green', 'blue', 'yellow']. User can choose colors as many as he wants. I don't think that making Color model and has_many relationship is good solution here to store colors data in model A. So question is: How to store multiple data in db for such multiple select forms?

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  • django updating m2m field

    - by Marconi
    I have a model service and a ModelForm named Service which I use to add and update the service model. The model looks like this: class Service(models.Model): categories = models.ManyToManyField(Category) The categories field is displayed as a tag with that allows multiple selection. It works well when I'm adding a new record but when I'm updating it, only one service is showing up on the request.POST['categories'] even if I selected multiple categories. I tried dumping the request object and I can see that the categories is showing something like: u'categories': [u'3', u'4', u'2'] I tried calling the request._get_post() and it did return only 1 category, hence the request.POST['categories'] returns only 1. Anybody who knows what's happening and how to fix it?

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  • iPhone MVC Question

    - by HM1
    Hi, I'm bit of a newbie and had a basic question regarding adhering to the MVC model in iPhone coding. How do I setup a Model class that holds my data and connect it to different controllers in the following setup: Using Interface Builder, I created a tab controller in which - Tab #1 has a Nav Controller and a hierarchy of View Controllers. - Tab #2 has a View Controller So with what I have now, the View Controller under Tab #1 alloc init's the model class and I know how to pass the model from one ViewController to the next in the Navigation Hierarchy where it can pass the data and/or be updated with new data. Question is how to pass it from Tab #1's View Controller to Tab #2 View Controller as there is no code linking the two??? Thanks in advance, Hiren.

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  • WPF StaticResource bound to subproperty

    - by mizipzor
    I have a class thats created as a resource: <Window.Resources> <Model:MyModel x:Key="model" /> </Window.Resources> The MyModel class has a cli property named Foo. I want the selected value in a combobox to be bound to this property. I thought I could do this but Im getting errors: <ComboBox SelectedItem="{Binding Source={StaticResource model.Foo}}" /> Heres the error: Cannot find resource named '{model.Foo}'. Where did I go wrong? What extra parameters do I need to specify to properly bind to a subproperty?

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  • Accessing inter-schema tables and relations in hibernate

    - by nitesh
    There is a typical situation being faced where different tables are scattered through different schemas in Oracle database and they are related to each other (encompassing all different types of relations). How can they be represented in Hibernate using annotations as when a sessionfactory handle is created for one schema, tables in that schema can't access other related tables (foreign key relation to tables in other schema)? For a query like following, exception is thrown - "from table1 as model where model.table2Name.table2column = "+foo Exception comes as - org.hibernate.QueryException: could not resolve property: table2column of: com.test.table1 [from com.test.table1 as model where model.table2Name.table2column = 1] Here table1 and table2 are present in different schemas.

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