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  • Multi-threading does not work correctly using std::thread (C++ 11)

    - by user1364743
    I coded a small c++ program to try to understand how multi-threading works using std::thread. Here's the step of my program execution : Initialization of a 5x5 matrix of integers with a unique value '42' contained in the class 'Toto' (initialized in the main). I print the initialized 5x5 matrix. Declaration of std::vector of 5 threads. I attach all threads respectively with their task (threadTask method). Each thread will manipulate a std::vector<int> instance. I join all threads. I print the new state of my 5x5 matrix. Here's the output : 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 It should be : 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 0 0 0 0 0 1 1 1 1 1 2 2 2 2 2 3 3 3 3 3 4 4 4 4 4 Here's the code sample : #include <iostream> #include <vector> #include <thread> class Toto { public: /* ** Initialize a 5x5 matrix with the 42 value. */ void initData(void) { for (int y = 0; y < 5; y++) { std::vector<int> vec; for (int x = 0; x < 5; x++) { vec.push_back(42); } this->m_data.push_back(vec); } } /* ** Display the whole matrix. */ void printData(void) const { for (int y = 0; y < 5; y++) { for (int x = 0; x < 5; x++) { printf("%d ", this->m_data[y][x]); } printf("\n"); } printf("\n"); } /* ** Function attached to the thread (thread task). ** Replace the original '42' value by another one. */ void threadTask(std::vector<int> &list, int value) { for (int x = 0; x < 5; x++) { list[x] = value; } } /* ** Return the m_data instance propertie. */ std::vector<std::vector<int> > &getData(void) { return (this->m_data); } private: std::vector<std::vector<int> > m_data; }; int main(void) { Toto toto; toto.initData(); toto.printData(); //Display the original 5x5 matrix (first display). std::vector<std::thread> threadList(5); //Initialization of vector of 5 threads. for (int i = 0; i < 5; i++) { //Threads initializationss std::vector<int> vec = toto.getData()[i]; //Get each sub-vectors. threadList.at(i) = std::thread(&Toto::threadTask, toto, vec, i); //Each thread will be attached to a specific vector. } for (int j = 0; j < 5; j++) { threadList.at(j).join(); } toto.printData(); //Second display. getchar(); return (0); } However, in the method threadTask, if I print the variable list[x], the output is correct. I think I can't print the correct data in the main because the printData() call is in the main thread and the display in the threadTask function is correct because the method is executed in its own thread (not the main one). It's strange, it means that all threads created in a parent processes can't modified the data in this parent processes ? I think I forget something in my code. I'm really lost. Does anyone can help me, please ? Thank a lot in advance for your help.

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  • remove the spaces...

    - by tekknolagi
    !/usr/bin/python import random lower_a = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z'] upper_a = ['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'] num = ['0', '1', '2', '3', '4', '5', '6', '7', '8', '9'] all = [] all = " ".join("".join(lower_a) + "".join(upper_a) + "".join(num)) all = all.split() x = 0 while x < 10: for i in range(7): a = random.choice(all) print a, print x += 1 what i want to do is remove the spaces from the output what it gives now is Z 3 a A I K R G B i N 9 c E v g E r A N 8 e B 6 d v H O c a V 8 c x y b g 2 W a T T f 8 H T r 6 E p D K l 5 p u x q 8 P Z 9 T n I W X n B Q

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  • The return value should be a list but doesn't return as expected?! - Python newbie

    - by user1432941
    Hi this must be a very simple solution that has eluded me this last hour. I've tried to build this test function where the return value of the test_cases list should match the values in the test_case_answers list but for some reason, test case 1 and test case 2 fail. When i print the return values for the test cases they return the correct answers, but for some reason test case 1 and test case 2 return False. Thanks for your help! import math test_cases = [1, 9, -3] test_case_answers = [1, 3, 0] def custom_sqrt(num): for i in range(len(test_cases)): if test_cases[i] >= 0: return math.sqrt(test_cases[i]) else: return 0 for i in range(len(test_cases)): if custom_sqrt(test_cases[i]) != test_case_answers[i]: print "Test Case #", i, "failed!" custom_sqrt(test_cases)

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  • In Python what's the best way to emulate Perl's __END__?

    - by FM
    Am I correct in thinking that that Python doesn't have a direct equivalent for Perl's __END__? print "Perl...\n"; __END__ End of code. I can put anything I want here. One thought that occurred to me was to use a triple-quoted string. Is there a better way to achieve this in Python? print "Python..." """ End of code. I can put anything I want here. """

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  • python compare time

    - by Jesse Siu
    i want to using python create filter for a log file. get recent 7 days record. but when i didn't know how to compare time. like current time is 11/9/2012, i want to get records from 04/9/2012 to now the log file like Sat Sep 2 03:32:13 2012 [pid 12461] CONNECT: Client "66.249.68.236" Sat Sep 2 03:32:13 2012 [pid 12460] [ftp] OK LOGIN: Client "66.249.68.236", anon password "[email protected]" Sat Sep 2 03:32:14 2012 [pid 12462] [ftp] OK DOWNLOAD: Client "66.249.68.236", "/pub/10.5524/100001_101000/100022/readme.txt", 451 i using this one def OnlyRecent(line): print time.strptime(line.split("[")[0].strip(),"%a %b %d %H:%M:%S %Y") print time.time() if time.strptime(line.split("[")[0].strip(),"%a %b %d %H:%M:%S %Y") < time.time(): return True return False But it shows (2012, 9, 2, 3, 32, 13, 5, 246, -1) 1347332968.08 (2012, 9, 2, 3, 32, 13, 5, 246, -1) 1347332968.08 (2012, 9, 2, 3, 32, 14, 5, 246, -1) 1347332968.08 the time format is different, and it can't compare time. So how to set this comparison in 7 days. Thanks

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  • Subtype polymorphism and arrays

    - by user133466
    Computer[] labComputers = new Computer[10]; with public class Computer { ... void toString(){ // print computer specs } } public class Notebook extends Computer{ ... void toString(){ // print computer specs + laptop color } } each subscripted variable labComputers[i] can reference either a Computer object or a Notebook object because Notebook is a subclass of Computer. For the method call labComputers[i].toString(), polymorphism ensures that the correct toString method is called. I wonder what if we do Notebook[] labComputers = new Notebook[10]; what kind or error would I get if I reference with Computer object and a Notebook object

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  • can list be converted into string

    - by PARIJAT
    Actually i have extracted some data from the file and want to write it in the file 2 but the program says 'sequence item 1: expected string, list found', I want to know how i can convert buffer[] ie string into sequence, so that it could be saved in file 2...I am new to the python please help* file = open('/ddfs/user/data/k/ktrip_01/hmm.txt','r') file2 = open('/ddfs/user/data/k/ktrip_01/hmm_write.txt','w') buffer = [] rec = file.readlines() for line in rec : field = line.split() print '>',field[0] term = field[0] buffer.append(term) print field[1], field[2], field[6], field[12] term1 = field [1] buffer.append(term1) term2 = field[2] buffer.append[term2] term3 = field[6] buffer.append[term3] term4 = field[12] buffer.append[term4] file2.write(buffer) file.close() file2.close()

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  • Check and avoid if a char is being entered in a int

    - by John
    Hi.... This is a exremely stupid question but i need help with this.... I'm trying to make a small program that i made robust and needed some help with tht.... int num1; int num2 = 0; System.out.print("Enter number 1: "); num1 = kb.nextInt(); while(num2<num1) { System.out.print("Enter number 2: "); num2 = kb.nextInt(); } Number 2 has to be greater than number 1 Also i want the program to automatically check and ignore if the user enters a char instead of an int... Cause right now when a user enters lets say "r" instead of a number the program just exists....

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  • Printing a list using reflection

    - by TFool
    public class Service{ String serviceName; //setter and getter } public class Version{ String VersionID; //setter and getter } public void test(Object list){ //it shd print the obtained list } List< Service list1; //Service is a Bean List< Version list2; //Version is a Bean test(list1); test(list2); Now the test method shd print the obtained list - (i.e) If the list is of type Service ,then serviceName should be printed using its getter. If the list type is Version versionID should be printed. Is it possible to achieve this without using Interface or abstract class?

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  • Alternative to css3 not selector

    - by Raynos
    Are there any alternatives to the :not css3 selector that are compliant with IE8 (and quirks mode). Either in css or javascript/jquery that emulates the selector or something similar. I am using *:not as follows below. Feel free to recommend a solution that avoids the use of :not completely. @media screen { #printable { visibility: hidden; } } @media print { *:not(#printable) { visibility: hidden; } #printable { position: absolute; visibility: visible; } } Note that the use of :not is tied to the use of @media print so just using a simple jQuery solution to apply css to $(":not(#printable)") won't work without being clever. Including an entire library like ie9.js or selectivirz isn't an option as it can effect various other parts of the pages and would involve a large section of re-testing. a jsfiddle that shows it working in browsers that support :not http://jsfiddle.net/Raynos/TjKbz/

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  • Why is Python 3.1 throwing a SyntaxError when printing after loop?

    - by bubersson
    Hi, I'm trying to run this snippet in Python 3.1 console and I'm getting SyntaxError: >>> while True: ... a=5 ... if a<6: ... break ... print("hello") File "<stdin>", line 5 print("hello") ^ SyntaxError: invalid syntax >>> (This is just shortened code to make a point.) Am I missing something? Is there some other Magic I don't know about? Thanks for your help (since this is my first StackOverflow question and I'm not a native English speaker)

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  • Regular Expression Program

    - by david robers
    Hi I have the following text: SMWABCCA ABCCAEZZRHM NABCCAYJG XABCCA ABCCADK ABCCASKIYRH ABCCAKY PQABCCAK ABCCAKQ This method takes a regex in out by the user and SHOULD print out the Strings it applies to but seems to print out something completely different: private void matchIt(String regex) { Pattern p = Pattern.compile(regex); Matcher m = null; boolean found = false; for(int i = 0; i < data.length; i++){ m = p.matcher(data[i]); if(m.find()){ out.println(data[i]); found = true; } } if(!found){ out.println("Pattern Not Found"); } } When inputting "[C]" It outputs: SMWABCCA ABCCAEZZRHM NABCCAYJG XABCCA ABCCADK ABCCASKIYRH ABCCAKY PQABCCAK ABCCAKQ Any ideas why? I think I'm using m.find() improperly...

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  • PHP variable question

    - by Kyle Parisi
    This works: $customerBox = mysql_query("MY SQL STATEMENT HERE"); $boxRow = mysql_fetch_array($customerBox); $customerBox = mysql_query("MY SQL STATEMENT AGAIN"); while($item = mysql_fetch_assoc($customerBox)) { foreach ($item as $columnName = $value) { if (empty($value)) { print $columnName; } } } This does not: $customerBox = mysql_query("MY SQL STATEMENT HERE"); $boxRow = mysql_fetch_array($customerBox); while($item = mysql_fetch_assoc($customerBox)) { foreach ($item as $columnName = $value) { if (empty($value)) { print $columnName; } } } Why? I guess I don't understand how variables work yet.

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  • Pagination, next page doesn`t display

    - by user1738013
    if I click page 2 that`s error: Not Found The requested URL /rank/GetAll/30 was not found on this server. My link is: http://localhost/rank/GetAll/30 Model: Rank_Model <?php Class Rank_Model extends CI_Model { public function __construct() { parent::__construct(); } public function record_count() { return $this->db->count_all("ranking"); } public function fifa_rank($limit, $start) { $this->db->limit($limit, $start); $query = $this->db->get("ranking"); if ($query->num_rows() > 0) { foreach ($query->result() as $row) { $data[] = $row; } return $data; } return false; } } ?> Controller: Rank <?php if ( ! defined('BASEPATH')) exit('No direct script access allowed'); class rank extends CI_Controller { function __construct() { parent::__construct(); $this->load->helper("url"); $this->load->helper(array('form', 'url')); $this->load->model('Rank_Model','',TRUE); $this->load->library("pagination"); } function GetAll() { $config = array(); $config["base_url"] = base_url() . "rank/GetAll"; $config["total_rows"] = $this->Rank_Model->record_count(); $config["per_page"] = 30; $config["uri_segment"] = 3; $this->pagination->initialize($config); $page = ($this->uri->segment(3)) ? $this->uri->segment(3) : 0; $data["results"] = $this->Rank_Model->fifa_rank($config["per_page"], $page); $data['errors_login'] = array(); $data["links"] = $this->pagination->create_links(); $this->load->view('left_column/open_fifa_rank',$data); } } View Open: open_fifa_rank <?php $this->load->view('mains/header'); $this->load->view('login/loggin'); $this->load->view('mains/menu'); $this->load->view('left_column/left_column_before'); $this->load->view('left_column/menu_left'); $this->load->view('left_column/left_column'); $this->load->view('center/center_column_before'); $this->load->view('left_column/fifa_rank'); $this->load->view('center/center_column'); $this->load->view('right_column/right_column_before'); $this->load->view('login/zaloguj'); $this->load->view('right_column/right_column'); $this->load->view('mains/footer'); ?> and View: fifa_rank <table> <thead> <tr> <td>Pozycja</td> <td>Kraj</td> <td>Punkty</td> <td>Zmiana</td> </tr> </thead> <?php foreach($results as $data) {?&gt; <tbody> <tr> <td><?php print $data->pozycja;?></td> <td><?php print $data->kraj;?></td> <td><?php print $data->punkty;?></td> <td><?php print $data->zmiana;?></td> </tr> <?php } ?> </tbody> </table> <p><?php echo $links; ?></p> Maybe you know where is my problem? Now I know where is my problem. In first page I have link: http://localhost/index.php/rank/GetAll But on the next: http://localhost/rank/GetAll/30 In secend link, I don`t have index.php. How can I fix it?

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  • Json request with Javascript

    - by chota
    Hi, I am just beginner on java script and JSON and never had done any work in these before. My employer has just asked me to create the basic POC of these. Scenario: I have a REST API and when i call it, it returns back response in JSON format. Need to To: Create a HTML page and use javascript to call that REST API and capture JSON response and print in the same HTML page. <script type="text/javascript"> function loadMe() { loadJSON('http://myrestAPI'); } function loadJSON(url) { //Help me here to capture the response and print in html page. } </script> I would appreciate your help. This might be simple, but for me i have no idea because i never have done anything similar in java script and json. I goggled but could not find anything. Thanks, chota

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  • TCP Scanner Python MultiThreaded

    - by user1473508
    I'm trying to build a small tcp scanner for a netmask. The code is as follow: import socket,sys,re,struct from socket import * host = sys.argv[1] def RunScanner(host): s = socket(AF_INET, SOCK_STREAM) s.connect((host,80)) s.settimeout(0.1) String = "GET / HTTP/1.0" s.send(String) data = s.recv(1024) if data: print "host: %s have port 80 open"%(host) Slash = re.search("/", str(host)) if Slash : netR,_,Wholemask = host.partition('/') Wholemask = int(Wholemask) netR = struct.unpack("!L",inet_aton(netR))[0] for host in (inet_ntoa(struct.pack("!L", netR+n)) for n in range(0, 1<<32-Wholemask)): try: print "Doing host",host RunScanner(host) except: pass else: RunScanner(host) To launch : python script.py 10.50.23.0/24 The problem I'm having is that even with a ridiculous low settimeout value set, it takes ages to cover the 255 ip addresses since most of them are not assigned to a machine. How can i make a way faster scanner that wont get stuck if the port is close.MultiThreading ? Thanks !

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  • Using varible in re.match in python

    - by screwuphead
    I am trying to create an array of things to match in a description line. So I cant ignore them later on in my script. Below is a sample script that I have been working on, on the side. Basically I am trying to take a bunch of strings and match it against a bunch of other strings. AKA: asdf or asfs or wrtw in string = true continue with script if not print this. import re ignorelist = ['^test', '(.*)set'] def guess(a): for ignore in ignorelist: if re.match(ignore, a): return('LOSE!') else: return('WIN!') a = raw_input('Take a guess: ') print guess(a) Thanks

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  • Second largest number in list python

    - by Manu Lakaster
    So I have to find THE SECOND LARGEST NUMBER IN A LIST. I am doing it through simple loops.My approach is I am going to divide a list into two parts and then find the largest number into two parts and then compare two nuumbers. I will choose the smaller number from two of them. I can not use ready functions or different approaches. Basically, this is my code....But it does not run correctly....Help me please to fix it because I spent a lot of time on it :( Thanks....P.S. Can we use indices to "divide" a list ??? #!/usr/local/bin/python2.7 alist=[-45,0,3,10,90,5,-2,4,18,45,100,1,-266,706] largest=alist[0] h=len(alist)/2 m=len(alist)-h print(alist) for i in alist: if alist[h]>largest: largest=alist[h] i=i+1 print(largest)

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  • Python: Give a class its own `self` at instantiation time

    - by SuperDisk
    I've got a button class that you can instantiate like so: engine.createElement((0, 0), Button(code=print, args=("Stuff!",))) And when it is clicked it will print "Stuff!". However, I need the button to destroy itself whenever it is clicked. Something like this: engine.createElement((0, 0), Button(code=engine.killElement, args=(self,))) However, that would just kill the caller, because self refers to the caller at that moment. What I need to do is give the class its own 'self' in advance... I thought of just making the string 'self' refer to the self variable upon click, but what if I wanted to use the string 'self' in the arguments? What is the way to do this? Is my architecture all wrong or something? Thanks.

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  • Resetting a while loop

    - by Patrick Beardmore
    I have found a confusing thing in a php script I am writing to generate some javascript. Here it is below, slightly simplified. The second while loop won't run unless I comment out the entire first while loop. Can anyone explain why? Many thanks. <?php $listid = 2; //DEMO ONLY $result1 = mysql_query("SELECT words.wid,words.wordmd5,words.word FROM words,instances WHERE words.wid = instances.wid AND instances.lid = \"$listid\""); $result1copy = $result1; $count1 = 1; while( $row = mysql_fetch_object( $result1 ) ) { print "words_left[$count1] = \"".$row->word."\";\n"; //Increment the array counter (starts at 1) $count1++; } ?> //Some javascript <?php $count2 = 1; while( $row = mysql_fetch_object( $result1copy ) ) { print " $count2 then $row->wordmd5 "; $count2++; } ?>

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  • Python "string_escape" vs "unicode_escape"

    - by Mike Boers
    According to the docs, the builtin string encoding string_escape: Produce[s] a string that is suitable as string literal in Python source code ...while the unicode_escape: Produce[s] a string that is suitable as Unicode literal in Python source code So, they should have roughly the same behaviour. BUT, they appear to treat single quotes differently: >>> print """before '" \0 after""".encode('string-escape') before \'" \x00 after >>> print """before '" \0 after""".encode('unicode-escape') before '" \x00 after The string_escape escapes the single quote while the Unicode one does not. Is it safe to assume that I can simply: >>> escaped = my_string.encode('unicode-escape').replace("'", "\\'") ...and get the expected behaviour?

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  • question about random select

    - by davit-datuashvili
    here is code print number in decreasing order import java.util.*; public class select { public static void Select(int m,int n){ Random r=new Random(); if (m>0) if (r.nextInt(0x3fff8001) % n <m ){ System.out.println(n-1); Select(m-1,n-1); } else{ Select(m,n-1); } } public static void main(String[]args){ int m=35; int n=200; Select(m,n); } } and question is how to changes code such that print number in increasing order? please help

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  • how to copy an array into somewhere else in the memory by using the pointer

    - by user2758510
    I am completely new in c++ programming. I want to copy the array called distances into where pointer is pointing to and then I want to print out the resul to see if it is worked or not. this is what I have done: int distances[4][6]={{1,0,0,0,1,0},{1,1,0,0,1,1},{1,0,0,0,0,0},{1,1,0,1,0,0}}; int *ptr; ptr = new int[sizeof(distances[0])]; for(int i=0; i<sizeof(distances[0]); i++){ ptr=distances[i]; ptr++; } I do not know how to print out the contents of the pointer to see how it works.

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  • String formatting [str.format()] with a dictionary having a key which is a str() of a number

    - by decimus phostle
    Python neophyte here. I was wondering if someone could help with the KeyError I am getting when using a dictionary for string interpolation in str.format. dictionary = {'key1': 'val1', '1': 'val2'} string1 = 'Interpolating {0[key1]}'.format(dictionary) print string1 The above works fine and yields: Interpolating val1 However doing the following: dictionary = {'key1': 'val1', '1': 'val2'} string2 = 'Interpolating {0[1]}'.format(dictionary) print string2 results in: Traceback (most recent call last): File "test.py", line 3, in <module> string2 = 'Interpolating {0[1]}'.format(dictionary) KeyError: 1L So the problem seems to be in the interpretation of the numeric key as a list index, IMHO. Is there any way to work around this? (i.e. convey that this is instead a dictionary key) TIA and apologies if this question has been asked before(couldn't find anything relevant with my search-fu).

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  • Why is Python 3.1 throwing a SyntaxError when printing after loop? [resolved]

    - by bubersson
    Hi, I'm trying to run this snippet in Python 3.1 console and I'm getting SyntaxError: >>> while True: ... a=5 ... if a<6: ... break ... print("hello") File "<stdin>", line 5 print("hello") ^ SyntaxError: invalid syntax >>> (This is just shortened code to make a point.) Am I missing something? Is there some other Magic I don't know about? Thanks for your help (since this is my first StackOverflow question and I'm not a native English speaker)

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