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• jQuery Validate - resetForm() Not Behaving as Expected

  - by Kevin C.

  Site in question is http://epraxadev.com/kw/palisade-palms/ "Click here for brochure" and "Learn More about Palisade Palms" both bring up a lightbox with the same HTML form to be filled out...the "learn more..." link also changes some of the HTML in the form (the value for a hidden form field, and the fields required). I'm using Colorbox for the lightbox, and for its onClosed event, I have this to reset the form: onClosed: function() { $('#brochure-form label em').remove(); $('#brochure-form').data('validator').resetForm(); } Now here's the problem: User tries to submit the "brochure" form, but it fails validation. User closes the lightbox. User opens up the "Learn more" lightbox, and tries to submit the form...now, instead of using the correct validation rules (only requiring e-mail and referrer), it requires all fields to be filled out (as is the case with the "Brochure Form") Is there something that I can add to the onClosed function, to clean up all the validation rules? Thanks guys!

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• (php) how to properly 'save' info in forms completed thus far

  - by hatorade

  So i have a form that on paper is 40 pages long. I was going to take the natural sections of this form, and make separate html forms for each section, with the idea that on the first page there would be a first form, then you hit 'Continue to next section' which essentially is the 'submit' button, which moves the user to section two, etc, until they hit the last section. i am not actually storing the results of the form in a database, but rather sending an email. the idea then is to store the separate form answers (one html form per section in the real form) as arrays or objects in the session, so that if they go back to a section in the form, it repopulates the values they entered since they are stored in the session. the result would be an array in the session storing the results for each of my forms, and i have one form for each section. my question is: is it secure to temporarily store things like SSNs or driver's license numbers as session variables? why or why not?

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• Django Initial for a ManyToMany Field

  - by gramware

  I have a form that edits an instance of my model. I would like to use the form to pass all the values as hidden with an inital values of username defaulting to the logged in user so that it becomes a subscribe form. The problem is that the normal initial={'field':value} doesn't seem to work for manytomany fields. how do i go about it? my views.py @login_required def event_view(request,eventID): user = UserProfile.objects.get(pk=request.session['_auth_user_id']) event = events.objects.get(eventID = eventID) if request.method == 'POST': form = eventsSusbcribeForm( request.POST,instance=event) if form.is_valid(): form.save() return HttpResponseRedirect('/events/') else: form = eventsSusbcribeForm(instance=event) return render_to_response('event_view.html', {'user':user,'event':event, 'form':form},context_instance = RequestContext( request )) my forms.py class eventsSusbcribeForm(forms.ModelForm): eventposter = forms.ModelChoiceField(queryset=UserProfile.objects.all(), widget=forms.HiddenInput()) details = forms.CharField(widget=forms.Textarea(attrs={'cols':'50', 'rows':'5'}),label='Enter Event Description here') date = forms.DateField(widget=SelectDateWidget()) class Meta: model = events exclude = ('deleted') def __init__(self, *args, **kwargs): super(eventsSusbcribeForm, self).__init__(*args, **kwargs) self.fields['username'].initial = (user.id for user in UserProfile.objects.filter())

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• ASP.NET MVC - Form Post always redirect when I just want to bind json result to a div

  - by Saxman

  Hi all, I'm having a little problem with json result. I'm submitting a contact form, and after the submission, I just want to return some json data (indicating either a success or failed and displays a message) back to the view, without causing a redirect, but it kept redirecting me to the action, here are the codes: HTML <div id="contactForm2" class="grid_6"> <div id="contactFormContainer"> @using (Html.BeginForm(MVC.Home.ActionNames.ContactForm, MVC.Home.Name, FormMethod.Post, new { id = "contactForm" })) { <p> <input type="text" tabindex="1" size="22" value="" id="contactName" class="text_input required" name="contactName" /> <label for="contactName"> <strong class="leftSpace">Your Name (required)</strong></label></p> <p> <input type="text" tabindex="2" size="22" value="" id="contactEmail" class="text_input required" name="contactEmail" /> <label for="contactEmail"> <strong class="leftSpace">Email (required)</strong></label></p> <p> <input type="text" tabindex="2" size="22" value="" id="contactPhone" class="text_input" name="contactPhone" /> <label for="contactPhone"> <strong class="leftSpace">Phone</strong></label></p> <p> <label> <strong class="leftSpace n">Message (required)</strong></label> <textarea tabindex="4" rows="4" cols="56" id="contactMessage" class="text_area required" name="contactMessage"></textarea></p> <p> <input type="submit" value="Send" tabindex="5" id="contactSubmit" class="button submit" name="contactSubmit" /></p> } </div> <div id="contactFormStatus"> </div> </div> Controller [HttpPost] public virtual JsonResult ContactForm(FormCollection formCollection) { var name = formCollection["contactName"]; var email = formCollection["contactEmail"]; var phone = formCollection["contactPhone"]; var message = formCollection["contactMessage"]; if (string.IsNullOrEmpty(name) || string.IsNullOrEmpty(email) || string.IsNullOrEmpty(message)) { return Json(new { success = false, message = "Please complete all the required fields so that I can get back to you. Thanks." }); } // Insert contact form data here... return Json(new { success = true, message = "Your inquery has been sent. Thank you." }); } javascript $(document).ready(function () { $('#contactSubmit').live('click', function () { var form = $('#contactForm'); var formData = form.serialize(); $.post('/Home/ContactForm', formData, function (result) { var status = $('#contactFormStatus'); if (result.success) { $('#contactForm')[0].reset; } status.append(result.message); }, 'json' ); return false; }); }); I've also tried this javascript, but also got a redirect $(document).ready(function () { $('#contactSubmit').live('click', function () { var form = $('#contactForm'); var formData = form.serialize(); $.ajax({ type: 'POST', url: '/Home/ContactForm', data: formData, success: function (result) { SubmitContactResult(result); }, cache: false }); }); function SubmitContactResult(result) { var status = $('#contactFormStatus'); if (result.success) { $('#contactForm')[0].reset; } status.append(result.message); } }); Any idea what's going on with my code? Thank you very much.

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• VB.net Enter Key

  - by Andrew

  I was given the following pseudo code in order to get the form that has focus and only allow the form I want to be submitted: <script> var currentForm = document.forms[0];</script> <form ...><input onfocus="currentForm = this.form;"/></form> <form ...><input onfocus="currentForm = this.form;"/></form> function globalKeyPressed(event) { if (event.keyCode == ENTER) { // This is pseudo-code, check how to really do it currentForm.submit(); } } How would I do this for VB.net because VB.net doesn't accept System.Windows.Forms.KeyPressEventArgs. I also wanted to add that I can't have multiple forms on my website as it disrupts the loginview. So my 2 seperate 'forms' are really just a loginview and then an asp:textbox and asp:button by themselves without a form.

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• MVC Validator numberOfInvalids not working

  - by user965445

  I dynamically add some elements to a form so I know I need to re-parse the form. Even if I have old invalid elements they don't get identified in numberOfInvalids It always comes back = 0 even though the invalid fields are highlighted on the page. var form = $("#form"); //Form Savingform.submit(function (e) { e.preventDefault(); form.removeData("validator"); form.removeData("unobtrusiveValidation"); $.validator.unobtrusive.parse(form); var val = form.validate(); if (val.numberOfInvalids() == 0) { $.blockUI({ fadeIn: 1000 }); AjaxRequest({ data: $(this).serializeArray(), success: function (data, status, xhr) { alert('sucess save or submit, use "'); }, complete: function () { $.unblockUI(); } }); } });

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• question about adding another column to a sql statement

  - by every_answer_gets_a_point

  i am starting with this table: SELECT [Lab Occurrence Form].[Practice Code], [Lab Occurrence Form].[1 0 Preanalytical (Before Testing)], Count([Lab Occurrence Form].[1 0 Preanalytical (Before Testing)]) AS [CountOf1 0 Preanalytical (Before Testing)] FROM [Lab Occurrence Form] WHERE ((([Lab Occurrence Form].[Occurrence Date]) Between [Forms]![By Number]![Text4] And [Forms]![By Number]![Text2])) GROUP BY [Lab Occurrence Form].[Practice Code], [Lab Occurrence Form].[1 0 Preanalytical (Before Testing)] HAVING ((([Lab Occurrence Form].[Practice Code])<>"") AND ((Count([Lab Occurrence Form].[1 0 Preanalytical (Before Testing)]))<>0)); it selects 3 columns but i need to aggregate the comments and put it in the fourth column where the first two values are the same

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• .NET MVC Ajax Form - How do you hide it?

  - by Tommy

  Ok, everything is 'functionally' working with what I am attempting to accomplish and once again, I am sure this is something dumb, but I cannot figure out how to do this one thing. I have an edit form for an entity, lets say a car. This 'car' can have 0 - many passengers. So on my edit form, I have all the fields for the car, then a list view showing each passenger (partial). I also have a 'add new passenger' button that will render a new partial view that allows you to enter a passenger. This has a cancel link and an add button to submit an Ajax form. When you add a passenger, the passenger is automatically added to the list, but I need the enter passenger form to go away. I have tried using the onSuccess and onComplete functions to hide the div that the form is in, but both render just the partial view HTML elements (white screen, text) and not the partialView in the context of the entire page. Sources: 1) Main Edit View <script type="text/javascript"> Function hideForm(){ document.getElementById('newPassenger').style.display = 'none'; } </script> <h2>Edit</h2> <%-- The following line works around an ASP.NET compiler warning --%> <%= ""%> <%Html.RenderPartial("EditCar", Model)%> <h2>Passengers for this car</h2> <%=Ajax.ActionLink("Add New Passenger", "AddPassenger", New With {.ID = Model.carID}, New AjaxOptions With {.UpdateTargetId = "newPassenger", .InsertionMode = InsertionMode.Replace})%> <div id="newPassenger"></div> <div id="passengerList"> <%Html.RenderPartial("passengerList", Model.Passengers)%> </div> <div> <%= Html.ActionLink("Back to List", "Index") %> </div> 2) AddPassenger View. The cancel link below is an action that returns nothing, thus removing the information in the div. <% Using Ajax.BeginForm("AddPassengerToCar", New With {.id = ViewData("carID")}, New AjaxOptions With {.UpdateTargetId = "passengerList", .InsertionMode = InsertionMode.Replace})%> <%=Html.DropDownList("Passengers")%> <input type="submit" value="Add" /> <%=Ajax.ActionLink("Cancel", "CancelAddControl", _ New AjaxOptions With {.UpdateTargetId = "newPassenger", .InsertionMode = InsertionMode.Replace})%><% end using %>

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• Reading POST data from html form sent to serversocket.

  - by user32167

  i try to write simplest possible server app in Java, displaying html form with textarea input, which after submitting gives me possibility to parse xml typed in that textarea. For now i build simple serversocket based server like that: import java.io.BufferedReader; import java.io.InputStreamReader; import java.io.PrintWriter; import java.net.ServerSocket; import java.net.Socket; public class WebServer { protected void start() { ServerSocket s; String gets = ""; System.out.println("Start on port 80"); try { // create the main server socket s = new ServerSocket(80); } catch (Exception e) { System.out.println("Error: " + e); return; } System.out.println("Waiting for connection"); for (;;) { try { // wait for a connection Socket remote = s.accept(); // remote is now the connected socket System.out.println("Connection, sending data."); BufferedReader in = new BufferedReader(new InputStreamReader( remote.getInputStream())); PrintWriter out = new PrintWriter(remote.getOutputStream()); String str = "."; while (!str.equals("")) { str = in.readLine(); if (str.contains("GET")){ gets = str; break; } } out.println("HTTP/1.0 200 OK"); out.println("Content-Type: text/html"); out.println(""); // Send the HTML page String method = "get"; out.print("<html><form method="+method+">"); out.print("<textarea name=we></textarea></br>"); out.print("<input type=text name=a><input type=submit></form></html>"); out.println(gets); out.flush(); remote.close(); } catch (Exception e) { System.out.println("Error: " + e); } } } public static void main(String args[]) { WebServer ws = new WebServer(); ws.start(); } } After form (textarea with xml and one additional text input) is submitted in 'gets' String-type variable I have Urlencoded values of my variables (also displayed on the screen, it looks like that: gets = GET /?we=%3Cnetwork+ip_addr%3D%2210.0.0.0%2F8%22+save_ip%3D%22true%22%3E%0D%0A%3Csubnet+interf_used%3D%22200%22+name%3D%22lan1%22+%2F%3E%0D%0A%3Csubnet+interf_used%3D%22254%22+name%3D%22lan2%22+%2F%3E%0D%0A%3C%2Fnetwork%3E&a=fooBar HTTP/1.1 What can i do to change GET to POST method (if i simply change it in form and than put " if (str.contains("POST")){" it gives me string like gets = POST / HTTP/1.1 with no variables. And after that, how i can use xml from my textarea field (called 'we')?

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• Why the parent page get refreshed when I click the link to open thickbox-styled form?

  - by user333205

  Hi, all: I'm using Thickbox 3.1 to show signup form. The form content comes from jquery ajax post. The jquery lib is of version 1.4.2. I placed a "signup" link into a div area, which is a part of my other large pages, and the whole content of that div area is ajax+posted from my server. To make thickbox can work in my above arangement, I have modified the thickbox code a little like that: //add thickbox to href & area elements that have a class of .thickbox function tb_init(domChunk){ $(domChunk).live('click', function(){ var t = this.title || this.name || null; var a = this.href || this.alt; var g = this.rel || false; tb_show(t,a,g); this.blur(); return false; });} This modification is the only change against the original version. Beacause the "signup" link is placed in ajaxed content, so I Use live instead of binding the click event directly. When I tested on my pc, the thickbox works well. I can see the signup form quickly, without feeling the content of the parent page(here, is the other large pages) get refreshed. But after transmiting my site files into VHost, when I click the "signup" link, the signup form get presented very slowly. The large pages get refreshed evidently, because the borwser(ie6) are reloading images from server incessantly. These images are set as background images in CSS files. I think that's because the slow connection of network. But why the parent pages get refreshed? and why the browser reloads those images one more time? Havn't those images been placed in local computer's disk? Is there one way to stop that reloadding? Because the signup form can't get displayed sometimes due to slow connection of network. To verified the question, you can access http://www.juliantec.info/track-the-source.html and click the second link in left grey area, that is the "signup" link mentioned above. Thinks!

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• How do you select form elements in JQuery based upon an html table?

  - by Swoop

  I am working on some ASP.NET web forms which involves some dynamic generation, and I need to add some onClick helpers on the client side. I have a basic outline of something working, except for one huge problem. There are multiple HTML tables, each generated by a different ASP.NET web control. Each table can contain overlapping field names, which is causing a problem with my JQuery click event handlers. The click event handler is linking to unintended form fields in addition to the intended form field. I have provided a simplified sample version of the code below. This code is trying to set the value of textbox box1 when a particular radiobutton is selected in the table with id=thing1. Obviously, the jquery code will be triggered for the form fields in both tables. The tables are dynamically added to the webpage based upon different conditions. It is possible that no tables will be loaded, only 1 table, or both tables might load. In the future, other tables could be added. Each table comes from a different .net web control. Other than renaming the form fields to make sure they are unique across all user controls, is there a way to have JQuery act only on the intended form fields? In other words, could the table ID be incorporated into the JQuery code in a manner that does not become a nightmare to maintain later? <script> $(document).ready(function() { $("[id$=radio1_0]").click(function() { $("[id$=box1]").attr("value", ""); }); $("[id$=radio1_1]").click(function() { $("[id$=box1]").attr("value", "N/A"); }); </script> <table id="thing1"> <tr><td> <radiobuttonlist id="radio1"/> <listitem>yes</listitem> <listitem>no</listitem> </td></tr> <tr><td> <textbox id="box1"/> </td></tr> </table> <table id="thing2"> <tr><td> <radiobuttonlist id="radio1"/> <listitem>yes</listitem> <listitem>no</listitem> </td></tr> <tr><td> <textbox id="box1"/> </tr></td> </table>

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• [java] reading POST data from html form sent to serversocket.

  - by user32167

  i try to write simplest possible server app in Java, displaying html form with textarea input, which after submitting gives me possibility to parse xml typed in thet textarea. For now i build simple serversocket based server like that: import java.io.BufferedReader; import java.io.InputStreamReader; import java.io.PrintWriter; import java.net.ServerSocket; import java.net.Socket; public class WebServer { protected void start() { ServerSocket s; String gets = ""; System.out.println("Start on port 80"); try { // create the main server socket s = new ServerSocket(80); } catch (Exception e) { System.out.println("Error: " + e); return; } System.out.println("Waiting for connection"); for (;;) { try { // wait for a connection Socket remote = s.accept(); // remote is now the connected socket System.out.println("Connection, sending data."); BufferedReader in = new BufferedReader(new InputStreamReader( remote.getInputStream())); PrintWriter out = new PrintWriter(remote.getOutputStream()); String str = "."; while (!str.equals("")) { str = in.readLine(); if (str.contains("GET")){ gets = str; break; } } out.println("HTTP/1.0 200 OK"); out.println("Content-Type: text/html"); out.println(""); // Send the HTML page String method = "get"; out.print("<html><form method="+method+">"); out.print("<textarea name=we></textarea></br>"); out.print("<input type=text name=a><input type=submit></form></html>"); out.println(gets); out.flush(); remote.close(); } catch (Exception e) { System.out.println("Error: " + e); } } } public static void main(String args[]) { WebServer ws = new WebServer(); ws.start(); } } After form (textarea with xml and one additional text input) is submitted in 'gets' String-type variable I have Urlencoded values of my variables (also displayed on the screen, it looks like that: gets = GET /?we=%3Cnetwork+ip_addr%3D%2210.0.0.0%2F8%22+save_ip%3D%22true%22%3E%0D%0A%3Csubnet+interf_used%3D%22200%22+name%3D%22lan1%22+%2F%3E%0D%0A%3Csubnet+interf_used%3D%22254%22+name%3D%22lan2%22+%2F%3E%0D%0A%3C%2Fnetwork%3E&a=fooBar HTTP/1.1 What can i do to change GET to POST method (if i simply change it in form and than put " if (str.contains("GET")){" it gives me string like gets = POST / HTTP/1.1 with no variables. And after that, how i can use xml from my textarea field (called 'we')?

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• How do I use jquery validate remote validation on a field that depends on another field in the form?

  - by Kevin J

  I have a form in which I am using remote validation to check if an email address already exists in the database. However, the catch is that on this form, the user can select between several different "groups", and each group has its own distinct set of email addresses (thus the same email can exist once in each group). The group selection is a dropdown on the form, and the email address is an input field with remote validation. I have a couple issues. First, I have set up my remote rule like this: remote: { url: 'remote_script.php', data: { group_id: $('select.group_id').val() } } However, this seems to statically set the group_id parameter to whatever the first value in the select is. Meaning, if I change the select, then trigger the remote validation again, the group_id parameter does not change First, how can I make this parameter dynamic, depending on the value of a select in the form? Secondly, how do I manually trigger the remote validation on the email address field? When the group_id select is changed, I want to re-trigger the remote validation on the email address field (without changing the value of the field). I tried using $(selector).validate().element('.email_addr') But this appears to only trigger the standard validation (required, email), and not the remote call.

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• Control 'ctl00_TextBox1' of type 'TextBox' must be placed inside a form tag with runat=server.

  - by Hiru

  When a form with a run at server is added there will be two forms with runat server and another error occurs. Can some one give me an idea. Thankx in advance. The details of the error are as follows. Control 'ctl00_TextBox1' of type 'TextBox' must be placed inside a form tag with runat=server. Description: An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code. Exception Details: System.Web.HttpException: Control 'ctl00_TextBox1' of type 'TextBox' must be placed inside a form tag with runat=server. Source Error: An unhandled exception was generated during the execution of the current web request. Information regarding the origin and location of the exception can be identified using the exception stack trace below. Stack Trace: [HttpException (0x80004005): Control 'ctl00_TextBox1' of type 'TextBox' must be placed inside a form tag with runat=server.] System.Web.UI.Page.VerifyRenderingInServerForm(Control control) +2052287 System.Web.UI.WebControls.TextBox.AddAttributesToRender(HtmlTextWriter writer) +49 System.Web.UI.WebControls.WebControl.RenderBeginTag(HtmlTextWriter writer) +17 System.Web.UI.WebControls.TextBox.Render(HtmlTextWriter writer) +17 System.Web.UI.Control.RenderControlInternal(HtmlTextWriter writer, ControlAdapter adapter) +25 System.Web.UI.Control.RenderControl(HtmlTextWriter writer, ControlAdapter adapter) +121 System.Web.UI.Control.RenderControl(HtmlTextWriter writer) +22 System.Web.UI.Control.RenderChildrenInternal(HtmlTextWriter writer, ICollection children) +199 System.Web.UI.Control.RenderChildren(HtmlTextWriter writer) +20 System.Web.UI.Control.Render(HtmlTextWriter writer) +7 System.Web.UI.Control.RenderControlInternal(HtmlTextWriter writer, ControlAdapter adapter) +25 System.Web.UI.Control.RenderControl(HtmlTextWriter writer, ControlAdapter adapter) +121 System.Web.UI.Control.RenderControl(HtmlTextWriter writer) +22 System.Web.UI.Control.RenderChildrenInternal(HtmlTextWriter writer, ICollection children) +199 System.Web.UI.Control.RenderChildren(HtmlTextWriter writer) +20 System.Web.UI.Page.Render(HtmlTextWriter writer) +26 System.Web.UI.Control.RenderControlInternal(HtmlTextWriter writer, ControlAdapter adapter) +25 System.Web.UI.Control.RenderControl(HtmlTextWriter writer, ControlAdapter adapter) +121 System.Web.UI.Control.RenderControl(HtmlTextWriter writer) +22 System.Web.UI.Page.ProcessRequestMain(Boolean includeStagesBeforeAsyncPoint, Boolean includeStagesAfterAsyncPoint) +2558 Version Information: Microsoft .NET Framework Version:2.0.50727.1873; ASP.NET Version:2.0.50727.1433

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• [C#][XNA 3.1] How can I host two different XNA windows inside one Windows Form?

  - by secutos

  I am making a Map Editor for a 2D tile-based game. I would like to host two XNA controls inside the Windows Form - the first to render the map; the second to render the tileset. I used the code here to make the XNA control host inside the Windows Form. This all works very well - as long as there is only one XNA control inside the Windows Form. But I need two - one for the map; the second for the tileset. How can I run two XNA controls inside the Windows Form? While googling, I came across the terms "swap chain" and "multiple viewports", but I can't understand them and would appreciate support. Just as a side note, I know the XNA control example was designed so that even if you ran 100 XNA controls, they would all share the same GraphicsDevice - essentially, all 100 XNA controls would share the same screen. I tried modifying the code to instantiate a new GraphicsDevice for each XNA control, but the rest of the code doesn't work. The code is a bit long to post, so I won't post it unless someone needs it to be able to help me. Thanks in advance.

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• KeyUp processed for wrong control

  - by Mikael

  I have made a simple test application for the issue, two winforms each containing a button. The button on the first form opens the other form when clicked. It also subscribes to keyup events. The second form has its button set as "AcceptButton" and in the Clicked event we sleep for 1s and then set DialogResult to true (the sleep is to simulate some processing done) When enter is used to close this second form the KeyUp event of the button on the first form is triggered, even though the key was released well before the second had passed so the second form was still shown and focused. If any key other then enter is pressed in the second form the event is not triggered for the button on the first form. First form: public Form1() { InitializeComponent(); buttonForm2.KeyUp += new KeyEventHandler(cntKeyUp); } void cntKeyUp(object sender, KeyEventArgs e) { MessageBox.Show(e.KeyCode.ToString()); } private void buttonForm2_Click(object sender, EventArgs e) { using (Form2 f = new Form2()) { f.ShowDialog(); } } Second form: private void button1_Click(object sender, EventArgs e) { Thread.Sleep(1000); this.DialogResult = DialogResult.OK; } Does anyone know why the event is triggered for the button on the non active form and what can be done to stop this from happening?

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• Problem with multiple forms on one page

  - by Jon

  I have two forms on a web page. The first is not an actual form since this is a .NET based site. So instead I have the standard input fields, along with asp:Button PostBackURL="http:/www...". One of the fields is "email". That works fine. Then I have an XSLT file with another form, and am using Javascript (via this.form.action, .method, etc) to post that form. Besides that it has the same fields as the form above. The problem is that when someone submits the second form, the script at the PostBackURL returns an error because the "email" field appears empty. So it seems as though the form is submitting the "email" field form the top form instead of the current one. I thought maybe the wrong form is being submitted, but if I remove the "email" field from the top form, and then submit the bottom one, it works fine. Any ideas on how to fix this? Thanks.

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• How do I insert an input's value into a separate form?

  - by ryan

  I'm making a tool for my university that allows students to create a list of classes by doing the following: Searching by course title for their course via an autocomplete input field. Adding that course to a separate form that upon being submitted creates a course list. I am trying to link the autocomplete and the course list form with an 'add to course list' button that inserts a hidden input field into the course list form which can subsequently be submitted by a 'create course list' button. My question is this: How do I take the value of the autocomplete input and insert it into the course list form without using AJAX? So far I have something like the following: <%= text_field_with_auto_complete :course, :title, :size => 40 %> <%= link_to_function "Add to Course List" do |page| page.insert_html :top, :course_list, hidden_field(:courses, :course, {:value => "$('course_title').value"}) %> <% form_for(@course_list) do |f|%> <div id="course_list">Insert selected courses here.</div> <% end %>

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• CakePHP 1.26: Bug in 'Security' component?

  - by Steve

  Okay, for those of you who may have read this earlier, I've done a little research and completely revamped my question. I've been having a problem where my form requests get blackholed by the Security component, although everything works fine when the Security component is disabled. I've traced it down to a single line in a form: <?php echo $form->create('Audition');?> <fieldset> <legend><?php __('Edit Audition');?></legend> <?php echo $form->input('ensemble'); echo $form->input('position'); echo $form->input('aud_date'); // The following line works fine... echo $form->input('owner'); // ...but the following line blackholes when Security included // and the form is submitted: // echo $form->input('owner', array('disabled'=>'disabled'); ?> </fieldset> <?php echo $form->end('Submit');?> (I've commented out the offending line for clarity) I think I'm following the rules by using the form helper; as far as I can tell, this is a bug in the Security component, but I'm too much of a CakePHP n00b to know for sure. I'd love to get some feedback, and if it's a real bug, I'll submit it to the CakePHP team. I'd also love to know if I'm just being dumb and missing something obvious here.

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• What's the best way to format this simple HTML form using CSS?

  - by GregH

  I have have a simple HTML form with say four input widgets (see below)...two lines with two widgets on each line. However, when this renders it is pretty ugly. I want the whole form to be indented from the edge of the left page say 40px and I want the left edge of the widgets to line up with each other and the right edge of the labels to line up. I also want to be able to specify a minimum distance between the right edge of the first widget and the label of the widget next to it. How would I do this using CSS? Basically so it looks something like: Name: _____________ Common Names: _____________ Version: ____________ Status: ____________ See current un-formatted HTML below: <form name="detailData"> <div id="dataEntryForm"> <label> Name: <input type="text" class="input_text" name="ddName"/> Common Names: <input type="text" class="input_text" name="ddCommonNames"><P> Version: <input type="text" class="input_text" name="ddVer"/> Status: <select name="ddStatus"><option value="A" selected="selected">Active</option><option value="P">Planned</option><option value="D">Deprecated</option> </label> </div> </form>

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• I am confused about how to use @SessionAttributes

  - by yusaku

  I am trying to understand architecture of Spring MVC. However, I am completely confused by behavior of @SessionAttributes. Please look at SampleController below , it is handling post method by SuperForm class. In fact, just field of SuperForm class is only binding as I expected. However, After I put @SessionAttributes in Controller, handling method is binding as SubAForm. Can anybody explain me what happened in this binding. ------------------------------------------------------- @Controller @SessionAttributes("form") @RequestMapping(value = "/sample") public class SampleController { @RequestMapping(method = RequestMethod.GET) public String getCreateForm(Model model) { model.addAttribute("form", new SubAForm()); return "sample/input"; } @RequestMapping(method = RequestMethod.POST) public String register(@ModelAttribute("form") SuperForm form, Model model) { return "sample/input"; } } ------------------------------------------------------- public class SuperForm { private Long superId; public Long getSuperId() { return superId; } public void setSuperId(Long superId) { this.superId = superId; } } ------------------------------------------------------- public class SubAForm extends SuperForm { private Long subAId; public Long getSubAId() { return subAId; } public void setSubAId(Long subAId) { this.subAId = subAId; } } ------------------------------------------------------- <form:form modelAttribute="form" method="post"> <fieldset> <legend>SUPER FIELD</legend> <p> SUPER ID:<form:input path="superId" /> </p> </fieldset> <fieldset> <legend>SUB A FIELD</legend> <p> SUB A ID:<form:input path="subAId" /> </p> </fieldset> <p> <input type="submit" value="register" /> </p> </form:form>

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• WindowsFormsApplicationBase SplashScreen makes login form ignore keypresses until I click on it - how to debug?

  - by Tom Bushell

  My WinForms app has a simple modal login form, invoked at startup via ShowDialog(). When I run from inside Visual Studio, everything works fine. I can just type in my User ID, hit the Enter key, and get logged in. But when I run a release build directly, everything looks normal (the login form is active, there's a blinking cursor in the User ID MaskedEditBox), but all keypresses are ignored until I click somewhere on the login form. Very annoying if you are used to doing everything from the keyboard. I've tried to trace through the event handlers, and to set the focus directly with code, to no avail. Any suggestions how to debug this (outside of Visual Studio), or failing that - a possible workaround? Edit Here's the calling code, in my Main Form: private void OfeMainForm_Shown(object sender, EventArgs e) { OperatorLogon(); } private void OperatorLogon() { // Modal dialogs should be in a "using" block for proper disposal using (var logonForm = new C21CfrLogOnForm()) { var dr = logonForm.ShowDialog(this); if (dr == DialogResult.OK) SaveOperatorId(logonForm.OperatorId); else Application.Exit(); } } Edit 2 Didn't think this was relevant, but I'm using Microsoft.VisualBasic.ApplicationServices.WindowsFormsApplicationBase for it's splash screen and SingleInstanceController support. I just commented out the splash screen code, and the problem has disappeared. So that's opened up a whole new line of inquiry... Edit 3 Changed title to reflect better understanding of the problem

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• In CakePHP, how do I create a form to list models withing a date range?

  - by anonymous coward

  I have a very simple model that includes the auto-filled field much like 'created'. (DateTime format). I'd like to use the Form helpers if possible, to validate the date fields and whatnot. I'd like a simple form with a "Begin Date" (YMD, 12 hours), and an "End Date" (same format). There is already a controller action set up as follows: function view_between($start_date = null, $end_date = null) { // ... stuff that works correctly when the URL is manually entered. } Have I defined the controller wrong, or how can I pass these values into that function? The reason I'm stuck is because I tried adding a $form->input('my_datetime_field' ...) twice, but obviously the name/id were the same on the respective elements. I have also tried using $form->dateTime(...) with similar results. I'm not sure how to uniquely identify a Begin and End date selection, when it should interact with a single field. Am I going about this wrong? A kind shove in the right direction should suffice.

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• C# - Is it possible to start my project with a class instead of a form?

  - by Irro

  I want my project to be started through an class instead of a form, is there any way to do this? Or to be more precise is there any good way to make sure that the first class, except Program, that is started isn't a form-class. I tried to change to my class in Program.main() but it looks like Application.run() needs a ApplicationContext. I guess that I could change the Program-class to start another class and let that class start the form with Application.run() but I think that it will cause a lot of problem since I don't want the same form to be started first each time and Application.run() have to be used at least once and at most once. So I think it will be hard to keep track of if Application.run() has been used or not. Another question that might be even more important; Is this a good way to do things in .net? The reason I want to do so is because I want to create some sort of MVC project where the class I want to start with is the controller and all forms I'll use will be views.

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• jQuery: How to use modifier keys on form submit?

  - by Svish

  Say I have a form that looks like this: [ Animal name input field ] Add button If I type a name and hit enter, an animal with the given name is added to a table. Works fine. What I would like now is to call the current way of working "quick add" and add a new feature called "slow add", which I am not quite sure how to do. Basically what I want is that if for example the shift key is held down when enter or the button is clicked, I want the form submit method to do something slightly different. In my case I want it to open up a form where more details on the animal can be added before it is added to the table. Problem is I'm not quite sure how to do this. I have tried add a FireBug console.info(eventData) in my current submit function and I have found that the eventData contains an altKey, shiftKey and controlKey property, but they are always undefined even when I hold those keys down. So, does anyone know how I can do something special in my submit handler when certain modifier keys were pressed when the form was submitted?

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