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  • ASP.NET server side show JS Alert box, doesn't work when using partial post back.

    - by jamone
    I have put the following method in my master page. It works when I call it on a full post back, but when I call it from a updatePanel's asyncPostBack no alert is shown. public void ShowAlertMessage(String message) { string alertScript = String.Format("alert('{0}');", message); Page.ClientScript.RegisterStartupScript(this.GetType(), "Key", alertScript, true); } What do I need to do so it works on partial post backs?

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  • How do I make the "back button" work with jQuery hide/show functions?

    - by Walker
    I'm looking for a way to append text to the url with jQuery so that the back button is not broken when a user loads new content with jQuery. For example, I have a three step form - the first step is (www.xyz.com/form-1). When the user clicks next step, jQuery slides in the next page. I would like that page to be (www.xyz.com/form-2). I know websites like hypem.com do this, I'm just looking for an elegant way to handle it.

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  • Can we only use the back-end of wordpress without any front-end ?

    - by Tristan
    Hello, i just asked a question few minutes ago which led me to this one : I want to know if there is any chance to use only the back-end of wordpress ? I mean, link my admin interface to post news link my visitor interface on my website to the wordpress news so the visitor can access the news So the visitor never find out that i'm using wordpress to generate the news and handle their comments and write my news ? Maybe it's possible but there is no point by doing so ? Thank you

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  • How to obtain listview information without refreshing the page?

    - by user1808098
    I am currently developing an Android Application for my Final Year Project. But to be honest I do not have any basic knowledges and everything started from scratch and referring to online tutorials a lot. Here is my question, I was trying to retrieve data from listview activity. There are two listview in my page using button. I was able to display the first listview but when it get data for the second listview, the data for first listview is disappeared because the page is refreshed, vice versa. What code should I modified to get both the data in the page? (Database not implemented yet) Please help, thanks a lot. Below are my codings. Codings for XML. <!-- Location --> <TextView android:id="@+id/TextViewLocation" android:layout_width="fill_parent" android:layout_height="wrap_content" android:layout_marginTop="5dip" android:layout_marginBottom="10dip" android:text="Location Information" android:gravity="center" android:textSize="15dip" android:textColor="#025f7c"/> <!-- Condition Label --> <TextView android:layout_width="fill_parent" android:layout_height="wrap_content" android:textColor="#372c24" android:text="Traffic Condition"/> <Button android:id="@+id/inputListView" android:layout_width="fill_parent" android:layout_height="wrap_content" android:layout_marginTop="5dip" android:layout_marginBottom="10dip" android:text="choose one..."/> <!-- Comment Label --> <TextView android:layout_width="fill_parent" android:layout_height="wrap_content" android:textColor="#372c24" android:text="What's Happening?"/> <Button android:id="@+id/inputListView2" android:layout_width="fill_parent" android:layout_height="wrap_content" android:layout_marginTop="5dip" android:layout_marginBottom="10dip" android:text="choose one..."/> <!-- Suggestion Label --> <TextView android:layout_width="fill_parent" android:layout_height="wrap_content" android:textColor="#372c24" android:text="Comments / Suggestion"/> <EditText android:layout_width="fill_parent" android:layout_height="80dp" android:layout_marginTop="5dip" android:layout_marginBottom="10dip" android:singleLine="true"/> <!-- Image button --> <Button android:id="@+id/btnImage" android:layout_width="fill_parent" android:layout_height="wrap_content" android:layout_marginTop="5dip" android:text="Upload Image"/> <!-- Report button --> <Button android:id="@+id/btnReportCheckin" android:layout_width="fill_parent" android:layout_height="wrap_content" android:layout_marginTop="5dip" android:text="Report"/> <!-- Link to Logout --> <TextView android:id="@+id/linkLogout" android:layout_width="fill_parent" android:layout_height="wrap_content" android:layout_marginTop="5dip" android:layout_marginBottom="40dip" android:text="Log Out" android:gravity="center" android:textSize="20dip" android:textColor="#025f7c"/> </LinearLayout> <!-- Check or Report Form Ends --> Codings for Activity Class public class CheckinActivity extends Activity { @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); // Set View to checkin.xml setContentView(R.layout.checkin); /* TextView LocationView = (TextView) findViewById(R.id.TextViewLocation); Intent h = getIntent(); // getting attached intent data String address = h.getStringExtra("address"); // displaying selected product name LocationView.setText(address); */ Button ListViewScreen = (Button) findViewById(R.id.inputListView); //Listening to Button ListViewScreen.setOnClickListener(new View.OnClickListener() { public void onClick(View v) { //Switching to ListView Screen Intent i = new Intent(getApplicationContext(), ListViewActivity.class); startActivity(i); } } ); Button SelectedView = (Button) findViewById(R.id.inputListView); Intent i = getIntent(); // getting attached intent data String product = i.getStringExtra("product"); // displaying selected product name SelectedView.setText(product); Button ListView2Screen = (Button) findViewById(R.id.inputListView2); //Listening to Button ListView2Screen.setOnClickListener(new View.OnClickListener() { public void onClick(View v) { //Switching to ListView Screen Intent j = new Intent(getApplicationContext(), ListView2Activity.class); startActivity(j); } } ); Button SelectedView2 = (Button) findViewById(R.id.inputListView2); Intent j = getIntent(); // getting attached intent data String product2 = j.getStringExtra("product2"); // displaying selected product name SelectedView2.setText(product2); TextView Logout = (TextView) findViewById(R.id.linkLogout); // Listening to Log out Logout.setOnClickListener(new View.OnClickListener() { public void onClick(View arg0) { // Closing menu screen // Switching to Login Screen/closing register screen finish(); } }); } } Coding for listview class public class ListViewActivity extends ListActivity { @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); // storing string resources into Array String[] traffic_condition = getResources().getStringArray(R.array.traffic_condition); // Binding resources Array to ListAdapter this.setListAdapter(new ArrayAdapter<String>(this, R.layout.listitem, R.id.listViewLayout, traffic_condition)); ListView lv = getListView(); // listening to single list item on click lv.setOnItemClickListener(new OnItemClickListener() { public void onItemClick(AdapterView<?> parent, View view, int position, long id) { // selected item String product = ((TextView) view).getText().toString(); // Launching new Activity on selecting single List Item Intent i = new Intent(getApplicationContext(), CheckinActivity.class); // sending data to new activity i.putExtra("product", product); startActivity(i); } }); } } Hope I made myself clear, I can provide a screen shot of my apps if it is required, thanks!

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  • how to pass an integeter array from a asp.net mvc controller action back to javascript using jquery

    - by oo
    Here is my jQuery code: $.get('/Home/GetList', function(data) { debugger; $('#myMultiSelect').val(data); }); Here is my controller code: public ActionResult GetList(int id) { int[] bodyParts = _repository.GetList(id); //how do i return this as an array back to javascript ?? } if I have the GetList function return an array of integers, how do I return this to the jQuery function?

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  • How can i read back an object stored in a session?

    - by strakastroukas
    First of all, here comes the load part. Structure MainStruct Dim Ans1 As String Dim Ans2 As String End Structure Dim Build As New List(Of MainStruct) ... ... ... Session("MyData") = Build The question is how can i read back the contents of the list, stored in the Session? I mean something like... Build = Session("MyData").Ans1

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  • how to pass an array from a asp.net mvc controller action back to javascript using jquery / ajax

    - by oo
    Here is my jQuery code: $.get('/Home/GetList', function(data) { debugger; $('#myMultiSelect').val(values); }); Here is my controller code: public ActionResult GetList(int id) { int[] bodyParts = _repository.GetList(id); //how do i return this as an array back to javascript ?? } if I have the GetList function return an array of integers, how do I return this to the jQuery function?

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  • Should I go back and fix work when you learn something new/better?

    - by SnOrfus
    Considering that we're all constantly learning, we've all got to come across a point where we learn something just awesome that improves our code or parts of it significantly. The question is, when you've learned some new technique, strategy or whatever, do your or should you go back to code that you know works, but could be so much better/maintainable/faster/generally improved and implement this new knowledge? I understand the concept of "if it ain't broke, don't fix it" but when does that become losing pride in code you've already written and what does it say for refactoring.

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