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  • FJSTransitionController setup and use in View Controller not main app delegate

    - by elliotrock
    I am trying to set up Corey Floyd's FJSTransitionController. My app uses a main view controller to manage the main view navigation. I also went through the source to fix it for ARC. Followed instructions and in my main delegate .h I have in the usual spots: FJTransitionController* mainTransitionController; @property (nonatomic,retain) FJTransitionController* mainTransitionController; delegate .m has the following @synthesize mainTransitionController And in the - (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions mainTransitionController=[[FJTransitionController alloc] init]; // do I need to instantise? [self.window addSubview:mainTransitionController.view]; [mainTransitionController setViewControllerClass:[[mainViewController sendMissionsPanelViewController] class] forKey:@"missionView"]; The last line is complaining that there is no @interface for FJTransitionController? Any help please.

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  • Threads in PHP.

    - by Muhammad Sajid
    Hello.. I am creating a web application using zend, here i create an interface from where user-A can send email to more than one user(s) & it works excellent but it slow the execution time because of which user-A wait too much for the "acknowledged response" ( which will show after the emails have sent. ) In Java there are "Threads" by which we can perform that task (send emails) & it does not slow the rest application. Is there any technique in PHP/Zend just like in Java by which we can divide our tasks which could take much time eg: sending emails. Thanks..

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  • How to pass a variable through url and use it inside a controller

    - by anthonypliu
    I have this controller: public ActionResult Details(String UserName) { using (var db = new MatchGamingEntities()) { var Users = from m in db.Users join m2 in db.MyProfiles on m.UserId equals m2.UserId where m.UserName == UserName select new UserViewModel { UserName = m.UserName, LastActivityDate = m.LastActivityDate, Address = m2.Address, City = m2.City, State = m2.State, Zip = m2.Zip }; return View(Users.SingleOrDefault()); } } I type in the url Profiles/Details/hello, but it does not work, if I do Profiles/Details?UserName=hello then it works. I have another ActionResult just like this except taking in an int id as parameter and it works fine with the first url format.

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  • Rails controller processing as HTML instead of XML

    - by Andy
    I've recently upgraded from Ruby 1.8.6 and Rails 2.3.4 to Ruby 1.9 and Rails 3.0.3. I have the following controller: class ChartController < ApplicationController before_filter :login_required respond_to :html, :xml def load_progress chart.add( :series, "Memorized", y_memorized ) chart.add( :series, "Learning", y_learning ) chart.add( :series, "Mins / Day", y_time ) chart.add( :user_data, :secondary_y_interval, time_axis_interval ) respond_to do |fmt| fmt.xml { render :xml => chart.to_xml } end # Also tried # respond_with chart end end However, when I call the 'load_progress method' I get the following: Started GET "/load_progress.xml" for 127.0.0. Processing by ChartController#load_progress as HTML Completed 406 Not Acceptable in 251ms I have also tried changing the respond_to block to respond_with chart But I get the same response. I've read all the new Rails documentation on the new respond_with format but I can't seem to elicit an XML response. Am desperately hoping someone has some ideas.

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  • Question and Answers form & controller problem

    - by user285245
    Hi, I have a Question table and an Answers table linked by questionID (1 to many). I'd like to be able to update both table from the one form. I can easily add a question but to have it also add the answers (into their own recordsets) is causing a headache. how do I set my form up to allow for the answers to be created and also what do I do in the Controller. Any help would be gratefully appreciated as I've not been able to locate any good examples on the web. thanks in advance.

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  • How to connect Model through Controller to View using bindings?

    - by Paperflyer
    I have an NSTextField in my view. Its value is bound to an NSNumber *number in my controller. The controller simply calls through to the model (value) to get the appropriate value. // In the controller - (NSNumber *)number { return [NSNumber numberWithFloat:[model value]]; } - (void)setNumber:(NSNumber *)aNumber { [model setValue:[aNumber floatValue]]; } This is fine, only the controller is not notified of model changes and thus, changing the value in the model does not update the NSTextField. The only other option I can think of is to have the model notify the controller and the controller manually update the view through an Outlet. But this circumvents the binding. // In the model, after value change [[NSNotificationCenter defaultCenter] postNotificationName:@"ValueChanged" object:self]; // In the controller, after being notified - (void)updateView:(NSNotification *)aNotification { [myTextField setFloatValue:[model value]]; } Is there a better, binding-aware way to implement this communication?

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  • Problems loading controller from url with codeigniter?

    - by Cody Short
    I'm currently in the process of putting up my first website for public use. I am using the codeigniter framework in order to do this, but I am having trouble loading the controllers from the url. I currently have the default codeigniter installment that you download trying to get things to work. The controller welcome is loaded by default, but when I try to load it through the url it doesn't work. I was having the same problem with the site that I had uploaded earlier. The site is located at this link any help on this would be appreciated.

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  • Micro Controller Serial Data identification or classification

    - by Posiedon
    I have a x51 family micro controller (P89V51RD2). I'm going to send some data from computer using serial port. The data i'll be sending are Character 'S' Character 'R' and a 2 digit integer. Upon receiving the data, I will be calling separate functions. I used if(chr=='S') and elseif(chr=='R')for character data. The main problem lies with identifying the 2 digit number sent. Any other data other than the above three mentioned will be discarded. Any ideas for identifying two digit integer ??

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  • Pass parameter to controller from @Html.ActionLink MVC 4

    - by NetraSW
    Hello All, @Html.ActionLink("Reply", "BlogReplyCommentAdd", "Blog", new { blogPostId = blogPostId, replyblogPostmodel = Model, captchaValid = Model.AddNewComment.DisplayCaptcha }) In above line: I get error on blogPostId. The parameters dictionary contains a null entry for parameter 'blogPostId' of non-nullable type 'System.Int32' for method 'System.Web.Mvc.ActionResult BlogReplyCommentAdd(Int32, Nop.Web.Models.Blogs.BlogPostModel, Boolean)' in 'Nop.Web.Controllers.BlogController'. An optional parameter must be a reference type, a nullable type, or be declared as an optional parameter. Parameter name: parameters I have already assign a value for this on top such as @{ var blogPostId = Model.Id; } My Controller : public ActionResult BlogReplyCommentAdd(int blogPostId, BlogPostModel model, bool captchaValid) {} M i doing something wrong? Please give me an example on this. Thanks

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  • Pass a datatable model to controller action in MVC

    - by user2906420
    Code: @model System.Data.DataTable <button type="submit" class="btn btn-primary" data-dismiss="modal" aria-hidden="true"> Download</button> [HttpPost] public void getCSV(DataTable dt) { MemoryStream stream = Export.GetCSV(dt); var filename = "ExampleCSV.csv"; var contenttype = "text/csv"; Response.Clear(); Response.ContentType = contenttype; Response.AddHeader("content-disposition", "attachment;filename=" + filename); Response.Cache.SetCacheability(HttpCacheability.NoCache); Response.BinaryWrite(stream.ToArray()); Response.End(); } I want to allow the user to export a CSV file when the button is clicked on. the datatable should be passed to the method getCSV. Please can someone help me. thanks I do not mind using Tempdata to store the datatable and then access it in the controller

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  • Problem in building a tab bar inside navigation controller

    - by Heba
    Hello Everyone! I am really frustrated and I rally hope that you will help me to solve this problem! I'm trying to build a tab bar inside a navigation controller. I used this template provided by WiredBob. My problem is that I want to add more bar items to the tab bar, but I keep getting crash! From the log: 2010-05-24 00:15:43.469 NavTab[9315:207] * Terminating app due to uncaught exception 'NSInternalInconsistencyException', reason: '-[UITableViewController loadView] loaded the "AnnView" nib but didn't get a UITableView.' Also, I tried to fix the size of the a view in IB to fit in with the tab bar, but I couldn't! It was unchangeable. Thanks in advance :-)

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  • rootview controller in Interface builder?

    - by senthilmuthu
    hi, i have done in didapplicationfinishing function tabBarController = [[UITabBarController alloc] init] ; tabBarController.navigationItem.title = @"News"; SimpleTableViewController *rtbfViewController = [[SimpleTableViewController alloc] init]; //initWithStyle:UITableViewStyleGrouped]; rtbfViewController.tabBarItem.title = @"News1"; rtbfViewController.tabBarItem.image = [UIImage imageNamed:@"home.png"];; UINavigationController *table2NavController = [[[UINavigationController alloc] initWithRootViewController:rtbfViewController] autorelease]; [rtbfViewController release]; it works fine .suppose if i have Navigation controller in Interface Builder,how can i set initWithRootViewController in Interface builder?

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  • Codeigniter: Using data in a controller

    - by Kevin Brown
    I'm new to php and CI, and I'm having some trouble in my controller. I feel that I'm doing this the wrong way, and it could be easier, I just don't know the syntax: $data['members'] = $this->home_model->getUser($id); $credit = $this->home_model->getCredit($id); if ($credit == '0'){stuff...} So I'm getting the user's data that has their the same information as "getCredit" does, but I don't know how to get the single variable that I need for my if statement... How can I just use the "getUser" function so that I'm not pulling redundant information?

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  • Connecting SceneBuilder edited FXML to Java code

    - by daniel
    Recently I had to answer several questions regarding how to connect an UI built with the JavaFX SceneBuilder 1.0 Developer Preview to Java Code. So I figured out that a short overview might be helpful. But first, let me state the obvious. What is FXML? To make it short, FXML is an XML based declaration format for JavaFX. JavaFX provides an FXML loader which will parse FXML files and from that construct a graph of Java object. It may sound complex when stated like that but it is actually quite simple. Here is an example of FXML file, which instantiate a StackPane and puts a Button inside it: -- <?xml version="1.0" encoding="UTF-8"?> <?import java.lang.*?> <?import java.util.*?> <?import javafx.scene.control.*?> <?import javafx.scene.layout.*?> <?import javafx.scene.paint.*?> <StackPane prefHeight="150.0" prefWidth="200.0" xmlns:fx="http://javafx.com/fxml"> <children> <Button mnemonicParsing="false" text="Button" /> </children> </StackPane> ... and here is the code I would have had to write if I had chosen to do the same thing programatically: import javafx.scene.control.*; import javafx.scene.layout.*; ... final Button button = new Button("Button"); button.setMnemonicParsing(false); final StackPane stackPane = new StackPane(); stackPane.setPrefWidth(200.0); stackPane.setPrefHeight(150.0); stacPane.getChildren().add(button); As you can see - FXML is rather simple to understand - as it is quite close to the JavaFX API. So OK FXML is simple, but why would I use it?Well, there are several answers to that - but my own favorite is: because you can make it with SceneBuilder. What is SceneBuilder? In short SceneBuilder is a layout tool that will let you graphically build JavaFX user interfaces by dragging and dropping JavaFX components from a library, and save it as an FXML file. SceneBuilder can also be used to load and modify JavaFX scenegraphs declared in FXML. Here is how I made the small FXML file above: Start the JavaFX SceneBuilder 1.0 Developer Preview In the Library on the left hand side, click on 'StackPane' and drag it on the content view (the white rectangle) In the Library, select a Button and drag it onto the StackPane on the content view. In the Hierarchy Panel on the left hand side - select the StackPane component, then invoke 'Edit > Trim To Selected' from the menubar That's it - you can now save, and you will obtain the small FXML file shown above. Of course this is only a trivial sample, made for the sake of the example - and SceneBuilder will let you create much more complex UIs. So, I have now an FXML file. But what do I do with it? How do I include it in my program? How do I write my main class? Loading an FXML file with JavaFX Well, that's the easy part - because the piece of code you need to write never changes. You can download and look at the SceneBuilder samples if you need to get convinced, but here is the short version: Create a Java class (let's call it 'Main.java') which extends javafx.application.Application In the same directory copy/save the FXML file you just created using SceneBuilder. Let's name it "simple.fxml" Now here is the Java code for the Main class, which simply loads the FXML file and puts it as root in a stage's scene. /* * Copyright (c) 2012, Oracle and/or its affiliates. All rights reserved. */ package simple; import java.util.logging.Level; import java.util.logging.Logger; import javafx.application.Application; import javafx.fxml.FXMLLoader; import javafx.scene.Scene; import javafx.scene.layout.StackPane; import javafx.stage.Stage; public class Main extends Application { /** * @param args the command line arguments */ public static void main(String[] args) { Application.launch(Main.class, (java.lang.String[])null); } @Override public void start(Stage primaryStage) { try { StackPane page = (StackPane) FXMLLoader.load(Main.class.getResource("simple.fxml")); Scene scene = new Scene(page); primaryStage.setScene(scene); primaryStage.setTitle("FXML is Simple"); primaryStage.show(); } catch (Exception ex) { Logger.getLogger(Main.class.getName()).log(Level.SEVERE, null, ex); } } } Great! Now I only have to use my favorite IDE to compile the class and run it. But... wait... what does it do? Well nothing. It just displays a button in the middle of a window. There's no logic attached to it. So how do we do that? How can I connect this button to my application logic? Here is how: Connection to code First let's define our application logic. Since this post is only intended to give a very brief overview - let's keep things simple. Let's say that the only thing I want to do is print a message on System.out when the user clicks on my button. To do that, I'll need to register an action handler with my button. And to do that, I'll need to somehow get a handle on my button. I'll need some kind of controller logic that will get my button and add my action handler to it. So how do I get a handle to my button and pass it to my controller? Once again - this is easy: I just need to write a controller class for my FXML. With each FXML file, it is possible to associate a controller class defined for that FXML. That controller class will make the link between the UI (the objects defined in the FXML) and the application logic. To each object defined in FXML we can associate an fx:id. The value of the id must be unique within the scope of the FXML, and is the name of an instance variable inside the controller class, in which the object will be injected. Since I want to have access to my button, I will need to add an fx:id to my button in FXML, and declare an @FXML variable in my controller class with the same name. In other words - I will need to add fx:id="myButton" to my button in FXML: -- <Button fx:id="myButton" mnemonicParsing="false" text="Button" /> and declare @FXML private Button myButton in my controller class @FXML private Button myButton; // value will be injected by the FXMLLoader Let's see how to do this. Add an fx:id to the Button object Load "simple.fxml" in SceneBuilder - if not already done In the hierarchy panel (bottom left), or directly on the content view, select the Button object. Open the Properties sections of the inspector (right panel) for the button object At the top of the section, you will see a text field labelled fx:id. Enter myButton in that field and validate. Associate a controller class with the FXML file Still in SceneBuilder, select the top root object (in our case, that's the StackPane), and open the Code section of the inspector (right hand side) At the top of the section you should see a text field labelled Controller Class. In the field, type simple.SimpleController. This is the name of the class we're going to create manually. If you save at this point, the FXML will look like this: -- <?xml version="1.0" encoding="UTF-8"?> <?import java.lang.*?> <?import java.util.*?> <?import javafx.scene.control.*?> <?import javafx.scene.layout.*?> <?import javafx.scene.paint.*?> <StackPane prefHeight="150.0" prefWidth="200.0" xmlns:fx="http://javafx.com/fxml" fx:controller="simple.SimpleController"> <children> <Button fx:id="myButton" mnemonicParsing="false" text="Button" /> </children> </StackPane> As you can see, the name of the controller class has been added to the root object: fx:controller="simple.SimpleController" Coding the controller class In your favorite IDE, create an empty SimpleController.java class. Now what does a controller class looks like? What should we put inside? Well - SceneBuilder will help you there: it will show you an example of controller skeleton tailored for your FXML. In the menu bar, invoke View > Show Sample Controller Skeleton. A popup appears, displaying a suggestion for the controller skeleton: copy the code displayed there, and paste it into your SimpleController.java: /** * Sample Skeleton for "simple.fxml" Controller Class * Use copy/paste to copy paste this code into your favorite IDE **/ package simple; import java.net.URL; import java.util.ResourceBundle; import javafx.fxml.FXML; import javafx.fxml.Initializable; import javafx.scene.control.Button; public class SimpleController implements Initializable { @FXML // fx:id="myButton" private Button myButton; // Value injected by FXMLLoader @Override // This method is called by the FXMLLoader when initialization is complete public void initialize(URL fxmlFileLocation, ResourceBundle resources) { assert myButton != null : "fx:id=\"myButton\" was not injected: check your FXML file 'simple.fxml'."; // initialize your logic here: all @FXML variables will have been injected } } Note that the code displayed by SceneBuilder is there only for educational purpose: SceneBuilder does not create and does not modify Java files. This is simply a hint of what you can use, given the fx:id present in your FXML file. You are free to copy all or part of the displayed code and paste it into your own Java class. Now at this point, there only remains to add our logic to the controller class. Quite easy: in the initialize method, I will register an action handler with my button: () { @Override public void handle(ActionEvent event) { System.out.println("That was easy, wasn't it?"); } }); ... -- ... // initialize your logic here: all @FXML variables will have been injected myButton.setOnAction(new EventHandler<ActionEvent>() { @Override public void handle(ActionEvent event) { System.out.println("That was easy, wasn't it?"); } }); ... That's it - if you now compile everything in your IDE, and run your application, clicking on the button should print a message on the console! Summary What happens is that in Main.java, the FXMLLoader will load simple.fxml from the jar/classpath, as specified by 'FXMLLoader.load(Main.class.getResource("simple.fxml"))'. When loading simple.fxml, the loader will find the name of the controller class, as specified by 'fx:controller="simple.SimpleController"' in the FXML. Upon finding the name of the controller class, the loader will create an instance of that class, in which it will try to inject all the objects that have an fx:id in the FXML. Thus, after having created '<Button fx:id="myButton" ... />', the FXMLLoader will inject the button instance into the '@FXML private Button myButton;' instance variable found on the controller instance. This is because The instance variable has an @FXML annotation, The name of the variable exactly matches the value of the fx:id Finally, when the whole FXML has been loaded, the FXMLLoader will call the controller's initialize method, and our code that registers an action handler with the button will be executed. For a complete example, take a look at the HelloWorld SceneBuilder sample. Also make sure to follow the SceneBuilder Get Started guide, which will guide you through a much more complete example. Of course, there are more elegant ways to set up an Event Handler using FXML and SceneBuilder. There are also many different ways to work with the FXMLLoader. But since it's starting to be very late here, I think it will have to wait for another post. I hope you have enjoyed the tour! --daniel

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  • Is there a way to route all traffic from Android through a proxy/tunnel to my Tomato router?

    - by endolith
    I'd like to be able to connect my Android phone to public Wi-Fi points with unencrypted connections, but People can see what I'm doing by intercepting my radio transmissions People who own the access point can see what I'm doing. There are tools like WeFi and probably others to automatically connect to access points, but I don't trust random APs. I'd like all my traffic to go through an encrypted tunnel to my home router, and from there out to the Internet. I've done such tunnels from other computers with SSH/SOCKS and PPTP before. Is there any way to do this with Android? I've asked the same question on Force Close, so I'll change this question to be about both sides of the tunnel. More specifically: My phone now has CyanogenMod 4.2.3 My router currently has Tomato Version 1.25 I'm willing to change the router firmware, but I was having issues with DD-WRT disconnecting, which is why I'm using Tomato. Some possible solutions: SSH with dynamic SOCKS proxy: Android supposedly supports this through ConnectBot, but I don't know how to get it to route all traffic. Tomato supports this natively. I've been using this with MyEntunnel for my web browsing at work. Requires setting up each app to go through the proxy, though. PPTP: Android supports this natively. Tomato does not support this, unless you get the jyavenard mod and compile it? I previously used PPTP for web browsing at work and in China because it's native in Windows and DD-WRT. After a while I started having problems with it, then I started having problems with DD-WRT, so I switched to the SSH tunnel instead. Also it supposedly has security flaws, but I don't understand how big of a problem it is. IPSec L2TP: Android (phone) and Windows (work/China) both support this natively I don't know of a router that does. I could run it on my computer using openswan, but then there are two points of failure. OpenVPN: CyanogenMod apparently includes this, and now has an entry to create a new OpenVPN in the normal VPN interface, but I have no idea how to configure it. TunnelDroid apparently handles some of this. Future versions will have native support in the VPN settings? Tomato does not support this, but there are mods that do? I don't know how to configure this, either. TomatoVPN roadkill mod SgtPepperKSU mod Thor mod I could also run a VPN server on my desktop, I guess, though that's less reliable and presumably slower than running it in the router itself. I could change the router firmware, but I'm wary of more fundamental things breaking. Tomato has been problem-free for the regular stuff. Related: Anyone set up a SSH tunnel to their (rooted) G1 for browsing?

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  • What is a reasonable range for signal strength when next to my router?

    - by Jeff
    I know that these things depend largely on specific hardware but I don't even know if I am in the neighborhood. What would a reasonable range of signal strength be when my device is less than 5 feet from my router? House3 is my main router at 61% strength and that seems very low! Repeater is my... repeater which is 50' away in the next room. I'm not terribly concerned with the Repeater until I get my main router settled.

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  • Accessing IPv6 router interface from a minimal Fedora installation?

    - by Zack
    I've recently installed Fedora 16 and am trying to set up a simple apache server. The only problem I've run into so far is that I'm unable to access my router's web interface from any box on my network. It assigns addresses via dhcp, and the router always responds to a ping. The server is also picking up an IP from the router on the proper subnet. Now, all I really need to do is forward a port, however I am receiving "Unable to connect" through the web interfaces and "connection refused" via telnet. What are my options, and how might I go about troubleshooting this? Will I need the server's ip to be static in order to change these settings? The router is a "Netopia" model, if that helps.

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  • If a raid controller changes, are the drives still usable without re-formatting?

    - by Jeremy
    I've been wanting to do a raid 1 setup in my home with a pair of sata drives. Someone told me that if the controller fails, you can't just get a new controller because you'll have to reformat the drives. Or is that true only in some implementations? I was originally just looking at an onboard raid controller, or an entry level nas drvice like the intel SS4200-E, but If the hardware (controller) ever fails, will I be out of luck accessing the data if I can't get the exact same hardware to replace it?

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  • How can I force Parallels' networking to obtain an IP through a wireless router?

    - by RLH
    Here is my setup. I have a Macbook, Thunderbolt display and an Ethernet connection plugged into the Thunderbolt display. During the day, most of my network use can (and should) operate across the ethernet associated with my display. However, I also need to be able to connect up to a wireless router. This hasn't been a problem on the Mac OS X side, but the program that I need to run on the router has to obtain an IP address from the wireless access point. Considering my current setup, how can I leave it so that I can access the internet in OS X, yet have my Window 7 instance running in Parallels, get it's assigned IP address from a wireless router that my Mac is also connected to? I've fiddled around with the Parallel's network settings for an hour, and I can't get Parallel's to see the router, even though my Mac is certainly connected to it.

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  • How to detect/list rogue computers connected to a WIFI network without access to the Wifi Router interface?

    - by JJarava
    This is what I believe to be an interesting challenge :) A relative (that leaves a bit too far to go there in person) is complaining that their WIFI/Internet network performance has gone down abysmally lately. She'd like to know if some of the neighbors are using her wifi network to access the internet but she's not too technically savvy. I know that the best way to prevent issues would be to change the Router password, but it's a bit of a PITA having to re-configure all wifi devices... and if the uninvited guest broke the password once, they can do it again... Her wifi router/internet connection is provided by the telco, and remotely managed so she can log-on to their telco account's page and remotely change the router's Wifi password, but doesn't have access to the router status page/config/etc unless she opts out of the telco's remote support and mainteinance service... So, how could she check if there are guests in the wifi with this restrictions and in the most "point and click way"? In this case I'd probably use nmap to look for other devices in the network, but I'm not sure if that's the easiest way to do it. I'm not a wifi expert, so I don't know if there are any wifi-scanning utils that can tell us who's talking to the router... Lastly, she's a Windows user as I guess that'll influence the choice of tools available Any suggestions more than welcome Regards!

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  • How can I configure multiple default gateways on a CISCO Router?

    - by Spirit
    Does any one knows a way to configure a cisco router with multiple gateways - multiple gateways of last resort? I've tried adding a gateway of last resort twice (with different metric) but only one is shown: Router(config)# ip route 0.0.0.0 0.0.0.0 2.2.2.2 10 Router(config)# ip route 0.0.0.0 0.0.0.0 3.3.3.3 100 And the show ip route output was: Router# show ip route Gateway of last resort is 2.2.2.2 to network 0.0.0.0 2.0.0.0/24 is subnetted, 1 subnets C 2.2.2.0 is directly connected, FastEthernet0/0 3.0.0.0/24 is subnetted, 1 subnets C 3.3.3.0 is directly connected, FastEthernet0/1 32.0.0.0/30 is subnetted, 1 subnets C 32.2.2.0 is directly connected, Serial0/2/0 S* 0.0.0.0/0 [10/0] via 2.2.2.2 The point is that i cannot see the other route with higher distance metric? Anyone has a sugestion? I mean will this config work if the link on 2.2.2.2 fails? Will the router choose the other network 3.3.3.3, if the link 2.2.2.2 fails?

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  • Cable installed - now my hub has no connection the router/modem - what do I need to buy?

    - by bcmcfc
    My previous setup was as follows: [modem/router]------[switch]+------ [pc1] +------ [pc2] I've just moved and had cable installed and I no longer have the option of running a lengthy LAN cable from the router to the switch to provide network and internet access to the two PCs. The cable company provided 2 wireless N USB adapters. What do I need to buy to plug into where in order to restore the network to its previous state? PC1 dual boots Windows 7 and Ubuntu 12. PC2 runs Debian 6. Edit: USB adapters - Netgear WNDA3200 Switch - TP-Link TL-SF1008D 8 port Ethernet switch Cabling - various patch cables cat5e rj45 Modem/Router - pretty standard cable company job - wireless Intention is something like- [modem/router] --wifi-- [some-new-hardware or perhaps to pc1] ----[switch]---[pc1/2]

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  • How to detect/list rogue computers connected to a WIFI network without access to the Wifi Router interface? [migrated]

    - by JJarava
    This is what I believe to be an interesting challenge :) A relative (that leaves a bit too far to go there in person) is complaining that their WIFI/Internet network performance has gone down abysmally lately. She'd like to know if some of the neighbors are using her wifi network to access the internet but she's not too technically savvy. I know that the best way to prevent issues would be to change the Router password, but it's a bit of a PITA having to re-configure all wifi devices... and if the uninvited guest broke the password once, they can do it again... Her wifi router/internet connection is provided by the telco, and remotely managed so she can log-on to their telco account's page and remotely change the router's Wifi password, but doesn't have access to the router status page/config/etc unless she opts out of the telco's remote support and mainteinance service... So, how could she check if there are guests in the wifi with this restrictions and in the most "point and click way"? In this case I'd probably use nmap to look for other devices in the network, but I'm not sure if that's the easiest way to do it. I'm not a wifi expert, so I don't know if there are any wifi-scanning utils that can tell us who's talking to the router... Lastly, she's a Windows user as I guess that'll influence the choice of tools available Any suggestions more than welcome Regards!

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  • How to get stable WIFI connection between phone and router when thousands of irrelevant phones are around?

    - by Karl
    I want to use Android phones to check tickets at the gate of an event. These phones are connected to a password protected router (WPA2) and a PC to validate. That all works nicely in a test setting, but I'm worried it might collaps if there are many other competing phones around. How can I get a stable WIFI connection between my phones and my router when thousands of irrelevant phones are around? Do the other phones clogg the router with requests even when the router is password protected? Shall I hide the SSID?

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  • MVC : Does Code to save data in cache or session belongs in controller?

    - by newbie
    I'm a bit confused if saving the information to session code below, belongs in the controller action as shown below or should it be part of my Model? I would add that I have other controller methods that will read this session value later. public ActionResult AddFriend(FriendsContext viewModel) { if (!ModelState.IsValid) { return View(viewModel); } // Start - Confused if the code block below belongs in Controller? Friend friend = new Friend(); friend.FirstName = viewModel.FirstName; friend.LastName = viewModel.LastName; friend.Email = viewModel.UserEmail; httpContext.Session["latest-friend"] = friend; // End Confusion return RedirectToAction("Home"); } I thought about adding a static utility class in my Model which does something like below, but it just seems stupid to add 2 lines of code in another file. public static void SaveLatestFriend(Friend friend, HttpContextBase httpContext) { httpContext.Session["latest-friend"] = friend; } public static Friend GetLatestFriend(HttpContextBase httpContext) { return httpContext.Session["latest-friend"] as Friend; }

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