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  • select distinct over specific columns

    - by Midhat
    A query in a system I maintain returns QID AID DATA 1 2 x 1 2 y 5 6 t As per a new requirement, I do not want the (QID, AID)=(1,2) pair to be repeated. We also dont care what value is selected from "data" column. either x or y will do. What I have done is to enclose the original query like this SELECT * FROM (<original query text>) Results group by QID,AID Is there a better way to go about this? The original query uses multiple joins and unions and what not, So I would prefer not to touch it unless its absolutely necesary

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  • INSERT INTO othertbl SELECT * tbl

    - by Harry
    Current situation: INSERT INTO othertbl SELECT * FROM tbl WHERE id = '1' So i want to copy a record from tbl to othertbl. Both tables have an autoincremented unique index. Now the new record should have a new index, rather then the value of the index of the originating record else copying results in a index not unique error. A solution would be to not use the * but since these tables have quite some columns i really think it's getting ugly. So,.. is there a better way to copy a record which results in a new record in othertbl which has a new autoincremented index without having to write out all columns in the query and using a NULL value for the index. -hope it makes sense....-

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  • Select past date from database x days from now

    - by Pr0no
    Consider the following table daterange _date trading_day ------------------------ 2011-08-01 1 2011-07-31 0 2011-07-30 0 2011-07-29 1 2011-07-28 1 2011-07-27 1 2011-07-26 1 2011-07-25 1 2011-07-24 0 2011-07-23 0 2011-07-22 1 2011-07-21 1 2011-07-20 1 2011-07-19 1 2011-07-18 1 2011-07-17 0 I'm in need of a query that returns a _date, x days before a given _date. When counting back, _days with trading_day = 0 should be ignored. A few examples: input | output -------------------------+------------ 1 day before 2011-07-19 | 2011-07-18 2 days before 2011-08-01 | 2011-07-28 (trading_day = 0 don't count) 3 days before 2011-07-29 | 2001-07-26 The first one is easy: SELECT _date FROM daterange WHERE trading_day = 0 AND _date < '2011-07-19' LIMIT 1 But I don't know how to query for the other examples. Do you?

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  • Select products with users

    - by Ploppe
    I have not worked with SQL for quite a long time, and I need some help for a basic query. I have the three following tables: users (id, name) products (id, name) owners (userid, productid, date) One product can be sold by user A to user B and then back to A. Now, I want the list of all products currently owned by every single user with the date of transaction. Currently, my query is this one, but I'm stuck with old data (first association of one product to one user, and not the newest one): SELECT users.name, products.name, date FROM products JOIN owners ON products.id = owners.id JOIN users ON owners.id = user.id GROUP BY product.id Do you have some hints? Thanks

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  • SELECT * , COUNT( * ) FROM GROUP BY ORDER BY DESC

    - by quanganh_developer
    I have a table like: gold gold_city | gold_type | gold_selltime ------------------------------------- city1 | type 1 | 2012-01-01 city1 | type 1 | 2012-02-02 city1 | type 1 | 2012-03-03 city2 | type 2 | 2012-01-01 city2 | type 2 | 2012-02-02 city2 | type 2 | 2012-03-03 city3 | type 3 | 2012-01-01 city3 | type 3 | 2012-02-02 city3 | type 3 | 2012-03-03 How can I get 1 last result order by gold_selltime desc each group by gold_city and gold_type I used this: SELECT * , COUNT( * ) FROM gold_2012 GROUP BY gold_type , gold_city ORDER BY gold_selltime DESC but it did work. I only have result like: gold_city | gold_type | gold_selltime ------------------------------------- city1 | type 1 | 2012-01-01 city2 | type 2 | 2012-01-01 city3 | type 3 | 2012-01-01 but I need it like: gold_city | gold_type | gold_selltime ------------------------------------- city1 | type 1 | 2012-03-03 city2 | type 2 | 2012-03-03 city3 | type 3 | 2012-03-03

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  • Mysql SELECT and INSERT Error

    - by nepaliking
    I am using sort field in order to sort records. My code is this $query = "SELECT max(sort) FROM $this->table LIMIT 1;"; $result = mysql_query($query); $row = mysql_fetch_row($result); $sort = $row[0]+1; $query = "INSERT INTO "$this->table." VALUES ( '', '$ini', '$time', '$ip', '0', '$type', '$sort', '$title', '$image', '0' );"; $result = mysql_query($query) or die(mysql_error()); What is the error here?

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  • how to define service runlevel order position?

    - by DmitrySemenov
    I setup bind-dlz and need mysql start prior NAMED when system starts here is what I have [root@semenov]# ./test.sh mysql 0:off 1:off 2:on 3:on 4:on 5:on 6:off named 0:off 1:off 2:off 3:on 4:on 5:on 6:off lrwxrwxrwx. 1 root root 15 Apr 15 18:57 /etc/rc3.d/S93mysql -> ../init.d/mysql lrwxrwxrwx. 1 root root 15 Apr 15 18:57 /etc/rc3.d/S90named -> ../init.d/named here is what I have in mysql init script # Comments to support chkconfig on RedHat Linux # chkconfig: 2345 84 16 # description: A very fast and reliable SQL database engine. # Comments to support LSB init script conventions ### BEGIN INIT INFO # Provides: mysql # Required-Start: $local_fs $network $remote_fs # Should-Start: ypbind nscd ldap ntpd xntpd # Required-Stop: $local_fs $network $remote_fs # Default-Start: 2 3 4 5 # Default-Stop: 0 1 6 # Short-Description: start and stop MySQL # Description: MySQL is a very fast and reliable SQL database engine. ### END INIT INFO so when I remove named from chkconfig and have there just mysql, it starts with order number 84: /etc/rc3.d/S84mysql - ../init.d/mysql but when I add named inside chkconfig it's order changes to 93: /etc/rc3.d/S93mysql - ../init.d/mysql as a result mysql will be starting after named and named will fail (no sql available) any ideas what I'm doing wrong? here is what I have in named init script # chkconfig: 345 90 16 # description: named (BIND) is a Domain Name Server (DNS) \ # that is used to resolve host names to IP addresses. # probe: true ### BEGIN INIT INFO # Provides: $named # Required-Start: $local_fs $network $syslog # Required-Stop: $local_fs $network $syslog # Default-Start:2 3 4 # Default-Stop: 0 1 2 3 4 5 6 # Short-Description: start|stop|status|restart|try-restart|reload|force-reload DNS server # Description: control ISC BIND implementation of DNS server ### END INIT INFO thanks, Dmitry

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  • Wordpress SQL Select Multiple Meta Values / Meta Keys / Custom Fields

    - by Wes
    I am trying to modify a wordpress / MySQL function to display a little more information. I'm currently running the following query that selects the post, joins the 'postmeta' and gets the info where the meta_key = _liked function most_liked_posts($numberOf, $before, $after, $show_count) { global $wpdb; $request = "SELECT ID, post_title, meta_value FROM $wpdb->posts, $wpdb->postmeta"; $request .= " WHERE $wpdb->posts.ID = $wpdb->postmeta.post_id"; $request .= " AND post_status='publish' AND post_type='post' AND meta_key='_liked' "; $request .= " ORDER BY $wpdb->postmeta.meta_value+0 DESC LIMIT $numberOf"; $posts = $wpdb->get_results($request); foreach ($posts as $post) { $post_title = stripslashes($post->post_title); $permalink = get_permalink($post->ID); $post_count = $post->meta_value; echo $before.'<a href="' . $permalink . '" title="' . $post_title.'" rel="nofollow">' . $post_title . '</a>'; echo $show_count == '1' ? ' ('.$post_count.')' : ''; echo $after; } } The important part being: $post_count = $post->meta_value; But now I want to also grab a value that is attached to each post called wbphoto How do I specify that $post_count = _liked and $photo = wbphoto ? Here is a screen cap of my Phpmyadmin

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  • Algorithm To Select Most Popular Places from Database

    - by Russell C.
    We have a website that contains a database of places. For each place our users are able to take one of the follow actions which we record: VIEW - View it's profile RATING - Rate it on a scale of 1-5 stars REVIEW - Review it COMPLETED - Mark that they've been there WISH LIST - Mark that they want to go there FAVORITE - Mark that it's one of their favorites In our database table of places each place contains a count of the number of times each action above was taken as well as the average rating given by users. views ratings avg_rating completed wishlist favorite What we want to be able to do is generate lists of the top places using the above information. Ideally, we would want to be able to generate this list using a relatively simple SQL query without needing to do any legwork to calculate additional fields or stack rank places against one another. That being said, since we only have about 50,000 places we could run a nightly cron job to calculate some fields such as rankings on different categories if it would make a meaningful difference in the overall results of our top places. I'd appreciate if you could make some suggestions on how we should think about bubbling the best places to the top, which criteria we should weight more heavily, and given that information - suggest what the MySQL query would need to look like in order to select the top 10 places. One thing to note is that at this time we are less concerned with the recency of a place being popular - meaning that looking at the aggregate information is fine and that more recent data doesn't need to be weighted more heavily. Thanks in advance for your help & advice!

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  • MYSQL - SELECT ALL FROM TABLE if...

    - by hornetbzz
    Hello I have a (nice) mysql table built like this : Fields Datas id (pk) 1 2 3 4 5 6 master_id 1000 1000 1000 2000 2000 2000 ... master_name home home home shop shop shop ... type_data value common client value common client ... param_a foo_a 1 0 bar_a 0 1 ... param_b foo_b 1 0 bar_b 1 0 ... param_c foo_c 0 1 bar_c 0 1 ... ... ... ... ... ... ... ... ... All these datas are embed in a single table. Each datas are dispatched on 3 "columns" set (1 for the values, 1 for identifying if these are common values and one for identifying client values). It's not the best I got but many other scripts depends on this structure. I'd need sthg like this: SELECT parameters name (eg param_a, param_b..) and their values (eg foo_a, foo_b..) WHEN master_id=? AND type_data=(common or client) (eg for values=1 on the 2nd column) . in order to get the parameters hash like param_a => foo_a param_b => foo_b param_c => foo_c ... I could not succeed in self joining on the same table till now but I guess it should be feasible. (I'd like to avoid to do several queries) Thx in advance

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  • mySQL select and group by values

    - by Foo
    I'd like to count and group rows by specific values. This seems fairly simple, but I can't seem to do it. I have a table set up similar to this: Table: Ratings id pID uID rating 1 1 2 7 2 1 7 7 3 1 5 4 4 1 1 1 id is the primary key, piD and uID are foreign-keys. Rating contains values between 1 and 10, and only between 1 and 10. I want to run some statistics and count the number of ratings with a certain value. In the example above, two have left a rating of 7. So I wrote the following query: SELECT COUNT(*) AS 'count' , 'rating' FROM 'ratings' WHERE pID= '1' GROUP BY `rating` ORDER BY `rating` Which yields the nice result as: count ratings 1 1 1 4 2 7 I'd like to get the mySQL query to include values between 1 and 10 as well. For example: Desired Result count ratings 1 1 0 2 0 3 1 4 0 5 0 6 2 7 0 8 0 9 0 10 Unfortunately, I'm relatively new to SQL and I've been reading through everything I could get my hands on for the past hour, but I can't get it to work. I've been leaning along the lines of a some type of JOIN. If anyone can point me in the right direction, it'd be appreciated. Thanks.

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  • Count Email Address Domains

    - by BRADINO
    A quick tidbit I came up with today to count email addresses in a mysql database table grouping them by domain. So say for example you have a large list of subscribers and you want to see the breakdown of people who use Hotmail, Yahoo, Gmail, etc. SELECT COUNT( SUBSTRING_INDEX( `email` , '@', -1 ) ) AS `count` , SUBSTRING_INDEX( `email` , '@', -1 ) AS `domain` FROM `subscribers` WHERE `email` != '' GROUP BY `domain` ORDER BY `count` DESC This sql statement assumes that the table is called 'subscribers' and the column containing the email addresses is 'email'. Change these two values to match your table name and email address column name. mysql count email mysql count domain mysql split email mysql split domain

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  • ...Welche DB-Hintergrundprozesse sind für was zuständig?... wie ging das nochmal? Und wie heisst noch diese eine wichtige Data Dictionary View? ...

    - by britta.wolf
    ...Gab es da nicht mal ein gutes Oracle-Poster, wo man schnell nachschauen konnte und einen guten Überblick bekam? Viele Datenbankadministratoren haben das besagte Poster, das die Architektur und Prozesse sowie die Data Dictionary-Struktur der Oracle Datenbank beschreibt, vermisst! Daher wurde nun eine handliche kleine Flash-Applikation mit erweitertem Inhalt entwickelt - Oracle Database 11g: Interactive Quick Reference - die man sich hier downloaden kann (einfach auf den Button "Download now" klicken (Größe der Zip-Datei: 4.6 MB). Ist genial, muss man haben!!! :-)

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  • DB Documentation Tool

    - by Hisham El-bereky
     Recently I have uploaded new project to codeplex site, DbDocument or DbDoc project is a helper tool used side by side with MS SQL server management studio tool, you can design your DB Tables in visualized way through Diagrams and then use “DbDoc” tool to generate design document in MS Word format, the generated file can be used in design review process or as history reference, the tool facilitate and reduce the time of writing DB structure documentthe current version is not so sophisticated which is intend to generate word document in table format with all tables in DB illustrating its structure and constraints, but for now it seems to be good.   For more details check DbDoc document or go immediately to DbDoc home page http://dbdocument.codeplex.com/

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  • EPM 11.1.2 - Issues during configuration when using Oracle DB if not using UTF8

    - by Ahmed A
    If you see issues during configuration when using Oracle DB if not using UTF8: Workaround: a. During configuration of EPM products, a warning message is displayed if the Oracle DB is not UTF8 enabled. If you continue with the configuration, certain products will not work as they will not be able to read the contents in the tables as the format is wrong.b. The Oracle DB must be setup to use AL32UTF8 or a superset that contains AL32UTF8. c. The only difference between AL32UTF8 and UTF8 character sets is that AL32UTF8 stores characters beyond U+FFFF as four bytes (exactly as Unicode defines UTF-8). Oracle’s “UTF8” stores these characters as a sequence of two UTF-16 surrogate characters encoded using UTF-8 (or six bytes per character). Besides this storage difference, another difference is better support for supplementary characters in AL32UTF8 character set.

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  • Itty bitty ITTIA DB for Java Embedded Device Development

    - by hinkmond
    Here's a nice 3rd party itty-bitty database, called ITTIA DB, for Java Embedded and Mobile development See: ITTIA DB for Java Embedded Here's a quote: Java applications on mobile devices and other embedded systems can now leverage the robust shared access and data distribution features of ITTIA DB SQL with a new JDBC (Java Database Connectivity) driver released this week. This driver provides significant value for Java developers targeting embedded platforms such as QNX and Linux. Plus, it can exchange data with an Oracle back-end database. That's good if that's what you have on the back-end. Hinkmond

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  • How to find classes that use certain DB tables

    - by Songo
    Problem: I'm asked to prepare a document where all our DB tables are listed and I'm supposed to list all Controllers that uses these DB tables for read and another list for Controllers that do write operations. Ex: +------------------------------------------+------------+ | DB table | tbl_Orders | +------------------------------------------+------------+ |Controllers that perform read operations | ?? | +------------------------------------------+------------+ |Controllers that perform write operations | ?? | +------------------------------------------+------------+ We are trying to write some documentation for a legacy system built using Zend framework. The code is scattered everywhere. There is code in the Controllers, in the models and even in the views. The application uses PROPEL as an ORM. What makes this really difficult is that the Controller may not be directly calling the table, but it may be instantiating a model class that calls that table. Is there an educated way to approach this crazy task? Note: Searching for the table name won't provide a solution because if a model uses that table I wouldn't know which Controller is using that model.

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  • Fatal error encountered during command execution with a mySQL INSERT

    - by Brian
    I am trying to execute a INSERT statement on a mySQL DB in C#: MySqlConnection connection = new MySqlConnection("SERVER=" + _dbConnection + ";" + "DATABASE=" + _dbName + ";" + "PORT=" + _dbPort + ";" + "UID=" + _dbUsername + ";" + "PASSWORD=" + _dbPassword + ";"); MySqlDataAdapter adapter; DataSet dataset = new DataSet(); command = new MySqlCommand(); command.Connection = connection; command.CommandText = "INSERT INTO plugins (pluginName, enabled) VALUES (@plugin,@enabled)"; command.Parameters.AddWithValue("@name", "pluginName"); command.Parameters.AddWithValue("@enabled", false); adapter = new MySqlDataAdapter(command); adapter.Fill(dataset); The plugin table consists of two columns: pluginName(varchar(50)) and enabled(boolean). This fails with the error: mysql Fatal error encountered during command execution. Any ideas on why this would fail?

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  • mysqldump from a query

    - by Hulk
    How do we take a mysql dump from the results of a query I need something like this.. `mysqldump -uroot -pxxxx mydb "select * from table where name='1';" /tmp/a Thanks

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  • Setup Padrino with DataMapper and MySQL database

    - by Ivo Sabev
    Hello I am trying to setup a Padrino project using DataMapper and MySQL on my Mac OSX Snow Leopard. I have the necessary gems: dm-core data_objects do_mysql mysql (linked to my original Mac OSX installation) But when I try to start the padrino with PADRINO START from the console, I get the following error: /Users/ivolution/.bundle/ruby/1.9.1/gems/dm-core-0.10.2/lib/dm-core/adapters/mysql_adapter.rb:3:in `require': no such file to load -- do_mysql (LoadError) But as I said I do have do_mysql gem installed so there shouldn't be such error, I did bundle install in my project folder before trying to start Padrino. Any ideas?

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  • Java Audit table logging, MySQL equivalent of CONTEXT_INFO.

    - by Julia
    Hi, I am looking for the MySQL equivalent of CONTEXT_INFO that is present in SQL Server. Or any other session variable like thing using which I can pass the username to the trigger. I am currently working on logging table data for audit. I need to pass the username of the logged in user to the delete trigger. Any ideas? We are deleting the rows from the table in a few cases and marking them as deleted in others. Any alternate solutions are welcome. I thought of using AOP but it could prove problematic when deleting a cascade. I want to look into Hibernate Interceptors, not sure at this point if that works. If I can find the MySQL equivalent of CONTEXT_INFO, my job is done and elegant as well. Thanks, Julia.

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  • iPhone SDK mySQL

    - by Kevin
    Hello everybody, I'm starting on a new iPhone project, and this application mostly relies on mySQL. I have a mysql database running on my computer, and I need this application to send queries to the server to gain information. One example is creating and logging into an account. I have successfully done this on my windows vb.net application, but I know that objective c will be harder. This is basically getting text from the sql database and displaying it on the iPhone application. If someone could simply help me on that, I'll easily get started. So I hope that you guys help me out here :). Thanks Kevin

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  • MySQL stored procedure, handling multiple cursors and query results

    - by Tirithen
    How can I use two cursors in the same routine? If I remove the second cursor declaration and fetch loop everthing works fine. The routine is used for adding a friend in my webapp. It takes the id of the current user and the email of the friend we want to add as a friend, then it checks if the email has a corresponding user id and if no friend relation exists it will create one. Any other routine solution than this one would be great as well. DROP PROCEDURE IF EXISTS addNewFriend; DELIMITER // CREATE PROCEDURE addNewFriend(IN inUserId INT UNSIGNED, IN inFriendEmail VARCHAR(80)) BEGIN DECLARE tempFriendId INT UNSIGNED DEFAULT 0; DECLARE tempId INT UNSIGNED DEFAULT 0; DECLARE done INT DEFAULT 0; DECLARE cur CURSOR FOR SELECT id FROM users WHERE email = inFriendEmail; DECLARE CONTINUE HANDLER FOR NOT FOUND SET done = 1; OPEN cur; REPEAT FETCH cur INTO tempFriendId; UNTIL done = 1 END REPEAT; CLOSE cur; DECLARE cur CURSOR FOR SELECT user_id FROM users_friends WHERE user_id = tempFriendId OR friend_id = tempFriendId; DECLARE CONTINUE HANDLER FOR NOT FOUND SET done = 1; OPEN cur; REPEAT FETCH cur INTO tempId; UNTIL done = 1 END REPEAT; CLOSE cur; IF tempFriendId != 0 AND tempId != 0 THEN INSERT INTO users_friends (user_id, friend_id) VALUES(inUserId, tempFriendId); END IF; SELECT tempFriendId as friendId; END // DELIMITER ;

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  • Is this possible to join tables in doctrine ORM without using relations?

    - by piemesons
    Suppose there are two tables. Table X-- Columns: id x_value Table Y-- Columns: id x_id y_value Now I dont want to define relationship in doctrine classes and i want to retrieve some records using these two tables using a query like this: Select x_value from x, y where y.id="variable_z" and x.id=y.x_id; I m not able to figure out how to write query like this in doctrine orm EDIT: Table structures: Table 1: CREATE TABLE IF NOT EXISTS `image` ( `id` int(11) NOT NULL AUTO_INCREMENT, `random_name` varchar(255) NOT NULL, `user_id` int(11) NOT NULL, `community_id` int(11) NOT NULL, `published` varchar(1) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=259 ; Table 2: CREATE TABLE IF NOT EXISTS `users` ( `id` int(11) NOT NULL AUTO_INCREMENT, `city` varchar(20) DEFAULT NULL, `state` varchar(20) DEFAULT NULL, `school` varchar(50) DEFAULT NULL, PRIMARY KEY (`id`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=20 ; Query I am using: $q = new Doctrine_RawSql(); $q ->select('{u.*}, {img.*}') ->from('users u LEFT JOIN image img ON u.id = img.user_id') ->addComponent('u', 'Users u') ->addComponent('img', 'u.Image img') ->where("img.community_id='$community_id' AND img.published='y' AND u.state='$state' AND u.city='$city ->orderBy('img.id DESC') ->limit($count+12) ->execute(); Error I am getting: Fatal error: Uncaught exception 'Doctrine_Exception' with message 'Couldn't find class u' in C:\xampp\htdocs\fanyer\doctrine\lib\Doctrine\Table.php:290 Stack trace: #0 C:\xampp\htdocs\fanyer\doctrine\lib\Doctrine\Table.php(240): Doctrine_Table- >initDefinition() #1 C:\xampp\htdocs\fanyer\doctrine\lib\Doctrine\Connection.php(1127): Doctrine_Table->__construct('u', Object(Doctrine_Connection_Mysql), true) #2 C:\xampp\htdocs\fanyer\doctrine\lib\Doctrine\RawSql.php(425): Doctrine_Connection- >getTable('u') #3 C:\xampp\htdocs\fanyer\doctrine\models\Image.php(33): Doctrine_RawSql- >addComponent('img', 'u.Image imga') #4 C:\xampp\htdocs\fanyer\community_images.php(31): Image->get_community_images_gallery_filter(4, 0, 'AL', 'ALBERTVILLE') #5 {main} thrown in C:\xampp\htdocs\fanyer\doctrine\lib\Doctrine\Table.php on line 290

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