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• Django many to many annotations and filters

  - by dl8

  So I have two models, Person and Film where they're in a many to many relationship. My goal is to grab a film, and output the persons that have also appeared in at least 10 films. For example I can get the count individually by: >>> Person.objects.get(short__istartswith = "Matt Damon").film_set.count() 71 However, if I try to filter all the actors of a particular film out: >>> Film.objects.get(name__istartswith="Saving Private Ryan").actors.all().annotate(film_count=Count('film')).filter(film_count__gte=10) [] it returns an empty set since if I manually look at everyone's film_count it's 1, even though an actor such as Matt Damon (as seen above) has been in 71 films in my db. As you can see with this query, the annotation doesn't work: >>> Film.objects.get(name__istartswith="Saving Private Ryan").actors.all().annotate(film_count=Count('film'))[0].film_count 1 >>> Film.objects.get(name__istartswith="Saving Private Ryan").actors.all().annotate(film_count=Count('film'))[0].film_set.count() 7 and I can't seem to figure out a way to filter it by the film_set.count()

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• django generic view update/create: update works but create raises IntegrityError

  - by smarber

  I'm using CreateView and UpdateView directely into urls.py of my application whose name is dydict. In the file forms.py I'm using ModelForm and I'm exluding a couple of fields from being shown, some of which sould be set when either creating or updating. So, as mentioned in the title, update part works but create part doesn't which is obvious because required fields that I have exluded are sent empty which is not allowed in my case. So the question here is, how should I do to fill exluded fields into the file forms.py so that I don't have to override CreateView? Thanks in advance.

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• Django templates tag error

  - by Hulk

  def _table_(request,id,has_permissions): dict = {} dict.update(get_newdata(request,rid)) return render_to_response('home/_display.html',context_instance=RequestContext(request,{'dict': dict, 'rid' : rid, 'has_permissions' : str(has_permissions)})) In templates the code is as, {% if has_permissions == "1" %} <input type="button" value="Edit" id="edit" onclick="javascript:edit('{{id}}')" style="display:inline;"/>&nbsp;&nbsp;&nbsp;&nbsp; {% endif %} There is a template error in has_permissions line. Can any 1 tell me what is wrong here. has_permissions has the value 1 or 0.

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• querying for timestamp field in django

  - by Hulk

  In my views i have the date in the following format s_date=20090106 and e_date=20100106 The model is defined as class Activity(models.Model): timestamp = models.DateTimeField(auto_now_add=True) how to query for the timestamp filed with the above info. Activity.objects.filter(timestamp>=s_date and timestamp<=e_date) Thanks.....

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• Creating a QuerySet based on a ManyToManyField in Django

  - by River Tam

  So I've got two classes; Picture and Tag that are as follows: class Tag(models.Model): pics = models.ManyToManyField('Picture', blank=True) name = models.CharField(max_length=30) # stuff omitted class Picture(models.Model): name = models.CharField(max_length=100) pub_date = models.DateTimeField('date published') tags = models.ManyToManyField('Tag', blank=True) content = models.ImageField(upload_to='instaton') #stuff omitted And what I'd like to do is get a queryset (for a ListView) given a tag name that contains the most recent X number of Pictures that are tagged as such. I've looked up very similar problems, but none of the responses make any sense to me at all. How would I go about creating this queryset?

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• Django templates check condition

  - by Hulk

  If there are are no values in the table how can should the code be to indicate no name found else show the drop down box in the below code {% for name in dict.names %} <option value="{{name.id}}" {% for selected_id in selected_name %}{% ifequal name.id selected_id %} {{ selected }} {% endifequal %} {% endfor %}>{{name.firstname}}</option>{% endfor %} </select> Thanks..

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• Django - calling full_clean() inside of clean() equivalent?

  - by orokusaki

  For transaction purposes, I need all field validations to run before clean() is done. Is this possible? My thinking is this: @transaction.commit_on_success def clean(self): # Some fun stuff here. self.full_clean() # I know this isn't correct, but it illustrates my point. but obviously that's not correct, because it would be recursive. Is there a way to make sure that everything that full_clean() does is done inside clean()?

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• Debugging "Premature end of script headers" - WSGI/Django [migrated]

  - by Marcin

  I have recently deployed an app to a shared host (webfaction), and for no apparent reason, my site will not load at all (it worked until today). It is a django app, but the django.log is not even created; the only clue is that in one of the logs, I get the error message: "Premature end of script headers", identifying my wsgi file as the source. I've tried to add logging to my wsgi file, but I can't find any log created for it. Is there any recommended way to debug this error? I am on the point of tearing my hair out. My WSGI file: import os import sys from django.core.handlers.wsgi import WSGIHandler import logging logger = logging.getLogger(__name__) os.environ['DJANGO_SETTINGS_MODULE'] = 'settings' os.environ['CELERY_LOADER'] = 'django' virtenv = os.path.expanduser("~/webapps/django/oneclickcosvirt/") activate_this = virtenv + "bin/activate_this.py" execfile(activate_this, dict(__file__=activate_this)) # if 'VIRTUAL_ENV' not in os.environ: # os.environ['VIRTUAL_ENV'] = virtenv sys.path.append(os.path.dirname(virtenv+'oneclickcos/')) logger.debug('About to run WSGIHandler') try: application = WSGIHandler() except (Exception,), e: logger.debug('Exception starting wsgihandler: %s' % e) raise e

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• Difference between django-openid and django-openid-auth ?

  - by Stefano Borini

  I found two python libs to perform openid authentication with django: django-openid and django-openid-auth. I don't get the difference between the two, mostly (I think) because I have no experience with the django authentication mechanisms.

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• Django admin, hide a model

  - by Hellnar

  Hello At the root page of the admin site where registered models appear, I want to hide several models that are registered to the Django admin. If I directly unregister those, I am not able to add new records as the add new symbol "+" dissapears. How can this be done ?

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• Disabling email-style usernames in Django 1.2 with django-registration

  - by shacker

  Django 1.2 allows usernames to take the form of an email address. Changed in Django 1.2: Usernames may now contain @, +, . and - characters I know that's a much-requested feature, but what if you don't want the new behavior? It makes for messy usernames in profile URLs and seems to break django-registration (if a user registers an account with an email-style username, the link in the django-registration activation email returns 404). Does anyone have a recipe for restoring the old behavior and disabling email-style usernames?

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• display one-to-many relationship for a model in Django admin (list mode)

  - by theactiveactor

  In Django admin site, when listing all the objects for a given model, I know we can customize which columns get displayed for a ModelA via list_display Say that ModelA has a one-to-many relationship with ModelB. I would like to add another column on the listing page for ModelA, where each entry is a URL pointing to all objects of ModelB having a foreign key relationship on corresponding instance of Model A in that row. How can I achieve this customization with the admin app?

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• Macports irssi & perl5 installation issues

  - by Dmitri DB

  Long time reader, first time poster. Big, appreciative thanks for everyone's collective questioning and answering here and at stackoverflow, it's helped me quite a lot over the time I've been learning answers through these sites! Apologies in advance if I didn't search hard enough on posts already up on this site to find out what I could do about this issue, but I thought I'd just reach out for the sake of trying at least once. I've experienced this issue while starting up my macports-installed version of irssi: 13:25 -!- Irssi: Error in script dispatch: 13:25 Can't locate lib.pm in @INC (@INC contains: /opt/local/lib/perl5/site_perl/5.12.4/darwin-multi-2level /opt/local/lib/perl5/site_perl/5.12.4 /opt/local/lib/perl5/vendor_perl/5.12.4/darwin-multi-2level /opt/local/lib/perl5/vendor_perl/5.12.4 /opt/local/lib/perl5/5.12.4/darwin-multi-2level /opt/local/lib/perl5/5.12.4 /opt/local/lib/perl5/site_perl/5.12.3/darwin-multi-2level /opt/local/lib/perl5/site_perl/5.12.3 /opt/local/lib/perl5/site_perl /opt/local/lib/perl5/vendor_perl .) at (eval 18) line 1. 13:25 BEGIN failed--compilation aborted at (eval 18) line 1. 13:25 Huh, strange. I looked into it a bit: [email protected] /opt/local/lib/perl5 ?- find . -name "lib.pm" -ls 14673887 16 -r--r--r-- 1 root admin 6853 25 Jun 23:39 ./5.12.4/darwin-thread-multi- 2level/lib.pm [email protected] /opt/local/lib/perl5 ?- l 5.12.4/darwin-thread-multi-2level total 1864 drwxr-xr-x 55 root admin 1870 28 Jun 19:28 . drwxr-xr-x 158 root admin 5372 28 Jun 19:28 .. -rw-r--r-- 1 root admin 177814 25 Jun 23:39 .packlist drwxr-xr-x 6 root admin 204 28 Jun 19:28 B -r--r--r-- 1 root admin 25714 25 Jun 23:39 B.pm drwxr-xr-x 64 root admin 2176 28 Jun 19:28 CORE drwxr-xr-x 3 root admin 102 28 Jun 19:28 Compress -r--r--r-- 1 root admin 3000 25 Jun 23:39 Config.pm -r--r--r-- 1 root admin 228094 25 Jun 23:39 Config.pod -r--r--r-- 1 root admin 409 25 Jun 23:39 Config_git.pl -r--r--r-- 1 root admin 38759 25 Jun 23:39 Config_heavy.pl -r--r--r-- 1 root admin 21174 25 Jun 23:39 Cwd.pm -r--r--r-- 1 root admin 63535 25 Jun 23:39 DB_File.pm drwxr-xr-x 3 root admin 102 28 Jun 19:28 Data drwxr-xr-x 5 root admin 170 28 Jun 19:28 Devel drwxr-xr-x 4 root admin 136 28 Jun 19:28 Digest -r--r--r-- 1 root admin 25185 25 Jun 23:39 DynaLoader.pm drwxr-xr-x 22 root admin 748 28 Jun 19:28 Encode -r--r--r-- 1 root admin 29731 25 Jun 23:39 Encode.pm -r--r--r-- 1 root admin 6736 25 Jun 23:39 Errno.pm -r--r--r-- 1 root admin 5445 25 Jun 23:39 Fcntl.pm drwxr-xr-x 5 root admin 170 28 Jun 19:28 File drwxr-xr-x 3 root admin 102 28 Jun 19:28 Filter -r--r--r-- 1 root admin 1819 25 Jun 23:39 GDBM_File.pm drwxr-xr-x 4 root admin 136 28 Jun 19:28 Hash drwxr-xr-x 3 root admin 102 28 Jun 19:28 I18N drwxr-xr-x 11 root admin 374 28 Jun 19:28 IO -r--r--r-- 1 root admin 1404 25 Jun 23:39 IO.pm drwxr-xr-x 6 root admin 204 28 Jun 19:28 IPC drwxr-xr-x 4 root admin 136 28 Jun 19:28 List drwxr-xr-x 4 root admin 136 28 Jun 19:28 MIME drwxr-xr-x 3 root admin 102 28 Jun 19:28 Math -r--r--r-- 1 root admin 2519 25 Jun 23:39 NDBM_File.pm -r--r--r-- 1 root admin 4208 25 Jun 23:39 O.pm -r--r--r-- 1 root admin 15563 25 Jun 23:39 Opcode.pm -r--r--r-- 1 root admin 21011 25 Jun 23:39 POSIX.pm -r--r--r-- 1 root admin 58962 25 Jun 23:39 POSIX.pod drwxr-xr-x 5 root admin 170 28 Jun 19:28 PerlIO -r--r--r-- 1 root admin 2515 25 Jun 23:39 SDBM_File.pm drwxr-xr-x 4 root admin 136 28 Jun 19:28 Scalar -r--r--r-- 1 root admin 10837 25 Jun 23:39 Socket.pm -r--r--r-- 1 root admin 41003 25 Jun 23:39 Storable.pm drwxr-xr-x 4 root admin 136 28 Jun 19:28 Sys drwxr-xr-x 3 root admin 102 28 Jun 19:28 Text drwxr-xr-x 5 root admin 170 28 Jun 19:28 Time drwxr-xr-x 3 root admin 102 28 Jun 19:28 Unicode -r--r--r-- 1 root admin 14462 25 Jun 23:39 attributes.pm drwxr-xr-x 38 root admin 1292 28 Jun 19:28 auto -r--r--r-- 1 root admin 19892 25 Jun 23:39 encoding.pm -r--r--r-- 1 root admin 6853 25 Jun 23:39 lib.pm -r--r--r-- 1 root admin 11044 25 Jun 23:39 mro.pm -r--r--r-- 1 root admin 997 25 Jun 23:39 ops.pm -r--r--r-- 1 root admin 13945 25 Jun 23:39 re.pm drwxr-xr-x 3 root admin 102 28 Jun 19:28 threads -r--r--r-- 1 root admin 33283 25 Jun 23:39 threads.pm So, it sort of seems to me that the permissions which perl5 got installed with for these modules has gotten mixed up somehow? I'm not really a perl user beyond enjoying it for massive directory-recursive find/replace operations within text files, so I haven't much of an idea what the permissions here are supposed to look like, and I'm not really sure how to go about determining how macports has gone and installed perl this way when it's otherwise worked without failure for years now. Does anyone have any recommendations for the sanest path towards rectifying this issue? Also, is there any interesting reason as to why the macports default for the perl5 port installs 5.12.4, and not 5.16.0, which has to be explicitly installed via the perl5.16 port? Thanks again!

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• Does Django cache url regex patterns somehow?

  - by Emre Sevinç

  I'm a Django newbie who needs help: Even though I change some urls in my urls.py I keep on getting the same error message from Django. Here is the relevant line from my settings.py: ROOT_URLCONF = 'mydjango.urls' Here is my urls.py: from django.conf.urls.defaults import * # Uncomment the next two lines to enable the admin: from django.contrib import admin admin.autodiscover() urlpatterns = patterns('', # Example: # (r'^mydjango/', include('mydjango.foo.urls')), # Uncomment the admin/doc line below and add 'django.contrib.admindocs' # to INSTALLED_APPS to enable admin documentation: #(r'^admin/doc/', include(django.contrib.admindocs.urls)), # (r'^polls/', include('mydjango.polls.urls')), (r'^$', 'mydjango.polls.views.homepage'), (r'^polls/$', 'mydjango.polls.views.index'), (r'^polls/(?P<poll_id>\d+)/$', 'mydjango.polls.views.detail'), (r'^polls/(?P<poll_id>\d+)/results/$', 'mydjango.polls.views.results'), (r'^polls/(?P<poll_id>\d+)/vote/$', 'mydjango.polls.views.vote'), (r'^polls/randomTest1/', 'mydjango.polls.views.randomTest1'), (r'^admin/', include(admin.site.urls)), ) So I expect that whenever I visit http://mydjango.yafz.org/polls/randomTest1/ the mydjango.polls.views.randomTest1 function should run because in my polls/views.py I have the relevant function: def randomTest1(request): # mainText = request.POST['mainText'] return HttpResponse("Default random test") However I keep on getting the following error message: Page not found (404) Request Method: GET Request URL: http://mydjango.yafz.org/polls/randomTest1 Using the URLconf defined in mydjango.urls, Django tried these URL patterns, in this order: 1. ^$ 2. ^polls/$ 3. ^polls/(?P<poll_id>\d+)/$ 4. ^polls/(?P<poll_id>\d+)/results/$ 5. ^polls/(?P<poll_id>\d+)/vote/$ 6. ^admin/ 7. ^polls/randomTest/$ The current URL, polls/randomTest1, didn't match any of these. I'm surprised because again and again I check urls.py and there is no ^polls/randomTest/$ in it, but there is ^polls/randomTest1/' It seems like Django is somehow storing the previous contents of urls.py and I just don't know how to make my latest changes effective. Any ideas? Why do I keep on seeing some old version of regexes when I try to load that page even though I changed my urls.py?

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• force delete row on django app after migration

  - by unsorted

  After a migration with south, I ended up deleting a column. Now the current data in one of my tables is screwed up and I want to delete it, but attempts to delete just result in an error: >>> d = Degree.objects.all() >>> d.delete() Traceback (most recent call last): File "<console>", line 1, in <module> File "C:\Python26\lib\site-packages\django\db\models\query.py", line 440, in d elete for i, obj in izip(xrange(CHUNK_SIZE), del_itr): File "C:\Python26\lib\site-packages\django\db\models\query.py", line 106, in _ result_iter self._fill_cache() File "C:\Python26\lib\site-packages\django\db\models\query.py", line 760, in _ fill_cache self._result_cache.append(self._iter.next()) File "C:\Python26\lib\site-packages\django\db\models\query.py", line 269, in i terator for row in compiler.results_iter(): File "C:\Python26\lib\site-packages\django\db\models\sql\compiler.py", line 67 2, in results_iter for rows in self.execute_sql(MULTI): File "C:\Python26\lib\site-packages\django\db\models\sql\compiler.py", line 72 7, in execute_sql cursor.execute(sql, params) File "C:\Python26\lib\site-packages\django\db\backends\util.py", line 15, in e xecute return self.cursor.execute(sql, params) File "C:\Python26\lib\site-packages\django\db\backends\sqlite3\base.py", line 200, in execute return Database.Cursor.execute(self, query, params) DatabaseError: no such column: students_degree.abbrev >>> Is there a simple way to just force a delete? Do I drop the table and then rerun manage.py schemamigration to recreate the table in south?

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• 2-step user registration with Django

  - by David S

  I'm creating a website with Django and want a fairly common 2-step user registration. What I mean by this is that the user fills in the some basic user information + some application specific information (sort of like a coupon value). Upon submit, an email is sent to ensure email address is valid. This email should contain a link to click on to "finish" the registration. When the link is clicked, the user is marked as validated and they are directed to a new page to complete optional "user profile" type information. So, pretty basic stuff. I have done some research and found django-registration by James Bennett. I do know who James is and have seen him at PyCons and DjanoCons in the past. There is obviously very few people in the world that know Django better than James (so, I know the quality of the code/app is good). But, it almost seems like a bit of over kill. I've read through the docs and was a bit confused (maybe I'm just being a bit dense today). I believe that if I do use django-registration, I will need to have some custom forms, etc. Is there anything else out there I should evaluate? Or are there any good tutorials or videos on using django-registration? I've done a bit of googling, but haven't found anything. But, I suspect that it might be a case of a lot of very common words that don't really find what you are looking for (django user registration tutorial/example). Or is just a case where it would be just about as easy to build your own solution with Django forms, etc? Here is the tech stack I'm using: Python 2.7.2 Django 1.3.1 PostgreSQL 9.1 psycopg2 2.4.1 Twitter Bootstrap 2.0.2

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• error in implementing static files in django

  - by POOJA GUPTA

  my settings.py file:- STATIC_ROOT = '/home/pooja/Desktop/static/' # URL prefix for static files. STATIC_URL = '/static/' # Additional locations of static files STATICFILES_DIRS = ( '/home/pooja/Desktop/mysite/search/static', ) my urls.py file:- from django.conf.urls import patterns, include, url from django.contrib.staticfiles.urls import staticfiles_urlpatterns from django.contrib import admin admin.autodiscover() urlpatterns = patterns('', url(r'^search/$','search.views.front_page'), url(r'^admin/', include(admin.site.urls)), ) urlpatterns += staticfiles_urlpatterns() I have created an app using django which seraches the keywords in 10 xml documents and then return their frequency count displayed as graphical representation and list of filenames and their respective counts.Now the list has filenames hyperlinked, I want to display them on the django server when user clicks them , for that I have used static files provision in django. Hyperlinking has been done in this manner: <ul> {% for l in list1 %} <li><a href="{{STATIC_URL}}static/{{l.file_name}}">{{l.file_name}}</a{{l.frequency_count</li> {% endfor %} </ul> Now when I run my app on the server, everything is running fine but as soon as I click on the filename, it gives me this error : Using the URLconf defined in mysite.urls, Django tried these URL patterns, in this order: ^search/$ ^admin/ ^static\/(?P<path>.*)$ The current URL, search/static/books.xml, didn't match any of these. I don't know why this error is coming, because I have followed the steps required to achieve this. I have posted my urls.py file and it is showing error in that only. I'm new to django , so Please help

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• Windows 7 - Non Admin run as Admin for Explorer - still can't see all tmp internet files

  - by Steve

  I'm trying to retrieve video files from the IE 8 cache for a user that's not an admin in Win 7. As a non admin user, I run Explorer as admin and still can't see the temp internet files for the non admin user. Only if I login as a user that is admin can I see the files. Is there any way I can see the files w/o having to go through the login process? Essentially, I want the video file from this page and others like it: http://video.yahoo.com/watch/111585/1027823

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• Foreign keys in django admin list display

  - by Olivier

  If a django model contains a foreign key field, and if that field is shown in list mode, then it shows up as text, instead of displaying a link to the foreign object. Is it possible to automatically display all foreign keys as links instead of flat text? (of course it is possible to do that on a field by field basis, but is there a general method?) Example: class Author(models.Model): ... class Post(models.Model): author = models.ForeignKey(Author) Now I choose a ModelAdmin such that the author shows up in list mode: class PostAdmin(admin.ModelAdmin): list_display = [..., 'author',...] Now in list mode, the author field will just use the __unicode__ method of the Author class to display the author. On the top of that I would like a link pointing to the url of the corresponding author in the admin site. Is that possible? Manual method: For the sake of completeness, I add the manual method. It would be to add a method author_link in the PostAdmin class: def author_link(self, item): return '<a href="../some/path/%d">%s</a>' % (item.id, unicode(item)) author_link.allow_tags = True That will work for that particular field but that is not what I want. I want a general method to achieve the same effect. (One of the problems is how to figure out automatically the path to an object in the django admin site.)

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• django internationalization doesn't work

  - by xRobot

  I have: * created translation strings in the template and in the application view. * run this command: django-admin.py makemessages -l it and the file it/LC_MESSAGES/django.po has been created * translated strings in the django.po file. * run this command: django-admin.py compilemessages and I receive: processing file django.po in /home/jobber/Desktop/library/books/locale/it/LC_MESSAGES * set this in settings.py: LANGUAGE_CODE = 'it' TEMPLATE_CONTEXT_PROCESSORS = ( "django.core.context_processors.auth", "django.core.context_processors.debug", "django.core.context_processors.i18n", "django.core.context_processors.media", ) USE_I18N = True MIDDLEWARE_CLASSES = ( 'django.middleware.common.CommonMiddleware', 'django.middleware.locale.LocaleMiddleware', 'django.contrib.sessions.middleware.SessionMiddleware', 'django.contrib.auth.middleware.AuthenticationMiddleware', ) but.... translation doesn't work !! I always see english text. Why ?

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• Admin interface in Rails

  - by yuval

  I have an admin controller located in controllers/admin/admin_controller.rb I also have a pages controller located in controllers/admin/pages_controller.rb pages_controller.rb inherits from admin_controller.rb in routes.rb, I have an admin namespace as such: map.namespace :admin do |admin| admin.resources :pages end I want the admin have basic CRUD functionality in pages_controller.rb (I know how to do that) I want the index and show methods to be available to front-end users I would like the show and index actions to use separate views, but the same code. Questions: Should I create a new pages_controller for the front-end, or share the methods index and show? If share, how would I display separate views depending on whether the url is /admin/pages or /pages If share, should I place pages_controller in /controllers/admin (where it is now) or just in /controllers? Thank you very much.

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• Django ValueError at /admin/

  - by mjaz

  Hello, I am running Django with mod_python on a Red Hat Linux box in production. A little while ago, for a reason unknown to me, the admin stopped working, throwing a 500 error. The error is as follows: ValueError at /admin/ Empty module name Request Method: GET Exception Type: ValueError Exception Value: Empty module name Exception Location: /usr/local/lib/python2.6/site-packages/django/utils/importlib.py in import_module, line 35 Python Executable: /usr/bin/python Python Version: 2.6.2 Has anyone encountered this before? I have absolutely no idea how to fix this problem. Thank you for any help.

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• Setting a preferred item of a many-to-one in Django

  - by Mike DeSimone

  I'm trying to create a Django model that handles the following: An Item can have several Names. One of the Names for an Item is its primary Name, i.e. the Name displayed given an Item. (The model names were changed to protect the innocent.) The models.py I've got looks like: class Item(models.Model): primaryName = models.OneToOneField("Name", verbose_name="Primary Name", related_name="_unused") def __unicode__(self): return self.primaryName.name class Name(models.Model): item = models.ForeignKey(Item) name = models.CharField(max_length=32, unique=True) def __unicode__(self): return self.name class Meta: ordering = [ 'name' ] The admin.py looks like: class NameInline(admin.TabularInline): model = Name class ItemAdmin(admin.ModelAdmin): inlines = [ NameInline ] admin.site.register(Item, ItemAdmin) It looks like the database schema is working fine, but I'm having trouble with the admin, so I'm not sure of anything at this point. My main questions are: How do I explain to the admin that primaryName needs to be one of the Names of the item being edited? Is there a way to automatically set primaryName to the first Name found, if primaryName is not set, since I'm using inline admin for the names?

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• Programmatically specifying Django model attributes

  - by mojbro

  Hi! I would like to add attributes to a Django models programmatically, at run time. For instance, lets say I have a Car model class and want to add one price attribute (database column) per currency, given a list of currencies. What is the best way to do this? I had an approach that I thought would work, but it didn't exactly. This is how I tried doing it, using the car example above: from django.db import models class Car(models.Model): name = models.CharField(max_length=50) currencies = ['EUR', 'USD'] for currency in currencies: Car.add_to_class('price_%s' % currency.lower(), models.IntegerField()) This does seem to work pretty well at first sight: $ ./manage.py syncdb Creating table shop_car $ ./manage.py dbshell shop=# \d shop_car Table "public.shop_car" Column | Type | Modifiers -----------+-----------------------+------------------------------------------------------- id | integer | not null default nextval('shop_car_id_seq'::regclass) name | character varying(50) | not null price_eur | integer | not null price_usd | integer | not null Indexes: "shop_car_pkey" PRIMARY KEY, btree (id) But when I try to create a new Car, it doesn't really work anymore: >>> from shop.models import Car >>> mycar = Car(name='VW Jetta', price_eur=100, price_usd=130) >>> mycar <Car: Car object> >>> mycar.save() Traceback (most recent call last): File "<console>", line 1, in <module> File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/django/db/models/base.py", line 410, in save self.save_base(force_insert=force_insert, force_update=force_update) File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/django/db/models/base.py", line 495, in save_base result = manager._insert(values, return_id=update_pk) File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/django/db/models/manager.py", line 177, in _insert return insert_query(self.model, values, **kwargs) File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/django/db/models/query.py", line 1087, in insert_query return query.execute_sql(return_id) File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/django/db/models/sql/subqueries.py", line 320, in execute_sql cursor = super(InsertQuery, self).execute_sql(None) File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/django/db/models/sql/query.py", line 2369, in execute_sql cursor.execute(sql, params) File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/django/db/backends/util.py", line 19, in execute return self.cursor.execute(sql, params) ProgrammingError: column "price_eur" specified more than once LINE 1: ...NTO "shop_car" ("name", "price_eur", "price_usd", "price_eur... ^

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• Django: CharField with fixed length, how?

  - by Giovanni Di Milia

  Hi everybody, I wold like to have in my model a CharField with fixed length. In other words I want that only a specified length is valid. I tried to do something like volumenumber = models.CharField('Volume Number', max_length=4, min_length=4) but it gives me an error (it seems that I can use both max_length and min_length at the same time). Is there another quick way? Thanks EDIT: Following the suggestions of some people I will be a bit more specific: My model is this: class Volume(models.Model): vid = models.AutoField(primary_key=True) jid = models.ForeignKey(Journals, db_column='jid', null=True, verbose_name = "Journal") volumenumber = models.CharField('Volume Number') date_publication = models.CharField('Date of Publication', max_length=6, blank=True) class Meta: db_table = u'volume' verbose_name = "Volume" ordering = ['jid', 'volumenumber'] unique_together = ('jid', 'volumenumber') def __unicode__(self): return (str(self.jid) + ' - ' + str(self.volumenumber)) What I want is that the volumenumber must be exactly 4 characters. I.E. if someone insert '4b' django gives an error because it expects a string of 4 characters. So I tried with volumenumber = models.CharField('Volume Number', max_length=4, min_length=4) but it gives me this error: Validating models... Unhandled exception in thread started by <function inner_run at 0x70feb0> Traceback (most recent call last): File "/Library/Python/2.5/site-packages/django/core/management/commands/runserver.py", line 48, in inner_run self.validate(display_num_errors=True) File "/Library/Python/2.5/site-packages/django/core/management/base.py", line 249, in validate num_errors = get_validation_errors(s, app) File "/Library/Python/2.5/site-packages/django/core/management/validation.py", line 28, in get_validation_errors for (app_name, error) in get_app_errors().items(): File "/Library/Python/2.5/site-packages/django/db/models/loading.py", line 131, in get_app_errors self._populate() File "/Library/Python/2.5/site-packages/django/db/models/loading.py", line 58, in _populate self.load_app(app_name, True) File "/Library/Python/2.5/site-packages/django/db/models/loading.py", line 74, in load_app models = import_module('.models', app_name) File "/Library/Python/2.5/site-packages/django/utils/importlib.py", line 35, in import_module __import__(name) File "/Users/Giovanni/src/djangoTestSite/../djangoTestSite/journaldb/models.py", line 120, in <module> class Volume(models.Model): File "/Users/Giovanni/src/djangoTestSite/../djangoTestSite/journaldb/models.py", line 123, in Volume volumenumber = models.CharField('Volume Number', max_length=4, min_length=4) TypeError: __init__() got an unexpected keyword argument 'min_length' That obviously doesn't appear if I use only "max_length" OR "min_length". I read the documentation on the django web site and it seems that I'm right (I cannot use both together) so I'm asking if there is another way to solve the problem. Thanks again

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