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  • Open default browser as standard user (C++)

    - by Disco
    I'm currently using ShellExecute "open" to open a URL in the user's browser, but running into a bit of trouble in Win7 and Vista because the program runs elevated as a service. When ShellExecute opens the browser, it seems to read the "Local Admin" profile instead of the user's. So for example, if the user at the keyboard has Firefox as his default browser, it may open IE (which is the admin's default). I know that the "runas" verb can be used to elevate, but how do you do it the other way around? Is there a way to open a URL in the default browser on a standard user's desktop from a service?

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  • Keystore and Aliases - is there a use to multiple aliases?

    - by Steve H
    When exporting a signed Android application using Eclipse, is there a purpose to using multiple aliases? According to the official guide about signing, it's recommended that you sign all applications with the same certificate to allow your applications to share data, code and be updated in modular fashion. Assuming that "alias", "key" and "certificate" are essentially interchangeable in this context, is there a reason why someone would want to use different aliases for all their applications? The only reason I can think of is that it adds more security to your applications, in the sense that a compromised key/password doesn't compromise everything. Are there other reasons? Also, is the generated key dependent on the name of the alias? In other words, if you change the name of the alias but not the password, would the generated certificate be different? Thanks.

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  • Lightbox getting open multiple time on enter.

    - by Salil
    Hi All, I am going through a weird problem while using lightbox . Where ever the new light box is used user is able to open the same light box on same page number of time. For e.g Using tab button go to `Lightbox link`. Press enter --> Light box will open. Press enter --> second light box open below the previous one. and so on....... The problem is occurred when I use tab and entered on the link my focus is not getting changed from the link and so user is able to open multiple lightbox on clicking enter. I try following but it not works for me <a href = '/calenders/add_shipment' onclick ="this.blur()" class='lbOn'> <img src='/images/box-plus.png' style='border:none;'> </a> what should be my approached to get out of this.

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  • Handling Model Inheritance in ASP.NET MVC2

    - by enth
    I've gotten myself stuck on how to handle inheritance in my model when it comes to my controllers/views. Basic Model: public class Procedure : Entity { public Procedure() { } public int Id { get; set; } public DateTime ProcedureDate { get; set; } public ProcedureType Type { get; set; } } public ProcedureA : Procedure { public double VariableA { get; set; } public int VariableB { get; set; } public int Total { get; set; } } public ProcedureB : Procedure { public int Score { get; set; } } etc... many of different procedures eventually. So, I do things like list all the procedures: public class ProcedureController : Controller { public virtual ActionResult List() { IEnumerable<Procedure> procedures = _repository.GetAll(); return View(procedures); } } but now I'm kinda stuck. Basically, from the list page, I need to link to pages where the specific subclass details can be viewed/edited and I'm not sure what the best strategy is. I thought I could add an action on the ProcedureController that would conjure up the right subclass by dynamically figuring out what repository to use and loading the subclass to pass to the view. I had to store the class in the ProcedureType object. I had to create/implement a non-generic IRepository since I can't dynamically cast to a generic one. public virtual ActionResult Details(int procedureID) { Procedure procedure = _repository.GetById(procedureID, false); string className = procedure.Type.Class; Type type = Type.GetType(className, true); Type repositoryType = typeof (IRepository<>).MakeGenericType(type); var repository = (IRepository)DependencyRegistrar.Resolve(repositoryType); Entity procedure = repository.GetById(procedureID, false); return View(procedure); } I haven't even started sorting out how the view is going to determine which partial to load to display the subclass details. I'm wondering if this is a good approach? This makes determining the URL easy. It makes reusing the Procedure display code easy. Another approach is specific controllers for each subclass. It simplifies the controller code, but also means many simple controllers for the many procedure subclasses. Can work out the shared Procedure details with a partial view. How to get to construct the URL to get to the controller/action in the first place? Time to not think about it. Hopefully someone can show me the light. Thanks in advance.

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  • VS 2010 SQL Update for SQL Statement

    - by Mike Tucker
    Please bear with me as I'm just beginning to learn this stuff. I have a VS 2010 Web project up and I'm trying to understand how I can make a custom UpdateCommand (Because I chose to write my own SQL statement, I do not have the option for VS 2010 to auto generate an update command for me.) Problem is: I don't know what the UpdateCommand should look like. Here is my Select: SELECT * FROM Dbo.MainAsset, dbo.Model, dbo.Hardware WHERE MainAsset.device = Hardware.DeviceID AND MainAsset.model = Model.DeviceID Which, VS 2010 turns into: SELECT MainAsset.pk, MainAsset.img, MainAsset.device, MainAsset.model, MainAsset.os, MainAsset.asset, MainAsset.serial, MainAsset.inyear, MainAsset.expyear, MainAsset.site, MainAsset.room, MainAsset.teacher, MainAsset.FirstName, MainAsset.LastName, MainAsset.Notes, MainAsset.Dept, MainAsset.AccountingCode, Model.Model AS Hardware, Model.pk AS Model, Model.DeviceID, Hardware.Computer, Hardware.pk AS Expr3, Hardware.DeviceID AS Expr4 FROM MainAsset INNER JOIN Hardware ON MainAsset.device = Hardware.DeviceID INNER JOIN Model ON MainAsset.model = Model.DeviceID How would I approach updating one column, say "MainAsset.site" if that's changed in the Gridview DDL? Any help constructive help would be appreciated. Thank you.

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  • C++ Multi Monitor - Find All Visible/Open Windows

    - by Paul
    I'm trying to find all the windows of ANY kind that are open (and have a taskbar 'button'). I have no problems finding the list processes/hWnd's, and then cycling through those, but how do I determine if a process/hwnd has a window open? (even if minimized). I've tried doing different combinations of the window parameters (such as WS_POPUP etc) but none of the parameters (or combinations of parameters) that I could find would give me all the open windows without some sort of false positives. As an example of a false positive was the fact that it gives me two 'windows' for google talk (even though one was open). Another false positive is considering the start menu as an open window. Any ideas? Solutions? I've been working on this for a while and its been driving me a bit insane. Note: I'm doing this for windows 7 (at this point). I'm not sure if there's any difference between how you would do this between XP and 7, but I thought it might be relevant.

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  • I need to model my Javascript application

    - by Totty
    Hy, I was looking for a software to model an application, because is becoming too big. Like this: Class - A Methods - a, b, c, d, e Class - B Methods - a, b, c, d, e This should be in graphical mode, Classes are some boxes, and the methods are in the box. Then I would like to be able to make a arrow from one method to another. Do you know some good software? thanks

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  • KindError: Property r must be an instance of SecondModel, why ?

    - by zjm1126
    class FirstModel(db.Model): p = db.StringProperty() r=db.ReferenceProperty(SecondModel) class SecondModel(db.Model): r = db.ReferenceProperty(FirstModel) class sss(webapp.RequestHandler): def get(self): a=FirstModel() a.p='sss' a.put() b=SecondModel() b.r=a b.put() a.r=b a.put() self.response.out.write(str(b.r.p)) the error is : Traceback (most recent call last): File "D:\Program Files\Google\google_appengine\google\appengine\ext\webapp\__init__.py", line 511, in __call__ handler.get(*groups) File "D:\zjm_code\helloworld\a.py", line 158, in get a.r=b File "D:\Program Files\Google\google_appengine\google\appengine\ext\db\__init__.py", line 3009, in __set__ value = self.validate(value) File "D:\Program Files\Google\google_appengine\google\appengine\ext\db\__init__.py", line 3048, in validate (self.name, self.reference_class.kind())) KindError: Property r must be an instance of SecondModel thanks

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  • How do I open a different page depending upon if user selects open in new tab or not.

    - by Timothy
    I am opening links on a page into an IFrame. But if the user right clicks and selects open in new window that will ruin the look I want since it will not have the parent page holding it. So is there a way to open the page as i have it working now when the user clicks on the link but if they choose to open in new tab to have it load the current page all over again in the new window with the link they selected loaded into the IFrame. Thankyou

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  • Change the default Open With

    - by emptyheaded
    How can I change the program a file is opened with by default (or at least add that program in the list of programs from Open With... ) using C# or VB.NET ? What I mean is, I would like to have programs with the extension abc open by default by the program abc.exe. Or, have the program abc.exe in the list of programs that will be shown in the context menu on the "Open With" option, for files with extension "xls".

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  • Model def in View State

    - by tinzawtun
    In my ruby on rails project in model, I have some of definition. class PlaySport < ActiveRecord::Base belongs_to :user belongs_to :sport def self.getLevel end def self.check_play_sport(cuser_id,sport_id) end def current_playing_sport end def all_played_sports end end I catch for this relation like this current_user.play_sports.current_playing_sport But I get the undefined method error "current_playing_sports" What is wrong

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  • Malthusian Growth Model in Ruby

    - by GregDean
    Hello. I am interested in modeling a Malthusian growth model in Ruby. Does anyone have any ideas, or are there any interesting libraries that cover this? Any help is appreciated. http://en.wikipedia.org/wiki/Malthusian_growth_model

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  • Multiple controllers with a single model

    - by Eric K
    I'm setting up a directory application for which I need to have two separate interfaces for the same Users table. Basically, administrators use the Users controller and views to list, edit, and add users, while non-admins need a separate interface which lists users in a completely different manner. To do this, would I be able to just set up another controller with different views but which accesses the Users model? Sorry if this is a simple question, but I've had a hard time finding how to do this.

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  • Inheritance not working

    - by Pendo826
    Hey im just practicing inheritance and i encountered a problem. Im getting an error in my car class(sub-class) that the variables in Vehicle(parent) are not visible. i didnt do anything to change this and i dont even know how to make it invisible. Can anyone help me with this. public class Vehicle { private String make, model, colour; private int registrationNumber; public Vehicle() { this.make = ""; this.model = ""; this.colour = ""; this.registrationNumber = 0; } public Vehicle(String make, String model, String colour, int registrationNumber) { this.make = make; this.model = model; this.colour = colour; this.registrationNumber = registrationNumber; } public String getMake() { return make; } public void setMake(String make) { this.make = make; } public String getModel() { return model; } public void setModel(String model) { this.model = model; } public String getColour() { return colour; } public void setColour(String colour) { this.colour = colour; } public int getRegistrationNumber() { return registrationNumber; } public void setRegistrationNumber(int registrationNumber) { this.registrationNumber = registrationNumber; } public String toString() { return "Vehicle [make=" + make + ", model=" + model + ", colour=" + colour + ", registrationNumber=" + registrationNumber + "]"; } } public Car() { super(); this.doors = 0; this.shape = ""; } public Car(int doors, String shape, String make, String model, String colour, int registrationNumber) { super(); this.doors = doors; this.shape = shape; this.make = make;//Error this.model = model;//Error this.colour = colour;//Error this.registrationNumber = registrationNumber;//Error } The error message: Description Resource Path Location Type The field Vehicle.make is not visible Car.java /VehicleApp/src line 19 Java Problem The field Vehicle.model is not visible Car.java /VehicleApp/src line 20 Java Problem The field Vehicle.colour is not visible Car.java /VehicleApp/src line 21 Java Problem The field Vehicle.registrationNumber is not visible Car.java /VehicleApp/src line 22 Java Problem

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  • Array structure returned by Yii's model

    - by user1104955
    I am a Yii beginner and am running into a bit of a wall and hope someone will be able to help me get back onto track. I think this might be a fairly straight forward question to the seasoned Yii user. So here goes... In the controller, let's say I run the following call to the model- $variable = Post::model()->findAll(); All works fine and I pass the variable into the view. Here's where I get pretty stuck. The array that is returned in the above query is far more complex than I anticipated and I'm struggling to make sense of it. Here's a sample- print_r($variable); gives- Array ( [0] => Post Object ( [_md:CActiveRecord:private] => CActiveRecordMetaData Object ( [tableSchema] => CMysqlTableSchema Object ( [schemaName] => [name] => tbl_post [rawName] => `tbl_post` [primaryKey] => id [sequenceName] => [foreignKeys] => Array ( ) [columns] => Array ( [id] => CMysqlColumnSchema Object ( [name] => id [rawName] => `id` [allowNull] => [dbType] => int(11) [type] => integer [defaultValue] => [size] => 11 [precision] => 11 [scale] => [isPrimaryKey] => 1 [isForeignKey] => [autoIncrement] => 1 [_e:CComponent:private] => [_m:CComponent:private] => ) [post] => CMysqlColumnSchema Object ( [name] => post [rawName] => `post` [allowNull] => [dbType] => text [type] => string [defaultValue] => [size] => [precision] => [scale] => [isPrimaryKey] => [isForeignKey] => [autoIncrement] => [_e:CComponent:private] => [_m:CComponent:private] => ) ) [_e:CComponent:private] => [_m:CComponent:private] => ) [columns] => Array ( [id] => CMysqlColumnSchema Object ( [name] => id [rawName] => `id` [allowNull] => [dbType] => int(11) [type] => integer [defaultValue] => [size] => 11 [precision] => 11 [scale] => [isPrimaryKey] => 1 [isForeignKey] => [autoIncrement] => 1 [_e:CComponent:private] => [_m:CComponent:private] => ) [post] => CMysqlColumnSchema Object ( [name] => post [rawName] => `post` [allowNull] => [dbType] => text [type] => string [defaultValue] => [size] => [precision] => [scale] => [isPrimaryKey] => [isForeignKey] => [autoIncrement] => [_e:CComponent:private] => [_m:CComponent:private] => ) ) [relations] => Array ( [responses] => CHasManyRelation Object ( [limit] => -1 [offset] => -1 [index] => [through] => [joinType] => LEFT OUTER JOIN [on] => [alias] => [with] => Array ( ) [together] => [scopes] => [name] => responses [className] => Response [foreignKey] => post_id [select] => * [condition] => [params] => Array ( ) [group] => [join] => [having] => [order] => [_e:CComponent:private] => [_m:CComponent:private] => ) ) [attributeDefaults] => Array ( ) [_model:CActiveRecordMetaData:private] => Post Object ( [_md:CActiveRecord:private] => CActiveRecordMetaData Object *RECURSION* [_new:CActiveRecord:private] => [_attributes:CActiveRecord:private] => Array ( ) [_related:CActiveRecord:private] => Array ( ) [_c:CActiveRecord:private] => [_pk:CActiveRecord:private] => [_alias:CActiveRecord:private] => t [_errors:CModel:private] => Array ( ) [_validators:CModel:private] => [_scenario:CModel:private] => [_e:CComponent:private] => [_m:CComponent:private] => ) ) [_new:CActiveRecord:private] => [_attributes:CActiveRecord:private] => Array ( [id] => 1 [post] => User Post ) [_related:CActiveRecord:private] => Array ( ) [_c:CActiveRecord:private] => [_pk:CActiveRecord:private] => 1 [_alias:CActiveRecord:private] => t [_errors:CModel:private] => Array ( ) [_validators:CModel:private] => [_scenario:CModel:private] => update [_e:CComponent:private] => [_m:CComponent:private] => ) ) [sorry if there's an easier way to show this array, I'm not aware of it] Can anyone explain to me why the model returns such a complex array? It doesn't seem to matter what tables or columns or relations are used in your application, they all seem to me to return this format. Also, can someone explain the structure to me so that I can isolate the variables that I want to recover? Many thanks in advance, Nick

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  • How to open the JavaScript console in different browsers?

    - by Šime Vidas
    Updated on October 7th 2012 Chrome: Press either CTRL + SHIFT + J to open the "Console" tab of the Developer Tools. Alternative method: Press either CTRL + SHIFT + I or F12 to open the Developer Tools. Press ESC (or click on "Show console" in the bottom right corner) to slide the console up. Note: In Chrome's dev tools, there is a "Console" tab. However, a smaller "slide-up" console can be opened while any of the other tabs is active. Safari: Press CTRL + ALT + I to open the Web Inspector. See Chrome's step 2. (Chrome and Safari have pretty much identical dev tools.) Note: Step 1 only works if the "Show Develop menu in menu bar" check box in the Advanced tab of the Preferences menu is checked! IE9: Press F12 to open the developer tools. Click the "Console" tab. Firefox: Press CTRL + SHIFT + K to open the Web console. or, if Firebug is installed (recommended): Press F12 to open Firebug. Click on the "Console" tab. Opera: Press CTRL + SHIFT + I to open Dragonfly. Click on the "Console" tab.

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  • TODAY! Partner Webcast: SPARC Marketing And Go-To-Market

    - by swalker
    THURSDAY, JUNE 21ST, 2012 AT 2:00 PM GMT (3:00 PM CET) Dear partner Oracle is pleased to invite you to our new webinar series on "Sparc Marketing and Go-to-Market" intended for our partners. Please join our second session in a series of new monthly webinars focused on everything related to SPARC and specifically designed to provide insights and selling guidance for channel partners worldwide on Thursday, June 21. Agenda: This month's guest speaker will focus on SPARC / T4 Marketing: a review of current assets and where we are going into FY13. Our presenter will be Bud Koch, Sr Principal Product Marketing Director. Please mark your diaries for this date and be sure to join. JOINING INFORMATION International Toll Free Dial-in Conference call ID: 90617465 Password: sparc To join the WebEx Conference Meeting Number: 590 744 943 Meeting Password: sparc REGISTER Delivery Format This FREE online LIVE eSeminar will be delivered over the Web and Conference Call. Duration 1 hour For assistance 1. Go to https://oraclemeetings.webex.com/oraclemeetings/mc 2. On the left navigation bar, click "Support". Note: Please join the call 10 minutes before the scheduled start time. We look forward to your participation. Best regards, Cinzia Mascanzoni EMEA Partner Marketing Director Giuseppe Facchetti EMEA Partner Business Development Manager

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  • Cannot open simple script application on mac

    - by streetpc
    Mac OS X 10.6 I created a very simple app, which is only a wrapper of a shell script (so that I can select this script in application selectors, like startup apps). I try to launch it and yesterday it worked, but today I changed the executable script's content and name (with something that perfeclty works in a shell script launched in the Terminal) and it will only display a Finder-iconed dialog saying Cannot open the application because it is not supported on this kind of Mac. I restored the previous script (content/name) but I still get the error! Same when re-bundling the app from scratch, or completely changing the bundle identifier… If I try to open it in the Terminal using open My.app, I get The application cannot be opened because it has an incorrect executable format. But when I executes directly the Contents/MacOS/Script, it allways works (iwth both contents). Also, it is displayed with correct icon and meta-information in the Finder (so I guess the Info.plist is understood). The app's file tree is: Contents/ Info.plist MacOS/ Script (executable bit set, works when launched directly) PkgInfo Resources/ AppIcon.icns Here is the Info.plist content: <?xml version="1.0" encoding="UTF-8"?> <!DOCTYPE plist PUBLIC "-//Apple//DTD PLIST 1.0//EN" "http://www.apple.com/DTDs/PropertyList-1.0.dtd"> <plist version="1.0"> <dict> <key>CFBundleExecutable</key> <string>Script</string> <key>CFBundleIconFile</key> <string>AppIcon</string> <key>CFBundleIdentifier</key> <string>asdf.ScriptApp</string> <key>CFBundleInfoDictionaryVersion</key> <string>6.0</string> <key>CFBundleName</key> <string>My script</string> <key>CFBundlePackageType</key> <string>APPL</string> <key>CFBundleShortVersionString</key> <string>1.0</string> <key>CFBundleSignature</key> <string>????</string> <key>CFBundleVersion</key> <string>1</string> <key>LSMinimumSystemVersion</key> <string>10.4</string> </dict> </plist> And the PkgInfo file only contains APPL????. I tested the Script with a simple echo "ok" and echo "ok" >/tmp/test (plus #!/bin/sh header). So my questions are: Is there some kind of validity caching for applications ? based on what ? how do I flush it ? Where does this message come from ? I tried to google it but all I get is a page talking about 32/64 bits Java…

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  • Cannot open simplest mac application

    - by streetpc
    I created a very simple app, which is only a wrapper of a shell script (so that I can select this script in application selectors, like startup apps). I try to launch it and yesterday it worked, but today I changed the executable script's content and name (with something that perfeclty works in a shell script launched in the Terminal) and it will only display a Finder-iconed dialog saying Cannot open the application because it is not supported on this kind of Mac. I restored the previous script (content/name) but I still get the error! Same when re-bundling the app from scratch, or completely changing the bundle identifier… If I try to open it in the Terminal using open My.app, I get The application cannot be opened because it has an incorrect executable format. But when I executes directly the Contents/MacOS/Script, it allways works (iwth both contents). Also, it is displayed with correct icon and meta-information in the Finder (so I guess the Info.plist is understood). The app's file tree is: Contents/ Info.plist MacOS/ Script (executable bit set, works when launched directly) PkgInfo Resources/ AppIcon.icns Here is the Info.plist content: <?xml version="1.0" encoding="UTF-8"?> <!DOCTYPE plist PUBLIC "-//Apple//DTD PLIST 1.0//EN" "http://www.apple.com/DTDs/PropertyList-1.0.dtd"> <plist version="1.0"> <dict> <key>CFBundleExecutable</key> <string>Script</string> <key>CFBundleIconFile</key> <string>AppIcon</string> <key>CFBundleIdentifier</key> <string>asdf.ScriptApp</string> <key>CFBundleInfoDictionaryVersion</key> <string>6.0</string> <key>CFBundleName</key> <string>My script</string> <key>CFBundlePackageType</key> <string>APPL</string> <key>CFBundleShortVersionString</key> <string>1.0</string> <key>CFBundleSignature</key> <string>????</string> <key>CFBundleVersion</key> <string>1</string> <key>LSMinimumSystemVersion</key> <string>10.4</string> </dict> </plist> And the PkgInfo file only contains APPL????. I tested the Script with a simple echo "ok" and echo "ok" >/tmp/test (plus #!/bin/sh header). So my questions are: * Is there some kind of validity caching for applications ? based on what ? how do I flush it ? * Where does this message come from ? I tried to google it but all I get is a page talking about 32/64 bits Java…

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