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  • How to modify the style of jQuery DatePicker's disabled dates?

    - by Clay
    Given this page: http://jqueryui.com/demos/datepicker/#min-max And viewing its source: http://jqueryui.com/themeroller/css/parseTheme.css.php I can change the following line (using Chrome's inspect element feature) and see those changes reflected: .ui-state-disabled, .ui-widget-content .ui-state-disabled { opacity: .35; filter:Alpha(Opacity=35); background-image: none; } However, if I try to override my own test page with something like... .ui-state-disabled, .ui-widget-content .ui-state-disabled { opacity: .99 !important; filter:Alpha(Opacity=99) !important; background-image: none !important; color:Red !important; } ...I do not see my changes reflected in the calendar. I can make other changes in my own test page and those are reflected for other classes in the datepicker. So, I'm not having any kind of path issue to the .js or .css files. What am I missing here? UPDATE/SOLUTION Firebug to the rescue...this took care of my styling needs: .ui-datepicker-week-end{color: #c0c0c0 !important;} div#ui-datepicker-div.ui-datepicker{color: #c0c0c0;} div#ui-datepicker-div.ui-datepicker:hover{cursor: default important;} .ui-datepicker-calendar th{color: #222222 !important;}

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  • Workaround for basic syntax not being parsed.

    - by Mark Tomlin
    I want to have a class property that allow for an expression to take place on the right side of the equals sign. All versions of PHP choke on the following code, but it is written in this way to allow for easier extendibility in the future. /* Example SDK Class */ class SDK { /* Runtime Option Flags */ // Strings # 0: Makes no change to the strings. var $STRING_NONE = (1 << 0); # 1: Removes color codes from the string. var $STRING_STRIP_COLOR = (1 << 1); # 2: Removes language codes from the string. var $STRING_STRIP_LANG = (1 << 2); # 3: Removes all formatting from the string. var $STRING_STRIP = SELF::STRING_STRIP_COLOR & SELF::STRING_STRIP_LANG; # 4: Converts color codes to HTML & UTF-8. var $STRING_HTML = (1 << 3); # 8: Converts color codes to ECMA-48 escape color codes & UTF-8. var $STRING_CONSOLE = (1 << 4); # 16: Changes player names only. var $STRING_NAMES = (1 << 5); # 32: Changes host names only. var $STRING_HOSTS = (1 << 6); function SDK($fString = SELF::STRING_HTML & SELF::STRING_NAMES & SELF_HOST) { // constructor code. } } $SDK &= new SDK(SDK::STRING_NONE); (1 << 0) seems like very basic syntax to me, and is not fathomable why PHP would not allow for such a thing. Can anyone think of a work around that would maintain readability and future expandability of the following code?

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  • Javascript: prototypeal inheritance and the prototype proprity

    - by JanD
    Hi, I have a simple code fragment in JS working with prototype inheritance. function object(o) { function F() {} F.prototype = o; return new F(); } //the following code block has a alternate version var mammal={ color: "brown", getColor: function(){ return this.color; } } var myCat = object(mammal); myCat.meow = function(){return "meow";} that worked fine but adding this: mammal.prototype.kindOf = "predator"; does not. ("mammal.prototype is undefined") Since I guessed that object maybe have no prototype I rewrote it, replacing the var mammal={... block with: function mammal(){ this.color="brown"; this.getColor = function(){return this.color;} } which gave me a bunch of other errors: "Function.prototype.toString called on incompatible object" and if I try to call _myCat.getColor() "myCat.getColor is not a function" Now I am totally confused. After reading Crockford, and Flanagan I did not get the solution for the errors. So it would be great if somebody knows... - why is the prototype undefined in the first example (which is foremost concern; I thought the prototype of explicitly set in the object() function) - why get I these strange errors trying to use the mammal function as prototype object in the object() function?

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  • silverlight styles

    - by Piyush
    <navigation:Page.Resources> <Style x:Key="PageBackground" TargetType="Grid"> <Setter Property="Background"> <Setter.Value> <LinearGradientBrush StartPoint="0,0.5" EndPoint="1,0.5"> <GradientStop Color="White" Offset="1"/> <GradientStop Color="Silver"/> </LinearGradientBrush> <Path x:Name="shinePath" Data="M0,0 L0,300 C-5.5,306.5 40,68 215,0 z" Stretch="Fill" Opacity="0.1"> <Path.Fill> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0" SpreadMethod="Pad"> <GradientStop Color="Black" Offset="0"/> <GradientStop Color="#00FFFFFF" Offset="0.871"/> </LinearGradientBrush> </Path.Fill> </Path> </Setter.Value> </Setter> </Style> </navigation:Page.Resources> error- property 'Value' is set more then once

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  • Javascript: prototypal inheritance and the prototype property

    - by JanD
    Hi, I have a simple code fragment in JS working with prototype inheritance. function object(o) { function F() {} F.prototype = o; return new F(); } //the following code block has a alternate version var mammal = { color: "brown", getColor: function() { return this.color; } } var myCat = object(mammal); myCat.meow = function(){return "meow";} that worked fine but adding this: mammal.prototype.kindOf = "predator"; does not. ("mammal.prototype is undefined") Since I guessed that object maybe have no prototype I rewrote it, replacing the var mammal={... block with: function mammal() { this.color = "brown"; this.getColor = function() { return this.color; } } which gave me a bunch of other errors: "Function.prototype.toString called on incompatible object" and if I try to call _myCat.getColor() "myCat.getColor is not a function" Now I am totally confused. After reading Crockford, and Flanagan I did not get the solution for the errors. So it would be great if somebody knows... - why is the prototype undefined in the first example (which is foremost concern; I thought the prototype of explicitly set in the object() function) - why get I these strange errors trying to use the mammal function as prototype object in the object() function? Edit by the Creator of the Question: These two links helped a lot too: Prototypes_in_JavaScript on the spheredev wiki explains the way the prototype property works relativily simple. What it lacks is some try-out code examples. Some good examples are provided by Morris John's Article. I personally find the explanations are not that easy as in the first link, but still very good. The most difficult part even after I actually got it is really not to confuse the .prototype propery with the internal [[Prototype]] of an object.

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  • jQuery plugin Tablesorter 2.0 behaves weird

    - by gunther-von-goetzen-sanchez
    I downloaded the jQuery plugin Tablesorter 2.0 from http://tablesorter.com/jquery.tablesorter.zip and modified the example-pager.html which is in tablesorter/docs directory I wrote additional Rollover effects: $(function() { $("table") .tablesorter({widthFixed: true, widgets: ['zebra']}) .tablesorterPager({container: $("#pager")}); /** Additional code */ $("tr").mouseover(function () { $(this).addClass('over'); }); $("tr").mouseout(function () { $(this).removeClass('over'); }); $("tr").click(function () { $(this).addClass('marked'); }); $("tr").dblclick(function () { $(this).removeClass('marked'); }); /** Additional code END */ }); And of course modified the themes/blue/style.css file: /* Additional code */ table.tablesorter tbody tr.odd td { background-color: #D1D1F0; } table.tablesorter tbody tr.even td { background-color: #EFDEDE; } table.tablesorter tbody tr.over td { background-color: #FBCA33; } table.tablesorter tbody tr.marked td { background-color: #FB4133; } /* Additional code END*/ All this works fine BUT when I go to further pages i.e. page 2 3 or 4 the effects are gone! I really appreciate your help

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  • .NET RichTextBox: unable to change Rtf property.

    - by Dave
    Hey guys, Perhaps I'm missing something real simple here, but I've been struggling to change the RTF property of my RichTextBox in order to apply some color coding to my text. Probably the most straight-forward example of the problem I'm having is setting the Rtf property to include a color table in its header. The default RTF string returned by the Rtf property: {\rtf1\ansi\ansicpg1252\deff0\deflang1033{\fonttbl{\f0\fnil\fcharset0 Microsoft Sans Serif;}}\viewkind4\uc1\pard\f0\fs17\par} And the new RTF string I'd like to set with my color table: {\rtf1\ansi\ansicpg1252\deff0\deflang1033{\fonttbl{\f0\fnil\fcharset0 Microsoft Sans Serif;}{\colortbl;\red128\green0\blue0;\red0\green128\blue0;\red0\green0\blue255;}}\viewkind4\uc1\pard\f0\fs17\par} And I set this using: RichTextBox richTextBox = new RichTextBox(); richTextBox.Rtf = rtfStr; // My new RTF string, as seen above. However, via debugger, it can be observed the that Rtf property stubbornly refuses to change; no exceptions are thrown, it just refuses to change. Same issue happens when I string.Replace() words to include RTF color tags around them. I've also tried turning off any ReadOnly properties on the text box. Any suggestions would be most helpful, thanks! Dave

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  • Silverlight: Binding a child controls property to a property in a user control

    - by Jeremy
    If I have a user control defined: public partial class MainFooter : UserControl { public System.Windows.Media.Color BkColor; } and it's xaml: <UserControl x:Class="Test.MainFooter"> <Grid x:Name="LayoutRoot"> <Rectangle x:Name="rctBottom_Background2" HorizontalAlignment="Stretch" Grid.Row="2"> <Rectangle.Fill> <LinearGradientBrush EndPoint="0.82,0.895" StartPoint="0.911,-0.442"> <GradientStop Color="{**How can I bind this to the BkColor property?}"/**> <GradientStop Color="#00FFFFFF" Offset="1"/> </LinearGradientBrush> </Rectangle.Fill> </Rectangle> </Grid> </UserControl> and used: <MyControls:MainFooter x:Name="rcrMainFooter" BkColor="#FFE2B42A"> </MyControls:MainFooter> How would I go about binding the GradientStop Color in the Rectangle to the value of the it's user controls BkColor property?

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  • CSS buttons and crossbrowser issue

    - by Jason
    I have a class 'button' that I want to use for button, input and a tags. The problem is that both button and input tags have a greater line height than the anchor tag does. I have attached an example here so you can play around with it in firebug or whatever. http://28dev.com/stackoverflow/css-buttons.html But for those who just want to see the css/html, here it is: .button { font-family : helvetica, arial, sans-serif; -moz-border-radius: 3px; -webkit-border-radius: 3px; background : url(/images/ui-bg_glass_75_e6e6e6_1x400.png) repeat-x scroll 50% 50% #E6E6E6; border-color : #636363 #888888 #888888 #636363; border-right : 1px solid #888888; border-style : solid; border-width : 1px; cursor : pointer; display : block; float : left; font-size : 12px; font-weight : normal; line-height : 100%; min-width : 100px; padding : 3px 12px; text-align : center; } .button, .button a { color : #282828; text-decoration : none; } .button:hover, .button:hover a { border-color : #343434; color : #080808; } .marginR { margin-right : 5px; } <button class='button marginR' type='submit'>button.button</button> <input type="submit" value="input.button" class="button marginR" /> <a class="button" href="">a.button</a>

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  • Problems with jQuery plugin Tablesorter 2.0

    - by gunther-von-goetzen-sanchez
    I downloaded the jQuery plugin Tablesorter 2.0 from http://tablesorter.com/jquery.tablesorter.zip and modified the example-pager.html which is in tablesorter/docs directory I wrote additional Rollover effects: $(function() { $("table") .tablesorter({widthFixed: true, widgets: ['zebra']}) .tablesorterPager({container: $("#pager")}); $("tr").mouseover(function () { $(this).addClass('over'); }); $("tr").mouseout(function () { $(this).removeClass('over'); }); $("tr").click(function () { $(this).addClass('marked'); }); $("tr").dblclick(function () { $(this).removeClass('marked'); }); }); And of course modified the themes/blue/style.css file: /* Additional code */ table.tablesorter tbody tr.odd td { background-color: #D1D1F0; } table.tablesorter tbody tr.even td { background-color: #EFDEDE; } table.tablesorter tbody tr.over td { background-color: #FBCA33; } table.tablesorter tbody tr.marked td { background-color: #FB4133; } /* Additional code END*/ All this works fine BUT when I go to further pages i.e. page 2 3 or 4 the effects are gone! I really appreciate your help

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  • Following code overflows my browser window

    - by oneat
    Why following HTML (CSS) code: <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> <title></title> </head> <body> <style type="text/css"> *{margin:0px 0px 0px 0px; padding:0px 0px 0px 0px;} div#header{width:100%;height:10%;min-width:100px;height:30%;background-color:red;} div#left_bar{width:20%;height:85%;float:left;background-color:green;} div#content{width:80%;height:85%;float:left;background-color:yellow;} div#foot{width:100%;height:5%;clear:both;background-color:black;} </style> <div id="header">a</div> <div id="left_bar">s</div> <div id="content">d</div> <div id="foot">f</div> </body> </html> Fails to fill my browser's (firefox 3.6.13 linux) window? I mean that I have to scroll down to see bottom. Any ideas?

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  • Why is graphviz drawing two arrows, and using a weird order?

    - by dmd
    Why is graphviz drawing two arrows from uncap_spike to peel, and why is it drawing peel to the right of hang? I want uncap_spike - peel - hang - spike, in that order, with one edge between each. digraph hangers { compound=true fontname="Gill Sans" node [fontname="Gill Sans" shape=box fillcolor=white style="rounded, filled"] edge [fontname="Gill Sans"] subgraph cluster_prep { style="filled" label=Prep gather [shape=Mrecord label="{gather | EtOH swab\nvented tubing}"] uncap_bottle [label="uncap bottle"] uncap_spike [label="uncap spike"] swab [shape=Mrecord label="{swab EtOH | wait 30 seconds for sterility}"] gather -> uncap_bottle -> swab -> uncap_spike {rank=same gather uncap_bottle swab uncap_spike} } subgraph cluster_hang { style=filled label=Hang {rank=same peel hang} } {rank=same uncap_spike -> peel -> hang -> spike -> prime} hang -> rip [color=firebrick] rip [label="eyelet\nripped" style="filled" shape=octagon regular fontcolor=white fontsize=10 width=.5 fixedsize color=firebrick fillcolor=firebrick ] swab -> not_sterile [color=firebrick] not_sterile [label="not\nsterile" style="filled" shape=octagon regular fontcolor=white fontsize=10 width=.5 fixedsize color=firebrick fillcolor=firebrick ] }

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  • Help to resolve 'Out of memory' exception when calling DrawImage

    - by Jack Juiceson
    Hi guys, About one percent of our users experience sudden crash while using our application. The logs show below exception, the only thing in common that I've seen so far is that, they all have XP SP3. Thanks in advance Out of memory. at System.Drawing.Graphics.CheckErrorStatus(Int32 status) at System.Drawing.Graphics.DrawImage(Image image, Rectangle destRect, Int32 srcX, Int32 srcY, Int32 srcWidth, Int32 srcHeight, GraphicsUnit srcUnit, ImageAttributes imageAttrs, DrawImageAbort callback, IntPtr callbackData) at System.Drawing.Graphics.DrawImage(Image image, Rectangle destRect, Int32 srcX, Int32 srcY, Int32 srcWidth, Int32 srcHeight, GraphicsUnit srcUnit, ImageAttributes imageAttr, DrawImageAbort callback) at System.Drawing.Graphics.DrawImage(Image image, Rectangle destRect, Int32 srcX, Int32 srcY, Int32 srcWidth, Int32 srcHeight, GraphicsUnit srcUnit, ImageAttributes imageAttr) at System.Windows.Forms.ControlPaint.DrawBackgroundImage(Graphics g, Image backgroundImage, Color backColor, ImageLayout backgroundImageLayout, Rectangle bounds, Rectangle clipRect, Point scrollOffset, RightToLeft rightToLeft) at System.Windows.Forms.Control.PaintBackground(PaintEventArgs e, Rectangle rectangle, Color backColor, Point scrollOffset) at System.Windows.Forms.Control.PaintBackground(PaintEventArgs e, Rectangle rectangle) at System.Windows.Forms.Control.OnPaintBackground(PaintEventArgs pevent) at System.Windows.Forms.ScrollableControl.OnPaintBackground(PaintEventArgs e) at System.Windows.Forms.Control.PaintTransparentBackground(PaintEventArgs e, Rectangle rectangle, Region transparentRegion) at System.Windows.Forms.Control.PaintBackground(PaintEventArgs e, Rectangle rectangle, Color backColor, Point scrollOffset) at System.Windows.Forms.Control.PaintBackground(PaintEventArgs e, Rectangle rectangle) at System.Windows.Forms.Control.OnPaintBackground(PaintEventArgs pevent) at System.Windows.Forms.ScrollableControl.OnPaintBackground(PaintEventArgs e) at System.Windows.Forms.Control.PaintTransparentBackground(PaintEventArgs e, Rectangle rectangle, Region transparentRegion) at System.Windows.Forms.Control.PaintBackground(PaintEventArgs e, Rectangle rectangle, Color backColor, Point scrollOffset) at System.Windows.Forms.Control.PaintBackground(PaintEventArgs e, Rectangle rectangle) at System.Windows.Forms.Control.OnPaintBackground(PaintEventArgs pevent) at System.Windows.Forms.Control.PaintWithErrorHandling(PaintEventArgs e, Int16 layer, Boolean disposeEventArgs) at System.Windows.Forms.Control.WmPaint(Message& m) at System.Windows.Forms.Control.WndProc(Message& m) at System.Windows.Forms.Control.ControlNativeWindow.OnMessage(Message& m) at System.Windows.Forms.Control.ControlNativeWindow.WndProc(Message& m) at System.Windows.Forms.NativeWindow.Callback(IntPtr hWnd, Int32 msg, IntPtr wparam, IntPtr lparam) Operation System Information ---------------------------- Name = Windows XP Edition = Home Service Pack = Service Pack 3 Version = 5.1.2600.196608 Bits = 32

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  • Open a buffer as a vertical split in VIM

    - by alfredodeza
    If you are editing a file in VIM and then you need to open an existing buffer (e.g. from your buffer list: :buffers) how can you open it in a vertical split? I know that you already can open it with a normal split like: :sbuffer N Wehere N is the buffer number you want, however, the above opens that N buffer horizontally, not vertically. I'm also aware that you can change the window placement after opening and have a Vertical Split like so: Ctrl-W H Ctrl-W L Which will vertically split the window to the right or the left. It seems to me that if there is a sbuffer there should be a vsbuffer but that doesn't exist (not that I am aware of) Also, please note that I am not looking for a plugin to solve this question. I know about a wealth of plugins that will allow you to do this. I am sure I might be missing something that is already there. EDIT: In the best spirit of collaboration, I have created a simple Function with a Mapping if someone else stumbles across this issue and do not want to install a plugin: Function: " Vertical Split Buffer Function function VerticalSplitBuffer(buffer) execute "vert belowright sb" a:buffer endfunction Mapping: " Vertical Split Buffer Mapping command -nargs=1 Vbuffer call VerticalSplitBuffer(<f-args>) This accomplishes the task of opening a buffer in a right split, so for buffer 1, you would call it like: :Vbuffer 1

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  • How can I fetch Google static maps with TIdHTTP?

    - by cloudstrif3
    I'm trying to return content from maps.google.com from within Delphi 2006 using the TIdHTTP component. My code is as follows procedure TForm1.GetGoogleMap(); var t_GetRequest: String; t_Source: TStringList; t_Stream: TMemoryStream; begin t_Source := TStringList.Create; try t_Stream := TMemoryStream.Create; try t_GetRequest := 'http://maps.google.com/maps/api/staticmap?' + 'center=Brooklyn+Bridge,New+York,NY' + '&zoom=14' + '&size=512x512' + '&maptype=roadmap' + '&markers=color:blue|label:S|40.702147,-74.015794' + '&markers=color:green|label:G|40.711614,-74.012318' + '&markers=color:red|color:red|label:C|40.718217,-73.998284' + '&sensor=false'; IdHTTP1.Post(t_GetRequest, t_Source, t_Stream); t_Stream.SaveToFile('google.html'); finally t_Stream.Free; end; finally t_Source.Free; end; end; However I keep getting the response HTTP/1.0 403 Forbidden. I assume this means that I don't have permission to make this request but if I copy the url into my web browser IE 8, it works fine. Is there some header information that I need or something else?

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  • Question about creating device-compatible bitmaps in C#

    - by MusiGenesis
    I am storing bitmap-like data in a two-dimensional int array. To convert this array into a GDI-compatible bitmap (for use with BitBlt), I am using this function: public IntPtr GetGDIBitmap(int[,] data) { int w = data.GetLength(0); int h = data.GetLength(1); IntPtr ret = IntPtr.Zero; using (Bitmap bmp = new Bitmap(w, h)) { for (int x = 0; x < w; x++) { for (int y = 0; y < h; y++) { Color color = Color.FromArgb(data[x, y]); bmp.SetPixel(x, y, color); } } ret = bmp.GetHbitmap(); } return ret; } This works as expected, but the call to bmp.GetHbitmap() has to allocate memory for the returned bitmap. I'd like to modify this method in two (probably related) ways: I'd like to remove the intermediate Bitmap from the above code entirely, and go directly from my int[,] array to the device-compatible bitmap (i.e. the IntPtr). I presume this would involve calling CreateCompatibleBitmap, but I don't know how to go from that call to actually manipulating the pixel values. This should logically follow from the answer to the first, but I'd also like my method to re-use existing GDI bitmap handles (instead of creating a new bitmap each time). How can I do this? NOTE: I don't really use Bitmap.SetPixel(), as its performance could best be described as "glacial". The code is just for illustration.

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  • How to include frameset under CGI.pm

    - by neversaint
    I want to have a cgi-script that does two things. Take the input from a form. Generate results base on the input values on a frame. Primarily I want the frame exist only after the results is generated/printed. Below is the simplified code of what I want to do. But somehow it doesn't work. What's the right way to do it? #!/usr/local/bin/perl use CGI ':standard'; print header; print start_html('A Simple Example'), h1('A Simple Example'), start_form, "What's your name? ",textfield('name'), p, "What's the combination?", p, checkbox_group(-name=>'words', -values=>['eenie','meenie','minie','moe'], -defaults=>['eenie','minie']), p, "What's your favorite color? ", popup_menu(-name=>'color', -values=>['red','green','blue','chartreuse']), p, submit, end_form, hr; if (param()) { # begin create the frame print <<EOF; <html><head><title>$TITLE</title></head> <frameset rows="10,90"> <frame src="$script_name/query" name="query"> <frame src="$script_name/response" name="response"> </frameset> EOF # Finish creating frame print "Your name is: ",em(param('name')), p, "The keywords are: ",em(join(", ",param('words'))), p, "Your favorite color is: ",em(param('color')), hr; } print end_html;

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  • Silverlight graphics pixel side position?

    - by Tuukka
    I try to port simple game to silverlight (SameGame). The problem is that my old source code used pixel sizes to allight game marks to board. I draw simple grid using lines and game mark (using rectangle). How i can set rentacle position correctly? Example 20 20 pixels to upper left corner). private void DrawGrid() { LayoutRoot.Children.Clear(); Rectangle r = new Rectangle(); r.Width = 20; r.Height = 20; r.Fill = new SolidColorBrush(Color.FromArgb(255, 0, 255, 0)); r.Stroke = new SolidColorBrush(Color.FromArgb(255, 0, 255, 0)); r.SetValue(Canvas.LeftProperty, (double)0); r.SetValue(Canvas.TopProperty, (double)0); LayoutRoot.Children.Add(r); Color GridColor = Color.FromArgb(0xFF, 0x00, 0x00, 0x00); for (int y = 0; y < 11; y++) { Line l = new Line(); l.X1 = 0; l.Y1 = 30 * y - 1; l.X2 = 20 * 30; l.Y2 = 30 * y - 1; l.Stroke = new SolidColorBrush(GridColor); l.StrokeThickness = 1; LayoutRoot.Children.Add(l); } for (int x = 0; x < 21; x++) { Line l = new Line(); l.X1 = 30 * x; l.Y1 = 0; l.X2 = 30 * x; l.Y2 = 10 * 30; l.Stroke = new SolidColorBrush(GridColor); l.StrokeThickness = 1; LayoutRoot.Children.Add(l); } }

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  • Struts ActionError

    - by user287663
    Hi all. Anyone knows why the code below doesn't compile? The reason is that it could not find symbol for ActionError. Thanks in advance. package com.hbs; import javax.servlet.RequestDispatcher; import javax.servlet.ServletException; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpSession; import javax.servlet.http.HttpServletResponse; import org.apache.struts.action.Action; import org.apache.struts.action.ActionError; import org.apache.struts.action.ActionErrors; import org.apache.struts.action.ActionForm; import org.apache.struts.action.ActionMapping; import org.apache.struts.action.ActionForward; import org.apache.struts.util.MessageResources; import org.apache.commons.beanutils.PropertyUtils; public class FeedbackAction extends org.apache.struts.action.Action { private final static String SUCCESS = "success"; public ActionForward execute(ActionMapping mapping, ActionForm form, HttpServletRequest request, HttpServletResponse response) throws Exception { ActionErrors errors = new ActionErrors(); String fullName = (String)PropertyUtils.getSimpleProperty(form, "fullName"); String fullName1 = ""; if(fullName.equals(fullName1)) { errors.add("fullName", new ActionError("error.fullName", fullName)); saveErrors(request,errors); return (new ActionForward(mapping.getInput())); } return mapping.findForward(SUCCESS); } }

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  • please convert this PHP code in ruby

    - by Arpit Vaishnav
    <?php // amcharts.com export to image utility // set image type (gif/png/jpeg) $imgtype = 'jpeg'; // set image quality (from 0 to 100, not applicable to gif) $imgquality = 100; // get data from $_POST or $_GET ? $data = &$_POST; // get image dimensions $width = (int) $data['width']; $height = (int) $data['height']; // create image object $img = imagecreatetruecolor($width, $height); // populate image with pixels for ($y = 0; $y < $height; $y++) { // innitialize $x = 0; // get row data $row = explode(',', $data['r'.$y]); // place row pixels $cnt = sizeof($row); for ($r = 0; $r < $cnt; $r++) { // get pixel(s) data $pixel = explode(':', $row[$r]); // get color $pixel[0] = str_pad($pixel[0], 6, '0', STR_PAD_LEFT); $cr = hexdec(substr($pixel[0], 0, 2)); $cg = hexdec(substr($pixel[0], 2, 2)); $cb = hexdec(substr($pixel[0], 4, 2)); // allocate color $color = imagecolorallocate($img, $cr, $cg, $cb); // place repeating pixels $repeat = isset($pixel[1]) ? (int) $pixel[1] : 1; for ($c = 0; $c < $repeat; $c++) { // place pixel imagesetpixel($img, $x, $y, $color); // iterate column $x++; } } } // set proper content type header('Content-type: image/'.$imgtype); header('Content-Disposition: attachment; filename="chart.'.$imgtype.'"'); // stream image $function = 'image'.$imgtype; if ($imgtype == 'gif') { $function($img); } else { $function($img, null, $imgquality); } // destroy imagedestroy($img); ?

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  • CSS renders Input in firefox mac vs firefox PC. can i detect os via javascript? or maybe a CSS hack

    - by adardesign
    I have a input[type="text"] the that has padding applied to it behaves differently in firefox PC then on a mac. Any hacks that can target firefox PC? These styles are what its seen on firefox PC firebug .searchContainer input { border-color:#7C7C7C #C3C3C3 #DDDDDD; border-style:solid; border-width:1px; color:#555555; float:left; height:12px; padding:3px; } These styles are what its seen on firefox PC firebug .searchContainer input { border-color:#7C7C7C #C3C3C3 #DDDDDD; border-style:solid; border-width:1px; color:#555555; float:left; height:12px; padding:3px; } No other styles are applied to these inputs. Here is a snapshot of FF PC http://tinyurl.com/2wdxmq5 Here is a snapshot of FF mac http://tinyurl.com/2u7f2nl any suggestions?

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  • Jquery Tabs Help

    - by Jacinto
    So I am trying to make a tabs in a menu but cant make the whole width of each of the tabs 219px. it only allows me to make the li 219 but I wanna make the li a 219px. I cant seem to figure it out. Also is there a way to make a next button or would the best way to go to each tab and literally put in the next tab in a type of way? any help would be greatly appreciated Css .servicesNavigation li { float: left; list-style: none; width: 219px; } ul.servicesNavigation li a { padding: 3px 5px; background-color: #ccc; color: #000; text-decoration: none; width: 219px; } ul.servicesNavigation li a.selected, ul.tabNavigation li a:hover { background-color: #333; color: #fff; padding-top: 7px; } ul.servicesNavigation li a:focus { outline: 0; } HTML <ul class="servicesNavigation"> <li><a href="#Web">Web</a></li> <li><a href="#Print">Print</a></li> <li><a href="#DynamicContent">Dynamic Content</a></li> <li><a href="#Hosting">Hosting</a></li> </ul> Jquery var tabContainers = $('div.servicesInfo > div'); tabContainers.hide().filter(':first').show(); $('div.servicesInfo ul.servicesNavigation a').click(function () { tabContainers.hide(); tabContainers.filter(this.hash).show(); $('div.servicesInfo ul.servicesNavigation a').removeClass('selected'); $(this).addClass('selected'); return false; }).filter(':first').click();

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  • Spring-MVC Problem using @Controller on controller implementing an interface

    - by layne
    I'm using spring 2.5 and annotations to configure my spring-mvc web context. Unfortunately, I am unable to get the following to work. I'm not sure if this is a bug (seems like it) or if there is a basic misunderstanding on how the annotations and interface implementation subclassing works. For example, @Controller @RequestMapping("url-mapping-here") public class Foo { @RequestMapping(method=RequestMethod.GET) public void showForm() { ... } @RequestMapping(method=RequestMethod.POST) public String processForm() { ... } } works fine. When the context starts up, the urls this handler deals with are discovered, and everything works great. This however does not: @Controller @RequestMapping("url-mapping-here") public class Foo implements Bar { @RequestMapping(method=RequestMethod.GET) public void showForm() { ... } @RequestMapping(method=RequestMethod.POST) public String processForm() { ... } } When I try to pull up the url, I get the following nasty stack trace: javax.servlet.ServletException: No adapter for handler [com.shaneleopard.web.controller.RegistrationController@e973e3]: Does your handler implement a supported interface like Controller? org.springframework.web.servlet.DispatcherServlet.getHandlerAdapter(DispatcherServlet.java:1091) org.springframework.web.servlet.DispatcherServlet.doDispatch(DispatcherServlet.java:874) org.springframework.web.servlet.DispatcherServlet.doService(DispatcherServlet.java:809) org.springframework.web.servlet.FrameworkServlet.processRequest(FrameworkServlet.java:571) org.springframework.web.servlet.FrameworkServlet.doGet(FrameworkServlet.java:501) javax.servlet.http.HttpServlet.service(HttpServlet.java:627) However, if I change Bar to be an abstract superclass and have Foo extend it, then it works again. @Controller @RequestMapping("url-mapping-here") public class Foo extends Bar { @RequestMapping(method=RequestMethod.GET) public void showForm() { ... } @RequestMapping(method=RequestMethod.POST) public String processForm() { ... } } This seems like a bug. The @Controller annotation should be sufficient to mark this as a controller, and I should be able to implement one or more interfaces in my controller without having to do anything else. Any ideas?

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  • How to modulate every texture unit in OpenGL ES 1.1?

    - by Jesse Beder
    I have two textures and a "blend factor", and I'd like to mix them, modulated by the current color; in effect, I want to use the following shader: gl_FragColor = gl_Color * mix(tex0, tex1, blendFactor); I'm using OpenGL ES 1.1, targeting all versions of the iPhone, so I can't use shaders, and I have two texture units. My best attempt is: // texture 0 glActiveTexture(GL_TEXTURE0); image1.Bind(); glTexEnvi(GL_TEXTURE_ENV, GL_TEXTURE_ENV_MODE, GL_MODULATE); // texture 1 glActiveTexture(GL_TEXTURE1); image2.Bind(); glTexEnvi(GL_TEXTURE_ENV, GL_TEXTURE_ENV_MODE, GL_COMBINE); glTexEnvi(GL_TEXTURE_ENV, GL_COMBINE_RGB, GL_INTERPOLATE); glTexEnvi(GL_TEXTURE_ENV, GL_SRC0_RGB, GL_PREVIOUS); glTexEnvi(GL_TEXTURE_ENV, GL_OPERAND0_RGB, GL_SRC_COLOR); glTexEnvi(GL_TEXTURE_ENV, GL_SRC1_RGB, GL_TEXTURE); glTexEnvi(GL_TEXTURE_ENV, GL_OPERAND1_RGB, GL_SRC_COLOR); glTexEnvi(GL_TEXTURE_ENV, GL_SRC2_RGB, GL_CONSTANT); glTexEnvi(GL_TEXTURE_ENV, GL_OPERAND2_RGB, GL_SRC_ALPHA); glTexEnvi(GL_TEXTURE_ENV, GL_COMBINE_ALPHA, GL_INTERPOLATE); glTexEnvi(GL_TEXTURE_ENV, GL_SRC0_ALPHA, GL_PREVIOUS); glTexEnvi(GL_TEXTURE_ENV, GL_OPERAND0_ALPHA, GL_SRC_ALPHA); glTexEnvi(GL_TEXTURE_ENV, GL_SRC1_ALPHA, GL_TEXTURE); glTexEnvi(GL_TEXTURE_ENV, GL_OPERAND1_ALPHA, GL_SRC_ALPHA); glTexEnvi(GL_TEXTURE_ENV, GL_SRC2_ALPHA, GL_CONSTANT); glTexEnvi(GL_TEXTURE_ENV, GL_OPERAND2_ALPHA, GL_SRC_ALPHA); const float factor[] = { 0, 0, 0, blendFactor }; glTexEnvfv(GL_TEXTURE_ENV, GL_TEXTURE_ENV_COLOR, factor); This has the effect of the shader: gl_FragColor = mix(gl_Color * tex0, tex1, blendFactor); but I don't see how to module texture 1 by the color. Is there any way to have the color provided by a texture unit automatically modulated by the incoming primary color? Or any other way to do what I want that I'm missing? Multiple passes are definitely allowed, but they have to have the proper blend effect; I have glBlend(GL_ONE, GL_ONE_MINUS_SRC_ALPHA); enabled, so it can be tricky to get right with multiple passes.

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  • Is the order of params important in NHibernate?

    - by Blake Blackwell
    If I have an int parameter followed by a string parameter in a sproc I get the following error: Input string was not in the correct format However, if I switch those parameters in the sproc than I get the result set I expect. Are params sorted by data type, or do I have to do anything special in my config file? I've included my code for reference: Config File <?xml version="1.0" encoding="utf-8" ?> <hibernate-mapping xmlns="urn:nhibernate-mapping-2.2" assembly="NHibernateDemo" namespace="NHibernateDemo.Domain"> <class name="Blake_Test" table="Blake_Test"> <id name="TestId" column="TESTID"></id> <property name="TestName" column="TESTNAME" /> <loader query-ref="GetBlakeTest"/> </class> <sql-query name="GetBlakeTest" callable="true"> <return class="Blake_Test" /> call procedure AREA51.NHIBERNATE_TEST.GetBlakeTest(:int_TestId, :vch_TestName) </sql-query> </hibernate-mapping> Sproc Code: PROCEDURE GetBlakeTest ( ret_cursor OUT SYS_REFCURSOR, int_testid integer, vch_testname varchar2 ) AS BEGIN OPEN ret_cursor FOR SELECT TestId, TestName FROM blake_test WHERE testid = int_testid ORDER BY TestName DESC; END GetBlakeTest; END NHIBERNATE_TEST; Executing Code: IQuery query1 = session.GetNamedQuery( "GetBlakeTest" ); query1.SetParameter( "int_TestId", 1 ); query1.SetParameter( "vch_TestName", "TEST" ); IList<Blake_Test> mystuff = query1.List<Blake_Test>();

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