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  • Google interdit l'accès aux applications Android aux tablettes et livres électroniques, seuls les sm

    Google interdit l'accès aux applications Android aux tablettes et livres électroniques, seuls les smartphones y sont bienvenus Après des discussions enflammées autour de l'AppStore et des politiques parfois douteuses d'approbation des applications d'Apple, c'est au tour de l'Android Market de faire la polémique. Malgré que l'OS Android soit open-source et adaptable sur de multiples appareils (téléphone, tablette, cadre photo, etc.) ; Google excerce un contrôle musclé de son marché d'applications sur lequel il n'accepte que les smartphones. Pour pouvoir accèder à l'Android Market, le mobile doit répondre à plusieurs critères : il doit possèder un écran tactile, le wi-fi, une cméra, etc... La liste est longue.

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  • Upgrading a live 8.04 LTS server to More uptodate version

    - by richardhx
    Running Apache, MySQL, PHP with Moodle 1.9.9 running as a school based CMS. All possible updates for 8.04 have been applied. Moodle 2.x from Versions 2.1 onwards needs Php version 5.3.2 which is included in more recent distribution version. Would I be better (safer) upgrading php & mysql or upgrading Ubuntu to a more recent version? - if upgrading Ubuntu is better, are there any caveats i should know before attempting this. I will be taking a Copy of the entire server before doing any upgrading. Hoping to run on a test version also. Bit green on Linux hence lack of confidence.

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  • Technically, How does uploading Apps to an Android Phone Work?

    - by unixman83
    Amazon.com has an Android Marketplace. How do the apps go from Amazon.com to my phone? I am looking for a protocol level analysis. Do they use a basic protocol like FTP and then check with a Google digital signature? I do not own an Android. I wish for an explanation of how the protocol operates because I want to provide an android app for free download for my users off my website, like Amazon does.

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  • Google traine à corriger un bug faisant disparaître certaines applications de l'Android Market, son

    Google traine à corriger un bug faisant disparaître certaines applications de l'Android Market, son service technique est-il assez compétent ? Ca gronde dans la communauté des développeurs Android, après que plusieurs cas de soucis avec la publications d'applications sur l'Android Market aient été racontés dans des forums spécialisés. D'après les récits qui y sont faits, il serait difficile de pouvoir entrer en contact avec un être humain du staff de Google, puisque la firme privilégie un suivi via FAQ, forum ou e-mail. Autrement dit, en cas de problème, le service technique serait long à la détente. Or, vendredi dernier, de nombreux développeurs ayant renvoyé leurs applications à l'Android Market après les avoir mis...

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  • (Android) How are OpenGL ES 1 framebuffers and textures sized?

    - by jens
    I am trying to draw to a texture using a framebuffer using OpenGL ES 1.1 on Android, Java. Afterwords I want to overlay this texture full-screen over my game. In theory, this works like a charm, but somehow the coordinates are off. For testing I drew something at (0,0) with width and height 200, and it partly is off-screen. This is how I create the framebuffer: fb = new int[1]; depthRb = new int[1]; renderTex = new int[1]; gl11ep.glGenFramebuffersOES(1, fb, 0); gl11ep.glGenRenderbuffersOES(1, depthRb, 0); // the depth buffer gl.glGenTextures(1, renderTex, 0);// generate texture gl.glBindTexture(GL10.GL_TEXTURE_2D, renderTex[0]); gl.glTexParameterf(GL10.GL_TEXTURE_2D, GL10.GL_TEXTURE_MIN_FILTER, GL10.GL_LINEAR); gl.glTexParameterf(GL10.GL_TEXTURE_2D, GL10.GL_TEXTURE_MAG_FILTER, GL10.GL_LINEAR); gl.glTexParameterf(GL10.GL_TEXTURE_2D, GL10.GL_TEXTURE_WRAP_S, GL10.GL_REPEAT); gl.glTexParameterf(GL10.GL_TEXTURE_2D, GL10.GL_TEXTURE_WRAP_T, GL10.GL_REPEAT); texBuffer = ByteBuffer.allocateDirect(buf.length*4).order(ByteOrder.nativeOrder()).asIntBuffer(); gl.glTexImage2D(GL10.GL_TEXTURE_2D, 0, GL10.GL_LUMINANCE, texW, texH, 0, GL10.GL_LUMINANCE, GL10.GL_UNSIGNED_BYTE, texBuffer); gl11ep.glBindRenderbufferOES(GL11ExtensionPack.GL_RENDERBUFFER_OES, depthRb[0]); gl11ep.glRenderbufferStorageOES(GL11ExtensionPack.GL_RENDERBUFFER_OES, GL11ExtensionPack.GL_DEPTH_COMPONENT16, texW, texH); Before I draw, I do this: gl11ep.glBindFramebufferOES(GL11ExtensionPack.GL_FRAMEBUFFER_OES, fb[0]); gl.glClearColor(0f, 0f, 0f, 0f); // specify texture as color attachment gl11ep.glFramebufferTexture2DOES(GL11ExtensionPack.GL_FRAMEBUFFER_OES, GL11ExtensionPack.GL_COLOR_ATTACHMENT0_OES, GL10.GL_TEXTURE_2D, renderTex[0], 0); // attach render buffer as depth buffer gl11ep.glFramebufferRenderbufferOES(GL11ExtensionPack.GL_FRAMEBUFFER_OES, GL11ExtensionPack.GL_DEPTH_ATTACHMENT_OES, GL11ExtensionPack.GL_RENDERBUFFER_OES, depthRb[0]); I set texW = 1024 and texH = 512. When rendering this texture fullscreen, with a lightmask (size 200x200) placed at (0, 0) and (texW/2, texH/2). You can see that it seems like the coordinate system doesnt start at (0,0) as that light overlaps the screen and the images are not drawn as squares (my lightcone-texture is a circle, not an ellipse). So, how is the coordinate system of this offscreen-drawn texture defined? Thanks

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  • Sortie de PostgreSQL 9.2 en version finale : performances et extensibilité accrues, flexibilité orientée développeurs

    Le PostgreSQL Global Development Group annonce la sortie de PostgreSQL 9.2, dernière version en date du système de gestion de bases de données libre de référence. Depuis l'annonce de la version bêta en mai, les développeurs et les intégrateurs louent les avancées en terme de performance, de flexibilité et d'extensibilité. Ils s'attendent à une adoption massive de cette version. [IMG]http://scheu.developpez.com/tutoriels/postgresql/log-shipping/images/logo-pgsql.png[/IMG] « PostgreSQL 9.2 intègre le support natif de JSON, les index couvrants, des performances et une réplication encore améliorées, et beaucoup d'autres fonctionnalités. Nous attendons cette version avec impatience. Elle sera disponible en "Early Access" dès sa...

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  • Google Drive SDK: Writing your first Drive app on Android

    Google Drive SDK: Writing your first Drive app on Android If you want to write a Drive app on Android and don't know how to get started, this is the sessions for you. We'll start from the very basics and go through all the steps needed to build an Android app that uses the device camera to take pictures and upload them to Google Drive. From: GoogleDevelopers Views: 0 0 ratings Time: 03:30:00 More in Science & Technology

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  • How can I use Android as a remote control for streaming?

    - by michael
    I would like to know if I can use Android to remote control streaming on my laptop? I would like to use my laptop as my streaming server and use my HDTV to view the stream. And I need some way to remote control my streaming server. I have read about http://maketecheasier.com/install-vlc-shares-in-Ubuntu-and-stream-videos-to-Android/2011/02/25 and http://code.google.com/p/android-vlc-remote/ but those are streaming to Android phone itself. I am just need something to remote control streaming to my TV. Is that possible?

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  • Eclipse will not install Android Support Package [migrated]

    - by Michael Mossman
    I am an experienced programmer but new to Android, hence using Eclipse for the first time. Unfortunately I cannot get my first project off the ground. I get as far trying to create the project when the following sequence happens. A screen arrives titled 'Install Dependencies' telling me that the required version is 8 and the installed version is 'Not installed' I click on the Install/Upgrade button and something must happen because Android SDK Manager pops up and I get a whole series of 'Fetching:' messages. The next screen asks me to Choose Package to Install and the only option is Android Support Library, revision 10. This doesn't bother me as I presume 10 is better than 8 so I hit the Install button. This is where it all goes wrong as I get a red message saying: File not found: C:\Program Files (X86)\Android\android-sdk\temp\support_r10.zip (Access is denied). Sure enough, when I check this folder, it is empty. Now, something must have happened as as SDK Manager did a whole lot of fetching and must have put these files somewhere. I am quite happy to find them and put them in the correct folder but the question is what is the name of the files that I am looking for?

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  • jQuery - upgrade from version 1.6.x to 1.7

    - by Renso
    Goal: Issues to consider when upgrading from jQuery version 1.6 to 1.7. This is a short list and may help identify the real issues you need to concern yourself with in stead of reading through all the release notesSummary of issues encountered during upgrade:As you prepare for upgrade to jQuery 1.7 from 1.6.x, this is a quick glimpse of all the issues that are relevant, not sure if it covers all but may be all you need to worry about.Use this method only for checking checkboxes and radio buttons:$("input:checked")http://api.jquery.com/checked-selector/This will work regardless of the version of jQuery you are using. Note that $("input).attr("checked") returns true prior to jQuery 1.6. Only retrieve "real" attributes with "attr", in order versions it would also retrieve properties like "tagName", this no longer works with jQuery 1.6.1+Why does $("input").attr("checked") no longer (from version 1.6.1+) return TRUE or FALSE, because if you look at the HTML (as well as W3C spec) it does not contain a true/false, but the value checked="checked", which is what it should have returned in the first place. $("input").prop("checked") works, return true, because there is in fact a DOM property for "checked" with the value being "true" or "false".Furthermore, if you want to upgrade to jQuery 1.7 you should only have to worry about this for most part:1. isNumeric() is new, be careful as the older version jQuery.isNaN() has been deprecated2. jqXHR success and error have been deprecated3. When rendering content with text(), white space issue cross-browsers: http://bugs.jquery.com/ticket/3144Other than the issues above I am not aware of any deprecations you need to worry about.Hope this helps to get everyone up to version 1.7

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  • What version(s) of Android should I be targeting?

    - by Bill Osuch
    If you're wondering about what screen sizes and flavors of Android are currently out in the wild, the Android Developers site has a handy little chart of both (each image below is hyperlinked to the page): So, as far as platforms go, there aren't many people still out there running less than 2.X... and you'd probably be safe not worrying about Small or Low Density screens. I'd be curious to know if any of the other app stores (Amazon, Archos, etc.) offer similar stats...

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  • Android pourra-t-il surpasser Windows ? En 2016, il y aurait plus de dispositifs sous Android que sous Windows selon Gartner

    Android pourra-t-il surpasser Windows ? En 2016, il y aurait plus de dispositifs sous Android que sous Windows. Le cabinet d'études Gartner prédit des changements massifs dans le secteur de la technologie et plus précisément des systèmes d'exploitation. Selon son rapport publié mercredi dernier, Android, le Système d'exploitation de Google équipera d'ici quatre ans plus d'appareils que Windows. [IMG]http://rdonfack.developpez.com/images/AndroidStand.png[/IMG] Selon les statistiques de Gartner, à la fin de 2016, il y aurait environ 2,3 milliards d'ordinateurs, tablettes et smartphones dotés d'Android, contre 2,28 milliards d'appareils Windows. Les analyste...

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  • Debian 6.0.6 disponible avec plusieurs correctifs de sécurité pour la version stable

    Debian 6.0.6 disponible avec plusieurs correctifs de sécurité pour la version stable Les développeurs de Debian viennent de publier la sixième mise à jour de la branche stable 6.0 du système d'exploitation basé sur le noyau Linux. Cette version n'apporte pas de nouvelles fonctionnalités à l'OS, mais juste une combinaison de mises à jour déjà publiées pour la distribution, permettant aux utilisateurs d'installer simplement cette version, au lieu de recherche et installer manuellement tous les patchs de sécurité. [IMG]http://rdonfack.developpez.com/images/debian.png[/IMG] Debian 6.0.6 alias « Squeeze » apporte donc plusieurs mises à j...

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  • Drupal 7 : la version finale est arrivée avec 800 modules complémentaires compatibles et prêt à l'utilisation

    Drupal 7 : la version finale est arrivée Avec 800 modules complémentaires compatibles et prêt à l'utilisation Mise à jour du 05/01/2011 par Idelways Drupal 7 en version finale et stable est enfin disponible après trois ans de développement, pour le plus grand bonheur des développeurs et intégrateurs Web adeptes de la puissance et de la flexibilité de ce système de gestion de contenus open-source et gratuit. Les développeurs principaux de cette version, épaulés par des milliers de contributeurs, ont axés leurs efforts sur l'amélioration de l'expérience utilisateur L'interface d'administration a subi un lif...

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  • 3.2.0-31-generic version doesn't boot

    - by user92526
    12.04 used to work just fine a month ago. Since August, I installed all of the available updates. Since then my mac-pro is acting weird. If I restart the computer, the screen gets stuck in the purple back ground without any texts. Then if I restart again, I can choose what versions of linux I want to run. If I select 3.2.0-31-generic, the machine gets stuck in a state of blinking cursor. If I boot again to run 3.2.0-31-generic recovery mode, the machine gets stuck in a "..... memory freed End of Stack" mode. I can't boot through this kernel. I have to choose an older version of linux like 3.2.0-12-generic to boot into my mac pro, but I have too boot twice to get into this version. I was wondering --if you could provide me a solution to boot the 3.2.0-31-generic version. -- if you could provide me a solution to boot into any version the first time I restart. (Usually I have to kill the first restart) --- If there is an option in linux to choose what version I want to run every time I restart so that I don't have to choose everytime. Thank you

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  • ?????????????Oracle Exadata Version 2????

    - by mamoru.kobayashi
    ????????????????????????Oracle Exadata Version 2???????????????? ????????????????????????????????Oracle Exadata Version 2?????????????????????????????????????????????????????????????????????Oracle Exadata Version 2?????Oracle Applications??????????????????????? ?????????????????????·??·??·??????????????????????????????????Biz ??????????????????????????????????????????????????????????????????? ????????????????

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  • Android: get current location from best available provider

    - by AP257
    Hi all, I have some Android code that needs to get the best available location QUICKLY, from GPS, network or whatever is available. Accuracy is less important than speed. Getting the best available location is surely a really standard task. Yet I can't find any code to demonstrate it. The Android location code expects you to specify criteria, register for updates, and wait - which is fine if you have detailed criteria and don't mind waiting around. But my app needs to work a bit more like the Maps app does when it first locates you - work from any available provider, and just check the location isn't wildly out of date or null. I've attempted to roll my own code to do this, but am having problems. (It's inside an IntentService where an upload happens, if that makes any difference. I've included all the code for info.) What's wrong with this code? @Override protected void onHandleIntent(Intent arg0) { testProviders(); doUpload(); } private boolean doUpload() { int j = 0; // check if we have accurate location data yet - wait up to 30 seconds while (j < 30) { if ((latString == "") || (lonString == "")) { Log.d(LOG_TAG, "latlng null"); Thread.sleep(1000); j++; } else { Log.d(LOG_TAG, "found lat " + latString + " and lon " + lonString); break; } //do the upload here anyway, with or without location data //[code removed for brevity] } public boolean testProviders() { Log.e(LOG_TAG, "testProviders"); String location_context = Context.LOCATION_SERVICE; locationmanager = (LocationManager) getSystemService(location_context); List<String> providers = locationmanager.getProviders(true); for (String provider : providers) { Log.e(LOG_TAG, "registering provider " + provider); listener = new LocationListener() { public void onLocationChanged(Location location) { // keep checking the location - until we have // what we need //if (!checkLoc(location)) { Log.e(LOG_TAG, "onLocationChanged"); locationDetermined = checkLoc(location); //} } public void onProviderDisabled(String provider) { } public void onProviderEnabled(String provider) { } public void onStatusChanged(String provider, int status, Bundle extras) { } }; locationmanager.requestLocationUpdates(provider, 0, 0, listener); } Log.e(LOG_TAG, "getting updates"); return true; } private boolean checkLoc(Location location) { float tempAccuracy = location.getAccuracy(); int locAccuracy = (int) tempAccuracy; Log.d(LOG_TAG, "locAccuracy = " + locAccuracy); if ((locAccuracy != 0) && (locAccuracy < LOCATION_ACCURACY)) { latitude = location.getLatitude(); longitude = location.getLongitude(); latString = latitude.toString(); lonString = longitude.toString(); return true; } return false; } public void removeListeners() { // Log.e(LOG_TAG, "removeListeners"); if ((locationmanager != null) && (listener != null)) { locationmanager.removeUpdates(listener); } locationmanager = null; // Log.d(LOG_TAG, "Removed " + listener.toString()); } @Override public void onDestroy() { super.onDestroy(); removeListeners(); } Unfortunately, this finds the network provider, but only ever outputs latlng null 30 times - it never seems to get a location at all. I never even get a log statement of locationChanged. It's funny, because from ddms I can see output like: NetworkLocationProvider: onCellLocationChanged [305,8580] NetworkLocationProvider: getNetworkLocation(): returning cache location with accuracy 75.0 seeming to suggest that the network provider does have some location info after all, I'm just not getting at it. Can anyone help? I think working example code would be a useful resource for the Android/StackOverflow community.

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  • Android 1.5 - 2.1 Search Activity affects Parent Lifecycle

    - by pacoder
    Behavior seems consistent in Android 1.5 to 2.1 Short version is this, it appears that when my (android search facility) search activity is fired from the android QSR due to either a suggestion or search, UNLESS my search activity in turn fires off a VISIBLE activity that is not the parent of the search, the search parents life cycle changes. It will NOT fire onDestroy until I launch a visible activity from it. If I do, onDestroy will fire fine. I need a way to get around this behavior... The long version: We have implemented a SearchSuggestion provider and a Search activity in our application. The one thing about it that is very odd is that if the SearchManager passes control to our custom Search activity, AND that activity does not create a visible Activity the Activity which parented the search does not destroy (onDestroy doesn't run) and it will not until we call a visible Activity from the parent activity. As long as our Search Activity fires off another Activity that gets focus the parent activity will fire onDestroy when I back out of it. The trick is that Activity must have a visual component. I tried to fake it out with a 'pass through' Activity so that my Search Activity could fire off another Intent and bail out but that didn't work either. I have tried setting our SearchActivity to launch singleTop and I also tried setting its noHistory attribute to true, tried setResult(RESULT_OK) in SearchACtivity prior to finish, bunch of other things, nothing is working. This is the chunk of code in our Search Activity onCreate. Couple of notes about it: If Intent is Action_Search (user typed in their own search and didn't pick a suggestion), we display a list of results as our Search Activity is a ListActivity. In this case when the item is picked, the Search Activity closes and our parent Activity does fire onDestroy() when we back out. If Intent is Action_View (user picked a suggestion) when type is "action" we fire off an Intent that creates a new visible Activity. In this case same thing, when we leave that new activity and return to the parent activity, the back key does cause the parent activity to fire onDestroy when leaving. If Intent is Action_View (user picked a suggestion) when type is "pitem" is where the problem lies. It works fine (the method call focuses an item on the parent activity), but when the back button is hit on the parent activity onDestroy is NOT called. IF after this executes I pick an option in the parent activity that fires off another activity and return to the parent then back out it will fire onDestroy() in the parent activity. Note that the "action" intent ends up running the exact same method call as "pitem", it just bring up a new visual Activity first. Also I can take out the method call from "pitem" and just finish() and the behavior is the same, the parent activity doesn't fire onDestroy() when backed out of. if (Intent.ACTION_SEARCH.equals(queryAction)) { this.setContentView(_layoutId); String searchKeywords = queryIntent.getStringExtra(SearchManager.QUERY); init(searchKeywords); } else if(Intent.ACTION_VIEW.equals(queryAction)){ Bundle bundle = queryIntent.getExtras(); String key = queryIntent.getDataString(); String userQuery = bundle.getString(SearchManager.USER_QUERY); String[] keyValues = key.split("-"); if(keyValues.length == 2) { String type = keyValues[0]; String value = keyValues[1]; if(type.equals("action")) { Intent intent = new Intent(this, EventInfoActivity.class); Long longKey = Long.parseLong(value); intent.putExtra("vo_id", longKey); startActivity(intent); finish(); } else if(type.equals("pitem")) { Integer id = Integer.parseInt(value); _application._servicesManager._mapHandlerSelector.selectInfoItem(id); finish(); } } } It just seems like something is being held onto and I can't figure out what it is, in all cases the Search Activity fires onDestroy() when finish() is called so it is definitely going away. If anyone has any suggestions I'd be most appreciative. Thanks, Sean Overby

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  • Android using ksoap calling PHP SOAP webservice fails: 'procedure 'CheckLogin' not found

    - by AmazingDreams
    I'm trying to call a PHP SOAP webservice. I know my webservice functions correctly because I use it in a WPF project succesfully. I'm also building an app in android, using the same webservice. The WSDL file can be found here: http://www.wegotcha.nl/servicehandler/service.wsdl This is my code in the android app: String SOAP_ACTION = "http://www.wegotcha.nl/servicehandler/CheckLogin"; String NAMESPACE = "http://www.wegotcha.nl/servicehandler"; String METHOD_NAME = "CheckLogin"; String URL = "http://www.wegotcha.nl/servicehandler/servicehandler.php"; String resultData = ""; SoapSerializationEnvelope soapEnv = new SoapSerializationEnvelope(SoapEnvelope.VER11); SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME); SoapObject UserCredentials = new SoapObject("Types", "UserCredentials6"); UserCredentials.addProperty("mail", params[0]); UserCredentials.addProperty("password", md5(params[1])); request.addSoapObject(UserCredentials); soapEnv.setOutputSoapObject(request); HttpTransportSE http = new HttpTransportSE(URL); http.setXmlVersionTag("<?xml version=\"1.0\" encoding=\"utf-8\"?>"); http.debug = true; try { http.call(SOAP_ACTION, soapEnv); } catch (IOException e) { e.printStackTrace(); } catch (XmlPullParserException e) { e.printStackTrace(); } SoapObject results = null; results = (SoapObject)soapEnv.bodyOut; if(results != null) resultData = results.getProperty(0).toString(); return resultData; Using fiddler I got the following: Android request: <?xml version="1.0" encoding="utf-8"?> <v:Envelope xmlns:i="http://www.w3.org/2001/XMLSchema-instance" xmlns:d="http://www.w3.org/2001/XMLSchema" xmlns:c="http://schemas.xmlsoap.org/soap/encoding/" xmlns:v="http://schemas.xmlsoap.org/soap/envelope/"><v:Header /> <v:Body> <n0:CheckLogin id="o0" c:root="1" xmlns:n0="http://www.wegotcha.nl/servicehandler"> <n1:UserCredentials6 i:type="n1:UserCredentials6" xmlns:n1="Types"> <mail i:type="d:string">myemail</mail> <password i:type="d:string">myhashedpass</password> </n1:UserCredentials6> </n0:CheckLogin> </v:Body> </v:Envelope> Getting the following response: Procedure 'CheckLogin' not present My request produced by my WPF app looks completely different: <s:Envelope xmlns:s="http://schemas.xmlsoap.org/soap/envelope/"> <s:Body xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <UserCredentials6 xmlns="Types"> <mail>mymail</mail> <password>mypassword</password> </UserCredentials6> </s:Body> </s:Envelope> After googling my ass off I was not able to solve this problem by myself. It may be possible there are some weird things in my Java code because I changed a lot since. I hope you guys will be able to help me, thanks. EDIT: My webservice is of document/literal encoding style, after doing some research I found I should be able to use SoepEnvelope Instead of SoapSerializationEnvelope Though when I replace this I get an error before the try cache block, causing my app to crash. Error: 11-04 16:23:26.786: E/AndroidRuntime(26447): Caused by: java.lang.ClassCastException: org.ksoap2.serialization.SoapObject cannot be cast to org.kxml2.kdom.Node Which is caused by these lines: request.addSoapObject(UserCredentials); soapEnv.setOutputSoapObject(request); This may be a solution though, how do I go about this? I found nothing about using a SoapEnvelope instead of a SoapSerializationEnvelope except for this awesome tutorial: http://ksoap.objectweb.org/project/mailingLists/ksoap/msg00849.html

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  • Android: HttpURLConnection not working properly

    - by giorgiline
    I'm trying to get the cookies from a website after sending user credentials through a POST Request an it seems that it doesn't work in android this way. ¿Am I doing something bad?. Please help. I've searched here in different posts but there's no useful answer. It's curious that this run in a desktop Java implementation it works perfect but it crashes in Android platform. And it is exactly the same code, specifically when calling HttpURLConnection.getHeaderFields(), it also happens with other member methods. It's a simple code and I don't know why the hell isn't working. DESKTOP CODE: This goes just in the main() HttpURLConnection connection = null; OutputStream out = null; try { URL url = new URL("http://www.XXXXXXXX.php"); String charset = "UTF-8"; String postback = "1"; String user = "XXXXXXXXX"; String password = "XXXXXXXX"; String rememberme = "on"; String query = String.format("postback=%s&user=%s&password=%s&rememberme=%s" , URLEncoder.encode(postback, charset) , URLEncoder.encode(user,charset) , URLEncoder.encode(password, charset) , URLEncoder.encode(rememberme, charset)); connection = (HttpURLConnection)url.openConnection(); connection.setRequestMethod("POST"); connection.setRequestProperty("Accept-Charset", charset); connection.setDoOutput(true); connection.setFixedLengthStreamingMode(query.length()); out = connection.getOutputStream (); out.write(query.getBytes(charset)); if (connection.getHeaderFields() == null){ System.out.println("Header null"); }else{ for (String cookie: connection.getHeaderFields().get("Set-Cookie")){ System.out.println(cookie.split(";", 2)[0]); } } } catch (IOException e){ e.printStackTrace(); } finally { try { out.close();} catch (IOException e) { e.printStackTrace();} connection.disconnect(); } So the output is: login_key=20ad8177db4eca3f057c14a64bafc2c9 FASID=cabf20cc471fcacacdc7dc7e83768880 track=30c8183e4ebbe8b3a57b583166326c77 client-data=%7B%22ism%22%3Afalse%2C%22showm%22%3Afalse%2C%22ts%22%3A1349189669%7D ANDROID CODE: This goes inside doInBackground AsyncTask body HttpURLConnection connection = null; OutputStream out = null; try { URL url = new URL("http://www.XXXXXXXXXXXXXX.php"); String charset = "UTF-8"; String postback = "1"; String user = "XXXXXXXXX"; String password = "XXXXXXXX"; String rememberme = "on"; String query = String.format("postback=%s&user=%s&password=%s&rememberme=%s" , URLEncoder.encode(postback, charset) , URLEncoder.encode(user,charset) , URLEncoder.encode(password, charset) , URLEncoder.encode(rememberme, charset)); connection = (HttpURLConnection)url.openConnection(); connection.setRequestMethod("POST"); connection.setRequestProperty("Accept-Charset", charset); connection.setDoOutput(true); connection.setFixedLengthStreamingMode(query.length()); out = connection.getOutputStream (); out.write(query.getBytes(charset)); if (connection.getHeaderFields() == null){ Log.v(TAG, "Header null"); }else{ for (String cookie: connection.getHeaderFields().get("Set-Cookie")){ Log.v(TAG, cookie.split(";", 2)[0]); } } } catch (IOException e){ e.printStackTrace(); } finally { try { out.close();} catch (IOException e) { e.printStackTrace();} connection.disconnect(); } And here there is no output, it seems that connection.getHeaderFields() doesn't return result. It takes al least 30 seconds to show the Log: 10-02 16:56:25.918: V/class com.giorgi.myproject.activities.HomeActivity(2596): Header null

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  • JPA @Version behaviour

    - by Albert Kam
    Hello, im using JPA2 with Hibernate 3.6.x I have made a simple testing on the @Version. Let's say we have 2 entities, Entity Team has a List of Player Entities, bidirectional relationship, lazy fetchtype, cascade-type All Both entities have @Version And here are the scenarios : Whenever a modification is made to one of the team/player entity, the team/player's version will be increased when flushed/commited (version on the modified record is increased). Adding a new player entity to team's collection using persist, the entity the team's version will be assigned after persist (adding a new entity, that new entity will got it's version). Whenever an addition/modification/removal is made to one of the player entity, the team's version will be increased when flushed/commited. (add/modify/remove child record, parent's version got increased also) I can understand the number 1 and 2, but the number 3, i dont understand, why the team's version got increased ? And that makes me think of other questions : What if i got Parent <- child <- granchildren relation ship. Will an addition or modification on the grandchildren increase the version of child and parent ? In scenario number 2, how can i get the version on the team before it's commited, like perhaps by using flush ? Is it a recommended way to get the parent's version after we do something to the child[s] ? Here's a code sample from my experiment, proving that when ReceivingGoodDetail is the owning side, and the version got increased in the ReceivingGood after flushing. Sorry that this use other entities, but ReceivingGood is like the Team, ReceivingGoodDetail is like the Player. 1 ReceivingGood/Team, many ReceivingGoodDetail/Player. /* Hibernate: select receivingg0_.id as id9_14_, receivingg0_.creationDate as creation2_9_14_, .. too long Hibernate: select product0_.id as id0_4_, product0_.creationDate as creation2_0_4_, .. too long before persisting the new detail, version of header is : 14 persisting the detail 1c9f81e1-8a49-4189-83f5-4484508e71a7 printing the size of the header : Hibernate: select details0_.receivinggood_id as receivi13_9_8_, details0_.id as id8_, details0_.id as id10_7_, .. too long 7 after persisting the new detail, version of header is : 14 Hibernate: insert into ReceivingGoodDetail (creationDate, modificationDate, usercreate_id, usermodify_id, version, buyQuantity, buyUnit, internalQuantity, internalUnit, product_id, receivinggood_id, supplierLotNumber, id) values (?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?) Hibernate: update ReceivingGood set creationDate=?, modificationDate=?, usercreate_id=?, usermodify_id=?, version=?, purchaseorder_id=?, supplier_id=?, transactionDate=?, transactionNumber=?, transactionType=?, transactionYearMonth=?, warehouse_id=? where id=? and version=? after flushing, version of header is now : 15 */ public void addDetailWithoutTouchingCollection() { String headerId = "3b373f6a-9cd1-4c9c-9d46-240de37f6b0f"; ReceivingGood receivingGood = em.find(ReceivingGood.class, headerId); // create a new detail ReceivingGoodDetail receivingGoodDetailCumi = new ReceivingGoodDetail(); receivingGoodDetailCumi.setBuyUnit("Drum"); receivingGoodDetailCumi.setBuyQuantity(1L); receivingGoodDetailCumi.setInternalUnit("Liter"); receivingGoodDetailCumi.setInternalQuantity(10L); receivingGoodDetailCumi.setProduct(getProduct("b3e83b2c-d27b-4572-bf8d-ac32f6de5eaa")); receivingGoodDetailCumi.setSupplierLotNumber("Supplier Lot 1"); decorateEntity(receivingGoodDetailCumi, getUser("3978fee3-9690-4377-84bd-9fb05928a6fc")); receivingGoodDetailCumi.setReceivingGood(receivingGood); System.out.println("before persisting the new detail, version of header is : " + receivingGood.getVersion()); // persist it System.out.println("persisting the detail " + receivingGoodDetailCumi.getId()); em.persist(receivingGoodDetailCumi); System.out.println("printing the size of the header : "); System.out.println(receivingGood.getDetails().size()); System.out.println("after persisting the new detail, version of header is : " + receivingGood.getVersion()); em.flush(); System.out.println("after flushing, version of header is now : " + receivingGood.getVersion()); }

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  • How to link paid app user account to the system ?

    - by user164589
    Hi guys, I have an issue related publishing the paid app to android market. (My application is internet connection based app.) If I've put the app to the android market, can user who bought the app pass to anyone ? How is its security (I mean safe of .apk file) ? Also, what is payment tool of android market ? My main point is choosing the best way to link paid user to our system. Actually I don't know how to link paid user account to my system(by email address or device unique id ?... what is better way ?). Can you suggest me on this part ? I really appreciate for help. Thanks in advance.

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  • How can one setup a version control system on a local network, without a server?

    - by Andrew
    Edit: Ok so I learned that I guess I need an distributed source control, however are there any UI based ones, and do they allow you to merge with other users on the network? This is kind of a two part question, so here it goes. I want to start developing a web application at home (with multiple developers). However, I don't have a dedicated server nor want to pay for on. So first, I don't know which version control system to use for this case, as at work we mostly have TFS setup, so I am not to familiar with whats out there. What are the best free CVS/SVN tools out there? Second, is it possible to somehow setup the CVS/SVN where there is no dedicated server and both clients store up to one week of the source code from the last check-in? Also, it would be helpful if it could integrate with visual studio, again this isn't that important at all. Problem: There are Five users, one is a Server. Server Connected: All Ok Server Disconnected: No one can share. What I am looking for: No Server: Users still have versioning based on version id of last check-in. Users must check all version on network to make sure they aren't outdated based on their last version id. If not check-in, otherwise merge/get latest. If they are update checkin, and set current version id +1.

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  • What can I access in Androids Native libraries? And How?

    - by Donal Rafferty
    I am completely new to the NDK. I have done a couple of the tutorials including the hello from jni one and another one that calculates the sum of two numbers. They involved using cygwin and the ndk to create the library so file and I have a bit of a grasp on how to insert my own libraries into the libraries layer of Android. I have now been asked to access the native libraries on Android and see what I can use them for. My question is can I do this? The STABLE-APIS.txt document is a bit vague and mentions the following as Stable C++ API's in Android 1.5 cstddef new utility stl_pair.h Does that mean I can access them? If so then how do I go about it? I dont think that following the tutorials I have already done would be any help? Any pointers on how to do this or links to tutorials etc.. would be greatly appreciated

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