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  • Why can't I connect to my home SSH (SFTP) server? What am I doing wrong?

    - by Rolo
    I am new to this topic of creating a SFTP server on one's computer. I would like to be able to access the folder on my Windows XP computer via SFTP from another computer or a phone. The following is what I have done so far: I have installed SSH Windows and everything is setup correctly because I can access it (the folder on my pc) via WinSCP. I however cannot access it from my phone. It doesn't connect. The phone can be on the same wireless network as the Windows XP computer, but I would prefer to be able to access this when not in the same network. Now, from what I have read and understood, the following is the information needed to connect: 1) Host Name: This would be my computer's ip address which I access by typing ipconfig in a cmd prompt (I access this easily on my computer because I simply put in localhost or 127.0.0.1) 2) Port Number: That would be port 22 (I have also added this to my router in the port forwarding section). 3) Username: This would be my Windows XP username. This however is my full name, including my middle initial followed by a period. I am wondering if this is maybe causing problems in accessing it from my phone, since the name has spaces and punctuation (the period). 4) Password: The password of my Windows XP computer Extra Info: When I say phone, I mean an Android phone and I am using an ftp / sftp app to access my pc via the phone's cellular network (I also tried the wireless, but that didn't work as well). I have tried more than one program. On one program it tells me Connection timed out and on another it tells me "timeout:socket is not established" Also, I know that I can use the site noip, but I prefer to connect this way first. Also, because I am new to this, I would like to look into what exactly noip is doing and if they would be seeing my files as they are transferred from phone to pc. Thanking you in advance for your help.

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  • apache front-end rewriting URL to different https ports?

    - by khedron
    Hi all, One of my users is having some trouble with forwarding to an internal web app from a public address. Everything worked fine for him when the situation was like this: front page: http://www.myexample.com/ public ref to internal app: http://www.example.com/app-8903/app.html secretly goes to: http://secret.example.com:8903/app-8903/app.html This is to say, my user is providing the very last URL, with the port information duplicated in the URL base, and they were using that to give a public face that hid both the port and the internal machine name. You could still read the port in the URL base if you looked, but the obvious reference and machine name were hidden. Doing it this way, he could have several different instances of the application running on secret.example.com with different ports, and on the front end it just looked like it was changing the URL directory/base. Now the user wants to do the same thing over https:, and the people helping him with apache config say it can't be done. Is that so? Without being there to tinker with the configuration myself, I'm not sure what his IT people have tried, but reading through the apache2 SSL FAQ and other docs, it seems like it should be possible to rewrite URLs to different ports and still use https:.

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  • How to prevent response to who-has requests on virtual eth interface?

    - by user42881
    Hi, we use small embedded X86 linux servers equipped with a single physical ethernet port as a gateway for an IP video surveillance application. Each downstream IP cam is mapped to a separate virtual IP address like this: real eth0 IP address= 192.168.1.1, camera 1 (eth0:1) =192.168.1.61, camera 2 (eth0:2) =192.168.1.62, etc. etc. all on the same eth0 physical port. This approach works well, except that a specific third-party windows video recording application running on a separate PC on the same LAN, automatically pings the virtual IPs looking for unique who-has responses on system startup and, when it gets back the same eth0 MAC address for each virtual interface, freaks out and won't allow us to subsequently manually enter those addresses. The windows app doesn't mind, tho, if it receives no answer to the who-has ping. My question - how can we either (a) shut off the who-has responses just for the virtual eth0:x interfaces while keeping them for the primary physical eth0 port, or, in the alternative, spoof a valid but different MAC address for each virtual interface? Thanks!

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  • IPtables and Remote Desktop with Proxy

    - by Sebastian
    So I setup a windows 2008 web server R2 on VirtualBox. Currently using Bridged Network. I can remote desktop to the machine hosting the VM (10.0.0.183) but cannot remote desktop to the VM itself (10.0.0.195). The remote port on the VM set to 5003. VM setup to accept remote connections (windows side). We also use a proxy for our internet, and I added these rules under NAT. (centOS 5) on our proxy box. -A INPUT -p tcp --dport 3389 -j ACCEPT -A REROUTING -i ppp0 -p tcp --dport 3389 -j REDIRECT --to-port 5003 -A FORWARD -d 10.0.0.195 --dport 5003 -m state --state NEW,ESTABLISHED,RELATED -j ACCEPT I've been trying for hours and hours and just cannot get it to work. I also used freedns so that we can use a domain name to connect too this VM over the internet. (the DNS points to our external IP address). If we don't get this right we will have to purchase a PPoE from an ISP to connect to this VM remotely, but I know that there is an alternative route if I can just get this port forwarding right!

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  • How to decouple development server from Internet?

    - by intoxicated.roamer
    I am working in a small set-up where there are 4 developers (might grow to 6 or 8 in cuople of years). I want to set-up an environment in which developers get an internet access but can not share any data from the company on internet. I have thought of the following plan: Set-up a centralized git server (Debian). The server will have an internet access. A developer will only have git account on that server, and won't have any other account on it. Do not give internet access to developer's individual machine (Windows XP/Windows 7). Run a virtual machine (any multi-user OS) on the centralized server (the same one on which git is hosted). Developer will have an account on this virtual machine. He/she can access internet via this virtual machine. Any data-movement between this virtual machine and underlying server, as well as any of the developer's machine, is prohibited. All developers require USB port on their local machine, so that they can burn their code into a microcontroller. This port will be made available only to associated software that dumps the code in a microcontroller (MPLAB in current case). All other softwares will be prohibited from accessing the port. As more developers get added, providing internet support for them will become difficult with this plan as it will slow down the virtual machine running on the server. Can anyone suggest an alternative ? Are there any obvious flaws in the above plan ? Some key details of the server are as below: 1) OS:Debian 2) RAM: 8GB 3) CPU: Intel Xeon E3-1220v2 4C/4T

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  • MAC-Address based routing

    - by d-fens
    Here is what i want to do: I have a bunch of systems, some might have the same Public-IP, i disable ARP. I have a Firewall (either IP Layer or bridge-FW) between these systems and the internet. Depending on the destination port of incoming IP-Packets to some of these Public-IPs i want to set the destinsation-Ethernet-Adress. So for instance System A has IP 8.8.8.8, mac de:ad:be:ef:de:ad, arp disabled System B has IP 8.8.8.8, mac 1f:1f:1f:1f:1f:1f, arp disabled Firewall has IP 8.8.8.1, arp disabled on that interface Incoming packet to IP 8.8.8.8 tcp dest port 100 Incoming packet to IP 8.8.8.8 tcp dest port 101 Firewall sets dest-mac for 1.) - de:ad:be:ef:de:ad Firewall sets dest-mac for 2.) - 1f:1f:1f:1f:1f:1f Second scenario: System A and System B establish outgoing TCP-Connections, and the firewall matches the dst-mac of the incoming IP-Packets (response packets) to the senders-mac address. is this possible in any way with linux and iptables? edit: i read ebtables might "work" in a hackish way for this purpose but i am not sure...

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  • using virtual machine like mySql server

    - by ffmm
    i'm developing a java program and i need a database. Now i'm using MAMP and it's pretty easy but i would have a virtual machine (ubuntu server) and i need to connect my java program with this virtual machine using vitualBox. the situation: I installed VirtualBox on my mac and I installed an ubuntu-server machine set "bridge adapter" in the network settings of VB I installed mysql on ubuntu-server and i created a simple database (all work well by ubuntu) doing ifconfig by ubuntu I get the ip: 192.168.1.217 so in the java program i made this function: public static Connection connect(String host, int port, String dbName, String user, String passwd) { Connection dbConnection = null; try { String dbString = null; Class.forName("com.mysql.jdbc.Driver").newInstance(); dbString = "jdbc:mysql://" + host + ":" + port + "/" + dbName; dbConnection = DriverManager.getConnection(dbString, user, passwd); } catch (Exception e) { System.err.println("Failed to connect with the DB"); e.printStackTrace(); } return dbConnection; } and in the main() i use: Connection con = connect(1, "192.168.1.217", 3306, "Ciao", "root", "cocacola"); 3306 was a default value. I don't know if is correct, it works on mamp, but…. how I can find the correct port that I have to use with VB? when I ran the program I get the catch excepion… what's wrong? ps: i have to install apache o something else?

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  • My Ubuntu 10.04 server kills all WAN bandwidth when it's attached to my LAN. Where do you begin troubleshooting?

    - by rrc7cz
    First I should say that my Linux knowledge is minimal; just enough to set up some servers (Apache, Tomcat, Couch, etc). I built a MiniITX server to host some simple sites, act as an SSH tunnel while I'm away, and act as a torrent server. It was not properly secured for a long time (iptables was empty, all ports open, no firewall) though my router did not have much port forwarding set up beyond HTTP, FTP, and SSH. A week or two ago my bandwidth at home dropped from around 27Mbps to 2Mbps and my upload went from 7Mbps to 0.06Mbps. When I unplug the server from the LAN, by bandwidth shoots back up. I threw up a restrictive iptables, removed most of the port forwarding, and checked my router logs to see if there were any open connections from the server (malware?) but there were none. What would you do? What are the first things you'd check? I can of course reinstall everything from scratch, but I'd like to find the root cause.

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  • I'm having trouble getting my server to appear online.

    - by JMRboosties
    Total newb question I'm sure. First I had installed WAMP (http://www.wampserver.com), and I was able to access my pages from other computers in my router network, and the virtual device used to debug Android programs (the purpose of my having a server). This functionality failed, however, at some point over these past few days. While my own browser displays the pages just fine, other computers, my Android phone (on our room's wifi), and my virtual device are no longer able to connect to my pages. I had not made any changes in the settings. I uninstalled WAMP and installed EasyPHP. However, the problem was not resolved. I know this is rather vague, but does anyone here have an idea of what may have happened? I forwarded both port 80 (I know its the default HTTP port, I did it just to be safe), and now port 8888 which EasyPHP uses. I turned my firewall on my hosting computer off for good measure. I cannot access my pages from neither remote computers or computers using my router. Any ideas you may have on how to resolve this would be awesome, thanks a lot. And if you need anymore info please tell me.

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  • Java Process "The pipe has been ended" problem

    - by Amit Kumar
    I am using Java Process API to write a class that receives binary input from the network (say via TCP port A), processes it and writes binary output to the network (say via TCP port B). I am using Windows XP. The code looks like this. There are two functions called run() and receive(): run is called once at the start, while receive is called whenever there is a new input received via the network. Run and receive are called from different threads. The run process starts an exe and receives the input and output stream of the exe. Run also starts a new thread to write output from the exe on to the port B. public void run() { try { Process prc = // some exe is `start`ed using ProcessBuilder OutputStream procStdIn = new BufferedOutputStream(prc.getOutputStream()); InputStream procStdOut = new BufferedInputStream(prc.getInputStream()); Thread t = new Thread(new ProcStdOutputToPort(procStdOut)); t.start(); prc.waitFor(); t.join(); procStdIn.close(); procStdOut.close(); } catch (Exception e) { e.printStackTrace(); printError("Error : " + e.getMessage()); } } The receive forwards the received input from the port A to the exe. public void receive(byte[] b) throws Exception { procStdIn.write(b); } class ProcStdOutputToPort implements Runnable { private BufferedInputStream bis; public ProcStdOutputToPort(BufferedInputStream bis) { this.bis = bis; } public void run() { try { int bytesRead; int bufLen = 1024; byte[] buffer = new byte[bufLen]; while ((bytesRead = bis.read(buffer)) != -1) { // write output to the network } } catch (IOException ex) { Logger.getLogger().log(Level.SEVERE, null, ex); } } } The problem is that I am getting the following stack inside receive() and the prc.waitfor() returns immediately afterwards. The line number shows that the stack is while writing to the exe. The pipe has been ended java.io.IOException: The pipe has been ended at java.io.FileOutputStream.writeBytes(Native Method) at java.io.FileOutputStream.write(FileOutputStream.java:260) at java.io.BufferedOutputStream.write(BufferedOutputStream.java:105) at java.io.BufferedOutputStream.flushBuffer(BufferedOutputStream.java:65) at java.io.BufferedOutputStream.write(BufferedOutputStream.java:109) at java.io.FilterOutputStream.write(FilterOutputStream.java:80) at xxx.receive(xxx.java:86) Any advice about this will be appreciated.

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  • Interesting issue with WCF wsHttpBinding through a Firewall

    - by Marko
    I have a web application deployed in an internet hosting provider. This web application consumes a WCF Service deployed at an IIS server located at my company’s application server, in order to have data access to the company’s database, the network guys allowed me to expose this WCF service through a firewall for security reasons. A diagram would look like this. [Hosted page] --- (Internet) --- |Firewall <Public IP>:<Port-X >| --- [IIS with WCF Service <Comp. Network Ip>:<Port-Y>] link text I also wanted to use wsHttpBinding to take advantage of its security features, and encrypt sensible information. After trying it out I get the following error: Exception Details: System.ServiceModel.EndpointNotFoundException: The message with To 'http://<IP>:<Port>/service/WCFService.svc' cannot be processed at the receiver, due to an AddressFilter mismatch at the EndpointDispatcher. Check that the sender and receiver's EndpointAddresses agree. Doing some research I found out that wsHttpBinding uses WS-Addressing standards, and reading about this standard I learned that the SOAP header is enhanced to include tags like ‘MessageID’, ‘ReplyTo’, ‘Action’ and ‘To’. So I’m guessing that, because the client application endpoint specifies the Firewall IP address and Port, and the service replies with its internal network address which is different from the Firewall’s IP, then WS-Addressing fires the above message. Which I think it’s a very good security measure, but it’s not quite useful in my scenario. Quoting the WS-Addressing standard submission (http://www.w3.org/Submission/ws-addressing/) "Due to the range of network technologies currently in wide-spread use (e.g., NAT, DHCP, firewalls), many deployments cannot assign a meaningful global URI to a given endpoint. To allow these ‘anonymous’ endpoints to initiate message exchange patterns and receive replies, WS-Addressing defines the following well-known URI for use by endpoints that cannot have a stable, resolvable URI. http://schemas.xmlsoap.org/ws/2004/08/addressing/role/anonymous" HOW can I configure my wsHttpBinding Endpoint to address my Firewall’s IP and to ignore or bypass the address specified in the ‘To’ WS-Addressing tag in the SOAP message header? Or do I have to change something in my service endpoint configuration? Help and guidance will be much appreciated. Marko. P.S.: While I find any solution to this, I’m using basicHttpBinding with absolutely no problem of course.

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  • Reading a POP3 server with only TcpClient and StreamWriter/StreamReader[SOLVED]

    - by WebDevHobo
    I'm trying to read mails from my live.com account, via the POP3 protocol. I've found the the server is pop3.live.com and the port if 995. I'm not planning on using a pre-made library, I'm using NetworkStream and StreamReader/StreamWriter for the job. I need to figure this out. So, any of the answers given here: http://stackoverflow.com/questions/44383/reading-email-using-pop3-in-c are not usefull. It's part of a larger program, but I made a small test to see if it works. Eitherway, i'm not getting anything. Here's the code I'm using, which I think should be correct. EDIT: this code is old, please refer to the second block problem solved. public Program() { string temp = ""; using(TcpClient tc = new TcpClient(new IPEndPoint(IPAddress.Parse("127.0.0.1"),8000))) { tc.Connect("pop3.live.com",995); using(NetworkStream nws = tc.GetStream()) { using(StreamReader sr = new StreamReader(nws)) { using(StreamWriter sw = new StreamWriter(nws)) { sw.WriteLine("USER " + user); sw.Flush(); sw.WriteLine("PASS " + pass); sw.Flush(); sw.WriteLine("LIST"); sw.Flush(); while(temp != ".") { temp += sr.ReadLine(); } } } } } Console.WriteLine(temp); } Visual Studio debugger constantly falls over tc.Connect("pop3.live.com",995); Which throws an "A socket operation was attempted to an unreachable network 65.55.172.253:995" error. So, I'm sending from port 8000 on my machine to port 995, the hotmail pop3 port. And I'm getting nothing, and I'm out of ideas. Second block: Problem was apparently that I didn't write the quit command. The Code: public Program() { string str = string.Empty; string strTemp = string.Empty; using(TcpClient tc = new TcpClient()) { tc.Connect("pop3.live.com",995); using(SslStream sl = new SslStream(tc.GetStream())) { sl.AuthenticateAsClient("pop3.live.com"); using(StreamReader sr = new StreamReader(sl)) { using(StreamWriter sw = new StreamWriter(sl)) { sw.WriteLine("USER " + user); sw.Flush(); sw.WriteLine("PASS " + pass); sw.Flush(); sw.WriteLine("LIST"); sw.Flush(); sw.WriteLine("QUIT "); sw.Flush(); while((strTemp = sr.ReadLine()) != null) { if(strTemp == "." || strTemp.IndexOf("-ERR") != -1) { break; } str += strTemp; } } } } } Console.WriteLine(str); }

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  • Ruby IRC bot don't works.

    - by JavaNoob
    require "socket" server = "irc.rizon.net" port = "6667" nick = "Ruby IRC Bot" channel = "#0x40" s = TCPSocket.open(server, port) s.print("USER Testing", 0) s.print("NICK #{nick}", 0) s.print("JOIN #{channel}", 0) This irc bot don't connect to the IRC server, What are i'm doing wrong?

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  • how to close selenium hub/grid from command prompt

    - by tejas trivedi
    I start selenium hub to start selenium grid from command prompt on port 4444. Now I start selenium RC from other command prompt. It show me error message that "selenium i s already running on port 4444. or some other service is " Now I am not able to start selenium RC. Please help me how to close /shutdown hub from command prompt.

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  • ! Extra }, or forgotten \endgroup. latex

    - by gzou
    hey, I met these latex format problem, anyone can offer some help? the .tex file: \begin{table}{} \renewcommand{\arraystretch}{1.1} \caption{Cambridge Flow feature definition and description} \label{cambridge-feature}} \centering \begin{tabular}{|c|c|} \hline\bfseries Abbreviation &\bfseries Description\\ \hline serv-port & Server port\\ \hline clnt-port & Client port\\ \hline push-pkts-serv & count of all packets with\\ & push bit set in TCP header (server to client)\\ \hline init-win-bytes-clnt & the total number of bytes \\ & sent in initial window (client to server)\\ \hline init-win-bytes-serv & the total number of bytes sent\\ & in initial window (server to client)\\ \hline avg-seg-size-clnt & average segment size: \\ & data bytes devided by number of packets\\ \hline IP-bytes-med-clnt & median of total bytes in IP packet\\ \hline act-data-pkt-serv & count of packet with at least one byte \\ & of TCP data playload (server to client)\\ \hline data-bytes-var-clnt & variance of total \\ & bytes in packets (client to server)\\ \hline min-seg-size-serv & minimum segment size \\ & observed (server to client)\\ \hline RTT-samples-serv & total number of RTT samples\\ & found (server to client),\\ & {\bf see also \cite{Moore05discriminators}}\\ \hline push-pkts-clnt & count of all packets with push bit set \\ & in TCP header (server to client)\\ \hline \end{tabular} \end{table} and the error message: ! Extra }, or forgotten \endgroup. \@endfloatbox ...pagefalse \outer@nobreak \egroup \color@endbox l.892 \end{table} I've deleted a group-closing symbol because it seems to be spurious, as in $x}$'. But perhaps the } is legitimate and you forgot something else, as in\hbox{$x}'. In such cases the way to recover is to insert both the forgotten and the deleted material, e.g., by typing `I$}'. there is no $ in my table, also this { are matching with the }, and also after I comment the citation, the error remains. anyone can offer help? really appreciate all the comments! ! Extra }, or forgotten \endgroup.

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  • Scheme Formatting Help

    - by Logan
    I've been working on a project for school that takes functions from a class file and turns them into object/classes. The assignment is all about object oriented programming in scheme. My problem however is that my code doesn't format right. The output it gives me whenever I give it a file to pass in wraps the methods of the class in a list, making it so that the class never really gets declared. I can't for the life of me figure out how to get the parenthesis wrapping the method list to remove. I would really appreciate any help. Below is the code and the class file. ;;;; PART1 --- A super-easy set of classes. Just models points and lines. Tests all of the ;; basics of class behavior without touching on anything particularly complex. (class pointInstance (parent:) (constructor_args:) (ivars: (myx 1) (myy 2)) (methods: (getx () myx) (gety () myy) (setx (x) (set! myx x)) (show () (begin (display "[") (display myx) (display ",") (display myy) (display "]"))) )) (require (lib "trace.ss")) ;; Continue reading until you hit the end of the file, all the while ;; building a list with the contents (define load-file (lambda (port) (let ((rec (read port))) (if (eof-object? rec) '() (cons rec (load-file port)))))) ;; Open a port based on a file name using open-input-file (define (load fname) (let ((fport (open-input-file fname))) (load-file fport))) ;(define lis (load "C:\\Users\\Logan\\Desktop\\simpletest.txt")) ;(define lis (load "C:\\Users\\Logan\\Desktop\\complextest.txt")) (define lis (load "C:\\Users\\Logan\\Desktop\\pointinstance.txt")) ;(display (cdaddr (cdddar lis))) (define makeMethodList (lambda (listToMake retList) ;(display listToMake) (cond [(null? listToMake) retList ;(display "The list passed in to parse was null") ] [else (makeMethodList (cdr listToMake) (append retList (list (getMethodLine listToMake)))) ] ) )) ;(trace makeMethodList) ;this works provided you just pass in the function line (define getMethodLine (lambda (functionList) `((eq? (car msg) ,(caar functionList)) ,(caddar functionList)))) (define load-classes (lambda paramList (cond [(null? paramList) (display "Your parameters are null, man.")] [(null? (car paramList))(display "Done creating class definitions.")] [(not (null? (car paramList))) (begin (let* ((className (cadaar paramList)) (classInstanceVars (cdaddr (cddaar paramList))) (classMethodList (cdr (cadddr (cddaar paramList)))) (desiredMethodList (makeMethodList classMethodList '())) ) ;(display "Classname: ") ;(display className) ;(newline)(newline) ;(display "Class Instance Vars: ") ;(display classInstanceVars) ;(newline)(newline) ;(display "Class Method List: ") ;(display classMethodList) ;(newline) ;(display "Desired Method List: ") ;(display desiredMethodList)) ;(newline)(newline) ;---------------------------------------------------- ;do not delete the below code!` `(define ,className (let ,classInstanceVars (lambda msg ;return the function list here (cond ,(makeMethodList classMethodList '()))) )) ;--------------------------------------------------- ))] ) )) (load-classes lis) ;(load-classes lis) ;(load-classes-helper lis) ;(load-classes "simpletest.txt") ;(load-classes "complextest.txt") ;method list ;(display (cdr (cadddr (cddaar <class>))))

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  • BindException with INTERNET permission requested

    - by Mondain
    I have seen several questions regarding SocketException when using Android, but none of them cover the BindException that I get even with the INTERNET permission specified in my manifest. Here is part of my manifest: <uses-permission android:name="android.permission.INTERNET"></uses-permission> <uses-permission android:name="android.permission.ACCESS_NETWORK_STATE"></uses-permission> <uses-permission android:name="android.permission.ACCESS_WIFI_STATE"></uses-permission> <uses-permission android:name="android.permission.READ_OWNER_DATA"></uses-permission> <uses-permission android:name="android.permission.READ_PHONE_STATE"></uses-permission> <uses-permission android:name="android.permission.ACCOUNT_MANAGER"></uses-permission> <uses-permission android:name="android.permission.AUTHENTICATE_ACCOUNTS"></uses-permission> Here is the relevant portion of my LogCat output: 04-22 14:49:06.117: DEBUG/MyLibrary(4844): Address to bind: 192.168.1.14 port: 843 04-22 14:49:06.197: WARN/System.err(4844): java.net.BindException: Permission denied (maybe missing INTERNET permission) 04-22 14:49:06.207: WARN/System.err(4844): at org.apache.harmony.luni.platform.OSNetworkSystem.socketBindImpl(Native Method) 04-22 14:49:06.207: WARN/System.err(4844): at org.apache.harmony.luni.platform.OSNetworkSystem.bind(OSNetworkSystem.java:107) 04-22 14:49:06.217: WARN/System.err(4844): at org.apache.harmony.luni.net.PlainSocketImpl.bind(PlainSocketImpl.java:184) 04-22 14:49:06.217: WARN/System.err(4844): at java.net.ServerSocket.bind(ServerSocket.java:414) 04-22 14:49:06.227: WARN/System.err(4844): at org.apache.harmony.nio.internal.ServerSocketChannelImpl$ServerSocketAdapter.bind(ServerSocketChannelImpl.java:213) 04-22 14:49:06.227: WARN/System.err(4844): at java.net.ServerSocket.bind(ServerSocket.java:367) 04-22 14:49:06.237: WARN/System.err(4844): at org.apache.harmony.nio.internal.ServerSocketChannelImpl$ServerSocketAdapter.bind(ServerSocketChannelImpl.java:283) 04-22 14:49:06.237: WARN/System.err(4844): at mylibrary.net.PolicyConnection$PolicyServerWorker.(PolicyConnection.java:201) I Really hope this is a simple problem and not something complicated by the fact that the binding is occurring within a worker thread on a port less than 1024. Update Looks as if this is a privileged port issue, anyone know how to bind to ports lower than 1024 in Android? SelectorProvider provider = SelectorProvider.provider(); try { ServerSocketChannel channel = provider.openServerSocketChannel(); policySocket = channel.socket(); Log.d("MyLibrary", "Address to bind: " + device.getAddress().getAddress() + " port: 843"); InetSocketAddress addr = new InetSocketAddress(InetAddress.getByName(device.getAddress().getAddress()), 843); policySocket.bind(addr); policySocket.setReuseAddress(true); policySocket.setReceiveBufferSize(256); } catch (Exception e) { e.printStackTrace(); }

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  • GCD and AppleEvents / NSOperationQueue and AppleScript

    - by mahal tertin
    As i understood, the threads provided by GCD do have a runloop but no source/port. Now i use some of methods that call AppleScripts thru AppleEvents inside an NSOperationQueue. And sometimes my app crashes with following stacktrace. my questions: Usage of AppleScript inside a NSInvocationOperation or NSBlockOperation Usage of AppleEvents inside GCD-Threads do i have to add a source / port to a runloop of a gcd-thread before using AppleEvents? do i have to add a source / port to a runloop of a gcd-thread before using [CATransaction commit]? do i have to add a source / port to a runloop of a gcd-thread before using [NSObject performSelectorAfterDelay...] ? if yes, how? can i simply call CFRunLoopRunInMode(kCFRunLoopDefaultMode, 5.0, false); /// or 30 or the defined timeout of appleevent? .. Thread 9: Dispatch queue: com.apple.root.default-priority 0 libSystem.B.dylib 0x00007fff88276e82 semaphore_wait_signal_trap 10 1 libSystem.B.dylib 0x00007fff8827c3cd pthread_mutex_lock 469 2 com.apple.applescript 0x000000011d3d461f AppleScriptComponent 50 3 com.apple.applescript 0x000000011d3edbcc AGenericCall::Delegate(ComponentInstanceRecord*) 46 4 com.apple.applescript 0x000000011d3ed520 AGenericManager::HandleOSACall(ComponentParameters*) 54 5 com.apple.applescript 0x000000011d3ed4b0 GenericComponent 219 6 com.apple.openscripting 0x00007fff8381c6da OSAExecuteEvent 63 7 com.apple.Foundation 0x00007fff86f320d8 -[NSAppleScript(NSPrivate) _executeAppleEvent:withMode:error:] 161 8 xxx 0x0000000100048af0 -[TCallScript callScript:withArrayOfParameters:] 480 9 xxx 0x0000000100048ffd -[TCallScript callHandler:withParameters:] 477 10 xxx 0x0000000100036032 -[ZFOpenWindowController getSafariItemForCurrentTabForWindow:] 66 11 xxx 0x00000001000346af -[ZFOpenWindowController refreshWindowList:] 1679 12 xxx 0x000000010003541c -[ZFOpenWindowController bringZFToForegroundZoomOut:orJustLinkFrontMost:toItem:] 2988 13 xxx 0x0000000100053556 __-[ZFSelectionTool openWithPreferredApplication:]_block_invoke_516 54 14 com.apple.Foundation 0x00007fff86ed87d9 -[NSBlockOperation main] 140 15 com.apple.Foundation 0x00007fff86ec906d -[__NSOperationInternal start] 681 16 com.apple.Foundation 0x00007fff86ec8d23 ____startOperations_block_invoke_2 99 17 libSystem.B.dylib 0x00007fff882b2ce8 _dispatch_call_block_and_release 15 18 libSystem.B.dylib 0x00007fff88291279 _dispatch_worker_thread2 231 19 libSystem.B.dylib 0x00007fff88290bb8 _pthread_wqthread 353 20 libSystem.B.dylib 0x00007fff88290a55 start_wqthread 13 ... Thread 11 Crashed: Dispatch queue: com.apple.root.default-priority 0 com.apple.applescript 0x000000011d40f658 BCHandleError() 182 1 com.apple.applescript 0x000000011d4059ca UASExecute1() 2546 2 com.apple.applescript 0x000000011d3dd1d5 ASExecuteEvent(AEDesc const*, unsigned int, int, unsigned int*) 695 3 ...ple.CoreServices.CarbonCore 0x00007fff85388e04 CallComponentFunction 28 4 com.apple.applescript 0x000000011d3d4cad AppleScriptComponent 1728 5 com.apple.applescript 0x000000011d3edbcc AGenericCall::Delegate(ComponentInstanceRecord*) 46 6 com.apple.applescript 0x000000011d3ed520 AGenericManager::HandleOSACall(ComponentParameters*) 54 7 com.apple.applescript 0x000000011d3ed4b0 GenericComponent 219 8 com.apple.openscripting 0x00007fff8381c6da OSAExecuteEvent 63 9 com.apple.Foundation 0x00007fff86f320d8 -[NSAppleScript(NSPrivate) _executeAppleEvent:withMode:error:] 161 10 xxx 0x0000000100048af0 -[TCallScript callScript:withArrayOfParameters:] 480 11 xxx 0x0000000100048ffd -[TCallScript callHandler:withParameters:] 477 12 xxx 0x0000000100035c67 -[ZFOpenWindowController getItemForAXDocumentOfFrontMostWindow] 119 13 xxx 0x00000001000359f1 -[ZFOpenWindowController getItemForFrontMostWindow:] 721 14 xxx 0x00000001000348ac -[ZFOpenWindowController bringZFToForegroundZoomOut:orJustLinkFrontMost:toItem:] 60 15 xxx 0x0000000100053556 __-[ZFSelectionTool openWithPreferredApplication:]_block_invoke_516 54 16 com.apple.Foundation 0x00007fff86ed87d9 -[NSBlockOperation main] 140 17 com.apple.Foundation 0x00007fff86ec906d -[__NSOperationInternal start] 681 18 com.apple.Foundation 0x00007fff86ec8d23 ____startOperations_block_invoke_2 99 19 libSystem.B.dylib 0x00007fff882b2ce8 _dispatch_call_block_and_release 15 20 libSystem.B.dylib 0x00007fff88291279 _dispatch_worker_thread2 231 21 libSystem.B.dylib 0x00007fff88290bb8 _pthread_wqthread 353 22 libSystem.B.dylib 0x00007fff88290a55 start_wqthread 13

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  • Does python's httplib.HTTPConnection block?

    - by python_noob
    Hello, I am unsure whether or not the following code is a blocking operation in python: import httplib import urllib def do_request(server, port, timeout, remote_url): conn = httplib.HTTPConnection(server, port, timeout=timeout) conn.request("POST", remote_url, urllib.urlencode(query_dictionary, True)) conn.close() return True do_request("http://www.example.org", 80, 30, "foo/bar") print "hi!" And if it is, how would one go about creating a non-blocking asynchronous http request in python? Thanks from a python noob.

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  • python Socket.IO client for sending broadcast messages to TornadIO2 server

    - by Alp
    I am building a realtime web application. I want to be able to send broadcast messages from the server-side implementation of my python application. Here is the setup: socketio.js on the client-side TornadIO2 server as Socket.IO server python on the server-side (Django framework) I can succesfully send socket.io messages from the client to the server. The server handles these and can send a response. In the following i will describe how i did that. Current Setup and Code First, we need to define a Connection which handles socket.io events: class BaseConnection(tornadio2.SocketConnection): def on_message(self, message): pass # will be run if client uses socket.emit('connect', username) @event def connect(self, username): # send answer to client which will be handled by socket.on('log', function) self.emit('log', 'hello ' + username) Starting the server is done by a Django management custom method: class Command(BaseCommand): args = '' help = 'Starts the TornadIO2 server for handling socket.io connections' def handle(self, *args, **kwargs): autoreload.main(self.run, args, kwargs) def run(self, *args, **kwargs): port = settings.SOCKETIO_PORT router = tornadio2.TornadioRouter(BaseConnection) application = tornado.web.Application( router.urls, socket_io_port = port ) print 'Starting socket.io server on port %s' % port server = SocketServer(application) Very well, the server runs now. Let's add the client code: <script type="text/javascript"> var sio = io.connect('localhost:9000'); sio.on('connect', function(data) { console.log('connected'); sio.emit('connect', '{{ user.username }}'); }); sio.on('log', function(data) { console.log("log: " + data); }); </script> Obviously, {{ user.username }} will be replaced by the username of the currently logged in user, in this example the username is "alp". Now, every time the page gets refreshed, the console output is: connected log: hello alp Therefore, invoking messages and sending responses works. But now comes the tricky part. Problems The response "hello alp" is sent only to the invoker of the socket.io message. I want to broadcast a message to all connected clients, so that they can be informed in realtime if a new user joins the party (for example in a chat application). So, here are my questions: How can i send a broadcast message to all connected clients? How can i send a broadcast message to multiple connected clients that are subscribed on a specific channel? How can i send a broadcast message anywhere in my python code (outside of the BaseConnection class)? Would this require some sort of Socket.IO client for python or is this builtin with TornadIO2? All these broadcasts should be done in a reliable way, so i guess websockets are the best choice. But i am open to all good solutions.

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  • What is SocketOptionName.ReuseAddress used for?

    - by Hemant
    I used to think that using SocketOptionName.ReuseAddress, I can reuse a port that is in TIME_WAIT state. But I tried to experiment with it and it seems it has no effect. If I check sockets using netstat, and it shows the socket is in TIME_WAIT state and I immediately run the client again, I get the exception: Only one usage of each socket address (protocol/network address/port) is normally permitted 172.16.16.16:12345 I cannot make anything out of it. Please can you elaborate what SocketOptionName.ReuseAddress is good for?

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  • migrating an embedded jetty server from v6 to v7

    - by Ceilingfish
    Hi chaps, I have an embedded servlet which I use in unit tests, looks like this: public class UnitTestWebservices extends AbstractHandler { private Server server; private Map<Route,String> data = new HashMap<Route,String>(); public UnitTestWebservices(int port) throws Exception { server = new Server(port); server.setHandler(this); server.start(); } public void handle(String url, HttpServletRequest request, HttpServletResponse response, int arg3) throws IOException, ServletException { final Route route = Route.valueOf(request.getMethod(), url); final String content = data.get(route); if(content != null) { final ServletOutputStream stream = response.getOutputStream(); stream.print(content); stream.flush(); stream.close(); } else { response.sendError(HttpServletResponse.SC_NOT_FOUND); } } .... } That's written using version 6.1.24 of Jetty. I tried switching over to use Jetty 7.1.1.v20100517, and updated that code to this: public class UnitTestWebservices extends AbstractHandler { private Server server; private Map<Route,String> data = new HashMap<Route,String>(); public UnitTestWebservices(int port) throws Exception { server = new Server(port); server.setHandler(this); server.start(); } public void handle(String url, Request request, HttpServletRequest servletRequest, HttpServletResponse response) throws IOException, ServletException { final Route route = Route.valueOf(request.getMethod(), url); final String content = data.get(route); request.setHandled(true); response.setContentType("application/json"); if(content != null) { response.setStatus(HttpServletResponse.SC_OK); final Writer stream = response.getWriter(); stream.append(content); } else { response.sendError(HttpServletResponse.SC_NOT_FOUND); } } } But whenever I tried to access make a request to the server it would hang indefinitely. Has anyone experienced anything similar?. It also printed this into the log: log4j:WARN No appenders could be found for logger (org.eclipse.jetty.util.log). log4j:WARN Please initialize the log4j system properly. org.eclipse.jetty.server.Server@670655dd STOPPED +-UnitTestWebservices@50ef5502 started

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  • need to use git behind firewall: trying ssh tunneling

    - by Jacko
    Hi, I am trying to use ssh port forwarding to defeat corporate firewall: ssh git@GIT_SERVER -L9418:GIT_SERVER:9418 and in another terminal I run git clone git://localhost:repositories/project.git But I get the following error: Initialized empty Git repository in /Users/aboxer/tmp/glucosia/.git/ fatal: Unable to look up localhost (port repositories) (nodename nor servname provided, or not known) Thanks!

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  • Connect to Mongodb in python

    - by SpawnCxy
    I'm a little confused by the document when I tried to connect to the Mongodb.And I find it's different from mysql.I want to create a new database named "mydb" and insert some posts into it.The follows is what I'm trying. from pymongo.connection import Connection import datetime host = 'localhost' port = 27017 user = 'ucenter' passwd = '123' connection = Connection(host,port) db = connection['mydb'] post = {'author':'mike', 'text':'my first blog post!', 'tags':['mongodb','python','pymongo'], 'date':datetime.datetime.utcnow()} posts = db.posts posts.insert(post) #print str(db.collection_names()) And I got an error as pymongo.errors.OperationFailure: database error: unauthorized.How can I do the authorizing part?Thanks.

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