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  • What is difference between "Office SharePoint Server Search" and "Windows SharePoint Services Searc

    - by Keshaw Khandelwal
    Hi, I have MOSS 2007 environment with multiple WFE servers. can any one know what is difference between "Office SharePoint Server Search" and "Windows SharePoint Services Search ". Which service i have to start ? If i have to Start "Office SharePoint Server Search" then what is the meaning of giving "Windows SharePoint Services Search " in Central Administration. ---Keshaw

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  • write behind cache Ehcache new feature?

    - by cometta
    Hi, i looking for guide/document/tutorial on how to use this new feature write-behind-cache in ehcache? Is there any demo in spring+jpa+ehcache+hibernate? just to clariyfing, write-behind-cache mean each time we persist entity, it will be written into cache rather than into database correct?

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  • Rolling back a transaction in a Grails Service

    - by UltraVi01
    I have been updating all my services to be transactional by using Grail's ability to rollback when a RuntimeException is thrown in the service. I have, in most cases, doing this: def domain = new Domain(field: field) if (!domain.save()) { throw new RuntimeException() } Anyways, I wanted to verify that this indeed will rollback the transaction... it got me thinking as to whether at this point it's already been committed.. Also, if not, would setting flush:true change that? I am not very familiar with how Spring/Hibernate does all of this :)

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  • How can i resolve the N+1 Selects problem ?

    - by Maxime ARNSTAMM
    Hello everyone, I have trouble understanding how to avoid the n+1 select in jpa or hibernate. From what i read, there's the 'left join fetch', but i'm not sure if it still works with more than one list (oneToMany).. Could someone explain it to me, or give me a link with a clear complete explanation please ? I'm sorry if this is a noob question, but i can't find a real clear article or doc on this issue. Thanks

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  • I simple search controller that stores search history, should I use resource routing or non-resource?

    - by vfilby
    I am learning rails and am toying with a simple web-app that integrates with flickr to search photos based on user given criteria and store the query in a search history table. I am seeking the best or 'rails' way of handling this. Should I setup a controller and non-resource routes that handle the search and store the data in a custom table; or should I create a resource for queries with a resource route and an additional path for search?

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  • HQl equivalent of sql query

    - by kash
    String SQL_QUERY = "SELECT count(*) FROM (SELECT * FROM Url as U where U.pageType=" + 1 + " group by U.pageId having count(U.pageId) = 1)"; query = session.createQuery(SQL_QUERY); I am getting an error org.hibernate.hql.ast.QuerySyntaxException: unexpected token: ( near line 1, column 23 [ SELECT count() FROM (SELECT * FROM Url as U where U.pageType = 2 group by U.pageId having count(U.pageId) = 1)]

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  • Using - Instead of + in WordPress Search Permalink

    - by poer
    Options +FollowSymLinks RewriteEngine On RewriteCond %{THE_REQUEST} ^[A-Z]+ /(#[^?& ]*)??([^& ]*&)?s=([^& ]+)[^ ]* HTTP/ RewriteRule ^$ http://wordpressblog.com/search/%3? [R=301,L] Currently I use the above .htaccess mod_rewrite rule to convert default WordPress search permalink: http://wordpressblog.com/?s=key+word into nice permalink like this: http://wordpressblog.com/search/key+word My question is: What part of the mod_rewrite rule above that I need to change to get a nicer permalink like this one: http://wordpressblog.com/search/key-word.html Thanks.

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  • Two Persistence Units, Two entityManagerFactory(s), SPring, JPA, Hibernate

    - by sebajb
    I am using Two entityManagerFactory{1,2} based on two persistence units, autowired through spring, hibernate, with resource local. My DaoImpls are configured with the PersistenceUnit(unitName='...') according to the unit needed. I was under the impression that using them with the unitName specified would allow me to use x number of PUs without problem but I still get: expected single matching bean but found two: [emf1, emf2]. Am I missing some other configuration?

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  • Why this search can not generate correct result?

    - by user482742
    Hi, All: Below is to find same customer and if he is in list, the number add one. If he is not in the list, just add him in the list. I use Search function to do this, but failed and generated incorrect records. It can not find the customer or the right number of customers. But if I use For..loop to iterate the list, it does well and can find the customer and add new customer in that for..loop search procedure. (I did not paste for ..loop search procedrue here). Another problem is that there is no difference between setting list.sorted true and false. It seems Search function is not correct. This search function is from an example of delphi textbook. The below is with Delphi 7. Thank you. Procedure Form1.create; begin list:=Tstringlist.create; list.sorted:=true; // Search function will generate exactly Same and Incorrect //records no matter list.sorted is set true or false. list.duplicates:=dupignore; .. end; Procedure addcustomer; var .. begin while p1.MatchAgain do begin //p1 is regular expression customer:=p1.MatchedExpression; if (search(customer)=false) then begin list.Add(customer+'=1'); end; allcustomer:=allcustomer+1; .. end; Function Tform1.search(customer: string): boolean; var fre:string; num:integer; L:integer; R:integer; M: Integer; CompareResult: Integer; found: boolean; begin result:=false; found:=false; L := 0; R := List.Count - 1; while (L <= R) and ( not found ) do begin M := (L + R) div 2; CompareResult := Comparetext(list.Names[m]), customer); if (compareresult=0) then begin fre:=list.ValueFromIndex [m]; num:=strtoint(fre); num:=num+1; list.ValueFromIndex[m]:=inttostr(num); Found := True; Result := true; exit; end else if compareresult > 0 then r := m - 1 else l := m + 1; end; end;

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  • What does the length attribute do when set on the @Column JPA annontation?

    - by James McMahon
    What exactly does setting the length on a column do in JPA? @Column(name = "middle_name", nullable = false, length = 32) public String getMiddleName() { return this.middleName; } I understand that you can use the annotations to generate the database schema based on the entity objects, but does length do any sort of check or truncation when persistence happens, or it solely used for schema creation? I also realize that JPA can sit on top of various implementations, the implementation I am concerned with in this case, is Hibernate.

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  • JPA and compatibility with persistance providers and databases vendors

    - by Kartoch
    JPA promises to be vendor neutral for persistence and database. But I already know than some persistence frameworks like hibernate are not perfect (character encoding, null comparison) and you need to adapt your schema for each database. Because there is two layers (the persistence framework and database), I would imagine they're some work to use some JPA codes... Does anyone has some experiences with multiple support and if yes, what are the tricks and recommendations to avoid such incompatibilities ?

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  • Problem persisting inheritance tree

    - by alaiseca
    I have a problem trying to map an inheritance tree. A simplified version of my model is like this: @MappedSuperclass @Embeddable public class BaseEmbedded implements Serializable { @Column(name="BE_FIELD") private String beField; // Getters and setters follow } @MappedSuperclass @Embeddable public class DerivedEmbedded extends BaseEmbedded { @Column(name="DE_FIELD") private String deField; // Getters and setters follow } @MappedSuperclass public abstract class BaseClass implements Serializable { @Embedded protected BaseEmbedded embedded; public BaseClass() { this.embedded = new BaseEmbedded(); } // Getters and setters follow } @Entity @Table(name="MYTABLE") @Inheritance(strategy=InheritanceType.SINGLE_TABLE) @DiscriminatorColumn(name="TYPE", discriminatorType=DiscriminatorType.STRING) public class DerivedClass extends BaseClass { @Id @Column(name="ID", nullable=false) private Long id; @Column(name="TYPE", nullable=false, insertable=false, updatable=false) private String type; public DerivedClass() { this.embedded = new DerivedClass(); } // Getters and setters follow } @Entity @DiscriminatorValue("A") public class DerivedClassA extends DerivedClass { @Embeddable public static NestedClassA extends DerivedEmbedded { @Column(name="FIELD_CLASS_A") private String fieldClassA; } public DerivedClassA() { this.embedded = new NestedClassA(); } // Getters and setters follow } @Entity @DiscriminatorValue("B") public class DerivedClassB extends DerivedClass { @Embeddable public static NestedClassB extends DerivedEmbedded { @Column(name="FIELD_CLASS_B") private String fieldClassB; } public DerivedClassB() { this.embedded = new NestedClassB(); } // Getters and setters follow } At Java level, this model is working fine, and I believe is the appropriate one. My problem comes up when it's time to persist an object. At runtime, I can create an object which could be an instance of DerivedClass, DerivedClassA or DerivedClassB. As you can see, each one of the derived classes introduces a new field which only makes sense for that specific derived class. All the classes share the same physical table in the database. If I persist an object of type DerivedClass, I expect fields BE_FIELD, DE_FIELD, ID and TYPE to be persisted with their values and the remaining fields to be null. If I persist an object of type DerivedClass A, I expect those same fields plus the FIELD_CLASS_A field to be persisted with their values and field FIELD_CLASS_B to be null. Something equivalent for an object of type DerivedClassB. Since the @Embedded annotation is at the BaseClass only, Hibernate is only persisting the fields up to that level in the tree. I don't know how to tell Hibernate that I want to persist up to the appropriate level in the tree, depending on the actual type of the embedded property. I cannot have another @Embedded property in the subclasses since this would duplicate data that is already present in the superclass and would also break the Java model. I cannot declare the embedded property to be of a more specific type either, since it's only at runtime when the actual object is created and I don't have a single branch in the hierarchy. Is it possible to solve my problem? Or should I resignate myself to accept that there is no way to persist the Java model as it is? Any help will be greatly appreciated.

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  • Loading index in MemoryIndex instance

    - by Javi
    Hello, Is there any way to load an existing index into an instance of MemoryIndex?. I have an application which uses Hibernate Search so I can use index() in FullTextEntityManager instance to index an object. I'd like to recover back the created index and insert it into a MemoryIndex instance to execute several queries over it. Is it possible? Thanks.

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  • [Grails] HibernateException: No session currently bound to execution context

    - by user289206
    I'm trying to create a very basic REST-ish web service with Grails and Postgres. I have the read() & delete() methods working, but I can't get create() to work. Hibernate just gripes, "HibernateException: No session currently bound to execution context." Here's my create method: def create = { def member = new Member(params) member.save() render(status: 201) } Any advice would be great. Thanks.

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  • How much memory does a hashtable use?

    - by Michael
    Would a hashtable/hashmap use a lot of memory if it only consists of object references and int's? As for a school project we had to map a database to objects (that's what being done by orm/hibernate nowadays) but eager to find a good way not to store id's in objects in order to save them again we thought of putting all objects we created in a hashmap/hashtable, so we could easily retrieve it's ID. My question is if it would cost me performance using this, in my opinion more elegant way to solve this problem.

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  • Unable to create session object

    - by Steven
    hi, i used the code Session session = new Configuration().configure(cfgurl).buildSessionFactory().openSession() ; to create a session. the cfgurl is of type URL and points to the hibernate.cfg.xml file of another project. The problem is it is getting hanged and unable to proceed further. What is the problem? Help

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  • Loading index in MamoryIndex instance

    - by Javi
    Hello, Is there any way to load an existing index into an instance of MemoryIndex?. I have an application which uses Hibernate Search so I can use index() in FullTextEntityManager instance to index an object. I'd like to recover back the created index and insert it into a MemoryIndex instance to execute several queries over it. Is it possible? Thanks.

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  • saveOrUpdate(Object) method of Hibernate

    - by Vikram
    when i use saveOrUpdate(Object) method of Hibernate. How can I know that row is updated or new row added into table??? Return type of method saveOrUpdate(Object) is void, so am not able to find out the result after calling this method. kindly help me.

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