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  • How to insert and call by row and column into sqlite3 python

    - by user291071
    Lets say i have a simple array of x rows and y columns with corresponding values, What is the best method to do 3 things? How to insert, update a value at a specific row column? How to select a value for each row and column, import sqlite3 con = sqlite3.connect('simple.db') c = con.cursor() c.execute('''create table simple (links text)''') con.commit() dic = {'x1':{'y1':1.0,'y2':0.0},'x2':{'y1':0.0,'y2':2.0,'y3':1.5},'x3':{'y2':2.0,'y3':1.5}} ucols = {} ## my current thoughts are collect all row values and all column values from dic and populate table row and columns accordingly how to call by row and column i havn't figured out yet ##populate rows in first column for row in dic: print row c.execute("""insert into simple ('links') values ('%s')"""%row) con.commit() ##unique columns for row in dic: print row for col in dic[row]: print col ucols[col]=dic[row][col] ##populate columns for col in ucols: print col c.execute("alter table simple add column '%s' 'float'" % col) con.commit() #functions needed ##insert values into sql by row x and column y?how to do this e.g. x1 and y2 should put in 0.0 ##I tried as follows didn't work for row in dic: for col in dic[row]: val =dic[row][col] c.execute("""update simple SET '%s' = '%f' WHERE 'links'='%s'"""%(col,val,row)) con.commit() ##update value at a specific row x and column y? ## select a value at a specific row x and column y?

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  • VBA: How go I get the total width from all controls in an MS-Access form?

    - by Stefan Åstrand
    Hi, This is probably very basic stuff, but please bear in mind I am completely new to these things. I am working on a procedure for my Access datasheet forms that will: Adjust the width of each column to fit content Sum the total width of all columns and subtract it from the size of the window's width Adjust the width of one of the columns to fit the remaining space This is the code that adjusts the width of each column to fit content (which works fine): Dim Ctrl As Control Dim Path As String Dim ClmWidth As Integer 'Adjust column width to fit content For Each Ctrl In Me.Controls If TypeOf Ctrl Is TextBox Then Path = Ctrl.Name Me(Path).ColumnWidth = -2 End If Next Ctrl How should I write the code so I get the total width of all columns? Thanks a lot! Stefan Solution This is the code that makes an Access datasheet go from this: To this: Sub AdjustColumnWidth(frm As Form, clm As String) On Error GoTo HandleError Dim intWindowWidth As Integer ' Window width property Dim ctrl As Control ' Control Dim intCtrlWidth As Integer ' Control width property Dim intCtrlSum As Integer ' Control width property sum Dim intCtrlAdj As Integer ' Control width property remaining after substracted intCtrSum 'Adjust column width to standard width For Each ctrl In frm.Controls If TypeOf ctrl Is TextBox Or TypeOf ctrl Is CheckBox Or TypeOf ctrl Is ComboBox Then Path = ctrl.Name frm(Path).ColumnWidth = 1500 End If Next ctrl 'Get total column width For Each ctrl In frm.Controls If TypeOf ctrl Is TextBox Or TypeOf ctrl Is CheckBox Or TypeOf ctrl Is ComboBox Then Path = ctrl.Name intCtrlWidth = frm(Path).ColumnWidth If Path <> clm Then intCtrlSum = intCtrlSum + intCtrlWidth End If End If Next ctrl 'Adjust column to fit window intWindowWidth = frm.WindowWidth - 270 intCtrlAdj = intWindowWidth - intCtrlSum frm.Width = intWindowWidth frm(clm).ColumnWidth = intCtrlAdj Debug.Print "Totalt (Ctrl): " & intCtrlSum Debug.Print "Totalt (Window): " & intWindowWidth Debug.Print "Totalt (Remaining): " & intCtrlAdj Debug.Print "clm : " & clm HandleError: GeneralErrorHandler Err.Number, Err.Description Exit Sub End Sub Code to call procedure: Private Sub Form_Load() Call AdjustColumnWidth(Me, "txtDescription") End Sub

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  • Why wont this compile its killing me. (java)

    - by Ryan The Leach
    import java.util.*; public class Caesar { public static void main(String [] args) { final boolean DEBUG = false; System.out.println("Welcome to the Caesar Cypher"); System.out.println("----------------------------"); Scanner keyboard = new Scanner (System.in); System.out.print("Enter a String : "); String plainText = keyboard.nextLine(); System.out.print("Enter an offset: "); int offset = keyboard.nextInt(); String cipherText = ""; for(int i=0;i<plainText.length();i++) { int chVal = plainText.charAt(i); if (DEBUG) {int debugchVal = chVal;} chVal +=offset; if (DEBUG) {System.out.print(chVal + "\t");} while (chVal <32 || chVal > 127) { if (chVal < 32) chVal += 96; if (chVal > 127) chVal -= 96; if(DEBUG) {System.out.print(chVal+" ");} } if (DEBUG) {System.out.println();} char c = (char) chVal; cipherText = cipherText + c; if (DEBUG) {System.out.println(i + "\t" + debugchVal + "\t" + chVal + "\t" + c + "\t" + cipherText);} } System.out.println(cipherText); } }

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  • How to access a superclass's class attributes in Python?

    - by Brecht Machiels
    Have a look at the following code: class A(object): defaults = {'a': 1} def __getattr__(self, name): print('A.__getattr__') return self.get_default(name) @classmethod def get_default(cls, name): # some debug output print('A.get_default({}) - {}'.format(name, cls)) try: print(super(cls, cls).defaults) # as expected except AttributeError: #except for the base object class, of course pass # the actual function body try: return cls.defaults[name] except KeyError: return super(cls, cls).get_default(name) # infinite recursion #return cls.__mro__[1].get_default(name) # this works, though class B(A): defaults = {'b': 2} class C(B): defaults = {'c': 3} c = C() print('c.a =', c.a) I have a hierarchy of classes each with its own dictionary containing some default values. If an instance of a class doesn't have a particular attribute, a default value for it should be returned instead. If no default value for the attribute is contained in the current class's defaults dictionary, the superclass's defaults dictionary should be searched. I'm trying to implement this using the recursive class method get_default. The program gets stuck in an infinite recursion, unfortunately. My understanding of super() is obviously lacking. By accessing __mro__, I can get it to work properly though, but I'm not sure this is a proper solution. I have the feeling the answer is somewhere in this article, but I haven't been able to find it yet. Perhaps I need to resort to using a metaclass?

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  • Python __subclasses__() not listing subclasses

    - by Mridang Agarwalla
    I cant seem to list all derived classes using the __subclasses__() method. Here's my directory layout: import.py backends __init__.py --digger __init__.py base.py test.py --plugins plugina_plugin.py From import.py i'm calling test.py. test.py in turn iterates over all the files in the plugins directory and loads all of them. test.py looks like this: import os import sys import re sys.path.append(os.path.join(os.path.abspath(os.path.dirname(os.path.abspath( __file__ ))))) sys.path.append(os.path.join(os.path.abspath(os.path.dirname(os.path.abspath( __file__ ))), 'plugins')) from base import BasePlugin class TestImport: def __init__(self): print 'heeeeello' PLUGIN_DIRECTORY = os.path.join(os.path.abspath(os.path.dirname(os.path.abspath( __file__ ))), 'plugins') for filename in os.listdir (PLUGIN_DIRECTORY): # Ignore subfolders if os.path.isdir (os.path.join(PLUGIN_DIRECTORY, filename)): continue else: if re.match(r".*?_plugin\.py$", filename): print ('Initialising plugin : ' + filename) __import__(re.sub(r".py", r"", filename)) print ('Plugin system initialized') print BasePlugin.__subclasses__() The problem us that the __subclasses__() method doesn't show any derived classes. All plugins in the plugins directory derive from a base class in the base.py file. base.py looks like this: class BasePlugin(object): """ Base """ def __init__(self): pass plugina_plugin.py looks like this: from base import BasePlugin class PluginA(BasePlugin): """ Plugin A """ def __init__(self): pass Could anyone help me out with this? Whatm am i doing wrong? I've racked my brains over this but I cant seem to figure it out Thanks.

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  • Perl Module from relative path not working in IIS6

    - by Laramie
    Disclaimer: I am not a PERL developer and am learning by the seat of my pants. I am using a Perl module called from a CGI scipt in IIS 6 that is bombing. The identical folder structure on an XP machine (IIS 5.1) works fantastic. If I remove the module loading command at line 9, it will print "about to load" and "ok", but When I try to run use Language::Guess; I receive The specified CGI application misbehaved by not returning a complete set of HTTP headers. in the browser. The folder structure is /cgi-bin/test.pl /PerlModules/Language/Guess.pm I have tried adjusting the file/folder permissions and have reviewed my IIS configuration time and again. It runs fine from the command line on the IIS machine or if I copy the module into \Perl\site\lib, but I don't have permission to load modules on the shared server this script is destined for. Am I missing something simple? Here is test.pl use strict; use CGI ':standard'; print header("text/html"); use lib "..\\PerlModules\\"; print "about to load<br/>"; #bombs here use Language::Guess; print "ok"

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  • pylab.savefig() and pylab.show() image difference

    - by Jack1990
    I'm making an script to automatically create plots from .xvg files, but there's a problem when I'm trying to use pylab's savefig() method. Using pylab.show() and saving from there, everything's fine. Using pylab.show() Using pylab.savefig() def producePlot(timestep, energy_values,type_line = 'r', jump = 1,finish = 100): fc = sp.interp1d(timestep[::jump], energy_values[::jump],kind='cubic') xnew = numpy.linspace(0, finish, finish*2) pylab.plot(xnew, fc(xnew),type_line) pylab.xlabel('Time in ps ') pylab.ylabel('kJ/mol') pylab.xlim(xmin=0, xmax=finish) def produceSimplePlot(timestep, energy_values,type_line = 'r', jump = 1,finish = 100): pylab.plot(timestep, energy_values,type_line) pylab.xlabel('Time in ps ') pylab.ylabel('kJ/mol') pylab.xlim(xmin=0, xmax=finish) def linearRegression(timestep, energy_values, type_line = 'g'): #, jump = 1,finish = 100): from scipy import stats import numpy #print 'fuck' timestep = numpy.asarray(timestep) slope, intercept, r_value, p_value, std_err = stats.linregress(timestep,energy_values) line = slope*timestep+intercept pylab.plot(timestep, line, type_line) def plottingTime(Title,file_name, timestep, energy_values ,loc, jump , finish): pylab.title(Title) producePlot(timestep,energy_values, 'b',jump, finish) linearRegression(timestep,energy_values) import numpy Average = numpy.average(energy_values) #print Average pylab.legend(("Average = %.2f" %(Average),'Linear Reg'),loc) #pylab.show() pylab.savefig('%s.jpg' %file_name[:-4], bbox_inches= None, pad_inches=0) #if __name__ == '__main__': #plottingTime(Title,timestep1, energy_values, jump =10, finish = 4800) def specialCase(Title,file_name, timestep, energy_values,loc, jump, finish): #print 'Working here ...?' pylab.title(Title) producePlot(timestep,energy_values, 'b',jump, finish) import numpy from pylab import * Average = numpy.average(energy_values) #print Average pylab.legend(("Average = %.2g" %(Average), Title),loc) locs,labels = yticks() yticks(locs, map(lambda x: "%.3g" % x, locs)) #pylab.show() pylab.savefig('%s.jpg' %file_name[:-4] , bbox_inches= None, pad_inches=0) Thanks in advance, John

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  • Access 2007 DAO VBA Error 3381 causes objects in calling methods to "break".

    - by MT
    ---AFTER FURTHER INVESTIGATION--- "tblABC" in the below example must be a linked table (to another Access database). If "tblABC" is in the same database as the code then the problem does not occur. Hi, We have recently upgraded to Office 2007. We have a method in which we have an open recordset (DAO). We then call another sub (UpdatingSub below) that executes SQL. This method has its own error handler. If error 3381 is encountered then the recordset in the calling method becomes "unset" and we get error 3420 'Object invalid or no longer set'. Other errors in UpdatingSub do not cause the same problem. This code works fine in Access 2003. Private Sub Whatonearth() Dim rs As dao.Recordset set rs = CurrentDb.OpenRecordset("tblLinkedABC") Debug.Print rs.RecordCount UpdatingSub "ALTER TABLE tblTest DROP Column ColumnNotThere" 'Error 3240 occurs on the below line even though err 3381 is trapped in the calling procedure 'This appears to be because error 3381 is encountered when calling UpdatingSub above Debug.Print rs.RecordCount End Sub Private Sub WhatonearthThatWorks() Dim rs As dao.Recordset set rs = CurrentDb.OpenRecordset("tblLinkedABC") Debug.Print rs.RecordCount 'Change the update to generate a different error UpdatingSub "NONSENSE SQL STATEMENT" 'Error is trapped in UpdatingSub. Next line works fine. Debug.Print rs.RecordCount End Sub Private Sub UpdatingSub(strSQL As String) On Error GoTo ErrHandler: CurrentDb.Execute strSQL ErrHandler: 'LogError' End Sub Any thoughts? We are running Office Access 2007 (12.0.6211.1000) SP1 MSO (12.0.6425.1000). Perhaps see if SP2 can be distributed? Sorry about formatting - not sure how to fix that.

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  • Comparing dicts and update a list of result

    - by lmnt
    Hello, I have a list of dicts and I want to compare each dict in that list with a dict in a resulting list, add it to the result list if it's not there, and if it's there, update a counter associated with that dict. At first I wanted to use the solution described at http://stackoverflow.com/questions/1692388/python-list-of-dict-if-exists-increment-a-dict-value-if-not-append-a-new-dict but I got an error where one dict can not be used as a key to another dict. So the data structure I opted for is a list where each entry is a dict and an int: r = [[{'src': '', 'dst': '', 'cmd': ''}, 0]] The original dataset (that should be compared to the resulting dataset) is a list of dicts: d1 = {'src': '192.168.0.1', 'dst': '192.168.0.2', 'cmd': 'cmd1'} d2 = {'src': '192.168.0.1', 'dst': '192.168.0.2', 'cmd': 'cmd2'} d3 = {'src': '192.168.0.2', 'dst': '192.168.0.1', 'cmd': 'cmd1'} d4 = {'src': '192.168.0.1', 'dst': '192.168.0.2', 'cmd': 'cmd1'} o = [d1, d2, d3, d4] The result should be: r = [[{'src': '192.168.0.1', 'dst': '192.168.0.2', 'cmd': 'cmd1'}, 2], [{'src': '192.168.0.1', 'dst': '192.168.0.2', 'cmd': 'cmd2'}, 1], [{'src': '192.168.0.2', 'dst': '192.168.0.1', 'cmd': 'cmd1'}, 1]] What is the best way to accomplish this? I have a few code examples but none is really good and most is not working correctly. Thanks for any input on this! UPDATE The final code after Tamås comments is: from collections import namedtuple, defaultdict DataClass = namedtuple("DataClass", "src dst cmd") d1 = DataClass(src='192.168.0.1', dst='192.168.0.2', cmd='cmd1') d2 = DataClass(src='192.168.0.1', dst='192.168.0.2', cmd='cmd2') d3 = DataClass(src='192.168.0.2', dst='192.168.0.1', cmd='cmd1') d4 = DataClass(src='192.168.0.1', dst='192.168.0.2', cmd='cmd1') ds = d1, d2, d3, d4 r = defaultdict(int) for d in ds: r[d] += 1 print "list to compare" for d in ds: print d print "result after merge" for k, v in r.iteritems(): print("%s: %s" % (k, v))

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  • Why does my perl server stop working when i press 'enter'?

    - by David
    I have created a server in perl that sends messages or commands to the client. I can send commands just fine, but when i am being prompted for the command on my server i have created, if i press 'enter', the server messes up. Why is this happening? Here is part of my code: print "\nConnection recieved from IP address $peer_address on port $peer_port "; $closed_message = "\n\tTerminated client session..."; while (1) { print "\nCommand: "; $send_data = <STDIN>; chop($send_data); if ($send_data eq 'e' or $send_data eq 'E' or $send_data eq ' E' or $send_data eq ' E ' or $send_data eq 'E ' or $send_data eq ' e' or $send_data eq ' e ' or $send_data eq 'e') { $client_socket->send ($send_data); close $client_socket; print "$closed_message\n"; &options; } else { $client_socket->send($send_data); } $client_socket->recv($recieved_data,8000); print "\nRecieved: $recieved_data"; } }

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  • How can i get rid of 0xFEEFEE in VC

    - by egebilmuh
    Hi guys I m programming C for an assingment in VC++ 2008. I simulate adjList for graph implementation. i can readly add edge between two vertex and print the graph. and i want to remove edge between two vertex and print the graph again. whatever i do,i cant print the graph after deleting the edge. i get 0xfeefee :( what is this? and how can i resolve this program. my delete function and print the graph function are illustrated below. void deleteEdge(Graph G, Vertex V, Vertex W) { Edge list,prev,temp; list=V->list; prev=NULL; // while(list!=NULL && list->to->value!=W->value){ prev=list; list=list->next; } // have found the element. if(list!=NULL){ temp=list; // if first element of list is deleted. if(prev==NULL) list=list->next; else prev->next=list->next; // reallocate. free(temp); } } void GRAPHprint(Graph G) { Vertex tmp; Edge list; for(tmp = G->head;tmp!=NULL;tmp=tmp->next) { fprintf(stdout,"V:%d\t",tmp->value); list=tmp->list; while(list!=NULL) { fprintf(stdout,"%d\t",list->to->value); list=list->next; } fprintf(stdout, "\n"); } system("pause"); }

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  • Python subprocess: 64 bit windows server PIPE doesn't exist :(

    - by Spaceman1861
    I have a GUI that launches selected python scripts and runs it in cmd next to the gui window. I am able to get my launcher to work on my (windows xp 32 bit) laptop but when I upload it to the server(64bit windows iss7) I am running into some issues. The script runs, to my knowledge but spits back no information into the cmd window. My script is a bit of a Frankenstein that I have hacked and slashed together to get it to work I am fairly certain that this is a very bad example of the subprocess module. Just wondering if i could get a hand :). My question is how do i have to alter my code to work on a 64bit windows server. :) from Tkinter import * import pickle,subprocess,errno,time,sys,os PIPE = subprocess.PIPE if subprocess.mswindows: from win32file import ReadFile, WriteFile from win32pipe import PeekNamedPipe import msvcrt else: import select import fcntl def recv_some(p, t=.1, e=1, tr=5, stderr=0): if tr < 1: tr = 1 x = time.time()+t y = [] r = '' pr = p.recv if stderr: pr = p.recv_err while time.time() < x or r: r = pr() if r is None: if e: raise Exception(message) else: break elif r: y.append(r) else: time.sleep(max((x-time.time())/tr, 0)) return ''.join(y) def send_all(p, data): while len(data): sent = p.send(data) if sent is None: raise Exception(message) data = buffer(data, sent) The code above isn't mine def Run(): print filebox.get(0) location = filebox.get(0) location = location.__str__().replace(listbox.get(ANCHOR).__str__(),"") theTime = time.asctime(time.localtime(time.time())) lastbox.delete(0, END) lastbox.insert(END,theTime) for line in CookieCont: if listbox.get(ANCHOR) in line and len(line) > 4: line[4] = theTime else: "Fill In the rip Details to record the time" if __name__ == '__main__': if sys.platform == 'win32' or sys.platform == 'win64': shell, commands, tail = ('cmd', ('cd "'+location+'"',listbox.get(ANCHOR).__str__()), '\r\n') else: return "Please use contact admin" a = Popen(shell, stdin=PIPE, stdout=PIPE) print recv_some(a) for cmd in commands: send_all(a, cmd + tail) print recv_some(a) send_all(a, 'exit' + tail) print recv_some(a, e=0) The Code above is mine :)

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  • Apply a Quartz filter while saving PDF under Mac OS X 10.6.3

    - by olpa
    Using Mac OS X API, I'm trying to save a PDF file with a Quartz filter applied, just like it is possible from the "Save As" dialog in the Preview application. So far I've written the following code (using Python and pyObjC, but it isn't important for me): -- filter-pdf.py: begin from Foundation import * from Quartz import * import objc page_rect = CGRectMake (0, 0, 612, 792) fdict = NSDictionary.dictionaryWithContentsOfFile_("/System/Library/Filters/Blue \ Tone.qfilter") in_pdf = CGPDFDocumentCreateWithProvider(CGDataProviderCreateWithFilename ("test .pdf")) url = CFURLCreateWithFileSystemPath(None, "test_out.pdf", kCFURLPOSIXPathStyle, False) c = CGPDFContextCreateWithURL(url, page_rect, fdict) np = CGPDFDocumentGetNumberOfPages(in_pdf) for ip in range (1, np+1): page = CGPDFDocumentGetPage(in_pdf, ip) r = CGPDFPageGetBoxRect(page, kCGPDFMediaBox) CGContextBeginPage(c, r) CGContextDrawPDFPage(c, page) CGContextEndPage(c) -- filter-pdf.py: end Unfortunalte, the filter "Blue Tone" isn't applied, the output PDF looks exactly as the input PDF. Question: what I missed? How to apply a filter? Well, the documentation doesn't promise that such way of creating and using "fdict" should cause that the filter is applied. But I just rewritten (as far as I can) sample code /Developer/Examples/Quartz/Python/filter-pdf.py, which was distributed with older versions of Mac (meanwhile, this code doesn't work too): ----- filter-pdf-old.py: begin from CoreGraphics import * import sys, os, math, getopt, string def usage (): print ''' usage: python filter-pdf.py FILTER INPUT-PDF OUTPUT-PDF Apply a ColorSync Filter to a PDF document. ''' def main (): page_rect = CGRectMake (0, 0, 612, 792) try: opts,args = getopt.getopt (sys.argv[1:], '', []) except getopt.GetoptError: usage () sys.exit (1) if len (args) != 3: usage () sys.exit (1) filter = CGContextFilterCreateDictionary (args[0]) if not filter: print 'Unable to create context filter' sys.exit (1) pdf = CGPDFDocumentCreateWithProvider (CGDataProviderCreateWithFilename (args[1])) if not pdf: print 'Unable to open input file' sys.exit (1) c = CGPDFContextCreateWithFilename (args[2], page_rect, filter) if not c: print 'Unable to create output context' sys.exit (1) for p in range (1, pdf.getNumberOfPages () + 1): #r = pdf.getMediaBox (p) r = pdf.getPage(p).getBoxRect(p) c.beginPage (r) c.drawPDFDocument (r, pdf, p) c.endPage () c.finish () if __name__ == '__main__': main () ----- filter-pdf-old.py: end

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  • SQLite transaction doesn't work as expected

    - by troll
    I prepared 2 files, "1.php" and "2.php". "1.php" is like this. <?php $dbh = new PDO('sqlite:test1'); $dbh->beginTransaction(); print "aaa<br>"; sleep(55); $dbh->commit(); print "bbb"; ?> and "2.php" is like this. <?php $dbh = new PDO('sqlite:test1'); $dbh->beginTransaction(); print "ccc<br>"; $dbh->commit(); print "ddd"; ?> and I excute "1.php". It starts a transaction and waits 55 seconds. So when I immediately excute "2.php", my expectation is this: "1.php" is getting transaction and "1" holds a database lock "2" can not begin a transaction "2" can not get database lock so "2" have to wait 55 seconds BUT, but the test went another way. When I excute "2",then "2" immediately returned it's result "2" did not wait so I have to think that "1" could not get transaction, or could not get database lock. Can anyone help?

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  • strange chi-square result using scikit_learn with feature matrix

    - by user963386
    I am using scikit learn to calculate the basic chi-square statistics(sklearn.feature_selection.chi2(X, y)): def chi_square(feat,target): """ """ from sklearn.feature_selection import chi2 ch,pval = chi2(feat,target) return ch,pval chisq,p = chi_square(feat_mat,target_sc) print(chisq) print("**********************") print(p) I have 1500 samples,45 features,4 classes. The input is a feature matrix with 1500x45 and a target array with 1500 components. The feature matrix is not sparse. When I run the program and I print the arrray "chisq" with 45 components, I can see that the component 13 has a negative value and p = 1. How is it possible? Or what does it mean or what is the big mistake that I am doing? I am attaching the printouts of chisq and p: [ 9.17099260e-01 3.77439701e+00 5.35004211e+01 2.17843312e+03 4.27047184e+04 2.23204883e+01 6.49985540e-01 2.02132664e-01 1.57324454e-03 2.16322638e-01 1.85592258e+00 5.70455805e+00 1.34911126e-02 -1.71834753e+01 1.05112366e+00 3.07383691e-01 5.55694752e-02 7.52801686e-01 9.74807972e-01 9.30619466e-02 4.52669897e-02 1.08348058e-01 9.88146259e-03 2.26292358e-01 5.08579194e-02 4.46232554e-02 1.22740419e-02 6.84545170e-02 6.71339545e-03 1.33252061e-02 1.69296016e-02 3.81318236e-02 4.74945604e-02 1.59313146e-01 9.73037448e-03 9.95771327e-03 6.93777954e-02 3.87738690e-02 1.53693158e-01 9.24603716e-04 1.22473138e-01 2.73347277e-01 1.69060817e-02 1.10868365e-02 8.62029628e+00] ********************** [ 8.21299526e-01 2.86878266e-01 1.43400668e-11 0.00000000e+00 0.00000000e+00 5.59436980e-05 8.84899894e-01 9.77244281e-01 9.99983411e-01 9.74912223e-01 6.02841813e-01 1.26903019e-01 9.99584918e-01 1.00000000e+00 7.88884155e-01 9.58633878e-01 9.96573548e-01 8.60719653e-01 8.07347364e-01 9.92656816e-01 9.97473024e-01 9.90817144e-01 9.99739526e-01 9.73237195e-01 9.96995722e-01 9.97526259e-01 9.99639669e-01 9.95333185e-01 9.99853998e-01 9.99592531e-01 9.99417113e-01 9.98042114e-01 9.97286030e-01 9.83873717e-01 9.99745466e-01 9.99736512e-01 9.95239765e-01 9.97992843e-01 9.84693908e-01 9.99992525e-01 9.89010468e-01 9.64960636e-01 9.99418323e-01 9.99690553e-01 3.47893682e-02]

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  • how to implement a really efficient bitvector sorting in python

    - by xiao
    Hello guys! Actually this is an interesting topic from programming pearls, sorting 10 digits telephone numbers in a limited memory with an efficient algorithm. You can find the whole story here What I am interested in is just how fast the implementation could be in python. I have done a naive implementation with the module bitvector. The code is as following: from BitVector import BitVector import timeit import random import time import sys def sort(input_li): return sorted(input_li) def vec_sort(input_li): bv = BitVector( size = len(input_li) ) for i in input_li: bv[i] = 1 res_li = [] for i in range(len(bv)): if bv[i]: res_li.append(i) return res_li if __name__ == "__main__": test_data = range(int(sys.argv[1])) print 'test_data size is:', sys.argv[1] random.shuffle(test_data) start = time.time() sort(test_data) elapsed = (time.time() - start) print "sort function takes " + str(elapsed) start = time.time() vec_sort(test_data) elapsed = (time.time() - start) print "sort function takes " + str(elapsed) start = time.time() vec_sort(test_data) elapsed = (time.time() - start) print "vec_sort function takes " + str(elapsed) I have tested from array size 100 to 10,000,000 in my macbook(2GHz Intel Core 2 Duo 2GB SDRAM), the result is as following: test_data size is: 1000 sort function takes 0.000274896621704 vec_sort function takes 0.00383687019348 test_data size is: 10000 sort function takes 0.00380706787109 vec_sort function takes 0.0371489524841 test_data size is: 100000 sort function takes 0.0520560741425 vec_sort function takes 0.374383926392 test_data size is: 1000000 sort function takes 0.867373943329 vec_sort function takes 3.80475401878 test_data size is: 10000000 sort function takes 12.9204008579 vec_sort function takes 38.8053860664 What disappoints me is that even when the test_data size is 100,000,000, the sort function is still faster than vec_sort. Is there any way to accelerate the vec_sort function?

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  • Compiling Objective-C project on Linux (Ubuntu)

    - by Alex
    How to make an Objective-C project work on Ubuntu? My files are: Fraction.h #import <Foundation/NSObject.h> @interface Fraction: NSObject { int numerator; int denominator; } -(void) print; -(void) setNumerator: (int) n; -(void) setDenominator: (int) d; -(int) numerator; -(int) denominator; @end Fraction.m #import "Fraction.h" #import <stdio.h> @implementation Fraction -(void) print { printf( "%i/%i", numerator, denominator ); } -(void) setNumerator: (int) n { numerator = n; } -(void) setDenominator: (int) d { denominator = d; } -(int) denominator { return denominator; } -(int) numerator { return numerator; } @end main.m #import <stdio.h> #import "Fraction.h" int main( int argc, const char *argv[] ) { // create a new instance Fraction *frac = [[Fraction alloc] init]; // set the values [frac setNumerator: 1]; [frac setDenominator: 3]; // print it printf( "The fraction is: " ); [frac print]; printf( "\n" ); // free memory [frac release]; return 0; } I've tried two approaches to compile it: Pure gcc: $ sudo apt-get install gobjc gnustep gnustep-devel $ gcc `gnustep-config --objc-flags` -o main main.m -lobjc -lgnustep-base /tmp/ccIQKhfH.o:(.data.rel+0x0): undefined reference to `__objc_class_name_Fraction' I created a GNUmakefile Makefile: include ${GNUSTEP_MAKEFILES}/common.make TOOL_NAME = main main_OBJC_FILES = main.m include ${GNUSTEP_MAKEFILES}/tool.make ... and ran: $ source /usr/share/GNUstep/Makefiles/GNUstep.sh $ make Making all for tool main... Linking tool main ... ./obj/main.o:(.data.rel+0x0): undefined reference to `__objc_class_name_Fraction' So in both cases compiler gets stuck at undefined reference to `__objc_class_name_Fraction' Do you have and idea how to resolve this issue?

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  • French date format

    - by kwek-kwek
    I am a newbie in PHP & wordpress. I wanted to know how to make this codde renders the date formating in french (e.g. 5 Fev) when your on the french side but in english format in English (e.g. Jan 5) Here is my code: <?php if (strtolower(ICL_LANGUAGE_CODE) == 'en') {$sidePosts = get_posts('cat=3,4,5,19&posts_per_page=5&order=DESC&orderby=date');} if (strtolower(ICL_LANGUAGE_CODE) == 'fr') {$sidePosts = get_posts('cat=9,10,11,17&posts_per_page=5&order=DESC&orderby=date');} foreach($sidePosts as $sidePosts) { $array = (array) $sidePosts; print("<li>"); print("<span class='date'>".get_the_time('M j', $array[ID])."</span>"); print("<a href='".get_permalink($array[ID])."' title='".$array[post_title]."'>".$array[post_title]."</a>"); print("</li>"); } ?>

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  • Have no idea with python-excel read data file

    - by Protoss Reed
    I am a student and haven't a big expirence to do this work. So problem is next. I have a part of code: import matplotlib.pyplot as plt from pylab import * import cmath def sf(prompt): """ """ error_message = "Value must be integer and greater or equal than zero" while True: val = raw_input(prompt) try: val = float(val) except ValueError: print(error_message) continue if val <= 0: print(error_message) continue return val def petrogen_elements(): """Input and calculations the main parameters for pertogen elements""" print "Please enter Petrogen elements: \r" SiO2 = sf("SiO2: ") Al2O3= sf("Al2O3: ") Na2O = sf("Na2O: ") K2O = sf("K2O: ") petro = [SiO2,TiO2,Al2O3,] Sum = sum(petro) Alcal = Na2O + K2O TypeA lcal= Na2O / K2O Ka= (Na2O + K2O)/ Al2O3 print '-'*20, "\r Alcal: %s \r TypeAlcal: %s \ \r Ka: %s \r" % (Alcal, TypeAlcal,Ka,) petrogen_elements() So the problem is next. I have to load and read excel file and read all data in it. After that program have to calculate for example Alcaline, Type of Alcaline etc. Excel file has only this structure 1 2 3 4 5   1 name1 SiO2 Al2O3 Na2O K2O 2 32 12 0.21 0.1 3 name2 SiO2 Al2O3 Na2O K2O 4 45 8 7.54 5 5 name3 SiO2 Al2O3 Na2O K2O 6. … …. …. … … … All excel file has only 5 columns and unlimited rows. User has choice input data or import excel file. First part of work I have done but it stays a big part Finally I need to read all file and calculate the values. I would be so grateful for some advice

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  • Perl's use encoding pragma breaking UTF strings

    - by Karel Bílek
    I have a problem with Perl and Encoding pragma. (I use utf-8 everywhere, in input, output, the perl scripts themselves. I don't want to use other encoding, never ever.) However. When I write binmode(STDOUT, ':utf8'); use utf8; $r = "\x{ed}"; print $r; I see the string "í" (which is what I want - and what is 00+ED unicode char). But when I add the "use encoding" pragma like this binmode(STDOUT, ':utf8'); use utf8; use encoding 'utf8'; $r = "\x{ed}"; print $r; all I see is a box character. Why? Moreover, when I add Data::Dumper and let the Dumper print the new string like this binmode(STDOUT, ':utf8'); use utf8; use encoding 'utf8'; $r = "\x{ed}"; use Data::Dumper; print Dumper($r); I see that perl changed the string to "\x{fffd}". Why?

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  • PyParsing: Not all tokens passed to setParseAction()

    - by Rosarch
    I'm parsing sentences like "CS 2110 or INFO 3300". I would like to output a format like: [[("CS" 2110)], [("INFO", 3300)]] To do this, I thought I could use setParseAction(). However, the print statements in statementParse() suggest that only the last tokens are actually passed: >>> statement.parseString("CS 2110 or INFO 3300") Match [{Suppress:("or") Re:('[A-Z]{2,}') Re:('[0-9]{4}')}] at loc 7(1,8) string CS 2110 or INFO 3300 loc: 7 tokens: ['INFO', 3300] Matched [{Suppress:("or") Re:('[A-Z]{2,}') Re:('[0-9]{4}')}] -> ['INFO', 3300] (['CS', 2110, 'INFO', 3300], {'Course': [(2110, 1), (3300, 3)], 'DeptCode': [('CS', 0), ('INFO', 2)]}) I expected all the tokens to be passed, but it's only ['INFO', 3300]. Am I doing something wrong? Or is there another way that I can produce the desired output? Here is the pyparsing code: from pyparsing import * def statementParse(str, location, tokens): print "string %s" % str print "loc: %s " % location print "tokens: %s" % tokens DEPT_CODE = Regex(r'[A-Z]{2,}').setResultsName("DeptCode") COURSE_NUMBER = Regex(r'[0-9]{4}').setResultsName("CourseNumber") OR_CONJ = Suppress("or") COURSE_NUMBER.setParseAction(lambda s, l, toks : int(toks[0])) course = DEPT_CODE + COURSE_NUMBER.setResultsName("Course") statement = course + Optional(OR_CONJ + course).setParseAction(statementParse).setDebug()

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  • Getting a UDP socket program in Python to accept messages from a Syslog client?

    - by Elvar
    I'm trying to write a Syslog listener and so far so good on getting it to accept incoming messages through TCP but I also want UDP to function. This is the UDP server code I'm using, which works using a python client app. I also have another app which also works just using the python client app. # Server program # UDP VERSION from socket import * # Set the socket parameters host = "localhost" port = 514 buf = 1024 addr = (host,port) # Create socket and bind to address UDPSock = socket(AF_INET,SOCK_DGRAM) UDPSock.bind(addr) # Receive messages while 1: data,addr = UDPSock.recvfrom(buf) if not data: print "Client has exited!" break else: print "\nReceived message '", data,"'" # Close socket UDPSock.close() Using this code I can send to the server and have it display the code. # Client program from socket import * # Set the socket parameters host = "localhost" port = 514 buf = 1024 addr = (host,port) # Create socket UDPSock = socket(AF_INET,SOCK_DGRAM) def_msg = "===Enter message to send to server==="; print "\n",def_msg # Send messages while (1): data = raw_input('>> ') if not data: break else: if(UDPSock.sendto(data,addr)): print "Sending message '",data,"'....." # Close socket UDPSock.close() I have tried the Kiwi Syslog Message Generator and Snare to send syslog messages to the UDP server and nothing comes up. Could someone help me understand?

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  • [PERL Tk] printing Line number in Text widget

    - by ungalnanban
    I use the following code for printing the line number in Text widget. my $c=0; my $r=0; $txt = $mw-Text( -background ='white', -width=>400, -height=>300, -selectbackground => 'skyblue', -insertwidth => 5, -borderwidth =>3, -highlightcolor => 'blue', ### after visit -highlightbackground => 'red' , ### default before visit -xscrollcommand => sub { print"CHAT NO :",$c++; }, # Determines the callback used when the Text widget is scrolled horizontally. -yscrollcommand = sub { print"LINR NO:",$r++; }, # Determines the callback used when the Text widget is scrolled vertically. -padx = 5, -pady = 5, )- pack (); the above code is printing the line number and character no is ok. but I used in Scrolled widget that output is not printing. what is the problem in the following code how can I solve this? $txt = $mw-Scrolled('Text', -scrollbars = 'se', -background ='white', -width=>400, -height=>300, -insertwidth => 5, -borderwidth =>3, -highlightcolor => 'blue', ### after visit -highlightbackground => 'red' , ### default before visit -padx => 5, -pady => 5, -xscrollcommand => sub { print"CHAT NO :",$c++; }, # Determines the callback used when the Text widget is scrolled horizontally. -yscrollcommand => sub { print"LINR NO :",$r++; }, # Determines the callback used when the Text widget is scrolled vertically. )->pack();

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  • Printing to different printers using mozilla.

    - by Nick-ACNB
    I am currently creating a web application that will be deployed in an intranet environment. I chose firefox to be the browser that will run it. However, in the application I am building, I need to be able to print to different printers quickly since they use different paper size depending on what client is coming. To avoid many time-wasting mistakes that could occur, for instance someone choosing the wrong printer and wasting paper. Also, the time used to find the right printer for the job and then pressing print is considered too long in the current context. Is there any solution to this problem? I understand the potential security flaw behind this, but please be aware that this is solely an intranet project and that I can reduce the browser's security to the lowest since they don't access internet. I know there could be something doable behind IE (ActiveX or VBScript) but I am using firefox. Also, I guess there could also be something rather tricky that when you press print on the browser, it saves what needs to be printed to a DB and then there is an exe app that runs and fetch that DB every set ammount of time and print to the right printer. Any suggestion would be greatly appreciated. I doubt I am the only one to ever face this issue! :) Thank you very much.

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  • Give a reference to a python instance attribute at class definition

    - by Guenther Jehle
    I have a class with attributes which have a reference to another attribute of this class. See class Device, value1 and value2 holding a reference to interface: class Interface(object): def __init__(self): self.port=None class Value(object): def __init__(self, interface, name): self.interface=interface self.name=name def get(self): return "Getting Value \"%s\" with interface \"%s\""%(self.name, self.interface.port) class Device(object): interface=Interface() value1=Value(interface, name="value1") value2=Value(interface, name="value2") def __init__(self, port): self.interface.port=port if __name__=="__main__": d1=Device("Foo") print d1.value1.get() # >>> Getting Value "value1" with interface "Foo" d2=Device("Bar") print d2.value1.get() # >>> Getting Value "value1" with interface "Bar" print d1.value1.get() # >>> Getting Value "value1" with interface "Bar" The last print is wrong, cause d1 should have the interface "Foo". I know whats going wrong: The line interface=Interface() line is executed, when the class definition is parsed (once). So every Device class has the same instance of interface. I could change the Device class to: class Device(object): interface=Interface() value1=Value(interface, name="value1") value2=Value(interface, name="value2") def __init__(self, port): self.interface=Interface() self.interface.port=port So this is also not working: The values still have the reference to the original interface instance and the self.interface is just another instance... The output now is: >>> Getting Value "value1" with interface "None" >>> Getting Value "value1" with interface "None" >>> Getting Value "value1" with interface "None" So how could I solve this the pythonic way? I could setup a function in the Device class to look for attributes with type Value and reassign them the new interface. Isn't this a common problem with a typical solution for it? Thanks!

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