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  • What else I must do allow my method to handle any type of objects

    - by NewHelpNeeder
    So to allow any type object I must use generics in my code. I have rewrote this method to do so, but then when I create an object, for example Milk, it won't let me pass it to my method. Ether there's something wrong with my generic revision, or Milk object I created is not good. How should I pass my object correctly and add it to linked list? This is a method that causes error when I insert an item: public void insertFirst(T dd) // insert at front of list { Link newLink = new Link(dd); // make new link if( isEmpty() ) // if empty list, last = newLink; // newLink <-- last else first.previous = newLink; // newLink <-- old first newLink.next = first; // newLink --> old first first = newLink; // first --> newLink } This is my class I try to insert into linked list: class Milk { String brand; double size; double price; Milk(String a, double b, double c) { brand = a; size = b; price = c; } } This is test method to insert the data: public static void main(String[] args) { // make a new list DoublyLinkedList theList = new DoublyLinkedList(); // this causes: // The method insertFirst(Comparable) in the type DoublyLinkedList is not applicable for the arguments (Milk) theList.insertFirst(new Milk("brand", 1, 2)); // insert at front theList.displayForward(); // display list forward theList.displayBackward(); // display list backward } // end main() } // end class DoublyLinkedApp Declarations: class Link<T extends Comparable<T>> {} class DoublyLinkedList<T extends Comparable<T>> {}

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  • Why can't my vector access the variables in my nested structs?

    - by chucknorris
    #include<iostream> #include<vector> #include<string> #include<list> using namespace std; struct record{ int id; string fName; }; struct cells{ list<record> rec; }; vector<cells> hp; int main() { **hp.front().rec.front().fName = "jon"; return 0; } I have 2 structs. The first struct, struct record, is composed of 2 regular variables. In struct 2, I have a linked list of type "record", which includes all the variable listed in struct 1. Why is it that when ever I attempt to access a variable in the structs, using my vector, I get the error "linked list iterator not dereferencable?"

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  • SQL server timeout 2000 from C# .NET

    - by Johnny Egeland
    I have run into a strange problem using SQL Server 2000 and two linked server. For two years now our solution has run without a hitch, but suddenly yesterday a query synchronizing data from one of the databases to the other started timing out. I connect to a server in the production network, which is linked to a server containing orders I need data from. The query contains a few joins, but basically this summarizes what is done: INSERT INTO ProductionDataCache (column1, column2, ...) SELECT tab1.column1, tab1.column2, tab2.column1, tab3.column1 ... FROM linkedserver.database.dbo.Table1 AS tab1 JOIN linkedserver.database.dbo.Table2 AS tab2 ON (...) JOIN linkedserver.database.dbo.Tabl32 AS tab3 ON (...) ... WHERE tab1.productionOrderId = @id ORDER BY ... Obviously my first attempt to fix the problem was to increase the timeout limit from the original 5 minutes. But when I arrived at 30 minutes and still got a timeout, I started to suspect something else was going on. A query just does not go from executing in less than 5 minutes to over 30 minutes over night. I outputted the SQL query (which was originally in the C# code) to my logs, and decided to execute the query in the Query Analyzer directly on the database server. To my big surprise, the query executed correctly in less than 10 seconds. So I isolated the SQL execution in a simple test program, and observed the same query time out both on the server originally running this solution AND when running it locally on the database server. Also I have tried to create a Stored Procedure and execute this from the program, but this also times out. Running it in Query Analyzer works fine in less than a few seconds. It seems that the problem only occurs when I execute this query from the C# program. Has anyone seen such behavior before, and found a solution for it? UPDATE: I have now used SQL Profiler on the server. The obvious difference is that when executing the query from the .NET program, it shows up in the log as "exec sp_executesql N'INSERT INTO ...'", but when executing from Query Analyzer it occurs as a normal query in the log. Further I tried to connect the SQL Query Analyzer using the same SQL user as the program, and this triggered the problem in Query Analyzer as well. So it seems the problem only occurs when connecting via TCP/IP using a sql user.

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  • LinkedList parameters in Java

    - by Walt
    Hi there, I created a program that contains linked lists that are passed various methods. While this works just fine in Java... a style checker program we have to use doesn't like it It says: Declaring variables, return values or parameters of type 'LinkedList' is not allowed. If I declare them as simply List then I don't have access to the methods I want. What should I do?

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  • How to pass parameters for OPENDATASOURCE

    - by Rapunzo
    I can connect to a linked server with this: SELECT testNo, soruTuruId, soruNo, cevap , degerlendirenTcNo, degerlendirilenTcNo FROM OPENDATASOURCE('SQLOLEDB', 'Data Source=192.168.150.42;User ID=readerUser;Password=1').akreditasyon.dbo.tblPerfCevap But I have to pass the password as parameter. and I try like this: SET @connectionString = 'Data Source=192.168.150.42;User ID=readerUser;Password='+@pw SELECT testNo, soruTuruId, soruNo, cevap , degerlendirenTcNo, degerlendirilenTcNo FROM OPENDATASOURCE('SQLOLEDB', @connectionString ).akreditasyon.dbo.tblPerfCevap and SELECT testNo, soruTuruId, soruNo, cevap , degerlendirenTcNo, degerlendirilenTcNo FROM OPENDATASOURCE('SQLOLEDB', 'Data Source=192.168.150.42;User ID=readerUser;Password='+@pw ).akreditasyon.dbo.tblPerfCevap but didnt work:S does anyone have an idea?

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  • Friday tips #2

    - by Chris Kawalek
    Welcome to our second Friday tips blog! You can ask us questions using the hash tag #AskOracleVirtualization on Twitter and we'll do our best to answer them. Today we've got a VDI related question on linked clones: Question: I want to use linked clones with Oracle Virtual Desktop Infrastructure. What are my options? Answer by John Renko, Consulting Developer, Oracle: First, linked clones are available with the Oracle VirtualBox hypervisor only. Second, your choice of storage will affect the rest of your architecture. If you are using a SAN presenting ISCSI LUNS, you can have linked clones with a Oracle Enterprise Linux based hypervisor running VirtualBox. OEL will use OCFS2 to allow VirtualBox to create the linked clones. Because of the OCFS2 requirement, a Solaris based VirtualBox hypervisor will not be able to support linked clones on remote ISCSI storage. If you using the local storage option on your hypervisors, you will have linked clones with Solaris or Linux based hypervisors running VirtualBox. In all cases, Oracle Virtual Desktop Infrastructure makes the right selection for creating clones - sparse or linked - behind the scenes. Plan your architecture accordingly if you want to ensure you have the higher performing linked clones.

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  • How to CompareTo two Object without known about their real type

    - by Kamil
    I have to implement a one linked list but it should put object in appropriate position. Everything was OK when I use it in conjunction with specific class, but when I tried make it universal and argument of method insert was Object some problem appeared. When I want to input Object in right position I should use CompareTo method, but there isn't method in Object class! The problem is how to compare two object elements without known about their real types. Maybe I should use generic class type? But what about CompareTo? Or maybe combine with Element class and place CompareTo there? I suppose it is feasible. :) public void insert(Object o) { Element el = new Element(o); // initializing and setting iterators while(!it.isDone() && ((it.current().getValue())).CompareTo(o)<0) // it.current() returns Element of List { //move interators } //... }

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  • How are lists implemented in Haskell (GHC)?

    - by eman
    I was just curious about some exact implementation details of lists in Haskell (GHC-specific answers are fine)--are they naive linked lists, or do they have any special optimizations? More specifically: Do length and (!!) (for instance) have to iterate through the list? If so, are their values cached in any way (i.e., if I call length twice, will it have to iterate both times)? Does access to the back of the list involve iterating through the whole list? Are infinite lists and list comprehensions memoized? (i.e., for fib = 1:1:zipWith (+) fib (tail fib), will each value be computed recursively, or will it rely on the previous computed value?) Any other interesting implementation details would be much appreciated. Thanks in advance!

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  • Accessing Active Directory Role Membership through LDAP using SQL Server 2005

    - by David Neale
    I would like to get a list of Active Directory users along with the security groups they are members of using SQL Server 2005 linked servers. I have the query working to retrieve records but I'm not sure how to access the memberOf attribute (it is a multi-value LDAP attribute). I have this temporary to store the information: DROP TABLE #ADUSERGROUPS CREATE TABLE #ADUSERGROUPS ( sAMAccountName varchar(30), UserGroup varchar(50) ) Each group/user association should be one row. This is my SELECT statement: SELECT sAMAccountName,memberOf FROM OpenQuery(ADSI, '<LDAP://hqdc04/DC=nt,DC=avs>; (&(objectClass=User)(sAMAccountName=9695)(sn=*)(mail=*)(userAccountControl=512)); sAMAccountName,memberOf;subtree') I get this error msg: OLE DB error trace [OLE/DB Provider 'ADSDSOObject' IRowset::GetData returned 0x40eda: Data status returned from the provider: [COLUMN_NAME=memberOf STATUS=DBSTATUS_E_CANTCONVERTVALUE], [COLUMN_NAME=sAMAccountName STATUS=DBSTATUS_S_OK]]. Msg 7346, Level 16, State 2, Line 2 Could not get the data of the row from the OLE DB provider 'ADSDSOObject'. Could not convert the data value due to reasons other than sign mismatch or overflow.

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  • Efficient data structure for fast random access, search, insertion and deletion

    - by Leonel
    I'm looking for a data structure (or structures) that would allow me keep me an ordered list of integers, no duplicates, with indexes and values in the same range. I need four main operations to be efficient, in rough order of importance: taking the value from a given index finding the index of a given value inserting a value at a given index deleting a value at a given index Using an array I have 1 at O(1), but 2 is O(N) and insertion and deletions are expensive (O(N) as well, I believe). A Linked List has O(1) insertion and deletion (once you have the node), but 1 and 2 are O(N) thus negating the gains. I tried keeping two arrays a[index]=value and b[value]=index, which turn 1 and 2 into O(1) but turn 3 and 4 into even more costly operations. Is there a data structure better suited for this?

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  • IEnumerable<T> representing the "rest" of an IEnumerable<T> sequence

    - by Henry Jackson
    If I am walking through an IEnumerable<T>, is there any way to get a new IEnumerable<T> representing the remaining items after the current one. For example, I would like to write an extension method IEnumerator<T>.Remaining(): IEnumerable<int> sequence = ... IEnumerator<int> enumerator = sequence.GetEnumerator(); if (enumerator.MoveNext() && enumerator.MoveNext()) { IEnumerable<int> rest = enumerator.Remaining(); // 'rest' would contain elements in 'sequence' start at the 3rd element } I'm thinking of the collection of a sort of singly-linked list, so there should be a way to represent any remaining elements, right? I don't see any way to do this exposed on either IEnumerable<T> or IEnumerator<T>, so maybe it's incompatible with the notion of a potentially unbounded, nondeterministic sequence of elements.

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  • Iterator for second to last element in a list

    - by BSchlinker
    I currently have the following for loop: for(list<string>::iterator jt=it->begin(); jt!=it->end()-1; jt++) I have a list of strings which is in a larger list (list<list<string> >). I want to loop through the contents of the innerlist until I get to the 2nd to last element. This is because I have already processed the contents of the final element, and have no reason to process them again. However, using it->end()-1 is invalid -- I cannot use the - operator here. While I could use the -- operator, this would decrement this final iterator on each cycle. I believe a STL list is a doubly linked list, so from my perspective, it should be possible to do this. Advice? Thanks in advance

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  • Can my tortoise vs. hare race be improved?

    - by FredOverflow
    Here is my code for detecting cycles in a linked list: do { hare = hare.next(); if (hare == back) return; hare = hare.next(); if (hare == back) return; tortoise = tortoise.next(); } while (tortoise != hare); throw new AssertionError("cyclic linkage"); Is there a way to get rid of the code duplication inside the loop? Am I right in assuming that I don't need a check after making the tortoise take a step forward? As I see it, the tortoise can never reach the end of the list before the hare (contrary to the fable). Any other ways to simplify/beautify this code?

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  • std::out_of_range error?

    - by vette982
    I'm dealing with a file with a linked list of lines with each node looking like this: struct TextLine{ //The actual text string text; //The line number of the document int line_num; //A pointer to the next line TextLine * next; }; and I'm writing a function that adds spaces at the beginning of the lines found in the variable text, by calling functions like linelist_ptr->text.insert(0,1,'\t'); The program compiles, but when I run it I get this error: terminate called after throwing an instance of 'std::out_of_range' what(): basic_string::at Aborted Any ideas?

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  • What sorting algorithm is this?

    - by Mike
    Hi, I have a sorting algorithm as follows. My question is, which sorting algorithm is this? I thought it was bubble sort, but it does not do multiple runs. Any idea? Thanks! //sorting in descending order struct node { int value; node* NEXT; } //Assume HEAD pointer denotes the first element in the //linked list // only change the values…don’t have to change the //pointers Sort( Node *Head) { node* first,second,temp; first= Head; while(first!=null) { second=first->NEXT; while(second!=null) { if(first->value < second->value) { temp = new node(); temp->value=first->value; first->value=second->value; second->value=temp->value; delete temp; } second=second->NEXT; } first=first->NEXT; } }

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  • Java, LinkedList of Strings. Insert in alphabetical order

    - by user69514
    I have a simple linked list. The node contains a string (value) and an int (count). In the linkedlist when I insert I need to insert the new Node in alphabetical order. If there is a node with the same value in the list, then I simply increment the count of the node. I think I got my method really screwed up. public void addToList(Node node){ //check if list is empty, if so insert at head if(count == 0 ){ head = node; head.setNext(null); count++; } else{ Node temp = head; for(int i=0; i<count; i++){ //if value is greater, insert after if(node.getItem().getValue().compareTo(temp.getItem().getValue()) > 0){ node.setNext(temp.getNext()); temp.setNext(node); } //if value is equal just increment the counter else if(node.getItem().getValue().compareTo(temp.getItem().getValue()) == 0){ temp.getItem().setCount(temp.getItem().getCount() + 1); } //else insert before else{ node.setNext(temp); } } } }

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  • Problem when reading input in C

    - by gcx
    I've made a Linked List. Its elements keep both previous and next items' address. It gets commands from an input file. It detects the command and uses the following statement as a parameter. (text: add_to_front john - means: add_to_front(john)) Code: http://pastebin.com/KcAm1y3L When I try to give the commands from an input file it gives me same output over and over. However, if I write inputs in main() manually, it works. For ex input file: add_to_front john add_to_back jane add_to_back jane print (unfortunately) the output is: >add_to_front john >add_to_back jane >add_to_back jane >print jane jane jane Although, if I write add_to_front(john); add_to_back(jane); add_to_back(jane); print(); instead of this command check: while (scanf("%s",command)!=EOF) { if (strcmp(command,"add_to_front")==0) { gets(parameter); add_to_front(parameter); } else if (strcmp(command,"add_to_back")==0) { gets(parameter); add_to_back(parameter); } else if (strcmp(command,"remove_from_back")==0) remove_from_back(parameter); ... printf(" HUH?\n"); } } in main() it gives the correct output. I know it's a lot to ask but this thing is bothering me for 2 days. What do you think i'm doing wrong?

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  • why toString method does not work here??

    - by user329820
    Hi this is my whole class ,I have added number 2 to the doubly linked list and then I want it to be be print in the concole but it will show this "datastructureproject.Node@f62373" thanks! package datastructureproject; public class DoublyLinkedList { private Node head = new Node(0); private Node tail = new Node(0); private int length = 0; public DoublyLinkedList() { head.setPrev(null); head.setNext(tail); tail.setPrev(head); tail.setNext(null); } public void add(int index, int value) throws IndexOutOfBoundsException { Node cursor = get(index); Node temp = new Node(value); temp.setPrev(cursor); temp.setNext(cursor.getNext()); cursor.getNext().setPrev(temp); cursor.setNext(temp); length++; } private Node get(int index) throws IndexOutOfBoundsException { if (index < 0 || index > length) { throw new IndexOutOfBoundsException(); } else { Node cursor = head; for (int i = 0; i < index; i++) { cursor = cursor.getNext(); } return cursor; } } public long size() { return length; } public boolean isEmpty() { return length == 0; } @Override public String toString() { StringBuffer result = new StringBuffer(); result.append("(head) - "); Node temp = head; while (temp.getNext() != tail) { temp = temp.getNext(); result.append(temp.getValue() + " - "); } result.append("(tail)"); return result.toString(); } public static void main(String[] args){ DoublyLinkedList list = new DoublyLinkedList(); list.add(0,2 ); System.out.println(list.get(0).toString()); } }

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  • Item in multiple lists

    - by Evan Teran
    So I have some legacy code which I would love to use more modern techniques. But I fear that given the way that things are designed, it is a non-option. The core issue is that often a node is in more than one list at a time. Something like this: struct T { T *next_1; T *prev_1; T *next_2; T *prev_2; int value; }; this allows the core have a single object of type T be allocated and inserted into 2 doubly linked lists, nice and efficient. Obviously I could just have 2 std::list<T*>'s and just insert the object into both...but there is one thing which would be way less efficient...removal. Often the code needs to "destroy" an object of type T and this includes removing the element from all lists. This is nice because given a T* the code can remove that object from all lists it exists in. With something like a std::list I would need to search for the object to get an iterator, then remove that (I can't just pass around an iterator because it is in several lists). Is there a nice c++-ish solution to this, or is the manually rolled way the best way? I have a feeling the manually rolled way is the answer, but I figured I'd ask.

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  • Question on passing a pointer to a structure in C to a function?

    - by worlds-apart89
    Below, I wrote a primitive singly linked list in C. Function "addEditNode" MUST receive a pointer by value, which, I am guessing, means we can edit the data of the pointer but can not point it to something else. If I allocate memory using malloc in "addEditNode", when the function returns, can I see the contents of first-next ? Second question is do I have to free first-next or is it only first that I should free? I am running into segmentation faults on Linux. #include <stdio.h> #include <stdlib.h> typedef struct list_node list_node_t; struct list_node { int value; list_node_t *next; }; void addEditNode(list_node_t *node) { node->value = 10; node->next = (list_node_t*) malloc(sizeof(list_node_t)); node->next->value = 1; node->next->next = NULL; } int main() { list_node_t *first = (list_node_t*) malloc(sizeof(list_node_t)); first->value = 1; first->next = NULL; addEditNode(first); free(first); return 0; }

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  • Why do I get "request for member in something not a struct or union" from this code?

    - by pyroxene
    I'm trying to teach myself C by coding up a linked list. I'm new to pointers and memory management and I'm getting a bit confused. I have this code: /* Remove a node from the list and rejiggle the pointers */ void rm_node(struct node **listP, int index) { struct node *prev; struct node *n = *listP; if (index == 0) { *listP = *listP->next; free(n); return; } for (index; index > 0; index--) { n = n->next; if (index == 2) { prev = n; } } prev->next = n->next; free(n); } to remove an element from the list. If I want to remove the first node, I still need some way of referring to the list, which is why the listP arg is a double pointer, so it can point to the first element of the list and allow me to free the node that used to be the head. However, when I try to dereference listP to access the pointer to the next node, the compiler tells me error: request for member ‘next’ in something not a structure or union . What am I doing wrong here? I think I might be hopelessly mixed up..?

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  • When to use () with classes?

    - by SoulBeaver
    This is really starting to confuse the hell out of me. When do I use them, when don't I? For example I was reading a .cpp on linked lists whose class declaration was: struct CarPart { long PartNumber; char Partname[40]; double UnitPrice; CarPart *next; }; class ListOfParts { int size; public: CarPart *head; ListOfParts(); ~ListOfParts(); const int count() const; void insert( CarPart *item ); CarPart *retrieve( int pos ); }; With this code, why am I allowed to write ListOfParts *pPart = new ListOfParts(); CarPart *pCarPart = new CarPart; Declaring an instance of ListOfParts requires (), but not my CarPart? That's confusing me. When I asked a question before and people told me that such a declaration is a function that returns a ListOfParts object, but not the actual constructor. So I'm guessing this is still something different. What's happening here? PS: Am I correct to assume that the const to the right of count() means I cannot modify any values in count?

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  • free( ) pointers

    - by user1043625
    I'm required to use a special library to keep track of my memory leaks where malloc()= allocate( ) and free( ) = unallocate( ). I'm trying to complete free a linked-list but it seems like the "root" value isn't being freed. typedef struct _node { struct _node *child; char *command; } Command_list; void delete_commands(Command_list **root) { Command_list *temp; while( *root != NULL ){ temp = (*root)->child; //printf("STRING: %s\n", *root->command ); unallocate( *root ); *root = temp; } } The function that's calling it void file_processing( .... ){ Command_list *root = allocate(sizeof (Command_list)); root = NULL; .... delete_commands( &root ); } } I believe that Command_list *root = allocate(sizeof (Command_list)) isn't being properly de-allocated for some reason. Anyone can give me some hints? UPDATE: I found out that instead of Command_list *root = allocate(sizeof (Command_list)); root = NULL; this works: Command_list *root = NULL;

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  • sorting char* arrays

    - by skazhy
    Hi! I have a datastructure struct record { char cont[bufferSize]; record *next; }; When I add new records to this structure, I want them to be sorted alphabetically. I made this function, that adds record in the right place (by alphabet) in the linked list: record *start=NULL, *p, *x; void recAdd(char*temp) { p = new record; temp[strlen(temp)] = '\0'; for (int j=0;j<bufferSize;j++) p->cont[j] = temp[j]; if (start==NULL) start=p; else { x=start; int c=0; while (recComp(x->cont,p->cont) <= 0 && x->next != NULL) { x=x->next; c++; } if (c == 0) { p->next=start; start=p; } else { x=start; for (int i=0;i<c;i++) x=x->next; p->next=x->next; x->next=p; } } for (int j=0;j<bufferSize;j++) temp[j] = NULL; }; But somehow it doesn't sort things right. What is wrong with my function?

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  • How do I find out what's linked to my Excel Worksheet?

    - by dwwilson66
    I've got an Excel 2007 worksheet that I inherited, and each time it opens, I get the dialog box asking if I would like to update values from an outside, linked worksheet. I'm trying to track down if I should be saying yes or no; as I'm not familiar with the linked spreadsheet, nor what types of data it creates, nor if it's even in use and updated regularly. Is there a way I can get a list of worksheets, paths, and linked cells so I can trace the formulae and see which links can be severed? d

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