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  • How to implement table-per-concrete-type using entity framework

    - by SDReyes
    Hello Guys! I'm mapping a set of tables that share a common set of fields: So as you can see I'm using a table-per-concrete-type strategy to map the inheritance. But... I have not could to relate them to an abstract type containing these common properties. It's possible to do it using EF? BONUS: The only non documented Entity Data Model Mapping Scenario is Table-per-concrete-type inheritance http://msdn.microsoft.com/en-us/library/cc716779.aspx : P

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  • Adding fields to Django form dynamically (and cleanly)

    - by scott
    Hey guys, I know this question has been brought up numerous times, but I'm not quite getting the full implementation. As you can see below, I've got a form that I can dynamically tell how many rows to create. How can I create an "Add Row" link that tells the view how many rows to create? I would really like to do it without augmenting the url... # views.py def myView(request): if request.method == "POST": form = MyForm(request.POST, num_rows=1) if form.is_valid(): return render_to_response('myform_result.html', context_instance=RequestContext(request)) else: form = MyForm(num_rows=1) return render_to_response('myform.html', {'form':form}, context_instance=RequestContext(request)) # forms.py class MyForm(forms.Form): def __init__(self, *args, **kwargs): num_rows = kwargs.pop('num_rows',1) super(MyForm, self).__init__(*args, **kwargs) for row in range(0, num_rows): field = forms.CharField(label="Row") self.fields[str(row)] = field # myform.html http://example.com/myform <form action="." method="POST" accept-charset="utf-8"> <ul> {% for field in form %} <li style="margin-top:.25em"> <span class="normal">{{ field.label }}</span> {{ field }} <span class="formError">{{ field.errors }}</span> </li> {% endfor %} </ul> <input type="submit" value="Save"> </form> <a href="ADD_ANOTHER_ROW?">+ Add Row</a>

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  • change available checkboxes after select[html] changed - Zend Framework

    - by Lormitto
    Hi, Could you please help me rosolve my troubling matter. I used Zend_Form to create what I needed. However as I have relations many to many i decided to present multiple choices via checkboxes. Unfortunately range of these checkboxes depends on select field available in form. I would like to change visible/availabe checkboxes depending on select option choosen. I found that it should be possible to use javascript however I've got no idea how to take advantege of it in form based on Zend_Form. Could you suggest possible solution? Thank you in advance. Kind Regards,

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  • Customizing Django Form: Required and InputId?

    - by Mark
    I'm trying to customize how my form is displayed by using a form_snippet as suggested in the docs. Here's what I've come up with so far: {% for field in form %} <tr> <th><label for="{{ field.html_name }}">{{ field.label }}:</label></th> <td> {{ field }} {% if field.help_text %}<br/><small class="help_text">{{ field.help_text }}</small>{% endif %} {{ field.errors }} </td> </tr> {% endfor %} Of course, field.html_name is not what I'm looking for. I need the id of the input field. How can I get that? Also, is there a way I can determine if the field is required, so that I can display an asterisk beside the label?

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  • Django: HTTPS for just login page?

    - by Mark
    I just added this SSL middleware to my site http://www.djangosnippets.org/snippets/85/ which I used to secure only my login page so that passwords aren't sent in clear-text. Of course, when the user navigates away from that page he's suddenly logged out. I understand why this happens, but is there a way to pass the cookie over to HTTP so that users can stay logged in? If not, is there an easy way I can use HTTPS for the login page (and maybe the registration page), and then have it stay on HTTPS if the user is logged in, but switch back to HTTP if the user doesn't log in? There are a lot of pages that are visible to both logged in users and not, so I can't just designate certain pages as HTTP or HTTPS.

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  • Does Entity Framework saves related classes automatically?

    - by herbatnic
    Let's assume that we have such classes public class A{ string someField { get; set; } public virtual B B {get; set; } } public class B { int someIntField {get; set; } [ForeignKey("Id")] [Required] public virtual A A { get; set; } } In code I create new instances for both of them and making relation like: A a = new A () { someField = "abcd"}; B b = new B () { someIntField = 42 }; A.B = b; B.A = a; Should I using DBContext to save both classes like that: using (var db = new myDbContext()) { myDbContext.As.Add(A); myDbContext.Bs.Add(B); myDBContext.SaveChanges(); } Or saving it like that: using (var db = new myDbContext()) { myDbContext.As.Add(A); myDbContext.SaveChanges(); } is enough to store related objects into database?

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  • Zend Framework: How do I modify/format the form view generated with Zend_Dojo_Form elements

    - by pinardelrio
    I have created a form: <?php class Application_Form_Issue extends Zend_Dojo_Form { public function init() { $this->setName('issue'); $this->setMethod('post'); $id = new Zend_Form_Element_Hidden('id'); $id->addFilter('Int'); $date_recvd = new Zend_Dojo_Form_Element_DateTextBox('date_recvd'); $date_recvd->setLabel('Date Received') //->setRequired(true) /*->addValidator('NotEmpty'); */; More Form elements ... To view this form my view script is: <?php echo $this->form; ?> This all works just fine, with fully functional dojo form elements (datepicker, timepicker, etc) and successfully saving the data. However, now, I want to format the form that is generated with css. Such as grouping some elements and floating left or right, making some input text fields wider/narrower, etc. How? I realize I can modify the view script but it seems like that defeats the purpose of using Zend_Dojo_Form or Zend_Form. Is that a correct assumption?

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  • Finding object count where a field is unique in Django

    - by Johnd
    I have a model that is something like this: class Input(models.Model): details = models.CharField(max_length=1000) user = models.ForeignKey(User) class Case(Input): title = models.CharField(max_length=200) views = models.IntegerField() class Argument(Input): case = models.ForeignKey(Case) side = models.BooleanField() A user can submit many arguments, per case. I want to be able to say how many users have submitted side=true arguments. I mean if 1 user had 10 arguments and another user had 2 arguments (both side=true) I'd want the count to be 2, not 12.

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  • add new records using signal in django admin

    - by ganesh
    I've a model called broadcastinfo, It has fields viz.. info,userid...userid is excluded. when i add an new info, my broadcastinfo table should get the records of all userid from user table and the given message. Im trying this via signal.Any idea is highly appreciated. Thanks

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  • Need help optimizing this Django aggregate query

    - by Chris Lawlor
    I have the following model class Plugin(models.Model): name = models.CharField(max_length=50) # more fields which represents a plugin that can be downloaded from my site. To track downloads, I have class Download(models.Model): plugin = models.ForiegnKey(Plugin) timestamp = models.DateTimeField(auto_now=True) So to build a view showing plugins sorted by downloads, I have the following query: # pbd is plugins by download - commented here to prevent scrolling pbd = Plugin.objects.annotate(dl_total=Count('download')).order_by('-dl_total') Which works, but is very slow. With only 1,000 plugins, the avg. response is 3.6 - 3.9 seconds (devserver with local PostgreSQL db), where a similar view with a much simpler query (sorting by plugin release date) takes 160 ms or so. I'm looking for suggestions on how to optimize this query. I'd really prefer that the query return Plugin objects (as opposed to using values) since I'm sharing the same template for the other views (Plugins by rating, Plugins by release date, etc.), so the template is expecting Plugin objects - plus I'm not sure how I would get things like the absolute_url without a reference to the plugin object. Or, is my whole approach doomed to failure? Is there a better way to track downloads? I ultimately want to provide users some nice download statistics for the plugins they've uploaded - like downloads per day/week/month. Will I have to calculate and cache Downloads at some point? EDIT: In my test dataset, there are somewhere between 10-20 Download instances per Plugin - in production I expect this number would be much higher for many of the plugins.

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  • Question creating PDF document in Zend Framework

    - by deaddancer
    I need to take a ZF rendered view and create a PDF that should look pretty much exactly the same, and email it. The major issue I have right now is getting the HTML created by the view into a string that I can then process with the Zend_PDF::parse method. The view I need to turn into a PDF is the result of a posted form. I've tried grabbing the contents of ob_get_contents into a string after a successful post, but for some reason its not in there. Should I press on with this angle? Any help would be greatly appreciated!

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  • sending the data from form to db in django

    - by BharatKrishna
    I have a form in which I can input text through text boxes. How do I make these data go into the db on clicking submit. this is the code of the form in the template. <form method="post" action="app/save_page"> <p> Title:<input type="text" name="title"/> </p> <p> Name:<input type="text" name="name"/> </p> <p> Phone:<input type="text" name="phone"/> </p> <p> Email:<input type="text" name="email"/> </p> <p> <textarea name="description" rows=20 cols=60> </textarea><br> </p> <input type="submit" value="Submit"/> </form> I have a function in the views.py for saving the data in the page. But I dont know how to impliment it properly: def save_page(request): title = request.POST["title"] name = request.POST["name"] phone = request.POST["phone"] email = request.POST["email"] description = request.POST["description"] Now how do I send these into the db? And what do I put in views.py so that those data goes into the db? so how do I open a database connection and put those into the db and save it? should I do something like : connection=sqlite3.connect('app.db') cursor= connection.cursor() ..... ..... connection.commit() connection.close() Thank you.

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  • possible to make codeigniter work with another framework?

    - by ajsie
    the situation is this. my client (who also is a programmer) asks me to develop an address book (with mysql database) with a lot of functions. then he can interact with some class methods i provide for him. kinda like an API. the situation is that the address book application is getting bigger and bigger, and i feel like its way better to use CodeIgniter to code it with MVC. i wonder if i can use codeigniter, then in some way give him the access to controller methods. eg. in a controller there are some functions u can call with the web browser. public function create_contact($information) {..} public function delete_contact($id) {..} public function get_contact($id) {..} however, these are just callable from web browser. how can i let my client have access to these functions like an API? then in his own application he can use: $result = $address_book-create_contact($information); if($result) { echo "Success"; } $contact = $address_book-get_contact($id); is this possible? cause i just know how to access the controller methods with the webbrowser. and i guess its not an option for him to use header(location) to access them. all suggestions to make this possible are welcomed! thanks

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  • Django: Inject errors into already validated form?

    - by Parand
    After my form.Form validates the user input values I pass them to a separate (external) process for further processing. This external process can potentially find further errors in the values. Is there a way to inject these errors into the already validated form so they can be displayed via the usual form error display methods? Or, are there better alternative approaches? One suggestions was to include the external processing in the form validation. I'm not crazy about this since the external process does a lot more than just validate.

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  • Python/Django tests running only one test at a time

    - by user2876296
    I have a unittest for my view class TestFromAllAdd(TestCase): fixtures = ['staging_accounts_user.json', 'staging_main_category.json', 'staging_main_dashboard.json', 'staging_main_location.json', 'staging_main_product.json', 'staging_main_shoppinglist.json'] def setUp(self): self.factory = RequestFactory() self.c = Client() self.c.login(username='admin', password='admin') def from_all_products_html404_test(self): request = self.factory.post('main/adding_from_all_products', {'product_id': ''}) request.user = User.objects.get(username= 'admin') response = adding_from_all_products(request) self.assertEqual(response.status_code, 404) But I have a few more classes with tests and I cant run them all at the same time: python manage.py test main doesnt run tests, but if i run; python manage.py test main.TestFromAllAdd.from_all_products_html404_test , runs one test;

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  • Django: ordering numerical value with order_by

    - by h3
    I'm in a situation where I must output a quite large list of objects by a CharField used to store street addresses. My problem is, that obviously the data is ordered by ASCII codes since it's a Charfield, with the predictable results .. it sort the numbers like this; 1, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 2, 20, 21.... Now the obvious step would be to change the Charfield the proper field type (IntegerField let's say), however it cannot work since some address might have apartments .. like "128A". I really don't know how I can order this properly ..

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  • How to join the results of two tables in django python

    - by user1787524
    I have two models class Weather(model.model): region = models.ForeignKey(Region) district = models.ForeignKey(District) temp_max = models.IntegerField(blank=True, null=True, verbose_name='Max temperature (C)') temp_min = models.IntegerField(blank=True, null=True, verbose_name='Min temperature (C)') and class Plan(model.model): name = tinymce_models.HTMLField(blank=True, null=True) region = models.ForeignKey(Region) district = models.ForeignKey(District) Provided for every region and district have unique row. I want to combine the result so that i can get all the columns of both tables These two Models are not related to each other. ' I need to make the join like join weather w on w.region = A.region and w.distric = A.district so that result contains all the columns in everyobject like obj.temp_max etc

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  • How to retrieve base class only (entity framework)?

    - by Juvaly
    Hi All, I've been scratching my head here for a while now... I have a Consumer class and a BillableConsumer class that inherits Consumer. They are both a part of the Consumers set. The problem is that this following query: Consumer consumer = (from c in _ctx.Consumers where c.ID = id select c).First(); returns a BillableConsumer instance! Just the same as this query: BillableConsumer bconsumer = (from c in _ctx.Consumers.OfType<BillableConsumer>() where c.ID = id select c).First(); How can I return an instance of just the base class? (these are separate tables in the data store).

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  • How to verify object creation in Django ?

    - by Martin
    So.. this never crossed my head before but now I just can't figure out how to do that !! I want to verify that the object I created was really created, and return True or False according to that : obj = object(name='plop') try: obj.save() return True except ???: return False Any idea ? Cheers, -M

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  • Query Entity Framework 4

    - by nick
    Hi, Is it possible to run a query on an EF4.0 data context and get all objects of a certain type? Say the context has books, genres & authors but I only have a generic parameter, t. Is it possible to get all of type just by using this t? I don't think it is :(

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  • Django: Save an uploaded file to a FileField

    - by David Wolever
    I feel a little stupid for having to ask this… But I can't seem find it documented anywhere. If I've got a Model with FileField, how can I stuff an uploaded FILE into that FileField? For example, I'd like to do something like this: class MyModel(Model): file = FileField(...) def handle_post(request, ...): mymodel = MyModel.objects.get(...) if request.FILES.get("newfile"): mymodel.file = request.FILES["newfile"] But that doesn't appear to work.

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