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  • bounding a sprite in cocos2d

    - by Srinivas
    am making a canon to fire objects. back of the canon the plunger is attached. plunger acts for set speed and angle. canon rotates 0-90 degree and plunger moves front and back for adjust speed. when am rotates the canon by touches moved its working fine. when plunger is pull back by touches moved and it rotates means the plunger is bounds outside of the canon. how to control this:- my code for plunger and canon rotation on touches moved. ( para3 is the canon , para6 is my plunger):- CGPoint touchLocation = [self convertTouchToNodeSpace:touch]; CGPoint oldTouchLocation = [touch previousLocationInView:touch.view]; oldTouchLocation = [[CCDirector sharedDirector] convertToGL:oldTouchLocation]; oldTouchLocation = [self convertToNodeSpace:oldTouchLocation]; if (CGRectContainsPoint(CGRectMake(para6.position.x-para6.contentSize.width/2, para6.position.y-para6.contentSize.height/2, para6.contentSize.width, para6.contentSize.height), touchLocation) && (touchLocation.y-oldTouchLocation.y == 0)) { CGPoint diff = ccpSub(touchLocation, oldTouchLocation); CGPoint currentpos = [para6 position]; NSLog(@"%d",currentpos); CGPoint destination = ccpAdd(currentpos, diff); if (destination.x < 90 && destination.x >70) { [para6 setPosition:destination]; speed = (70 + (90-destination.x))*3.5 ; } } if(CGRectIntersectsRect((CGRectMake(para6.position.x-para6.contentSize.width/8, (para6.position.y+30)-para6.contentSize.height/10, para6.contentSize.width, para6.contentSize.height/10)),(CGRectMake(para3.position.x-para3.contentSize.width/2, para3.position.y-para3.contentSize.height/2, para3.contentSize.width, para3.contentSize.height)))) { [para3 runAction:[CCSequence actions: [CCRotateTo actionWithDuration:rotateDuration angle:rotateDiff], nil]]; CGFloat plungrot = (rotateDiff); CCRotateTo *rot = [CCRotateTo actionWithDuration:rotateDuration angle:plungrot]; [para6 runAction:rot]; } }

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  • New to animation in Iphone

    - by mindfreak
    Hello guys , I am fairly new to transition and animation methods in Iphone. Can somebody pl. guide me the basics of transition and Animation in Iphone. This is needed frequently in my Apps. Can anybody tell me any link where i can Understand ABC of animation ?

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  • UITableView overlaps with NavigationBar in Storyboard Setting on first run

    - by Evils
    I know this seems to be a duplicate question which has been around here many many times, but believe me, I tried all iOS7 and earlier fixes which sets the Layout to a different Edge configuration without any change. My Storyboard looks like this: -> Navigation Controller -> Tab Bar Controller -> MyTableViewController -> VCForCellOne With the first run of my application the UITableView overlaps with the source NavigationController as shown here: After clicking on one of my Cells which pushes the corresponding ViewController to the NavigationController and going back again, everything looks fine as shown here: So everything is as it should be after once pushing another ViewController to the NavigationController and then going back. Switching from Portrait to Landscape and back also fixes the layout problem and everything is layed out as it should be. My ViewController within the Storyboard looks like this: I left it the default value, so I don't know what goes wrong here. I hope you understand my problem here. There's no custom class ViewController here, so no additional code which messes up something here. Any help highly appreciated!

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  • Template neglects const (why?)

    - by Gabriel
    Does somebody know, why this compiles?? template< typename TBufferTypeFront, typename TBufferTypeBack = TBufferTypeFront> class FrontBackBuffer{ public: FrontBackBuffer( const TBufferTypeFront front, const TBufferTypeBack back): ////const reference assigned to reference??? m_Front(front), m_Back(back) { }; ~FrontBackBuffer() {}; TBufferTypeFront m_Front; ///< The front buffer TBufferTypeBack m_Back; ///< The back buffer }; int main(){ int b; int a; FrontBackBuffer<int&,int&> buffer(a,b); // buffer.m_Back = 33; buffer.m_Front = 55; } I compile with GCC 4.4. Why does it even let me compile this? Shouldn't there be an error that I cannot assign a const reference to a non-const reference?

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  • PHP delete script, return to 'viewsubjects.php?classroom_id=NO VALUE'

    - by Derek
    Hi, As the title states... I am deleting a 'subject' from a 'classroom' I view classrooms, then can click on a classroom to view the subject for that classroom. So the link where I am viewing subjects looks like: viewsubjects.php?classroom=23 When the user selects the delete button (in a row) to remove a subject from a class, I simply want the user to be redirected back to the list of subjects for the classroom (exactly where they were before!!) So I though this is simply a case of calling up the classroom ID within my delete script. Here is what I have: EDIT: corrected spelling mistake in code (this was not the problem) $subject_id = $_GET['subject_id']; $classroom_id = $_GET['classroom_id']; $sql = "DELETE FROM subjects WHERE subject_id=".$subject_id; $result = mysql_query($sql, $connection) or die("MySQL Error: ".mysql_error()); header("Location: viewsubjects.php?classroom_id=".$classroom_id); exit(); The subject is being removed from the DB, but when I am redirected back the URI is displaying with an empty classroom ID like: viewsubjects.php?classroom_id= Is there a way to carry the classroom ID through successfully through the delete script so it can be displayed after, allowing the user to be redirected back to the page? Thanks for any help!

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  • Ordering z-indexes in an array

    - by Tom Gullen
    I have an array which looks something along the lines of resourceData[0][0] = "pic1.jpg"; resourceData[0][1] = 5; resourceData[1][0] = "pic2.jpg"; resourceData[1][1] = 2; resourceData[2][0] = "pic3.jpg"; resourceData[2][1] = 900; resourceData[3][0] = "pic4.jpg"; resourceData[3][1] = 1; The numeric represents the z-index of the image. Minimum z-index value is 1. Maximum (not really important) is 2000. I have all the rendering and setting z-indexes done fine. My question is, I want to have four functions: // Brings image to z front function bringToFront(resourceIndex) { // Set z-index to max + 1 resourceData[resourceIndex][1] = getBiggestZindex() + 1; // Change CSS property of image to bring to front $('#imgD' + resourceIndex).css("z-index", resourceData[resourceIndex][1]); } function bringUpOne(resourceIndex) { } function bringDownOne(resourceIndex) { } // Send to back z function sendToBack(resourceIndex) { } So given then index [3] (900 z): If we send it to the back, it will take the value 1, and [3] will have to go to 2, but that conflicts with [1] who has a 2 z-index so they need to go to three etc. Is there an easy programatical way of doing this because as soon as I start doing this it's going to get messy. It's important that the indexes of the array don't change. We can't sort the array unfortunately due to design. Update Thanks for answers, I'll post the functions here once they are written incase anyone comes across this in the future (note this code has zindex listed in [6]) // Send to back z function sendToBack(resourceIndex) { resourceData[resourceIndex][6] = 1; $('#imgD' + resourceIndex).css("z-index", 1); for (i = 0; i < resourceData.length; i++) { if (i != resourceIndex) { resourceData[i][6]++; $('#imgD' + i).css("z-index", resourceData[i][6]); } } }

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  • jQuery: Problems cookies internet explorer

    - by user1140479
    I have made a login page. When the user logs in a request to an API is send. This API is PHP and checks the username and password. When both are correct an unique key is send back (this is placed in the database for further use: userid and other stuff needed in the website). After that key is sent back it is placed in a cookie: $.cookie("session", JSON.stringify(result)); After the cookie is set I send the user to a new page: location.href = 'dashboard.htm'; In this page jQuery checks if the cookie "session" is present. If not, the user is send back to the login page. sessionId = ($.cookie("session") ? JSON.parse($.cookie("session")).SessionId : 0); return sessionId; This works fine in Chrome, but IE (8/9) has some problems with this. I figured out that when you get to dashboard.htm the session is present. As soon as I hit F5 the session is gone. And sometimes the cookie isn't set at all! I can't seem to figure out why this is happening in IE. Has someone any idea? Other options/ideas to save that unique key are also welcome. Thanks in advance.

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  • A problem of a repeated parameter in the pagination links?

    - by myaccount
    The problem is that when I load page 2 for example the URL becomes: http://domain.com/index.php?restaurant-id=45&currentpage=2 And that's fine but when I get to page 3 it becomes: http://domain.com/index.php?restaurant-id=45&currentpage=2&currentpage=3 And so on, it adds one more currentpage parameter everytime a new page is loaded from the pagination links! I wonder how this problem can be fixed? Here's some of the pagination function's code /****** build the pagination links ******/ // Getting current page URL with its parameters $current_page_url = ($_SERVER["PHP_SELF"].(isset($_SERVER["QUERY_STRING"])?"?".htmlentities($_SERVER["QUERY_STRING"]):"")); // Determine which sign to use (? or &) before the (currentpage=xx) parameter $sign = preg_match('/\?/', $current_page_url) ? '&' : '?'; $pagination_links = ''; // if not on page 1, don't show back links if ($currentpage > 1) { // show << link to go back to page 1 $pagination_links .= " <a href='{$current_page_url}{$sign}currentpage=1'>First page</a> "; // get previous page num $prevpage = $currentpage - 1; // show < link to go back 1 page $pagination_links .= " <a href='{$current_page_url}{$sign}currentpage=$prevpage'>previous</a> "; } else { $pagination_links .= "? ?"; }// end if

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  • What is the best Networking implementation for my application?

    - by CaptainPhil
    I am in the planning phases of a project for myself, it is to be a single and multi-player card game. I would like to track statistics for each person such as world rankings etc... My problem is I do not know the best approach for the client - server architecture and programming. My original goal was to program everything in C# as I want to get proficient in that language. My original idea was to have a back-end database and a back end server run on some sort of hosting on the internet, however that seems costly for such a small project that may or may not make any money. I have tried looking into cloud services however I am unfamiliar with the technology, and I am not sure I can make them suit my needs, especially since most like Google's cloud wants you to use their coding architecture from what I understand. Finally my last problem is that I would like an architecture that can be used for different languages so that I can port it from PC to IPhone, Xbox etc... So does anyone have any advice on the best architecture and language to do this in? Am I worrying about architecture and back-end costs to much and should just concentrate on getting the game running any which way?

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  • From Java/C++ to XML

    - by Greenhouse Gases
    I know Java and C++ but am looking to get in to XML. I don't want to waste time reading over the basics of programming in a book, so has anyone any recommendations for resources for learning XML that assume a knowledge of programming already, or even better highlight how to switch from Java/C++ to XML ie. main differences etcs.

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  • JIRA or Trac?

    - by seedhead
    I used Atlassian JIRA for bug and issue tracking at my last job. I absolutely loved it and it was particularly easy on the eyes. My present company is using Trac instead, and while it does do all the basics, I am finding it really lacking, particularly with the inability to easily setup multiple projects and link issues. Oh, and the fact that it uses SQLLite is a bit of an issue for me to. Does anyone have any other good reasons to switch?

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  • PHP Session doesn't get read in next page after login validation, Why?

    - by NetStar
    I have a web site and when my users login it takes them to verify.php (where it connects to the DataBase and matches email and password to the user input and if OK puts client data into sessions and take the client to /memberarea/index.php ELSE back to login page with message "Invalid Email or password!") <?php ob_start(); session_start(); $email=$_POST['email']; $pass=md5($_POST['pass']); include("conn.php"); // connects to Database $sql="SELECT * FROM `user` WHERE email='$email' AND pass='$pass'"; $result=mysql_query($sql); $new=mysql_fetch_array($result); $_SESSION['fname']=$new['fname']; $_SESSION['lname']=$new['lname']; $_SESSION['email1']=$new['email1']; $_SESSION['passwrd']=$new['passwrd']; $no=mysql_num_rows($result); if ($no==1){ header('Location:memberarea/index.php'); }else { header("Location:login.php?m=$msg"); //msg="Invalid Login" } ?> then after email id and password is verified it takes them to ` /memberarea/index.php (This is where the problem happens.) where in index.php it checks if a session has been created in-order to block hackers to enter member area and sends them back to the login page. <? session_start(); isset($_SESSION['email'])` && `isset($_SESSION['passwrd'])` The problem is the client gets verified in verify.php (the code is above) In varify.php only after I put ob_start(); ontop of session_start(); It moves on to /memberarea/index.php , If I remove ob_start() It keeps the client on the verify.php page and displays error header is alredy SENT. after I put ob_start() it goes in to /memberarea/index.php but the session is blank, so it goes back to the login page and displays the error ($msg) "Invalid Login" which I programed to display. Can anyone tell me why the session cant pass values from verify.php to /memberarea/index.php

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  • how to send on previous page where a part of html was loaded

    - by I Like PHP
    hello all, i m using Jquery ajax post method to edit a form on same page, but if there is some mistake then how do i send user back on that page where data were loaded. now i describe u what i do? i have a page manageMovies.php there are list of movie name, now when i click on a name of any movie, then i load editMovie.php on same page now when i do some mistakes( i.e when validations fails) then i want to go back on same page manageMovies.php loaded with editunit.php regarding that movie on the page. here is my page structure manageMovies.php <div id="display"></div> <div id="movieList"> <table > <tr><td id="mov_10">Apharan</td></tr> <tr><td id="mov_11">Gangaajal</td></tr> <tr><td id="mov_12">Rajniti</td></tr> </table> </div> <script type="text/javascript"> jQuery('td').click(function () { jQuery('#movieList').hide(); // hide the div 'movielist' jQuery.post('editMovie.php', { idForEdit: jQuery(this).attr('id') }, function (data) { jQuery("#display").html(data); //display the editMovie.php page on 'display' div }); }); </script> now when i do some mistakes on editunit.php and go further for post, then i need to go back on same page (manageMovies.php) where editMovie.php is shown on display div and movielist div should be hidden

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  • How to make link become inactive?

    - by Konstantin Vasilcov
    The idea was simple: change li background color on hover to one color ul#menu li a:hover {...} change it on mouse press to the other color ul#menu li a:active {...} return the color to the original (normal) if the link is neither hover nor pressed The problem appeared to be that, if user rejected his intention and lets the mouse up away from the link, the back color stays as if it was pressed. Then I tried to research and came up with this: ul#menu li a:hover:active {...} It became better, and the link is not marked with special back color in a normal state after user presses the link and rejects. But the "on-hover" back color became equal to the active one. So it looks like the link gets "active" state and stays in it even after user releases mouse button. Hate to write this, but I am very new to html and css. So I may be missing something very basic here. Could you, please, suggest any way, how to achieve my goal? EDIT I've read this source CSS Styling links (thought there could be some other state to use instead of active), but found nothing suitable there...

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  • How with lambda function in MVC3

    - by doogdeb
    I have a model which contains view models for each view. This model is held in session and is initialised when application starts. I need to be able to populate a field from one view model with the value from another so have used a lambda function. Below is my model. I am using a lambda so that when I get Test2.MyProperty it will use the FunctionTestProperty to retrieve the value from Test1.TestProperty. public class Model { public Model() { Test1 = new Test1() Test2 = new Test2(FunctionTestProperty () => Test1.TestProperty) } } public class Test1 { public string TestProperty { get; set; } } public class Test2 { public Test2() : this (() => string.Empty) {} public Test2(Func<string> functionTestProperty) { FunctionTestProperty = functionTestProperty; } public Func<string> FunctionTestProperty { get; set; } public string MyProperty { get{ return FunctionTestProperty() ?? string.Empty; } } } This works perfectly when I first run the application and navigate from Test1 to Test2; I can see that when I get the value for MyProperty it calls back to Model constructor and retrieves the Test1.TestProperty value. However when I then submit the form (Test2) it calls the default constructor which sets it to string.Empty. So if I go back to Test1 and back to Test2 again it always then calls the Test2 default constructor. Does anyone know why this works when first running the application but not after the view is submitted, or if I have made an obvious mistake?

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  • What goes into the "Controller" in "MVC"?

    - by P72endragon
    I think I understand the basic concepts of MVC - the Model contains the data and behaviour of the application, the View is responsible for displaying it to the user and the Controller deals with user input. What I'm uncertain about is exactly what goes in the Controller. Lets say for example I have a fairly simple application (I'm specifically thinking Java, but I suppose the same principles apply elsewhere). I organise my code into 3 packages called app.model, app.view and app.controller. Within the app.model package, I have a few classes that reflect the actual behaviour of the application. These extends Observable and use setChanged() and notifyObservers() to trigger the views to update when appropriate. The app.view package has a class (or several classes for different types of display) that uses javax.swing components to handle the display. Some of these components need to feed back into the Model. If I understand correctly, the View shouldn't have anything to do with the feedback - that should be dealt with by the Controller. So what do I actually put in the Controller? Do I put the public void actionPerformed(ActionEvent e) in the View with just a call to a method in the Controller? If so, should any validation etc be done in the Controller? If so, how do I feedback error messages back to the View - should that go through the Model again, or should the Controller just send it straight back to View? If the validation is done in the View, what do I put in the Controller? Sorry for the long question, I just wanted to document my understanding of the process and hopefully someone can clarify this issue for me!

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  • Is there a good GUI SVN app for Mac (better than XCode)

    - by Lawrence Johnston
    Hey everybody, I'm looking for a more robust and fully featured GUI SVN manager for Mac than what is built into XCode (which works, but only as long as you don't need anything beyond the bare basics and doesn't work for versioning scripts and such created in other editors). I can use the terminal commands, but I'd really like the option of using a GUI. On windows I use TortoiseSVN and Visual SVN, which do pretty much everything I need, but as far as I'm aware there's nothing even remotely resembling those on the Mac side.

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  • determine week when pick a day

    - by derikluv
    I'm trying to accomplish the following task. I'm developing a custom calendar with three views (day,week and month), there may be something out there already but I'm rewriting this as part of learning tool for me as well. So user will face with Day view when they first visit, with arrows to go back and forth to next day or previous day of course. If they click on Week View, it will give them a 7 days overview with today date as default, and once again they can go back and forth to next week or previous week. The last view is the full month calendar, once they click on the day, it will give them the detail of the day and at the same time reset the default as the day they pick. So if they go back to week view, they will see the detail for the week contain the day that they picked. This is where I have trouble wrapping my head around with, I know there are PHP functions that determine the day of the week but I can't seem to think about how to pass in the date and get the full week starting from Sunday for the day that passed in. For example, if I passed in 10/12/2012, I'd like to start the week at 10/07/12 - 10/13/12. Thank you kindly for your help or pointing to the right direction. Please excuse my grammar/spelling mistakes as well.

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  • More RAM vs. more servers [closed]

    - by user357972
    I was recently asked "Do you know when to decide between going for more RAM or more servers?" (in the context of scaling data mining applications). I had no idea, so what are some ways to decide? I have very little knowledge of architecture and scaling (my understanding of computer memory and what a server does is limited to the high-level basics), so tips on learning more about these things in general are also very welcome.

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