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  • Match Phrases (in array) in text string

    - by Tim Hanssen
    I'm using the Twitter API streaming to collect thousand of tweets every minute. They need to be matched to a list of keywords (can contain spaces). This is my current method: $text = preg_replace( '/[^a-z0-9]+/i', ' ', strtolower( $data['text'] ) ); $breakout = explode( " ", $text ); $result = array_intersect( $this->_currentTracks, $breakout ); I chop the tweet into words, and the matches them against my current keywords. This works well for all the keywords without a space ofc. If I wanted to find for example "Den Haag", It won't show up, because the string is exploded into words (based on the spaces). Any ideas about how I can do this in a quick way? Kind regards, Tim

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  • Sed: regular expression match lines without <!--

    - by sixtyfootersdude
    I have a sed command to comment out xml commands sed 's/^\([ \t]*\)\(.*[0-9a-zA-Z<].*\)$/\1<!-- Security: \2 -->/' web.xml Takes: <a> <!-- Comment --> <b> bla </b> </a> Produces: <!-- Security: <a> --> <!-- Security: <!-- Comment --> --> // NOTE: there are two end comments. <!-- Security: <b> --> <!-- Security: bla --> <!-- Security: </b> --> <!-- Security: </a> --> Ideally I would like to not use my sed script to comment things that are already commented. Ie: <!-- Security: <a> --> <!-- Comment --> <!-- Security: <b> --> <!-- Security: bla --> <!-- Security: </b> --> <!-- Security: </a> --> I could do something like this: sed 's/^\([ \t]*\)\(.*[0-9a-zA-Z<].*\)$/\1<!-- Security: \2 -->/' web.xml sed 's/^[ \t]*<!-- Security: \(<!--.*-->\) -->/\1/' web.xml but I think a one liner is cleaner (?) This is pretty similar: http://stackoverflow.com/questions/436850/matching-a-line-that-doesnt-contain-specific-text-with-regular-expressions

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  • Regular expression - starting and ending with a letter, accepting only letters, numbers and _

    - by jreid9001
    I'm trying to write a regular expression which specifies that text should start with a letter, every character should be a letter, number or underscore, there should not be 2 underscores in a row and it should end with a letter or number. At the moment, the only thing I have is ^[a-zA-Z]\w[a-zA-Z1-9_] but this doesn't seem to work properly since it only ever matches 3 characters, and allows repeated underscores. I also don't know how to specify requirements for the last character.

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  • How can I handle validation of non-latin script input in PHP?

    - by Matt
    I am trying to adapt a php application to handle non-latin scripts (specifically: Japanese, simplified Chinese and Arabic). The app's data validation routines make frequent use of regular expressions to check input, but I am not sure how to adapt the \w character type to other languages without installing additional locales on the system (which I cannot rely on). Previous developers to have worked on the app have simply added needed characters to the regexes as the number of languages we supported grew (you frequently see "[\wÀÁÂÃÄÅÆÇÈÉ... etc" in the code), but I can't really do this for all the alphabets I need to support now. Does anybody out there have some advice on how to tackle this?

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  • Need to add specific characters to regular expression

    - by lordryan
    i'm using the following regular expression to form a basic email validation. var emailRegEx = /^([a-zA-Z0-9])(([a-zA-Z0-9])*([\._\+-])*([a-zA-Z0-9]))*@(([a-zA-Z0-9\-])+(\.))+([a-zA-Z]{2,4})+$/; this works pretty well for what i need but i also need to exclude these specific characters for reasons i won't go into. !,#,$,%,^,&,*,(,),-,+,|,{,},[,],:,>,<,?,/,\,= - (the characters between the "," if that isn't clear) could someone help me with adding the second group to the first? I know the pro's and cons of using javascript to validate email addresses - i have to do it this way. thanks.

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  • How can I test if an input field contains foreign characters?

    - by zeckdude
    I have an input field in a form. Upon pushing submit, I want to validate to make sure the user entered non-latin characters only, so any foreign language characters, like Chinese among many others. Or at the very least test to make sure it does not contain any latin characters. Could I use a regular expression for this? What would be the best approach for this? I am validating in both javaScript and in PHP. What solutions can I use to check for foreign characters in the input field in both programming languages?

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  • Regular expression to match text that doesn't start with substring?

    - by Steven
    I have text with file names scattered throughout. The filenames appear in the text like this: |test.txt| |usr01.txt| |usr02.txt| |foo.txt| I want to match the filenames that don't start with usr. I came up with (?<=\|).*\.txt(?=\|) to match the filenames, but it doesn't exclude the ones starting with usr. Is this possible with regular expressions?

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  • How to match a variable list of items separated by commas

    - by user261915
    I want to turn something like this CS 240, CS 246, ECE 222, ... (more or less); Software Engineering students only into ('CS 240', 'CS 246', 'ECE 222', 'ECE 220') in Python, code that matches a single course looks like >>> re.search('([A-Z]{2,5} \d{3})', 'SE 112').groups() ('SE 112',) I prefer a regular expression only method because I have a bunch of other alternate reg exps using '|' to combine them. However, a method with split is acceptable.

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  • Apply a class to a <h1> based on the site url

    - by user1870639
    I'm new to PHP and want to apply a specific class to the title of my page depending on what part of the site the viewer is browsing. For instance, I want to apply the class "blog" to the if the viewer is at domain.com/blog OR domain.com/blog/post-1 so on and so forth BUT apply the class "pics" if they're viewing domain.com/pics or domain.com/pics/gallery-1 etc etc. I found something that could be modified to serve my needs using javascript here but I figured seeing as I'm using PHP already, it'd make more sense to keep this sort of thing server side. As I say, I'm new to PHP. I've experimented with some regular expressions, but to no avail.

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  • extract word with regular expression

    - by farka
    I have a string 1/temperatoA,2/CelcieusB!23/33/44,55/66/77 and I would like to extract the words temperatoA and CelcieusB. I have this regular expression (\d+/(\w+),?)*! but I only get the match 1/temperatoA,2/CelcieusB! Why?

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  • Elegant way to distinct Path or Entry key

    - by sum1stolemyname
    I have an application loading CAD data (Custom format), either from the local filesystem specifing an absolute path to a drawing or from a database. Database access is realized through a library function taking the drawings identifier as a parameter. the identifiers have a format like ABC 01234T56-T, while my paths a typical windows Paths (eg x:\Data\cadfiles\cadfile001.bin). I would like to write a wrapper function Taking a String as an argument which can be either a path or an identifier which calls the appropriate functions to load my data. Like this: Function CadLoader(nameOrPath : String):TCadData; My Question: How can I elegantly decide wether my string is an idnetifier or a Path to a file? Use A regexp? Or just search for '\' and ':', which are not appearing in the Identifiers?

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  • preg_replace replacing with array

    - by Scott
    What I want to do is replace the "[replace]" in input string with the corresponding vaule in the replace array. The total number of values will change but there will always be the same number in the replace array as in input string. I have tried doing this with preg_replace and preg_replace_callback but I can't get the pattern right for [replace], I also tried using vsprintf but the % in <table width="100%"> was messing it up. All help is greatly appreciated! Replace Array: $array = array('value 1','value 2','value 3'); Input String $string = ' <table width="100%"> <tr> <td>Name:</td> <td>[replace]</td> </tr> <tr> <td>Date:</td> <td>[replace]</td> </tr> <tr> <td>Info:</td> <td>[replace]</td> </tr> </table> '; Desired Result <table width="100%"> <tr> <td>Name:</td> <td>value 1</td> </tr> <tr> <td>Date:</td> <td>value 2</td> </tr> <tr> <td>Info:</td> <td>value 3</td> </tr> </table>

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  • Censoring selected words (replacing them with ****) using a single replaceAll?

    - by aioobe
    I'd like to censor some words in a string by replacing each character in the word with a "*". Basically I would want to do String s = "lorem ipsum dolor sit"; s = s.replaceAll("ipsum|sit", $0.length() number of *)); so that the resulting s equals "lorem ***** dolor ***". I know how to do this with repeated replaceAll invokations, but I'm wondering, is this possible to do with a single replaceAll?

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  • How can I match everything in a string until the second occurrence of a delimiter with a regular expression?

    - by Steve
    I am trying to refine a preg_match_all by finding the second occurrence of a period then a space: <?php $str = "East Winds 20 knots. Gusts to 25 knots. Waters a moderate chop. Slight chance of showers."; preg_match_all ('/(^)((.|\n)+?)(\.\s{2})/',$str, $matches); $dataarray=$matches[2]; foreach ($dataarray as $value) { echo $value; } ?> But it does not work: the {2} occurrence is incorrect. I have to use preg_match_all because I am scraping dynamic HTML. I want to capture this from the string: East Winds 20 knots. Gusts to 25 knots.

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  • PHP: Return string between two characters

    - by Nic Hubbard
    I am wanting to use "keywords" within a large string. These keywords start and end using *my_keyword* and are user defined. How, within a large string, can I search and find what is between the two * characters and return each instance? The reason it might change it, that parts of the keywords can be user defined, such as *page_date_Y* which might show the year in which the page was created. So, again, I just need to do a search and return what is between those * characters. Is this possible, or is there a better way of doing this if I don't know the "keyword" length or what i might be?

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  • JavaScript: add or subtract from number in string

    - by yoavf
    I have a string that looks like "(3) New stuff" where 3 can be any number. I would like to add or subtract to this number. I figured out the following way: var thenumber = string.match((/\d+/)); thenumber++; string = string.replace(/\(\d+\)/ ,'('+ thenumber +')'); Is there a more elegant way to do it?

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  • Finding C#-style unescaped strings using regular expressions

    - by possan
    I'm trying to write a regular expression that finds C#-style unescaped strings, such as string x = @"hello world"; The problem I'm having is how to write a rule that handles double quotes within the string correctly, like in this example string x = @"before quote ""junk"" after quote"; This should be an easy one, right?

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  • what is the regular expression for this

    - by bn
    I want to parse this (adv) much (thanks) I want to eliminate the words and the bracket (adv) but not (thanks) the condition is: inside bracket, and word length inside bracket is 1-5 characters I am using preg_match in PHP Thank You

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  • Next line matching the regex in bash

    - by Lin_freak
    I have a file in the format: Port Number IP address Port Number IP address (Not sure how the output will be displayed here but let me tell you they are on separate lines) and so on.... I use the command grep -C 1 'port number' file.txt i.e. I want all IP addresses corresponding to a particular port. Making it simple, I want the next line matching a regular expression. Like if my regular expression matches line 2,4 and 6 then I want lines 3, 5 and 7 to be printed. How to do that?

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  • java - check if string ends with certain pattern

    - by The Learner
    I have string like: This.is.a.great.place.too.work. (or) This/is/a/great/place/too/work/ than my java program should give me that the sentence is valid and it has "work". if i Have : This.is.a.great.place.too.work.hahahha (or) This/is/a/great/place/too/work/hahahah Should not give me that there is a work in the sentance. so I am looking at java strings to find a word at the end of the sentance having . (or),(or)/ before it. How can I achieve that

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