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  • Why is my PHP upload script not working?

    - by Turner
    Hello all, I am doing some simple work with uploading a file. I am ignoring error checking and exceptions at this point just to get my uploads working. I have this HTML form: <form action='addResult.php' method='post' enctype='multipart/form-data' target='results_iFrame' onsubmit='startUpload();'> Entry: <input type='text' id='entry' /> Stop: <input type='text' id='stop' /> Final: <input type='text' id='final' /> Chart: <input type='file' id='chart' /> <input type='submit' value='Add' /></form> As you can see, it calls 'addResult.php' within the iFrame 'results_iFrame'. The Javascript is just for animation purposes and to tell me when things are finished. addResult.php has this code in it (along with processing the other inputs): $upload_dir = "../img/"; $chart_loc = $upload_dir.basename($_FILES['chart']['name']); move_uploaded_file($_FILES['chart']['tmp_name'], $chart_loc); print_r($_FILES); It uses the 'chart' input from the form and tries to upload it. I have the print_r() function to display some information on $_FILES, but the array is empty, thus making this fail. What could I be doing wrong?

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  • Recommended/Standard image thumbnails sizes

    - by Rakan
    Hello, Based on my experience in web development, HTML page designs for every website may have different < img tags showing the same image in different sizes. i.e: the website's main page might show the image in 500*500, the listing page might show it in 200*150 and other sections of the website will use different sizes. As you can see the ratios of the images to be displayed to the user are different and therefore will cause a problem in having the image stretched, pixelated and/or other quality problems. How i currently handle this issue is by using a jQuery cropping tool to make the user select the area to crop the thumbnail from. the cropped image is then resized using imagick to fit every position in the page design. However, although i can force the user to crop an image based on a pre-defined ratio, the HTML will still contain image placeholders which require a different ratio for its thumbnail. So for every image, i will have to force the user to crop the uploaded image based on every possible ratio my site requires. I don't think this is a friendly solution, how would you do it? is there a standard/recommended ratio for the web? Thanks

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  • Location of Embedly (JQuery-Preview) Results

    - by user749798
    Embedly/Jquery-Preview has been fantastic. However, I'm trying to change the location of the preview result, and having trouble. Right now, the result appears right below the input field...but I'd rather have it in a separate part of the page. Is there a way to do this? I've tried changing the location of the selector and loading divs, but that hasn't helped. It seems to ignore those divs and put it right below the submit button. Below is my code: <form accept-charset="UTF-8" action="private" class="new_comment" data-remote="true" id="new_comment" method="post"> <input class="photo_comm" id="comment_comment" name="comment[comment]" placeholder="add a comment or link..." size="30" type="text" /><span type="text" id="counter">1000</span> <input class="btn btn-primary btn-mini" data-disable-with="Submitting..." name="commit" type="submit" value="Post" /> </form> <!-- Placeholder that tells Preview where to put the loading icon--> <div class="loading"> <img src='http://embedly.github.com/jquery-preview/images/loading-rectangle.gif'> </div> <!-- Placeholder that tells Preview where to put the selector--> <div class="selector"></div> $('#comment_comment').preview({ key:'60f1dcdf3258476794784148a6eb65e7', // Sign up for a key: http://embed.ly/pricing selector : {type:'rich'}, preview : { submit : function(e, data){ e.preventDefault(); $.ajax({ dataType: 'script', url: this.form.attr('action'), type: 'POST', data: data }); }, }, autoplay : 0, maxwidth : 400, display : {display : 'rich'} });

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  • php while selecting a node should be highlighted.

    - by shaibi
    I need to highlight the node value when I select it.how can I wrirte code for that in php my code is function generate_menu($parent) { $has_childs = false; global $menu_array; foreach($menu_array as $key = $value) { //print_r($value); if ($value['parentid'] == $parent) { if ($has_childs === false) { $has_childs = true; $menu .= '<ul>'; } $clor = 'black'; if(($_GET['id']>0) &&($key == $_GET['id'])) { $clor = '#990000'; } $chld = generate_menu($key); $cls = ($chld != '')? 'folder' : 'file'; $menu .= '<li><span class="'.$cls.'" color='.$clor.'>&nbsp;' . $value['humanid'].'-'.$value['title'] . ' <a href="index.php?id='.$key.'"><img src="images/edit.png" alt=" Edit" title="Edit"/></a></span>'; $menu .= $chld; $menu .= '</li>'; } } if ($has_childs === true) $menu .= '</ul>'; return $menu ; } ?

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  • Object-C: initWithContentsOfURL returning null

    - by AragornSG
    Hey! I'm working on an app that would display a remote html and use local images, so what I'm trying to do is download the HTML of the website and display it as a "local" page, that would have access to images in my bundle. For some reason I can't get initWithContentsOfURL to work. I checked all manuals and examples I could find and it seems that I'm doing it correctly, but the thing just won't work, returns null all the time. The same page loaded with NSURLRequest requestWithURL works fine. Appreciate your help! Here is the code: - (void)awakeFromNib { appURL = @"http://dragontest.fantasy-fan.org"; notConnectedHTML = @"Could not connect."; NSString *seedString = [[NSString alloc] initWithContentsOfURL:[NSURL URLWithString:[NSString stringWithFormat:@"%@/seed.php", appURL]]]; NSString *HTMLdata = @""; if (seedString = @"(null)") { NSLog(@"Can't connect on awakeFromNib."); HTMLdata = notConnectedHTML; }else { HTMLdata = [NSString stringWithFormat:@"<body style='padding:0px;margin:0px;'>%@%@</body>", seedString, @"<br><img src='images/Default.png'>"]; } [homeView loadHTMLString:HTMLdata baseURL:[NSURL fileURLWithPath:[[NSBundle mainBundle] resourcePath]]]; }

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  • ASP.NET enum dropdownlist validation

    - by Arun Kumar
    I have got a enum public enum TypeDesc { [Description("Please Specify")] PleaseSpecify, Auckland, Wellington, [Description("Palmerston North")] PalmerstonNorth, Christchurch } I am binding this enum to drop down list using the following code on page_Load protected void Page_Load(object sender, EventArgs e) { if (TypeDropDownList.Items.Count == 0) { foreach (TypeDesc newPatient in EnumToDropDown.EnumToList<TypeDesc>()) { TypeDropDownList.Items.Add(EnumToDropDown.GetEnumDescription(newPatient)); } } } public static string GetEnumDescription(Enum value) { FieldInfo fi = value.GetType().GetField(value.ToString()); DescriptionAttribute[] attributes = (DescriptionAttribute[])fi.GetCustomAttributes(typeof(DescriptionAttribute), false); if (attributes != null && attributes.Length > 0) return attributes[0].Description; else return value.ToString(); } public static IEnumerable<T> EnumToList<T>() { Type enumType = typeof(T); // Can't use generic type constraints on value types, // so have to do check like this if (enumType.BaseType != typeof(Enum)) throw new ArgumentException("T must be of type System.Enum"); Array enumValArray = Enum.GetValues(enumType); List<T> enumValList = new List<T>(enumValArray.Length); foreach (int val in enumValArray) { enumValList.Add((T)Enum.Parse(enumType, val.ToString())); } return enumValList; } and my aspx page use the following code to validate <asp:DropDownList ID="TypeDropDownList" runat="server" > </asp:DropDownList> <asp:RequiredFieldValidator ID="TypeRequiredValidator" runat="server" ControlToValidate="TypeDropDownList" ErrorMessage="Please Select a City" Text="<img src='Styles/images/Exclamation.gif' />" ValidationGroup="city"></asp:RequiredFieldValidator> But my validation is accepting "Please Specify" as city name. I want to stop user to submit if the city is not selected.

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  • This code is not submitting to a form? Why

    - by Ankur
    Since I am using get I expect to see the submitted values appended to the queryString but instead all I see is the URL of the servlet being called with nothing added at the end. <form id="editClassList" name="editClassList" method="get" action="EditClassList"> <% HashMap<Integer,String> classes = new HashMap<Integer,String>(); classes = (HashMap<Integer,String>) request.getAttribute("classes"); %> <% if(classes.size()==0){ %> <label><input class="small-link" type="text" id="add-this-class" size="42" value="" /></label> <% } %> <% Set<Integer> classIds = new HashSet<Integer>(); classIds = classes.keySet(); Iterator<Integer> itr = classIds.iterator(); while(itr.hasNext()){ int nextId = (Integer)itr.next(); %> <label><input class="small-link" type="text" id="<% out.print(nextId); %>" size="42" value="<% out.print(classes.get(nextId)); %>" /> </label> <img id="add-class" src="images/add.png" width="16" height="16" /><br /> <label><input class="small-link" type="text" id="class-to-add" size="42" value="" /></label> <% } %> <label><input type="submit" id="save-class-btn" value="Save Class(es)" /></label> </form>

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  • Get Browser to send both If-None-Match and If-Modified-Since

    - by Glen
    My Browser isn't sending back an If-Modified-Since Header for PHP generated Content on the first request my script sends: (Status-Line) HTTP/1.1 200 OK Date Thu, 21 Jan 2010 08:55:25 GMT Server Apache/2.2.11 (Win32) PHP/5.2.9-1 X-Powered-By PHP/5.2.9-1 Pragma no-cache x-ua-compatible IE=8;FF=3;OtherUA=4 Last-Modfied Sat, 02 Jan 2010 02:02:20 GMT Content-Length 28453 Etag b98e0795b509be20146f58e06fbb624f Keep-Alive timeout=5, max=90 Connection Keep-Alive Content-Type image/png it on the second request it sends: (Request-Line) GET /kincumberunitingchurch/banner_image.php?id=1 HTTP/1.1 Host localhost User-Agent Mozilla/5.0 (Windows; U; Windows NT 6.1; en-US; rv:1.9.0.17) Gecko/2009122116 Firefox/3.0.17 Accept image/png,image/*;q=0.8,*/*;q=0.5 Accept-Language en-us,en;q=0.5 Accept-Encoding gzip,deflate Accept-Charset ISO-8859-1,utf-8;q=0.7,*;q=0.7 Keep-Alive 300 Connection keep-alive Referer http://localhost/kincumberunitingchurch/index.php?sid=tgl9jq3f71nau3cj9vps6pna03 Cookie sid=tgl9jq3f71nau3cj9vps6pna03; PHPSESSID=m0jvven6d7l65pl6odm9ecfnt4 If-None-Match b98e0795b509be20146f58e06fbb624f Cache-Control max-age=0 for other files the sever sends first: (Status-Line) HTTP/1.1 200 OK Date Thu, 21 Jan 2010 08:55:25 GMT Server Apache/2.2.11 (Win32) PHP/5.2.9-1 Last-Modified Wed, 30 Dec 2009 02:40:58 GMT Etag "1000000013d35-40d9-47be9117f6280" Accept-Ranges bytes Content-Length 16601 Keep-Alive timeout=5, max=84 Connection Keep-Alive Content-Type image/png and my browser send the following on the next request: (Request-Line) GET /kincumberunitingchurch/img/cbuttons.png HTTP/1.1 Host localhost User-Agent Mozilla/5.0 (Windows; U; Windows NT 6.1; en-US; rv:1.9.0.17) Gecko/2009122116 Firefox/3.0.17 Accept image/png,image/*;q=0.8,*/*;q=0.5 Accept-Language en-us,en;q=0.5 Accept-Encoding gzip,deflate Accept-Charset ISO-8859-1,utf-8;q=0.7,*;q=0.7 Keep-Alive 300 Connection keep-alive Referer http://localhost/kincumberunitingchurch/mystyle.css Cookie sid=tgl9jq3f71nau3cj9vps6pna03; PHPSESSID=m0jvven6d7l65pl6odm9ecfnt4 If-Modified-Since Wed, 30 Dec 2009 02:40:58 GMT If-None-Match "1000000013d35-40d9-47be9117f6280" Cache-Control max-age=0 why would it send the If-Modified-Since header

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  • HTML relative links on various domains

    - by Adam Kiss
    I have quickie: When you code/develop themes, how do you link to various files in your html/css code? Example: We at our firm use mostly <base target="http://whatever"> in our main template and then just <img src="./images/file.png"> in our html, "/category/page" as links and something alike in our css. However, when testing on different machines, we use ip address rather than localhost on main dev station of coder, so all base links don't work (because localhost goes to viewing machine, not coder's, in our network). Same thing happens when updating pages - on dev server, we have to edit base target, so browsing site won't take us to live site - this part is actually rather simple PHP (if ... echo else echo something else), but it still not solve problem of more coding-testing problems. So, my question is, how do YOU solve it? How do you use relative links, which basically don't care for what domain is the page on and don't care for url rewrite? (because ../images/ is different for / and different for /something/somethingElse/page)?

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  • Codeigniter return config file as array with autoload enabled

    - by Fverswijver
    So I'm using CodeIgniter to build a website and I've made it so that all my specific settings are stored in a config file that's automatically loaded. I've also built a page that loads the settings file, makes a nice little table and allows me to edit everything from that page, afterwards it saves the entire page again (I know I could've done the same with a database but I want to try it this way). My problem is that I can't seem to use this bit when autoloading of my config file is enabled, but when I disable autoloading I can't seem to manually load it, it never finds my variables. So what I'm doing here is just taking all values from the config file and putting them in a single array so I can pass this array onto my settings administration page (edit/show all settings). $this->config->load('site_settings', TRUE); $data['settings'] = $this->config->item('site_settings'); ... $this->load->view('template', $data); config/site_settings.php <?php if ( ! defined('BASEPATH')) exit('No direct script access allowed'); $config['header_img'] = './img/header/'; $config['copyright_text'] = 'Copyright Instituto Kabu'; $config['copyright_font'] = './system/fonts/motoroil.ttf'; $config['copyright_font_color'] = 'ffffff'; $config['copyright_font_size'] = '32';

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  • Posting a form using Ajax

    - by hopes
    Hi everyone, do u have an idea of how to send my radio button name for myAjaxPostrequest.send(parameters); can parameters be like this: var answername=document.getElementById('option1').name; var parameters=answername; ? this code is for using ajax to post a form and my php page needs the name of the radiobutton clicked I tried this code and it works as I want except for inserting in the database. It means parameters is the problem what I want to insert is the number located between brakects of the radiobutton name. I could do it when I post form without Ajax but now I can't send the name of the radiobutton any clue about what I can send as parameter for function myAjaxPostrequest.send(parameters);? <form id="Question1" method="post"> <br /> <P> The sky color is.. </P><img border="0" src="images/wonder.png" width="94" height="134"/><br /><br /><br /> <input type="radio" id="option1" name="answer[1]" value="correct!" onclick="submitFormWithAjax();"/> blue <br /> <input type="radio" id="option1" name="answer[1]" value="false!" onclick="submitFormWithAjax();"/> red <br /> <input type="radio" id="option1" name="answer[1]" value="false!" onclick="submitFormWithAjax();"/> green <br /> <input type="radio" id="option1" name="answer[1]" value="false!" onclick="submitFormWithAjax();"/> white <br /> <br /> </Form>

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  • Determine an elements position in a variable length grid of elements

    - by gaoshan88
    I have a grid of a variable number of elements. Say 5 images per row and a variable number of images. I need to determine which column (for lack of a better word) each image is in... i.e. 1, 2, 3, 4 or 5. In this grid, images 1, 6, 12 and 17 would be in column 1 while 4, 9 and 15 would be in column 4. 1 2 3 4 5 6 7 8 9 10 12 13 14 15 16 17 18 19 What I am trying to do is apply a background image to each element based on it's column position. An example of this hard coded and inflexible (and if I'm barking up the wrong tree here by all means tell me how you'd ideally accomplish this as it always bugs me when I see someone ask "How do I build a gold plated, solar powered jet pack to get to the top of this building?" when they really should be asking "Where's the elevator?"): switch (imgnum){ case "1" : case "6" : case "11" : value = "1"; break; case "2" : case "7" : case "12" : value = "2"; break; case "3" : case "8" : case "13" : value = "3"; break; case "4" : case "9" : case "14" : value = "4"; break; case "5" : case "10" : case "15" : value = "5"; break; default : value = ""; } $('.someclass > ul').css('background','url("/img/'+value+'.png") no-repeat');

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  • Syntax Error? When parsing XML value

    - by Ace Munim
    I don't know if I'm having a syntax error but the compiler is giving me TypeError: 'undefined' is not an object (evaluating 'xmlDoc.getElementsByTagName("icon")[i].childNodes') Its me giving me this problem when im parsing the XML from my server, my actual javascript code is like this var xmlDoc = Obj.responseXML; var count = 0; if(xmlDoc){ while(count <= xmlDoc.getElementsByTagName("item").length){ document.getElementById("flow").innerHTML += "<div class='item'><img class='content' src='" + xmlDoc.getElementsByTagName("icon")[i].childNodes[0].nodeValue.replace(/\s+$/g,' ') +"' /></div>"; count++; } }else{ alert("Unable to parse!"); } and my XML goes like this. <feed> <item> <title>Given Title</title> <icon> http://i178.photobucket.com/albums/w255/ace003_album/Logo-ETC-RGB-e1353503652739.jpg </icon> </item> <item>...</item> <item>...</item> <item>...</item> <item>...</item> <item>...</item> <item>...</item> </feed> i just want to parse the image link and to show it.

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  • jQuery and AJAX?

    - by Moshe
    I'm making a simple form which has 5 input elements for parts of an address. I use jQuery to build and send an AJAX request to a PHP file on my server. For some reason my jQuery is not properly able to read the values from my input elements. What could be wrong? Here is my jQuery: $('#submitButton').click(function(){ $('#BBRequestBox').html('<img src="images/loading.gif" />'); alert('Info: ' + $('#name').val() + ' ' + $('#street').val() + ' ' + $('#city').val() + ' ' + $('#state').val() + ' ' + $('#zip').val() + ' '); $.ajax({ type: "POST", url: "./bbrequest.php", data: {name: $('#name').val(), street: $('#street').val(), city: $('#city').val(), state: $('#state').val(), zip: $('#zip').val() }, success: function(msg){ $('#BBRequestBox').html('<p>' + msg + '</p>'); }, error: function(XMLHttpRequest, textStatus, errorThrown){ $('#BBRequestBox').html('<p> There\'s been an error: ' + errorThrown + '</p>'); } }); return false; }); Here is my HTML: <form action="#"> <label>Name:</label><input type="text" id="name" class="textbox"/> <label>Street:</label><input type="text" id="street" class="textbox" /> <label>City:</label><input type="text" id="city"class="textbox" /> <label>State:</label><input type="text" id="state" class="textbox"/> <label>Zip:</label><input type="text" id="zip" class="textbox" /> <input type="submit" value="Send Me a Bitachon Builder!" id="submitButton" /> </form>

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  • Passing a variable from beggining to end - Paypal

    - by Phil Jackson
    Hi all, I'be been at this for days and i cant seem to figure it out. All i want to do is when subscribe button is pushed, a variable is send ( post get i dont care ) payment is completed and landed on the success page, with my variable! From what i can gather this should be able to do it: <form action="https://www.sandbox.paypal.com/cgi-bin/webscr" method="post"> <input type="hidden" name="cmd" value="_s-xclick"> <input type="hidden" name="hosted_button_id" value="0000000"> <Input type="hidden" name="custom" value="<?php md5($code.microtime()); ?>"/> <input type="image" src="https://www.sandbox.paypal.com/en_US/i/btn/btn_subscribeCC_LG.gif" border="0" name="submit" alt="PayPal - The safer, easier way to pay online!"> <img alt="" border="0" src="https://www.sandbox.paypal.com/en_US/i/scr/pixel.gif" width="1" height="1"> </form> Any help much appreciated ( and yes I've read paypal and sandbox documentation, just not that good at reading. )

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  • How do I use curl to display a table on a page?

    - by user272899
    I want to use curl to retrieve a table from an external page. So far my code retrieves all data from the page. I have read that using preg_match or preg_replace is the way to go about it. This is my code so far: <?php $ch = curl_init() or die(curl_error()); curl_setopt($ch, CURLOPT_URL,"http://www.megaupload.com/?d=XE30L1GA&w=631&h=392"); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); $data1=curl_exec($ch) or die(curl_error()); echo "<font color=black face=verdana size=3>".$data1."</font>"; echo curl_error($ch); curl_close($ch); ?> This is the data I want to retrieve from the page: <FORM method="POST" id="captchaform"> <INPUT type="hidden" name="captchacode" value="1a589e0a53c54f937eb8"> <INPUT type="hidden" name="megavar" value="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"> <TR> <TD>Enter this </TD> <TD width="100" align="center" height="40"><img src="http://wwwq32.megaupload.com/gencap.php?23243f17c2404dd4.gif" border="0" alt=""></TD> <TD> here:</TD> <TD><input type="text" name="captcha" id="captchafield" maxlength="4" style="border:solid 1px; border-color:#C4C4C4; background-color:#F9F9F9; width:50px; height:25px;"></TD> </TR> </FORM>

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  • Dynamically including multiple files within php for image descriptions

    - by Steve Jones
    Working on implementing image descriptions to a php run gallery and can't seem to figure out how to call each text file for each individual image. //total number of images $total = 77; //max number of thumbnails per page $max = 9; //what image do we want to start from? $startcount = $_GET["start"]; //if there is not a defined starting image, we start with the first if(empty($startcount)) { $startcount = 0; } //start off the loop at 1 $loop = 1; //start the loop while($loop <= $max) { //for the picture labels $num = $startcount + $loop; if($num > $total) { $num = $num - 1; break; } // Add class="last" to every third list item if(is_int($num / 3)) { $last = ' class="last"'; } else { $last = ""; } //the code for the image echo ' <li'.$last.'><a href="images/portfolio/pic-'.$num.'.jpg" rel="milkbox[gall1]"><img src="images/portfolio/thumbs/pic-'.$num.'-thumb.jpg" width="256" height="138" alt="Thumbnail of image '.$num.'" /></a><div>'.$num.'</div></li>'; I see that I can call the text files by number using '.$num.' (I have 77 individual text files with a phrase in each) but how do I tell it to call the files?

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  • php, image dosn't show

    - by lolalola
    Hi, whats wrong with my code. image dosn't show in test2.php file File: test2.php: <img src = "test.php" /> File: test.php session_start(); $md5_hash = md5(rand(0,999)); $security_code = substr($md5_hash, 15, 5); $_SESSION["security_code"] = $security_code; $width = 100; $height = 20; header("Content-type: image/png"); $image = ImageCreate($width, $height); $white = ImageColorAllocate($image, 255, 255, 255); $black = ImageColorAllocate($image, 0, 0, 0); $grey = ImageColorAllocate($image, 204, 204, 204); ImageFill($image, 0, 0, $black); //Add randomly generated string in white to the image ImageString($image, 3, 30, 3, $security_code, $white); //Throw in some lines to make it a little bit harder for any bots to break imageRectangle($image,0,0,$width-1,$height-1,$grey); imageline($image, 0, $height/2, $width, $height/2, $grey); imageline($image, $width/2, 0, $width/2, $height, $grey); imagepng($image); imagedestroy($image);

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  • Image generated with PHP dosn't show

    - by lolalola
    Hi, whats wrong with my code. image dosn't show in test2.php file File: test2.php: <img src = "test.php" /> File: test.php session_start(); $md5_hash = md5(rand(0,999)); $security_code = substr($md5_hash, 15, 5); $_SESSION["security_code"] = $security_code; $width = 100; $height = 20; header("Content-type: image/png"); $image = ImageCreate($width, $height); $white = ImageColorAllocate($image, 255, 255, 255); $black = ImageColorAllocate($image, 0, 0, 0); $grey = ImageColorAllocate($image, 204, 204, 204); ImageFill($image, 0, 0, $black); //Add randomly generated string in white to the image ImageString($image, 3, 30, 3, $security_code, $white); //Throw in some lines to make it a little bit harder for any bots to break imageRectangle($image,0,0,$width-1,$height-1,$grey); imageline($image, 0, $height/2, $width, $height/2, $grey); imageline($image, $width/2, 0, $width/2, $height, $grey); imagepng($image); imagedestroy($image);

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  • Facebook - generating fb tag in Jquery - not working

    - by Gublooo
    Hey guys Kind of stuck here - I have this functionality on my site where I display 10 user comments along with their photo and when a user clicks on "More" - using Jquery more results are fetched from DB and the results are displayed via string generated in the Jquery method. This is a shortened version of my Jquery function $(".more_swipes").live('click',function() { var profile_id = 'profile-user_id; ?'; $.getJSON("/profile/more-swipes", { user_id: profile_id},function(swipes) { $.each(swipes, function(i,data){ newcomment="<div"; newcomment +="<fb:profile-pic uid='"+data.fb_userid+"' linked='false'/"; newcomment +="Name="+data.user_name+"-Comment="+data.comment; $("#moreswipes").append(newcomment); }); }); return false; }); Here as you can see I'm using the tag <fb:profile-pic uid='"+data.fb_userid+"' linked='false'/ Now when more results get displayed, the profile pic of the user is not getting displayed - when I look at the source code - this is how the fb tag looks when its generated thru Jquery <fb:profile-pic uid="222222" linked="false" height="50" width="50" Whereas the FB tags not generated thru the Jquery code look like <fb:profile-pic uid="222222" linked="false" height="50" width="50" class="FB_profile_pic <fb_profile_pic_rendered FB_ElementReady" style="width:px;height:50px" <img src="http://profile.atk......2025.jpg" alt="User Name" title="User Name" style="width:px;height:50px" class="FB_profile_pic"/ </fb:profile-pic So when I add it as a String in JQuery function - facebook is not identifying it and executing it Any idea how to fix this Thanks a bunch

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  • How to proceed jpeg Image file size after read--rotate-write operations in Java?

    - by zamska
    Im trying to read a JPEG image as BufferedImage, rotate and save it as another jpeg image from file system. But there is a problem : after these operations I cannot proceed same file size. Here the code //read Image BufferedImage img = ImageIO.read(new File(path)); //rotate Image BufferedImage rotatedImage = new BufferedImage(image.getHeight(), image.getWidth(), BufferedImage.TYPE_3BYTE_BGR); Graphics2D g2d = (Graphics2D) rotatedImage.getGraphics(); g2d.rotate(Math.toRadians(PhotoConstants.ROTATE_LEFT)); int height=-rotatedImage.getHeight(null); g2d.drawImage(image, height, 0, null); g2d.dispose(); //Write Image Iterator iter = ImageIO.getImageWritersByFormatName("jpeg"); ImageWriter writer = (ImageWriter)iter.next(); // instantiate an ImageWriteParam object with default compression options ImageWriteParam iwp = writer.getDefaultWriteParam(); try { FileImageOutputStream output = null; iwp.setCompressionMode(ImageWriteParam.MODE_EXPLICIT); iwp.setCompressionQuality(0.98f); // an integer between 0 and 1 // 1 specifies minimum compression and maximum quality File file = new File(path); output = new FileImageOutputStream(file); writer.setOutput(output); IIOImage iioImage = new IIOImage(image, null, null); writer.write(null, iioImage, iwp); output.flush(); output.close(); writer.dispose(); Is it possible to access compressionQuality parameter of original jpeg image in the beginning. when I set 1 to compression quality, the image gets bigger size. Otherwise I set 0.9 or less the image gets smaller size. How can i proceed the image size after these operations? Thank you,

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  • Load more function in Javascript

    - by erastusnjuki
    EDIT: This question was initially too general, I think. So What I really need is a very good tutorial on how to implement the Load More function on Safari for iPhone just like the Twitter website(mobile.twitter.com) does. Just a wordpress plugin won't really help. But if the plugin is well explained, like if it is wptouch, home(that also has this function) that can also do. I know that it doesn't really matter that it is being displayed on a mobile device, but the point I am stressing is that if such a function is well explained, then it will be up to me to know how to customize it to suit me. I am using a javascript function to load entries that come from the database dynamically, so that content opens in the same page (like with twitter(tweets feed) and facebook(news feed)). The php/html version(That opens a page in a new tab) is echo '<a href="http://'. $_SERVER['HTTP_HOST'] .'/'.$domain_page.'?form='.$form_id.'&page='.($page+1).'">Load more entries&rsaquo; </a>'; The javascript/ajax version: <div id="call_hv<?php echo md5($_SERVER['REQUEST_URI']); ?>" class="ajax-load-more"> <img id="spinner<?php echo md5($_SERVER['REQUEST_URI']); ?>" class="spin" src="<?php bloginfo('template_directory'); ?>/images/main-ajax-loader.gif" style="display:none" alt="" /> <a class="ajax" href="javascript:$ajax_hv('#spinner<?php echo md5($_SERVER['REQUEST_URI']); ?>').fadeIn(200); $ajax_hv('#ajaxentries_hv<?php echo md5($_SERVER['REQUEST_URI']); ?>').load('form='<? echo $form_id; ?>&page=<?php echo $page+1;?>', {}, function(){ $ajax_hv('#call_hv<?php echo md5($_SERVER['REQUEST_URI']); ?>').fadeOut();})">Load more entries... </a>

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  • Image in table cell doesn't scale down: using ie8/7

    - by monks1975
    Can anyone help me troubleshoot my website? http://www.andrewstonyer.co.uk/test/ My problem: On IE8/7 if you click on a thumbnail (only 'Pulse' and 'Time Within The Hour' are wired in right now) an overlay appears with detail of that piece. What should happen, and does in Gecko/Webkit, is that the overlay contains a table with a heading, a scaled, centered image, and a nav menu. There is a toggle for text, which pushes up the image cell and makes the image smaller, keeping proportion. I know the overlay looks like ass right now- those are just placeholder colours :) On IE, the image doesn't fit perfectly in the table cell, which means that everything is pushed down outside the window. I can't see the nav menu. It appears to render the image at actual pixel size (in the CSS, the img class element is set to 100% height). The text cell is toggled with jquery, when toggled on in IE, it doesn't appear to 'squeeze' the above cell, which is what I want to happen. Could any experts help? Regards, Jon

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  • Dynamically writing out li with jquery. Element is not clickable after being written

    - by estern
    I have have a a function that when a checkbox is checked i dynamically write out an li into a ol that is empty. Code: $(":checkbox").click(function() { var checkedState = $(this).is(':checked'); if (checkedState == true) { var productName = $(this).attr("title"); $("#selectedProductsList").append("<li class=\"productList " + this + "\"><p class=\"removeIcon\"><img src=\"images/remove-icon.png\" alt=\"Remove Product\" /></p><span class=\"productName\">"+ productName +"</span></li>"); }; }); Then when that writes out there is a remove icon that will remove the item from the ol when clicked. This remove icon has a class of removeIcon which can be seen in the dynamic li above. I have a function that processes the remove call and then does some actions: Code: $('.removeIcon').click(function() { alert("starting"); }); Right now i have the remove action just trying to alert a message that it got called. But it seems that it is not getting into the function. Is there a certain way that i need to access these dynamic li's other then the .click method? I saw this post: Dynamically Inserted DOM Elements are not Clickable using $.click() Where they added .live vs .click but this doesn't seem to work either. Any ideas?

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  • AJAX: Permission denied to access property in iframe

    - by Muhammad Sajid
    Hi I created an php website which uses for AJAX post and was live at http://sprook.com.au/ but my client change it's domain to http://www.sprookit.net/ from his service provider Godaddy and now the firebug says: Permission denied to access property 'stopAjax' here stopAjax is my method name. script is there: <div class="post_area"> <form action="post.php" method="post" id="addVideo" enctype="multipart/form-data" target="post" onsubmit="return startAjax(this);"> <iframe id="post" name="post" src="#" style="width:0;height:0;border:0px solid #fff;"></iframe> <table width="860" border="0" cellspacing="0" cellpadding="0"> <tr> <td width="435">POST YOUR AD FREE<br /> <em>Paste embed code from YouTube</em></td> <td width="322"><input type="text" id="videoLink" name="videoLink" class="input_textbox" /> </td> <td width="95"><input type="submit" name="set_video_link" id="set_video_link" value="" class="submt_post" /> </td> </tr> <tr> <td>&nbsp;</td> <td><div id="process"> Connecting please wait <img src="images/loading.gif" /><br/> </div></td> </tr> </table> </form> </div> And all content comes from old domain i removed index file and it stoped working, therefore it is cleared that scripts run from old domain.

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