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  • Convert a post-order binary tree traversal index to an level-order (breadth-first) index

    - by strfry
    Assuming a complete binary tree, each node can be adressed with the position it appears in a given tree traversal algorithm. For example, the node indices of a simple complete tree with height 3 would look like this: breadth first (aka level-order): 0 / \ 1 2 / \ / \ 3 4 5 6 post-order dept first: 6 / \ 2 5 / \ / \ 0 1 3 4 The height of the tree and an index in the post-order traversal is given. How can i calculate the breadth first index from this information?

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  • Cladogram, tree of life, cladistics, taxonomy in JS or canvas?

    - by boblet
    Good people - I need some help to find a way to create an interactive cladogram or phylogenetic tree (yes, I have read all related posts, and do not find what I am looking for). The thing is, I need the nodes to be name-able. An example would be something like this Most scripts I find are either applets, flash, or simply do not show the node classification, ie it would skip "feliformia" in this example. This is useless to me, as I would then end up with carnivore - anonymous node - anonymous node - anonymous node - tiger, and that is not good. This tree will in theory cover all life, so it could get rather large, and get links and names in english and latin from database. So: no flash, no applets. It must be horizontal, no supertrees (circular). I have gone through this http://bioinfo.unice.fr/biodiv/Tree_editors.html but most of them seems to be either old, not displaying sub-node levels, applets, or way too complex. I imagine this would be a delightful job for canvas/jQuery..? And chances are, someone got there before me? Any pointers much appreciated. Note: if anyone out there would like to do something like this as a project, I will be happy to help, even though it would not benefit me for this project.This type of taxonomy is not as simple as it may seem, and I would be happy see this happen.

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  • Dojo How to ColorPalette + TooltipDialog + DropDownButton

    - by portoalet
    I am trying to add a ColorPalette into a TooltipDialog, which in turn is contained inside DropDownButton (dojo 1.3.1) Code: var paramsContent = new dijit.layout.ContentPane(); var colorPalette = new dijit.ColorPalette(); var tooltipThematic = new dijit.TooltipDialog({content: paramsContent}); var colorField = new dijit.form.DropDownButton( {label: 'Select Color', dropDown: tooltipThematic } ); How can I add the colorPalette into tooltipThematic? I did var tooltipThematic = new dijit.TooltipDialog(new dijit.ColorPalette()) but then I got this message: Already registered widget (error message on 1.0) http://o.dojotoolkit.org/forum/dijit-dijit-0-9/dijit-support/already-registered-widget-error-message How can I add the ColorPalette into the TooltipDialog?

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  • How can you get the call tree with python profilers?

    - by Oliver
    I used to use a nice Apple profiler that is built into the System Monitor application. As long as your C++ code was compiled with debug information, you could sample your running application and it would print out an indented tree telling you what percent of the parent function's time was spent in this function (and the body vs. other function calls). For instance, if main called function_1 and function_2, function_2 calls function_3, and then main calls function_3: main (100%, 1% in function body): function_1 (9%, 9% in function body): function_2 (90%, 85% in function body): function_3 (100%, 100% in function body) function_3 (1%, 1% in function body) I would see this and think, "Something is taking a long time in the code in the body of function_2. If I want my program to be faster, that's where I should start." Does anyone know how I can most easily get this exact profiling output for a python program? I've seen people say to do this: import cProfile, pstats prof = cProfile.Profile() prof = prof.runctx("real_main(argv)", globals(), locals()) stats = pstats.Stats(prof) stats.sort_stats("time") # Or cumulative stats.print_stats(80) # 80 = how many to print but it's quite messy compared to that elegant call tree. Please let me know if you can easily do this, it would help quite a bit. Cheers!

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  • A data structure based on the R-Tree: creating new child nodes when a node is full, but what if I ha

    - by Tom
    I realize my title is not very clear, but I am having trouble thinking of a better one. If anyone wants to correct it, please do. I'm developing a data structure for my 2 dimensional game with an infinite universe. The data structure is based on a simple (!) node/leaf system, like the R-Tree. This is the basic concept: you set howmany childs you want a node (a container) to have maximum. If you want to add a leaf, but the node the leaf should be in is full, then it will create a new set of nodes within this node and move all current leafs to their new (more exact) node. This way, very populated areas will have a lot more subdivisions than a very big but rarely visited area. This works for normal objects. The only problem arises when I have more than maxChildsPerNode objects with the exact same X,Y location: because the node is full, it will create more exact subnodes, but the old leafs will all be put in the exact same node again because they have the exact same position -- resulting in an infinite loop of creating more nodes and more nodes. So, what should I do when I want to add more leafs than maxChildsPerNode with the exact same position to my tree? PS. if I failed to explain my problem, please tell me, so I can try to improve the explanation.

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  • reiserfsck --rebuild-tree failed: Not enough allocable blocks

    - by mojo
    I have a reiserfs volume that required a --rebuild-tree, but is currently failing to complete when I pass it --rebuild-tree. Here is the output that I receive when running it: reiserfsck 3.6.19 (2003 www.namesys.com) # reiserfsck --rebuild-tree started at Mon Oct 26 13:22:16 2009 # Pass 0: # Pass 0 The whole partition (7864320 blocks) is to be scanned Skipping 8450 blocks (super block, journal, bitmaps) 7855870 blocks will be read 0%....20%....40%....60%....80%....100% left 0, 9408 /sec 287884 directory entries were hashed with "r5" hash. "r5" hash is selected Flushing..finished Read blocks (but not data blocks) 7855870 Leaves among those 6105606 Objectids found 287892 Pass 1 (will try to insert 6105606 leaves): # Pass 1 Looking for allocable blocks .. finished 0%....20%....40%....60%....80%....Not enough allocable blocks, checking bitmap...there are 1 allocable blocks, btw out of disk space Aborted I can't mount it, and I can't fsck it. I've tried extending the volume, but that hasn't helped either.

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  • reiserfsck --rebuild-tree failed: Not enough allocable blocks

    - by mojo
    I have a reiserfs volume that required a --rebuild-tree, but is currently failing to complete when I pass it --rebuild-tree. Here is the output that I receive when running it: reiserfsck 3.6.19 (2003 www.namesys.com) # reiserfsck --rebuild-tree started at Mon Oct 26 13:22:16 2009 # Pass 0: # Pass 0 The whole partition (7864320 blocks) is to be scanned Skipping 8450 blocks (super block, journal, bitmaps) 7855870 blocks will be read 0%....20%....40%....60%....80%....100% left 0, 9408 /sec 287884 directory entries were hashed with "r5" hash. "r5" hash is selected Flushing..finished Read blocks (but not data blocks) 7855870 Leaves among those 6105606 Objectids found 287892 Pass 1 (will try to insert 6105606 leaves): # Pass 1 Looking for allocable blocks .. finished 0%....20%....40%....60%....80%....Not enough allocable blocks, checking bitmap...there are 1 allocable blocks, btw out of disk space Aborted I can't mount it, and I can't fsck it. I've tried extending the volume, but that hasn't helped either.

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  • How can I force a tree itemrenderer to redraw during a drag and drop operation?

    - by swidnikk
    I have a tree control with a custom item renderer. The item renderer has different states that should be set while an item is being dragged over the item renderer. I understand from reading this post http://forums.adobe.com/message/2091088 that the 'right way' to do this is to override the 'getCurrentState' method and append some text. I do that. Now in my tree control I handle the drag over event and get a reference to the itemrenderer that is being dragged over and I set the boolean 'dragOver' property to true. Now I just need to force my itemRenderer to redraw. I can't figure that out. A workaround, is to just set the currentState of the itemRenderer. My question then, how can I force my itemRenderer to refresh? (and I've tried calling validateNow, invalideDisplayList/Properties/Size, to no avail) <?xml version="1.0" encoding="utf-8"?> <s:MXTreeItemRenderer xmlns:fx="http://ns.adobe.com/mxml/2009" xmlns:s="library://ns.adobe.com/flex/spark" xmlns:mx="library://ns.adobe.com/flex/mx"> <fx:Script> <![CDATA[ import mx.events.DragEvent; import mx.events.FlexEvent; import spark.layouts.supportClasses.DropLocation; public var dragOver:Boolean = false; override protected function getCurrentRendererState():String { var skinState:String = super.getCurrentRendererState(); if( dragOver ) skinState += "AndDragOver"; trace('getCurrentRendererState', skinState); return skinState; } ]]> </fx:Script> <s:states> <s:State name="normal" /> <s:State name="hovered" /> <s:State name="selected" /> <s:State name="normalAndDragOver" stateGroups="dragOverGroup" /> <s:State name="hoveredAndDragOver" stateGroups="dragOverGroup" /> <s:State name="selectedAndDragOver" stateGroups="dragOverGroup" /> </s:states> ...

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  • How to modify preorder tree traversal algorithm to handle nodes with multiple parents?

    - by poldo
    I've been searching for a while now and can't seem to find an alternative solution. I need the tree traversal algorithm in such a way that a node can have more than 1 parent, if it's possible (found a great article here: Storing Hierarchical Data in a Database). Are there any algorithms so that, starting from a root node, we can determine the sequence and dependencies of nodes (currently reading topological sorting)?

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  • merge sort recursion tree height

    - by Tony
    Hello! I am learning about recursion tree's and trying to figure out how the height of the tree is log b of n where n = 2 and one has 10 elements as input size. I am working with Merge sort. The number of times the split is done is the height of the tree as far as I understood, and the number of levels in the tree is height + 1. But if you take (for merge sort) log2 of 10 you get 1, where if you draw the tree you get at least 2 times that the recursion occurs. Where have I gone wrong? (I hope I am making sense here) NOTE: I am doing a self study, this is not homework!

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  • Tree item edit event listener in flex

    - by Biroka
    I want to catch itemEditEnd in a tree control, but i'm having a little trouble. I call the item editing a bit different: <mx:Tree id="tree" width="100%" height="100%" itemDoubleClick="treeProjects_itemDoubleClickHandler(event)" doubleClickEnabled="true" editable="true" itemEditBeginning="treeProjects_itemEditBeginingHandler(event)" itemEditEnd="treeProjects_itemEditEndHandler(event)" > but: protected function treeProjects_itemEditBeginingHandler(event:ListEvent):void { event.preventDefault(); } i do this, because I want to edit the field just when clicking rename in the context menu. And when I click rename in the context menu, this is what i'm doing (contextParentItem is the event catched on itemRollOver in the tree) : Tree( contextParentItem.target ).editedItemPosition = { columnIndex: 0, rowIndex: contextParentItem.rowIndex }; Thisway I can't catch the itemEditEnd event, but I want to handle some stuff, like: if the new entered value is an empty string, then I don't want to accept the new value if I hit ESC then, the old value should remain.

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  • Very long tree control inside a <frame>

    - by ryancerium
    I have an tree control inside of a frame. It's quite tall, around 2000 pixels. Right now, we use the frame's scroll bars, which is mostly good. Unfortunately, when you select an item near the bottom of the list, the page reloads and the view goes back to the top of the list. I tried calling the tree control's ScrollNodeIntoView() function, but since we're not using the tree's scroll bars, it just thinks that it's displaying the full 2000 pixels and the control doesn't have its own scroll bar. I'm not much of an HTML guru, so I have two ideas, neither of which I know how to do. 1) Tell the frame to not to let the tree render all 2000 pixels and instead stay inside the viewable area. 2) Tell the tree to not render all 2000 pixels and instead stay within the viewable area. Setting the CSS height property on the within the frame doesn't do anything. Thanks.

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  • Virtual String Tree - Display subnode when parent node is hidden

    - by daemon_x
    Is there a way to show subnode if the parent node is hidden in the Virtual String Tree ? I have some tasks in the tree structure and I wish to display only tasks which belongs to the current user as the list, but from all levels. What I've done is the function to display a list, which hides tree buttons, tree lines, sets the fixed indent and enable toShowHiddenNodes option. Then in this function I iterate through the whole tree (all levels) and hide nodes which doesn't belong to the current user IsVisible[Node] := False and show those which belongs him IsVisible[Node] := True, but the subnodes which should be displayed are invisible when their parent is hidden. VT.TreeOptions.PaintOptions - toShowButtons - toShowTreeLines + toFixedIndent + toShowHiddenNodes

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  • Last element not getting insert in Tree

    - by rdk1992
    So I was asked to make a Binary Tree in Haskell taking as input a list of Integers. Below is my code. My problem is that the last element of the list is not getting inserted in the Tree. For example [1,2,3,4] it only inserts to the tree until "3" and 4 is not inserted in the Tree. data ArbolBinario a = Node a (ArbolBinario a) (ArbolBinario a) | EmptyNode deriving(Show) insert(x) EmptyNode= insert(tail x) (Node (head x) EmptyNode EmptyNode) insert(x) (Node e izq der) |x == [] = EmptyNode --I added this line to fix the Prelude.Head Empty List error, after I added this line the last element started to be ignored and not inserted in the tree |head x == e = (Node e izq der) |head x < e = (Node e (insert x izq) der) |head x > e = (Node e izq (insert x der)) Any ideas on whats going on here? Help is much appreciated

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  • Virtual Brown Bag Recap: FancyHands, CanCan, 1KB XMas Tree, YouTube Yuks

    - by Brian Schroer
    At this week's Virtual Brown Bag meeting: Claudio has some one-month Evernote premium accounts to give away Claudio & George talked about FancyHands, the 4-hour work week, and paying people to do the stuff you don't want to JB shared more Ruby gems: cancan and open and talked about insert and other Ruby Enumerable functions We looked at the winner of the 1KB JavaScript Christmas contest and some fun YouTube videos For detailed notes, links, and the video recording, go to the VBB wiki page: https://sites.google.com/site/vbbwiki/main_page/2010-12-23

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  • Most efficient way to rebuild a tree structure from data

    - by Ahsan
    Have a question on recursively populating JsTree using the .NET wrapper available via NuGet. Any help would be greatly appreciated. the .NET class JsTree3Node has a property named Children which holds a list of JsTree3Nodes, and the pre-existing table which contains the node structure looks like this NodeId ParentNodeId Data AbsolutePath 1 NULL News /News 2 1 Financial /News/Financial 3 2 StockMarket /News/Financial/StockMarket I have a EF data context from the the database, so my code currently looks like this. var parentNode = new JsTree3Node(Guid.NewGuid().ToString()); foreach(var nodeItem in context.Nodes) { parentNode.Children.Add(nodeItem.Data); // What is the most efficient logic to do this recursively? } as the inline comment says in the above code, what would be the most efficient way to load the JStree data on to the parentNode object. I can change the existing node table to suite the logic so feel free to suggest any changes to improve performance.

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  • Efficiently representing a dynamic transform hierarchy

    - by Mattia
    I'm looking for a way to represent a dynamic transform hierarchy (i.e. one where nodes can be inserted and removed arbitrarily) that's a bit more efficient than using a standard tree of pointers . I saw the answers to this question ( Efficient structure for representing a transform hierarchy. ), but as far as I can determine the tree-as-array approach only works for static hierarchies or dynamic ones where nodes have a fixed number of children (both deal-breakers for me). I'm probably wrong about that but could anyone point out how? If I'm not wrong are there other alternatives that work for dynamic hierarchies?

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  • Faking Display tree (Sprite) parent child relationships with rasters (BitmapData) in ActionScript 3

    - by Arthur Wulf White
    I am working with Rasters (bitmapData) and blliting (copypixels) in a 2d-game in actionscript 3. I like how you can move a sprite and it moves all it's children, and you can simultaneously move the children creating an interesting visual effect. I do not want to use rotation or scaling however cause I do not know how that can be done without hampering with performance. So I'm not simulating Sprite parent-child behavior and sticking to the movement on the (x, y) axis. What I am planning to do is create a class called RasterContainer which extends bitmapData that has a vector of children of type Raster(extending bitmapData), now I am planning to implement recursive rendering in RasterContainer, that basically copyPixels every child, only changing their (x, y) offset to reflect their parent's offset. My question is, has this been implemented in an existing framework? Is this a good plan? Do I expect a serious performance hit for using recursive methods this way?

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