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  • ASP.NET MVC 1: Model Binding With Disabled Textbox

    - by modernzombie
    I have a textbox that I am defining as <%= Html.TextBox("Username", Model.Form.Username, new { @class = "textbox", @disabled = "disabled" })%> In my action [AcceptVerbs(HttpVerbs.Post)] [ValidateAntiForgeryToken] public ActionResult EditLogin(LoginForm post) { ... return View(model); } post.Username will be blank, all other properties bind correctly, but if I change @disabled="disabled to @readonly="readonly" the username binds properly and everything works. It looks like model binding ignores values in disabled fields. Is their a way around this? I still need the field's value to bind to the model. I can use readonly but would prefer to use disabled so it is visually apparent to the user that they cannot edit the value of the field.

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  • Is Inheritance in Struts2 Model-Driven Action possible?

    - by mryan
    Hello, I have a Model-Driven Struts2 action that provides correct JSON response. When I re-structure the action I get an empty JSON response back. Has anyone got inheritance working with Struts2 Model-Driven actions? Ive tried explicitly setting include properties in struts config: <result name="json" type="json"> <param name="includeProperties"> jsonResponse </param> </result> Code for all actions below - not actual code in use - I have edited and stripped down for clarity. Thanks in advance. Action providing correct response: public class Bike extends ActionSupport implements ModelDriven, Preparable { @Autowired private Service bikeService; private JsonResponse jsonResponse; private com.ets.model.Vehicle bike; private int id; public Bike() { jsonResponse = new JsonResponse("Bike"); } @Override public void prepare() throws Exception { if (id == 0) { bike = new com.ets.model.Bike(); } else { bike = bikeService.find(id); } } @Override public Object getModel() { return bike; } public void setId(int id) { this.id = id; } public void setBikeService(@Qualifier("bikeService") Service bikeService) { this.bikeService = bikeService; } public JsonResponse getJsonResponse() { return jsonResponse; } public String delete() { try { bike.setDeleted(new Date(System.currentTimeMillis())); bikeService.updateOrSave(bike); jsonResponse.addActionedId(id); jsonResponse.setAction("delete"); jsonResponse.setValid(true); } catch (Exception exception) { jsonResponse.setMessage(exception.toString()); } return "json"; } } Re-structured Actions providing incorrect response: public abstract class Vehicle extends ActionSupport implements ModelDriven { @Autowired protected Service bikeService; @Autowired protected Service carService; protected JsonResponse jsonResponse; protected com.ets.model.Vehicle vehicle; protected int id; protected abstract Service service(); @Override public Object getModel() { return bike; } public void setId(int id) { this.id = id; } public void setBikeService(@Qualifier("bikeService") Service bikeService) { this.bikeService = bikeService; } public void setCarService(@Qualifier("carService") Service carService) { this.carService = carService; } public JsonResponse getJsonResponse() { return jsonResponse; } public String delete() { try { vehicle.setDeleted(new Date(System.currentTimeMillis())); service().updateOrSave(vehicle); jsonResponse.addActionedId(id); jsonResponse.setAction("delete"); jsonResponse.setValid(true); } catch (Exception exception) { jsonResponse.setMessage(exception.toString()); } return "json"; } } public class Bike extends Vehicle implements Preparable { public Bike() { jsonResponse = new JsonResponse("Bike"); } @Override public void prepare() throws Exception { if (id == 0) { vehicle = new com.ets.model.Bike(); } else { vehicle = bikeService.find(id); } } @Override protected Service service() { return bikeService; } } public class Car extends Vehicle implements Preparable { public Car() { jsonResponse = new JsonResponse("Car"); } @Override public void prepare() throws Exception { if (id == 0) { vehicle = new com.ets.model.Car(); } else { vehicle = carService.find(id); } } @Override protected Service service() { return carService; } }

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  • Model validation with enumerable properties in Asp.net MVC2 RTM

    - by Robert Koritnik
    I'm using DataAnnotations attributes to validate my model objects. My model class looks similar to this: public class MyModel { [Required] public string Title { get; set; } [Required] public List<User> Editors { get; set; } } public class User { public int Id { get; set; } [Required] public string FullName { get; set; } [Required] [DataType(DataType.Email)] public string Email { get; set; } } My controller action looks like: public ActionResult NewItem(MyModel data) { //... } User is presented with a view that has a form with: a text box with dummy name where users enter user's names. For each user they enter, there's a client script coupled with ajax that creates an <input type="hidden" name="data.Editors[0].Id" value="userId" /> for each user entered (enumeration index is therefore not always 0 as written here), so default model binder is able to consume and bind the form without any problems. a text box where users enter the title Since I'm using Asp.net MVC 2 RTM which does model validation instead of input validation I don't know how to avoid validation errors. The thing is I have to use BindAttribute on my controller action. I would have to either provide a white or a black list of properties. It's always a better practice to provide a white list. It's also more future proof. The problem My form works fine, but I get validation errors about user's FullName and Email properties since they are not provided. I also shouldn't feed them to the client (via ajax when user enters user data), because email is personal contact data and is not shared between users. If there was just a single user reference on MyModel I would write [Bind(Include = "Title, Editor.Id")] But I have an enumeration of them. How do I provide Bind white list to work with my model?

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  • Model availability inside ActionFilter

    - by Sayed Ibrahim Hashimi
    I have created a new ActionFilter for an ASP.NET MVC application that I'm creating. I have an action which accepts an Http Post and the argument of the action method accepts an object, for which I have created and registered a custom model binder. I noticed that inside the IActionFilter.OnActionExecuting the value for filterContext.Controller.ViewData.Model is always null despite the fact that it looks like the model binder is always invoked before the action filter OnActionExecuting method. In contrast to this inside the IActionFilter.OnActionExecuted method of the same action filter the value for filterContext.Controller.ViewData.Model is not null. Do you guys know if this is by design or a bug? If by design are their any links which describe why this is? Thanks.

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  • Model validation with enumerations

    - by Robert Koritnik
    I'm using DataAnnotations attributes to validate my model objects. My model class looks similar to this: public class MyModel { [Required] public string Title { get; set; } [Required] public List<User> Editors { get; set; } } public class User { public int Id { get; set; } [Required] public string FullName { get; set; } [Required] [DataType(DataType.Email)] public string Email { get; set; } } My controller action looks like: public ActionResult NewItem(MyModel data) { //... } User is presented with a view that has a form with: a text box with dummy name where users enter user's names. For each user they enter, there's a client script coupled with ajax that creates an <input type="hidden" name="data.Editors[0].Id" value="userId" /> for each user entered (enumeration index is therefore not always 0 as written here), so default model binder is able to consume and bind the form without any problems. a text box where users enter the title Since I'm using Asp.net MVC 2 RTM which does model validation instead of input validation I don't know how to avoid validation errors. The thing is I have to use BindAttribute on my controller action. I would have to either provide a white or a black list of properties. It's always a better practice to provide a white list. It's also more future proof. The problem My form works fine, but I get validation errors about user's FullName and Email properties since they are not provided. I also shouldn't feed them to the client (via ajax when user enters user data), because email is personal contact data and is not shared between users. If there was just a single user reference on MyModel I would write [Bind(Include = "Title, Editor.Id")] But I have an enumeration of them. How do I provide Bind white list to work with my model?

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  • mvc presentation model best-practices

    - by Andrew Florko
    Hello, everybody How do you usually convert business objects to presentation? For example: Business object Person { Id, FirstName, LastName, Patronymic ... } should be presented as "LastName F. P. " in html layout. We use Presentation classes hierarchy to represent data ready for output from Business model. Questions: Will you keep presentation model completely separated from Business Model. For example, can strong-typed views (MVC ASP.NET) aggregate formatted business data as well as raw business objects (that leads toward <%=Html.Encode(PersonHelper.ToShort(Model.Person))% html layout injections) What architecture layer do you choose for conversion (mvc controllers that formats business data from business layer, for instance). Thank you in advance

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  • Custom Validation Attribute with Custom Model Binder in MVC 2

    - by griegs
    I apologise for the amount of code I have included. I've tried to keep it to a minimum. I'm trying to have a Custom Validator Attribute on my model as well as a Custom Model binder. The Attribute and the Binder work great seperately but if I have both, then the Validation Attribute no longer works. Here is my code snipped for readability. If I leave out the code in global.asax the custom validation fires but not if I have the custom binder enabled. Validation Attribute; public class IsPhoneNumberAttribute : ValidationAttribute { public override bool IsValid(object value) { //do some checking on 'value' here return true; } } Useage of the attribute in my model; [Required(ErrorMessage = "Please provide a contact number")] [IsPhoneNumberAttribute(ErrorMessage = "Not a valid phone number")] public string Phone { get; set; } Custom Model Binder; public class CustomContactUsBinder : DefaultModelBinder { protected override void OnModelUpdated(ControllerContext controllerContext, ModelBindingContext bindingContext) { ContactFormViewModel contactFormViewModel = bindingContext.Model as ContactFormViewModel; if (!String.IsNullOrEmpty(contactFormViewModel.Phone)) if (contactFormViewModel.Phone.Length > 10) bindingContext.ModelState.AddModelError("Phone", "Phone is too long."); } } Global asax; System.Web.Mvc.ModelBinders.Binders[typeof(ContactFormViewModel)] = new CustomContactUsBinder();

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  • How to launch the market intent in 'Give Feedback' mode on android.

    - by Paul Maidment
    Hi There, I have just written a game for the Android market and would like to remind my customers to leave feeback on the market for the application (especially the demo version.) Is there any way to launch the market intent in a mode that will take the user to the feedback / comments section of the page? I already use this approach for linking my demo to the paid app... Intent goToMarket = null; goToMarket = new Intent(Intent.ACTION_VIEW,Uri.parse("market://details?id=com.paulmaidment.games.flagsoftheworld")); startActivity(goToMarket); Is there a best practice that any Android devs out there might know of? Additionally, is there any way to track referalls from my demo app so that I can try to calculate some kind of a conversion rate? (i.e. how effective the demo app is at generating sales.) Thanks, Paul

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  • Django anonymous user in model

    - by jack
    I have a model defined as below: class Example(models.Model): user = models.ForeignKey(User, null=True) other = models.CharField(max_length=100) The problem is Django refuses to assign django.contrib.auth.models.AnonymousUser directly to Example.user as null field so everytime I have to check if request.user.is_authenticated() ans assign Example.user = None manually. Is there a default value for AnonymousUser to use in a model field?

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  • zend framework can't find Model classes ?

    - by user284503
    Yall: I have a simple question, it might be a simple configuration issue, but I have a Model defined, and when I try to access it from a controller it fails. The Model is in the model directory, and when I look at the quickstart app, it seems like this should work. Here is my model: <?php class Application_Model_User { protected $_user; protected $_password; protected $_userId; // very simple right } ?> My controller just stops.. here is the controller code: <?php class UserController extends Zend_Controller_Action { public function init() { } public function indexAction() { // display login form $users = new Application_Model_User(); echo "test never echos.. stopped above ? weird huh.."; // fails before .. } ?> Thank you everyone,

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  • turning open source software into a consulting business ?

    - by sofreakinghigh
    just some general and specific questions about running a business which uses open source software and sells training, services, and other value added solutions utilizing the open source asset(s). 1) how much modification do you need to make to an existing open source software/framework to give a new brand ? open source (GPLv3) branding issues here.... for ex) Mambo and Joomla, i think they are pretty much same ? but they have different labels. 2) Is there a disadvantage of promoting open source software/framework/suite in hopes of selling value added services and solutions on top of the Open source asset ? 3) can Open source assets be marketing point for lowered Total Ownership Cost and transparency ? meaning, clients will not be using some mysterious, opaque proprietary asset ? 4) is competition fierce? cost of developing software is non existing because you are using an open source asset. barrier to entry is minimal ??

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  • Alloy MVC Framework Titanium Network (Model)

    - by flyingDuck
    I'm trying to authenticate using the Model in Alloy. I have been trying to figure this problem out since yesterday. If anybody could help me, I'd really appreciate it. So, I have a view login.xml, then a controller login.js. The login.js contains the following function: var user = Alloy.Models.user; //my user.js model function login(e) { if($.username.value !== '' && $.password.value !== ''){ if(user.login($.username.value, $.password.value)){ Alloy.createController('home').getView().open(); $.login.close(); } }else{ alert('Username and/or Password required!'); } } Then in my user.js model, it's like this: extendModel : function(Model) { _.extend(Model.prototype, { login: function(username, password) { var first_name, last_name, email; var _this = this; var url = 'http://myurl.com/test.php'; var auth = Ti.Network.createHTTPClient({ onerror: function(e){ alert(e.error); }, onload: function(){ var json = this.responseText; var response = JSON.parse(json); if(response.logged == true){ first_name = response.f_name; last_name = response.l_name; email = response.email; _this.set({ loggedIn: 1, username: email, realname: first_name + ' ' + last_name, email: email, }); _this.save(); }else{ alert(response.message); } }, }); auth.open('POST', url); var params = { usernames: username, passwords: password, }; auth.send(params); alert(_this.get('email')); //alert email }, }); When I click on login in login.xml it calls the function login in index.js. So, now my problem is that, when I click the button for the first time, I get an empty alert from alert(_this.get('email')), but then when I click the button the second time, everything works fine, it alerts the email. I have no idea what's going on. Thank you for the help.

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  • Proper design a Model-Controller in Cocoa?

    - by legege
    Hi, I'm trying to design a simple Cocoa application and I would like to have a clear and easy to understand software architecture. Of course, I'm using a basic MVC design and my question concerns the Model layer. For my application, the Model represents data fetched on the Internet with a XML-RPC API. I'm planning to use Core Data to represent a locally fetched version. How should the data be loaded initially? I'm reading the Cocoa Design Pattern book, and they talk about a Model-Controller that is centric to the Model. How would that be done? Thanks!

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  • symfony 1.4: doctrine build model warning

    - by tigerstyle
    Hi volks, I copied my sources from my lokal dev (everything works fine) to my repository and from there I did a checkout on my remote dev. Now when I try to build everything I get this error: devel:/var/www/myproject# ./symfony doc:build-model doctrine generating model classes file+ /tmp/doctrine_schema_48726.yml Warning: file_get_contents(/var/www/myproject/lib/model/doctrine//base/BaseAdvert.class.php): failed to open stream: No such file or directory in /var/www/myproject/lib/vendor/symfony/lib/plugins/sfDoctrinePlugin/lib/task/sfDoctrineBuildModelTask.class.php on line 77 Do you know what the problem could be? Thx for your answers :)

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  • List of models in Model in MVC

    - by arri
    I have two models: class ModelIn{ public string FirstName { get; set; } public string LastName { get; set; } public string Address { get; set; } } class ModelOut{ public ModelOut(){ People = new List<ModelIn>();} public List<ModelIn> People { get; private set;} public string Country { get; set; } } And I have Controller editing ModelOut: public ActionResult People() { ... return View(SomeModelOutInstanceWith3People); } [HttpPost] public ActionResult(ModelOut m) { ... } In view I have sth like: <% using (Html.BeginForm()) { %> <%: Html.EditorFor(m => Model.Country) %> <% for(int i = 0; i < Model.People.Count; ++i){ %> <%: Html.EditorFor(m => Model.People[i].FirstName) %> <%: Html.EditorFor(m => Model.People[i].LastName) %> <%: Html.EditorFor(m => Model.People[i].Address) %> <% } %> <input type="submit" /> <% } %> It works all OK, but in post action I have empty ModelOut m. I can see in logs that data is sent correctly. I have tried everything, nothing works.

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  • Android -- How to post app rating/comments to Market from within app?

    - by borg17of20
    Hello all, This is a simple question. Is there a way to allow users to enter in a comment and or rating for my app from directly within my app and have that data posted back to the Android Market? If so, what would the code for that look like if I used an EditText view to allow user input? If not, then is my only other option directly linking to my app in the Market (i.e. the user clicks the link in my app, or a button, and the Market app launches with my app page displayed)? For example: view.setOnClickListener( new OnClickListener(){ public void onClick(View v) { startActivity( new Intent( Intent.ACTION_VIEW, Uri.parse("market://details?id=packagename") ) ); } } *where "packagename" is replaced by my app's package name from the manifest. Thanks.

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  • Django model help

    - by dotty
    Does anyone have any clue why this doesn't work as expected. If i use the python shell and do team.game_set or team.games It returns an error AttributeError: 'Team' object has no attribute 'game' If i create a Game object and call game.home_team it returns the correct team object Heres my model class Team(models.Model): name = models.CharField(blank=True, max_length=100) class Game(models.Model): home_team = models.ForeignKey(Team, related_name="home_team")

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  • Codeigniter: Check where model is loaded from?

    - by qwerty
    I'm having the strangest thing ever right now. I "disabled" a model because i don't need to access it ever again. I did so by echoing out an error string in the __construct() and right after that die(). That way i would notice if i ever loaded the model, even by mistake, which should never happen. Alright? The problem is, the model is not loaded ANYWHERE in the entire project, but it still gets loaded for some reason. It's not auto loaded, that's for sure. Is it possible to track down where a model is loaded? Like which line it happens etc?

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  • Implementing a Cakephp Model using an Array

    - by Zubin
    The CakePHP Cookbook states that a Model can use a file (csv for example) instead of an actual database table but I couldn't find any implementation for it. I was wondering if it is possible to use an Array of data as a model in CakePHP since I have a fairly static set of data which is important to me in a relationship with another table but it doesn't make a whole lot of sense to create a complete table for it. Is it possible to implement a CakePHP Model using an Array?

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  • Error Handling in Model (MVC)

    - by Andre
    I was wondering what the excepted standard is for handling errors in the Model. Currently I have 'setError' and 'getError' methods that's in use by all my Models. This means I'm only concerned with whether a call to a method in my Model is true or false. If it's false then I would use $this-model-getError() in my Controller. Additionally I'm contemplating setting up a separate file that contains all my errors. One file per model, also wanted to have thoughts on this.

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  • Formating a date field in the Model (Codeigniter)

    - by Landitus
    Hi, I', trying to re-format a date from a table in Codeigniter. The Controller is for a blog. I was succesfull when the date conversion happens in the View. I was hoping to convert the date in the Model to have things in order. This is the Model: class Novedades_model extends Model { function getAll() { $this->db->order_by('date','desc'); $query = $this->db->get('novedades'); if($query->num_rows() > 0) { foreach ($query->result() as $row) { $data[] = $row; } } return $data; } } This is part of the controller $this->load->model('novedades_model'); $data['records'] = $this->novedades_model->getAll(); Here's the date conversion as it happens in the View. This is inside the posts loop: <?php foreach($records as $row) : ?> <?php $fdate = "%d <abbr>%M</abbr> %Y"; $dateConv = mdate($fdate, mysql_to_unix($row->date)); ?> <div class="article section"> <span class="date"><?php echo $dateConv ;?></span> ... Keeps going ... How can I convert the date in the Model? Can I access the date key and refactor it?

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  • Five stars of open data - example and review

    - by Joe
    (there may be a more suited SE site for this question so feel free to shift) I have some data I'd like to make open to the public - It's synatesis of some related data retrived from freedom of infomation requests over the last year. The data itself is at http://www.cs.rhul.ac.uk/home/joseph/domesday/Domesday-Scotland.csv or for fans of Excel, at http://www.cs.rhul.ac.uk/home/joseph/domesday/Domesday-Scotland.xlsx . It's no more than a table with about five columns. I'd like to make this properly open data, so I was looking at the 5 star deployment scheme for Open Data. Much of which is fine but I'm confused towards the end and I could do with an explenation from people who know the answers. So to get achieve the star levels I need: "make your stuff available on the Web (whatever format) under an open license" trival - all I have to do is put the notes up on the page that will give the provance of the data. "make it available as structured data (e.g., Excel instead of image scan of a table)"… done… "use non-proprietary formats (e.g., CSV instead of Excel)" - done… "use URIs to identify things, so that people can point at your stuff" - this is where I start to get a bit hazy - does this mean there should be an URI for every line in the table? "link your data to other data to provide context" - this isn't massively clear to me - does this mean to give the provence of the data? One column of the data I've put out is a link to where the data came from - is that the sort of thing we're looking at? Any and all information and answers welcome… EDIT - or if anyone wants to recommend a place SE or other place to ask the question - that would be cool...

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  • Changing open-files-limit in mysql 5.5

    - by davidv
    I'm having an issue with mysql 5.5 running on Ubuntu 12.04 with the open-files-limit parameter. I recently noticed some problems due to the 1024 limit, and actually the main system limit was set to 1024, so I modified /etc/security/limits.conf with the following: * soft nofile 32000 * hard nofile 32000 root soft nofile 32000 root hard nofile 32000 After that I check the ulimit value for root and even for mysql user, both returned the new value: 32000, so I assume the change has already been done. I also changed the value at the my.cnf file, setting open-files-limit to 24000, like this: open-files-limit = 24000 Now comes the odd part, when I restart the mysql service and check the open_files_limit variable, it returns that it's still set to 1024, so I'm having the same problems that before (obviously), I tried to use open-files-limit instead open_files_limit in the my.cnf config file, same result, BUT if I override the service command to start the service and start only using mysqld (no additional parameters), the service starts and when I check the parameter it returns 32000... I don't know where it's taking that value from, as it's not set at my.cnf and it's not being given through command line, at least, not for myself. Any ideas about why it's not working the change and how to solve it the normal way (launching it through service...)?

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  • What is the difference (if any) between Html.Partial(view, model) and Html.RenderPartial(view,model)

    - by Stephane
    Other than the type it returns and the fact that you call it differently of course <% Html.RenderPartial(...); %> <%= Html.Partial(...) %> If they are different, why would you call one rather than the other one? The definitions: // Type: System.Web.Mvc.Html.RenderPartialExtensions // Assembly: System.Web.Mvc, Version=2.0.0.0, Culture=neutral, PublicKeyToken=31bf3856ad364e35 // Assembly location: C:\Program Files (x86)\Microsoft ASP.NET\ASP.NET MVC 2\Assemblies\System.Web.Mvc.dll using System.Web.Mvc; namespace System.Web.Mvc.Html { public static class RenderPartialExtensions { public static void RenderPartial(this HtmlHelper htmlHelper, string partialViewName); public static void RenderPartial(this HtmlHelper htmlHelper, string partialViewName, ViewDataDictionary viewData); public static void RenderPartial(this HtmlHelper htmlHelper, string partialViewName, object model); public static void RenderPartial(this HtmlHelper htmlHelper, string partialViewName, object model, ViewDataDictionary viewData); } } // Type: System.Web.Mvc.Html.PartialExtensions // Assembly: System.Web.Mvc, Version=2.0.0.0, Culture=neutral, PublicKeyToken=31bf3856ad364e35 // Assembly location: C:\Program Files (x86)\Microsoft ASP.NET\ASP.NET MVC 2\Assemblies\System.Web.Mvc.dll using System.Web.Mvc; namespace System.Web.Mvc.Html { public static class PartialExtensions { public static MvcHtmlString Partial(this HtmlHelper htmlHelper, string partialViewName); public static MvcHtmlString Partial(this HtmlHelper htmlHelper, string partialViewName, ViewDataDictionary viewData); public static MvcHtmlString Partial(this HtmlHelper htmlHelper, string partialViewName, object model); public static MvcHtmlString Partial(this HtmlHelper htmlHelper, string partialViewName, object model, ViewDataDictionary viewData); } }

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