Search Results

Search found 9970 results on 399 pages for 'regular john'.

Page 146/399 | < Previous Page | 142 143 144 145 146 147 148 149 150 151 152 153  | Next Page >

  • byte[] to wav file

    - by John
    Hi, It would be great if you could tell me how I could save a byte[] to a wav file. Sometimes I need to set different samplerate, number of bits and channels. Thanks for your help.

    Read the article

  • Packaging an application that uses the ImageMagick C API

    - by John Gardeniers
    I've created a little Windows app that uses the ImageMagick C API but have run into a bit of a brick wall. The app works fine and I'm ready to share it with a few others in our organisation but I can't find documentation on distributing such an app without installing ImageMagick on the target machine. Does anyone here have information, or a link to information, that details how to package this up for distribution? What DLLs are required and which one(s) need to registered with Windows? The target users will be on a mix of XP and Win7.

    Read the article

  • Best practices, PHP, tracking millions of impressions per day.

    - by John
    What do I have to do to make 20k mysql inserts per second possible (during peak hours around 1k/sec during slower times)? I've been doing some research and I've seen the "INSERT DELAYED" suggestion, writing to a flat file, "fopen(file,'a')", and then running a chron job to dump the "needed" data into mysql, etc. I've also heard you need multiple servers and "load balancers" which I've never heard of, to make something like this work. I've also been looking at these "cloud server" thing-a-ma-jigs, and their automatic scalability, but not sure about what's actually scalable. The application is just a tracker script, so if I have 100 websites that get 3 million page loads a day, there will be around 300 million inserts a day. The data will be ran through a script that will run every 15-30 minutes which will normalize the data and insert it into another mysql table. How do the big dogs do it? How do the little dogs do it? I can't afford a huge server anymore so any intuitive ways, if there are multiple ways of going at it, you smart people can think of.. please let me know :)

    Read the article

  • Advanced Regex: Smart auto detect and replace URLs with anchor tags

    - by Robert Koritnik
    I've written a regular expression that automatically detects URLs in free text that users enter. This is not such a simple task as it may seem at first. Jeff Atwood writes about it in his post. His regular expression works, but needs extra code after detection is done. I've managed to write a regular expression that does everything in a single go. This is how it looks like (I've broken it down into separate lines to make it more understandable what it does): 1 (?<outer>\()? 2 (?<scheme>http(?<secure>s)?://)? 3 (?<url> 4 (?(scheme) 5 (?:www\.)? 6 | 7 www\. 8 ) 9 [a-z0-9] 10 (?(outer) 11 [-a-z0-9/+&@#/%?=~_()|!:,.;cšžcd]+(?=\)) 12 | 13 [-a-z0-9/+&@#/%?=~_()|!:,.;cšžcd]+ 14 ) 15 ) 16 (?<ending>(?(outer)\))) As you may see, I'm using named capture groups (used later in Regex.Replace()) and I've also included some local characters (cšžcd), that allow our localised URLs to be parsed as well. You can easily omit them if you'd like. Anyway. Here's what it does (referring to line numbers): 1 - detects if URL starts with open braces (is contained inside braces) and stores it in "outer" named capture group 2 - checks if it starts with URL scheme also detecting whether scheme is SSL or not 3 - start parsing URL itself (will store it in "url" named capture group) 4-8 - if statement that says: if "sheme" was present then www. part is optional, otherwise mandatory for a string to be a link (so this regular expression detects all strings that start with either http or www) 9 - first character after http:// or www. should be either a letter or a number (this can be extended if you'd like to cover even more links, but I've decided not to because I can't think of a link that would start with some obscure character) 10-14 - if statement that says: if "outer" (braces) was present capture everything up to the last closing braces otherwise capture all 15 - closes the named capture group for URL 16 - if open braces were present, capture closing braces as well and store it in "ending" named capture group First and last line used to have \s* in them as well, so user could also write open braces and put a space inside before pasting link. Anyway. My code that does link replacement with actual anchor HTML elements looks exactly like this: value = Regex.Replace( value, @"(?<outer>\()?(?<scheme>http(?<secure>s)?://)?(?<url>(?(scheme)(?:www\.)?|www\.)[a-z0-9](?(outer)[-a-z0-9/+&@#/%?=~_()|!:,.;cšžcd]+(?=\))|[-a-z0-9/+&@#/%?=~_()|!:,.;cšžcd]+))(?<ending>(?(outer)\)))", "${outer}<a href=\"http${secure}://${url}\">http${secure}://${url}</a>${ending}", RegexOptions.Compiled | RegexOptions.CultureInvariant | RegexOptions.IgnoreCase); As you can see I'm using named capture groups to replace link with an Anchor tag: "${outer}<a href=\"http${secure}://${url}\">http${secure}://${url}</a>${ending}" I could as well omit the http(s) part in anchor display to make links look friendlier, but for now I decided not to. Question I would like my links to be replaced with shortenings as well. So when user copies a very long link (for instance if they would copy a link from google maps that usually generates long links) I would like to shorten the visible part of the anchor tag. Link would work, but visible part of an anchor tag would be shortened to some number of characters. I could as well append ellipsis at the end of at all possible (and make things even more perfect). Does Regex.Replace() method support replacement notations so that I can still use a single call? Something similar as string.Format() method does when you'd like to format values in string format (decimals, dates etc...).

    Read the article

  • R: How can I reorder the rows of a matrix, data.frame or vector according to another one.

    - by John
    test1 <- as.matrix(c(1, 2, 3, 4, 5)) row.names(test1) <- c("a", "b", "c", "d", "e") test2 <- as.matrix(c(6, 7, 8, 9, 10)) row.names(test2) <- c("e", "d", "c", "b", "a") test1 [,1] a 1 d 2 c 3 b 4 e 5 test2 [,1] e 6 d 7 c 8 b 9 a 10 How can I reorder test2 so that the rows are in the same order as test1? e.g: test2 [,1] a 10 d 7 c 8 b 9 e 6 I tried to use the reorder function with: reorder (test1, test2) but I could not figure out the correct syntax. I see that reorder takes a vector, and I'm here using a matrix. My real data has one character vector and another as a data.frame. I figured that the data structure would not matter too much for this example above, I just need help with the syntax and can adapt it to my real problem.

    Read the article

  • Question about oracle db connection with .NET

    - by john
    I'm trying to connect to an oracle database with .net but i get the error: ERROR [IM002] [Microsoft][ODBC Driver Manager] Data source name not found and no default driver specified however, when I enter add a new database connection through toolsconnect to database. it works fine. even after copying the connection string which is: Data Source=source here;Persist Security Info=True;User ID=userhere;Password=pass;Unicode=True

    Read the article

  • SQL: GROUP BY after JOIN without overriding rows?

    - by krismeld
    I have a table of basketball leagues, a table af teams and a table of players like this: LEAGUES ID | NAME | ------------------ 1 | NBA | 2 | ABA | TEAMS: ID | NAME | LEAGUE_ID ------------------------------ 20 | BULLS | 1 21 | KNICKS | 2 PLAYERS: ID | TEAM_ID | FIRST_NAME | LAST_NAME | --------------------------------------------- 1 | 21 | John | Starks | 2 | 21 | Patrick | Ewing | Given a League ID, I would like to retrieve all the players' names and their team ID from all the teams in that league, so I do this: SELECT t.id AS team_id, p.id AS player_id, p.first_name, p.last_name FROM teams AS t JOIN players AS p ON p.team_id = t.id WHERE t.league_id = 1 which returns: [0] => stdClass Object ( [team_id] => 21 [player_id] => 1 [first_name] => John [last_name] => Starks ) [1] => stdClass Object ( [team_id] => 21 [player_id] => 2 [first_name] => Patrick [last_name] => Ewing ) + around 500 more objects... Since I will use this result to populate a dropdown menu for each team containing each team's list of players, I would like to group my result by team ID, so the loop to create these dropdowns will only have to cycle through each team ID instead of all 500+ players each time. But when I use the GROUP BY like this: SELECT t.id AS team_id, p.id AS player_id, p.first_name, p.last_name FROM teams AS t JOIN players AS p ON p.team_id = t.id WHERE t.league_id = 1 GROUP BY t.id it only returns one player from each team like this, overriding all the other players on the same team because of the use of the same column names. [0] => stdClass Object ( [team_id] => 21 [player_id] => 2 [first_name] => Patrick [last_name] => Ewing ) [1] => stdClass Object ( [team_id] => 22 [player_id] => 31 [first_name] => Shawn [last_name] => Kemp ) etc... I would like to return something like this: [0] => stdClass Object ( [team_id] => 2 [player_id1] => 1 [first_name1] => John [last_name1] => Starks [player_id2] => 2 [first_name2] => Patrick [last_name2] => Ewing +10 more players from this team... ) +25 more teams... Is it possible somehow?

    Read the article

  • how to return comma seperated values in oracle SP

    - by john
    If I have a simple query like: OPEN cursor FOR SELECT USER_ID FROM USER_TABLE WHERE USER_ID = V_SOME_USER; this will return records in different rows but how can I return the rows in the following format: 'userid1', 'userid2', 'userid3'.....'useridN' I want to do this because I want to send this off as a parameter to another stored procedure...Also, what is the limit on how big the string can be when passed to the SP as parameter

    Read the article

  • close android open home widget

    - by John
    Hi, I have android open home running on my google android phone. I'd like to close it but I can't see how to. I don't want to un-install it just close it. I've tried turning my phone off and on but it boots up with it loaded. Anyone have any ideas? Thanks

    Read the article

  • jQuery.addClass not adding a class

    - by John Nolan
    Just why is my style not being applied in the jquery below. It aslo only adds the table in FireFox $.each(data.AdvisorPerformances, function(i) { $("#advisorPerfomance").append("<tr>" + "<td>" + data.AdvisorPerformances[i].Advisor + "</td>" + "<td>" + data.AdvisorPerformances[i].PackInCount + "</td>" + "<td>" + data.AdvisorPerformances[i].PacksInValue + "</td>" + "<td>" + data.AdvisorPerformances[i].PacksOutCount + "</td>" + "<td> " + data.AdvisorPerformances[i].PaymentsInCount + "</td>" + "<td>" + data.AdvisorPerformances[i].PaymentsInValue + "</td>" + "</tr>"); }); $("#advisorPerfomance").append("</table>"); $("#advisorPerfomance").addClass("NOTAPPLIEDSTYLE"); Also is there a better way to add a table?

    Read the article

  • Removing trailing newline character from fgets() input

    - by sfactor
    i am trying to get some data from the user and send it to another function in gcc. the code is something like this. printf("Enter your Name: "); if(!(fgets(Name, sizeof Name, stdin) != NULL)) { fprintf(stderr, "Error reading Name.\n"); exit(1); } However, i find that it has an \n character in the end. so if i enter John it ends up sending John\n. so how do i remove that \n and send a proper string.

    Read the article

  • Can I run a 64-bit VMWare image on a 32-bit machine?

    - by John Sibly
    Can I run a 64-bit VMWare image on a 32-bit machine? I've Googled this but there doesn't seem to be a conclusive answer. I know that it would have to be completely emulated and would run like a dog - but slow performance isn't necessarily an issue as I'm just interested in testing some of my background services code on 64-bit platforms.

    Read the article

  • Font advance calculation problem on Blackberry OS 5.0

    - by John
    I am currently working on my own implementation of a tab bar for a BlackBerry app, where each tab bar has a title that is right aligned (i.e. the last character in each should be the same distance from the right hand side of the screen). To work out where to draw the text I am using the following calculation: screen width - advance of title - indent. The font I am using is 'BBAlpha Sans' (height 28). Using BlackBerry OS 4.6 everything seems to be calculated properly and the text is aligned when I move between tabs, however I am finding that when I use OS 5.0 it doesn't calculate the advance properly and as a result the alignment is off by maybe 5 pixels or so. With the default font (also BBAlpha Sans, but height 24 - for OS 5.0 at least) it works fine in both versions.. but I don't necessarily always want to use the default font/size, so any ideas what could be going wrong? Is this a bug in the 5.0 API? Thanks. Code: public class TitleBarBackground extends Background { .. public void draw(Graphics graphics, XYRect rect) { graphics.pushRegion(rect); .. Font titleBarFont = FontFamily.forName("BBAlpha Sans").getFont(Font.PLAIN, 28); ... int textWidth = titleBarFont.getAdvance(title); graphics.drawText(title, rect.width - textWidth - TITLE_OFFSET, textYOffset); graphics.popContext(); } .. }

    Read the article

  • Very different font sizes across browsers

    - by Yang
    Chrome/WebKit and Firefox have different rendering engines which render fonts differently, in particular with differing dimensions. This isn't too surprising, but what's surprising is the magnitude of some of the differences. I can always tweak individual elements on a page to be more similar, but that's tedious, to say the least. I've been searching for more systematic solutions, but many resources (e.g. SO answers) simply say "use a reset package." While I'm sure this fixes a bunch of other things like padding and spacing, it doesn't seem to make any difference for font dimensions. For instance, if I take the reset package from http://html5reset.org/, I can show pretty big differences (note the layout dimensions shown in the inspectors). [The images below are actually higher res than shown/resized in this answer.] <h1 style="font-size:64px; background-color: #eee;">Article Header</h1> With Helvetica, Chrome is has the shorter height instead. <h1 style="font-size:64px; background-color: #eee; font-family: Helvetica">Article Header</h1> Using a different font, Chrome again renders a much taller font, but additionally the letter spacing goes haywire (probably due to the boldification of the font): <style> @font-face { font-family: "MyriadProRegular"; src: url("fonts/myriadpro-regular-webfont.eot"); src: local("?"), url("fonts/myriadpro-regular-webfont.woff") format("woff"), url("fonts/myriadpro-regular-webfont.ttf") format("truetype"), url("fonts/myriadpro-regular-webfont.svg#webfonteknRmz0m") format("svg"); font-weight: normal; font-style: normal; } @font-face { font-family: "MyriadProLight"; src: url("fonts/myriadpro-light-webfont.eot"); src: local("?"), url("fonts/myriadpro-light-webfont.woff") format("woff"), url("fonts/myriadpro-light-webfont.ttf") format("truetype"), url("fonts/myriadpro-light-webfont.svg#webfont2SBUkD9p") format("svg"); font-weight: normal; font-style: normal; } @font-face { font-family: "MyriadProSemibold"; src: url("fonts/myriadpro-semibold-webfont.eot"); src: local("?"), url("fonts/myriadpro-semibold-webfont.woff") format("woff"), url("fonts/myriadpro-semibold-webfont.ttf") format("truetype"), url("fonts/myriadpro-semibold-webfont.svg#webfontM3ufnW4Z") format("svg"); font-weight: normal; font-style: normal; } </style> ... <h1 style="font-size:64px; background-color: #eee; font-family: Helvetica">Article Header</h1> I've tried a few resets/normalize packages to no avail. I just wanted to confirm here that this is indeed a fact of life (even omitting the more glaring offenders like IE and mobile) and I'm not missing some super-awesome solution to this mess.

    Read the article

  • jQuery.keypad Performance Issues

    - by John Duff
    I am working on a Kiosk Touch Screen application and using the JQuery.keypad plugin and noticing some major performance issues. If you click a number of buttons in rapid succession the CPU gets pegged, the button clicks don't keep up with the clicking and some button presses even get lost. On my dev machine this isn't as noticeable, but on the Kiosk itself with 1 gig of ram it's painful. Trying the demo keypad at http://keith-wood.name/keypad.html#inline the one with multiple targets (which is the case with mine) has the exact same issues. Does anyone have any suggestions on how we might be able to improve this? The Kiosk runs in Firefox only so something specific to that would work. I'm using v1.2.1 of jquery.keypad and just upgraded to v1.4.2 of jquery.

    Read the article

  • F# Interactive bug?

    - by John Reynolds
    I've tried the following code in VS2010: open System.Security.Cryptography let rsaTest1 = let ecKey = [|0uy..143uy|] // junk data for testing let ecKeyMod = ecKey.[8..8+128-1] let ecKeyExp = ecKey.[136..136+8-1] let rsa = RSAParameters(Modulus = ecKeyMod, Exponent = ecKeyExp) rsa let rsaTest2 = let ecKey = [|0uy..143uy|] // junk data for testing let rsa = RSAParameters(Modulus = ecKey.[8..8+128-1], Exponent = ecKey.[136..136+8-1]) rsa If I highlight all code and send it to F# Interactive (Alt+Enter), then rsaTest1 works, but rsaTest2 gives an error message, System.NullReferenceException: Object reference not set to an instance of an object. at <StartupCode$FSI_0004>.$FSI_0004.main@() in P:\proj\Tachograph\Project\CompuTachTest\CompuTachTest\rsaTest.fsx:line 16 However, if I change rsaTest2 from a value into a function and call it, let rsaTest2 () = let ecKey = [|0uy..143uy|] // junk data for testing let rsa = RSAParameters(Modulus = ecKey.[8..8+128-1], Exponent = ecKey.[136..136+8-1]) rsa let x = rsaTest2 () then there is no error. F# bug or my mistake?

    Read the article

  • How to match multiple substrings in jQuery combobox autocomplete

    - by John R
    I found more than a couple examples of this with a plain jquery autocomplete but not in a way that will work with the autocomplete included in the combobox code from the demo because the structure of the code is structured so differently. I want to match every item that has all of the search tokens anywhere in any word. I don't need to match the start of any word, any part of it is fine. I don't care if the search strings are highlighted in the autocomplete list if that makes things too complicated. Desired search/result combos: (please excuse the spacing) "fi th" "fi rst second th ird" "rs on" "fi rs t sec on d third" "ec rd" "first s ec ond thi rd" but not limited to any max/min length or number of tokens. EDIT I figured part of it out using the code structure from the other autocorrect I had working. source: function( requestObj, responseFunc ) { var matchArry = $("select > option").map(function(){return this.innerHTML;}).get(); var srchTerms = $.trim(requestObj.term).split(/\s+/); // For each search term, remove non-matches $.each (srchTerms, function (J, term) { var regX = new RegExp (term, "i"); matchArry = $.map (matchArry, function (item) { if( regX.test(item) ){ return{ label: item, value: item, option: HTMLOptionElement } ? item :null; } } ); }); // Return the match results responseFunc (matchArry); }, and select: function( event, ui ) { ui.item.option.selected = true; self._trigger( "selected", event, { item: ui.item.option }); $("destination").val(ui.item.value); // I added this line }, but I can't get both multiple words AND being able to click to select working at the same time. If I remove the } ? item :null; on the return in the map function I can click to select an item. If I leave it I can type multiple words, but I can't click any of the items... Is that the problem or the option: this? I've tried replacing it with HTMLOptionElement and null and I'm stuck. I am able to set the value of another field with ui.item.value within the select label but that doesn't put the value in the search box or close the dropdown menu. Fiddle of current code: http://jsfiddle.net/eY3hM/

    Read the article

  • forward invocation, by hand vs magically?

    - by John Smith
    I have the following two class: //file FruitTree.h @interface FruitTree : NSObject { Fruit * f; Leaf * l; } @end //file FruitTree.m @implementation FruitTree //here I get the number of seeds from the object f @end //file Fruit @interface Fruit : NSObject { int seeds; } -(int) countfruitseeds; @end My question is at the point of how I request the number of seeds from f. I have two choices. Either: Since I know f I can explicitly call it, i.e. I implement the method -(int) countfruitseeds { return [f countfruitseeds]; } Or: I can just use forwardInvocation: - (NSMethodSignature *)methodSignatureForSelector:(SEL)selector { // does the delegate respond to this selector? if ([f respondsToSelector:selector]) return [f methodSignatureForSelector:selector]; else if ([l respondsToSelector:selector]) return [l methodSignatureForSelector:selector]; else return [super methodSignatureForSelector: selector]; } - (void)forwardInvocation:(NSInvocation *)invocation { [invocation invokeWithTarget:f]; } (Note this is only a toy example to ask my question. My real classes have lots of methods, which is why I am asking.) Which is the better/faster method?

    Read the article

  • How do I install something from source and make it available to root?

    - by pwny
    I have a CentOS VM and I need to install the latest version of Ruby on it. Unfortunately, yum only makes Ruby 1.8.6 available so I'm trying to install Ruby from source. Here's what I'm using: cd /usr/src sudo -s wget http://ftp.ruby-lang.org/pub/ruby/1.9/ruby-1.9.3-p125.tar.gz tar -xvzf ruby-1.9.3-p125.tar.gz cd ruby-1.9.3-p125 ./configure make && make install The problem is that once that's done, I can only use Ruby as a regular user but I need to use it as root to install some gems. For example, as a regular user I can do ruby -v and it works but sudo ruby -v outputs bash: ruby: command not found. What am I missing to make stuff I install from source available to all users?

    Read the article

< Previous Page | 142 143 144 145 146 147 148 149 150 151 152 153  | Next Page >