Search Results

Search found 17941 results on 718 pages for 'title bar'.

Page 137/718 | < Previous Page | 133 134 135 136 137 138 139 140 141 142 143 144  | Next Page >

  • Add a sub-view to a DetailView UIView in iPad

    - by Elisabeth
    I'm creating a split view controller app, the detail view has a segmented control in a navigation bar at the top. Clicking on a segment will add a new view to the detail view with the appropriate information on it (covering up the DetailViewController's default UIView). I've created two new UIViews, corresponding to each segment, and I'm trying to add them to the view like this (in DetailViewController.m): if (exerciseSegmentControl.selectedSegmentIndex == UISegmentedControlNoSegment) { NSLog(@"No segment selected"); } UIView *viewToShow; if (selectedView == 0 && exerciseSegmentControl.selectedSegmentIndex == 1) { viewToShow = exerciseSolutionView; } else { viewToShow = exerciseView; } [self.view addSubview:viewToShow]; I see the view appear, but it's in the wrong place, it is placed at the very top of the window, instead of below the navigation bar. In IB, I've created instances of the views, and I've used the Attributes inspector to specify "Navigation Bar" for top bar, which sets the height of the view correctly. But the view is clearly being added too far up in the window - I see the view below it (the DetailViewController's UIView) peaking out at the bottom (I changed the background color so I know which view I'm seeing). Any tips on how to get the subview I'm adding to get placed correctly in the window? Thanks!

    Read the article

  • python sqlite3 won't execute a join, but sqlite3 alone will

    - by Francis Davey
    Using the sqlite3 standard library in python 2.6.4, the following query works fine on sqlite3 command line: select segmentid, node_t, start, number,title from ((segments inner join position using (segmentid)) left outer join titles using (legid, segmentid)) left outer join numbers using (start, legid, version); But If I execute it via the sqlite3 library in python I get an error: >>> conn=sqlite3.connect('data/test.db') >>> conn.execute('''select segmentid, node_t, start, number,title from ((segments inner join position using (segmentid)) left outer join titles using (legid, segmentid)) left outer join numbers using (start, legid, version)''') Traceback (most recent call last): File "<stdin>", line 1, in <module> sqlite3.OperationalError: cannot join using column start - column not present in both tables The (computed) table on the left hand side of the join appears to have the relevant column because if I check it by itself I get: >>> conn.execute('''select * from ((segments inner join position using (segmentid)) left outer join titles using (legid, segmentid)) limit 20''').description (('segmentid', None, None, None, None, None, None), ('html', None, None, None, None, None, None), ('node_t', None, None, None, None, None, None), ('legid', None, None, None, None, None, None), ('version', None, None, None, None, None, None), ('start', None, None, None, None, None, None), ('title', None, None, None, None, None, None)) My schema is: CREATE TABLE leg (legid integer primary key, t char(16), year char(16), no char(16)); CREATE TABLE numbers ( number char(16), legid integer, version integer, start integer, end integer, prev integer, prev_number char(16), next integer, next_number char(16), primary key (number, legid, version)); CREATE TABLE position ( segmentid integer, legid integer, version integer, start integer, primary key (segmentid, legid, version)); CREATE TABLE 'segments' (segmentid integer primary key, html text, node_t integer); CREATE TABLE titles (legid integer, segmentid integer, title text, primary key (legid, segmentid)); CREATE TABLE versions (legid integer, version integer, primary key (legid, version)); CREATE INDEX idx_numbers_start on numbers (legid, version, start); I am baffled as to what I am doing wrong. I have tried quitting/restarting both the python and sqlite command lines and can't see what I'm doing wrong. It may be completely obvious.

    Read the article

  • Any Other Ideas for prototyping..

    - by davehamptonusa
    I've used Douglass Crockford's Object.beget, but augmented it slightly to: Object.spawn = function (o, spec) { var F = function () {}, that = {}, node = {}; F.prototype = o; that = new F(); for (node in spec) { if (spec.hasOwnProperty(node)) { that[node] = spec[node]; } } return that; }; This way you can "beget" and augment in one fell swoop. var fop = Object.spawn(bar, { a: 'fast', b: 'prototyping' }); In English that means, "Make me a new object called 'fop' with 'bar' as its prototype, but change or add the members 'a' and 'b'. You can even nest it the spec to prototype deeper elements, should you choose. var fop = Object.spawn(bar, { a: 'fast', b: Object.spawn(quux,{ farple: 'deep' }), c: 'prototyping' }); This can help avoid hopping into an object's prototype unintentionally in a long object name like: foo.bar.quux.peanut = 'farple'; If quux is part of the prototype and not foo's own object, your change to 'peanut' will actually change the protoype, affecting all objects prototyped by foo's prototype object. But I digress... My question is this. Because your spec can itself be another object and that object could itself have properties from it's prototype in your new object - and you may want those properties...(at least you should be aware of them before you decided to use it as a spec)... I want to be able to grab all of the elements from all of the spec's prototype chain, except for the prototype object itself... This would flatten them into the new object. Should I use: Object.spawn = function (o, spec) { var F = function () {}, that = {}, node = {}; F.prototype = o; that = new F(); for (node in spec) { that[node] = spec[node]; } that.prototype = o; return that; }; I would love thoughts and suggestions...

    Read the article

  • Cannot create list in SharePoint 2010 using Client Object Model

    - by Boris
    I am trying to utilize SharePoint 2010 Client Object Model to create a List based on a custom template. Here's my code: public void MakeList(string title, string listTemplateGUID, int localeIdentifier) { string message; string listUrl; List newList; Guid template; ListCreationInformation listInfo; Microsoft.SharePoint.Client.ListCollection lists; try { listUrl = title.Replace(spaceChar, string.Empty); template = GetListTemplate((uint)localeIdentifier, listTemplateGUID); listInfo = new ListCreationInformation(); listInfo.Url = listUrl; listInfo.Title = title; listInfo.Description = string.Empty; listInfo.TemplateFeatureId = template; listInfo.QuickLaunchOption = QuickLaunchOptions.On; clientContext.Load(site); clientContext.ExecuteQuery(); lists = site.Lists; clientContext.Load(lists); clientContext.ExecuteQuery(); newList = lists.Add(listInfo); clientContext.ExecuteQuery(); } catch (ServerException ex) { //... } } Now, this particular part, newList = lists.Add(listInfo); clientContext.ExecuteQuery(); the one that is supposed to create the actual list, throws an exception: Message: Cannot complete this action. Please try again. ServerErrorCode: 2130239231 ServerErrorTypeName: Microsoft.SharePoint.SPException Could anyone please help me realize what am I doing wrong? Thanks.

    Read the article

  • jstree will not fire onchange event

    - by vasion
    i have been really stuck on this. this is the code: js: var treeoptions={"data":{"type":"json","opts":{"url":"\/surveytags\/treejson"}}}; $('#treecontainer').tree(treeoptions); $("#treecontainer").tree({ callback : { ondblclk : function (node, tree) { alert(node.id); }, onmove : function (node,ref,type){ data= new Object(); data.node= new Object(); data.node.id = node.id; data.ref=new Object(); data.ref.id = ref.id; data.type = type; moveitem(data); }, onchange : function (){ alert('focused'); }, oncreate : function(node){ alert('create'); alert(node.data); } } }); this is the json: {"attributes":{"id":"1"},"data":{"title":"root"},"children":[{"attributes":{"id":"2"},"data":{"title":"blah"},"children":[{"attributes":{"id":"3"},"data":{"title":"tworows down"}},{"attributes":{"id":"4"},"data":{"title":"tooope"}}]}]} it loads. other events fire. BUT onchange will not...

    Read the article

  • Django one form for two models

    - by martinthenext
    Hello! I have a ForeignKey relationship between TextPage and Paragraph and my goal is to make front-end TextPage creating/editing form as if it was in ModelAdmin with 'inlines': several field for the TextPage and then a couple of Paragraph instances stacked inline. The problem is that i have no idea about how to validate and save that: @login_required def textpage_add(request): profile = request.user.profile_set.all()[0] if not (profile.is_admin() or profile.is_editor()): raise Http404 PageFormSet = inlineformset_factory(TextPage, Paragraph, extra=5) if request.POST: try: textpageform = TextPageForm(request.POST) # formset = PageFormSet(request.POST) except forms.ValidationError as error: textpageform = TextPageForm() formset = PageFormSet() return render_to_response('textpages/manage.html', { 'formset' : formset, 'textpageform' : textpageform, 'error' : str(error), }, context_instance=RequestContext(request)) # Saving data if textpageform.is_valid() and formset.is_valid(): textpageform.save() formset.save() return HttpResponseRedirect(reverse(consults)) else: textpageform = TextPageForm() formset = PageFormSet() return render_to_response('textpages/manage.html', { 'formset' : formset, 'textpageform' : textpageform, }, context_instance=RequestContext(request)) I know I't a kind of code-monkey style to post code that you don't even expect to work but I wanted to show what I'm trying to accomplish. Here is the relevant part of models.py: class TextPage(models.Model): title = models.CharField(max_length=100) page_sub_category = models.ForeignKey(PageSubCategory, blank=True, null=True) def __unicode__(self): return self.title class Paragraph(models.Model): article = models.ForeignKey(TextPage) title = models.CharField(max_length=100, blank=True, null=True) text = models.TextField(blank=True, null=True) def __unicode__(self): return self.title Any help would be appreciated. Thanks!

    Read the article

  • Mvc2 validation summary and required metadata

    - by Arnis L.
    source code... Thing is, if i specify required metadata using fluent modelmetadata provider like this= public class Foo { public string Bar { get; set; } } public class FooModelMetadataConfiguration : ModelMetadataConfiguration<Foo> { public FooModelMetadataConfiguration() { Configure(x => x.Bar) .Required("lapsa") ; } } And write this into my view = <% Html.BeginForm(); %> <%= Html.ValidationSummary() %> <%= Html.TextBoxFor(x=>x.Bar) %> <% Html.EndForm(); %> And add this to home controller = [HttpPost] public ActionResult Index(Foo foo) { ViewData["Message"] = "Welcome to ASP.NET MVC!"; return View(foo); } It will output this html = <div class="validation-summary-errors"> <ul> <li>lapsa</li> <li>The Bar field is required.</li> </ul> </div> I can't understand why 2nd error is rendered and how to omit it. Author of System.Web.Mvc.Extensibility framework replied with = I think this is a known issue of asp.net mvc, i could not remember the exact location where I have read it, I suggest you post the issue in asp.net mvc issue tracker over codeplex. But before i post anything on issue tracker - i would like to understand first what exactly is wrong. Any help with that?

    Read the article

  • Two Linked CSS Files Not working

    - by Oscar Godson
    <head> <title>Water Bureau</title> <link rel="shortcut icon" href="/favicon.ico" /> <link rel="stylesheet" href="/css/main.css" type="text/css" media="screen" title="Main CSS"> <link rel="stylesheet" href="custom.css" type="text/css" media="screen" title="Custom Styles"> <script language="JavaScript" src="/shared/js/createWin.js" type="text/javascript"></script> </head> Thats the code, but the "custom.css" isn't working. It doesn't work at all. If we add a @import into main.css OR into the header instead of a it works fine though. Any ideas? We also got rid of the media="screens" on both as well. The CSS inside of it is working fine, it's just when we stack those two, the first one parsed is the only one read by the browser. So if we swap main below custom, custom than works but NONE of main works. and custom just has snippet of CSS, and doesn't override all the CSS in main, just 1 element. I can't figure it out! We have other ed stylesheets in the head (which we took out for trying to fix this) and they worked fine...

    Read the article

  • Boost Solr results based on the field that contained the hit

    - by TomFor
    Hi, I was browsing the web looking for a indexing and search framework and stumbled upon Solr. A functionality that we abolutely need is to boost results based on what field contained the hit. A small example: Consider a record like this: <movie> <title>The Dark Knight</title> <alternative_title>Batman Begins 2</alternative_title> <year>2008</year> <director>Christopher Nolan</director> <plot>Batman, Gordon and Harvey Dent are forced to deal with the chaos unleashed by an anarchist mastermind known only as the Joker, as it drives each of them to their limits.</plot> </movie> I want to combine for example the title, alternative_title and plot fields into one search field, which isn't too difficult after looking at the Solr/Lucene documentation and tutorials. However I also want that movies that have a hit in title have a higher score than hits on alternative_title and those in their turn should score higher than hits in the plot field. Is there any way to indicate this kond of scoring in the xml or do we need to develop some custom scoring algorythm? Please also note that the example I've givnen is fictional end the real data will probably contain 100+ fields. Thanks in advance, Tom

    Read the article

  • Asp.net mvc 2 .net 4.0 error when View model type is Tuple with more than 4 items

    - by Bojan
    When I create strongly typed View in Asp.net mvc 2, .net 4.0 with model type Tuple I get error when Tuple have more than 4 items example 1: type of view is Tuple<string, string, string, string> (4-tuple) and everything works fine view: <%@ Page Title="" Language="C#" MasterPageFile="~/Views/Shared/WebUI.Master" Inherits="System.Web.Mvc.ViewPage<Tuple<string, string, string, string>>" %> controller: var tuple = Tuple.Create("a", "b", "c", "d"); return View(tuple); example 2: type of view is Tuple<string, string, string, string, string> (5-tuple) and I have this error: Compiler Error Message: CS1003: Syntax error, '>' expected view: <%@ Page Title="" Language="C#" MasterPageFile="~/Views/Shared/WebUI.Master" Inherits="System.Web.Mvc.ViewPage<Tuple<string, string, string, string, string>>" %> controller: var tuple = Tuple.Create("a", "b", "c", "d", "e"); return View(tuple); example 3 if my view model is of type dynamic I can use both 4-tuple and 5-tuple and there is no error on page view: <%@ Page Title="" Language="C#" MasterPageFile="~/Views/Shared/WebUI.Master" Inherits="System.Web.Mvc.ViewPage<dynamic>" %> controller: dynamic model = new ExpandoObject(); model.tuple = Tuple.Create("a", "b", "c", "d"); return View(model); or view: <%@ Page Title="" Language="C#" MasterPageFile="~/Views/Shared/WebUI.Master" Inherits="System.Web.Mvc.ViewPage<dynamic>" %> controller: dynamic model = new ExpandoObject(); model.tuple = Tuple.Create("a", "b", "c", "d", "e"); return View(model); Even if I have something like Tuple<string, Tuple<string, string, string>, string> 3-tuple and one of the items is also a tuple and sum of items in all tuples is more than 4 I get the same error, Tuple<string, Tuple<string, string>, string> works fine

    Read the article

  • ASP.Net RadioButton loses ViewState

    - by Carl
    I'm having trouble with a simple radio set of two radio buttons (I don't want to use a RadioButtonList [RBL] because RBL doesn't allow child controls, and in my case, if you select one option, I want to enable a textbox next to the button; yes you could hack this with jQuery to move the textbox, but that's dirty!). I would check one, submit the form (either explicitly or through AutoPostBack), and the CheckedChanged event would never fire. When the page was reloaded, both buttons would be unchecked, regardless of their initial state on non-postback load or the state before form submission. I took out the checkbox and stripped this down to the simplest example I could come up with. I tossed EnableViewState=true all over the place just in case it was being disabled somewhere I couldn't find. <form id="form1" runat="server" enableviewstate="true"> <div> <asp:RadioButton ID="foo" Text="foo" runat="server" AutoPostBack="true" OnCheckedChanged="rbChanged" Checked="true" GroupName="foobar" EnableViewState="true" /> <asp:RadioButton ID="bar" Text="bar" runat="server" AutoPostBack="true" GroupName="foobar" OnCheckedChanged="rbChanged" Checked="false" EnableViewState="true" /> <asp:Label runat="server" ID="resultLbl" /> </div> </form> protected void rbChanged(object sender, EventArgs e) { if (foo.Checked) resultLbl.Text = "foo is checked"; else if (bar.Checked) resultLbl.Text = "bar is checked"; else resultLbl.Text = "neither is checked"; }

    Read the article

  • Magento MAGMI: Product attributes (custom options) not showing up in import

    - by Rodgers and Hammertime
    When importing a CSV into Magento with the MAGMI importing tool, I am unable to import Custom Options (as in size: smalee/medium/large). The import manages to put in the basic products, but the Custom Options don't transfer accross. By custom options I mean the fields Title, Input Type, Is Required, Sort Order Title, Price, Price Type, SKU, Sort Order Title, Price, Price Type, SKU, Sort Order Title, Price, Price Type, SKU, Sort Order and so on ... Found in the custom options menu... Even using the example CSV from the MAGMI SourceForge Wiki: sku,name,description,price,Size:drop_down:1 T-Shirt1,T-Shirt,A T-Shirt,5.00,Small|Medium|Large T-Shirt2,T-Shirt2,Another T-Shirt,6.00,XS|S|M|L|XL ...it fails to import the attributes. So i'm simply using MAGMI with the supplied example data from SourceForge on a blank magento product list, and it doesn't transfer properly. Can anyone shed any light on what might be wrong? I am using Magento ver. 1.6.1.0 if that changes anything. Thanks.

    Read the article

  • PHP's SimpleXML: How to use colons in names

    - by nute
    I am trying to generate an RSS Google Merchant, using SimpleXML. The sample given by Google is: <?xml version="1.0"?> <rss version="2.0" xmlns:g="http://base.google.com/ns/1.0"> <channel> <title>The name of your data feed</title> <link>http://www.example.com</link> <description>A description of your content</description> <item> <title>Red wool sweater</title> <link> http://www.example.com/item1-info-page.html</link> <description>Comfortable and soft, this sweater will keep you warm on those cold winter nights.</description> <g:image_link>http://www.example.com/image1.jpg</g:image_link> <g:price>25</g:price> <g:condition>new</g:condition> <g:id>1a</g:id> </item> </channel> </rss> My code has things like: $product->addChild("g:condition", 'new'); Which generates: <condition>new</condition> I read online that I should instead use: $product->addChild("g:condition", 'new', 'http://base.google.com/ns/1.0'); Which now generates: <g:condition xmlns:g="http://base.google.com/ns/1.0">new</g:condition> This seems very counter-intuitive to me, as now the "xmlns" declaration is on almost EVERY line of my RSS feed intead of just once in the root element. Am I missing something?

    Read the article

  • adding tabbar to uiview (not tabbarcontroller) to switch views

    - by Pavan
    Hi, i added a Tab bar to my existing view called secondViewController where there are now 4 tab bar items using interface builder. This tab bar will allow the users to switch between views. This is what ive tried to do: If i use a tabbar controller, then a new view pops up and i dont want that. i simply want to be able to add a tab bar as ive done and carry on from there. i dont know how to actually connect it all up and make everything work together. This is what i understand: i have to make my current - secondViewController an tabbardelegate which is what ive done as shown @interface paddedDholViewController : UIViewController <AVAudioPlayerDelegate, UITabBarDelegate> { } then i understand that i have to add tabBar.delegate = self; for me to be able to detect the tabBar:didSelectItem: so i can then implement something like this - (void)tabBarController:(UITabBarController *)tabBarController didSelectViewController:(UIViewController *)viewController { if ([viewController.tabBarItem.title isEqualToString:@"FIRST"]) { NSLog(@"FIRST"); } else if ([viewController.tabBarItem.title isEqualToString:@"SECOND"]) { NSLog(@"SECOND"); } } to be able to switch between the views The thing is as ive said before i dont know how to implement all of this and how to connect everything up. can someone help me please. Thank you in advance

    Read the article

  • Enum "does not have a no-arg default constructor" with Jaxb and cxf

    - by Dave
    A client is having an issue running java2ws on some of their code, which uses & extends classes that are consumed from my SOAP web services. Confused yet? :) I'm exposing a SOAP web service (JBoss5, Java 6). Someone is consuming that web service with Axis1 and creating a jar out of it with the data types and client stubs. They are then defining their own type, which extends one of my types. My type contains an enumeration. class MyParent { private MyEnumType myEnum; // getters, settters for myEnum; } class TheirChild extends MyParent { ... } When they are running java2ws on their code (which extends my class), they get Caused by: com.sun.xml.bind.v2.runtime.IllegalAnnotationsException: 2 counts of IllegalAnnotationExceptions net.foo.bar.MyEnuMType does not have a no-arg default constructor. this problem is related to the following location: at net.foo.bar.MyEnumType at public net.foo.bar.MyEnumType net.foo.bar.MyParent.getMyEnum() The enum I've defined is below. This is now how it comes out after being consumed, but it's how I have it defined on the app server: @XmlType(name = "MyEnumType") @XmlEnum public enum MyEnumType { Val1("Val1"), Val2("Val2") private final String value; MyEnumType(String v) { value = v; } public String value() { return value; } public static MyEnumType fromValue(String v) { if (v == null || v.length() == 0) { return null; } if (v.equals("Val1")) { return MyEnumType.Val1; } if (v.equals("Val2")) { return MyEnumType.Val2; } return null; } } I've seen things online and other posts, like (this one) regarding Jaxb's inability to handle Lists or things like that, but I'm baffled about my enum. I'm pretty sure you can't have a default constructor for an enum (well, at least a public no-arg constructor, Java yells at me when I try), so I'm not sure what makes this error possible. Any ideas? Also, the "2 counts of IllegalAnnotationsExceptions" may be because my code actually has two enums that are written similarly, but I left them out of this example for brevity.

    Read the article

  • How to implement iPhone TitleBar in Android

    - by edwar12345
    You know in iPhone, The four components of a typical iPhone application are a title bar, a navigation list, a destination page, and a button bar. for The Title Bar The title bar includes the following elements: Back button: Screen title: Command button: My question comes, although i can use UI framework tool, such as: Phonegap, iui, jtquery to develop web app, but i can't display the TitleBar effect in Android, i can't use below code in Android: meta content="yes" name="apple-mobile-web-app-capable" Actually, the above can work in Apple Safari Browser, but I can't use Safari to display our Android Project, which is i don't want to see. Does anyone know how to fulfill this effect in Android, please help me, your help will be great appreciated. to "It's unclear if you developing a native android application or a webapp. – alexanderblom yesterday" sorry that i forget to mention, i want to develop a iphone-webapp-style application in Android. Since it's too difficult, i want to use iWebkit, but it seems only work in apple iPhone OS or Safari which contain the specific engine to display the beautiful layout, like below:( -_-! i am new so i can't post images here) http://images.appshopper.com/screenshots/305/690205_2.jpg

    Read the article

  • JQuery Simple Modal OSX Multiple dialogs

    - by Aneef
    HI, I'm planning to use the jquery Simple modal for login and registration on my project site. i tried to have 2 modals as mentioned here. but im still unable to make it work. here is my code jQuery(function ($) { var OSX = { container: null, init: function () { $("a.osx").click(function (e) { e.preventDefault(); $(this.id + "_osx-modal-content").modal({ overlayId: this.id+'_osx-overlay', containerId: this.id+'_osx-container', closeHTML: null, minHeight: 80, opacity: 65, position: ['0',], overlayClose: true, onOpen: OSX.open, onClose: OSX.close }); }); }, open: function (d) { var self = this; self.container = d.container[0]; d.overlay.fadeIn('slow', function () { $("#osx-modal-content", self.container).show(); var title = $("#osx-modal-title", self.container); title.show(); d.container.slideDown('slow', function () { setTimeout(function () { var h = $("#osx-modal-data", self.container).height() + title.height() + 20; // padding d.container.animate( {height: h}, 200, function () { $("div.close", self.container).show(); $("#osx-modal-data", self.container).show(); } ); }, 300); }); }) }, close: function (d) { var self = this; // this = SimpleModal object d.container.animate( {top:"-" + (d.container.height() + 20)}, 500, function () { self.close(); // or $.modal.close(); } ); } }; OSX.init(); I guess its something to do with the open: function part, anyone can help me ?

    Read the article

  • get property from XML using PHP

    - by Adnan
    Hello, I am using PHP's SimpleXML to get some values out of the following XML; - <entry> <id>http://www.google.com/m8/feeds/contacts/email_address%40gmail.com/base/0</id> <updated>2010-01-14T22:06:26.565Z</updated> <category scheme="http://schemas.google.com/g/2005#kind" term="http://schemas.google.com/contact/2008#contact" /> <title type="text">Customer Name</title> <link rel="http://schemas.google.com/contacts/2008/rel#edit-photo" type="image/*" href="http://www.google.com/m8/feeds/photos/media/email_address%40gmail.com/0/34h5jh34j5kj3444" /> <link rel="self" type="application/atom+xml" href="http://www.google.com/m8/feeds/contacts/email_address%40gmail.com/full/0" /> <link rel="edit" type="application/atom+xml" href="http://www.google.com/m8/feeds/contacts/email_address%40gmail.com/full/0/5555" /> <gd:email rel="http://schemas.google.com/g/2005#other" address="[email protected]" primary="true" /> </entry> I can get the title with: $xml = new SimpleXMLElement($response_h1); foreach ($xml->entry as $entry) { echo $entry->title, '<br />'; } But how to get the address="[email protected]" property?

    Read the article

  • jQuery ajax link, returned data includes a from that wont submit

    - by calumogg
    Hi everyone, I have a problem with the returned data from a ajax request. Basically when I click on a link it runs a ajax request to load some html into a div, that part is working fine the problem comes when the data has been loaded. Part of the html loaded is a form, this form works fine if I load the page directly but when it is loaded through ajax into the div it wont submit but the rest of the links in the html work fine. Here is the code that requests the remote html data: // Ajax to load image editing page $('a.editpicture').click(function(e) { e.preventDefault(); var picture = $(this).attr("id") $.ajax({ url: 'http://localhost/digital-xposure/index.php/members/viewpicture/' + picture, success: function(data) { $('#update-picture').html(data); } }); }); This is the form it loads: <form method="post" id="updatepicture" name="updatepicture" action="http://localhost/digital-xposure/index.php/members/editpicture"/> <p>Title<input type="text" name="title" id="title" style="input" value="<?php echo $title; ?>"></P> <p>Album<?php echo $albums;?></p> <p>Description<textarea name="description" id="description" cols="50" rows="5"><?php echo $description; ?></textarea></P> <input type="hidden" name="filename" id="filename" value="<?php echo $filename; ?>" /> <input type="button" name="update-submit" id="update-submit" value="Update details" class="button"> Or <input type="button" onClick="location.href='<?php echo base_url(); ?>index.php/members/deletepicture/<?php echo $filename; ?>'" value="Delete picture" class="button"> </form> Any ideas why the form wont submit after being loaded into the div? Any help is greatly appreciated, thanks. Calum

    Read the article

  • Is jQuery.parseJSON able to process all valid json?

    - by murze
    This piece of valid json (it has been generated using php's json_encode): {"html":"form is NOT valid<form id=\"articleform\" enctype=\"application\/x-www-form-urlencoded\" method=\"post\" action=\"\"><dl class=\"zend_form\">\n<dt id=\"title-label\">&nbsp;<\/dt>\n<dd id=\"title-element\">\n<input type=\"text\" name=\"title\" id=\"title\" value=\"Artikel K\"><\/dd>\n<dt id=\"articleFormSubmitted-label\">&nbsp;<\/dt>\n<dd id=\"articleFormSubmitted-element\">\n<input type=\"hidden\" name=\"articleFormSubmitted\" value=\"1\" id=\"articleFormSubmitted\"><\/dd>\n<dt id=\"submit-label\">&nbsp;<\/dt><dd id=\"submit-element\">\n<input type=\"submit\" name=\"submit\" id=\"submit\" value=\"Bewaar artikel\" onclick=\"this.value='Bezig...';\"><\/dd><\/dl><\/form><script type=\"text\/javascript\">\n\t $(\"#articleform\").submit(function(){\n $.post(\"\/admin\/ajax\/contenttree\/node\/9\/ajaxtarget\/ajaxContainer\", $(\"#articleform\").serialize(), function(html){$(\"#ajaxContainer\").html(html);} );\n\t\t return false;\n\t });\n\n <\/script>","newNodeName":""} is giving jQuery.parseJSON(data) and me a hard time. With this piece of code: alert('start'); alert(data); jQuery.parseJSON(data) alert('stop'); I get a message start and then the data (jsonstring above) is shown. The message "stop" never appears. When I use this json: {"html":"test","newNodeName":""} I've verified that my first big chick of json is valid. Why isn't it processed by jQuery.parseJSON Are there any special characters that don't go well with json?

    Read the article

  • popViewController does not autorotate back to allowed orientation

    - by JoeGaggler
    I have two UIViewControllers, "A" and "B", where "A" overrides the shouldAutorotateToInterfaceOrientation to return YES for UIInterfaceOrientationPortrait, and "B" returns YES for all orientations. In my example "A" is the root navigation view controller, and I then use pushViewController for "B". After that I rotate the device into landscape, which successfully autorotates "B", then I pop "B" (back button or via popViewController) to return to "A". When targetting iPhone OS 3.1.3, "A" returns to the portrait orientation as expected. When targetting iPhone OS 3.2, I have two side-effects: "A" is displayed in landscape. The navigation bar does not update even though "A" is now displayed. The navigation bar still shows the items for "B". Only after trying to go back/pop one more time will the navigation bar animate to show the items for "A". If I instead attempt to push "B" again and go back, I have to pop twice before the navigation bar animates to show the items for "A". During these "intermediate pops" the view for "A" remains displayed. While researching this issue, I have seen other answers suggesting performing the rotation manually ([UIDevice setOrientation] or via a tranformation), however this does not help understand what the problem is, especially why it behaves differently between the two OS's. So my question is: must all of my UIViewControllers on the UINavigationController stack support exactly the same orientations going forward? And if not, then is there something that I need to do to make it behave as it did for OS 3.1.3?

    Read the article

  • Android & SQLite: "Table audios has no column named downloaded"

    - by Erik
    I get this weird exception when i run my app on both the emulator and a USB connected device. i can see the table inside the shell, but when I try to insert a record from the Activity acton I get this exception: android.database.sqlite.SQLiteException: table audios has no column named downloaded I am mostly running on an emulator with Android 1.5. The predominant part of my code is linked to this tutorial - http://www.devx.com/wireless/Article/40842/1954. This is the create statement I use: private static final String DATABASE_CREATE = "create table audios ( _id integer primary key autoincrement, " + "user_name text not null, title text not null, file_path text not null, download integer not null, " + "created_at integer not null, downloaded_at integer not null );"; This is the insert code I use: //--- insert a title into the database --- public long insertTitle(String user_name, String title, String file_path, Integer downloaded, long created_at, String downloaded_at ) { ContentValues initialValues = new ContentValues(); initialValues.put(KEY_USER_NAME, user_name); initialValues.put(KEY_TITLE, title); initialValues.put(KEY_FILE, file_path); initialValues.put(KEY_DOWNLOADED, downloaded); initialValues.put(KEY_CREATED_AT, created_at); initialValues.put(KEY_DOWNLOADED_AT, downloaded_at); return db.insert(DATABASE_TABLE, null, initialValues); }

    Read the article

  • MS AJAX Library 4.0 Sys.create.dataView

    - by azamsharp
    One again Microsoft poor documentation has left me confused. I am trying to use the new features of the .NET 4.0 framework. I am using the following code to populate the Title and Director but it keeps getting blank. <script language="javascript" type="text/javascript"> Sys.require([Sys.components.dataView, Sys.components.dataContext,Sys.scripts.WebServices], function () { Sys.create.dataView("#moviesView", { dataProvider: "MovieService.svc", fetchOperation: "GetMovies", autoFetch: true }); }); </script> And here it the HTML code: <ul id="moviesView"> <li> {{Title}} - {{Director}} </li> </ul> IS THIS THE LATEST URL TO Start.js file. Here is the Ajax-Enabled WCF Service: [ServiceContract(Namespace = "")] [AspNetCompatibilityRequirements(RequirementsMode = AspNetCompatibilityRequirementsMode.Allowed)] public class MovieService { [OperationContract] public Movie GetMovies() { return new Movie() { Title = "SS", Director = "SSSSS" }; } } [DataContract] public class Movie { [DataMember] public string Title { get; set; } [DataMember] public string Director { get; set; } }

    Read the article

  • Git-svn refuses to create branch on svn repository error: "not in the same repository"

    - by Danny
    I am attempting to create a svn branch using git-svn. The repository was created with --stdlayout. Unfortunately it generates an error stating the "Source and dest appear not to be in the same repository". The error appears to be the result of it not including the username in the source url. $ git svn branch foo-as-bar -m "Attempt to make Foo into Bar." Copying svn+ssh://my.foo.company/r/sandbox/foo/trunk at r1173 to svn+ssh://[email protected]/r/sandbox/foo/branches/foo-as-bar... Trying to use an unsupported feature: Source and dest appear not to be in the same repository (src: 'svn+ssh://my.foo.company/r/sandbox/foo/trunk'; dst: 'svn+ssh://[email protected]/r/sandbox/foo/branches/foo-as-bar') at /home/me/.install/git/libexec/git-core/git-svn line 610 I intially thought this was simply a configuration issue, examination of .git/config doesn't suggest anything incorrect. [svn-remote "svn"] url = svn+ssh://[email protected]/r fetch = sandbox/foo/trunk:refs/remotes/trunk branches = sandbox/foo/branches/*:refs/remotes/* tags = sandbox/foo/tags/*:refs/remotes/tags/* I am using git version 1.6.3.3. Can anyone shed any light on why this might be occuring, and how best to address it?

    Read the article

  • Django DRY Feeds

    - by Mandx
    I'm using the Django Feeds Framework and it's really nice, very intuitive and easy to use. But, I think there is a problem when creating links to feeds in HTML. For example: <link rel="alternate" type="application/rss+xml" title="{{ feed_title }}" href="{{ url_of_feed }}" /> Link's HREF attribute can be easily found out, just use reverse() But, what about the TITLE attribute? Where the template engine should look for this? Even more, what if the feed is build up dinamically and the title depends on parameters (like this)? I can't come up with a solution that "seems" DRY to me... All that I can come up with is using context processors o template tags, but it gets messy when the context procesor/template tag has to find parameters to construct the Feed class, and writing this I realize I don't even know how to create a Feed instance myself within the view. If I put all this logic in the view, it would not be just one view. Also, the value for TITLE would be in the view AND in the feed.

    Read the article

< Previous Page | 133 134 135 136 137 138 139 140 141 142 143 144  | Next Page >