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  • Detect the language & django locale-url

    - by mamcx
    I want to deploy a website in english & spanish and detect the user browser languaje & redirect to the correct locale site. My site is www.elmalabarista.com I install django-localeurl, but I discover that the languaje is not correctly detected. This are my middlewares: MIDDLEWARE_CLASSES = ( 'django.contrib.sessions.middleware.SessionMiddleware', 'django.middleware.locale.LocaleMiddleware', 'multilingual.middleware.DefaultLanguageMiddleware', 'middleware.feedburner.FeedburnerMiddleware', 'lib.threadlocals.ThreadLocalsMiddleware', 'middleware.url.UrlMiddleware', 'django.contrib.auth.middleware.AuthenticationMiddleware', 'maintenancemode.middleware.MaintenanceModeMiddleware', 'middleware.redirect.RedirectMiddleware', 'openidconsumer.middleware.OpenIDMiddleware', 'django.middleware.doc.XViewMiddleware', 'middleware.ajax_errors.AjaxMiddleware', 'pingback.middleware.PingbackMiddleware', 'localeurl.middleware.LocaleURLMiddleware', 'multilingual.flatpages.middleware.FlatpageFallbackMiddleware', 'django.middleware.common.CommonMiddleware', ) But ALWAYS the site get to US despite the fact my OS & Browser setup is spanish. LANGUAGES = ( ('en', ugettext('English')), ('es', ugettext('Spanish')), ) DEFAULT_LANGUAGE = 1 Then, I hack the middleware of locale-url and do this: def process_request(self, request): locale, path = self.split_locale_from_request(request) if request.META.has_key('HTTP_ACCEPT_LANGUAGE'): locale = utils.supported_language(request.META['HTTP_ACCEPT_LANGUAGE'].split(',')[0]) locale_path = utils.locale_path(path, locale) if locale_path != request.path_info: if request.META.get("QUERY_STRING", ""): locale_path = "%s?%s" % (locale_path, request.META['QUERY_STRING']) return HttpResponseRedirect(locale_path) request.path_info = path if not locale: locale = settings.LANGUAGE_CODE translation.activate(locale) request.LANGUAGE_CODE = translation.get_language() However, this detect fine the language but redirect the "en" urls to "es". So is impossible navigate in english. UPDATE: This is the final code (after the input from Carl Meyer) with a fix for the case of "/": def process_request(self, request): locale, path = self.split_locale_from_request(request) if (not locale) or (locale==''): if request.META.has_key('HTTP_ACCEPT_LANGUAGE'): locale = utils.supported_language(request.META['HTTP_ACCEPT_LANGUAGE'].split(',')[0]) else: locale = settings.LANGUAGE_CODE locale_path = utils.locale_path(path, locale) if locale_path != request.path_info: if request.META.get("QUERY_STRING", ""): locale_path = "%s?%s" % (locale_path, request.META['QUERY_STRING']) return HttpResponseRedirect(locale_path) request.path_info = path translation.activate(locale) request.LANGUAGE_CODE = translation.get_language()

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  • UnicodeDecodeError on attempt to save file through django default filebased backend

    - by Ivan Kuznetsov
    When i attempt to add a file with russian symbols in name to the model instance through default instance.file_field.save method, i get an UnicodeDecodeError (ascii decoding error, not in range (128) from the storage backend (stacktrace ended on os.exist). If i write this file through default python file open/write all goes right. All filenames in utf-8. I get this error only on testing Gentoo, on my Ubuntu workstation all works fine. class Article(models.Model): file = models.FileField(null=True, blank=True, max_length = 300, upload_to='articles_files/%Y/%m/%d/') Traceback: File "/usr/lib/python2.6/site-packages/django/core/handlers/base.py" in get_response 100. response = callback(request, *callback_args, **callback_kwargs) File "/usr/lib/python2.6/site-packages/django/contrib/auth/decorators.py" in _wrapped_view 24. return view_func(request, *args, **kwargs) File "/var/www/localhost/help/wiki/views.py" in edit_article 338. new_article.file.save(fp, fi, save=True) File "/usr/lib/python2.6/site-packages/django/db/models/fields/files.py" in save 92. self.name = self.storage.save(name, content) File "/usr/lib/python2.6/site-packages/django/core/files/storage.py" in save 47. name = self.get_available_name(name) File "/usr/lib/python2.6/site-packages/django/core/files/storage.py" in get_available_name 73. while self.exists(name): File "/usr/lib/python2.6/site-packages/django/core/files/storage.py" in exists 196. return os.path.exists(self.path(name)) File "/usr/lib/python2.6/genericpath.py" in exists 18. st = os.stat(path) Exception Type: UnicodeEncodeError at /edit/ Exception Value: ('ascii', u'/var/www/localhost/help/i/articles_files/2010/03/17/\u041f\u0440\u0438\u0432\u0435\u0442', 52, 58, 'ordinal not in range(128)')

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  • force users to activate account before using service?

    - by fxuser
    i am not sure if this is the correct SE site to post this, but ill go on... So at the moment i force my users to activate their account upon registration if they want to sign in. I see some decent sites let their users sign in and use their features even their account is not activated and just show a message on top of the page letting them know that their account is not yet activated and that you need to activate it. So which practice is best? Should i stick with that i have or change it?

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  • How to get useful feedback/bug reports from users

    - by Mikael Eliasson
    I'm sure most webmasters have recived a mail like this: Creating [insert item here] is not working! When you check it out there is no general problem with the function but rather the user has discovered an edge case. Almost every mail I get is like this and in the long run it gets a bit annoying to always have to ask the user for more information. Is there anything I can do to get my users provide more useful feedback? Right now I have a mailto: for the webmaster mail in the page footer. I was thinking of changing this so that they have to report through a form on the site. Anyone got any experience with this? Do you get better/more reports by having a feedback form instead of giving the users the email?

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  • Django facebook integration error

    - by Gaurav
    I'm trying to integrate facebook into my application so that users can use their FB login to login to my site. I've got everything up and running and there are no issues when I run my site using the command line python manage.py runserver But this same code refuses to run when I try and run it through Apache. I get the following error: Environment: Request Method: GET Request URL: http://helvetica/foodfolio/login Django Version: 1.1.1 Python Version: 2.6.4 Installed Applications: ['django.contrib.auth', 'django.contrib.contenttypes', 'django.contrib.sessions', 'django.contrib.sites', 'foodfolio.app', 'foodfolio.facebookconnect'] Installed Middleware: ('django.contrib.sessions.middleware.SessionMiddleware', 'facebook.djangofb.FacebookMiddleware', 'django.middleware.common.CommonMiddleware', 'django.contrib.auth.middleware.AuthenticationMiddleware', 'facebookconnect.middleware.FacebookConnectMiddleware') Template error: In template /home/swat/website-apps/foodfolio/facebookconnect/templates/facebook/js.html, error at line 2 Caught an exception while rendering: No module named app.models 1 : <script type="text/javascript"> 2 : FB_RequireFeatures(["XFBML"], function() {FB.Facebook.init("{{ facebook_api_key }}", " {% url facebook_xd_receiver %} ")}); 3 : 4 : function facebookConnect(loginForm) { 5 : FB.Connect.requireSession(); 6 : FB.Facebook.get_sessionState().waitUntilReady(function(){loginForm.submit();}); 7 : } 8 : function pushToFacebookFeed(data){ 9 : if(data['success']){ 10 : var template_data = data['template_data']; 11 : var template_bundle_id = data['template_bundle_id']; 12 : feedTheFacebook(template_data,template_bundle_id,function(){}); Traceback: File "/usr/lib/pymodules/python2.6/django/core/handlers/base.py" in get_response 92. response = callback(request, *callback_args, **callback_kwargs) File "/home/swat/website-apps/foodfolio/app/controller.py" in __showLogin__ 238. context_instance = RequestContext(request)) File "/usr/lib/pymodules/python2.6/django/shortcuts/__init__.py" in render_to_response 20. return HttpResponse(loader.render_to_string(*args, **kwargs), **httpresponse_kwargs) File "/usr/lib/pymodules/python2.6/django/template/loader.py" in render_to_string 108. return t.render(context_instance) File "/usr/lib/pymodules/python2.6/django/template/__init__.py" in render 178. return self.nodelist.render(context) File "/usr/lib/pymodules/python2.6/django/template/__init__.py" in render 779. bits.append(self.render_node(node, context)) File "/usr/lib/pymodules/python2.6/django/template/debug.py" in render_node 71. result = node.render(context) File "/usr/lib/pymodules/python2.6/django/template/__init__.py" in render 946. autoescape=context.autoescape)) File "/usr/lib/pymodules/python2.6/django/template/__init__.py" in render 779. bits.append(self.render_node(node, context)) File "/usr/lib/pymodules/python2.6/django/template/debug.py" in render_node 81. raise wrapped Exception Type: TemplateSyntaxError at /foodfolio/login Exception Value: Caught an exception while rendering: No module named app.models

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  • Javascript error when integrating django-tinymce and django-filebrowser

    - by jwesonga
    I've set up django-filebrowser in my app without any bugs, I already had django-tinymce set up and it loads the editor in the admin forms. I now want to use django-filebrowser with django-tinymce, but I keep getting a weird javascript error when I click on "Image URL" in the Image popup: r is undefined the error is js/tiny_mce/tiny_mce.js My settings.py file has the following configuration: TINYMCE_JS_URL=MEDIA_URL + 'js/tiny_mce/tiny_mce.js' TINYMCE_DEFAULT_CONFIG = { 'mode': "textareas", 'theme': "advanced", 'language': "en", 'skin': "o2k7", 'dialog_type': "modal", 'object_resizing': True, 'cleanup_on_startup': True, 'forced_root_block': "p", 'remove_trailing_nbsp': True, 'theme_advanced_toolbar_location': "top", 'theme_advanced_toolbar_align': "left", 'theme_advanced_statusbar_location': "none", 'theme_advanced_buttons1': "formatselect,styleselect,bold,italic,underline,bullist,numlist,undo,redo,link,unlink,image,code,template,visualchars,fullscreen,pasteword,media,search,replace,charmap", 'theme_advanced_buttons2': "", 'theme_advanced_buttons3': "", 'theme_advanced_path': False, 'theme_advanced_blockformats': "p,h2,h3,h4,div,code,pre", 'width': '700', 'height': '300', 'plugins': "advimage,advlink,fullscreen,visualchars,paste,media,template,searchreplace", 'advimage_update_dimensions_onchange': True, 'file_browser_callback': "CustomFileBrowser", 'relative_urls': False, 'valid_elements' : "" + "-p," + "a[href|target=_blank|class]," + "-strong/-b," + "-em/-i," + "-u," + "-ol," + "-ul," + "-li," + "br," + "img[class|src|alt=|width|height]," + "-h2,-h3,-h4," + "-pre," + "-code," + "-div", 'extended_valid_elements': "" + "a[name|class|href|target|title|onclick]," + "img[class|src|border=0|alt|title|hspace|vspace|width|height|align|onmouseover|onmouseout|name]," + "br[clearfix]," + "-p[class<clearfix?summary?code]," + "h2[class<clearfix],h3[class<clearfix],h4[class<clearfix]," + "ul[class<clearfix],ol[class<clearfix]," + "div[class]," } TINYMCE_FILEBROWSER = False TINYMCE_COMPRESSOR = False i've tried switching back to older versions of tinyMCE Javascript but nothing seems to work. Would appreciate some help

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  • While trying to set up Django on Windows: AttributeError: 'Settings' object has no attribute 'DATABA

    - by user326370
    I'm following these instructions in order to set up Django on Windows. I have installed Python 2.6, PostgreSQL 8.4, Psycopg 2.0.14 for Python 2.6 and the latest version of Django from SVN. I'm now following these instructions to run a test project (copied from the page linked to above): C:\Documents and Settings\John>cd C:\ C:\>mkdir django C:\>cd django C:\django>django-admin.py startproject testproject C:\django>cd testproject C:\django\testproject>python manage.py runserver When I run the last line, this is the output: Validating models... Unhandled exception in thread started by <function inner_run at 0x01ECB930> Traceback (most recent call last): File "J:\Python26\lib\site-packages\django\core\management\commands\runserver.py", line 48, in inn er_run self.validate(display_num_errors=True) File "J:\Python26\lib\site-packages\django\core\management\base.py", line 249, in validate num_errors = get_validation_errors(s, app) File "J:\Python26\lib\site-packages\django\core\management\validation.py", line 22, in get_validat ion_errors from django.db import models, connection File "J:\Python26\lib\site-packages\django\db\__init__.py", line 14, in <module> if not settings.DATABASES: File "J:\Python26\lib\site-packages\django\utils\functional.py", line 273, in __getattr__ return getattr(self._wrapped, name) AttributeError: 'Settings' object has no attribute 'DATABASES' Did I forget to do something with the database? Any help will be appreciated. Thank you!

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  • How to do custom display and auto-select in django admin multi-select field?

    - by rsp
    I'm new to django, so please feel free to tell me if I'm doing this incorrectly. I am trying to create a django ordering system. My order model: class Order(models.Model): ordered_by = models.ForeignKey(User, limit_choices_to = {'groups__name': "Managers", 'is_active': 1}) in my admin ANY user can enter an order, but ordered_by must be someone in the group "managers" (this is the behavior I want). Now, if the logged in user happens to be a manager I want it to automatically fill in the field with that logged in user. I have accomplished this by: class OrderAdmin(admin.ModelAdmin): def formfield_for_foreignkey(self, db_field, request, **kwargs): if db_field.name == "ordered_by": if request.user in User.objects.filter(groups__name='Managers', is_active=1): kwargs["initial"] = request.user.id kwargs["empty_label"] = "-------------" return db_field.formfield(**kwargs) return super(OrderAdmin, self).formfield_for_foreignkey(db_field, request, **kwargs) This also works, but the admin puts the username as the display for the select box by default. It would be nice to have the user's real name listed. I was able to do it with this: class UserModelMultipleChoiceField(forms.ModelMultipleChoiceField): def label_from_instance(self, obj): return obj.first_name + " " + obj.last_name class OrderForm(forms.ModelForm): ordered_by = UserModelChoiceField(queryset=User.objects.all().filter(groups__name='Managers', is_active=1)) class OrderAdmin(admin.ModelAdmin): form = OrderForm My problem: I can't to both of these. If I put in the formfield_for_foreignkey function and add form = OrderForm to use my custom "UserModelChoiceField", it puts the nice name display but it won't select the currently logged in user. I'm new to this, but my guess is that when I use UserModelChoiceField it "erases" the info passed in via formfield_for_foreignkey. Do I need to use the super() function somehow to pass on this info? or something completely different?

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  • Django: Filtering datetime field by *only* the year value?

    - by unclaimedbaggage
    Hi folks, I'm trying to spit out a django page which lists all entries by the year they were created. So, for example: 2010: Note 4 Note 5 Note 6 2009: Note 1 Note 2 Note 3 It's proving more difficult than I would have expected. The model from which the data comes is below: class Note(models.Model): business = models.ForeignKey(Business) note = models.TextField() created = models.DateTimeField(auto_now_add=True) updated = models.DateTimeField(auto_now=True) class Meta: db_table = 'client_note' @property def note_year(self): return self.created.strftime('%Y') def __unicode__(self): return '%s' % self.note I've tried a few different ways, but seem to run into hurdles down every path. I'm guessing an effective 'group by' method would do the trick (PostGres DB Backend), but I can't seem to find any Django functionality that supports it. I tried getting individual years from the database but I struggled to find a way of filtering datetime fields by just the year value. Finally, I tried adding the note_year @property but because it's derived, I can't filter those values. Any suggestions for an elegant way to do this? I figure it should be pretty straightforward, but I'm having a heckuva time with it. Any ideas much appreciated.

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  • Methodologies for Managing Users and Access?

    - by MadBurn
    This is something I'm having a hard time getting my head around. I think I might be making it more complicated than it is. What I'm trying to do is develop a method to store users in a database with varying levels of access, throughout different applications. I know this has been done before, but I don't know where to find how they did it. Here is an example of what I need to accomplish: UserA - Access to App1, App3, App4 & can add new users to App3, but not 4 or 1. UserB - Access to App2 only with ReadOnly access. UserC - Access to App1 & App4 and is able to access Admin settings of both apps. In the past I've just used user groups. However, I'm reaching a phase where I need a bit more control over each individual user's access to certain parts of the different applications. I wish this were as cut and dry as being able to give a user a role and let each role inherit from the last. Now, this is what I need to accomplish. But, I don't know any methods of doing this. I could easily just design something that works, but I know this has been done and I know this has been studied and I know this problem has been solved by much better minds than my own. This is for a web application and using sql server 2008. I don't need to store passwords (LDAP) and the information I need to store is actually very limited. Basically just username and access.

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  • Joomla Secondary Users

    - by Gaz_Edge
    Background I have a joomla based application. My customers sign up and they register as a user on the site. My customers (primary customers) then have their own space on the site that they can then setup their own customers (secondary customer). Question/Problem The problem I am having is that I need to tag each secondary customer to a primary customer. I thought about just creating a new component and having a separate table that includes all the secondary customers. The problem is that I then lose out on all the authentication, session handling and login/logout that the core joomla _users component offers. I then thought about just having all the users in the core _users table and add the primary customer associated with each secondary customer to a field in a profile plugin. This would work for the most part, but this means that primary customers cannot create a secondary customer with a user name that already exists in the _users table. I didn't think this would be an issue, but several of my primary customers (currently only test users) have been confused by the site telling them a username is not available, since they can only see the names of their own secondary customers. Any ideas on some architectural changes I could make to solve this?

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  • How much knowledge do I need to begin a project in Django

    - by Smock
    I started learning django about a month ago. I have an intermediate C, Java programming experience. I read the first 8 chapters of the django book . Afterwards, I picked up Practical Django Projects by James Bennett and did the first two projects: CMS & Web Blog. Although, I started getting lost when he got to the generic views part. I know that's important but I'm not sure how important that is when trying to implement a project. Anyway, I have a project in mind that I'd like to start; however, I'm nervous as to where to begin. I'm overwhelmed with the number of things that I'd like my project to do but no knowledge or minimal knowledge as to how e.g. how do i implement css and javascript in my project. Moreover, I am aware that some django packages exists to ease development but I don't know if I should use them or not. Anyway, I apologize for my length message. I just want some advice/encouragement. I have a project in mind but do you think I need to read more materials/tutorials or is it smart to just start working on my project based on the minimal knowledge i've gained from those books? Any information that can be provided is much appreciated. I really want to get good at this but I just need some direction.

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  • Single django instance with subdomains for each app in the django project

    - by jwesonga
    I have a django project (django+apache+mod_wsgi+nginx) with multiple apps, I'd like to map each app as a subdomain: project/ app1 (domain.com) app2 (sub1.domain.com) app3 (sub3.domain.com) I have a single .wsgi script serving the project, which is stored in a folder /apache. Below is my vhost file. I'm using a single vhost file instead of separate ones for each sub-domain: <VirtualHost *:8080> ServerAdmin [email protected] ServerName www.domain.com ServerAlias domain.com DocumentRoot /home/path/to/app/ Alias /admin_media/ /usr/local/lib/python2.6/dist-packages/django/contrib/admin/media <Directory /home/path/to/wsgi/apache/> Order deny,allow Allow from all </Directory> LogLevel warn ErrorLog /home/path/to/logs/apache_error.log CustomLog /home/path/to/logs/apache_access.log combined WSGIDaemonProcess domain.com user=www-data group=www-data threads=25 WSGIProcessGroup domain.com WSGIScriptAlias / /home/path/to/apache/kcdf.wsgi </VirtualHost> <VirtualHost *:8081> ServerAdmin [email protected] ServerName sub1.domain.com ServerAlias sub1.domain.com DocumentRoot /home/path/to/app Alias /admin_media/ /usr/local/lib/python2.6/dist-packages/django/contrib/admin/media <Directory /home/path/to/wsgi/apache/> Order deny,allow Allow from all </Directory> LogLevel warn ErrorLog /home/path/to/logs/apache_error.log CustomLog /home/path/to/logs/apache_access.log combined WSGIDaemonProcess sub1.domain.com user=www-data group=www-data threads=25 WSGIProcessGroup sub1.domain.com WSGIScriptAlias / /home/path/to/apache/kcdf.wsgi </VirtualHost> My Nginx configuration for the domain.com: server { listen 80; server_name domain.com; access_log off; error_log off; # proxy to Apache 2 and mod_wsgi location / { proxy_pass http://127.0.0.1:8080/; proxy_redirect off; proxy_set_header Host $host; proxy_set_header X-Real-IP $remote_addr; proxy_set_header X-Forwarded-For $proxy_add_x_forwarded_for; proxy_max_temp_file_size 0; client_max_body_size 10m; client_body_buffer_size 128k; proxy_connect_timeout 90; proxy_send_timeout 90; proxy_read_timeout 90; proxy_buffer_size 4k; proxy_buffers 4 32k; proxy_busy_buffers_size 64k; proxy_temp_file_write_size 64k; } } Configuration for the sub.domain.com: server { listen 80; server_name sub.domain.com; access_log off; error_log off; # proxy to Apache 2 and mod_wsgi location / { proxy_pass http://127.0.0.1:8081/; proxy_redirect off; proxy_set_header Host $host; proxy_set_header X-Real-IP $remote_addr; proxy_set_header X-Forwarded-For $proxy_add_x_forwarded_for; proxy_max_temp_file_size 0; client_max_body_size 10m; client_body_buffer_size 128k; proxy_connect_timeout 90; proxy_send_timeout 90; proxy_read_timeout 90; proxy_buffer_size 4k; proxy_buffers 4 32k; proxy_busy_buffers_size 64k; proxy_temp_file_write_size 64k; } } This set up doesn't seem to work, everything seems to point to the main domain. I've tried http://effbot.org/zone/django-multihost.htm which kind of worked but seems to have issues with loading my css,images,js files.

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  • In Django Combobox choices, how do you lookup description from short value?

    - by MikeN
    In Django models/forms the choices for a combobox often look like this: food_choices = (("",""), ("1", "Falafel"), ("2", "Hummus"), ("3", "Eggplant Stuff, Babaganoush???"), So the value to be stored in the database will be 1/2/3, but the displayed value on the form will be the long description. When we are working in code outside a form, how can we quickly lookup the long description given the short value stored in the model? So I want to map short values to long values: print foo("1") "Falafel"

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  • Do Django Models inherit managers? (Mine seem not to)

    - by Zach
    I have 2 models: class A(Model): #Some Fields objects = ClassAManager() class B(A): #Some B-specific fields I would expect B.objects to give me access to an instance of ClassAManager, but this is not the case.... >>> A.objects <app.managers.ClassAManager object at 0x103f8f290> >>> B.objects <django.db.models.manager.Manager object at 0x103f94790> Why doesn't B inherit the objects attribute from A?

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  • South migration error: NoMigrations exception for django.contrib.auth

    - by danpalmer
    I have been using South on my project for a while, but I recently did a huge amount of development and changed development machine and I think something messed up in the process. The project works fine, but I can't apply migrations. Whenever I try to apply a migration I get the following traceback: danpalmer:pest Dan$ python manage.py migrate frontend Traceback (most recent call last): File "manage.py", line 11, in <module> execute_manager(settings) File "/Library/Python/2.6/site-packages/django/core/management/__init__.py", line 362, in execute_manager utility.execute() File "/Library/Python/2.6/site-packages/django/core/management/__init__.py", line 303, in execute self.fetch_command(subcommand).run_from_argv(self.argv) File "/Library/Python/2.6/site-packages/django/core/management/base.py", line 195, in run_from_argv self.execute(*args, **options.__dict__) File "/Library/Python/2.6/site-packages/django/core/management/base.py", line 222, in execute output = self.handle(*args, **options) File "/Library/Python/2.6/site-packages/South-0.7-py2.6.egg/south/management/commands/migrate.py", line 102, in handle delete_ghosts = delete_ghosts, File "/Library/Python/2.6/site-packages/South-0.7-py2.6.egg/south/migration/__init__.py", line 182, in migrate_app applied = check_migration_histories(applied, delete_ghosts) File "/Library/Python/2.6/site-packages/South-0.7-py2.6.egg/south/migration/__init__.py", line 85, in check_migration_histories m = h.get_migration() File "/Library/Python/2.6/site-packages/South-0.7-py2.6.egg/south/models.py", line 34, in get_migration return self.get_migrations().migration(self.migration) File "/Library/Python/2.6/site-packages/South-0.7-py2.6.egg/south/models.py", line 31, in get_migrations return Migrations(self.app_name) File "/Library/Python/2.6/site-packages/South-0.7-py2.6.egg/south/migration/base.py", line 60, in __call__ self.instances[app_label] = super(MigrationsMetaclass, self).__call__(app_label_to_app_module(app_label), **kwds) File "/Library/Python/2.6/site-packages/South-0.7-py2.6.egg/south/migration/base.py", line 88, in __init__ self.set_application(application, force_creation, verbose_creation) File "/Library/Python/2.6/site-packages/South-0.7-py2.6.egg/south/migration/base.py", line 159, in set_application raise exceptions.NoMigrations(application) south.exceptions.NoMigrations: Application '<module 'django.contrib.auth' from '/Library/Python/2.6/site-packages/django/contrib/auth/__init__.pyc'>' has no migrations. I am not that experienced with South and I haven't met this error before. The only helpful mention I can find online about this error is for pre-0.7 I think and I am on South 0.7. I ran 'easy_install -U South' just to make sure. Thanks for any help that you can provide. I really appreciate it.

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  • Django App for Image heavy Magazine Publishing?

    - by stapler
    I'm about to begin work on a Django project for an image heavy non-profit "community arts" magazine. The magazine is published monthly with about 6-8 articles that include with 4-10 images. I've been looking around for other projects that people have started specifically for publishing in Django... Are there any publishing specific Django apps you'd recommend? At the moment the only thing I can find is django-newsroom which looks interesting. Currently I'm just Image Kit / Photologue to attach galleries to an Article Model... but I'd love to figure out a way to more fully integrate images into the article content. Thanks in advance

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  • Django CMS error when running project

    - by 47
    I'd set up a site a while back using Django-CMS and it was working fine. However, after upgrading to the latest version of both Django and Django-CMS, it doesn't work anymore...when I try to run the development server, I get this message: "Signal recerivers must accept keyword arguments (**kwargs)." AssertionError: Signal receivers must accept keyword arguments (**kwargs). What could be the problem here? I've tried running the sample app that comes with the CMS and it works just fine.

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  • Why can't I use __getattr__ with Django models?

    - by Joshmaker
    I've seen examples online of people using __getattr__ with Django models, but whenever I try I get errors. (Django 1.2.3) I don't have any problems when I am using __getattr__ on normal objects. For example: class Post(object): def __getattr__(self, name): return 42 Works just fine... >>> from blog.models import Post >>> p = Post() >>> p.random 42 Now when I try it with a Django model: from django.db import models class Post(models.Model): def __getattr__(self, name): return 42 And test it on on the interpreter: >>> from blog.models import Post >>> p = Post() ERROR: An unexpected error occurred while tokenizing input The following traceback may be corrupted or invalid The error message is: ('EOF in multi-line statement', (6, 0)) --------------------------------------------------------------------------- TypeError Traceback (most recent call last) /Users/josh/project/ in () /Users/josh/project/lib/python2.6/site-packages/django/db/models/base.pyc in init(self, *args, **kwargs) 338 if kwargs: 339 raise TypeError("'%s' is an invalid keyword argument for this function" % kwargs.keys()[0]) -- 340 signals.post_init.send(sender=self.class, instance=self) 341 342 def repr(self): /Users/josh/project/lib/python2.6/site-packages/django/dispatch/dispatcher.pyc in send(self, sender, **named) 160 161 for receiver in self._live_receivers(_make_id(sender)): -- 162 response = receiver(signal=self, sender=sender, **named) 163 responses.append((receiver, response)) 164 return responses /Users/josh/project/python2.6/site-packages/photologue/models.pyc in add_methods(sender, instance, signal, *args, **kwargs) 728 """ 729 if hasattr(instance, 'add_accessor_methods'): -- 730 instance.add_accessor_methods() 731 732 # connect the add_accessor_methods function to the post_init signal TypeError: 'int' object is not callable Can someone explain what is going on? EDIT: I may have been too abstract in the examples, here is some code that is closer to what I actually would use on the website: class Post(models.Model): title = models.CharField(max_length=255) slug = models.SlugField() date_published = models.DateTimeField() content = RichTextField('Content', blank=True, null=True) # Etc... Class CuratedPost(models.Model): post = models.ForeignKey('Post') position = models.PositiveSmallIntegerField() def __getattr__(self, name): ''' If the user tries to access a property of the CuratedPost, return the property of the Post instead... ''' return self.post.name # Etc... While I could create a property for each attribute of the Post class, that would lead to a lot of code duplication. Further more, that would mean anytime I add or edit a attribute of the Post class I would have to remember to make the same change to the CuratedPost class, which seems like a recipe for code rot.

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  • Syncing data between devel/live databases in Django

    - by T. Stone
    With Django's new multi-db functionality in the development version, I've been trying to work on creating a management command that let's me synchronize the data from the live site down to a developer machine for extended testing. (Having actual data, particularly user-entered data, allows me to test a broader range of inputs.) Right now I've got a "mostly" working command. It can sync "simple" model data but the problem I'm having is that it ignores ManyToMany fields which I don't see any reason for it do so. Anyone have any ideas of either how to fix that or a better want to handle this? Should I be exporting that first query to a fixture first and then re-importing it? from django.core.management.base import LabelCommand from django.db.utils import IntegrityError from django.db import models from django.conf import settings LIVE_DATABASE_KEY = 'live' class Command(LabelCommand): help = ("Synchronizes the data between the local machine and the live server") args = "APP_NAME" label = 'application name' requires_model_validation = False can_import_settings = True def handle_label(self, label, **options): # Make sure we're running the command on a developer machine and that we've got the right settings db_settings = getattr(settings, 'DATABASES', {}) if not LIVE_DATABASE_KEY in db_settings: print 'Could not find "%s" in database settings.' % LIVE_DATABASE_KEY return if db_settings.get('default') == db_settings.get(LIVE_DATABASE_KEY): print 'Data cannot synchronize with self. This command must be run on a non-production server.' return # Fetch all models for the given app try: app = models.get_app(label) app_models = models.get_models(app) except: print "The app '%s' could not be found or models could not be loaded for it." % label for model in app_models: print 'Syncing %s.%s ...' % (model._meta.app_label, model._meta.object_name) # Query each model from the live site qs = model.objects.all().using(LIVE_DATABASE_KEY) # ...and save it to the local database for record in qs: try: record.save(using='default') except IntegrityError: # Skip as the record probably already exists pass

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  • Django internationalization for admin pages - translate model name and attributes

    - by geekQ
    Django's internationalization is very nice (gettext based, LocaleMiddleware), but what is the proper way to translate the model name and the attributes for admin pages? I did not find anything about this in the documentation: http://docs.djangoproject.com/en/dev/topics/i18n/internationalization/ http://www.djangobook.com/en/2.0/chapter19/ I would like to have "???????? ????? ??? ?????????" instead of "???????? order ??? ?????????". Note, the 'order' is not translated. First, I defined a model, activated USE_I18N = True in settings.py, run django-admin makemessages -l ru. No entries are created by default for model names and attributes. Grepping in the Django source code I found: $ ack "Select %s to change" contrib/admin/views/main.py 70: self.title = (self.is_popup and ugettext('Select %s') % force_unicode(self.opts.verbose_name) or ugettext('Select %s to change') % force_unicode(self.opts.verbose_name)) So the verbose_name meta property seems to play some role here. Tried to use it: class Order(models.Model): subject = models.CharField(max_length=150) description = models.TextField() class Meta: verbose_name = _('order') Now the updated po file contains msgid 'order' that can be translated. So I put the translation in. Unfortunately running the admin pages show the same mix of "???????? order ??? ?????????". I'm currently using Django 1.1.1. Could somebody point me to the relevant documentation? Because google can not. ;-) In the mean time I'll dig deeper into the django source code...

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