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  • expand a varchar column very slowly , why?

    - by francs
    Hi We need to modify a column of a big product table , usually normall ddl statments will be excutely fast ,but the above ddl statmens takes about 10 minnutes?I wonder know the reason! I just want to expand a varchar column?The following is the detailsl --table size wapreader_log= select pg_size_pretty(pg_relation_size('log_foot_mark')); pg_size_pretty ---------------- 5441 MB (1 row) --table ddl wapreader_log= \d log_foot_mark Table "wapreader_log.log_foot_mark" Column | Type | Modifiers -------------+-----------------------------+----------- id | integer | not null create_time | timestamp without time zone | sky_id | integer | url | character varying(1000) | refer_url | character varying(1000) | source | character varying(64) | users | character varying(64) | userm | character varying(64) | usert | character varying(64) | ip | character varying(32) | module | character varying(64) | resource_id | character varying(100) | user_agent | character varying(128) | Indexes: "pk_log_footmark" PRIMARY KEY, btree (id) --alter column wapreader_log= \timing Timing is on. wapreader_log= ALTER TABLE wapreader_log.log_foot_mark ALTER column user_agent TYPE character varying(256); ALTER TABLE Time: 603504.835 ms

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  • Excel 2007 UDF keeps failing, why?

    - by Zan
    I've been trying to browse info about this for a while now. The user defined functions in Excel 2007 just make no sense to me whatsoever. According to all the tutorials, it should be really simple. Just press alt + f11, insert a new module, and enter the VBA code there. At this point typing '=FUNCTIONNAME(parameters)' into any cell should make it work. It did, at first. Then upon closing and reopening the worksheet it stopped working. I checked to see that macros were enabled, but either way, that didn't help. Then I browsed the graphic UI from the function button to locate user defined functions. I found it there by name of 'MyExcelWorksheet.xls!FUNCTIONNAME.FUNCTIONNAME' and clicking that, it started working again. Now, a day later, I get back to working on this and it's broken, again. I just get #NAME? error or some "Function Arguments - Function doesn't use any arguments" -popup (translated from Finnish Excel, not sure what that msg is in English) when I select the function from the GUI. So what does it take to just create a function, and actually make it work and KEEP working? For the life of me I can't figure out why this has to be so difficult. :) I'm starting to think my company has some weird settings enabled or whatever, because judging by the lack of information I've found on the subject, this isn't supposed to happen.

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  • Why would MessageBox fail silently?

    - by Tim Gradwell
    Does anyone know how MessageBox(...) could fail silently? MessageBox(g_hMainhWnd, buffer, "Oops!", MB_OK | MB_ICONERROR); ShellExecute(0, "open", "http://intranet/crash_handler.php", NULL, "", SW_SHOWNORMAL); For a little context, this code is called inside our own exception handler, which was registered with SetUnhandledExceptionFilter() Most of the time, I see the message box, and then it launches a web browser. However, I have an exe, which as far as I'm aware uses this exact code, and it successfully launches the web browser, but I do not see the message box first. Thanks Tim

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  • why i^=j^=i^=j isn't equal to *i^=*j^=*i^=*j

    - by klvoek
    In c , when there is variables (assume both as int) i less than j , we can use the equation i^=j^=i^=j to exchange the value of the two variables. For example, let int i = 3, j = 5; after computed i^=j^=i^=j, I got i = 5, j = 3 . What is so amazing to me. But, if i use two int pointers to re-do this , with *i^=*j^=*i^=*j , use the example above what i got will be i = 0 and j = 3. Then, describe it simply: In C 1 int i=3, j=5; i^=j^=i^=j; // after this i = 5, j=3 2 int i = 3, j= 5; int *pi = &i, *pj = &j; *pi^=*pj^=*pi^=*pj; // after this, $pi = 0, *pj = 5 In JavaScript var i=3, j=5; i^=j^=i^=j; // after this, i = 0, j= 3 the result in JavaScript makes this more interesting to me my sample code , on ubuntu server 11.0 & gcc #include <stdio.h> int main(){ int i=7, j=9; int *pi=&i, *pj=&j; i^=j^=i^=j; printf("i=%d j=%d\n", i, j); i=7, j==9; *pi^=*pj^=*pi^=*pj printf("i=%d j=%d\n", *pi, *pj); } however, i had spent hours to test and find out why, but nothing means. So, please help me. Or, just only i made some mistake???

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  • Why is BorderLayout calling setSize() and setBounds()?

    - by ags
    I'm trying to get my head around proper use of the different LayoutManagers to make my GUI design skills more efficient and effective. For me, that usually requires a detailed understanding of what is going on under the hood. I've found some good discussion of the interaction and consequences of a Container using BorderLayout containing a Container using FlowLayout. I understand it for the most part, but wanted to confirm my mental model and to do so I am looking at the code for BorderLayout. In the code snippet below taken from BorderLayout.layoutContainer(), note the calls to the child Component's setSize() method followed by setBounds(). Looking at the source for these methods of Component, setSize() actually calls setBounds() with the current values for Component.x and Component.y. Why is this done (and not entirely redudant?) Doesn't the setBounds() call completely overwrite the results of the setSize() call? if ((c=getChild(NORTH,ltr)) != null) { c.setSize(right - left, c.height); Dimension d = c.getPreferredSize(); c.setBounds(left, top, right - left, d.height); top += d.height + vgap; } I'm also tring to understand where/when the child Component's size is initially set (before the LayoutManager.layoutContainer() method is called). Finally, this post itself raises a "meta-question": in a situation like this, where the source is available elsewhere, is the accepteed protocol to include the entire method? Or some other way to make it easier for folks to participate in the thread? Thanks.

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  • Why should I use core.autocrlf in Git

    - by Rich
    I have a Git repository that is accessed from both Windows and OS X, and that I know already contains some files with CRLF line-endings. As far as I can tell, there are two ways to deal with this: Set core.autocrlf to false everywhere, Follow the instructions here (echoed on GitHub's help pages) to convert the repository to contain only LF line-endings, and thereafter set core.autocrlf to true on Windows and input on OS X. The problem with doing this is that if I have any binary files in the repository that: a). are not correctly marked as binary in gitattributes, and b). happen to contain both CRLFs and LFs, they will be corrupted. It is possible my repository contains such files. So why shouldn't I just turn off Git's line-ending conversion? There are a lot of vague warnings on the web about having core.autocrlf switched off causing problems, but very few specific ones; the only that I've found so far are that kdiff3 cannot handle CRLF endings (not a problem for me), and that some text editors have line-ending issues (also not a problem for me). The repository is internal to my company, and so I don't need to worry about sharing it with people with different autocrlf settings or line-ending requirements. Are there any other problems with just leaving line-endings as-is that I am unaware of?

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  • Multiple exports with MEF does some really heinous stuff -- why, and why is it allowed?

    - by Dave
    I have an interesting situation where I need to do something like this: [Export[typeof(ICandy1)] [Export[typeof(ICandy2)] public class Candy : ICandy2 { ... } where public interface ICandy1 { ... } public interface ICandy2 : ICandy1 { ... } I couldn't find any posts anywhere regarding using multiple [Export] attributes, so I figured, what the hell, might as well try it. At first glance, it actually seemed to work. I have a couple of methods that call into both interfaces of a Candy instance, and it was fine. However, as I started to test the app, I saw that the behavior wasn't right, and when looking at the Output window, I saw that I was getting tons of COMExceptions. I couldn't track down where they were all coming from, but they always occurred when a worker thread was sleeping. I figured that it had to be from the main thread, then, but didn't know how to debug this at all. Nothing should have been going on in the GUI, and I disabled my DispatchTimers just in case -- same thing. Even more strange than the COMExceptions was the really, really erratic behavior when stepping through code. About 30% of the time, when I single stepped, it would pop out of the method, or it would single step over two lines of code! Totally weird stuff that I am not used to seeing. The only thing that changed between working and non-working code was the introduction of MEF through my plugin loading code. So as a test, I changed my plugin assembly to only export one interface, and I hardcoded everything in the app that relied on the other (now not-implemented) interface. And now the COMExceptions are gone, and the weird debugging behavior is gone. Is this something people here have seen before? If MEF is not expected to allow a class to Export multiple interfaces, then shouldn't a CompositionException get raised when composing the parts? Can anyone explain why MEF would cause these weird problems???

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  • O(log N) == O(1) - Why not?

    - by phoku
    Whenever I consider algorithms/data structures I tend to replace the log(N) parts by constants. Oh, I know log(N) diverges - but does it matter in real world applications? log(infinity) < 100 for all practical purposes. I am really curious for real world examples where this doesn't hold. To clarify: I understand O(f(N)) I am curious about real world examples where the asymptotic behaviour matters more than the constants of the actual performance. If log(N) can be replaced by a constant it still can be replaced by a constant in O( N log N). This question is for the sake of (a) entertainment and (b) to gather arguments to use if I run (again) into a controversy about the performance of a design.

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  • Why doesn't this external JavaScript load?

    - by Ben Herila
    I've been futzing with this for hours trying to figure out why codemirror.js won't load in any browser other than Firefox. Any ideas? index.html <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en"> <head> <title></title> <script src="CodeMirror/js/codemirror.js"></script> <link href="Styles/Style.css" rel="stylesheet" type="text/css" /> <link href="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/themes/base/jquery-ui.css" rel="stylesheet" type="text/css" /> <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.4/jquery.min.js"></script> <script src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/jquery-ui.min.js"></script> <script type="text/javascript"> $(document).ready(function () { $('#container-1').tabs(); }); </script> <style type="text/css"> /* (some css) */ </style> </head><body> <!-- (some stuff) --> </body></html> CodeMirror/js/codemirror.js alert("LOL");

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  • Why is this Java Calendar comparison bad?

    - by joe7pak
    Hello folks. I'm having an inexplicable problem with the Java Calendar class when I'm trying to compare to dates. I'm trying to compare to Calendars and determine if their difference is than 1 day, and do things bases on that difference or not. But it doesn't work. If I do this with the two dates: String currDate = aCurrentUTCCalendar.getTime().toString(); String localDate = aLocalCalendar.getTime().toString(); I get these results: currDate = "Thu Jan 06 05:58:00 MST 2010" localDate = "Tue Jan 05 00:02:00 MST 2010" This is correct. But if I do this: long curr = aCurrentUTCCalendar.getTime().getTime(); long local = aLocalCalendar.getTime().getTime(); I get these results: ( in milliseconds since the epoch ) curr = -125566110120000 local = 1262674920000 Since there is only about a 30 hour different between the two, the magnitudes are vastly different, not to mention that annoying negative sign. This causes problems if I do this: long day = 60 * 60 * 24 * 1000; // 86400000 millis, one day if( local - curr > day ) { // do something } What's wrong? Why are the getTime().toString() calls correct, but the getTime().getTime() calls are vastly different? I'm using jdk 1.6_06 on WinXP. I can't upgrade the JDK for various reasons.

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  • Why doesn't my text be bold when displaying on device screen

    - by john123
    My string.xml: <!--I try to bold my argument %s, like below:--> <string name="hello">Hello to: <b>%s</b> !</string> My layout main.xml: <LinearLayout ...> <TextView android:id="@+id/hello_txt" ... .../> </LinearLayout> My Fragment class: public class MyFragment extends Fragment{ TextView helloTxt; @Override public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) { super.onCreateView(inflater, container, savedInstanceState); helloTxt = (TextView) findViewById(R.id.hello_txt); } @Override public void onStart() { super.onStart(); //pass "Monday" as the argument to my string helloTxt.setText(String.format(getString(R.string.hello), "Monday")); } } When I run my app on my device, I got "Hello to: Monday !" displaying on screen, but the "Monday" is not bold, but I used <b> in my string.xml. Why it is not bold??

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  • Why is UseCompatibleTextRendering needed here?

    - by HotOil
    Hi, I think I'm missing something fundamental. Please tell me what it is, if you can. I have developed a little C++ WinForms app using VS2008. So it is built using .NET 3.5 SP1. My development box is Win7, if that matters. The default value of UseCompatibleTextRendering property in WinForms controls is false in this version of VStudio. And this should not matter to me, I don't think. I don't have any custom-drawn text or controls. The app looks good running on my Win7 box. If I package it up (dragging along .NET 3.5) and install it on one of our WinXP desktops, the buttons and labels don't look good; the text is chopped off in them. If I set UseCompatibleTextRendering to true and then run it on the XP boxes, the text fits into the buttons and labels. My question is: Why? The installation puts .Net 3.5 on the XP boxes, so the app should be able to find and use the right version of WinForms, right? I should note that before I put my app + .NET 3.5 on these boxes, they have no .NET at all. They do not get automatic Microsoft updates; our IT guy gates the patches and upgrades. [ This sort of thing has happened before with apps I create.. they look/work great on the Engineering machines, because we maintain those and they mostly have up-to-date stuff. When they are run on the corporate boxes, they usually don't run and need the VCredist installed. ] Back to the question at hand: The text looks better with the UseCompatibleTextRendering set to false, so I'd rather keep it that way, if I can. I'd like to understand what might be missing on those XP boxes that is making the text not fit. Thanks S

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  • why malloc+memset slower than calloc?

    - by kingkai
    It's known that calloc differentiates itself with malloc in which it initializes the memory alloted. With calloc, the memory is set to zero. With malloc, the memory is not cleared. So in everyday work, i regard calloc as malloc+memset. Incidentally, for fun, i wrote the following codes for benchmark. The result is confused. Code 1: #include<stdio.h> #include<stdlib.h> #define BLOCK_SIZE 1024*1024*256 int main() { int i=0; char *buf[10]; while(i<10) { buf[i] = (char*)calloc(1,BLOCK_SIZE); i++; } } time ./a.out real 0m0.287s user 0m0.095s sys 0m0.192s Code 2: #include<stdio.h> #include<stdlib.h> #include<string.h> #define BLOCK_SIZE 1024*1024*256 int main() { int i=0; char *buf[10]; while(i<10) { buf[i] = (char*)malloc(BLOCK_SIZE); memset(buf[i],'\0',BLOCK_SIZE); i++; } } time ./a.out real 0m2.693s user 0m0.973s sys 0m1.721s Repalce memset with bzero(buf[i],BLOCK_SIZE) in Code 2 produce the result alike. My Question is that why malloc+memset is so much slower than calloc? How can calloc do that ? Thanks!

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  • what are the recent dataStructure and algorithms that one should know?

    - by Shamik
    Recently I came across the SkipList data structure. It really helped me to solve one otherwise critical problem to be solved. I was struggling to solve the same problem with Balanced Binary tree but it became very complex as the tree needs to be always balanced and I wanted to know the existence of not only a particular value but values in certain range. SkipList helped me to solve that problem effectively. I am wondering what else data structures that I need to know? I know - Array, List, Stack, Queue, Linked List, hashtable, tree and its different forms like B-tree, Trie etc. Would like to know if you find some other data structure/concept very interesting to know yet effective enough to be used in a daily development cycle.

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  • Why jquery have problem with onbeforeprint event?

    - by Cesar Lopez
    Hi all, I have the following function. $(function() { $(".sectionHeader:gt(0)").click(function() { $(this).next(".fieldset").slideToggle("fast"); }); $("img[alt='minimize']").click(function(e) { $(this).closest("table").next(".fieldset").slideUp("fast"); e.stopPropagation(); return false; }); $("img[alt='maximize']").click(function(e) { $(this).closest("table").next(".fieldset").slideDown("fast"); e.stopPropagation(); return false; }); }); <script type="text/javascript"> window.onbeforeprint = expandAll; function expandAll(){ $(".fieldset:gt(0)").slideDown("fast"); } </script> For this html <table class="sectionHeader" ><tr ><td>Heading 1</td></tr></table> <div style="display:none;" class="fieldset">Content 1</div> <table class="sectionHeader" ><tr ><td>Heading 2</td></tr></table> <div style="display:none;" class="fieldset">Content 2</div> I have several div class="fieldset" over the page, but when I do print preview or print, I can see all divs sliding down before opening the print preview or printing but on the actual print preview or print out they are all collapse. I would appreciate if anyone comes with a solution for this. Anyone have any idea why is this or how to fix it? Thanks. PS:Using a does not work either ( I assume because jquery using toggle) and its not the kind of question I am looking for.

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  • Why is my quick sort so slow?

    - by user513075
    Hello, I am practicing writing sorting algorithms as part of some interview preparation, and I am wondering if anybody can help me spot why this quick sort is not very fast? It appears to have the correct runtime complexity, but it is slower than my merge sort by a constant factor of about 2. I would also appreciate any comments that would improve my code that don't necessarily answer the question. Thanks a lot for your help! Please don't hesitate to let me know if I have made any etiquette mistakes. This is my first question here. private class QuickSort implements Sort { @Override public int[] sortItems(int[] ts) { List<Integer> toSort = new ArrayList<Integer>(); for (int i : ts) { toSort.add(i); } toSort = partition(toSort); int[] ret = new int[ts.length]; for (int i = 0; i < toSort.size(); i++) { ret[i] = toSort.get(i); } return ret; } private List<Integer> partition(List<Integer> toSort) { if (toSort.size() <= 1) return toSort; int pivotIndex = myRandom.nextInt(toSort.size()); Integer pivot = toSort.get(pivotIndex); toSort.remove(pivotIndex); List<Integer> left = new ArrayList<Integer>(); List<Integer> right = new ArrayList<Integer>(); for (int i : toSort) { if (i > pivot) right.add(i); else left.add(i); } left = partition(left); right = partition(right); left.add(pivot); left.addAll(right); return left; } }

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  • Why won't my WPF XAML Grid TranslateTransform.X ?

    - by George
    I'm able to change the width/height of the grid using this, so why won't it work when I use (Grid.RenderTransform).TranslateTransform.X as such: <Window.Triggers> <EventTrigger RoutedEvent="Button.Click" SourceName="button"> <BeginStoryboard> <Storyboard> <DoubleAnimation Storyboard.TargetProperty="(Grid.RenderTransform).(TranslateTransform.X)" From="0" To="200" Storyboard.TargetName="grid" Duration="0:0:2" /> </Storyboard> </BeginStoryboard> </EventTrigger> </Window.Triggers> The application loads etc, but nothing happens when the button is clicked. Here is the XAML for my grid: <Grid x:Name="grid" Height="714" Canvas.Left="240" Canvas.Top="8" Width="360" RenderTransformOrigin="0.5,0.5"> <Grid.Background> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="Black" Offset="0"/> <GradientStop Color="White" Offset="1"/> </LinearGradientBrush> </Grid.Background> <Grid.ColumnDefinitions> <ColumnDefinition Width="0*"/> <ColumnDefinition/> </Grid.ColumnDefinitions> </Grid> Note that I've tried many different Canvas.Left values, to no avail.

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  • Why is url not registered?(Drupal 6.x)

    - by Andrew
    I'm using hook_menu to register new url so that accessing this url would return some data to ajax function. As title suggested, this url is not registered. How do I know that? I've tried typing this in address bar but, drupal, return main template only rather than the tests string that I created. I'm positive that my module is working for php issues error if I intentionally write wrong syntax. And, yes, I clear cache whenever I make changes. Here's the code - function test_menu() { $my_form['test'] = array( 'title' => 'Test address', 'page callback' => 'test', 'access arguments' => array('access content'), 'type' => MENU_CALLBACK, ); return $my_form; } function test(){ $a= "testing"; return $a; }

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  • On C++ global operator new: why it can be replaced

    - by Jimmy
    I wrote a small program in VS2005 to test whether C++ global operator new can be overloaded. It can. #include "stdafx.h" #include "iostream" #include "iomanip" #include "string" #include "new" using namespace std; class C { public: C() { cout<<"CTOR"<<endl; } }; void * operator new(size_t size) { cout<<"my overload of global plain old new"<<endl; // try to allocate size bytes void *p = malloc(size); return (p); } int main() { C* pc1 = new C; cin.get(); return 0; } In the above, my definition of operator new is called. If I remove that function from the code, then operator new in C:\Program Files (x86)\Microsoft Visual Studio 8\VC\crt\src\new.cpp gets called. All is good. However, in my opinion, my implementations of operator new does NOT overload the new in new.cpp, it CONFLICTS with it and violates the one-definition rule. Why doesn't the compiler complain about it? Or does the standard say since operator new is so special, one-definition rule does not apply here? Thanks.

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  • Why are controls (null) in awakeFromNib?

    - by fuzzygoat
    This is a follow on from another question regarding why I could not set UIControls in awakeFromNib. The answer to that is that as you can see below the controls are nil in the awakeFromNib, although they are initialised to the correct objects by the time we get to viewDidLoad. I setup the view the same as I always do, should I be doing something different to access them here, the xib(nib) was designed and saved with the current version of Image Builder. CODE: @interface iPhone_TEST_AwakeFromNibViewController : UIViewController { UILabel *myLabel; UIImageView *myView; } @property(nonatomic, retain)IBOutlet UILabel *myLabel; @property(nonatomic, retain)IBOutlet UIImageView *myView; @end . @synthesize myLabel; @synthesize myView; -(void)awakeFromNib { NSLog(@"awakeFromNib ..."); NSLog(@"myLabel: %@", [myLabel class]); NSLog(@"myView : %@", [myView class]); //[myLabel setText:@"AWAKE"]; [super awakeFromNib]; } -(void)viewDidLoad { NSLog(@"viewDidLoad ..."); NSLog(@"myLabel: %@", [myLabel class]); NSLog(@"myView : %@", [myView class]); //[myLabel setText:@"VIEW"]; [super viewDidLoad]; } OUTPUT: awakeFromNib ... myLabel: (null) myView : (null) viewDidLoad ... myLabel: UILabel myLabel: UIImageView Much appreciated ... gary

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  • JavaScript: why `null == 0` is false?

    - by lemonedo
    I had to write a routine that increments the value of a variable by 1 if it is a number, or assigns 0 to the variable if it is not a number. The variable can be incremented by the expression, or be assigned null. No other write access to the variable is allowed. So, the variable can be in three states: it is 0, a positive integer, or null. My first implementation was: v >= 0 ? v += 1 : v = 0 (Yes, I admit that v === null ? v = 0 : v += 1 is the exact solution, but I wanted to be concise then.) It failed since null >= 0 is true. I was confused, since if a value is not a number, an numeric expression involving it must be false always. Then I found that null is like 0, since null + 1 == 1, 1 / null == Infinity, Math.pow(2.718281828, null) == 1, ... Strangely enough, however, null == 0 is evaluated to false. I guess null is the only value that makes the following expression false: (v == 0) === (v >= 0 && v <= 0) So why null is so special in JavaScript?

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  • Why are these lines being skipped? (java)

    - by David
    Here's the relevant bit of the source code: class Dice { String name ; int x ; int[] sum ; ... public Dice (String name) { this.name = name ; this.x = 0 ; this.sum = new int[7] ; } ... public static void main (String[] arg) { Dice a1 = new Dice ("a1") ; printValues (a1) ; } public static void printDice (Dice Dice) { System.out.println (Dice.name) ; System.out.println ("value: "+Dice.x) ; printValues (Dice) ; } public static void printValues (Dice Dice) { for (int i = 0; i<Dice.sum.length; i++) System.out.println ("#of "+i+"'s: "+Dice.sum[i]) ; } } Here is the output: #of 0's: 0 #of 1's: 0 #of 2's: 0 #of 3's: 0 #of 4's: 0 #of 5's: 0 #of 6's: 0 Why didn't these two lines execute inside printDice: System.out.println (Dice.name) ; System.out.println ("value: "+Dice.x) ; if they had then i would expect to see "a1" and "Value: 0" printed at the top of the rows of #of's

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  • Boost threading/mutexs, why does this work?

    - by Flamewires
    Code: #include <iostream> #include "stdafx.h" #include <boost/thread.hpp> #include <boost/thread/mutex.hpp> using namespace std; boost::mutex mut; double results[10]; void doubler(int x) { //boost::mutex::scoped_lock lck(mut); results[x] = x*2; } int _tmain(int argc, _TCHAR* argv[]) { boost::thread_group thds; for (int x = 10; x>0; x--) { boost::thread *Thread = new boost::thread(&doubler, x); thds.add_thread(Thread); } thds.join_all(); for (int x = 0; x<10; x++) { cout << results[x] << endl; } return 0; } Output: 0 2 4 6 8 10 12 14 16 18 Press any key to continue . . . So...my question is why does this work(as far as i can tell, i ran it about 20 times), producing the above output, even with the locking commented out? I thought the general idea was: in each thread: calculate 2*x copy results to CPU register(s) store calculation in correct part of array copy results back to main(shared) memory I would think that under all but perfect conditions this would result in some part of the results array having 0 values. Is it only copying the required double of the array to a cpu register? Or is it just too short of a calculation to get preempted before it writes the result back to ram? Thanks.

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  • Why won't my Setup Project Perform my Custom Registration Process

    - by Jordan S
    I am trying to write an Setup Project/Installer for a class library driver that I wrote in C# using Visual Studio 2008. The driver project has a section of code that looks like this... [ComRegisterFunction] public static void RegisterASCOM(Type t) { Trace.WriteLine("Registration Started."); DoRegistration(true); } In the driver project Properties - "Assembly Information" I have set checked the box that says Make COM-Visible = true. I added a Setup Project to the solution in VS, added the output dll from the driver project so that it installs on the target machine and set the Register property of the dll to "vsdraCOM". So, my understanding is that when the installer runs it SHOULD execute the methods of the dll that are marked with [COMRegisterFunction]. Using SysInternals Debug View I can monitor when the above code snippet is hit by watching for the "Registration started" text to show up in the window. When I build the solution, I can see the text show up so I know the driver is registering properly. The problem is that when I run the installer, I don't think it is doing the registration bit. I see nothing show up in Debug View. And if i try to access my driver via another application I get an error saying it "Cannot create ActiveX object". Why does the registration not occur during the install process? The driver does register for COM but it does NOT call my custom registration method. Does anyone have and suggestions of what I could be missing? Is there another way I can debug this? (I can provide more code if anyone want's to take a look!!)

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  • Why can't I open a JBoss vfs:/ URL?

    - by skiphoppy
    We are upgrading our application from JBoss 4 to JBoss 6. A couple of pieces of our application get delivered to the client in an unusual way: jars are looked up inside of our application and sent to the client from a servlet, where the client extracts them in order to run certain support functions. In JBoss 4 we would look these jars up with the classloader and find a jar:// URL which would be used to read the jar and send its contents to the client. In JBoss 6 when we perform the lookup we get a vfs:/ URL. I understand that this is from the org.jboss.vfs package. Unfortunately when I call openStream() on this URL and read from the stream, I immediately get an EOF (read() returns -1). What gives? Why can't I read the resource this URL refers to? I've tried trying to access the underlying VFS packages to open the file through the JBoss VFS API, but most of the API appears to be private, and I couldn't find a routine to translate from a vfs:/ URL to a VFS VirtualFile object, so I couldn't get anywhere. I can try to find the file on disk within JBoss, but that approach sounds very failure prone on upgrade. Our old approach was to use Java Web Start to distribute the jars to the client and then look them up within Java Web Start's cache to extract them. But that broke on every minor upgrade of Java because the layout of the cache changed.

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