Search Results

Search found 21888 results on 876 pages for 'django rest framework'.

Page 144/876 | < Previous Page | 140 141 142 143 144 145 146 147 148 149 150 151  | Next Page >

  • possible to make codeigniter work with another framework?

    - by ajsie
    the situation is this. my client (who also is a programmer) asks me to develop an address book (with mysql database) with a lot of functions. then he can interact with some class methods i provide for him. kinda like an API. the situation is that the address book application is getting bigger and bigger, and i feel like its way better to use CodeIgniter to code it with MVC. i wonder if i can use codeigniter, then in some way give him the access to controller methods. eg. in a controller there are some functions u can call with the web browser. public function create_contact($information) {..} public function delete_contact($id) {..} public function get_contact($id) {..} however, these are just callable from web browser. how can i let my client have access to these functions like an API? then in his own application he can use: $result = $address_book-create_contact($information); if($result) { echo "Success"; } $contact = $address_book-get_contact($id); is this possible? cause i just know how to access the controller methods with the webbrowser. and i guess its not an option for him to use header(location) to access them. all suggestions to make this possible are welcomed! thanks

    Read the article

  • is it safe to refactor my django models?

    - by Johnd
    My model is similar to this. Is this ok or should I make the common base class abstract? What are the differcenes between this or makeing it abstract and not having an extra table? It seems odd that there is only one primary key now that I have factored stuff out. class Input(models.Model): details = models.CharField(max_length=1000) user = models.ForeignKey(User) pub_date = models.DateTimeField('date published') rating = models.IntegerField() def __unicode__(self): return self.details class Case(Input): title = models.CharField(max_length=200) views = models.IntegerField() class Argument(Input): case = models.ForeignKey(Case) side = models.BooleanField() is this ok to factor stuff out intpu Input? I noticed Cases and Arguments share a primary Key. like this: CREATE TABLE "cases_input" ( "id" integer NOT NULL PRIMARY KEY, "details" varchar(1000) NOT NULL, "user_id" integer NOT NULL REFERENCES "auth_user" ("id"), "pub_date" datetime NOT NULL, "rating" integer NOT NULL ) ; CREATE TABLE "cases_case" ( "input_ptr_id" integer NOT NULL PRIMARY KEY REFERENCES "cases_input" ("id"), "title" varchar(200) NOT NULL, "views" integer NOT NULL ) ; CREATE TABLE "cases_argument" ( "input_ptr_id" integer NOT NULL PRIMARY KEY REFERENCES "cases_input" ("id"), "case_id" integer NOT NULL REFERENCES "cases_case" ("input_ptr_id"), "side" bool NOT NULL )

    Read the article

  • How to set the session timeout in Zend Framework 2

    - by user2261761
    I don't have much Zend experience and want to change someone's login code in Zend to make the session not expire. It seems the code is basic behavior: $adapter = $this->getAuthService()->getAdapter(); $adapter->setIdentity($email)->setCredential($password); $result = $this->getAuthService()->authenticate(); What do I have to do to make the session not expire or to at least set the session for a specific time? Right now the user doesn't stay logged in for long, I think perhaps it is just relying on default php settings behavior like the standard 24 minutes for the gc_maxlifetime. What is the connection between Zend_Session and AuthService?

    Read the article

  • Django: HTTPS for just login page?

    - by Mark
    I just added this SSL middleware to my site http://www.djangosnippets.org/snippets/85/ which I used to secure only my login page so that passwords aren't sent in clear-text. Of course, when the user navigates away from that page he's suddenly logged out. I understand why this happens, but is there a way to pass the cookie over to HTTP so that users can stay logged in? If not, is there an easy way I can use HTTPS for the login page (and maybe the registration page), and then have it stay on HTTPS if the user is logged in, but switch back to HTTP if the user doesn't log in? There are a lot of pages that are visible to both logged in users and not, so I can't just designate certain pages as HTTP or HTTPS.

    Read the article

  • Entity framework Update fails when object is linked to a missing child

    - by McKay
    I’m having trouble updating an objects child when the object has a reference to a nonexising child record. eg. Tables Car and CarColor have a relationship. Car.CarColorId CarColor.CarColorId If I load the car with its color record like so this var result = from x in database.Car.Include("CarColor") where x.CarId = 5 select x; I'll get back the Car object and it’s Color object. Now suppose that some time ago a CarColor had been deleted but the Car record in question still contains the CarColorId value. So when I run the query the Color object is null because the CarColor record didn’t exist. My problem here is that when I attach another Color object that does exist I get a Store update, insert error when saving. Car.Color = newColor Database.SaveChanges(); It’s like the context is trying to delete the nonexisting color. How can I get around this?

    Read the article

  • Django: ordering numerical value with order_by

    - by h3
    I'm in a situation where I must output a quite large list of objects by a CharField used to store street addresses. My problem is, that obviously the data is ordered by ASCII codes since it's a Charfield, with the predictable results .. it sort the numbers like this; 1, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 2, 20, 21.... Now the obvious step would be to change the Charfield the proper field type (IntegerField let's say), however it cannot work since some address might have apartments .. like "128A". I really don't know how I can order this properly ..

    Read the article

  • Django: optimizing queries

    - by Josh
    I want to list the number of items for each list. How can I find this number in a single query, rather than a query for each list? Here is a simplified version of my current template code: {% for list in lists %} <li> {{ listname }}: {% with list.num_items as item_count %} {{ item_count }} item{{ item_count|pluralize }} {% endwith %} </li> {% endfor %} lists is passed as: List.objects.filter(user=user) and num_items is a property of the List model: def _get_num_items(self): return self.item_set.filter(archived=False).count() num_items = property(_get_num_items) This queries SELECT COUNT(*) FROM "my_app_item" WHERE... n times, where n is the number of lists. Is it possible to make a single query here?

    Read the article

  • Question creating PDF document in Zend Framework

    - by deaddancer
    I need to take a ZF rendered view and create a PDF that should look pretty much exactly the same, and email it. The major issue I have right now is getting the HTML created by the view into a string that I can then process with the Zend_PDF::parse method. The view I need to turn into a PDF is the result of a posted form. I've tried grabbing the contents of ob_get_contents into a string after a successful post, but for some reason its not in there. Should I press on with this angle? Any help would be greatly appreciated!

    Read the article

  • Query Entity Framework 4

    - by nick
    Hi, Is it possible to run a query on an EF4.0 data context and get all objects of a certain type? Say the context has books, genres & authors but I only have a generic parameter, t. Is it possible to get all of type just by using this t? I don't think it is :(

    Read the article

  • .NET Compact Framework app that will run on both Professional and Standard

    - by CJCraft.com
    Is there any guidance on creating apps that will run on both professional (touch-screen) and standard (non-touch-screen) devices. I have a simple application that is mostly text and buttons that in theory should be able to run on both professional and standard devices with little if any modification. It seems the IDE wants to make this hard to impossible, but I expect it to be possible. Any advice?

    Read the article

  • Django: Inject errors into already validated form?

    - by Parand
    After my form.Form validates the user input values I pass them to a separate (external) process for further processing. This external process can potentially find further errors in the values. Is there a way to inject these errors into the already validated form so they can be displayed via the usual form error display methods? Or, are there better alternative approaches? One suggestions was to include the external processing in the form validation. I'm not crazy about this since the external process does a lot more than just validate.

    Read the article

  • Entity Framework with SQL Server 2000 (APPLY Operator) issue

    - by How Lun
    Hello, I have a simple Linq query below: var seq = (from n in GetObjects() select n.SomeKey) .Distinct() .Count(); This query works find with SQL Server 2005 and above. But, this start to give headache when I hooked the EF to SQL Server 2000. Because EF is using APPLY operator which only SQL Server 2005 and above can be supported. I do not know why the hell EF is using APPLy operator instead of sub queries. My current work around is: var seq = (from n in GetObjects() select n.SomeKey) .Distinct() .ToList() .Count(); But, I can forsee more problems to come. The above query is just a simple one. Did anyone come across such issue? And how you guys work around it? Or is there a way to force EF not to use APPLY operator? Any help will be very much appreciated. How Lun.

    Read the article

  • Add Page Parameter in Zend Framework Doesn't Work

    - by deerawan
    Hello guys, I've been trying to figure this out these days. I got a problem when I want to add 'page' parameter in my URL for my pagination. This is my router -addRoute('budi',new Zend_Controller_Router_Route(':lang/budi',array('controller' = 'budi', 'action' = 'index', 'page' = 1), array('lang'=$s, 'page' = '\d+'))) -addRoute('budi1',new Zend_Controller_Router_Route(':lang/budi/page/:page',array('controller' = 'budi', 'action' = 'index', 'page' = 1), array('lang'=$s, 'page' = '\d+'))) Then I access my URL http://localhost/learningsystem/en/budi but when I hover on my pagination links, the page parameter doesn't appear. The URL is still http://localhost/learningsystem/en/budi but if I enter same URL with index in the end like this one http://localhost/learningsystem/en/budi/index or like this one http://localhost/learningsystem/en/budi/page/1 the page parameter appears perfectly when I click the page 2 link http://localhost/learningsystem/en/budi/index/page/2 Actually, I don't want include 'index' or 'page' at first in my URL. Anyway, I use default pagination.phtml template from Zend. Anyone please help me to solve this problem? Thank you very much

    Read the article

  • How to retrieve base class only (entity framework)?

    - by Juvaly
    Hi All, I've been scratching my head here for a while now... I have a Consumer class and a BillableConsumer class that inherits Consumer. They are both a part of the Consumers set. The problem is that this following query: Consumer consumer = (from c in _ctx.Consumers where c.ID = id select c).First(); returns a BillableConsumer instance! Just the same as this query: BillableConsumer bconsumer = (from c in _ctx.Consumers.OfType<BillableConsumer>() where c.ID = id select c).First(); How can I return an instance of just the base class? (these are separate tables in the data store).

    Read the article

  • Finding object count where a field is unique in Django

    - by Johnd
    I have a model that is something like this: class Input(models.Model): details = models.CharField(max_length=1000) user = models.ForeignKey(User) class Case(Input): title = models.CharField(max_length=200) views = models.IntegerField() class Argument(Input): case = models.ForeignKey(Case) side = models.BooleanField() A user can submit many arguments, per case. I want to be able to say how many users have submitted side=true arguments. I mean if 1 user had 10 arguments and another user had 2 arguments (both side=true) I'd want the count to be 2, not 12.

    Read the article

  • sending the data from form to db in django

    - by BharatKrishna
    I have a form in which I can input text through text boxes. How do I make these data go into the db on clicking submit. this is the code of the form in the template. <form method="post" action="app/save_page"> <p> Title:<input type="text" name="title"/> </p> <p> Name:<input type="text" name="name"/> </p> <p> Phone:<input type="text" name="phone"/> </p> <p> Email:<input type="text" name="email"/> </p> <p> <textarea name="description" rows=20 cols=60> </textarea><br> </p> <input type="submit" value="Submit"/> </form> I have a function in the views.py for saving the data in the page. But I dont know how to impliment it properly: def save_page(request): title = request.POST["title"] name = request.POST["name"] phone = request.POST["phone"] email = request.POST["email"] description = request.POST["description"] Now how do I send these into the db? And what do I put in views.py so that those data goes into the db? so how do I open a database connection and put those into the db and save it? should I do something like : connection=sqlite3.connect('app.db') cursor= connection.cursor() ..... ..... connection.commit() connection.close() Thank you.

    Read the article

  • Django: Save an uploaded file to a FileField

    - by David Wolever
    I feel a little stupid for having to ask this… But I can't seem find it documented anywhere. If I've got a Model with FileField, how can I stuff an uploaded FILE into that FileField? For example, I'd like to do something like this: class MyModel(Model): file = FileField(...) def handle_post(request, ...): mymodel = MyModel.objects.get(...) if request.FILES.get("newfile"): mymodel.file = request.FILES["newfile"] But that doesn't appear to work.

    Read the article

  • Django - count date between

    - by DJPy
    I have many record in my database wich contains datetime field (e.g. 2010-05-23 17:45:57). I want to count all records between e.g. 15:00 and 15:59 (it all can by from other day, month or year). How can I do this?

    Read the article

  • Django query - join on the same table

    - by dana
    i have a mini blog app, and a 'timeline' . there i want to be displayed all the posts from all the friends of a user, plus the posts of that user himself. For that, i have to make some kind of a 'join' between the results of two queries (queries on the same table) , so that the final result will be the combination of the user - posesor of the account, and all his friends. My query looks like this: blog = New.objects.filter(created_by = following,created_by = request.user) By that ',' i wanted to make a 'join' -i found something like this on a doc- but this method is not correct- i'm getting an error. How else could be done this 'join' ? Thanks!

    Read the article

< Previous Page | 140 141 142 143 144 145 146 147 148 149 150 151  | Next Page >