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  • IE session (-nomerge) manager

    - by skrco
    I'm looking for an application that can manage (save/open) multiple Internet Explorer instances (to be precise nomerge sessions), host them in single window and arrange these instances e.g. in tabs, so in result you have double tab bar. In functionality it's similar to Remote Desktop Manager, where you can create Web session, but in embedded mode you cannot set the nomerge option. I've been searching the web, but with no results. So I put this question whether anyone know of such application or workaround. Or I have to write my own app.

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  • Windows update not working (2008 R2)

    - by Le_Quack
    long story short, one of our domain controllers is won't update. when an update is attempted it says the service is not running (checked and restarted yes it is) and event viewer says its error 0x80072ee2 but this apparently means there is a connection issue but as far as I can work out there isn't. this isn't a short term issue either seems to have been going on since at least feburary. any ideas? Note: Server updates fall to another (more senior) member of the team please do not ask me why they have been so neglected. He doesn't know what the issue is so I'm just trying to get to the bottom of this. many thanks

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  • Manage a flexible and elastic Data Center with Oracle VM Manager (By Tarry Singh - PACKT Publishing)

    - by frederic.michiara
    For the ones looking at an easy reading and first good approach to Oracle VM Manager and VM Servers, I would recommend reading the following book even so it was written for 2.1.2 whereas we can use now Oracle VM 2.2 : Oracle VM Manager 2.1.2 Manage a Flexible and Elastic Data Center with Oracle VM Manager Learn quickly to install Oracle VM Manager and Oracle VM Servers Learn to manage your Virtual Data Center using Oracle VM Manager Import VMs from the Web, template, repositories, and other VM formats such as VMware Learn powerful Xen Hypervisor utilities such as xm, xentop, and virsh A practical hands-on book with step-by-step instructions Oracle VM experts might be frustrated, but to me it's not aim to Oracle VM experts, but to the ones who needs an introduction to the subject with a good coverage of all what you need to know. This book is available on https://www.packtpub.com/oracle-vm-manager-2-1-2/book Need to find out about Table of contents : https://www.packtpub.com/article/oracle-vm-manager-2-1-2-table-of-contents Discover a sample chapter : https://www.packtpub.com/sites/default/files/sample_chapters/7122-oracle-virtualization-sample-chapter-4-oracle-vm-management.pdf Read also articles from Tarry Singh on http://www.packtpub.com/ : Oracle VM Management : http://www.packtpub.com/article/oracle-vm-management-1 Extending Oracle VM Management : http://www.packtpub.com/article/oracle-vm-management-2 Hope you'll enjoy this book as a first approach to Oracle VM. For more information on Oracle VM : Oracle VM on n OTN : http://www.oracle.com/technology/products/vm/index.html Oracle VM Wiki : http://wiki.oracle.com/page/Oracle+VM Oracle VM on IBM System x : http://www-03.ibm.com/systems/x/solutions/infrastructure/erpcrm/oracle/virtualization.html

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  • Does a team of developers need a manager?

    - by Amadiere
    Background: I'm currently part of a team of four: 1 manager, 1 senior developer and 2 developers. We do a range of bespoke in-house systems / projects (e.g. 6-8 weeks) for an organisation of around 3500 staff, as well as all the maintenance and support required from the systems that have been created before. There is not enough of us to do all the work that is potentially coming our way - we're understaffed. Management acknowledge this, but budget restraints limit our ability to recruit additional members to the team (even if we make the salary back in savings). The Change This leaves us where we are now. Our manager is due to leave his role for pastures new, leaving a vacancy in the team. Management are using this opportunity to restructure our team which would see the team manager role replaced by another developer and another senior developer. Their logic being that we need more developers, so here's a way of funding it (one of the roles is partially funded from another vacant post). The team would have no direct line manager and the roles and responsibilities would be divided up between the seniors and the (relatively new to post) service manager (a non-technical role with little-to-no development knowledge/experience whose focus is shared amongst a number of other teams and individuals) - who would be our next actual manager up the food chain. I guess the final question is: Is it possible to run a development team without an manager? Have you had experience of this? And what things could go wrong / could be of benefit to us? I'd ideally like to "see the light" and the benefits of doing things this way, or come up with some points for argument against it.

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  • Early Adopters of Oracle Enterprise Manager 12c Report Agility and Productivity Benefits

    - by Anand Akela
    Earlier this month at the Oracle Open World 2012, we celebrated the first anniversary of Oracle Enterprise Manager 12c . Early adopters of  Oracle Enterprise manager 12c have benefited from its federated self-service access to complete application stacks, automated provisioning, elastic scalability, metering, and charge-back capabilities. Crimson Consulting Group recently interviewed multiple early adopters of Oracle Enterprise Manager 12c and captured their finding in a white Paper "Real-World Benefits of Private Cloud: Early Adopters of Oracle Enterprise Manager 12c Report Agility and Productivity Gains".  Here is summary of the finding :- On October 25th at 10 AM pacific time, Kirk Bangstad from the Crimson Consulting group will join us in a live webcast and share what learnt from the early adopters of Oracle Enterprise Manager 12c. Don't miss this chance to hear how private clouds could impact your business and ask questions from our experts. Webcast: Real-World Benefits of Private Cloud Early Adopters of Oracle Enterprise Manager 12c Report Agility and Productivity Benefits Date: Thursday, October 25, 2012 Time: 10:00 AM PDT | 1:00 PM EDT Register Today All attendees will receive the White Paper: Real-World Benefits of Private Cloud: Early Adopters of Oracle Enterprise Manager 12c Report Agility and Productivity Gains. Stay Connected Twitter |  Face book |  You Tube |  Linked in |  Newsletter

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  • Change the Log Level of Node Manager.

    - by adejuanc
    This is useful to troubleshoot issues related to Node Manager, such as problems starting a Managed Server or reasons a server could be (re)started. To change the Log Level of Node Manager, you need to edit the nodemanager.properties file. This is usually located at: <MIDDLEWARE_HOME>/wlserver_10.3/common/nodemanager What you need to modify is property: ...LogLevel=INFO... Information about the appropriate values for this property is available in the Node Manager Documentation at 10.3 WebLogic Documentation (and in further releases) which states: LogLevel: Severity level of logging used for the Node Manager log. Node Manager uses the same logging levels as WebLogic Server. Default value: INFO However, this is incorrect. WLS has its own implementation of LogLevel, but Node Manager uses the standard Log Level from the java.util.logging.Level class. Therefore, the possible values for Node Manager LogLevel, in descending order are: SEVERE (highest value) WARNING INFO CONFIG FINE FINER FINEST (lowest value) The highest value provides only messages at the severe level. The warning level provides warning messages and severe messages, and so on. Besides those levels, ALL and OFF are also accepted. For example, if you only want Severe messages to be logged, select SEVERE. If you need the most detailed tracing available, select FINEST. For more information on what it will log at each level, please read the Java SE API for LoggingLevel.

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  • SQL (mySQL) update some value in all records processed by a select

    - by jdmuys
    I am using mySQL from their C API, but that shouldn't be relevant. My code must process records from a table that match some criteria, and then update the said records to flag them as processed. The lines in the table are modified/inserted/deleted by another process I don't control. I am afraid in the following, the UPDATE might flag some records erroneously since the set of records matching might have changed between step 1 and step 3. SELECT * FROM myTable WHERE <CONDITION>; # step 1 <iterate over the selected set of lines. This may take some time.> # step 2 UPDATE myTable SET processed=1 WHERE <CONDITION> # step 3 What's the smart way to ensure that the UPDATE updates all the lines processed, and only them? A transaction doesn't seem to fit the bill as it doesn't provide isolation of that sort: a recently modified record not in the originally selected set might still be targeted by the UPDATE statement. For the same reason, SELECT ... FOR UPDATE doesn't seem to help, though it sounds promising :-) The only way I can see is to use a temporary table to memorize the set of rows to be processed, doing something like: CREATE TEMPORARY TABLE workOrder (jobId INT(11)); INSERT INTO workOrder SELECT myID as jobId FROM myTable WHERE <CONDITION>; SELECT * FROM myTable WHERE myID IN (SELECT * FROM workOrder); <iterate over the selected set of lines. This may take some time.> UPDATE myTable SET processed=1 WHERE myID IN (SELECT * FROM workOrder); DROP TABLE workOrder; But this seems wasteful and not very efficient. Is there anything smarter? Many thanks from a SQL newbie.

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  • Multi-table Update(MySQL)

    - by smokinguns
    Hey all, I have a question regarding multi-table update(MySQL). Consider table t1 and t2. The PKEY for t1 is 'tid' which is a foreign Key in t2. There is a field "qtyt2" in t2 which depends on a field called "qtyt1" in table t1. Consider the foll SQL statement: UPDATE t2,t1 SET t2.qtyt2=IF(( t2.qtyt2- t1.qtyt1 )<0,0,( t2.qtyt2- t1.qtyt1 ) ), t1.qtyt1 ="Some value.." where t2.tid="some value.." AND t2.tid=t1.tid In this example qtyt2 depends on qtyt1 for update and the latter itself is updated.Now the result should return 2 if two rows are updated. Is there a guarantee that the fields will be updated in the order in which they appear in the statement( first qtyt2 will be set and then qtyt1).Is it possible that qtyt1 will be set first and then qtyt2? Is the order of tables in the statement important (UPDATE t2, t1 or UPDATE t1,t2)? I found that if I wrote "UPDATE t1,t2" then only t1 would get updated, but on changing the statement to "UPDATE t2,t1" everything worked correctly.

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  • select for update problem in jdbc

    - by kartiku
    I'm having a problem with select for update in jdbc. The table i'm trying to update is the smalldb table, i'm having problems-- i'm using select for update which does a lock on the selected row the update statement is -- String updateQ = "UPDATE libra.smalldb SET hIx = ? WHERE name = ?"; the select statement is -- rs = stmt1.executeQuery("SELECT hIx FROM libra.smalldb for update"); rs0 = stmt2.executeQuery("SELECT name,aff FROM libra.smalldb"); the second statement is because i need those fields as well. Here is the complete code -- import java.sql.*; import java.util.ArrayList; import java.util.Collections; public class Jdbcexample1 { /** * @param args */ public static void main(String[] args) { Connection con = null; try { Class.forName("com.mysql.jdbc.Driver").newInstance(); con = DriverManager.getConnection("jdbc:mysql:///test", "root", "*****"); //String url = "jdbc:msql://200.210.220.1:1114/Demo"; //Connection conn = DriverManager.getConnection(url,"",""); Statement stmt1 = con.createStatement(); Statement stmt2 = con.createStatement(); Statement stmt3 = con.createStatement(); Statement stmt4 = con.createStatement(); ResultSet rs0; ResultSet rs; ResultSet rs1; ResultSet rs2; String name; String hIx; int hIxInt; StringBuffer sb = new StringBuffer(); String affiliationSmall; ArrayList<String> affiliation = new ArrayList<String>(); ArrayList<Float> matchValues = new ArrayList<Float>(); ArrayList<Integer> hixValues = new ArrayList<Integer>(); ArrayList<Integer> idValues = new ArrayList<Integer>(); boolean moreFlag = false; String queryString; int tmpIdx; String name1; //get the hix at that index where the similarity is maximum int tmpHidx = 0; int tmpHix = 0; int id = 0; int count; int tmpidIdx = 0; //rs = stmt.executeQuery("SELECT id FROM libra.researchint WHERE id = 910887"); // Get name, affiliation , hIx from smalldb //rs = stmt1.executeQuery("SELECT name,aff,hIx FROM libra.smalldb"); // String cursorName = "OUR_CURSOR"; // stmt1.setCursorName(cursorName); //rs = stmt1.executeQuery("SELECT name,aff,hIx FROM libra.smalldb for update"); rs = stmt1.executeQuery("SELECT hIx FROM libra.smalldb for update"); rs0 = stmt2.executeQuery("SELECT name,aff FROM libra.smalldb"); while ( rs.next() && rs0.next() ) { //String lastName = rs.getString("id"); hIx = rs.getString("hIx"); hIxInt = Integer.parseInt(hIx); //if hIx if (hIxInt==-1) continue; //name = rs.getString("name"); name = rs0.getString("name"); name1 = new String(name); System.out.println(name); //affiliationSmall = rs.getString("aff"); affiliationSmall = rs0.getString("aff"); //name = "\"" +name+ "\""; // Get matching names from large faculty table //String queryString = "SELECT id,name,hIx FROM libra.faculty WHERE name = " +name; //name = does not work names are similar but not same (in faculty and // smalldb) String query = "SELECT id,name,hIx FROM libra.faculty WHERE name like ?"; //String query = "SELECT id,name,hIx FROM libra.faculty for update of hIx WHERE name like ?"; PreparedStatement prepStmt = con.prepareStatement(query); String[] nameArr = name.split(" "); StringBuffer tmpSb = new StringBuffer(); for(int idx = 0;idx<nameArr.length;idx++) { tmpSb.append(nameArr[idx] + "%"); } name = tmpSb.toString(); prepStmt.setString(1, name); rs1 = prepStmt.executeQuery(); //Try to get matching names from faculty big db //Execute the query on faculty table //rs1 = stmt2.executeQuery(queryString); if(rs1.isClosed()) continue; count = 0; matchValues.clear(); affiliation.clear(); while(rs1.next()) { //name = rs1.getString("name"); id = Integer.parseInt(rs1.getString("id")); //idValues.add(id); tmpHix = Integer.parseInt(rs1.getString("hIx")); queryString = "SELECT aff FROM libra.affiliation WHERE id = "+id; rs2 = stmt3.executeQuery(queryString); //affiliation = rs1.getString("aff"); sb.delete(0, sb.length()); while (rs2.next()) { //Concatenate it to the same string using a stringbuffer sb.append(rs2.getString("aff")); //affiliation.add(rs2.getString("aff")); } affiliation.add(sb.toString()); count++; // if(count1) // { // moreFlag = true; // //Call fuzzy match function, store the distance values and select the // //affiliation that has the minimum distance from affiliationSmall // // //problem is here, affiliation.get Index: 2, Size: 2 // // matchValues.add(fuzzyMatch(affiliationSmall,affiliation.get(count))); // hixValues.add(tmpHix); // idValues.add(id); // } }//end of while rs1 -> faculty rs1.close(); int idx = 0; if(count>1) { moreFlag = true; //Call fuzzy match function, store the distance values and select the //affiliation that has the minimum distance from affiliationSmall //problem is here, affiliation.get Index: 2, Size: 2 matchValues.add(fuzzyMatch(affiliationSmall,affiliation.get(idx))); hixValues.add(tmpHix); idValues.add(id); idx++; } if(moreFlag) { Object obj = Collections.max(matchValues); float maxVal = Float.parseFloat(obj.toString()); //int tmpIdx = matchValues.indexOf(new Float(maxVal)); //get the index at which similarity between affiliation strings is maximum, //as returned by fuzzyMatch //int tmpIdx = matchValues.indexOf(maxVal); tmpIdx = matchValues.indexOf(maxVal); //get the hix at that index where the similarity is maximum //int tmpHidx = hixValues.get(tmpIdx); tmpHidx = hixValues.get(tmpIdx); tmpidIdx = idValues.get(tmpIdx); //update the smalldb table String updateQ = "UPDATE libra.smalldb SET hIx = ? WHERE name = ?"; //String updateQ = "UPDATE libra.smalldb SET hIx = ? WHERE current of "+cursorName; //PreparedStatement prepStmt1 = con.prepareStatement("UPDATE libra.smalldb SET hIx = ? WHERE current of "+cursorName); PreparedStatement prepStmt1 = con.prepareStatement(updateQ); //PreparedStatement prepStmt1 = con.prepareStatement(updateQ); prepStmt1.setString(2, name1); prepStmt1.setString(1, Integer.toString(tmpHidx)); prepStmt1.executeUpdate(updateQ); //prepStmt1.execute(); //stmt4.executeUpdate(updateQ); }//end of if //For matching names get the affiliation based on id from affiliation table //con.close(); //System.out.println(lastName); System.out.println(name); }//end of while rs -> smalldb rs.close(); // String updateQ = "UPDATE libra.smalldb1 SET hIx = "+Integer.toString(tmpHidx)+ "WHERE id = "+Integer.toString(tmpidIdx); // stmt4.executeUpdate(updateQ); con.close(); } catch (Exception e) { System.err.println("Got an exception! "); System.err.println(e.getMessage()); e.printStackTrace(); } } public static float fuzzyMatch(String affiliationSmall, String affiliation) { //float distance = 0; String[] temp = null; temp = affiliationSmall.split(" "); int index; //int index1 = affiliation.indexOf(affiliationSmall); int matchCount = 0; for (int idx = 0;idx<temp.length; idx++) { index = affiliation.indexOf(temp[idx]); if (index!=-1) { matchCount++; } } float tmpFloat = matchCount/temp.length; //int[] aff1= new int[affiliation1.length()]; //int[] aff2 = new int[affiliation2.length()]; return tmpFloat; } } i think it is because of the second select statement (rs0) Here is the error- Got an exception! You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '?' at line 1 com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '?' at line 1 at sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method) at sun.reflect.NativeConstructorAccessorImpl.newInstance(Unknown Source) at sun.reflect.DelegatingConstructorAccessorImpl.newInstance(Unknown Source) at java.lang.reflect.Constructor.newInstance(Unknown Source) at com.mysql.jdbc.Util.handleNewInstance(Util.java:409) at com.mysql.jdbc.Util.getInstance(Util.java:384) at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:1054) at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:3562) at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:3494) at com.mysql.jdbc.MysqlIO.sendCommand(MysqlIO.java:1960) at com.mysql.jdbc.MysqlIO.sqlQueryDirect(MysqlIO.java:2114) at com.mysql.jdbc.ConnectionImpl.execSQL(ConnectionImpl.java:2690) at com.mysql.jdbc.StatementImpl.executeUpdate(StatementImpl.java:1648) at com.mysql.jdbc.StatementImpl.executeUpdate(StatementImpl.java:1567) at Jdbcexample1.main(Jdbcexample1.java:184)

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  • Cisco IP Phone Call Manager handle events

    - by dankyy1
    I 'm new on cisco IP Phones. I have a cisco call manager system also a 7970 Ip phone. The phone cominicates with Cisco Call Manager application. I want to listen events when user logon and send some commands to phone., Is there any idea about this task? Is there a way to got events from cisco call manager or i have to listen up the ports of Ip phone? thanks

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  • Problem with UPDATE statement in stored-procedure in Oracle Database

    - by MKP
    Hello, I have stored-procedure in Oracle database like this: create or replace PROCEDURE EDYTUJ_PRACOWNIKA (PR_IMIE IN VARCHAR2, PR_NAZWISKO IN VARCHAR2, PR_PENSJA IN FLOAT, PR_PRZELOZONY IN NUMBER, PR_ODDZIAL IN NUMBER, PRAC_ID IN NUMBER) AS tmpPensja FLOAT := 0; tmpPrzel NUMBER := 0; BEGIN select przelozony into tmpPrzel from pracownik where id = PRAC_ID; IF(tmpPrzel IS NOT NULL) THEN select pensja into tmpPensja from pracownik where id = tmpPrzel; IF(tmpPensja < 1150) THEN UPDATE PRACOWNIK SET pensja = 1000 WHERE id = tmpPrzel; ELSE UPDATE PRACOWNIK SET pensja = pensja - 150 WHERE id = tmpPrzel; (4) END IF; END IF; IF(PR_PRZELOZONY > 0) THEN UPDATE PRACOWNIK SET imie = PR_IMIE, nazwisko = PR_NAZWISKO, pensja = PR_PENSJA, przelozony = PR_PRZELOZONY, oddzial = PR_ODDZIAL WHERE id = PRAC_ID; (2) select pensja into tmpPensja from pracownik where id = PR_PRZELOZONY; IF(tmpPensja > 4850) THEN UPDATE PRACOWNIK SET pensja = 5000 WHERE id = PR_PRZELOZONY; ELSE UPDATE PRACOWNIK SET pensja = pensja + 150 WHERE id = PR_PRZELOZONY; (1) END IF; ELSE UPDATE PRACOWNIK SET imie = PR_IMIE, nazwisko = PR_NAZWISKO, pensja = PR_PENSJA, przelozony = NULL, oddzial = PR_ODDZIAL WHERE ID = PRAC_ID; (3) END IF; END; where przelozony and pensja are columns in pracownik table. And I have problem that when running procedure with parameters that provide that line marked with "(1)" (there is the same problem with line marked with "(4)") should be executed that update statement don't have any effect. What's more statements in lines marked with "(2)" and "(3)" works fine. I have no ideas how to fix it. Thank you in advance for your help.

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  • Visual Studio and TFS for Test manager

    - by bisjom
    Hi I have Visual Studio test manager installed in my machine, I have TFS Server installed on another server, I want to connect to that TFS server with new VS 2010. Do I need to install the Visual studio 2010 full version or just the test manager? I installed test manager and its asking a URL to add and I added the one we already have , but its not connecting to that site. Do I need to isntall Full version and TFS on same machine?? Please help Thanks

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  • Update table instantly or “Bulk” Update in database later? And is it advisable?

    - by Mestika
    Hi, I have a question regarding a semi-constant update in a database. In short it is regarding a checkout function on a web page, which each time the checkout function is evoked it do five steps. I want to try to optimize this function and have my eye on a step where I update a table each time the checkout is performed. I take the information retrieved from the shopping cart and then update the table in question. I do have some indexes on the table, the gain from those are greater than leaving them so this is a cost I’m willing to take. Now, my question is. Could it in some way regarding to performance be better to not update the table instantly but collect every checkout items and save them in some way (maybe in a file) and then at a specific time (or several times) at day take this file and then update the table with the new information. Then I started thinking about if there was a possibility to use some sort of Bulk Update to take a file, hashmap, array (or?) and then update it. And I’m using IBM DB2 version 9.7 Mestika

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  • Oracle Enterprise Manager Logs

    - by idea_
    Hi, I'm attempting to investigate the root cause of the following error which occurs each time a users call an Oracle 10g Forms applet: FRM-92102: A network error has occurred. The Forms Client has attempted to reestablish its connection to the Server 1 time(s) without success. Please check the network connection and try again later. Details... Java Exception: java.io.IOException: Connection failure with 503 This error remained after restarting all my system components: HTTP_Server, OC4J_BI_Forms, Web Cache, Reports Server, etc. The only way to clear this issue was to restart the server entirely. During the downtime, web pages were rendered with the PL/SQL cartridge and being served, so it appears as though this was isolated to forms. Does anybody know which log files may provide clues here? Any help would be much appreciated :) Update: If somebody can provide me with a way or reference to increase the capacity of my web server to minimize these errors, I will accept this as the solution.

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  • SQL: Using a CASE Statement to update 1000 rows at once

    - by SoLoGHoST
    Ok, I would like to use a CASE STATEMENT for this, but I am lost with this. Basically, I need to update a ton of rows, but just on the "position" column. I need to update all "position" values from 0 - count(position) for each id_layout_position column per id_layout column. OK, here is a pic of what the table looks like: Now let's say I delete the circled row, this will remove position = 2 and give me: 0, 1, 3, 5, 6, 7, and 4. But I want to add something at the end now and make sure that it has the last possible position, but the positions are already messed up, so I need to reorder them like so before I insert the new row: 0, 1, 2, 3, 4, 5, 6. But it must be ordered by lowest first. So 0 stays at 0, 1 stays at 1, 3 gets changed to 2, the 4 at the end gets changed to a 3, 5 gets changed to 4, 6 gets changed to 5, and 7 gets changed to 6. Hopefully you guys get the picture now. I'm completely lost here. Also, note, this table is tiny compared to how fast it can grow in size, so it needs to be able to do this FAST, thus I was thinking on the CASE STATEMENT for an UPDATE QUERY. Here's what I got for a regular update, but I don't wanna throw this into a foreach loop, as it would take forever to do it. I'm using SMF (Simple Machines Forums), so it might look a little different, but the idea is the same, and CASE statements are supported... $smcFunc['db_query']('', ' UPDATE {db_prefix}dp_positions SET position = {int:position} WHERE id_layout_position = {int:id_layout_position} AND id_layout = {int:id_layout}', array( 'position' => $position++, 'id_layout_position' => (int) $id_layout_position, 'id_layout' => (int) $id_layout, ) ); Anyways, I need to apply some sort of CASE on this so that I can auto-increment by 1 all values that it finds and update to the next possible value. I know I'm doing this wrong, even in this QUERY. But I'm totally lost when it comes to CASES. Here's an example of a CASE being used within SMF, so you can see this and hopefully relate: $conditions = ''; foreach ($postgroups as $id => $min_posts) { $conditions .= ' WHEN posts >= ' . $min_posts . (!empty($lastMin) ? ' AND posts <= ' . $lastMin : '') . ' THEN ' . $id; $lastMin = $min_posts; } // A big fat CASE WHEN... END is faster than a zillion UPDATE's ;). $smcFunc['db_query']('', ' UPDATE {db_prefix}members SET id_post_group = CASE ' . $conditions . ' ELSE 0 END' . ($parameter1 != null ? ' WHERE ' . (is_array($parameter1) ? 'id_member IN ({array_int:members})' : 'id_member = {int:members}') : ''), array( 'members' => $parameter1, ) ); Before I do the update, I actually have a SELECT which throws everything I need into arrays like so: $disabled_sections = array(); $positions = array(); while ($row = $smcFunc['db_fetch_assoc']($request)) { if (!isset($disabled_sections[$row['id_group']][$row['id_layout']])) $disabled_sections[$row['id_group']][$row['id_layout']] = array( 'info' => $module_info[$name], 'id_layout_position' => $row['id_layout_position'] ); // Increment the positions... if (!is_null($row['position'])) { if (!isset($positions[$row['id_layout']][$row['id_layout_position']])) $positions[$row['id_layout']][$row['id_layout_position']] = 1; else $positions[$row['id_layout']][$row['id_layout_position']]++; } else $positions[$row['id_layout']][$row['id_layout_position']] = 0; } Thanks, I know if anyone can help me here it's definitely you guys and gals... Anyways, here is my question: How do I use a CASE statement in the first code example, so that I can update all of the rows in the position column from 0 - total # of rows found, that have that id_layout value and that id_layout_position value, and continue this for all different id_layout values in that table? Can I use the arrays above somehow? I'm sure I'll have to use the id_layout and id_layout_position values for this right? But how can I do this? Ok, guy, I get an error, saying "Hacking Attempt" with the following code: // Updating all positions in here. $smcFunc['db_query']('', ' SET @pos = 0; UPDATE {db_prefix}dp_positions SET position=@pos:=@pos+1 ORDER BY id_layout_position, position', array( ) ); Am I doing something wrong? Perhaps SMF has safeguards against this approach?? Perhaps I need to use a CASE STATEMENT instead?

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  • IIS Manager - Connect to Another Server (Win7 to Win2008 server)

    - by Matt
    I am running Windows 7 Ultimate. If I open up IIS Manager, I see a list of "connections" on the left hand side. In previous versions, I would be able to select an option to "connect to another server" or "connect to another machine", but there is no such option visible anywhere here. The only thing in the list is my local machine. Even in the address bar, if I manually type in the server location (\servername, even tried just servername), nothing happens (it just reverts back to my current local computer) The documentation at http://technet.microsoft.com/en-us/library/cc732466%28WS.10%29.aspx seems to imply the very same steps... but there is just no button or menu option anywhere to do this. Am I missing something? I'm not even seeing a grayed out menu option. EDIT: Under the "File" menu, I see 2 options: Save Connections (grayed out) Exit Under the "Connections" pane, I see 1 button, grayed out. When I hover the mouse, it simply says "Up", appears to be usable if I browse into an element in my local computers IIS settings If I right click inside the pane itself, I see Refresh Add website (to the current host) Start Stop Rename Switch to Content View UPDATE: I downloaded and installed the Remote Server Administration tools from http://www.microsoft.com/downloads/details.aspx?FamilyID=7D2F6AD7-656B-4313-A005-4E344E43997D&displaylang=en, and I enabled everything listed under "Remote Server Administration Tools" under "Turn Windows Features On or Off". Still nothing.

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  • Looking for a "light" compositing manager for GNOME

    - by detly
    I have an HP Pavilion DM3 (graphics is nVidia GeForce G105M), running Debian Squeeze with GNOME 2.30. My preference for DE is Gnome + Metacity + Nautilus. I'd like to use Docky, but it requires compositing. So I'm looking for a relatively "light" compositing manager. I realise that "light" is ambiguous, but I basically want something that won't chew through my notebook's batteries because of CPU or GPU usage. I know that Metacity is capable of compositing, but as far as I'm aware it's still testing. Some people report that it's smooth and lightweight, others claim that it eats up processor time. I've also seen references to a problem with nVidia, but no actual details. I'm not averse to Compiz, but I haven't used it before and I don't know what to expect in terms of "weight." And maybe there's something else I haven't heard of. So can anyone recommend anything? Or dispel my idea that Metacity is not the right tool for the job? (Originally posted on GNOME forums.)

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  • "Steam needs to be online to update" - 404 fetching *_osx.zip.*

    - by Chris Boyle
    Since yesterday evening, when I launch Steam on OSX, a self-update progress bar appears instead (at 0 of 30MB or so). This bar does not advance, an error dialog appears: Steam needs to be online to update Please confirm your network connection and try again. The app then exits. This happens whether wifi or ethernet or both are connected, and pings to the outside world succeed throughout. If I look at the logs in Console, they are very similar to this example (though that's not mine). Specifically: Success! http://store.steampowered.com/public/client/steam_client_osx?date=718277 [...] Failed! http://cdn.store.steampowered.com/public/client/breakpad_osx.zip.27f59114a86fcd50533e1d7b128f9300947f9969 Failed! http://cdn.store.steampowered.com/public/client/steam_osx.zip.11a99384214805f2dd3be5084ba6be61d662f8ac Failed! http://cdn.store.steampowered.com/public/client/miles_osx.zip.d9fb546541f59c1fdd03962a605236b1021abab8 Requesting the first URL successfully returns some data including the filenames of the latter three, and requesting any of those gives me a 404 (I've tried multiple clients on multiple continents). Searches on Google and Twitter show about 10-20 others having this problem in the past 24 hours, but hardly the angry mob I'd expect if the problem affected all Steam OSX users. Things that have already been tried with no effect: Switching between wifi and ethernet. Killing all Steam processes including ipcserver. Moving the ~/Library/Application Support/Steam/registry.vdf file away. Requesting those URLs with other clients and from other locations. Interesting: that first URL with the date parameter returns the same content even without that parameter (thus would lead to the same 404s) suggesting that the problem is not necessarily specific to coming from a particular currently-installed version of Steam.

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  • How to avoid Windows Genuine Advantage for an XP update?

    - by hlovdal
    I am about to apply updates to a windows xp installation I have not booted in a couple of years. When going to update.microsoft.com, it forced me first to accept an activex installation and now it wants me to install wga: Windows Update To use this latest version of Windows Update, you will need to upgrade some of its components. This version provides you with the following enhancements to our service: <... useless list of "advantages" ... Details Windows Genuine Advantage Validation Tool (KB892130) 1.1 MB , less than 1 minute The Windows Genuine Advantage Validation Tool enables you to verify that your copy of Microsoft Windows is genuine. The tool validates your Windows installation by checking Windows Product Identification and Product Activation status. Update for Windows XP (KB898461) 477 KB , less than 1 minute This update installs a permanent copy of Package Installer for Windows to enable software updates to have a significantly smaller download size. The Package Installer facilitates the install of software updates for Microsoft Windows operating systems and other Microsoft products. After you install this update, you may have to restart your system. Total: 1.5 MB , less than 1 minute I have heard nothing but bad things about wga, and I absolutely do not want it installed on my system (this answer seems to give some options). Searching for "windows xp" at microsoft's web pages brought up this page which says Windows XP Service Pack 3 Network Installation Package for IT Professionals and Developers Brief Description This installation package is intended for IT professionals and developers downloading and installing on multiple computers on a network. If you're updating just one computer, please visit Windows Update at http://update.microsoft.com . ... File Name: WindowsXP-KB936929-SP3-x86-ENU.exe I am currently downloading this file. Will installing this bring my installation up to date with security updates? What about later updates whenever a new problem is discovered, how can i update without using wga?

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  • Mac "Steam needs to be online to update" - 404 fetching *_osx.zip.*

    - by Chris Boyle
    Since yesterday evening, when I launch Steam on OSX, a self-update progress bar appears instead (at 0 of 30MB or so). This bar does not advance, an error dialog appears: Steam needs to be online to update Please confirm your network connection and try again. The app then exits. This happens whether wifi or ethernet or both are connected, and pings to the outside world succeed throughout. If I look at the logs in Console, they are very similar to this example (though that's not mine). Specifically: Success! http://store.steampowered.com/public/client/steam_client_osx?date=718277 [...] Failed! http://cdn.store.steampowered.com/public/client/breakpad_osx.zip.27f59114a86fcd50533e1d7b128f9300947f9969 Failed! http://cdn.store.steampowered.com/public/client/steam_osx.zip.11a99384214805f2dd3be5084ba6be61d662f8ac Failed! http://cdn.store.steampowered.com/public/client/miles_osx.zip.d9fb546541f59c1fdd03962a605236b1021abab8 Requesting the first URL successfully returns some data including the filenames of the latter three, and requesting any of those gives me a 404 (I've tried multiple clients on multiple continents). Searches on Google and Twitter show about 10-20 others having this problem in the past 24 hours, but hardly the angry mob I'd expect if the problem affected all Steam OSX users. Things that have already been tried with no effect: Switching between wifi and ethernet. Killing all Steam processes including ipcserver. Moving the ~/Library/Application Support/Steam/registry.vdf file away. Requesting those URLs with other clients and from other locations. Interesting: that first URL with the date parameter returns the same content even without that parameter (thus would lead to the same 404s) suggesting that the problem is not necessarily specific to coming from a particular currently-installed version of Steam.

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  • Updating PHP on Linux - "No Packages marked for Update"?

    - by Aristotle
    I'm very new to server-administration, but I was thinking the task of updating PHP to 5.2+ should be relatively simple. Online I found that the following was allegedly sufficient to do this: yum update php But when I run this, the following is output: [root@ip-XXX-XXX-XXX-XXX /]# php -v PHP 5.1.6 (cli) (built: Jan 13 2010 17:13:05) Copyright (c) 1997-2006 The PHP Group Zend Engine v2.1.0, Copyright (c) 1998-2006 Zend Technologies [root@ip-XXX-XXX-XXX-XXX /]# yum update php Loaded plugins: fastestmirror Determining fastest mirrors * addons: p3plmirror02.prod.phx3.secureserver.net * base: p3plmirror02.prod.phx3.secureserver.net * extras: p3plmirror02.prod.phx3.secureserver.net * turbopanel-base: p3plmirror02.prod.phx3.secureserver.net * turbopanel-centos5: p3plmirror02.prod.phx3.secureserver.net * update: p3plmirror02.prod.phx3.secureserver.net addons | 951 B 00:00 addons/primary | 201 B 00:00 base | 2.1 kB 00:00 base/primary_db | 1.6 MB 00:00 extras | 1.1 kB 00:00 extras/primary | 107 kB 00:00 extras 325/325 turbopanel-base | 951 B 00:00 turbopanel-base/primary | 72 kB 00:00 turbopanel-base 494/494 turbopanel-centos5 | 951 B 00:00 turbopanel-centos5/primary | 2.1 kB 00:00 turbopanel-centos5 8/8 update | 1.9 kB 00:00 update/primary_db | 463 kB 00:00 Setting up Update Process No Packages marked for Update [root@ip-XXX-XXX-XXX-XXX /]# php -v PHP 5.1.6 (cli) (built: Jan 13 2010 17:13:05) Copyright (c) 1997-2006 The PHP Group Zend Engine v2.1.0, Copyright (c) 1998-2006 Zend Technolog [root@ip-XXX-XXX-XXX-XXX /]# No Packages marked for Update [root@ip-XXX-XXX-XXX-XXX /]# php -v bash: No: command not found [root@ip-XXX-XXX-XXX-XXX /]# [root@ip-XXX-XXX-XXX-XXX /]# php -v bash: [root@ip-XXX-XXX-XXX-XXX: command not found [root@ip-XXX-XXX-XXX-XXX /]# PHP 5.1.6 (cli) (built: Jan 13 2010 17:13:05) bash: syntax error near unexpected token `(' [root@ip-XXX-XXX-XXX-XXX /]# Copyright (c) 1997-2006 The PHP Group bash: syntax error near unexpected token `c' [root@ip-XXX-XXX-XXX-XXX /]# Zend Engine v2.1.0, Copyright (c) 1998-2006 Zend Technologies bash: syntax error near unexpected token `(' [root@ip-XXX-XXX-XXX-XXX /]# My PHP version is 5.1.6 before, and after running the command. Am I being too naive here with this update process? Is there a more verbose route that is necessary for me to take?

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  • Accessing SSRS Report Manager on Windows 7 and Windows 2008 Server

    - by Testas
      Here is a problem I was emailed last night   Problem   SSRS 2008 on Windows 7 or Windows 2008 Server is configured with a user account that is a member of the administrator's group that cannot access report Manager without running IE as Administrator and adding  the SSRS server into trusted sites. (The Builtin administrators account is by default made a member of the System Administrator and Content Manager SSRS roles).   As a result the OS limits the use of using elevated permissions by removing the administrator permissions when accessing applications such as SSRS     Resolution - Two options   Continue to run IE as administrator, you must still add the report server site to trusted sites Add the site to trusted sites and manually add the user to the system administrator and content manager role Open a browser window with Run as administrator permissions. From the Start menu, click All Programs, right-click Internet Explorer, and select Run as administrator. Click Allow to continue. In the URL address, enter the Report Manager URL. Click Tools. Click Internet Options. Click Security. Click Trusted Sites. Click Sites. Add http://<your-server-name>. Clear the check box Require server certification (https:) for all sites in this zone if you are not using HTTPS for the default site. Click Add. Click OK. In Report Manager, on the Home page, click Folder Settings. In the Folder Settings page, click Security. Click New Role Assignment. Type your Windows user account in this format: <domain>\<user>. Select Content Manager. Click OK. Click Site Settings in the upper corner of the Home page. Click security. Click New Role Assignment. Type your Windows user account in this format: <domain>\<user>. Select System Administrator. Click OK. Close Report Manager. Re-open Report Manager in Internet Explorer, without using Run as administrator.   Problems will also exist when deploying SSRS reports from Business Intelligence Development Studio (BIDS) on Windows  7 or Windows 2008, therefore you should run Business Intelligence Development Studio as Administor   information on this issue can be found at <http://msdn.microsoft.com/en-us/library/bb630430.aspx>

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  • Oracle Enterprise Manager 12c webcast-ok

    - by lsarecz
    Az elmúlt hetekben sajnos kicsit hanyagoltam a blog írást. Igyekszem újraindítani, csakúgy mint kollégám. Elso bejegyzésként szeretném felhívni az üzemeltetés iránt érdeklodok figyelmét, hogy a héten több Oracle Enterprise Manager 12c webcast lesz, melyekre elozetes regisztráció szükséges az alábbi linkeken: Oracle Enterprise Manager 12c Automated Agent Deployment November 29. 17 óra Perform a Zero Downtime Upgrade to Oracle Enterprise Manager 12cNovember 30. 17 óra Oracle Enterprise Manager Ops Center: Global Systems Management Made EasyDecember 1. 19 óra

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  • Server 2008 R2 domain windows update strategy

    - by Joost Verdaasdonk
    Let me explain my question a bit. We are a small company that have now made the first move to a bigger network. For now the network contains of 5 servers 2008 R2 (dc,sql,web,etc..). Everything we need is now in place but for now we cannot afford to finish the network by implementing redundant systems. (secondary dc, dns, sql cluster, etc...) For some people this is hard to understand but this is the current situation. (and we are aware and will fix this when we can) Because we want to keep our system secure and up to date I've made sure that all systems are updated regularly. The problem is ofc that the nr of updates Microsoft rolls out that need a system reboot seam to occur more often. (maybe I'm wrong and it just feels like this) ;-) In our domain servers depend on each other for services (like SQL, WEB, or whatever) so just rebooting a server at will is NOT a good idea! For now I update all of them without rebooting at once. After all are up to date I bring them down in the order they are depended on each other. After this I reboot all of them in the inverse order. I understand ofc that if I DID have redundancy in my system that updating and rebooting would not be such a problem because the server task could be taken over by another node but this is something we generally need to add when we can. So my question is. If you read my above situation can you suggest me more Update strategies or general ideas that could help me do this process in a better / faster way? Thanks for your thoughts!

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  • Fedora 14 update probelem

    - by Marko
    How is everybody doin? :) Im having this problem with Fedora 14 update for last couple of weeks.. when I run yum update I get the following result: Running rpm_check_debug ERROR with rpm_check_debug vs depsolve: kernel-uname-r = 2.6.32.10-90.fc12.i686.PAE is needed by (installed) kmod-nvidia-2.6.32.10-90.fc12.i686.PAE-1:195.36.15-1.fc12.1.i686 kernel-uname-r = 2.6.32.16-150.fc12.i686.PAE is needed by (installed) kmod-nvidia-2.6.32.16-150.fc12.i686.PAE-1:195.36.31-1.fc12.2.i686 kernel-uname-r = 2.6.32.21-168.fc12.i686.PAE is needed by (installed) kmod-nvidia-2.6.32.21-168.fc12.i686.PAE-1:195.36.31-1.fc12.5.i686 kernel-uname-r = 2.6.32.10-90.fc12.i686.PAE is needed by (installed) kmod-nvidia-2.6.32.10-90.fc12.i686.PAE-1:195.36.15-1.fc12.1.i686 kernel-uname-r = 2.6.32.16-150.fc12.i686.PAE is needed by (installed) kmod-nvidia-2.6.32.16-150.fc12.i686.PAE-1:195.36.31-1.fc12.2.i686 kernel-uname-r = 2.6.32.21-168.fc12.i686.PAE is needed by (installed) kmod-nvidia-2.6.32.21-168.fc12.i686.PAE-1:195.36.31-1.fc12.5.i686 Please report this error in http://yum.baseurl.org/report ** Found 9 pre-existing rpmdb problem(s), 'yum check' output follows: VirtualBox-3.2-3.2.10_66523_fedora13-1.i686 has missing requires of libpython2.6.so.1.0 VirtualBox-3.2-3.2.10_66523_fedora13-1.i686 has missing requires of python(abi) = ('0', '2.6', None) 1:kmod-nvidia-2.6.32.10-90.fc12.i686.PAE-195.36.15-1.fc12.1.i686 has missing requires of kernel-uname-r = ('0', '2.6.32.10', '90.fc12.i686.PAE') 1:kmod-nvidia-2.6.32.16-150.fc12.i686.PAE-195.36.31-1.fc12.2.i686 has missing requires of kernel-uname-r = ('0', '2.6.32.16', '150.fc12.i686.PAE') 1:kmod-nvidia-2.6.32.21-168.fc12.i686.PAE-195.36.31-1.fc12.5.i686 has missing requires of kernel-uname-r = ('0', '2.6.32.21', '168.fc12.i686.PAE') mysql-workbench-gpl-5.2.28-1fc13.i386 has missing requires of libpython2.6.so.1.0 pysvn-1.7.2-1.fc13.i686 has missing requires of python(abi) = ('0', '2.6', None) system-config-display-2.2-1.fc12.i686 has missing requires of libpython2.6.so.1.0 system-config-display-2.2-1.fc12.i686 has missing requires of python(abi) = ('0', '2.6', None) does anybody have a similar issue?

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