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Search found 4637 results on 186 pages for 'john bracciano'.

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  • simple question about oracle indexes

    - by john
    If I have an oracle query like below: SELECT * FROM table_a where A = "1", B = "2", C = "3" for this query to pickup one of the indexes of table_a...does the index need to be on all 3 of these columns? What I am asking is: What if Index is on A, B, C, D? What if Index is on B, C? Will the index only be picked when it is on A, B, C?

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  • What's the best way to stop multiple instances of a Windows app being launched?

    - by John
    Many Windows apps (like Skype or MSN for instance) don't let you start multiple instances, rather trying to run it a 2nd time just leaves the existing version running. Is this typically done in some simple way - the start-menu shortcut is a 'wrapper' app around the main app - or is there some registry magic you can do to delegate the problem to Windows itself? Specifically dealing with Win32 here (unmanaged C++) but happy to hear more general solutions as long as they are workable on Windows XP or alter.

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  • Configuring jdbc-pool (tomcat 7)

    - by john
    i'm having some problems with tomcat 7 for configuring jdbc-pool : i`ve tried to follow this example: http://www.tomcatexpert.com/blog/2010/04/01/configuring-jdbc-pool-high-concurrency so i have: conf/server.xml <GlobalNamingResources> <Resource type="javax.sql.DataSource" name="jdbc/DB" factory="org.apache.tomcat.jdbc.pool.DataSourceFactory" driverClassName="com.mysql.jdbc.Driver" url="jdbc:mysql://localhost:3306/mydb" username="user" password="password" /> </GlobalNamingResources> conf/context.xml <Context> <ResourceLink type="javax.sql.DataSource" name="jdbc/LocalDB" global="jdbc/DB" /> <Context> and when i try to do this: Context initContext = new InitialContext(); Context envContext = (Context)initContext.lookup("java:/comp/env"); DataSource datasource = (DataSource)envContext.lookup("jdbc/LocalDB"); Connection con = datasource.getConnection(); i keep getting this error: javax.naming.NameNotFoundException: Name jdbc is not bound in this Context at org.apache.naming.NamingContext.lookup(NamingContext.java:803) at org.apache.naming.NamingContext.lookup(NamingContext.java:159) pls help tnx

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  • Very basic database theory.

    - by John R
    I have a set of tables to show the relationship between organziations and supporters below. Although I have done some basic mySQL querries, I know very little about database 'design'. I plan to querry the database for: -a list of contributors to a specific organization... or, -a list of organizations that a specific suporter supports. The database tables for organiations and contributors may have other columns in the future and recieve a lesser amount of querries based on that information. A | X A | Y A | Z B | X B | Y C | X C | Z How should the tables be set up? I assume that there should be a third table, but there is still redundent information in the third table. Is there a better way of setting up the tables? +----+-------+ +-------------+----------+ +----+-------+ | id | org | | org | contr | | id | contr.| +----+-------+ +-------------+----------+ +----+-------+ | 1 | A | | 1 | 1 | | 1 | X | | 2 | B | | 1 | 2 | | 2 | Y | | 3 | C | | 1 | 3 | | 3 | Z | +----+-------+ | 2 | 1 | +----+-------+ | 2 | 2 | | 3 | 1 | | 3 | 3 | +-------------+----------+

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  • PHP String to Float

    - by John
    I am not familiar with PHP at all and had a quick question. I have 2 variables @pricePerUnit and @invoicedUnits. Here's the code that is setting these to values: $InvoicedUnits = ((string) $InvoiceLineItem->InvoicedUnits); $pricePerUnit = ((string) $InvoiceLineItem->PricePerUnit); If I output this, I get the correct values. Lets say 5000 invoiced units and 1.00 for price. Now, I need to show the total amount spent. When I multiply these two together it doesn't work (as expected, these are strings). But I have no clue how to parse/cast/convert variables in PHP. What should I do?

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  • code to check spellings

    - by john
    hi guys, can anyone help me how to write code for checking spellings in android? or can anyone provide me the sites which will be useful to me. thanks in advance any help will be appreciated.

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  • Mysql ADDDATE() or DATE_ADD() with table columns?

    - by John
    How do I do something like the following SELECT ADDDATE(t_invoice.last_bill_date, INTERVAL t_invoice.interval t_invoice.interval_unit) FROM t_invoice ...where the column t_invoice.last_bill_date is a date, t_invoice.interval is an integer and t_invoice.interval_unit is a string. Basically, I want to determine a person's next bill date based on his desired billing frequency. Is there a better way to achieve this?

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  • simplify in declaring variables value in php

    - by Robert John Concepcion
    $jan5 = 0; $feb5 = 0; $mar5 = 0; $apr5 = 0; $may5 = 0; $jun5 = 0; $jul5 = 0; $aug5 = 0; $sep5 = 0; $oct5 = 0; $nov5 = 0; $dec5 = 0; $jan4 = 0; $feb4 = 0; $mar4 = 0; $apr4 = 0; $may4 = 0; $jun4 = 0; $jul4 = 0; $aug4 = 0; $sep4 = 0; $oct4 = 0; $nov4 = 0; $dec4 = 0; $jan3 = 0; $feb3 = 0; $mar3 = 0; $apr3 = 0; $may3 = 0; $jun3 = 0; $jul3 = 0; $aug3 = 0; $sep3 = 0; $oct3 = 0; $nov3 = 0; $dec3 = 0; this is the most time consuming code when i try to make for example i want the default value of $jan5 is equal to zero.. can some one teach me how to make this short? thank you so much for reading $date = 'smi_initialdate'; $level = 'smi_level'; $year = '2012'; $result1 = mysql_query("SELECT *, DATE_FORMAT( $date, '%m' ) As monthz FROM eis_mngt_sales_iti WHERE year($date) = '$year' ORDER BY $date"); while($row=mysql_fetch_array($result1)) { $count++; if($row['smi_level']=='5star') { if($row['monthz']==1) { $jan++; }elseif($row['monthz']==2) { $feb++; }elseif($row['monthz']==3) { $mar++; }elseif($row['monthz']==4) { $apr++; }elseif($row['monthz']==5) { $may++; }elseif($row['monthz']==6) { $jun++; }elseif($row['monthz']==7) { $jul++; }elseif($row['monthz']==8) { $aug++; }elseif($row['monthz']==9) { $sep++; }elseif($row['monthz']==10) { $oct++; }elseif($row['monthz']==11) { $nov++; }elseif($row['monthz']==12) { $dec++; } } } i decide to put this $jan5 = 0;$feb5 = 0;$mar5 = 0;$apr5 = 0;$may5 = 0;$jun5 = 0;$jul5 = 0; so that if the data did not pass to this condition if($row['smi_level']=='5star') they have the return value of zero(0). so that my output can adapt in this code [<?php echo$jan5.",".$feb5.",".$mar5.",".$apr5.",".$may5.",".$jun5.",".$jul5.",".$aug5.",".$sep5.",".$oct5.",".$nov5.",".$dec5; ?] if a dont use the above code the $jan5 = 0;$feb5 = 0;$mar5 = 0;$apr5 = 0;$may5 = 0;$jun5 = 0;$jul5 = 0;................ when i echo or print it i look like this 1,2,5,11,12 but with the use of that(the first sample code above) the output will be 1,0,0,0,0,0,0,1,2,5,11,12. thank, sorry if this became confusing, sorry about my grammar

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  • Feedback on implementation of function which compares integer signs in Python.

    - by John Magistr
    Hi all. I've made a small function which, given a tuple, compares if all elements in this tuple is of the same sign. E.g., tuple = [-1, -4, -6, -8] is good, while [-1, -4, 12, -8] is bad. I am not sure I've made the smartest implementation, so I know this is the place to ask. def check_consistent_categories(queryset): try: first_item = queryset[0].amount if first_item < 0: for item in queryset: if item > 0: return False return True else: for item in queryset: if item < 0: return False return True except: return False

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  • MySQL join not returning rows

    - by John
    I'm attempting to create an anti-bruteforcer for the login page on a website. Unfortunately, my query is not working as expected. I would like to test how many times an IP address has attempted to login, and also return the ID of the user for my next step in the login process. However, I'm having a problem with the query... for one thing, this would only return rows if it was the same user as they had been trying to login to before. I need it to be any user. Secondly, regardless of whether I use LEFT JOIN, RIGHT JOIN, INNER JOIN or JOIN, it will not return the user's ID unless there is a row for the user in login_attempts. SELECT COUNT(`la`.`id`), `u`.`id` FROM `users` AS `u` LEFT JOIN `login_attempts` AS `la` ON `u`.`id` = `la`.`user_id` WHERE `u`.`username` = 'admin' AND `la`.`ip_address` = '127.0.0.1' AND `la`.`timestamp` >= '1'

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  • Any easy way to delete a user (having many to many relation with role) in acegi, grails?

    - by john
    Hi, In default acegi setting, person and authority have many to many relations. Thus, in addtion to people and authorities, there is a table authotiries-people. To delete a person (a user) I have to delete the related record in authotiries-people first....then come back to delete the record... the problem is: other people are still using this authority (ROLE) could some one enlighten me how to delete the user without deleting the authority? thanks.

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  • python check value not in unicode list

    - by John
    Hi, I have a list and a value and want to check if the value is not in the list. list = [u'first record', u'second record'] value = 'first record' if value not in list: do something however this is not working and I think it has something to do with the list values having a u at the start, how can I fix this? And before someone suggests the list is returned from Django queryset so I can't just take the u out of the code :) Thanks

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  • Java:How to align Jpanels

    - by John
    I have this code but it doesn't work: jPanel1.add(jLabel1); jPanel2.add(jButton1); jPanel2.add(jButton2); jPanel3.add(jPanel1,jPanel1.TOP_ALIGNMENT); jPanel3.add(jPanel2,jPanel2.BOTTOM_ALIGNMENT); setContentPane(jPanel3); pack(); Please tell me why!

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  • form.has_errors tag not working

    - by John
    Hello, Im using Django 1.2.3. I have login functionality in my site using django.contrib.auth.views.login. The user is able to login after entering correct username and password. But, form.has_errors is not working i.e. if the login credentials entered are incorrect i dont see the error message. My login.html in templates/registration is as follows : <html> <head> <title>Login</title> </head> <body> <h1>User Login</h1> {% if form.has_errors %} <p>Your username and password didn't match. Please try again.</p> {% endif %} <form method="post" action="."> {% csrf_token %} <p><label for="id_username">Username:</label> {{ form.username }}</p> <p><label for="id_password">Password:</label> {{ form.password }}</p> <input type="hidden" name="next" value="/" /> <input type="submit" value="login" /> </form> </body> </html> Any way to fix this problem? Please Help Thank You.

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  • jQuery Nested Droppables

    - by John
    I have a nested set of jQuery droppables...one outer droppable that encompasses most of the page and an a set of nested inner droppables on the page. The functionality I want is: If a draggable is dropped outside of any of the inner droppables it should be accepted by the outer droppable. If a draggable is dropped onto any of the inner droppables it should NOT be accepted by the outer droppable, regardless of whether the inner droppable accepts the draggable. So that would be easy if I could guarantee 1+ inner droppables would accept the draggable, because the greedy attribute would make sure it would only get triggered once. Unfortunately the majority of the time the inner droppable will also reject the draggable, meaning the greedy option doesn't really help. Summary: The basic functionality is a set of valid/invalid inner droppables to accept the draggable, but when you toss the draggable outside any of the draggables it gets destroyed by the outer droppable. What's the best way of doing this?

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  • django: how to use many-to-many relationships in values()?

    - by john
    i need to group results by a field that requires a few joins from the original model: // response_filter_args is created dynamically responses = Response.objects.filter(**response_filter_args) \ .values('customer__tags__tag') \ # django doesn't like this .annotate(average_score=Avg('rating__score')) Response - customer - tags (many-to-many field pointing to Tag) - tag (the tag as a string) Models are: class Response(models.Model): customer = models.ForeignKey(Customer) ... class Customer(models.Model): tags = models.ManyToManyField(Tag) ... class Tag(models.Model): tag = models.CharField(max_length=255) ... i'm trying to calculate average ratings. to make it work i need to tell django to group by 'tag', but it refuses to. it gives an error: Invalid field name: 'customer__tags__tag' anyone know how i can get it to group by tag? i've tried all the combinations of underscores in customer_tags_tag that i can think of, but nothing works.

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  • Is it possible to use CSS round-corners and still pass validation?

    - by John
    IIRC the situation is that IE simply doesn't support rounded corners, but some other browsers need browser-specific extensions... either FF or web-kit, I don't recall. I'm happy to use it in some cases and let IE fall-back to square corners, but does using browser-extension CSS break validation... I quite like having my site validate AND work on IE6.

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